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Course: CHEM chem 152, Spring 2010
School: Arizona
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7 How Unit do we analyze a complex chemical system? Through this course, we have learned to use thermodynamic and kinetic properties at the macroscopic level, and electronic and steric factors Chemistry XXI at the submicroscopic scale to predict and control chemical reactions. Can you apply what you have learned to analyze a relevant complex system? Unit 7 How do we analyze a complex chemical system The central...

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7 How Unit do we analyze a complex chemical system? Through this course, we have learned to use thermodynamic and kinetic properties at the macroscopic level, and electronic and steric factors Chemistry XXI at the submicroscopic scale to predict and control chemical reactions. Can you apply what you have learned to analyze a relevant complex system? Unit 7 How do we analyze a complex chemical system The central goal of this unit is to apply and extend central concepts and ideas discussed in this course to the analysis of a complex chemical system. M1. Tracking Electron Transfer Detect electron transfer among reacting species in a system. Analyze electron sharing among . reacting species in a system. Analyze processes occurring simultaneously in a system. Chemistry XXI M2. Detecting Electron Sharing M3. Analyzing Coupled Processes Context To illustrate the power of the concepts, ideas, and ways of thinking discussed in the course, we will focus our attention on understanding the causes and effects of water acidification in our environment. 2 2 3 NO (g) + O (g) NO(g) + O (g) 2 3 CO (g) + H O(l) H CO (aq) 323 + 32 Chemistry XXI CO (s) + H O (aq) HCO (aq) + H O(l) 2 2 8 18 C(s) 2+ O (g) CO (g) 2 2 C H (l) + 12.5O (g) 8CO (g) + 9H O(g) In which ways can we use what we have learned to help us predict and control water acidification in our planet? Why do we care? The Problem Many complex systems of interest, such as our body or our planet, are made of hundreds of substances in constant interaction. The central question is how to apply chemical concepts, ideas, and ways of thinking to predict and control relevant processes: Outcomes Chemistry XXI Mechanism Directionality Extent Unit 7 How do we analyze a complex chemical system? Module 1: Tracking Electron Transfer Central goal: To analyze charge distribution in chemical compounds to detect transfer of electron density among reacting species. Chemistry XXI The Challenge Transformation How do I change it? We live in a complex environment made of hundreds of different substances in constant chemical interaction. Some of these interactions are crucial for the survival of life on Earth; others threaten several ecosystems. How can we analyze the types of chemical processes in which these substances are involved? Chemistry XXI Substances To face this challenge we need to analyze: a) the chemical nature of the substances that comprise the system; Chemistry XXI For example, identifying whether the substances are molecular or ionic is very useful in predicting their physical and chemical properties. Lets Think NO Chemistry XXI This is a list of substances involved in or affected by water acidification in our planet. Classify them as molecular or ionic. The Substances Ionic: Properties determined by the charge and size of the ions in the ionic network. Molecular: Chemistry XXI Properties determined by their molecular structure and charge distribution. Substances and Reactions In the analysis of complex chemical systems we also need to understand: a) the chemical nature of the substances that comprise the system; b) the characteristics of the chemical reactions in which they participate. Again, analysis of structure and charge distribution in reactants and products is crucial to make predictions about the types of processes that may occur. Chemistry XXI The Reactions For example, this set of interrelated chemical processes lead to water acidification in our planet: Chemistry XXI Acid Formation and Dissolution Acid Neutralization How do we differentiate these processes? Chemical Reactions Most chemical reactions are driven by the interaction between positive and negative charge centers on different particles. Thus, a chemical reaction tends to result in the transfer or redistribution of charged particles: Electrons Chemistry XXI Ions + - - + among the reacting species. How can we decide what is actually happening? Focus on Structure To distinguish types of reactions and make predictions about reactivity we need to have a good idea of the structural features of reactants and products. Lets consider one of the triggering reactions for water acidification: Chemistry XXI Lets think! Build the Lewis structure each substance. Predict their molecular geometry, and their bond and molecular polarity. Focus on Structure Chemistry XXI We can gain insights about chemical reactions by analyzing the changes they induce in the electron density around each atom. Charge Transfer Combustion reactions belong to an important type of chemical processes characterized by the transfer of electron density from one atom