Exam 2-solutions
9 Pages

Exam 2-solutions

Course Number: CH 302 52460, Spring 2010

College/University: University of Texas

Word Count: 2055

Rating:

Document Preview

Version 291 Exam 2 Holcombe (52460) This print-out should have 33 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. Some constants: Kw=1e-14; R=8.314 J/Kmol 001 10.0 points When dissolved in water, bases produce 1. salts. 2. H+ ions. 3. OH ions. correct 4. hydronium ions. 5. H3 O+ ions. Explanation: Bases produce hydroxide ions (OH ) in water; acids...

Unformatted Document Excerpt
Coursehero >> Texas >> University of Texas >> CH 302 52460

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

291 Version Exam 2 Holcombe (52460) This print-out should have 33 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. Some constants: Kw=1e-14; R=8.314 J/Kmol 001 10.0 points When dissolved in water, bases produce 1. salts. 2. H+ ions. 3. OH ions. correct 4. hydronium ions. 5. H3 O+ ions. Explanation: Bases produce hydroxide ions (OH ) in water; acids produce hydronium ions (H3 O+ ). 002 10.0 points A diprotic acid H2 A has values of Ka1 = 1.0 106 and Ka2 = 1.0 1010 . What is the [A2 ] in a 0.10 M solution of H2 A? 1. 1.0 1010 M correct 2. 3.2 106 M 3. 0.10 M 4. 0.20 M 5. 3.2 104 M Explanation: 003 10.0 points How many grams of HNO3 are needed to make 315 mL of a solution with a pH of 2.60? The molar mass of HNO3 is 63.02 g/mol. 1. 19.9 g 2. 0.158 g 3. 1.25 105 g 4. 0.0498 g correct 5. 0.502 g Explanation: pH = 2.6 MM = 63.02 g/mol 1 V = 315 mL = 0.315 L [H+ ] = 10pH = 102.6 = 0.00251189 Since HNO3 is a strong acid, One HNO3 one H+ , so (0.315 L) HNO3 (aq) H+ (aq) + NO (aq) . 3 [H+ ] = [HNO3 ] = 0.00251189 mol and 0.00251189 mol HNO3 1L = 0.000791244 mol HNO3 . Thus 63.02 g HNO3 (0.000791244 mol HNO3 ) 1 mol HNO3 = 0.0498642 g HNO3 004 10.0 points What would be the pH of a 1 M solution of Na2 HPO4 ? Assume H3 PO4 has a pKa1 of 2 and a pKa2 of 7 and a pKa3 of 13. 1. 10 correct 2. 13 3. 7.5 4. 4.5 5. 2 6. 7 Explanation: For a solution composed of a single amphoteric species (HPO4 2 ), pH = 0.5(pKa2 + pKa3 ) = 0.5(7 + 13) = 10 Version 291 Exam 2 Holcombe (52460) 005 10.0 points A solution containing an unspecied amount of HCl and ammonia (NH3 ) has a pH of 8.81 What is the ratio of NH3 to NH+ in the 4 solution? (For NH3 , Kb = 1.8 105 ) 1. 0.233 2. 0.359 correct 3. 2.06 4. cannot be determined 5. 0.485 6. 2.79 7. 5.6 1010 5. pH = 4.74 2 Explanation: [base] = 0.05 M As mentioned, this is a weak base, so use the equation to calculate weak base [OH ] concentration: [OH ] = = Kb Cb (6.6 109 ) (0.05) = 1.81659 105 After nding [OH ], you can nd pH using either method below: A) pOH = log 1.81659 105 = 4.74074 pH = 14 4.74074 = 9.25926 or B) Kw = [H+ ][OH ] = 1 1014 Kw [H+ ] = [OH ] 1 1014 = 5.50482 1010 = 5 1.81659 10 pH = log 5.50482 1010 = 9.25926 007 10.0 points What is the pH of a 0.020 M solution of hydrosulfuric acid, a diprotic acid? Ka1 = 1.1 107 Ka2 = 1.0 1014 1. 9.67 Explanation: Consider this equilibria... NH+ NH3 + H+ 4 Rearranging the equilibrium expression gives... Ka [NH3] = = ratio +] [H [NH4+] [H+] = 108.81 = 1.54882 109 M Ka = Kw /1.8 105 = 5.556 1010 5.556 1010 = 0.359 ratio = 1.54882 109 M Note that the same answer could be obtained by using the base equilibria and Kb 006 10.0 points You have a weak molecular base with Kb = 6.6 109 . What is the pH of a 0.0500 M solution of this weak base? 1. None of these 2. pH = 7.12 3. pH = 3.63 4. pH = 9.26 correct 2. 4.69 3. 3.65 4. 4.33 correct 5. 5.22 6. 7.84 7. 