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University of Phoenix - MGT - 437
Management Structures1Project Management Organizational Structures University of Phoenix MGT 437Project management organizational structure can be summed up in three different traditional types: Functional, Matrix and Pure Project. Each structure can b
University of Phoenix - MGT - 437
T e a m C r e a t i o n s |1RUNNING HEADER: TEAM CREATIONS PAPERTeam Creations Paper University of Phoenix MGT437/Project ManagementT e a m C r e a t i o n s |2Abstract A project is only as successful as its team is a safe methodology to use when cons
University of Phoenix - MGT - 437
Human Capital Paper HUMAN CAPITAL PAPER1Mills-Jones Wedding Ron Hill University of Phoenix MGT 437Human Capital Paper The Jones-Mills wedding is all planned, now is the time for the team to come to finalize all the plans that were agreed upon. First th
University of Phoenix - MGT - 437
Project Proposal Paper1Project Implementation, Control and Termination MGT437: Project Management University of Phoenix Mr. Ronald HillProject Proposal Paper1Project IntroductionA project is a series of activities and tasks that (1) have a specific
University of Phoenix - MGT - 437
Final Paper FINAL PAPER1Mills-Jones Wedding LT University of PhoenixMGT 437Introduction Christies Wedding Planners is a small business that helps customers plans their perfect wedding. Our team took on the Jones-Mills wedding which was planned to be h
University of Phoenix - MGT - 437
Performance Measurements 1 Performance Measurements University of Phoenix MGT 437 Ron HillPerformance measurement is the statistical evaluation of a project in obtaining the specified goals. Performance measurement exists in all projects but is character
University of Phoenix - MGT - 437
FinalProjectPaperClicktoeditMastersubtitlestyle4/8/10cfw_704906B2-31D5-4BD4-9B5F-3C7B5D693C6Ccfw_9164A2D2-0EE7-4842-AF0D-65DFEC6272EDcfw_3C7C1AFB-6DBF-4991-B46D-E76907D59979BUDGET AND TIME TERMS OF TRIPLE CONSTRAINT PROJECT GOALS IN BACKGROUND AND S
University of Phoenix - MGT - 437
P a g e |1Performance Measurement Paper University of Phoenix Project Management MGT/437 Professor Ron HillP a g e |2Performance Measurement Paper Many businesses have engaged in performance measurement to help their organization structure. There are s
University of Phoenix - SCI - 151
SCI 201 Survey of Alternative MedicineUniversity of Phoenix MaterialWeeks One and Two Content NotesWEEKS ONE AND TWO TOPICS AND OBJECTIVESComplementary and Alternative Medical Systems (CAM) Define complementary, alternative, and integrative medicine
University of Phoenix - SCI - 151
MGT417 Business Continuity Management and PlanningMGT417 Week OneINTRODUCTION TO BUSINESS CONTINUITY AND ASSESSMENTIntroductionDavid Laster (in Shimpi, 2001) suggested risk and uncertainty are fundamental to life, both human and corporate (p. 3). What
University of Phoenix - SCI - 151
SCI 151 AstronomyUniversity of Phoenix MaterialWeek One Content Questions WorksheetUsing the assigned readings for Week One, prepare a 50 to 75-word response to each of the following questions. Be sure to include the questions with your responses. Your
University of Phoenix - SCI - 151
