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### hw5soln

Course: EE 202, Fall 2009
School: Purdue
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Word Count: 1093

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202 ECE - Linear Circuit Analysis II Purdue University, Spring 2009 Homework Set 2 Solutions Solution 17 VC(s) 2 VL(s) 3 2 4/s s 2/s Note that the current sources I in (s) and CvC (0-) have been combined into a single current source(2+1=3). From the above simplified circuit in s-domain, we can write 1 , VC - VL (s + 2)VC + 2 4 VL - VC 2 + 2 s = = 3 - VL s Solving using cramer's rule and ilaplace command...

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202 ECE - Linear Circuit Analysis II Purdue University, Spring 2009 Homework Set 2 Solutions Solution 17 VC(s) 2 VL(s) 3 2 4/s s 2/s Note that the current sources I in (s) and CvC (0-) have been combined into a single current source(2+1=3). From the above simplified circuit in s-domain, we can write 1 , VC - VL (s + 2)VC + 2 4 VL - VC 2 + 2 s = = 3 - VL s Solving using cramer's rule and ilaplace command in MATLAB, VC vC (t) = = = = 4(3s + 4) s2 + 4s + 8 12 cos(2t) - 1 sin(2t) e-2t u(t) 3 VL vL (t) 8(s - 2) s2 + 4s + 8 8[cos(2t) - 2 sin(2t)]e-2t u(t) Solution 18 (a) The equiva...
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