7.00 Version 291 Exam 2 Holcombe (52460) Explanation: Solve using ONLY the 1st ionization. So this works like any other monoprotic acid where the assumption [H+ ] = (Conc)(Ka1 ) is valid. 008 10.0 points The pH of a solution changes from 5.5 to 3.5. This indicates that the [OH ] of the solution has 1. increased by a factor of 100. 2. increased by a factor of 2. 3. decreased by a factor of 100. correct 4. decreased by a factor of 2. 5. decreased by 2 M. 6. increased by 2 M. Explanation: 009 10.0 points A solution has [H+ ] = 1.5 107 M. What is the [OH ] in this solution? 1. 6.7 107 M 2. 6.7 106 M 3. 6.7 108 M correct 4. None of these 5. 1.5 107 M 3 Calculate the [OH ] concentration in a 0.5 M solution of potassium uoride (KF). Ka for HF is 7.2 104 . 1. 3.6 1011 M 2. 0.5 M 3. 2.64 106 M correct 4. 6.94 1012 M 5. 6.0 106 M Explanation: 011 10.0 points The pH of 0.1 M (C3 H7 NH2 ) propylamine aqueous solution was measured to be 11.86. What is the value of pKb of propylamine? 1. 3.35 2. 2.14 3. 11.86 4. 3.25 correct 5. 0.11 6. 0.96 Explanation: M = 0. 1 M pH = 11.86 Analyzing the reaction with molarities, C3 H7 NH2 + H2 O C3 H7 NH+ + OH 3 0. 1 0 0 x x x 0. 1 x x x pOH = 14 11.86 = 2.14 . [C3 H7 NH+ ] = [OH ] = 10pOH 3 = 102.14 = 0.00724436 mol/L Explanation: [H+ ] = 1.5 107 M Kw = [H+ ][OH ] = 1.0 1014 Kw [OH ] = + [H ] 1.0 1014 = 6.7 108 M = 1.5 107 010 10.0 points Version 291 Exam 2 Holcombe (52460) The Kb is [C3 H7 NH+ ][OH ] 3 Kb = [C3 H7 NH2 ] (0.00724436)2 = 0.1 0.00724436 = 0.000565796 . and the pKb is pKb = log(0.000565796) = 3.24734 . 012 10.0 points Consider the fractional composition diagram for phosphoric acid. 1.0 Fractional Composition 0.8 0.6 0.4 0.2 2 4 6 8 10 12 14 4 Based on its dot structure, the best classication for O2 is as 1. an Arrhenius base. 2. an Arrhenius acid. 3. a Lewis base. correct 4. a Bronsted Lowry acid. 5. a Lewis acid. Explanation: The oxygen anion has a complete octet as its dot structure shows. Since it can only make available a share in an electron pair, it must be a Lewis base. 014 10.0 points A solution of 0.2 M boric acid is prepared as an eye wash. What is the approximate pH of this solution? For boric acid Ka = 7.2 1010 . 1. pH = 3 2. pH = 7 3. pH = 5 correct 4. pH = 4 5. pH = 6 Explanation: pH What is the approximate pH of a solution prepared by adding several grams of Na2 HPO4 to a few hundred mL of water? 1. 10 correct 2. 2 3. 12 4. 7 5. 5 Explanation: Na2 HPO4 is the salt of the monoprotic species which is the dominate species between pHs of 7.2 and 12.7 which is the orange or shortest dashed curve. The best estimate of the pH is the dead center of that range which is a pH of 10 which is the average of pK2 and pK3 for the acid. 013 10.0 points 015 10.0 points Would the value of Kw change if the temperature were raised from 25 C to 50 C? 1. Yes correct 2. No Explanation: 016 10.0 points If 17.6 g of HCl are used to produce a 14.5 L solution, what is the pH of the solution? 1. 11.2 Version 291 Exam 2 Holcombe (52460) 2. 3.01 3. 0.316 4. 1.48 correct 5. 2.54 Explanation: m = 17.6 g V = 14.5 L To nd the pH we need to calculate the concentration of H+ : 1 mol HCl ? M H = 17.6 g HCl 36.46 g + 1 1 mol H 1 mol HCl 14.5 L = 0.0333 M H+ + 5 A water solution of NaI will exhibit a pH value of 1. about 7. correct 2. less than 7. 3. zero. greater 4. than 7. Explanation: 019 10.0 points What is the concentration of SO2 in 2.0 M 4 H2 SO4 ? Ka1 is strong and Ka2 = 1.2 102 . 1. 1.2 102 M correct 2. 4.0 101 M 3. 2.0 101 M 4. 1.0 107 M 5. 4.0 102 M Explanation: 020 10.0 points Which of the following is a correct mass balance expression for the addition of H2 CO3 to water? 