From Perfect Circles to EllipsesIntroduction:Welcome to the wonderful world of Astronomy. In the next five weeks, you will be hearing a wonderful story, comparable to the great creation myths. You will learn about where you are in the universe, what is
University of Phoenix - SCI - 151
From Telescopes To SpacecraftIntroduction:This week, the course will cover:1. The surface and structure of planet earth. 2. Unique aspects of each planet of the solar system. 3. Why there are similarities and differences between the planets. 4. The nat
University of Phoenix - SCI - 151
SCI 151 AstronomyUniversity of Phoenix MaterialWeek Two Content Questions WorksheetUsing the assigned readings for Week Two, prepare a 50 to 75-word response to each of the following questions. Be sure to include the questions with your responses. Your
University of Phoenix - SCI - 151
SCI 151 AstronomyWeek Three Content OutlineTOPICS AND OBJECTIVESThe Sun and Stars Describe the nature and importance of light and other electromagnetic waves. Explain the nature of the Sun. Describe the properties of stars. Explain the life cycle of
University of Phoenix - SCI - 151
Stellar Models and The BombIntroduction:This week, the course will cover: The nature and importance of light and electromagnetic waves. The nature of the sun. The structure and properties of stars. Stellar evolution.In this week's lecture, I would li
University of Phoenix - SCI - 151
SCI 151 AstronomyUniversity of Phoenix MaterialWeek Four Content Questions WorksheetUsing the assigned readings for Week Four, prepare a 50 to 75-word response to each of the following questions. Be sure to include the questions with your responses. Yo
University of Phoenix - SCI - 151
SCI 151 AstronomyWeek Four Content OutlineTOPICS AND OBJECTIVESThe Large Scale Universe Describe the origin of the universe. Examine the hierarchy of the universe. Describe the structure of the Milky Way Galaxy.CONTENT OUTLINE Introduction to the Mi
University of Phoenix - SCI - 151
Measuring Distances To GalaxiesIntroduction:This week, the course will cover: The structure of the Milky Way Galaxy. The life cycle of stars. The hierarchy of the universe. The origin of the universe.In this week's lecture, I would like to expand upo
University of Phoenix - SCI - 151
The Economics of Interstellar TravelIntroduction:This week, the course will cover: The properties of life. The possibilities of extraterrestrial life in our solar system. The types of stars that could have life bearing planets. The search for extrater
University of Phoenix - SCI - 151
Elementary School Science Core Content for Assessment Crosswalk 3.0-4.0-4.1Physical ScienceVersion 3.0 Version 4.0 Version 4.1Structure and Transformation of MatterSC-E-1.1.1 Objects have many observable properties such as size, mass, shape, color, te
University of Phoenix - SCI - 151
SCI 151 AstronomyWeek Five Content OutlineTOPICS AND OBJECTIVESExtraterrestrial Life/Astronomy Research Examine the properties of life on Earth. Examine the possibilities of extraterrestrial life in our solar system. Describe the types of stars that
University of Phoenix - SCI - 201
Team MatrixSYSTEM DESCRIPTION EDUCATION LICENSE/CERT?AllopathyMedical doctor (MD). Performs Four years medical school after Licensed by state upon passing a surgery, orders lab and diagnostic college, followed by residency series of three national exam
University of Phoenix - SCI - 201