to another. Chemistry XXI C goes from having - to + (loses electron density). O goes from neutral to - (gains electron density). How can we better characterize this charge transfer? Oxidation Number The extent to which a reaction leads to electron density transfer can be assessed by analyzing changes in the oxidation number (or state) each of atom. Chemistry XXI The oxidation number is defined as the partial charge that an atom in a molecule would have if all of the bonding electrons were assigned to the most electronegative atom in the bond (molecule seen as fully ionic). H+ H+ -4 H+ H+ C Oxidation Number How do we determine the oxidation number? Consider this distribution of If the bonding electrons are assigned to the most electronegative atom: Chemistry XXI Central Question: How does these numbers compare with what they would have in their elemental form? Oxidation Number To calculate the oxidation number (ON) we compare the number of valence electron each atom has with those that it would have in its elemental form: FC(O) = 6 8 = -2 Chemistry XXI FC(C) = 4 0 = +4 Notice that ON = charge of molecule We say carbon in the molecule is in a highly oxidized state (largest positive ON), while oxygen is in a highly reduced state (largest negative ON). Lets Think + + + + Chemistry XXI Redox Reactions Combustion reactions are typical examples of oxidation-reduction (redox) reactions in which the oxidation number of the atoms involved changes, signaling a transfer of electron density. Assigning oxidation numbers is useful in: Chemistry XXI Identifying electron-rich and electron-poor centers in molecules; Tracking electron transfer or redistribution during a chemical reaction; Making predictions about reaction directionality. Redox Reactions In general, we may expect that compounds with highly electronegative atoms in high oxidation states ( ) will be good oxidizing agents 0 (they can oxidize other substances). 0 0 Chemistry XXI On the other hand, compounds with weakly eletronegative atoms in low oxidation states ( ) 0 will be good reducing agents (they can reduce other substances). +1 -4 + Hydrocarbons are good reducing agents. G < 0 Favored Processes Simple Rules The assignation of the oxidation numbers of atoms in chemical compounds can be greatly facilitated by applying these basic rules: 1) ON = 0 for all atoms in elemental substances: Chemistry XXI Simple Rules 4) ON = 0 for a neutral polyatomic formula. Chemistry XXI Lets Think Most of the reactions that generate the substances that are ultimately responsible for water acidification in our planet are redox reactions: The relevant substances are oxides of non metallic elements. Chemistry XXI Identify the oxidized and reduced atoms as well as the oxidizing and reducing species. Lets apply! Chemistry XXI Assess what you know Natural Cycles Compounds of sulfur and nitrogen play a central role at various levels in our planet. They participate in natural cycles that have been altered by human activities. Compounds of sulfur and nitrogen, for example, not only are the cause of acid rain but also contribute to Global Warming and to the depletion of the Ozone Layer. Chemistry XXI Sulfur Cycle 72 Chemistry XXI In million of tons/year 9 FeS2 Main Sources Biogenic Sources: Anaerobic bacteria CH3 S H3C + DMSP CH2 CH2 O C OH Enzyme H3C H3C DMS S O H2C CH C OH + Plankton Chemistry XXI Anthropogenic Sources: Combustion of coal, which typically contains 1% to 3% Lets apply! Analyze CH3 S H3C + DMSP CH2 CH2 O C OH Enzyme H3C H3C DMS S O H2C CH C OH + Chemistry XXI Are these redox reactions? If they are, identify the oxidized and reduced atoms, and the oxidizing and reducing agents. Further Oxidations Further oxidation of sulfur compounds in the gas phase in the atmosphere tends to follow reaction mechanisms involving free radicals. h Chemistry XXI The hydroxyl radical HO, constantly formed and destroyed in the atmosphere, plays a central role in these processes. H ON = +1 O ON = -1 Lets apply! Analyze Chemistry XXI a) In which of these steps are sulfur atoms being? Oxidized; b) How is their ON changing in each step? 3 2 Chemistry XXI Working in pairs, summarize the important chemical information that can be derived from the analysis of the oxidation numbers of atoms in reactants and products. Tracking Electron Transfer Summary Oxidation-Reduction (Redox) are an important type of chemical processes characterized by the transfer of electron density from one atom to another. The extent to which a reaction leads to electron density transfer can be assessed by analyzing changes in the oxidation number (or state) of each atom. Chemistry XXI +1 -4 0 0 +1 -2 +1 -2 +4 -2 Oxidation Numbers The oxidation number is defined as the partial charge that an atom in a molecule would have if all of the bonding electrons were assigned to the most electronegative atom in the bond (molecule seen as fully ionic). Assigning oxidation numbers is useful in: Chemistry XXI Identifying electron-rich and electron-poor centers in molecules; Tracking electron transfer or redistribution during a chemical reaction; Making predictions about reaction directionality. For next class, Chemistry XXI Investigate what is a Lewis acid and a Lewis base.