1. CH2 CO3 = [HCO ] + [CO2 ] 3 3 2. CH2 CO3 = [H2 CO3 ] + [HCO ] + [CO2 ] 3 3 correct 3. Kw = [H+ ] + [OH ] 4. [H+ ] = [HCO ] + [CO2 ] + [OH ] 3 3 Explanation: 021 10.0 points Consider the [H3 O+ ] in each of the following solutions. For which system is the percent dissociation to produce H3 O+ the greatest? Do not go through the calculations. pH = log[0.0333] = 1.48 017 10.0 points 3 A 1.0 10 M NH3 solution is prepared. What is the pH of the solution? 1. 3 or less 2. between 7 and 11 correct 3. 7 4. 11 or more 5. between 3 and 7 Explanation: NH3 is a weak base, and will not generate 100 percent OH ions. The solution would be more basic than a neutral solution, and so the pH should be greater than 7. The solution will be less basic than strong base solution of the same concentration, and so the pH should be less than 11 since a 1.0 103 M strong base solution would have a hydroxide ion concentration of 1.0 103 and a pH of 11. 018 10.0 points Version 291 Exam 2 Holcombe (52460) 1. 1.00 M NH3 , K = 1.8 105 2. 0.010 M HCN, K = 4.0 1010 3. 0.010 M H2 S, K1 = 1.0 10 4. 0.010 M (COOH)2 , correct 7 6 2. indicates an H+ concentration of 0.0176 M. 3. indicates an H+ concentration of 0.176 M. 4. is impossible because pH cannot be negative. 5. indicates an H+ concentration of 31.6 M. correct 6. indicates an H+ concentration of 0.0316 M. Explanation: [H+ ] = 10pH = 10(1.5) = 31.6228 M pH CAN be negative! 024 10.0 points Carbonic acid (H2 CO3 ) is a diprotic acid with Ka1 = 4.2 107 and Ka2 = 4.8 1011 . The ion product for water is Kw = 1.0 1014 . What is the [H3 O+ ] concentration in a saturated carbonic acid solution that is 0.037 molar? 1. 4.2 107 M 2. 3.7 1020 M 3. 6.5 104 M 4. 7.4 102 M 5. 1.2 104 M correct Explanation: 025 10.0 points The conjugate base of H2 SO4 is: 1. H2 O 2. H3 SO+ 4 3. H2 SO3 K1 = 5.9 102 Explanation: The general reaction for a weak acid is HA + H2 O H3 O+ + A [H3 O+ ][A ] . [HA] The acid for which Ka is the greatest will have the greatest percent dissociation. All of the given species are weak acids, with the exception of NH3 . Since NH3 is a weak base its value of [H3 O+ ] will be less than that of the acids. Ka = 022 10.0 points Which acid has the strongest conjugate base? 1. HBr 2. HI 3. HCl 4. HF correct Explanation: HBr, HCl and HI are strong acids which completely ionize in water so their conjugate base is a poor proton acceptor. HF is a weak acid which is only partially ionized in water. Its conjugate base F is better able to bond with a proton. 023 10.0 points Complete the following statement. A pH value of 1.5 1. indicates an H+ concentration of 0.0316 M. 5. 0.010 M H2 O2 , K = 2.4 1012 Version 291 Exam 2 Holcombe (52460) 4. SO2 4 8. CO2 ; CO2 3 3 7 5. OH 6. H3 O+ 7. HSO correct 4 Explanation: Remove one H+ ion from a species to nd its conjugate base. 026 10.0 points What would be the pH of a 109 M solution of HCl? 1. 6.954 2. 6.921 3. 6.876 4. 6.998 correct Explanation: For a dilute strong +2 + [H ] Ca[H ] Kw = 0 b b2 4ac + [H ] = x = 2a pH = 6.998 027 10.0 points The conjugate acid of HCO is ? 3 conjugate base of HCO is ? . 3 1. H+ ; OH 2. H2 CO3 ; CO2 correct 3 3. H2 CO3 ; H2 O 4. H+ ; CO2 3 5. CO2 ; H2 CO3 3 6. H2 CO3 ; H2 CO3 7. CO2 ; OH 3 acid, Explanation: To produce a conjugate acid, HCO must 3 be acting as a base. Therefore it is a proton acceptor forming H2 CO3 . To produce a conjugate base, it must be acting as an acid. Therefore it is a proton donator forming CO2 . 