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7-1CHAPTER 7Incremental AnalysisASSIGNMENT CLASSIFICATION TABLEStudy ObjectivesQuestionsBriefExercisesExercisesAProblemsBProblems1.Identify the steps inmanagements decision-making process.1, 2112.Describe the conceptof incremental analysis.3, 4213.Identify the relevantcosts in accepting anorder at a special price.532, 3, 4, 141A1B4.Identify the relevantcosts in a make-or-buydecision.6, 745, 6, 142A2B5.Identify the relevant costsin determining whether tosell or process materialsfurther.8, 9, 105, 67, 8, 9, 143A3B6.Identify the relevant coststo be considered inretaining or replacingequipment.11710, 11, 144A4B7.Identify the relevant costsin deciding whether toeliminate an unprofitablesegment.12812, 13, 145A5B7-2ASSIGNMENT CHARACTERISTICS TABLEProblemNumberDescriptionDifficultyLevelTimeAllotted (min.)1AMake incremental analysis for special order and identifynonfinancial factors in the decision.

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Georgia Perimeter - ACCT - 2102

CHAPTER 8PricingASSIGNMENT CLASSIFICATION TABLEStudy Objectives *1. Compute a target cost when the market determines a product price. Compute a target selling price using cost-plus pricing. Use time-and-material pricing to determine the cost of service

Georgia Perimeter - ACCT - 2102

CHAPTER 9Budgetary PlanningASSIGNMENT CLASSIFICATION TABLEStudy Objectives 1. 2. 3. Indicate the benefits of budgeting. State the essentials of effective budgeting. Identify the budgets that comprise the master budget. Describe the sources for preparin

Georgia Perimeter - ACCT - 2102

CHAPTER 10Budgetary Control and Responsibility AccountingASSIGNMENT CLASSIFICATION TABLEBrief Exercises A Problems B ProblemsStudy Objectives 1. Describe the concept of budgetary control. 2. Evaluate the usefulness of static budget reports. 3. Explain

Georgia Perimeter - ACCT - 2102

CHAPTER 11Standard Costs and Balanced ScorecardASSIGNMENT CLASSIFICATION TABLEBrief Study Objectives 1. Distinguish between a standard and a budget. 2. Identify the advantages of standard costs. 3. Describe how companies set standards. 4. State the for

Georgia Perimeter - ACCT - 2102

CHAPTER 12Planning for Capital InvestmentsASSIGNMENT CLASSIFICATION TABLEStudy Objectives 1. Discuss capital budgeting evaluation, and explain inputs used in capital budgeting. Describe the cash payback technique. Explain the net present value method.

Georgia Perimeter - ACCT - 2102

CHAPTER 13Statement of Cash FlowsASSIGNMENT CLASSIFICATION TABLEBrief Exercises A Problems B ProblemsStudy Objectives *1. Indicate the usefulness of the statement of cash flows. Distinguish among operating, investing, and financing activities. Prepare

Georgia Perimeter - ACCT - 2102

CHAPTER 14Financial Statement Analysis: The Big PictureASSIGNMENT CLASSIFICATION TABLEStudy Objectives 1. 2. 3. 4. 5. Discuss the need for comparative analysis. Identify the tools of financial statement analysis. Explain and apply horizontal analysis.

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 1-1B (a) Factory utilities. Depreciation on factory equipment. Indirect factory labor. Indirect materials. Factory managers salary. Property taxes on factory building. Factory repairs. Manufacturing overhead. (b) Direc

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 2-1B (a) Factory Labor. 68,000 Factory Wages Payable. Employer Payroll Taxes Payable. Employer Fringe Benefits Payable. (b) Work in Process Inventory ($68,000 X 85%). 57,800 Manufacturing Overhead. 10,200 Factory Labor

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 3-1B (a) April 30 Work in ProcessCooking. Work in ProcessCanning. Raw Materials Inventory. Work in ProcessCooking. Work in ProcessCanning. Factory Labor. Work in ProcessCooking. Work in ProcessCanning. Manufacturing Ov

