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BIOL2609_L5_2007

Course: DEB BIOL2609, Spring 2010
School: HKU
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2007 ECOL Lecture 6 Darwinism and DNA What is a species? A species is an actually or potentially interbreeding population that does not interbreed with other such populations when there is opportunity to do so It has been proposed that a genome difference of 2% between individuals is the limit for reproductive compatibility Gene trees and species trees are not the same Morphological species are based upon...

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2007 ECOL Lecture 6 Darwinism and DNA What is a species? A species is an actually or potentially interbreeding population that does not interbreed with other such populations when there is opportunity to do so It has been proposed that a genome difference of 2% between individuals is the limit for reproductive compatibility Gene trees and species trees are not the same Morphological species are based upon phenotypic characters All taxonomic levels above a species are arbitrary Scientists variously try and group together (lump) or separate (split) species into genus, family, order etc Phylogenetic species are based upon DNA evidence for evolutionary history These are also subject to arbitrary judgements including: Back mutation, gene transfer, variable rates of evolution Choice of target gene(s) How phylogenies are constructed Phylogenetic and Phenotypic trees are not the same Pisces Mammalia How do new species arise? Speciation Subspecies P Species A Race X divergence Race Y Subspecies Q Species C Species B Darwin visited the remote Galapagos Islands in 1835 aboard HMS Beagle He used observations of 13 endemic finch species to illustrate his theory of natural selection Darwins 1859 theory of evolution by natural selection Individuals within a species are variable Some of these variations are passed on to offspring In every generation, more offspring are produced than survive Survival and reproduction are not random the individuals that survive and go on to reproduce, or reproduce the most, are those with the most favourable variations They are naturally selected! Natural selection is NOT evolution It is just one type of evolutionary mechanism As it was the first to be discovered it is often wrongly used to describe evolution as a whole An analogy is the way some people describe a vacuum cleaner as a Hoover or a blender as a Kenwood after the first manufacturer Evolution can be viewed as a two-stage process: Mutation creates hereditary variation Natural selection, genetic drift and gene flow affect the way these variations are passed on to offspring Natural selection Sometimes called adaptive evolution its all about fitness Fitness is a measure of reproductive success Those individuals who create the largest number of mature offspring are the fittest Types of natural selection: Survival (or mortality) selection Mating (sexual) selection Family size (fecundity) selection Heritability Neutral trait Environmental factors Advantageous gene How does selection affect populations? Stabilizing selection Natural selection often works to weed out individuals at both extremes of a range of phenotypes Results in the reproductive success of those near the mean This maintains the status quo It is not always obvious why both extremes should be disadvantaged! perhaps sexual selection or liability to predation is at work In any case, stabilizing selection is common Directional selection Here individuals displaying one extreme of phenotype are advantaged Darwins finches again provide an an example! During a drought in the 1970s few seeds were available to ground finches Only larger tough seeds survived Only finches with larger beaks and bodies could eat these After the drought average body and beak size of offspring remained large = directional selection beak and body size Another famous example is that of the peppered moth that experienced severe directional selection for colour during the Industrial revolution in England in the 19th Century By 1849 black moths formed 90% of the population Disruptive selection Here individuals at both extremes of phenotype are advantaged Eg: Plants growing on toxic soil often develop resistance but lose their ability to compete on clean soil with the wild type This can lead to split gene pools Genetic drift Sometimes called neutral evolution An allele may increase or decrease in frequency simply through chance In the short term allele frequencies would increase/decrease at random creating a high level of polymorphism But the long term effect of genetic drift is a loss in diversity as alleles are lost or fixed such that they are the only variant This is genetic drift and it is particularly strong in: Small populations When the gene is neutral (neither helpful nor deleterious) At any point in time, many genes are on their way to loss/fixation Frequency Time Eventually the entire population may become homozygous for the allele (it becomes fixed) Or equally likely the allele