3 028 10.0 points Sodium uoride is added to pure water and stirred to dissolve. Compared to pure water, the new solution is 1. acidic pH 2. neutral pH 3. basic pH correct 4. More than one of these is true. 5. unchanged pH Explanation: Sodium uoride is a basic salt and therefore changes solutions to a more basic pH. 029 10.0 points Consider ve generic acids (HA, HB, HC, HD, and HE) that have the following ionization constants. and the Acid HA HB HC HD HE Ionization Constant Ka value 3.6 103 8.3 104 2.6 106 9.3 106 7.3 107 Which of the following anions will be the WEAKEST base? 1. B 2. A correct Version 291 Exam 2 Holcombe (52460) 3. E 4. C 5. D Explanation: The larger the Ka , the greater the dissociation and the stronger the acid. In general, a conjugate base is opposite in strength from its parent acid strength. HA is the strongest acid listed (largest Ka ), therefore A is the weakest base. 030 10.0 points Rank following acids from most to least acidic: NH+ Ka = 1.35 1010 4 N2 H+ Ka = 7.94 109 5 CH3 NH+ Ka = 2.34 1011 3 (CH3 )3 NH+ Ka = 1.8 1010 1. (CH3 )3 NH + 8 6. 103 M, NaOH. Explanation: HCl is the only strong acid so all the HCl present will produce H3 O+ . 103 M HCl has a higher concentration than 105 M HCl. 032 10.0 points What is the pH of a solution made by dissolving 0.100 mole of sodium acetate (NaCH3COO) in enough water to make one liter of solution? Ka for CH3 COOH is 5 1.80 10 . 1. 7.46 106 2. 1.82 106 3. 3.75 4. 5.13 5. 9.25 6. 1.80 106 7. 8.87 correct 8. 5.56 1011 9. 10.25 10. 5.56 1010 Explanation: 033 10.0 points A solution at a pH of 1.0 contains the weak acid HA and its conjugate base A . What percent of the acid is dissociated? (Ka = 106 and [HA] + [A ] = 103 M). 1. < 10% correct 2. 100% 3. between 10% and 90% 4. between 90% and 100% > CH3 NH+ > N2 H+ 3 5 > NH+ 4 > NH+ 4 + 2. CH3 NH+ > N2 H+ 3 5 > (CH3 )3 NH 3. N2 H+ >(CH3 )3 NH+ > NH+ > CH3 NH+ 5 4 3 correct 4. NH+ > (CH3 )3 NH+ > CH3 NH+ > N2 H+ 5 3 4 Explanation: Explanation: The value of Ka is directly proportional to the acidity (strength) of the acid. By ranking from the largest (7.94 109) to the smallest (2.34 1011 ) Ka, one is ranking from the most to least acidic. 031 10.0 points Select the solution with the lowest pH 1. 103 M, acetic acid. 2. 103 M, HCl. correct 3. 105 M, HCl. 4. 105 M, acetic acid. 5. 103 M, Ca(OH)2 . Version 291 Exam 2 Holcombe (52460) 5. Not enough information is given. Explanation: 9

Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

University of Texas - CH 302 - 52460
gonzales (pag757) Homework #1 Holcombe (52460) This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points What factor determines whether a reaction will be ex
University of Texas - CH 302 - 52460
gonzales (pag757) Homework #2 Holcombe (52460) This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points Consider two closed containers. Container X is a 2 L
University of Texas - CH 302 - 52460
gonzales (pag757) Homework #3 Holcombe (52460) This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points An equilibrium in which processes occur continuously
University of Texas - CH 302 - 52460
gonzales (pag757) Homework #4 Holcombe (52460) This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points For the heterogeneous reaction 2 MnO2 (s) 2 MnO(s) +
University of Texas - CH 302 - 52460
gonzales (pag757) Homework #5 Holcombe (52460) This print-out should have 25 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points Of the following, a solution with which pH would be
University of Texas - CH 302 - 52460
gonzales (pag757) Homework #6 Holcombe (52460) This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points What is the pH of a 0.13 M Ba(OH)2 aqueous solution?
