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ch17

Course: ECE 4350, Spring 2007
School: Villanova
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andDevices Topic17:MetalSemiconductorJunctions ECE3500SemiconductorMaterials andHeterojunctions Fall2007 Learning Objectives Inthistopicyouwilllearn: Howmetalsemiconductorjunctions resultineitherohmicorrectifying contacts Howpnjunctionsofdissimilarmaterials behavebothatthermalequilibriumand underbias. Metal-Semiconductor Junctions Theworkfunction,,ofamaterialis definedastheenergyrequiredto...

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andDevices Topic17:MetalSemiconductorJunctions ECE3500SemiconductorMaterials andHeterojunctions Fall2007 Learning Objectives Inthistopicyouwilllearn: Howmetalsemiconductorjunctions resultineitherohmicorrectifying contacts Howpnjunctionsofdissimilarmaterials behavebothatthermalequilibriumand underbias. Metal-Semiconductor Junctions Theworkfunction,,ofamaterialis definedastheenergyrequiredto takeanelectronfromtheFermi leveltothevacuumlevel. vacuum level q m EF q S q S EC EF metal EV semiconductor Metal-Semiconductor Junctions (contd) Whenametalandasemiconductor arebroughtintointimatecontact, Metal-Semiconductor Junctions (contd) Consideranntypesemiconductor beingbroughtintocontactwithametal withworkfunctiongreaterthanthatof thesemiconductor. eq m EF q S EC EF metal EV n-type semiconductor Metal-Semiconductor Junctions (contd) Metal-Semiconductor Junctions (contd) Rectifying behavior i V Schottky Barrier Metal-Semiconductor Junctions (contd) Nowconsiderthecaseofanntype semiconductorbroughtintointimate m contactwithametalwith.< S q m metal eq S n-type Junctions semiconductor Metal-Semiconductor (contd) Metal-Semiconductor Junctions (contd) Ohmic behavior i V OhmicContactallowscurrenttoflow easilyintoandoutofthe semiconductor. Schottky Contact to p-type Semiconductor Ohmic Contact to p-type Semiconductor Heterojunctions EC1 EC EC2 EF2 EV2 E g = E g1 E g 2 EF1 Ev1 EV qV01 = EC + EV EC EF qV0 = q (V01 +V02 ) qV02 EV V01 2 N d 2 = V02 1 N d 1 Procedure for Sketching Heterojunctions Step1.AligntheFermilevelsofthetwo semiconductorsleavingspaceforthe transitionregion. EC EF EV Procedure for Sketching Heterojunctions (contd) Step2.Placethemetallurgicaljunctioncloser tothemoreheavilydopedside.Atthispoint placeECandEV,separatedbythe appropriatebandgaps. EC EF EC EV EV Procedure for Sketching Heterojunctions (contd) Step3.Connecttheconductionandvalence bandskeepingthebandgapconstantineach region. EC EF EV Summary Inthistopicyouhavelearned: Howmetalsemiconductorjunctions resultineitherohmicorrectifying contacts Howpnjunctionsofdissimilarmaterials behavebothatthermalequilibriumand underbias.