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 4-1B (a) Estimated overhead = Predetermined overhead rate Direct labor costs $270,000 = 180% of direct labor cost $50,000 + $100,000 (b) Activity cost pools Machining Machine setup Cost drivers Machine hours Set up hou

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 5-1 B (a)(b)The relevant range is 4,000 9,000 units of output since a straight-line relationship exists for both direct materials and rent within this range. Variable cost per unit Within the relevant range (4,000 9,

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 6-1B (a) (1) Contribution margin per room = Contribution margin per room = Contribution margin ratio = $50 ($5 + $30) $15 $15 $50 = 30%Fixed costs = $10,000 + $2,000 + $1,000 + $500 = $13,500 Break-even point in rooms

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 7-1B (a) Reject Order Revenues Materials ($0.50) Labor ($1.20) Variable overhead ($1.00) Fixed overhead Sales commissions Net income $ -0-0-0-0-0 -0$ -0Accept Order $19,000 (2,000) (4,800) (4,000) (5,000) -0$3,200Net

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 8-1B (a) The target cost formula is: Target cost = Market price Desired profit. In this case, the market price is $15 and the desired profit is $3 (20% X $15). Therefore the target cost is $12 ($15 $3). (b) Target cost

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 10-1B (a)SANTO COMPANY Selling Expense Report For March By Month Actual $31,000 $35,500 $53,000 Year-to-Date Budget Actual Difference $ 30,000 $ 31,000 $1,000 U $ 67,000 $ 66,500 $ 500 F $112,000 $119,500 $7,500 UMon

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 11-1B (a) Direct materials: (2,000 X 3) X $5 = $30,000 Direct labor: (2,000 X 1/2) X $16 = $16,000 Overhead: $16,000 X 70% = $11,200 (b) Direct materials: 3 X $5 = $15.00 Direct labor: 1/2 X $16 = 8.00 Overhead: $8 X 7

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 12-1B (a) The cash payback period is: $48,000 $8,000 = 6 years The net present value is: 8% Cash Discount Present Flows X Factor = Value Present value of net annual cash flows Present value of salvage value Capital inv

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 13-1B 1. (a) Cash. Land. Gain on Disposal. 18,000 12,000 6,000(b) The cash receipt ($18,000) is reported in the investing section. The gain ($6,000) is deducted from net income in the operating section. 2. (a) Cash. C

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO EXERCISESSET BEXERCISE 14-1B LONGBINE INC. Condensed Balance Sheets December 31 Increase or (Decrease) Amount Percentage ($25,000 (33,000 58,000 (25.0%) (10.0%) (13.5%)2009 Assets Current assets Plant assets (net) Total assets Liabilities C

Georgia Perimeter - ACCT - 2102

SOLUTIONS TO CASES FOR MANAGEMENT DECISION MAKINGCASE 1 1. A predetermined manufacturing overhead rate means that all manufacturing overhead costs, as defined by generally accepted accounting principles (GAAP), are allocated to each job based on a cost d

Georgia Perimeter - ACCT - 2102

CASE 21.ABC is beneficial when traditional overhead allocation results in inaccurate product costing. Wall Dcor should investigate the product costing system because in order to sell the unframed prints the stores must mark them up only slightly above t

Georgia Perimeter - ACCT - 2102

CASE 31.Several different views are likely to surface. Below are representative responses: Now you have a much better understanding of Mr. Burns situation and realize that finding a good solution rests on setting the transfer price so that: (1) Wall Dco

Georgia Perimeter - ACCT - 2102

CASE 41.Present value of future cash flows: Cost of equipment (zero residual value) Cost of ink and paper supplies (purchased immediately) Annual cash flow savings for Wall Dcor ($175,000 X 3.60478)* Annual additional store cash flow from increased sale

