hwk_17
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hwk_17

Course Number: CE 2450, Spring 2010

College/University: LSU

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Since CD is a two-force member, the force it exerts on member ABD is directed along DC. Free-Body Diagram of ABD: (Three-Force E member) tana=- = 0.6 5 a= 30.964 in. 3 AE= IOtana=6 GE = AE - AG = 6 -1.5 = 4.5 in. tanjJ=-=GB 3 50 Ib "\0 GE 4.5 jJ = 33.690 B sin 120.964 D sin 33.690 50lb sin 25.346 + oc. -= ''2.o:'1~+o ~ ~oo-t:/.._~ = Z5".3~"o B = 100.2 Ib ~ C = D = 64.8 Ib ~ 56.3 .. 31.0 .....

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CD Since is a two-force member, the force it exerts on member ABD is directed along DC. Free-Body Diagram of ABD: (Three-Force E member) tana=- = 0.6 5 a= 30.964 in. 3 AE= IOtana=6 GE = AE - AG = 6 -1.5 = 4.5 in. tanjJ=-=GB 3 50 Ib "\0 GE 4.5 jJ = 33.690 B sin 120.964 D sin 33.690 50lb sin 25.346 + oc. -= ''2.o:'1~+o ~ ~oo-t:/.._~ = Z5".3~"o B = 100.2 Ib ~ C = D = 64.8 Ib ~ 56.3 .. 31.0 .. B = 100.155 1b D = 64.789 Ib PROPRIETARY reprodllced MATERIAL. c 2010 The McGraw-Hili or hy (/Ill' Companies, Inc, All rights reser.'ed, \lTillell permission illJiI'idllo! ,Yo pari of Il1is ,I!alllwlmm' of Ihe pllhlisher, be disp!m'eJ. Ihe lillliled ,\10111101, or dislrihllied in anI' /orm means, \I'ii/lOlIl Il1e prior or IIsed henmd dislribllliolllO leachers alld "dl/COlOrSpermilled ."1111 are IIsillg il \I'illlOlIlpermissioll, hI' ,1!cGra\l'-Hillforlheir COllrse preparalioll. If.l'oll are a s/lldelll IIsillg Ihis I) /,;$-1 /' /' A 50-kg crate is attached to the trolley-beam system shown. Knowing that 0 = 1.5 Ill, determine (0) the tension in cable CD, (b) the reaction at B. tan f3 = _0_.7_49_7_m_ 1.5 m ISit',,3s tJ = I. (U1)j '" E f3 = 26.56 W = (50 kg) 9.81 rn/s2 =490.5 N 490.5 N sin 61.56 TeD TeD B sin 63.44 = 498.9 N sin 55 B = 456.9 N TeD =499 N ~ B = 457 N ~26.6 ~ PROPRIETARY TERIAL. JIA C 20 I 0 The McGraw-Hili Companies, Inc, All rights reserved, ,Vo part of this Jfanual lIIay be diSplay~ reproduced or distributed in (1m' form or by am' means, lI'ithout the prior lrrillen permission of the publisher. or used beyond the Jim/teL distribution to teachers and educators permil/ed by .\fcGrall'-Hillfor their indil'idual course preparation. I/\'Ou (Ire a student using tillS Manua .\'ou are using it lI'itholl/ permission. :300 mil' 1 !hT PROBLEM (a) h=O, 4.21 Detennine (b) h=200mm. the reactions at A and B when h=O Reaction A must pass through C where 150-N weight and B interect. !+ ~ ISON .. [? -"'_ A = 150.0 N L 30.0 . 30.0 . B = 150.0 N ~ (b) tan fJ = 55.662 250 ,... :]0" fJ = 12.552 Force triangle Law of sines 150 N sin 17.448 A sin 60 = 488.31 N B sin 102.552 A = 433.247 N B A = 433 N ~ B = 488 N ~ 12.55 . 30.0 . PROPRIETARY MATERIAL. c 2010 The McGraw-Hili Companies, Inc. All rights reserved. No part o/this Manual may be displa)'ed. reproduced or distributed ill an)' /orl/1 or bl' anI' meallS, lI"itholl/ the prior lI'fillen permission o/the publisher. or used beyond the limited distribution to teachers alld educators permilled bl- McGr(/\I'-Hill/or their indil'idual course preparation. /fyou are a student using this Malll/al, you are I/sing it lI'ithol/t permission.

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National Institute of Technology, Calicut - CSE - CS501
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National Institute of Technology, Calicut - CSE - CS501
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National Institute of Technology, Calicut - CSE - CS501
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