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Villanova - ECE - 4350
ECE3500SemiconductorMaterials andDevicesTopic18:JunctionFieldEffectTransistorsFall2007Learning ObjectivesInthistopicyouwilllearn: HowBJTsdifferfromFETs Thedifferentmodesofoperationof transistors ThephysicaloperationoftheJFET. Howtocalculatethecurrentv
Villanova - ECE - 4350
ECE3500SemiconductorMaterials andDevicesTopic19:MetalOxideSemiconductorField EffectTransistors(MOSFETs)Fall2007 Learning ObjectivesInthistopicyouwilllearn: Thedifferencebetweenenhancementand depletionmodeMOSFETs ThephysicaloperationofaMOSFET. Howtoca
Villanova - ECE - 4350
ECE3500SemiconductorMaterials andDevicesTopic20:BipolarJunctionTransistors PrinciplesofOperationand ActiveModeBiasingFall2007 Learning ObjectivesInthistopicyouwilllearn: ThephysicaloperationofaBJT. HowtodesignahighgainBJT. Howtocalculatetheemitter,ba
Cornell - ECE - 2200
Cornell - ECE - 2200
Cornell - ECE - 2200
ECE 2200 / Spring 2010: Course Information1ECE 2200 / Spring 2010 SIGNALS AND INFORMATIONCOURSE INFORMATION11 Basic Info Professor: Rick Johnson (e-mail: johnson at ece.cornell.edu) Oce: 390 Frank H. T. Rhodes Hall (phone: 607 255-0429) Oce Hours: Tu
Cornell - ECE - 2200
EE 2200 / Spring 2010: Section ONE1ECE 2200 / Spring 2010 SECTION ONE (Week 2: Feb 1-4)1. Find the cyclic frequency, radian frequency, period, phase shift, and amplitude of the following signals (i) x(t) = 6.5 cos(2 420t /3) (ii) y (t) = 11 cos(0.2 ) c
Cornell - ECE - 2200
EE 2200 / Spring 2010: Section FOUR1ECE 2200 / Spring 2010 SECTION Four (Week 5: Feb 22-25)1. The impulse response h[n] of an FIR lter is h[n] = [n 1] 3 [n 3] + 0.1 [n 4] + 0.04 [n 7] Write the dierence equation for the FIR lter. 2. Consider the unit s
Cornell - ECE - 2200
EE 2200 / Spring 2010: Section FIVE1ECE 2200 / Spring 2010 SECTION Five (Week 6: Mar 1-4)1. The FIR lter with impulse response h[n] = 2 [n 2] where [k ] is 1 for k = 0 and 0 otherwise, has output y [n] = u[n 3] u[n 6] where u[k ] is 1 for k 0 and 0 oth
Cornell - ECE - 2200
EE 2200 / Spring 2010: Section SIX1ECE 2200 / Spring 2010 SECTION Six (Week 7: Mar 8-11)1. Consider the linear, time-invariant FIR system with system function H (z ) = 1.2 + 4.7z 1 3.2z 2 + 2.8z 3 + 4.2z 7 (a) Determine the dierence equation that relat
Cornell - ECE - 2200
ECE 2200 Signals and Information Section 1 (Week 2 Feb 1-4)Page 11. Find the cyclic frequency, radian frequency, period, phase shift and amplitude of the following signals: (i) x(t) = 6.5 cos(2 420t /3) (ii) y (t) = 11 cos(0.2 ) cos(157(t + 0.02) (iii)
Cornell - ECE - 2200
EE 2200 / Spring 2010: Section TWO1ECE 2200 / Spring 2010 SECTION Two (Week 3: Feb 8-11)1. Problem P-2.21 in text. 2. Consider the system that with input u u(t) = cos(at) produces the output y y (t) = u(t)(cos(bt) Given that the magnitude spectrum of y
Cornell - ECE - 2200
ECE 2200 Signals and Information Section 2 Solutions (Week 3 Feb 8-11) Page 11. Problem P-2.21 in text (page 34). Solution: (i) The time delays are the distances traveled by each signal divided by the speed of light (c0 = 3 108 m/s): x2 + 106 d 1 ( x) t
Cornell - ECE - 2200
EE 2200 / Spring 2010: Section THREE1ECE 2200 / Spring 2010 SECTION Three (Week 4: Feb 15-18)1. The continuous-time sinusoid x(t) = 4.5sin(16.6 t) is to be sampled at fs to produce the discrete-time sinusoid x[k ] = M cos( k + ) (i) For fs = 15 Hz, det
Cornell - ECE - 2200
ECE 2200 Signals and Information Section 3 (Week 4 Feb 15-18)1. The continuous-time sinusoid x(t) = 4.5 sin(16.6t) is to be sampled at fs to produce the discrete-time sinusoid x[k ] = M cos(k + )Page 1(i) For fs = 15 Hz, determine M , , and . Has x(t)
Cornell - ECE - 2200
ECE 2200 Signals and Information Section 4 (Week 5 Feb 22-25)1. The impulse response h[n] of an FIR lter is h[n] = [n 1] 3 [n 3] + 0.1 [n 4] + 0.04 [n 7] Write the dierence equation for the FIR lter. Page 1Solution (read 5-3 The General FIR Filter and
Cornell - ECE - 2200
ECE 2200 Signals and Information Section 5 (Week 5 Mar 1-4)1. The FIR lter with impulse response h[n] = 2 [n 2] has output y [n] = u[n 3] u[n 6]. Determine the input x[n]. The deconvolution of y [n] is as follows: y [n] = x[n] h[n] = 2x[n 2] 1 1 x[n] = u
Clemson - ECON - 211
