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16 Pages

### P1710_MWF29

Course: CAS 1710, Fall 2009
School: North Texas
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Word Count: 718

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1710--Warm-up Physics Quiz 0 In the movie &quot;Armaggedon&quot; a comet &quot;the size of Texas'&quot; (800 miles or 1250 km in diameter) was heading for Earth. If the density were 800 kg/m3, the mass would be about 8.x10 20 kg. How far would a ball on the surface fall in 1.0 second? A. B. C. D. About 5 m About 7 cm About 2 cm None of the above Answer Now ! 78% 0 16% 4% A B C 2% D 35% 50...

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1710--Warm-up Physics Quiz 0 In the movie "Armaggedon" a comet "the size of Texas'" (800 miles or 1250 km in diameter) was heading for Earth. If the density were 800 kg/m3, the mass would be about 8.x10 20 kg. How far would a ball on the surface fall in 1.0 second? A. B. C. D. About 5 m About 7 cm About 2 cm None of the above Answer Now ! 78% 0 16% 4% A B C 2% D 35% 50 of 140 81 101 82 102 83 103 84 104 85 105 86 106 87 107 88 108 89 109 90 110 91 111 92 112 93 113 94 114 95 115 96 116 97 117 98 118 99 119 100 120 Physics 1710--Chapter 12 Apps: Gravity 0 Gravitation g =G M/ R2 g=(6.67x10-11 N m2/kg2)(8x1020 kg)/(625x103 m)2 g = 0.14 N/kg d = g t 2 = 0.5 (0.14 m/s2)(1 sec)2 = 0.0 7 m = 7 cm Physics 1710--Chapter 13 Apps: Gravity 1 Lecture The gravitational force constant g is equal to g = G M/(R+h) 2, M and R are the mass and radius of the planet. The gravitation field is the force divided by the mass. The gravitation potential energy for a point mass is proportional to the product of the masses and inversely proportional to the distance between their centers. The escape velocity is the initial velocity at the surface required to leave a body. vescape = [ 2GM/R] 0 Physics 1710--Chapter 13 Apps: Gravity Does the position of the moon affects us as astrology claims? 0 Think! No Talking! Confer! Peer Instruction Time Physics 1710--Chapter 13 Apps: Gravity Does the position of the moon affects us as astrology claims? Answer Now ! A. B. C. D. Yes, I strongly agree Yes, I Agree No, I disagree No, I strongly disagree 17% 2% A B C D 0 0 58% 23% 34% 48 of 140 81 101 82 102 83 103 84 104 85 105 86 106 87 107 88 108 89 109 90 110 91 111 92 112 93 113 94 114 95 115 96 116 97 117 98 99 119 100 120 118 Physics 1710--Chapter 13 Apps: Gravity Astrology: Does the moon affect us? 0 F = - G M m/ d 2 M = 7.36x1023 kg; d = 3.84x108 m |F/m|= (7x10-11)(7x1023)/(4x108)2 = 3x10-4 N/kg ~ 30 g d moon=3.84x108 m M =7.36x1023 kg Physics 1710--Chapter 13 Apps: Gravity Gravitational Potential Energy U = -R Fd r U = -R G Mm/r 2d r U = GMm/R = mgR U = 0 as r F dr 0 Physics 1710--Chapter 13 Apps: Gravity Escape Velocity If K is such that E = 0 as r , then KR = m v 2 = UR = GMm/ R and vescape = [ 2GM/R] = [2gR] 0 UR = GMm/R K = m v2 U = 0 K = 0 Physics 1710--Chapter 13 Apps: Gravity Were the astronauts in danger of jumping the off "Armaggedon" comet? (Hint: What is the escape velocity from our "Armaggedon" comet? M = 8x1020 kg, R =6.25x10 5 m, g = 0.14 N/kg) Answer Now ! A. B. C. D. Yes. Definitely. Maybe. No. Definitely not. Not enough information. 37% 52 of 140 A B C D 0 0 48% 35% 13% 4% 41 61 42 62 43 63 44 64 45 65 46 66 47 67 48 68 49 69 50 70 51 71 52 72 53 73 54 74 55 75 56 76 57 77 58 78 59 79 60 80 Physics 1710--Chapter 13 Apps: Gravity Escape Velocity vescape = [ 2GM/R] = [2gR] = [2(0.14 N/kg)(625 km)] ~ 400 m/s ~ 900 mph. Safe! 0 vescape = [ 2GM/R] = [2gR]?? Physics 1710--Chapter 13 Apps: Gravity Escape Velocity of Earth? vescape = [ 2GM/R] = [2gR] = [2(9.8 N/kg)(6.3 x10 6 m)] ~ 11,000 m/s 25,000 mph. Stuck! 0 vescape = [ 2GM/R] = [2gR]?? Physics 1710--Chapter 13 Apps: Gravity Total Energy for Gravitationally Bound Mass E=K+U E = m v 2 GMm/r E = L2/2mr 2 GMm/r Bound orbit if E 0 and - dE/dr |r = 2 (L2/2mro) - GMm = 0 o 0 E = - GMm/2ro Physics 1710--Chapter 13 Apps: Gravity Total Energy for Gravitationally Bound Mass E=K+U E = - GMm/2ro r E<0 0 L2 /2mr 2 GMm/r ro = - 2E/(GMm) Physics 1710--Chapter 13 Apps: Gravity Summary: The force of attraction between two bodies with mass M and m respectively is proportional to the product of their masses and inversely proportional to the distance between their centers squared. F = - G M m/ r 2 The proportionality consta...

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