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Arizona - CHEM - chem 152
Unit 6How do we control chemical change?The central goal of this unit is to help you identify the structural and environmental factors that can be used to control chemical reactions.M1. Characterizing Interactions M2. Changing the EnvironmentRecognizi
Arizona - CHEM - chem 152
Unit 6How do we control chemical change?The central goal of this unit is to help you identify the structural and environmental factors that can be used to control chemical reactions.M1. Characterizing Interactions M2. Changing the Environment M3. Analy
Arizona - CHEM - chem 152
Unit 5How do we predict chemical change?The central goal of this unit is to help you identify and apply the different factors that help predict the likelihood of chemical reactions.M1. Analyzing Structure M2. Comparing Free EnergiesComparing the relat
Arizona - CHEM - chem 152
Unit 5How do we predict chemical change?The central goal of this unit is to help you identify and apply the different factors that help predict the likelihood of chemical reactions.M1. Analyzing Structure M2. Comparing Free Energies M3. Measuring Rates
Arizona - CHEM - chem 152
Unit 6How do we control chemical change?The central goal of this unit is to help you identify the structural and environmental factors that can be used to control chemical reactions.M1. Characterizing Interactions M2. Changing the Environment M3. Analy
Arizona - CHEM - chem 152
Unit 6How do we control chemical change?The central goal of this unit is to help you identify the structural and environmental factors that can be used to control chemical reactions.M1. Characterizing Interactions M2. Changing the Environment M3. Analy
Arizona - CHEM - chem 152
Unit 5How do we predict chemical change?The central goal of this unit is to help you identify and apply the different factors that help predict the likelihood of chemical reactions.M1. Analyzing Structure M2. Comparing Free Energies M3. Measuring Rates
Arizona - CHEM - chem 152
Unit 6How do we control chemical change?The central goal of this unit is to help you identify the structural and environmental factors that can be used to control chemical reactions.M1. Characterizing Interactions M2. Changing the Environment M3. Analy
Arizona - CHEM - chem 152
This section is extracted from John McMurray's &quot;Organic Chemistry&quot;, 6th edition, chapter 11 (Cengage Publishing). It is to be used only as reading material for this course. Any other distribution or use of this is prohibited.
Arizona - CHEM - chem 152
The Kinetic Control of Substitution ReactionsStudy Problems1) Which pair will react faster via the SN2 mechanism. What factor is important in each decision and draw reaction coordinate diagrams that display the rate differences. a) CH3CH2Br CH3CH2Cl+ +
Arizona - CHEM - chem 152
Exam I KEY CHEM XXI- Spring 2010 1. Silicon can react with oxygen in the atmosphere according to the following chemical equation: Si(s) + O2(g) SiO2(s) a) (5) Predict the sign of Horxn. Justify your answer based on the relative energetic stability of reac
Arizona - CHEM - chem 152
Chemistry 152Spring 2010- Exam 1 Information Sheet Dr. PollardSilicon is the second most abundant element in the Earth's crust, after oxygen. However, it does not exist in pure form on our planet. Most rock consists of compounds of silicon, and sand con
Arizona - CHEM - chem 152
Module 3 Study Assignment The Stability of TyrosineSpring 2010- CHEM XXI *This is to be turned in on Friday, Feb. 19th at the beginning of class. Before you turn it in, you must get it signed off by a preceptor. See D2L for a list of preceptors and their
Arizona - CHEM - chem 152
Chemistry 152Spring 2010- Exam 2 Info Sheet Dr. Pollard The steady expansion of population and industrial civilization in the past two hundred years has had a strong impact on the quality of the air that we breathe. The pervasive effects of human-made at
Arizona - CHEM - chem 152
KEY- EXAM 2- CHEM XXI-152 SPRING 2010 Dr. Pollard 1. Nitrogen monoxide (NO) is a pollutant commonly formed by the reaction of oxygen (O2) and nitrogen (N2) inside our cars combustion engines: N2(g) + O2(g) 2 NO(g) The NO(g) produced reacts with O2(g) to p
Arizona - CHEM - chem 152