Austin Savage Robert Southworth AL 362- Special Project 1 Special Project 1- Interview with Head Coach Mike Noonan One of the primary objectives as an athletic coach is to develop their athletes mentally and physically. Coaches must motivate their players
Clemson - AL - 362
Jamir Shefton AL 62 Assignment 2Ch.1 Vocabulary I hope to acquire a solid coaching philosophy that will be beneficial in both coaching and life. By enhancing my self awareness, I should be able to target and assess my faults. I am more focused on learnin
Clemson - AL - 362
Assignment 3: Copy and paste this into the assignment window. Then type the word RESPONSE after each question followed by your answer.Using the text as your resource, answer the following questions. If a question is false, provide the correct answer. Tru
Clemson - AL - 362
Chapter 9 Review Questions1. What is arousal and how does it develop? RESPONSE: Arousal is the energy that fuels a performance which causes fight-or-flight syndrome.3. What are the major reasons that too little or too much arousal impairs performance? R
Clemson - AL - 362
D uring the spring of my 04' JV basketball season, the coastal area in South Carolina experienced quite a frost which in the count ry: knocks down t rees, that take down power l ines, that r id you of power. W hile some were taking time to play survivor m
Clemson - HIST - 173
Jamir Shefton Prof. Richard Saunders History of Western Civ. November 11, 2009King Leopolds Ghost Not long after King Leopold II of Belgium came into power, he began his search to acquire a larger area than that of his own country. Leopold II was very in
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Jamir Shefton Acct. 201 Pitsa Johnson October 30, 2009 Rusty and Dusty Slow Movers While trying to straighten out her books, Penny notices the high inventory of old &quot;high ticket&quot; items. She is concerned about how accurately the inventory on the books refl
Clemson - LANG - 100
Jamir Shefton Language&amp; International Trade Paula Heusinkveld October 14, 2009 The Career Fair I attended the Study Abroad Fair that was held in Cox Plaza. I was quite impressed with the number of study abroad programs Clemson has to offer. I believe they
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Jamir Shefton Prof. Richard Saunders History of Western Civ. October 14, 2009 Vienna, 1814 Vienna is the capital of the Republic of Austria. It currently serves as the headquarters for OPEC(Organization of the Petroleum Exporting Countries) and an office
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ACCT 201 ANNUAL REPPORT PROJECT Immediately after I assign you to a group, email your group members. Let me know of any problems. For your assigned company, obtain a copy of the most recently audited annual report and/or Form 10K. Go to your companys inte
Clemson - ACCT - 201
PRESENTATION ASSIGNMENT A. Using a financial reporting source (Wall Street Journal, New York Times, NYSE, internet, etc.) answer the following questions. 1. What was the highest, lowest, and closing selling price per share of your companys common stock on
Clemson - ACCT - 201
Depreciation calculations Straight line p279 Units of production p280 Double declining balance p280 Net book value Residual (salvage) value p278 Gain/loss from the sale of a depreciated asset Capitalized costs of long term assets Basket purchases p276 Fix
Dallas - PHYSICS - 1523
ASSIGNMENT 4k q1q2 and solve for r. r2 SET UP: F = 650 N . EXECUTE: r = k q1q2 (8.99 109 N m 2 /C2 )(1.0 C)2 = = 3.7 103 m = 3.7 km F 650 N21.5.IDENTIFY:Apply F =EVALUATE:Charged objects typically have net charges much less than 1 C. 21.44. IDENTIFY:Fo
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 521.55. IDENTIFY:For a ring of charge, the electric field is given by Eq. (21.8). F = qE . In part (b) use Newton's third law to relate the force on the ring to the force exerted by the ring. SET UP: Q = 0.125 109 C, a = 0.025 m and
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 622.3. IDENTIFY:The electric flux through an area is defined as the product of the component of the electric field perpendicular to the area times the area. (a) SET UP:In this case, the electric field is perpendicular to the surface