may disappear Before either of these occurs the allele represents a polymorphism So at any given time there are numerous alleles on their way to loss or fixation, not yet represented in all individuals hence high polymorphism! Polymorphism can be reduced in a population by: Founder effect (single gravid female colonizing a new area) Bottleneck phenomenon (severe reduction in population size) Example: Cheetahs seem to have passed through a historical period of small population size with its accompanying genetic drift Examination of 52 different gene loci has failed to reveal any polymorphisms These animals are homozygous at all 52 loci This lack of genetic variability is so profound that cheetahs will accept skin grafts from each other just as identical twins! Must get a skin graft for this cut on my paw! Balanced polymorphism can also occur Example: In parts of Africa where malaria is caused by Plasmodium falciparum The allele for sickle-cell hemoglobin is also common Heterozygous children who inherit one gene for the normal beta chain of hemoglobin and one sickle gene are more likely to survive that either homozygote Homozygous sickle allele children die young from sickle-cell disease Homozygous normal beta chain children are far more susceptible to illness and death from malaria The main result of genetic drift is a loss in genetic variation With every generation there will be an allele that has become rare by chance that is lost when it is not passed on to the next generation The smaller the population the greater the effect Genetic drift also results in greater genetic difference between populations Since different alleles become fixed by chance in each population Genetic drift affects how a population evolves by natural selection Genetic drift tends to make natural selection less likely It can also counteract the effects of natural selection It makes all individuals genetically more similar It can cause alleles that lead to low fitness by chance So it is often assumed that small populations (for example) have lower levels of adaptation than large populations Other evolutionary mechanisms Gene flow Caused by individuals moving between populations Increased genetic diversity within a population since new alleles are introduced to the gene pool But it also makes populations genetically more similar because of this (introgression) The wolf gray and the coyote Phylogeny of mtDNA genotypes in gray wolves and coyotes based on RFLP data (W = wolf genotype, C = coyote genotype, * = gray wolf genotype identical or very similar to coyote) Hybrids are red wolves But we have also observed that evolution appears not to occur in a smooth fashion over time Remember the Cambrian explosion! Stephen J Gould (1941-2002) proposed a theory to explain this: Punctuated Equilibrium Basically he suggests that when a population finds itself isolated or in new environmental conditions, an initial rapid period of evolution will be followed by a period where individuals vary little from their ancestors This is in contrast to the more traditional view that changes occur gradually Evidence for this: Fossil records seem to show (in some cases) sudden changes between types of adaptation Gould suggests that the absence of transitional species is evidence for punctuated equilibrium Whales are a good example of transitional species - 4 legged land mammals that returned to the oceans, visible in redundant leg bones in fins He also argues that the transition to say have woings is not a single step There would have to be intermediates with 5%, 20%, 60% of a wing for example - but that this appendage would be no use So where is the natural selection for these intermediate stages? So how do these evolutionary factors affect the genetics of natural populations? Allopatric Speciation This is basically the role of isolation Allopatry = other country Populations begin to diverge when gene flow between them is restricted It is no coincidence that races and subspecies of an organism almost never occur in the same location Geographical barrier to movement of breeding individuals - and therefore gene transfer Darwins finches are a good illustration of allopatric speciation The ancestral species arrived in the Galapagos several million years ago It found no predators and few competitors Proximity between islands allowed migration But was an effective barrier to interbreeding In isolation changes to the gene pool (genetic diversity of a population) occur via Natural selection Genetic drift Founder effect (in this case) Sometimes a change in only one or a few loci can give rise to sufficient change for a new race/subspecies If subspecies are reunited in the same location it is possible to resolve their status If they reunite but fail to resume breeding then they are separate subspecies Eg: C.pauper is found only on Floreana island, where it shares territory with the C.psittacula found on all central Galapagos islands Isolating mechanisms that prevent subspecies interbreeding when they are reunited can be: Prezygotic Factors relating to phenotype prevent