Beth A. Simon Matching Matrix Week 2 | 1University of Phoenix MaterialIndividual Matching and Fill-in AssignmentMatch the following therapies in Column One with their correct description from Column Two. Place the corresponding letter in the space by t
Waterloo - MATH - 148
MATH 148 Assignment #1Due: Monday, January 17 1) For each of the following limits of Riemann Sums identify the corresponding integral. In each case, sketch the graph of the function over the region of integration and nd the limit (integral). a) lim ( i )
Waterloo - ACTSC - 231
7.2, 7.3, 7.4 (you need to know the difference between premium/discount, but not the details of bond amortization. 7.5 (only the semi-theoretic method. Note the book uses the term "flat" price incorrectly. What the book calls flat price should be called t
Waterloo - ACTSC - 231
University of Waterloo Department of Statistics and Actuarial ScienceActuarial Science 231 Winter 2006 Mathematics of FinanceCourse OutlineInstructor: Dr. R. Keith Freeland Office: MC 6082A Phone: 3356 (I seldom check my voice mail so its best to email
Waterloo - MATH - 138
Math 138Assignment 1 SolutionsFall 20081. Evaluate each of the following indenite integrals: x2 (x3 + 5)9 dx Solution Let u = x3 + 5, then du = 3x2 dx, and by substitution, we obtain: (u)9 du = 3 1 10 13 19 u du = u +C = (x + 5)10 + C . 3 30 30a)b)e
Waterloo - MATH - 138
Math 138Assignment 2 SolutionsFall 20081. Determine the volume obtained by rotating the region dened by the given curves about the specied line. Include a sketch of the region with a typical cylindrical shell, and sketch the solid. a) x = 4y 2 y 3 , x
Waterloo - MATH - 138
Math 138Assignment 3 SolutionsFall 20081. Determine the volume obtained by rotating the region bounded by y = sec x, about the line y = 1. Solutiony y=s inx 1 y=cos x x 3y = cos x,0x 3On the interval 0 x 3 3,sec x cos x thus the volume, V , is
Waterloo - MATH - 138
Math 138Assignment 4 SolutionsFall 20081. Use Comparison to determine the convergence or divergence of the following: xx dx a) x + x2 1 Solution Try to show that the Type 1 improper integral diverges. For x 1, x + x2 x2 + x2 1 1 2 2 x + x2 x+x xx xx xx
Waterloo - MATH - 138
Math 138Assignment 5 SolutionsFall 20081. Biologists stocked a lake with 400 sh and estimated the carrying capacity (the maximum population for the sh of that species in the lake) to be 10 000. The number of sh tripled in the rst year. a) Assuming that
Waterloo - MATH - 138
Math 1381.Assignment 6 SolutionsxaFall 2008a) Use the denition of lim f (x) = L to prove the limit: lim 4 3x 5 = 7.x5Solution Given any > 0, we must show that there is a such that 4 0 < |x + 5| < . 4 Thus 4 3x 7 < 5for all x such that3x x 3 3x =
Waterloo - MATH - 138
Math 1381.Assignment 7 SolutionsFall 2008a) Use the Integral Test to show that the seriesn=2ln n n23converges.Solution for x 2. 3 x2 3 1 31 x 2 x ln x 2 x 2 2 3 ln x Then f (x) = = . 5 x3 2x 2 2 2 Thus f (x) < 0 for ln x > or x > e 3 1.95, and f
Waterloo - MATH - 138
Math 1381.Assignment 8 SolutionsFall 2008a) Determine the radius of convergence and the interval of convergence for the power series :(2 3x)n . n n=1 Note: the series is not in standard power series form, but can be treated in the same manner. Soluti
Waterloo - MATH - 138
