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M3_5s

Course: CHEM chem 152, Spring 2010
School: Arizona
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5 How Unit do we predict chemical change? The central goal of this unit is to help you identify and apply the different factors that help predict the likelihood of chemical reactions. M1. Analyzing Structure M2. Comparing Free Energies M3. Measuring Rates M4. Understanding Mechanism Comparing the relative stability of different substances Determining the directionality and extent of a chemical reaction. Chemistry...

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5 How Unit do we predict chemical change? The central goal of this unit is to help you identify and apply the different factors that help predict the likelihood of chemical reactions. M1. Analyzing Structure M2. Comparing Free Energies M3. Measuring Rates M4. Understanding Mechanism Comparing the relative stability of different substances Determining the directionality and extent of a chemical reaction. Chemistry XXI Analyzing the factors that affect reaction rate. Identifying the steps that determine reaction rates. Unit 5 How do we predict chemical change? Module 3: Measuring Rates Chemistry XXI Central goal: To analyze the effect of concentration and temperature on the rate of chemical reactions. The Challenge Imagine that you were interested in comparing the rates at which different substances appeared or were decomposed on the primitive Earth. Transformation How do I change it? Chemistry XXI How could we evaluate the kinetic stability of a substance? How could we determine the effect of concentration and temperature on reaction rates? Time Issues Consider these two possible routes for the synthesis of glycine, the simplest amino acid, on the primitive Earth: Chemistry XXI Activation Energy G Thermo vs. Kinetics Occurs readily a t 2 5 oC Chemistry XXI Themodynamically favored, but does not occur for all practical purposes Reaction Coordinate Analyzing Stability Analyzing chemical systems from both the thermodynamic and kinetic point of view is crucial in making decisions about the actual stability of substances. For example, the decomposition or transformation of a substance may be favored thermodynamically, but can take millions of years to occur. How stable is it then? Chemistry XXI C(diamond) C(graphite) Kinetic Stability The analysis of the kinetic stability of biomolecules has been crucial in the analysis of different theories about the origin of life. For example, it has been proposed that amino acid synthesis could have occurred deep in the Earth's crust and that these amino acids were subsequently shot up along with hydrothermal fluids into cooler waters. Chemistry XXI How stable are amino acids under such conditions? Unstable? Many aqueous solutions of amino acids are thermodinamically unstable. Lets consider the case of alanine: 2 3 3 2 + 2 Decarboxylation Alanine (Ala) Ethyl Amine Chemistry XXI The kinetics of this reaction has been thoroughly explored by measuring the concentration of alanine [Ala] as a function of time (t) in aqueous solutions at various temperatures. Lets Think How would you quantify the rate of decomposition of alanine at any given time? o Chemistry XXI Reaction Rate o Chemistry XXI Lets Think What does this data tell you about the kinetic stability of alanine as a function of concentration and temperature? Hint: How does the rate change with C and T? (The higher the rate, the lower the kinetic stability) o o Chemistry XXI Reaction Rate o The slope decreases o Chemistry XXI Kinetic stability is a function of [R] and T. Rate Laws The effect of temperature and concentration on reaction rates can be modeled mathematically: xA+yB+zC wD+yE+zF RATE LAW Rate = k [A] [B] [C] a b c Reaction order Rate Constant Chemistry XXI a k depends on the value of T, E , and other relevant factors for each reaction. a Concentration Effects How can determine reaction orders and rate constants? Rate Law Rate = k[ Ala ] a Reaction order? Rate constant? What are their values? We may assume values for the reaction order a and analyze the implications: Chemistry XXI If a = 1 (first-order): By integration of this differential equation we get: d [ Ala ] Rate = = k[ Ala ] dt [ Ala ] = [ Ala ]o e kt ln[ Ala ] = ln[ Ala]o kt Graphical Analysis If the reaction is first-order: For example, is the decomposition of alanine at 150 C (423 K) ln[ Ala ] = ln[ Ala]o kt y ln[Ala] ln[Ala]o = b + mx 1 t (years)order?: [Ala] (mM) 0 2 4 6 8 10 12 14 t 16 1.000 0.8705 0.7578 0.6597 0.5743 0.5000 0.4352 0.3789 0.3298 Chemistry XXI m = -k Reaction Order t (years) [Ala] 0 (mM) 2 4 6 8 10 12 14 16 1.000 0.8705 0.7578 0.6597 0.5743 0.5000 0.4352 0.3789 0.3298 ln[Ala] 0 -0.1387 -0.2773 -0.4160 -0.5546 -0.6931 -0.7914 -0.9704 -1.1092 We have a first-order Chemistry XXI Lets Think Given the Rate Law: Rate = 0.0693[Ala] If [Ala] = 1.00 mM, predict the time it will take for Chemistry XXI Half Life A half-life is the time it takes for the concentration of a reactant to be reduced in half. Chemistry XXI t=0 t = 1 half-life t = 2 half-lives t = 3 half-lives Half Life For first order reactions: [C ] ln = kt [C ]o If [C] = [C]o/2 1 ln = o kt1/ 2 2 Chemistry XXI t1/ 2 ln(1 / 2) = k Independent of Concentration Concentration Effects If the reaction is first-order Rate = k[C]: ln[C ] = ln[C ]o kt What if Rate = k[C]a with a = 2 (second-order)? 