University of Texas - CH 302 - 52460
gonzales (pag757) Homework #7 Holcombe (52460) This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points Consider a solution that is 0.10 M in a weak triprot
University of Texas - CH 302 - 52460
gonzales (pag757) Homework #8 Holcombe (52460) This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points Which of the following is NOT true for a solution bu
University of Texas - EE 312 - 16005
Assignment 1: Introduction to the LRC Lab, Visual Studio, and CEE312 The University of Texas at Austin Spring 2010 Assigned: Due: Value: Thursday, January 21st Thursday, January 28th , before midnight 20 points (for successfully submitting a correct prog
University of Texas - EE 312 - 16005
Assignment 2 Manipulating Numeric Data EE312 - The University of Texas at Austin Spring 2010 Assigned: Monday, Feb 1st Due: Thursday, Feb 11th, before midnight. Value: 20 points (18 for correctness and 2 for good style) File submitted: Submit (upload) the
University of Texas - EE 312 - 16005
Assignment3:FunwithPrimesEE312TheUniversityofTexasatAustinSpring2010 Assigned: Design Due: Program Due: Total Value: Friday, Feb 12th On Friday, Feb. 19th , at the beginning of your recitation Thursday, Feb. 25th , before 11:59PM 20 points total (see Del
University of Texas - EE 312 - 16005
Answers to Book Exercises Chapters 2-10, 22.3, 23.1-3 Here are the answers to exercises from the second edition of C Programming: A Modern Approach. These answers do not necessarily conform to the coding standards for this course. Note: Some of these exer
University of Texas - EE 312 - 16005
EE312 C Coding Standards 2010Writing code that is easy for others (or you later) to read is an important part of programming. Style entails a program's readability and logic structuring. Style is almost as important as correctness in programming. This is
University of Texas - EE 312 - 16005
Q0Q1Q2Q3Q4Q5Q6Q7Q8Exam 1EE 312 - University of Texas at Austin - Sample Your Name _Unique Section # [1 pt.] _ Test taking instructions. No calculators, laptops or other assisting devices are allowed. Write your answers on these sheets. You can u
University of Texas - EE 312 - 16005
Answers to Book Exercises Chapters 11-18, and 22 Here are the answers to exercises from the second edition of C Programming: A Modern Approach. These answers do not necessarily conform to the coding standards for this course. Note: Some of these exercises
University of Texas - EE 312 - 16005
IntroductionsEE312 Introduction to ProgrammingSpring 2010 Unique #s: 15920-16005 Herb Krasner Senior Lecturer in Software Engineering hkrasner@ece.utexas.edu Ofce: ENS 423 Ofce Hours: MWF, 9:55-10:55am, or by appointment The Teaching Team Instructor P
University of Texas - EE 312 - 16005
1/22/10 EE312 - Lecture 2 Announcements Meet with the TA at your recitation session today Go over surveys, discuss assignment 1, visit LRC TA office hour schedule will be posted on the BB this weekend starts next week in ENS 307 Assignment 1 is out, due
University of Texas - EE 312 - 16005
EE312 - Lecture 3 Announcements Read chapters 3 and 4 in the book Assignment 1 due on Thursday TA Office hours are posted on the BBBuilt-in Data Types in C A variable is a symbolic name for a type of value that can change as your program runs. It mu
University of Texas - EE 312 - 16005
1/27/10 EE312 - Lecture 4 Announcements Assignment 1 Due tomorrow Upload your .c file, attach the file, then submitInteger Literals These are numeric values that cannot be altered during program execution They may appear in one of three formats: dec
University of Texas - EE 312 - 16005
1/29/10 EE312 - Lecture 5 Announcements Assignment 2 out next week Monday Downloading a free IDE for Windows http:/www.microsoft.com/express/Downloads/#2008-Visual-CPP http:/www.dreamspark.comThe scanf Functionscanf ( Format string , list-of-variab
University of Texas - EE 312 - 16005
