19 Pages

2 - Calculating Enthalpy Changes_S10

Course: CHE 102, Spring 2010
School: WVU
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Changes Calculating of Enthalpy, Internal Energy, Volume For a Process of Interest ChE 202 Spring 2010 Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating Changes of Enthalpy, Internal Energy, Volume H , U , V Why do I care? So we can use these in (MB,) EB: - - (vsys2)/2 + g zsys + U sys 0 = etc = Q(in)/msys Ws(by)/msys Pext Vsys & & ( H i + E k ,i + E p,i )mi ( H i +...

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Changes Calculating of Enthalpy, Internal Energy, Volume For a Process of Interest ChE 202 Spring 2010 Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating Changes of Enthalpy, Internal Energy, Volume H , U , V Why do I care? So we can use these in (MB,) EB: - - (vsys2)/2 + g zsys + U sys 0 = etc = Q(in)/msys Ws(by)/msys Pext Vsys & & ( H i + E k ,i + E p,i )mi ( H i + E k ,i + E p,i )mi + Q& (in) W&s(by) in out Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating Changes of Enthalpy, Internal Energy, Volume - 2 H , U , V For V(T,P), Can calculate absolute value, or can use data sources For H and U, Can calculate M = M(T2,P2) M(T1, P1) Or can use data sources Value of H(T,P) read off is actually H(T,P) H(Tref, Pref) Get U from H = U + PV Make sure different data sources have the same reference states Data sources first, then calculations Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Sources of Data Steam tables/other tables advantages much data, wide range of conditions disadvantage specific species (e.g., water) need for interpolation Diagrams (like P H diagrams) advantage good for quick calculations disadvantage not accurate Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Sources of Data - 2 Perrys Handbook the ChE data bible It also contains instructional material We have hard copies, and PDF version is on all computers advantage it contains most ChE information ever needed disadvantage sometimes hard to find what you want until you know your way around it Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Sources of Data - 3 CD accompanying book (and similar data bases) advantage has huge amount of information no need for interpolation disadvantage not always near computer Chemcad advantage has huge data base disadvantage too costly for individual use, data not always in user-friendly format Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating H, U in general For an arbitrary process Break up process into sub-processes Calculate (M) for each Then Mprocess = M1 + M2 + Can do this because H and U are State Functions (path-independent) Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating H, U in general -- 2 What sorts of sub-processes? Simple ones Change in pressure at constant temperature Change in temperature at constant pressure Change in T or P at constant volume Change in phase at constant P and T Mixing of pure components to multicomponent system at constant T and P (and reverse) Pure components in stoichiometric amounts reacting to form pure products(s) Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating H, U in general -- 3 Examples (multiple paths possible) Ice at -5C, 1 atm -> Steam at 300C, 5 atm (Water at 30C, 1 atm) + (NaCl at 25C, 1 atm) -> Saline solution at 50C, 1 atm Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating M for P at constant T (P)T For Ideal Gases, U IG so ( U ) IG T Now Then 0 = U (T ) not P H IG U IG + ( PV ) IG = U IG + ( RT ) H IG = H (T ) not P 0 so ( H ) IG T For Real Gases, correlations with Z, etc, but (IG) ok upto P Pc For liquids and solids, U and H are ~ independent of P (but PV RT !) correlations (later) Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating M for T at constant P (T)P At constant P, can show that T2 H = H (T2 , P ) H (T1, P ) = T1 C p dT where Cp is the specific heat at pressure constant Then T2 U = H ( PV ) = C p dT P {V2 V1} T1 Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating M for T at constant V (T)V At constant V, can show that T2 U = U (T2 , V ) U (T1, V ) = T1 Cv dT where Cv is the specific heat at constant specific volume Then T2 H = U + ( PV ) = Cv dT + V {P2 P } 1 T1 Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Heat Capacity Integrals C p tabulated for (s), (l), (v) as f(T); see, for example, Table B.2, p. 635 C p = a + bT + cT 2 + dT 3 T2 H = ( a + bT + cT 2 + dT 3 )dT T1 Must use form and units indicated Or can estimate by Kopps rule (Table B.10, p. 653) Cv: For IG, Cp Cv = R => Cv = (a R) + bT + cT2 + dT3 For non-ideal gases, generally a good approximation upto Pc (better estimates in Thermodynamics) For (l), (s): Cv ~ Cp Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating M for at constant T and P H = H (2 , T , P ) H (1, T , P ) = H -- Latent heat of phase change, a measurable quantity U = H ( PV ) = H P(V [2 , T , P ] V [1, T , P ]) 2 = ( v ), 1 = (l ) H vap , latent heat of vaporization 2 = (l ), 1 = ( s ) H fus , latent heat of fusion 2 = ( v ), 1 = ( s ) H sub , latent heat of sub lim ation Can show that, at constant T & P, Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Calculating M for at constant T and P - 2 H: Estimate, or use data sources Data sources: Table B-1 in F&R Other sources as described earlier Estimates: Use P*(T) data Clausius-Clayperon -> ln[P*] = - {H*/(RT)} + B For vaporization Troutons Rule Chens Equation Watsons Rule For fusion as f (Tm) Generally tabulated only at 1 atm, T2 (normal boiling point, etc.) At other T,P values - use sub-processes Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Example not at normal bp What is Hv for water at 200C (same as H for water from liquid to vapor at 200C)? only Hv at normal boiling point is tabulated take advantage of enthalpy as state function H for this change in state Hv (200C) 200C vapor T2 Tb 200C liquid Tb Cp L dT T1 C p dT v 100C liquid Hv (normal bp) 100C vapor is the sum of H values for these three changes in state Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz Example not at normal bp What is Hv for water at 200C? 200C liquid Tb Hv (200C) 200C vapor Cp T2 Tb L dT T1 C p dT v 100C liquid Hv (normal bp) 100C vapor 100 H = C pL dT + H v (Tnbp ) + C pv dT 100 positive numbers Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz negative number 200 200 Enthalpy Changes for Phase Transitions general result H L V = C pL dT + H v + C pv dT T1 take from initial T to boiling point vaporize Tb T2 Tb take from boiling point to final T If T1 = T2, this is Hv at T1 = T2 If T1 T2, this is H between liquid at T1 and vapor at T2 For condensation, reverse signs If going from (s) to (v), add fusion enthalpy and another integral Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz this is what is meant by a state function Sub-processes considered to date Change in pressure at constant temperature Change in temperature at constant pressure Change in T or P at constant volume Change in phase at constant P and T Mixing of pure components to multicomponent system at constant T and P (and reverse) Pure components in stoichiometric amounts reacting to form pure products(s) Copyright 2010 D.B. Dadyburjor and J. A. Shaeiwitz
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