Georgia Perimeter - ACCT - 2102

CASE 51.Yes. All organizations should set goals. A large-scale project such as a professional rodeo may not make a profit in the first year. Based on ticket sales, the Auburn Circular Club Pro Rodeo Roundup appears to be a popular attraction. Therefore,

Georgia Perimeter - ACCT - 2102

CASE 6 SWEATS GALORE 1. Yes, it is important for Michael to stipulate certain criteria during planning for his new business. Michael is wise to set criteria other than simply making a profit. First, Michael wants to do something he enjoys. Because he has

Georgia Perimeter - ACCT - 2102

CASE 7 ARMSTRONG HELMET COMPANY 1.Direct Materials Product Costs Direct Manufacturing Labor Overhead Period Costs $15,500 11,000Item Administrative salaries Advertising for helmets Depreciation on factory building Depreciation on office equipment Insura

AIB College of Business - MATHEWS - SOC 2000

Solutions to homework # 2 I.15. The area of a triangle is equal to half the area of the parallelogram dened by two sides of the triangle and the angle between them. The latter area is the absolute value of the cross product of the two vectors correspondin

AIB College of Business - MATHEWS - SOC 2000

Solutions to homework # 1 35. First note u1 + u2 = u3 , i.e., the vectors u1 , u2 , u3 are linearly dependent, i.e., they lie in the same plane. The vectors u1 and u2 , on the other hand, are not not proportional, hence linearly independent. So, it is eno

AIB College of Business - MATHEWS - SOC 2000

Solutions to homework # 3 II.16. (a) f (z ) = z 2 sin z . Since sin z = ei(x+iy) ei(x+iy) ey (cos x + i sin x) ey (cos x i sin x) eiz eiz = = 2i 2i 2i cos x(ey ey ) (ey + ey ) sin x +i = 2 2and z 2 = (x2 y 2 ) + 2ixy , we get f (x, y ) = u(x, y ) + iv (x

AIB College of Business - MATHEWS - SOC 2000

Solutions to homework # 4 II.27. (a) Res f (i) = lim(z i)f (z ) = lim(z i)z i z iz2 i2 z2 = lim = . (z i)(z + i) z i z + i 2i(b) Since e1/z 1 = e1 e1/z , we get e1/z 1 = e1 (1 + 1 1 + + ). 1!z 2!z 2The coecient c1 of 1/z in this Laurent series, i.e.,

AIB College of Business - MATHEWS - SOC 2000

Solutions to homework # 5 II.31. (a) Consider the rectangular contour CR consisting of the intervals IR :=[R, R], + SR :=[R, R + 2 i/b], JR :=[R + 2 i/b, R + 2 i/b], SR :=[R + 2 i/b, R]. First note thatJReaz dz = 1 + ebzIRea(x+2i/b) dx = e2ia/b 1 + eb

AIB College of Business - MATHEWS - SOC 2000

Answers and comments on homework # 7 IV.2. (a) f (x) = 11 2 sin(2nx) . n n=1(b)2 n=1(1)nsin(nx) . n(c) The series for [0, 1] converges faster to the function f on [0, 1] than the series for [1, 1]. On the other hand, the second series approximates

AIB College of Business - MATHEWS - SOC 2000

Answers to homework # 10 VI.2. (a) 2 cos(nx/L), L n=1, n odd (b) 1 1 + cos(nx/L). 2L n=0 LVI.6. (a) VI.7. y (x, t) = VI.11. ex (x) = (x) + (x). 2I 1 (sin(n/3) + sin(2n/3) sin(nx/L) sin(nvt/L). v n=1 n 1 3 e + e1 , 4 (b) 1 9 e + e4 . 5

Aarhus Universitet - MATH - 0984321

Fsica Bsica: Mecnica - H. Moyss Nussenzveig, 4.ed, 2003Problemas do Captulo 2por Abraham Moyss Cohen Departamento de Fsica - UFAM Manaus, AM, Brasil - 2004Problema 1Na clebre corrida entre a lebre e a tartaruga, a velocidade da lebre de 30 km/h e a da