1/[C] d [C ] Rate = = k[C ]2 dt Chemistry XXI By integration we get: 1 1 = + kt [C ] [C ] o 1/[C]o m=k t Lets Think Is half-life for second order reactions independent of the initial concentration of reactant? Chemistry XXI Temperature Effects How can we predict how rate varies with temperature? The decomposition of alanine at different temperatures illustrates the effect of T on the reaction rate. T (K) 323 373 423 473 523 573 k (y-1) Larger T Larger rate constant Shorter half lives. Ho do we explain it and make quantitative predictions? Chemistry XXI Collision Rate Model According to this model: 1. For a reaction to occur, the reactant particles must collide. 2. Colliding particles must be positioned so that the reacting groups interact effectively. Chemistry XXI 3. Colliding particles must have enough energy to reach a transition state that leads to the formation of the new products. Ep Transition State Ea R H P Reaction Coordinate Arhenius Equation The fraction of molecules with enough energy to react at a given T is proportional to: e Chemistry XXI Ea RT The rate constant k is then given by: Ea ln(k ) = + ln( A) RT y = mx + b y ln(k) x 1/T k = Ae Ea RT Likelihood of collisions Lets Think ln(k ) = Ea + ln( A) RT Chemistry XXI T (K) 323 373 423 473 523 573 623 k (y-1) 3 2 3 2 + 2 Lets apply! Chemistry XXI Assess what you know Lets apply! Analyze Go back and analyze the notes for the decomposition of Alanine. Based on our overall results, analyze the likelihood of amino acids forming in hydrothermal vents on the primitive Earth. Chemistry XXI Lets apply! New Data Recent experimental results indicate that there may be other reactions that compete with the decomposition of amino acids at T > 100 oC: 2 Dimerization 2 3 2 3 3 + H2O Peptide Bond Chemistry XXI The formation of dimers and polymers may have helped amino acids to accumulate on the planet. Lets apply! Analyze Go to: http://www.chem.arizona.edu/chemt/C21/sim (Dimerization) or use the simulation on the next page. Use the simulation of the dimerization of alanine to: Determine the order of the reaction; Chemistry XXI Compare the half-lives of the process for a 1 M solution of alanine at 100 oC and 200 oC. Lets apply! Analyze Chemistry XXI Chemistry XXI Identify with a partner two important ideas discussed in this module. Measuring Rates Summary Reaction rates allow us to follow the kinetic evolution of a chemical process. xA yB RateInst d [ A] = dt The effect of temperature and concentration on a process reaction rate is summarized in the RATE LAW: Chemistry XXI RATE LAW Rate = k [A] a Reaction order Rate Constant C and T Effects Given a rate law, we can derive information about how the concentration of reactants or products changes with time. xA yB If a = 1 (first-order): If a = 2 (second-order): Chemistry XXI Rate = k [A]a ln[ A] = ln[ A]o kt 1 1 = + kt [ A] [ A] o Temperature effects on reaction rate are determined by Arhenius Equation for the rate constant k: k = Ae Ea RT For next class, Chemistry XXI Investigate how the overall rate of a reaction is related to the reaction mechanism. How can we use the reaction mechanism to derive the rate law or use the rate law to evaluate the reaction mechanism?
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Arizona - CHEM - chem 152
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Michigan - CHEMISTRY - 230
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Michigan - CHEMISTRY - 230
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Michigan - CHEMISTRY - 230
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Michigan - CHEMISTRY - 230
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Michigan - CHEMISTRY - 230
CHEM 230 F09 L38Chapter 17: Nuclear Chemistry Session ID: 230Homework 10: Nuclear Chem due Monday, Dec 14th 10 pm Course Evaluations: If you reach 95% completion then everyone in the section will receive 5 extra points. Fill out by Dec 15th. Exam regrad
Michigan - CHEMISTRY - 230
CHEM 230 F09 L38Chapter 17: Nuclear Chemistry Session ID: 230TopicsRadiation dose Rate of nuclear decay Mass to energy conversion Fission FusionHomework 10: 5-21 Due Monday 12/14Measure Nuclear Decay: RadiationActivity: # disintegrations per time Bq
Michigan - CHEMISTRY - 230
CHEM 230 F09 L40Review Final Exam Session ID 230Homework 10: Nuclear Chem due Monday, Dec 14th 10 pm Evaluations: If you reach 95% completion then everyone in the section will receive 5 extra points. Fill out by Dec 15th.Final Exam Friday, Dec 18th 8-1
Michigan - CHEMISTRY - 230
9) Which of the following gases most likely deviates from ideality due to the van der Waals parameter a? a) He b) Xe c) NH3 d) F 10) If the most probable speed of a Maxwell-Boltzmann Distribution is increased, what happens to the slowest speed of the dist
Michigan - CHEMISTRY - 230
9) Which of the following gases most likely deviates from ideality due to the van der Waals parameter a? a) He b) Xe *c) NH3 d) Fa deals with attraction only (polarity, van der Waals), not charges. 10) If the most probable speed of a Maxwell-Boltzmann Dis
Michigan - CHEMISTRY - 230
Worksheet Chemical Kinetics 1. For the reaction shown below, the rate is expressed as1 HO [2] . 6 t6 2 + H(H 4 6O C 4 3 C6 + 2 HN O ) 2N H An equivalent expression is: 1 C 2)6N [( H 4 a. 2 t C 2O [H ] b. 6 t C 2O [H ] 6 c. t 1 HO [2] d. 6 t 1 N 3] [H e.