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 722.13. rr E (a) IDENTIFY and SET UP:It is rather difficult to calculate the flux directly from = dA since the r r magnitude of E and its angle with dA varies over the surface of the cube. A much easier approach is to use Gauss's la
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 822.51. IDENTIFY:The net electric field is the vector sum of the fields due to the sheet of charge on each surface of the plate. SET UP:The electric field due to the sheet of charge on each surface is E = / 2P and is directed 0 away
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 9 plus Problem 23.2523.10. IDENTIFY:The work done on the alpha particle is equal to the difference in its potential energy when it is moved from the midpoint of the square to the midpoint of one of the sides. SET UP:We apply the for
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 10kq . The total potential at any point is the algebraic sum of the r23.25.IDENTIFY:For a point charge, V =potentials of the two charges. SET UP:(a) The positions of the two charges are shown in Figure 23.25a.Figure 23.25a (b) x
Dallas - PHYSICS - 1523
Solutions, Assignment 1124.1.IDENTIFY: C =Q VabSET UP: 1 F =106 F EXECUTE: Q = CVab = (7.28 106 F)(25.0 V) = 1.82 104 C = 182 C EVALUATE:One plate has charge +Q and the other has charge Q . 24.2. IDENTIFY and SET UP: C = (a) C = P 0PA Q 0 , C = and V
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 1224.10. IDENTIFY:Capacitance depends on the geometry of the object. (a) SET UP:The capacitance of a cylindrical capacitor is C = rb = ra e 2 P0 L / C . EXECUTE:Substituting in the numbers for the exponent gives = 0.182 3.67 1011 F
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 1324.30.0 A Q2 CV 2 . The stored energy can be expressed either as or as , whichever is more d 2C 2 convenient for the calculation. SET UP:Since d is halved, C doubles. EXECUTE:(a) If the separation distance is halved while the cha
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 1425.1. IDENTIFY: I = Q / t . SET UP: 1.0 h = 3600 s EXECUTE: Q = It = (3.6 A)(3.0)(3600 s) = 3.89 104 C. EVALUATE:Compared to typical charges of objects in electrostatics, this is a huge amount of charge. (a) IDENTIFY:By definition
Dallas - PHYSICS - 1523
Solutions, Assignment 1525.33. IDENTIFY: V = E Ir . SET UP:The graph gives V = 9.0 V when I = 0 and I = 2.0 A when V = 0. EXECUTE:(a) E is equal to the terminal voltage when the current is zero. From the graph, this is 9.0 V. (b) When the terminal voltag
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 16 26.2. IDENTIFY:It may appear that the meter measures X directly. But note that X is in parallel with three other resistors, so the meter measures the equivalent parallel resistance between ab. SET UP:We use the formula for resisto
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 1726.38. IDENTIFY:An uncharged capacitor is placed into a circuit. Apply the loop rule at each time. SET UP:The voltage across a capacitor is VC = q / C . EXECUTE:(a) At the instant the circuit is completed, there is no voltage over
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 18r 27.1.IDENTIFY and SET UP:Apply Eq.(27.2) to calculate F . Use the cross products of unit vectors from Section 1.10. r 4 4 j EXECUTE: v = ( +4.19 10 m/s ) i + ( 3.85 10 m/s ) r (a) B = ( 1.40 T ) i r r r F = qv B = ( 1.24 108 C )
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 1927.28. IDENTIFY:For no deflection the magnetic and electric forces must be equal in magnitude and opposite in direction. 2 SET UP: v = E / B for no deflection. With only the magnetic force, q vB = mv / R EXECUTE:(a) v = E B = (1.5
Dallas - PHYSICS - 1523
Solutions, Assignment 2027.42. IDENTIFY: = IAB sin . The magnetic moment of the loop is = IA . SET UP:Since the plane of the loop is parallel to the field, the field is perpendicular to the normal to the loop and = 90 . EXECUTE:(a) = IAB = (6.2 A)(0.050
Dallas - PHYSICS - 1523
Solutions, Assignment 2128.11.IDENTIFY and SET UP:The magnetic field produced by an infinitesimal current element is given by Eq. (28.6). r r 0 Il r As in Example 28.2 use this equation for the finite 0.500-mm segment of wire since the dB = 2 4 r l = 0.