Aarhus Universitet - MATH - 0984321

Problemas Resolvidos do Captulo 3MOVIMENTO BIDIMENSIONALAteno Leia o assunto no livro-texto e nas notas de aula e reproduza os problemas resolvidos aqui. Outros so deixados para v. treinarPROBLEMA 1Um projtil disparado com velocidade de 600 m/s, num n

Aarhus Universitet - MATH - 0984321

Problemas Resolvidos do Captulo 5APLICAES DAS LEIS DE NEWTONAteno Leia o assunto no livro-texto e nas notas de aula e reproduza os problemas resolvidos aqui. Outros so deixados para v. treinar PROBLEMA 1Um astronauta, vestindo seu traje espacial, cons

Aarhus Universitet - MATH - 0984321

Problemas Resolvidos do Captulo 6TRABALHO E ENERGIA MECNICAAteno Leia o assunto no livro-texto e nas notas de aula e reproduza os problemas resolvidos aqui. Outros so deixados para v. treinar PROBLEMA 1Resolva o problema 8 do Captulo 4 a partir da con

Aarhus Universitet - MATH - 0984321

Problemas Resolvidos do Captulo 7CONSERVAO DA ENERGIA NO MOVIMENTO GERALAteno Leia o assunto no livro-texto e nas notas de aula e reproduza os problemas resolvidos aqui. Outros so deixados para v. treinar PROBLEMA 1No Exemplo 1 da Se. 5.3, considere a

Aarhus Universitet - MATH - 0984321

Problemas Resolvidos do Captulo 8CONSERVAO DO MOMENTOAteno Leia o assunto no livro-texto e nas notas de aula e reproduza os problemas resolvidos aqui. Outros so deixados para v. treinar PROBLEMA 1Dois veculos espaciais em rbita esto acoplados. A massa

Aarhus Universitet - MATH - 0984321

Problemas Resolvidos do Captulo 9COLISESAteno Leia o assunto no livro-texto e nas notas de aula e reproduza os problemas resolvidos aqui. Outros so deixados para v. treinar PROBLEMA 1Calcule a magnitude (em kgf) da fora impulsiva que atua em cada um d

Vanderbilt - CS - CS 103

CS 103 Test 1 Fall 2009Enter your answers into the M-files provided. Each problem has its own M-file. Problem 1. (15 points) A. Which of the following is not an algorithm. 1. Start with 11, add each successive prime number until the sum is greater than 1

Vanderbilt - CS - CS 103

CS 103 Test 2 Fall 2009Enter your answers into the M-files provided. Suppress all printing to the Command Window. Problem 1. (15 points) A. Polymorphism is 1. Dependence of the behavior of a function on the type of its input arguments 2. Dependence of th

Vanderbilt - CS - CS 103

CS 103 Test 3 Fall 2009Problem 1. (15 points) Enter answers to this problem into the function p1 (in the provided M-file p1.m). A. In computer programming, the word robust describes 1. a program that does something reasonable with all inputs 2. a compute

Vanderbilt - CS - CS 103

CS 103 Test 4 Fall 2009Problem 1. (15 points) Enter answers to this problem into the function p1 (in the provided M-file p1.m). A. The break statement is used to 1. terminate a loop 2. terminate a for loop but not a while loop 3. terminate a while loop b

Vanderbilt - CS - CS 103

CS 103Test 5Fall 2009Problem 1. (15 points) Enter answers to this problem into the function t5p1 (in the provided M-file t5p1.m). A. In computer science, the term stack denotes a 1. first-in-first-out data structure 2. last-in-first-out data structure

Vanderbilt - CS - CS 103

CS 103 Test 41 (the rest of Test 4) Fall 2009Problem 1. (15 points) Enter answers to this problem into the function t4p1 (in the provided M-file t4p1.m). A. The break statement is used to 1. terminate a loop 2. terminate a for loop but not a while loop 3