mating Eg: beak size (in mate selection), behaviour Postzygotic Mating does occur but offspring are not viable Eg: sterile offspring (mules) The opposite scenario is where two subspecies reunite and interbreed to create a new hybrid species (hybridization) This is particularly common in flowering plants Eg: genetic recombination of parental genomes in the sunflower species H.annulus and H.petiolarus produced three hybrid species that grow in conditions distinct from either original species and cannot reproduce with wild types Sometimes a reunion creates intense competition and this increases the rate of speciation One species is eliminated or character displacement occurs to lessen competition Eg: insectivorous C.psittacula and C.pauper have similar beak size as they eat similar prey but on Florean island P.psittacula has evolved a larger beak so the two species do not compete for food When a number of diverse species form from a single ancestor species it is termed adaptive radiation A more recent example demonstrated this phenomenon at the genetic level in the house mouse The island of Madeira off the northwest African coast supports 6 distinct subspecies of house mouse isolated in different valleys They have different karyotypes (chromosomal complements) Whilst there appear to be no prezygotic barriers to mating, this would prevent offspring arising between subspecies Sympatric Speciation Sympatric speciation refers to the formation of two new species from a single ancestral species all occupying the same geographic location Some evolutionary biologists do not believe this occurs! They feel that interbreeding would soon eliminate any genetic differences that might appear But there is strong (but indirect) evidence that sympatric speciation does occur Mechanisms: Disruptive selection favours individuals at extremes of an expressed trait, so intermediate phenotypes are discriminated against Assortative mating individuals prefer mates similar to themselves, and so mating with wild type prevented Two different species of three-spined sticklebacks inhabit five lakes in BC Canada Large benthic species with a large mouth that feeds on large prey in the littoral zone A smaller limnetic species with a smaller mouth that feeds on the small plankton in open water Each lake was colonized by a single ancestor The two species in each lake are genetically more closely related to each other than they are to any of the species in other lakes But the two species in each lake are reproductively isolated neither mates with the other Aquarium tests showed that The benthic species of one lake will spawn with the benthic species of another lake Even though they are less related to them than their limnetic cousins! Parapatric speciation This is another possible way for new species to arise in the absence of geographical barriers Again indirect evidence only Where a population ranges over a vast area with geographical gradients Individuals can disperse over a relatively small part of this area due to distance Genetic isolation arises simply from the great distance separating subpopulations This has been proposed to explain the enormous diversity in the Amazonian basin Ecological speciation Level of reproductive isolation 0% Allopatric phase Speciation occurs as a by-product of adaptation to alternative environments 100% Sympatric phase Speciation occurs through reinforcement, due to pre-mating isolation caused by low fitness of hybrids Adaptation to specific habitats: Niche-variation model predicts specialized organisms in a narrowly-defined niche will exhibit low genetic variability Fine-coarse grain model predicts fine grained environments (seasonal variation but predictable over time) will support organisms of lower heterozygosity than coarse-grained (vary randomly between generations) Indeed, low levels of heterozygosity in fossil animals such as the American alligator (Alligator mississippiensis) may reflect their stable environment over time Directed Reading Evolution, S.C. Stearns & R.H Hoekstra, Oxford University Press (Ch2 & 3) Main Library call number 576.S79
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80. (a) Using Eq. 7-32, the work becomes W = 2 x2 x3 (SI units understood). The plot is shown below:9(b) We see from the graph that its peak value occurs at x = 3.00 m. This can be verified by taking the derivative of W and setting equal to zero, or sim
The Petroleum Institute - PHYSICS - 191262
51. (a) The objects displacement is d = d f di = (8.00 m) + (6.00 m) + (2.00 m) k . i j Thus, Eq. 7-8 gives W = F d = (3.00 N)(8.00 m) + (7.00 N)(6.00 m) + (7.00 N)(2.00 m) = 32.0 J. (b) The average power is given by Eq. 7-42: Pavg = W 32.0 = = 8.00 W. t
The Petroleum Institute - PHYSICS - 191262
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The Petroleum Institute - PHYSICS - 191262
53. (a) We set up the ratio50 km E = 1 km 1 megaton and find E = 503 1 105 megatons of TNT.FG HIJ K1/ 3(b) We note that 15 kilotons is equivalent to 0.015 megatons. Dividing the result from part (a) by 0.013 yields about ten million bombs.