Final Exam InformationThe final exam is scheduled for Wednesday, December 107:30 p.m. - 10:00 p.m.in the PAC main gym, areas 4 and 5.The exam will cover the entire course.Calculators are allowed.NO notes, formula sheets, or other aids are allowed.
Waterloo - MATH - 138
MATH 138Instructors Section 001 002Calculus 2 for MathematicsFall 2008Name P. Camire B. Ferguson (Coord.)Oce MC 5052 MC 5100Bemail pcamire@math.uwaterloo.ca bafergus@math.uwaterloo.caExtension 33571 36845Course website is on UW-ACE. Text: Calculus
Waterloo - MATH - 138
University of Waterloo Midterm TestMATH 138 Fall Term 2008Name (Print): UW Student ID Number: Please indicate your section: 9:30-10:20 (P. Camir ) Section 001 e 10:30-11:20 (B. Ferguson) Section 002 Course Abbreviation and Number: Course Title: Date of
Waterloo - MATH - 138
MATH 138Calculus 2 for MathematicsRecommended problems from the text book.Fall 2008Text Section 5.5 6.1 6.2 6.3 6.5 7.1 7.2 7.3 7.4 7.5 7.8 9.1 9.2 9.3 9.4 9.5 9.6 10.1 10.2 11.1 11.2 11.3 11.4 11.5 11.6 11.7 11.8 11.9 11.10 11.11Questions 7,9,15,17,
Waterloo - ACTSC - 231
ACTSC 231 Quiz 5 blue1. (a) 8000a12j = 8000 1 (b) 8000a12j = 8000 1 ln (1 + i) (c) 8000a12j = 8000 1 ln 1 +i(m)v 12 v= 8000 1e:06(12):06 (1:06) ln 1:06= 68433: 031212= 8000 11= 69063: 33Note=v 12= 8000m06 (1+ :12 ) 06 12 ln(1+ :12 )12
Waterloo - ACTSC - 231
ACTSC 231 Quiz 5 pink1. (a) 8000a12j = 8000 1 (b) 8000a12j = 8000 1 ln (1 + i) (c) 8000a12j = 8000 1 ln 1 +i(m)v 12 v= 8000 1e:08(12):08 (1:08) ln 1:08= 61710: 711212= 8000 11= 62669: 24Note=v 12= 8000m(1+ :08 ) 2 2 ln(1+ :08 ) 22(12)
Waterloo - ACTSC - 231
ACTSC 231 Solutions to Quiz 6 blue1. a) 5000 = 450a16jj =) j = 4:652225351% per quarter i = (1:04652225351)41 = 19:95%b) 450s16j1% = 7766:04 AV of the payments reinvested at i(4) = 4% 5000 (1 + i) = 7766:04 =) i =(4)47766:04 1=4 50001 = 11:64%1 =
Waterloo - ACTSC - 231
ACTSC 231 Solutions to Quiz 6 pink1. a) 5000 = 150a48jj =) j = 1:599092374% per month i = (1:01599092374)121 = 20:97%b) 150s48j:333333% = 7793:94 AV of the payments reinvested at i(12) = 4% 5000 (1 + i) = 7793:94 =) i =(12)47793:94 1=4 5000 1=121
Waterloo - ACTSC - 231
ACTSC 231 Solutions for Quiz 7 blue 8 71. a) 3000 (1:02) 750 (1:02) 250s7j2% = 794:89 b) Principal repaid B0 B12 = 3000 794:89 = 2205: 10Interest paid 750 + 7 (250)2205: 10 = 294: 901
Waterloo - ACTSC - 231
ACTSC 231 Solutions for Quiz 7 pink 12 111. a) B12 = 3000 (1:005) b) Principal repaid B0 500 (1:005) B12 = 3000 1528:91 = 1471: 10100s11j:5% = 1528:91Interest repaid 500 + 11 (100)1471: 10 = 128: 901
Waterloo - ACTSC - 231
ACTSC 231 Quiz 8 blue 121. B12 = 200a12j:5% + 200 (1:005) I13 = :005 (6488:99) = 32:448a24j:666667% = 6488:992. 5000s7j5% (1:05) + Ds8j5% = 90000 D=90000 5000s7j5% (1:05)8 s8j5%= 3126:231
Waterloo - ACTSC - 231
ACTSC 231 Quiz 8 pink 241. B12 = 200a24j:5% + 200 (1:005) I13 = :005 (6552:35) = 32:769a12j:666667% = 6552:352. 5000s6j5% (1:05) + Ds9j5% = 90000 D=90000 5000s6j5% (1:05)9 s9j5%= 3377:301
Waterloo - ACTSC - 231
ACTSC 231 Solutions to Quiz 9 blue 8%n2 = 2 (4) = 8, j2 = 3:5% = 1:75% 2 P2 = 200a8j1:75% + 5000(1:0175) 8 = 5833:07 NPV =>j = 6284:93 + 200a7jj + 5833:07(1 + j )i(2) 2 71. C = F = 5000, r = 2 = 4%, F r = 200; n1 = 2 (7:5) = 15, j1 = P1 = 200a15j2% + 5
Waterloo - ACTSC - 231
ACTSC 231 Solutions to Quiz 9 pink 8%1. C = F = 5000, r =2= 4%, F r = 200; n1 = 2 (7:5) = 15, j1 =154% 2= 2%P1 = 200a15j2% + 5000(1:02)= 6284:92n2 = 2 (3) = 6, j2 = 3:5% = 1:75% 2 P2 = 200a6j1:75% + 5000(1:0175) 6 = 5635:51 NPV =>j = 6284:92 + 20