2/1/10 Lecture 6 Announcements Assignment 2 out this afternoon You will need to sketch out a high level algorithm so that you can see the necessary decision and iteration logic; go see a TA in lab hours or recitation if you need help getting startedco
University of Texas - EE 312 - 16005
2/3/10Announcements Lecture 7 Assignment 2, due next Thurs. questions? Tip:#include &lt;stdlib.h&gt; . system (cls); /* clear the screen */For loop The for statement has the form for ( expression1 ; expression2 ; expression3 ) statement The following code
University of Texas - EE 312 - 16005
Announcements Lecture 8 Assignment 2 Q&amp;A; due ThursdayChar data references Different computers may have different character sets. We will use ASCII standard Ascii character set see book Appendix E orhttp:/www.ascii.cl/ Topics for today Character da
University of Texas - EE 312 - 16005
Announcements Lecture 9 Assignment 2 - due Thursday - Q&amp;A Keep track of how many hours you spend on it Keep track of how many logic errors you have to fix (not syntax errors)Creating a Type Alias typedef lets you create an alias for a data type,e.g.:
University of Texas - EE 312 - 16005
Announcements - Lecture 10 Assignment 2 Q&amp;A due tomorrow Count the number of statements in your code and write that down too/* goal - find the lowest score in the exam1Scores array */ #define CLASS_SIZE 142 . int exam1Scores [CLASS_SIZE ], numberOfStud
University of Texas - EE 312 - 16005
Announcements - Lecture 11 Read Goto Considered Harmful goto statements are no longer allowed All programs can be implemented with only sequence, selection and iteration logic constructs Example in the book on pg. 114 is wrong!Book Example pg. 114 Pro
University of Texas - EE 312 - 16005
Announcements Lecture 12 Assignment 3 out today Designs due on Friday at the beginning of your recitation session Functional block diagram, algorithm, IPO diagram IPO diagram describes the inputs, outputs and general operations to be performed Functio
University of Texas - EE 312 - 16005
Announcements Lecture 13 Assignment 3 designs due Friday to your TA at beginning of recitation (not in lecture) IPO, functional block diagram, algorithmsrcTowers of Hanoi - 4 disc example aux dst Exam 1 on Friday Study tip: work the sample exam, sp
University of Texas - EE 312 - 16005
Announcements - Lecture 14 Exam 1 back High 100 Low 31.5 Median 87.5 Average 84.5 MIAs - 5 As 40% Bs 35% Cs 15% Ds 7% Fs 3% Curve - ? Regrades to me! Inputs Maximum # of the range Y/N to repeat the processAssn 3 Design - IPOProcess Find all primes up
University of Texas - EE 312 - 16005
Announcements - Lecture 15 Assignment 3 Program due tomorrow Write down: # statements, #hours, #logic errors Topics for today (Ch. 13)Exam Q0 ResultsAssignment 2 Data SLOCs Hrs. Defectshighs 257 lows med. 68 15020 1 550 0 4string -&gt; a series/sequen
University of Texas - EE 312 - 16005
Announcements - Lecture 16 Assignment 3 write down your stats SLOCs, hours, logic defects Lessons: start sooner, expect problemsPointers 101 Important and difficult subject in C Memory addresses and pointer variables Address of and indirection (conten
University of Texas - EE 312 - 16005
Announcements - Lecture 17 Assignment 4 out today Q&amp;A Lines of code counter Designs due in recitation Friday IPO, functional block diagram, algorithm (high level) Topics for today start File IO (rest of Chapter 22, minus 22.3) Files and streams Text
University of Texas - EE 312 - 16005
3/3/10Announcements - Lecture 18 Assignment 4 Designs due in Fridays recitation Q&amp;AYour SLOC Counter - IPOName of the file which contains the C program SLOC Counter Program Functions SLOC Count Report Topics for today (more Ch. 22) Formatted file I
University of Texas - EE 312 - 16005
Announcements Lecture 19 Assignment 4 Designs due today in recitation; Q&amp;A Topics for today (Read Ch. 16, and then 14-15 for next week) Finish file IO More on pointers Stacks and The system stackFile IO Reminders from Last TimeFormatted file IO functio