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 2228.66. r r 0 Idl r IDENTIFY:Apply dB = . 4 r 2 SET UP:The two straight segments produce zero field at P. The field at the center of a circular loop of I I radius R is B = 0 , so the field at the center of curvature of a semicircul
Dallas - PHYSICS - 1523
SOLUTIONS, Assignment 2328.40. = IDENTIFY: B nI0 = 0 NI LSET UP: L = 0.150 m 0 (600) (8.00 A) = 0.0402 T EXECUTE: B = (0.150 m) EVALUATE:The field near the center of the solenoid is independent of the radius of the solenoid, as long as the radius is muc
Dallas - PHYSICS - 1523
Solutions, Assignment 2429.6.IDENTIFY:Apply Eq.(29.4). I = E/R. SET UP: d B /dt = AdB/dt. EXECUTE:(a) E = Nd B d d = NA ( B ) = NA ( (0.012 T/s)t + (3.00 105 T/s 4 )t 4 ) dt dt dtE = NA ( (0.012 T/s) + (1.2 104 T/s 4 )t 3 ) = 0.0302 V + (3.02 104 V/s3 )
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 2529.15. IDENTIFY and SET UP:The field of the induced current is directed to oppose the change in flux. EXECUTE:(a) The field is into the page and is increasing so the flux is increasing. The field of the induced current is out of t
Dallas - PHYSICS - 1523
SOLUTIONS, ASSIGNMENT 2629.28. IDENTIFY:Use Eq.(29.10) to calculate the induced electric field E at a distance r from the center of the solenoid. Away from the ends of the solenoid, B = 0 nI inside and B = 0 outside. (a) SET UP:The end view of the soleno
Dallas - ECON - 2301
NationalIncomeAccountingCHAPTER5MeasuresofOutputNationalincomeaccountingreferstothemeasurementofaggregateeconomicactivity, particularlynationalincomeanditscomponents.1.GDPGrossdomesticproduct(GDP)isthetotaldollarvalueoffinaloutputproducedwithinanat
Dallas - ECON - 2301
Economics:TheCoreIssuesCHAPTER1EconomicsCoreIssuesEconomicsisthestudyofhowbesttoallocatescarceresourcesamongcompetinguses.WHATtoproducewithourlimitedresources. HOWtoproducethegoodsandservicesweselect. FORWHOMgoodsandservicesareproduced;thatis,who sho
Dallas - ECON - 2301
TheU.S.Economy: AGlobalViewCHAPTER2WhatAmericaProducesWithlessthan5percentoftheworldspopulation. and12percentoftheworldsarableland. theU.S.producesmorethan20percentoftheworldsoutput.LO1GDPComparisonsGrossDomesticProduct(GDP)isthetotalmarketvalueof
Dallas - ECON - 2301
ThePublicSectorCHAPTER4LessonsfromaMarketEconomyThemarketmechanismusesmarketpricesandsalestosignaldesiredoutputs(orresource allocations).Ideally,themarketmechanismshouldleadtoanoptimalmixofoutput.Anoptimalmixofoutputisthemostdesirablecombinationof
Dallas - ECON - 2301
UnemploymentCHAPTER6TheLaborForceThelaborforceincludesallpersonsoveragesixteenwhoareeitherworkingforpayoractivelyseeking paidemployment.Peoplewhoarenotemployedorarenotactivelyseekingworkarenotconsideredpartofthelabor force.TheLaborForceThelaborfor
Dallas - ECON - 2301
InflationCHAPTER7WhatIsInflation?Inflationisanincreaseintheaveragelevelofprices,notachangeinanyspecificprice.Theaveragepriceisdeterminedbyfindingtheaveragepriceofalloutput. Ariseintheaveragepriceiscalledinflation. Afallintheaveragepriceiscalleddef
Dallas - ECON - 2301
TheBusinessCycleCHAPTER8MacroeconomicsBusinesscyclesarealternatingperiodsofeconomicgrowthandcontraction.Macroeconomictheoriestrytoexplainthebusinesscycle,economicpoliciestrytocontrolit.StableorUnstable?Priorto1930s,macroeconomiststhoughttherecoul
Dallas - ECON - 2301
TheKeynesianCrossCHAPTER9APPENDIXTheKeynesianCrossTheKeynesiancrossfocusesontherelationshipoftotalspendingtothevalueofoutput.Itdoesntmakeanexplicitdistinctionbetweenpricelevelsandrealoutput.Aggregateexpendituresaretherateoftotalexpendituredesireda
Dallas - ECON - 2301
AggregateDemandCHAPTER9KeynesQuestions:Whatarethecomponentsofaggregatedemand? Whatdeterminesthelevelofspendingforeachcomponent?Willtherebeenoughdemandtomaintainfullemployment?MacroEquilibriumAggregatedemandandaggregatesupplyconfronteachotherinthe