The Petroleum Institute - PHYSICS - 191262
54. (a) The compression of the spring is d = 0.12 m. The work done by the force of gravity (acting on the block) is, by Eq. 7-12, W1 = mgd = (0.25 kg) 9.8 m / s2 (0.12 m) = 0.29 J. (b) The work done by the spring is, by Eq. 7-26, 1 1 W2 = kd 2 = (250 N /
The Petroleum Institute - PHYSICS - 191262
55. One approach is to assume a path from ri to rf and do the line-integral accordingly. Another approach is to simply use Eq. 7-36, which we demonstrate: W=xf xiFx dx +yf yiFy dy =4 2(2x)dx +3 3(3) dywith SI units understood. Thus, we obtain W =
The Petroleum Institute - PHYSICS - 191262
56. (a) The force of the worker on the crate is constant, so the work it does is given by WF = F d = Fd cos , where F is the force, d is the displacement of the crate, and is the angle between the force and the displacement. Here F = 210 N, d = 3.0 m, and
The Petroleum Institute - PHYSICS - 191262
57. There is no acceleration, so the lifting force is equal to the weight of the object. We note that the persons pull F is equal (in magnitude) to the tension in the cord. (a) As indicated in the hint, tension contributes twice to the lifting of the cani
The Petroleum Institute - PHYSICS - 191262
58. With SI units understood, Eq. 7-8 leads to W = (4.0)(3.0) c(2.0) = 12 2c. (a) If W = 0, then c = 6.0 N. (b) If W = 17 J, then c = 2.5 N. (c) If W = 18 J, then c = 15 N.
The Petroleum Institute - PHYSICS - 191262
59. Using Eq. 7-8, we find W = F d = ( F cos sin (x + y = Fx cos + Fy sin i+F j) i j) where x = 2.0 m, y = 4.0 m, F = 10 N, and = 150 . Thus, we obtain W = 37 J. Note that the given mass value (2.0 kg) is not used in the computation.
The Petroleum Institute - PHYSICS - 191262
60. The acceleration is constant, so we may use the equations in Table 2-1. We choose the direction of motion as +x and note that the displacement is the same as the distance traveled, in this problem. We designate the force (assumed singular) along the x
The Petroleum Institute - PHYSICS - 191262
61. The total weight is (100)(660 N) = 6.60 104 N, and the words raises at constant speed imply zero acceleration, so the lift-force is equal to the total weight. Thus P = Fv = (6.60 104)(150 m/60.0 s) = 1.65 105 W.
The Petroleum Institute - PHYSICS - 191262
62. (a) The force F of the incline is a combination of normal and friction force which is serving to cancel the tendency of the box to fall downward (due to its 19.6 N weight). Thus, F = mg upward. In this part of the problem, the angle between the belt a
The Petroleum Institute - PHYSICS - 191262
63. (a) In 10 min the cart moves d = 6.0 so that Eq. 7-7 yields W = Fdcos = (40 lb)(5280 ft) cos 30 = 1.8 105 ft lb. (b) The average power is given by Eq. 7-42, and the conversion to horsepower (hp) can be found on the inside back cover. We note that 10 m
The Petroleum Institute - PHYSICS - 191262
64. Using Eq. 7-7, we have W = Fd cos = 1504 J . Then, by the work-kinetic energy theorem, we find the kinetic energy Kf = Ki + W = 0 + 1504 J. The answer is therefore 1 .5 kJ .
The Petroleum Institute - PHYSICS - 191262
65. (a) To hold the crate at equilibrium in the final situation, F must have the same magnitude as the horizontal component of the ropes tension T sin , where is the angle between the rope (in the final position) and vertical: = sin 1FG 4.00IJ = 19.5 .
The Petroleum Institute - PHYSICS - 191262
66. From Eq. 7-32, we see that the area in the graph is equivalent to the work done. We 1 find the area in terms of rectangular [length width] and triangular [ 2 base height] areas and use the work-kinetic energy theorem appropriately. The initial point i
The Petroleum Institute - PHYSICS - 191262
67. (a) Noting that the x component of the third force is F3x = (4.00 N)cos(60), we apply Eq. 7-8 to the problem: W = [5.00 N 1.00 N + (4.00 N)cos 60](0.20 m) = 1.20 J. (b) Eq. 7-10 (along with Eq. 7-1) then yields v = 2W/m = 1.10 m/s.