Vanderbilt - CS - CS 103

CS 103Test 6Fall 2009Problem 1. (15 points) Enter answers to this problem into the function t6p1 (in the provided M-file t6p1.m). A. An activation record is 1. the set of values assigned to a variable throughout a Matlab session 2. the set of locations

Texas San Antonio - CS - 2213

CS 2213 Final 1. [10] Consider the following function:void funct(int u, int *v, int w) cfw_ printf(0 0 0 0\n, u, v, w, *v); *v = u; v = &u; *v = w; printf(0 0 0 0\n, *v, u); What is printed from the following code (including what funct() prints) assumin

Salem State - GLS - 1133

Rock Identifiable FeaturesBy Francesco De Sisto1. Sedimentary Rocks a. Have strata layers b. Have certain grain size c. Are made up of other rock fragments d. Some sedimentary rocks react to acid such as coquina, micrite limestone, chalk limestone, etc

UT Dallas - SE - 3306

Exam 03 04/19/2007SE3306 Mathematical Foundations of SEName: WebCT ID:Instructions: Read through the whole exam rst and plan your time. The exam is worth 25 points, with each question valued as indicated. Closed book: Reference to notes, the text or ot

UT Dallas - SE - 3306

Exam 02 03/22/2007SE3306 Mathematical Foundations of SEName: WebCT ID:Instructions: Read through the whole exam rst and plan your time. The exam is worth 25 points, with each question valued as indicated. Closed book: Reference to notes, the text or ot

UT Dallas - SE - 3306

Exam 01 02/14/2006SE3306 Mathematical Foundations of SEName: WebCT ID:Instructions: Read through the whole exam rst and plan your time. The exam is worth 25 points, with each question valued as indicated. Closed book: Reference to notes, the text or ot

UT Dallas - SE - 3306

SE 3306 - Mathematical Foundations of SEHomework # 6Due on 04/17/2007 10am(1)Can a simple graph exist with 15 vertices of degree ve? Explain! (2) The complementary graph G of a simple graph G has the same vertices as G. Two ver tices are adjacent in G

UT Dallas - SE - 3306

SE 3306 - Mathematical Foundations of SEHomework # 5Due on 04/22/2009 10:30am(1) Consider a small north-south street that terminates as it meets a large east-west avenue, as shown in the Figure below. Due to the heavy trac along the avenue, the westbou

UT Dallas - SE - 3306

SE 3306 - Mathematical Foundations of SEHomework # 4Due on 03/25/2009 10:30am(1) Let = cfw_a, b, c. Give a FSA that will describe 1. L1 = cfw_x |(x begins with c) (x contains two consecutive bs. 2. L2 = cfw_x |x|a is odd |x|b is even. (2) Let = cfw_0,

UT Dallas - SE - 3306

UT Dallas - SE - 3306

SE 3306 Problem Set on Language Theory Required Reading: class notes, Rosen 5th edition 11.1-11.41. Class notes on regular expressions, automata, machines, problems at back 2. Section 11.1 Examples 2,3,4 , problem 18 pg. 750 3. Section 11.2 Examples 2,3,

UT Dallas - SE - 3306

Introduction to Axiomatic Set TheoryPrepared by: Prof. Kendra Cooper Contents Axiomatic Set Theory Frege Russell Zermelo-Fraenkel ZF Set Theory Axioms - Summary Continuum Hypothesis Problems Nave set theory is elegant, simple, intuitive, and generally lo

UT Dallas - SE - 3306

UT Dallas - SE - 3306

Propositional Calculus Solution Outline Problem 1: (a) E R S T = = = = Relation Relation Relation Relation is is is is an Equivalence Relation Reflexive Symmetric TransitiveE <=> (R and S and T) (b) C = person has courage S = person has skill M = person