Waterloo - ACTSC - 231
ACTSC 231 Quiz 10 blue:500 1. a) 95 = 100 (1 + i0;:5 ) =) i0;:5 = 195 1 = 10:80332410% :5 1 97:40 = 4 (1 + i0;:5 ) + 104 (1 + i0;1 ) =) i0;1 = 97:40104(:95) 1= 4 11:1111111111% :5 1 1 :5 101:20 = 6 (1 + i0;:5 ) + 6 (1 + i0;1 ) + 106 (1 + i0;1:5 ) =) i0;
Waterloo - ACTSC - 231
ACTSC 231 Quiz 10 pink:500 1. a) 95 = 100 (1 + i0;:5 ) =) i0;:5 = 195 1 = 10:80332410% :5 1 97:40 = 4 (1 + i0;:5 ) + 104 (1 + i0;1 ) =) i0;1 = 97:40104(:95) 4 11:1111111111% 1 :5 00 2=3 1 = 11:443322% 85 = 100 (1 + i0;1:5 ) =) i0;1:5 = 18521=101 = 6
Waterloo - ACTSC - 231
ACTSC 231 Quiz 11blue solutions1. For an n-year zero coupon bond d (i) = n, v (i) = nv and c (i) = n (n + 1) v 2 d (i) = 16 and v (i) = 15:2 ( i) v (i) = v d (i) =) v = v(i) = 15:2 = 0:95 16 d c (i) = 16 (16 + 1) (:95) = 245: 484(1:03) ) i = 4(1:03)+103
Waterloo - ACTSC - 231
ACTSC 231 Quiz 11 pink solutions1. For an n-year zero coupon bond d (i) = n, v (i) = nv and c (i) = n (n + 1) v 2 d (i) = 12 and v (i) = 11:4 ( i) v (i) = v d (i) =) v = v(i) = 11:4 = 0:95 12 d c (i) = 12 (12 + 1) (:95) = 140: 795(1:04) ) i = 5(1:04)+10
Waterloo - ACTSC - 231
ACTSC 231 Solutions to extra problems 1a 1. a) A (0) = 7 A(t) b) a (t) = A(0) = e:03t c) I7 = A (7) A (6) = 7e:03(7) 7e:03(6) = :2552 :03(7) 7e:03(6) 7 d) i7 = AI(6) = 7e 7e:03(6) = e:03 1 = 3:045% 2. 900 (1 + i) = 900 + 130:41 =) i = 1030:41 1 = 7% 900 5
Waterloo - ACTSC - 231
ACTSC 231 Solution to Extra Problems 1 5 1. 400 . 06 8 0 50 . 06 13658 550 . 18 25 15 1450 . 06 29 25 450 . 06 30 29 1. 10 365 365 365 365 (interest withdrawn on April 30th) bal on April 30 is 448.90 0 448. 90 . 06 5 0 551. 10 . 18 23655 1448. 90 . 06 31
Waterloo - ACTSC - 231
ACTSC 231 Solutions to Extra Problem set 2 360 1. a. 100000 1 d 170 96000 d 1 360 170 m i 100000 96006 365 m b. m (eff. rate per 170 days) i 96006 170 365 year compounded every 170 days or 170 times per year. 2.The value at time three100e1200e2500e
Waterloo - ACTSC - 231
2 (1:01) =) 2 (t 1) ln 1:03 = ln 2 + 4t ln 1:01 =) t [2 ln 1:03 4 ln 1:01] = ln 2 + 2 ln 1:03 =) t = 944 597 years or 38 years and 345 days. 3. The annual accumulation factors are: a. 1:05 2 b. 1 + :0495 = 1:050112563 2 1 c. (1 :0475) = 1:049868766 :0485
Waterloo - ACTSC - 231
ACTSC 231 Solutions to Extra Problems 2b 13 1. a)1000000 1 :0384 360 = 998; 6 13:33 48 b) Sell for: 5000000 1 :0387 360 = 4; 974; 200:00 Buy for: 5000000 1 :0377 4; 982; 197:20 The net transaction results in the bank paying the dealer: 4; 982; 197:20 4; 9
Waterloo - ACTSC - 231
ACTSC 231 Solutions Extra Problems 3 a1. (a) 300a6j = 300 1 (b) 300a6j = 300 1 (c) 300a6j = 300 1 ln 1 +i(m) m m v6 v6= 300 1 = 300 1e :04(6) :04 (1:04) ln 1:04 16= 1600: 291 = 1603: 888 3 Note4(6)= ln (1 + i) Note =v6= 300(1+ :04 ) 4 4 ln(1+ :
Waterloo - ACTSC - 231
ACTSC 231 Extra Problem Set 3 Solutions 1. 250 a 1 . 5 a 1 1 a 1 1. 5 a 1 2 250 1 . 03 . 5 1 . 03 1 1 . 03 1. 5 1 . 03 2 962. 5 AV at time 3 is: 962. 50a 3 962. 50/a 1 3 962. 50/ 1 . 03 3 1057. 69 2. 4000 200a 20|i 100v 20 a 20|i 2500 250v 20 a 20|i v 20
Waterloo - ACTSC - 231
1.B7 = 500a5j:05 +500 (1:05) a12j:06 = 500 +500 (1:05) :05 = 5449:2189 I8 = :05OB7 = :05 (5449:2189) = 272:46095 P8 = 500 272:46095 = 227:539 05 06) 10 = 3680: 043 5 b.B14 = 500a10j:06 = 500 1 (1:06 I15 = :6B14 = :06 (3680: 043 5) = 220: 802 61 P15 = 500