The Petroleum Institute - PHYSICS - 191262
68. (a) In the work-kinetic energy theorem, we include both the work due to an applied force Wa and work done by gravity Wg in order to find the latter quantity. K = Wa + Wg leading to Wg = 2.1 102 J . (b) The value of Wg obtained in part (a) still applie
The Petroleum Institute - PHYSICS - 191262
69. (a) Eq. 7-6 gives Wa = Fd = (209 N)(1.50 m) 314 J. (b) Eq. 7-12 leads to Wg = (25.0 kg)(9.80 m/s2)(1.50 m)cos(115) 155 J. (c) The angle between the normal force and the direction of motion remains 90 at all times, so the work it does is zero. (d) The
The Petroleum Institute - PHYSICS - 191262
70. After converting the speed to meters-per-second, we find K = 2 mv2 = 667 kJ.1
The Petroleum Institute - PHYSICS - 191262
71. (a) Hookes law and the work done by a spring is discussed in the chapter. Taking absolute values, and writing that law in terms of differences F and x , we analyze the first two pictures as follows: | F | = k | x| 240 N 110 N = k (60 mm 40 mm) which y
The Petroleum Institute - PHYSICS - 191262
72. (a) Using Eq. 7-8 and SI units, we find W = F d = (2 4 (8 + c = 16 4c i j) i j) which, if equal zero, implies c = 16/4 = 4 m. (b) If W > 0 then 16 > 4c, which implies c < 4 m. (c) If W < 0 then 16 < 4c, which implies c > 4 m.
The Petroleum Institute - PHYSICS - 191262
73. A convenient approach is provided by Eq. 7-48. P = F v = (1800 kg + 4500 kg)(9.8 m/s2)(3.80 m/s) = 235 kW. Note that we have set the applied force equal to the weight in order to maintain constant velocity (zero acceleration).
The Petroleum Institute - PHYSICS - 191262
74. (a) The component of the force of gravity exerted on the ice block (of mass m) along the incline is mg sin , where = sin 1 0.91 15 gives the angle of inclination for the . inclined plane. Since the ice block slides down with uniform velocity, the work
The Petroleum Institute - PHYSICS - 191262
75. (a) The plot of the function (with SI units understood) is shown below.Estimating the area under the curve allows for a range of answers. Estimates from 11 J to 14 J are typical. (b) Evaluating the work analytically (using Eq. 7-32), we have W=2 01
The Petroleum Institute - PHYSICS - 191262
76. (a) Eq. 7-10 (along with Eq. 7-1 and Eq. 7-7) leads to vf = (2 m F cos )1/2= (cos )1/2, where we have substituted F = 2.0 N, m = 4.0 kg and d = 1.0 m. (b) With vi = 1, those same steps lead to vf = (1 + cos )1/2. (c) Replacing with 180 , and still usi
The Petroleum Institute - PHYSICS - 191262
which (by taking two derivatives) we find the acceleration to be a = 0.20 m/s2. The (constant) force is therefore F = ma = 0.40 N, with a corresponding work given by W = 2 Fx = 50 t(t 10). It also follows from the x expression that vo = 1.0 m/s. This mean
The Petroleum Institute - PHYSICS - 191262
78. The problem indicates that SI units are understood, so the result (of Eq. 7-23) is in Joules. Done numerically, using features available on many modern calculators, the result is roughly 0.47 J. For the interested student it might be worthwhile to quo
The Petroleum Institute - PHYSICS - 191262
79. (a) To estimate the area under the curve between x = 1 m and x = 3 m (which should yield the value for the work done), one can try counting squares (or half-squares or thirds of squares) between the curve and the axis. Estimates between 5 J and 8 J ar
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/ d d d d d d d d d dWWWdddddddddd W WW//h/hWapplyFactorToTextSize, since there only exist one big nested if-statement instead of many if statements. The choice for paths are limited, thus to cover ADC, AUC and ADUPC are simple(because you cant ha
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