Predictions of Energetic and Entropic StabilityProblems for Contemplation Key1) Rank the indicated bonds in order of increasing bond dissociation energy.ICCl3ClCCl3BrCCl321 (weakest)3 (strongest)NNHNNHH2NNH23 (strongest)21 (weakest)2)
Arizona - CHEM - chem 152
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Arizona - CHEM - chem 152
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Arizona - CHEM - chem 152
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Michigan - CHEMISTRY - 230
Clearly circle the one correct answer for each question #1-8. 1) Which of the following mixtures gives a buffer with a pH greater than 7.0? For HCNO, Ka = 2.2x 104 and for NH3, Kb = 1.8x105. A) 10 mL of 0.1 M NH3(aq) + 10 mL of 0.1 M HCl(aq) B) 10 mL of 0
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CHEM 230 F09 Exam 3 Worksheet 211) Citric acid (H3C6H5O7) is a triprotic acid with pKa1 = 3, pKa2 = 4, and pKa3 = 6.5. What is the approximate pH of a 0.01 mol/L solution of H3C6H5O7? (No math needed.) A) 2.5 B) 3 C) 4 D) 4.5 2) In a titration of a weak
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CHEM 230 F09 E3 Worksheet 111) Ca(OH)2 has Ksp ~ 1x10-6. If 0.1 mol of Ca(OH)2 was added to 1 L of pure water, what would be the approximate pH of the resulting solution? A) 2 B) 8 C) 12 D) 13 E) None of the above 2) Phenolphthalein is an acid-base indi
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CHEM 230 F09Exam 1 p1Name:_For questions 1-17, place the correct letter (or other information requested) on the answer sheet. 1) In an experiment a gas is heated up and gains 65 J of heat from the surroundings. As the gas heats up, it does work on the
Michigan - CHEMISTRY - 230
Michigan - CHEMISTRY - 230
F=105 C mol-1 h=7x20-34 J sh/4 =0.5x10-34 J s SECTION I: Transition Metals, Solids, Gases, and Enthaply1) Ionic solids are primarily held together by what kind of interactions? a. Metallic b. Covalent c. Electrostatic d. All of the above e. None of the
Michigan - CHEMISTRY - 230
CHEM 230 F09 Equation Sheet1J k g m 2 s- 2 1N kg m s-2 Pressure 1 Pa 1 k g m - 1 s- 2 1 bar 1 0 5 Pa 1 atm 101325 Pa 1 atm 1.01325 bar 1 atm 760 torr Length 1 in 2.54 cm 1 1x10-10m Volume 1L 1000 cm3 1 gal 3.785 L Energy 1 cal 4.184 J 1 eV 1.602-19J 1 CV
Michigan - CHEMISTRY - 230
CHEM 230 F09 Exam 1 Practice worksheet 1) Which of the following would have a higher heat capacity? a) H-O-H b) CO c) N=N d) Ar 2) Which of the following gases deviates most from ideal behavior? a) H2 b) C6H6 c) N2 d) CH4 3) Which of the following is an e
Michigan - CHEMISTRY - 230
Name: Chem 230 Exam #2 March 10, 2009 Discussion Section #: INSTRUCTIONS: Use only the space provided to answer the questions. If you need more work space, start your answer on the back of a page and then write only your final answer in the space provided
Michigan - CHEMISTRY - 230
Name:ANSWER KEY Chem 230 Exam #2 March 10, 2009Discussion Section #: INSTRUCTIONS: Use only the space provided to answer the questions. If you need more work space, start your answer on the back of a page and then write only your final answer in the spa
Michigan - CHEMISTRY - 230
Name:BLANK Chem 230 Exam #3 April 7, 2009Discussion Section #: INSTRUCTIONS: Use only the space provided to answer the questions. If you need more work space, start your answer on the back of a page and then write only your final answer in the space pro
Michigan - CHEMISTRY - 230
Name:KEY Chem 230 Exam #3 April 7, 2009Discussion Section #: INSTRUCTIONS: Use only the space provided to answer the questions. If you need more work space, start your answer on the back of a page and then write only your final answer in the space provi
Michigan - CHEMISTRY - 230
CHEM 230 F09 E2Name:_1) The freezing point of which of the following aqueous solutions would be lowest? Assume complete dissociation of all electrolytes. A) 0.1 m Ca(NO3)2 B) 0.1 m KNO3 C) 0.1 m HCl D) 0.1 m sucrose 2) Which of the following indicates v
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 2Qwizdom Click to edit Master subtitle style Quick Fundamental Review Start Chapter 4: Gases Session 230WebAssign Access Book with BJ access code No book but want to buy one Asked to pay extra for e-book onlineWelcome to Qwizdom!