University of Texas - EE 312 - 16005
Announcements Lecture 20 Assignment 4 Q&amp;A; programs due before Thursday midnight Spring Break is next week no assignments Topics for today (Read Ch. 16, and then 14-15 for this week) Finish pointers Stacks and the system stack (not in book) structsProbl
University of Texas - EE 312 - 16005
Announcements Lecture 21 Friday recitations cancelled Assignment 4 Due tomorrow if you havent started yet, you probably wont finish Q&amp;AArrays of Structures#define CLASS_SIZE 142 struct Person_record cfw_ char firstName[32]; char lastName[32]; int age;
University of Texas - EE 312 - 16005
Announcements Lecture 22 No recitations today Assignment 4 write down your stats Assignment 5 comes out after spring break Topics for today - Ch. 14 Finish enums What the Preprocessor Does Its just a fancy text manipulatorenum Type An enumeration typ
University of Texas - EE 312 - 16005
Branching If, else switch Looping While, do while, for For building a menu you need both branching and looping Loop cfw_ print cfw_ Menu Options Scanf ( , i) Branching cfw_ cfw_ code1-EUR&gt;$ cfw_ code 2: $ to EUR Code 1 extract if(score&gt;=90) printf(A);
University of Texas - HIS 314K - 39271
February6,2010 WordCount:1204PaulGonzales HIS314KSession:39271 AnglosandMexicansintheStruggleforConquestConquest, political exclusivity, and the upheaval of prime racism and segregation through socialization created a society that could not function app
University of Texas - HIS 314K - 39271
Paul Gonzales H IS314K 39271 Beyond the Latino, World War I I Hero, The Social and Political Legacy of a Generation From the t i tle of the book, we can immediately determine the message of this novel; there were other heroes in WWI I besides the Caucasia
University of Texas - HIS 314K - 39271
Notes January 24, 2010The Alamo is the purported origin of Texas society, claiming its past is a principal means of establishing groups and individuals as being heirs to the present. The main role of the Hispanic is that of the executioner.Alamo myth se
University of Texas - HIS 314K - 39271
Repatr iation 1929- 1939 economically motivated Johnson-Reed Act , 1924 Also known as National Originals Act Deportation something that happens at the federal level vs. state or local, usually involves crime, and often forbids return, if immigrant were to
University of Texas - HIS 314K - 39271
The Frescoes of Diego Rivera Michael Camerini 1986 Was a kind of national monument by the time he painted the Frescoes It was attacked and mutilated by protestors He was a young painter in Paris and the Mexican revolution was coming to a close Full of ene
University of Texas - BIO 206L - 49540
1.4 Group Indiv. Weights (g) Mean Weight (g) 1 58.44 58.18 57.57 58.29 58.12 2 58.95 59.01 58.85 59.45 59.07 3 59.13 59.29 59.64 59.78 59.46 3 58.91 57.32 58.43 58.34 58.25 5 58.64 58.71 58.14 58.41 58.48 6 59.12 59.40 59.36 59.07 59.241.5 Group Indiv. W
University of Texas - BIO 206L - 49540
Paul Gonzales Lab Session: 49540 BIO206L Lab 2 1) a) I t has a built in illuminator b) Binocular microscope c) Adjustments of the field diaphragm allow more or less of the light passing t hrough the organism to show. d) By adjusting the aperture diaphragm
University of Texas - BIO 206L - 49540
Lab 2 Paul Gonzales BIO206L Session 49540
University of Texas - BIO 206L - 49540
February 12, 2010Paul Gonzales BIO206L Session: 49540Lab 4 1) Agarose gel electrophoresis works by separating molecules of DNA by size and charge. An electric field is used to separate positive charged molecules (cations) and negative charged molecules
University of Texas - BIO 206L - 49540
Paul Gonzales BIO 206L Session: 49540 Lab 5 1) Use of the BLAST (Basic Local Alignment Search Tool) was used to search for protein sequences and nucleotide sequences of various organisms. First we went to the homepage for BLAST and you either choose prote