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 3Chapter 4: Gases 14.1-14.8 Session Info: 230TopicsPressure Measurement Units Gas Laws Relationships between pressure, volume, moles, and temperature Ideal Gas Law Calculations including density and molar mass Solvings stochiometri
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 3Chapter 4: Master Click to edit Gases subtitle style 14.1-14.8 Session Info: 230TopicsPressure Measurement Units Gas Laws Relationships between pressure, volume, moles, and temperature Ideal Gas Law Calculations including density
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 4Chapter 4: Master subtitle style Click to edit Gases 14.9-14.14 Putting the P into Pchem Session ID: 230TopicsPressure Measurement Units Gas Laws Relationships between pressure, volume, moles, and temperature Ideal Gas Law Calcula
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 5Chapter 4: Click to edit Master subtitle style Speed and Non-Ideality Session ID: 230TopicsKinetic Model of Gases Root-mean-square speed of a gas Maxwell Distribution of Speeds Real Gases Assumptions for an ideal gas Real gases di
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 6Chapter 6: Thermodynamics Click to edit Master subtitle style First Law Session ID: 230Wrapping up CH 4Real Gases Assumptions for an ideal gas Real gases differ from a ideal gases van der Waals coefficientsvan der Waals Equation
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 7Chapter 6: Thermodynamics First Law Session ID: 230Thermodynamics = study of energy consevation Work free expansion (no work done against a vacuum) no volume change w =0 irreversible: w = -P V work at constant pressure reversible:
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 8Chapter 6: Thermodynamics First Law Session ID: 230OutlineWork Problem Measuring Enthalpy Heat exchange: Temperature change q = mCT qA = -qB Phase change Hvap, Hfus Measure with calorimeter Reactions Themochemical equations (addin
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 9Chapter 6: Thermodynamics First Law Session ID: 230 Homework 2 due Wed 9/30 at 10pmSelf-Lighting Candlea) C12H22O11(s)H2SO412 C(s) + 11 H2O(g) + heat 2 KCl(s) + 3O2(g)b) heat + 2KClO3(s)Cc) C(s) + O2(g) Frozen BeakerCO2(g) +
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 9Chapter 6: Thermodynamics First Law Session ID: 230 Homework 2 due Wed 9/30 at 10pmSelf-Lighting CandleH2SO4a) C12H22O11(s) heatCb)12 C(s) + 11 H2O(g) +heat + 2KClO3(s)2 KCl(s) + 3O2(g)b)C(s) + O2(g)CO2(g) + heathttp:/ww
Michigan - CHEMISTRY - 230
CHEM 230 F09 Lecture 10Chapter 7: Thermodynamics the Second and Third Laws Session ID: 230OutlineEntropy Thermochemical entropy = sharing of energy among microstates Defining microstate via quantized translational, rotational, and vibrational energy S
Michigan - CHEMISTRY - 230
CHEM 230 F09 L36Chapter 17: Nuclear Chemistry Session ID 230TopicsNuclear Decay Balancing Nuclear Reactions Nuclear Stability RadiationHomework 10: 1-7Nuclear ChemistryNuclear chemistry is the study of changes to the atomic nucleus- individual atom
Michigan - CHEMISTRY - 230
CHEM 230 F09 L38Chapter 17: Nuclear Chemistry Session ID: 230Homework 10: Nuclear Chem due Monday, Dec 14th 10 pm Course Evaluations: If you reach 95% completion then everyone in the section will receive 5 extra points. Fill out by Dec 15th. Exam regrad
Michigan - CHEMISTRY - 230
CHEM 230 F09 L38Chapter 17: Nuclear Chemistry Session ID: 230TopicsRadiation dose Rate of nuclear decay Mass to energy conversion Fission FusionHomework 10: 5-21 Due Monday 12/14Measure Nuclear Decay: RadiationActivity: # disintegrations per time Bq