University of Texas - BIO 206L - 49540
Paul Gonzales BIO 206L Lab 6 1)After the addition of sperm it took about 3-5 minutes for the fertilization membrane to form. It took about an hour after fertilization for cleavage to occur. 2) First the sea urchin egg and sperm meet and form a zygote, an
University of Texas - BIO 206L - 49540
Paul Gonzales BIO206L Lab 7 1. a) Chelipeds-first pair of walking legs that has large pincers that are used for grasping and tearing food and for defense b) Walking legs- used for walking, food gathering, and moving water over the gills c) Maxillapeds-man
University of Texas - BIO 206L - 49540
J anuary 24, 2010Paul Gonzales Pag757 BIO206L Session #495401) Mean the average or center of a set of data. You can predict future results as to where values may end up in a cluster of values. Standard Deviation a measure of the spread of data in relati
University of Texas - BIO 206L - 49540
1.3Data graduatedcylinder 57.41g ErlenmeyerFlask 51.38g Beaker 48.95g 1.4Data 58.44g 58.18g 57.57g 58.29g 1.5Data 4.03g 4.07g 3.93g 3.93g 58.44mL 58.18mL 57.57mL 58.29mL 4.03mL 4.07mL 3.93mL 3.93mL .26g .05g 0.01g X50mL 3.03g1.6Data 1001000microL 20200mi
University of Texas - BIO 206L - 49540
J anuary 26, 2010Paul Gonzales Lab Session: 49540 Bio206L Total Image M agnification (with 10X ocular) 40X 100X 400X 1000X2.1 Objective M agnification 4X objective 10X objective 40X objective 100X objective Numerical A perture (NA) .1 .25 .65 1.25 Resol
University of Texas - BIO 206L - 49540
3.1(100X objective 10X = 1000X mag.) (100X objective 10X = 1000X mag.) Red Blood Cell White Blood Cell Diameter: Diameter: There are about 40 red blood cells for each white blood cell present in a sample of blood. 3.2 Diatom 1: long and skinny Diatom 2:c
University of Texas - BIO 206L - 49540
February 4, 2010Paul Gonzales BIO206L Session 49540Lab 3 Analysis 1) Only the 100X objective requires the use of immersion oil because as you increase the objective size, the resolution and clarity of the image seen becomes less and less, so the oil ser
University of Texas - BIO 206L - 49540
3.7 3 3 3 3.5 3.4 3.62.91 3.21 3.21 3.21 3 3.04 2.96rithmMolecularWeightFragmentsvs.MigrationDistance3.25 3.2 3.15 3.1 3.05 logDNAMarkerSizes(bp) 3 2.95 2.9 2.85 2.8 2.75 2.8 3 3.2 3.4 3.6 3.8 f(x) = -0.42x + 4.47 R = 1MigrationDistance(cm)
Binghamton - BIOL - 118
Bio 118 1/25/10 Chapter 1: Biology and the tree of life Two great ideas that revolutionized science The cell theory The theory of evolution by natural selection Theory An explanation for a very general class of phenomenon or observations Theories are base
UCSD - ECON - 111
Tao notes:Coherence of principles Go with the flow man Dont over govern Laozi's writings on how a ruler should govern their kingdom wiki Ways of the people wiki After all ambition and action had not solved political and social problemsThe origins The ph
Keller Graduate School of Management - AC - 553
Yazan Herbawi AC553 Assignment Week 1 Chapter 3 Problem 33: a. b. c. d. Problem 36: 500,000 159,950 = 340,050 * 3% = 10,201.5 * 1/3 = 3,400.5 Deductions = 20,000 3,400.5 = 16,599.5 Chapter 13 Problem 55: 2006: 25% * 25,000 = 6,250 2007: 27% * 80,000 = 21,
Keller Graduate School of Management - AC - 553
AC553 Week 2 Assignment Yazan Herbawi Chapter 4 Problem 25: Regardless of the period the payment covers, it is recognized as income by the taxpayer upon receipt. However, the security deposit would be excluded from income until Billy actually forfeits all
Keller Graduate School of Management - AC - 553
AC553 Week 3 Yazan Herbawi Chapter 7 Question 7: Active income is income derived from the main course of business or trade, i.e. the taxpayers full-time job or main means of generating income. Passive income on the other hand, is income derived from passi