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ch01-Actsc231

Course: MATH 235/237, Spring 2010
School: Waterloo
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1. Chapter The Growth of Money ACTSC231 Mathematics of Finance Department of Statistics and Actuarial Science University of Waterloo Fall 2010 Instructor: Chengguo Weng C. Weng (c2weng@uwaterloo.ca) p. 1/3 Interest (p10) Monday has time value investment opportunities theory. time preference theory. (p10) Interest is the payment by a borrower to a lender (investor) in return for the use of the capital....

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1. Chapter The Growth of Money ACTSC231 Mathematics of Finance Department of Statistics and Actuarial Science University of Waterloo Fall 2010 Instructor: Chengguo Weng C. Weng (c2weng@uwaterloo.ca) p. 1/3 Interest (p10) Monday has time value investment opportunities theory. time preference theory. (p10) Interest is the payment by a borrower to a lender (investor) in return for the use of the capital. Interest may be paid annually, monthly, weekly, or daily...... = continuously. The original sum invested (or borrowed) is the capital or principal. The total repaid is the principal plus interest. C. Weng (c2weng@uwaterloo.ca) p. 2/3 John lends Tom $10,000 for 5 years. Tom offers the following three options of repayments: Example 1.1. Opt1: Pay $10,500 at the end of 5 years. Opt2: Pay $100 at the end of each year, and repay the principal after 5 years. Opt3: Make payment of principal and interest of $2,100 at the end of each year. Which option is most favorable for John and which one is best for Tom? C. Weng (c2weng@uwaterloo.ca) p. 3/3 Accumulation Function (p11) Consider a single investment of $1 at time 0 without any withdrawal up to time t > 0 At time t, the accumulated value (or accumulation) of the investment is the total of the principal plus interest added. Notation: a(t) is used to denote the accumulation at time t of $1 invested at time 0. a(t) as a function of t is called accumulation function. a(0) = 1 if interest is positive, a(t) is an increasing function of t C. Weng (c2weng@uwaterloo.ca) p. 4/3 Amount Function (p11) We use AK (t) to denote the accumulated value at time t of $K invested at time 0. Is it true: AK (t) = K a(t)? It may not be true e.g. A bank account earns 3% if K 5000, and 2.5% otherwise. Unless stated otherwise, we generally assume AK (t) = K a(t). C. Weng (c2weng@uwaterloo.ca) p. 5/3 Example 1 of accumulation functions (p12-13) e.g.1. a(t) = 1 + 0.05t (simple interest). 5% of original capital is added each year, paid continuously. Graph of a(t): C. Weng (c2weng@uwaterloo.ca) p. 6/3 Example 2 of accumulation functions (p12-13) e.g.2. a(t) = 1 + 0.05t, where t denotes the oor of t, i.e. the integer part of t. interest is added only at the end of year Graph of a(t): C. Weng (c2weng@uwaterloo.ca) p. 7/3 Example 3 of accumulation functions (p12-13) e.g.3. a(t) = 1.05t (compound interest). 5% of the accumulation (capital+interest earned) is added continually. Graph of a(t): C. Weng (c2weng@uwaterloo.ca) p. 8/3 Simple Interest (p15) An investment accumulates with simple at rate i per time unit (e.g. one year) paid continuously if and only if a(t) = 1 + it, t 0. Example 1.2. Consider an investment of $500 for 5 years and suppose it earns simple interest at a rate of 10% per year payable continuously. What is its accumulation at time 4.25? What if the interest is added only at the end of year? C. Weng (c2weng@uwaterloo.ca) p. 9/3 Simple Interest (p15) Simple interest is inconsistent: Compare the following two investments by analyzing their accumulation at the end of 3 years: A: Invest $100 for 3 years to earn simple interest at a rate of 8% per year; B: Invest $100 for 1 year to earn simple interest at a rate of 8% per year; then withdraw the proceeds and reinvest it for 2 more years. Example 1.3. C. Weng (c2weng@uwaterloo.ca) p. 10/3 Compound interest (p19) An investment accumulates with compound interest at rate i per time unit (e.g. one year) if and only if a(t) = (1 + i)t , t 0. Compound interest is consistency: a(t + s) = a(t) a(s) C. Weng (c2weng@uwaterloo.ca) p. 11/3 Simple interest Versus compound interest Suppose you put $1,000 in a bank account which earn interest at a rate of 4% per annum. Example 1.4 How much is the account balance at the end of one year? How much is the balance at the end of 2 years? C. Weng (c2weng@uwaterloo.ca) p. 12/3 The Effective Interest Rate (p14) The effective interest rate on period [t1 , t2 ] is dened as i[t1 ,t2 ] a(t2 ) a(t1 ) interest earned on [t1 , t2 ] = = a(t1 ) capital at the beginning of the period ) in = a(na(na(n1) , for integer n. 1) in is the nth time unit. AK (t2 ) AK (t1 ) i[t1 ,t2 ] = AK (t1 ) Yes only when AK (t) = K a(t) (We usually assume this) ? Generally, it is still called interest rate, but maybe not effective interest rate C. Weng (c2weng@uwaterloo.ca) p. 13/3 Examples of effective interest rates a(t) = 1 + it (simple interest) in a(n) a(n 1) [1 + in] [1 + i(n 1)] = = a(n 1) 1 + i(n 1) i = , decreasing in n. 1 + i(n 1) a(t) = (1 + i)t (compound interest) in a(n) a(n 1) (1 + i)n (1 + i)(n1) = = = (1 + i) 1 (n1) a(n 1) (1 + i) = i, a constant for all n. C. Weng (c2weng@uwaterloo.ca) p. 14/3 Examples Example 1.5. Compare the proceeds of 20-year investment of $1,000 earning simple interest and compound interest. Assume the rate is 8% per year for both the simple interest and compound interest. You are given that $600 invested for 2 years accumulates to $864. What is the effective annual rate of interest? Example 1.6. C. Weng (c2weng@uwaterloo.ca) p. 15/3 Examples Example 1.7. An investor lends $1,000 at 10% of effective rate of interest and receives $2,000 after t years. Whats t? Example 1.8. An investor wants to buy a car which costs $12,000 in 1.5 years. How much should he/she invest now if he/she earns interest at 8% per year effective? C. Weng (c2weng@uwaterloo.ca) p. 16/3 Examples Suppose the investor in the above example can only invest $900 at time 0, and another $X at time 1. Find X . Example 1.9. An investor can get interest 4% per half year or 8.1% per year. Which is better for the investor? Example 1.10. C. Weng (c2weng@uwaterloo.ca) p. 17/3 Example: varying interest Deposit $1,000 at an account which earns interest at annual rate of 10% in rst year and 15% in the second year. Whats the balance at the end of 2 years? Example 1.11. C. Weng (c2weng@uwaterloo.ca) p. 18/3 Example:Present Value Suppose that Alice owes $1,000 due in 1 year. How much should she invest now (at time 0) to accumulate to exactly enough to pay her debt at time 1? Assume the effective annual rate of interest is i. Example 1.12. C. Weng (c2weng@uwaterloo.ca) p. 19/3 Present Value (p30) The amount invested at time 0 so as to accumulate to $C at time t is called the Present Value (PV) of $C at time t, denoted PV($C at t) 1 PVa(t) = C = PV= C a(t) Let v (t) = 1/a(t), then v (t) is called the discount function, so that the PV of $C due at time t is simply $C v (t) C. Weng (c2weng@uwaterloo.ca) p. 20/3 Discount Function (p28) In compound interest world: a(t) = (1 + i)t = v (t) = 1 1+i t 1 v := is called discount factor per time unit, 1+i e.g., annual discount factor, i.e. PV of $1 in 1 year. e.g., PV of $1,000 due in ve years is $1, 000 v 5 . e.g. PV of $P due in t years is $P v t . In simple interest world: 1 a(t) = (1 + ti) = v (t) = , not constant. 1 + it C. Weng (c2weng@uwaterloo.ca) p. 21/3 Geometric Series (progression) a + ar + ar2 + (n terms in total), where arst term, rcommon ratio and nnumber terms of a(1 rn ) a(rn 1) . Formula for sum: sum = = 1r r1 e.g. Find the sum of 1 + 2 + 4 + 8 + 16 + 32 e.g. Find the sum of 1 + x + x2 + + xn e.g. If |r| < 1, then limn rn = 0 and the sum a + ar + ar2 + (innitely many items) is a rst term = 1r 1 common ratio C. Weng (c2weng@uwaterloo.ca) p. 22/3 Example for PV Example 1.13. Paul invests $100 at the start of each month for 10 years. The interest is earned at 1% per month effective. 1) Calculate the accumulated value at time 10. 2) Calculate the present value at time 0. C. Weng (c2weng@uwaterloo.ca) p. 23/3 Example for PV Example 1.14. Paul invests $100 at the start of each month for 10 years. The interest is earned at 1% per month effective. 1) Calculate the accumulated value at time 10. 2) Calculate the present value at time 0. C. Weng (c2weng@uwaterloo.ca) p. 24/3 Example for PV Assume the interest is earned at 8% per year effective. Which of the following two cash ows has the higher value: A: 50 at time 0.5 and 50 at time 1.5. B: 100 at time 1. Example 1.15. C. Weng (c2weng@uwaterloo.ca) p. 25/3 Effective Rate of Discount If the borrower agrees to repay $X in one year after receiving $(1 d)X today, then d is called the annual effective rate of discount. In perspective of the lender: invest $(1 d)X today and receive $X after one year. D = dX is the discount amount, interest amount paid in advance instead of in arrear. e.g. A bank might loan you $1,000 at an annual discount rate of 8% by giving you $920 now and asking you to pay back $1,000 after one year. C. Weng (c2weng@uwaterloo.ca) p. 26/3 General Effective Rate of Discount (p27) Discount amount on interval [t1 , t2 ] is AK (t2 ) Ak (t1 ) Effective discount rate on [t1 , t2 ] is Discount Amount AK (t2 ) AK (t1 ) = Balance at the end AK (t2 ) a(t2 ) a(t1 ) , if AK (t) = K a(t). = a(t2 ) The EDR in the nth period is d[t2 t1 ] = dn = = AK (n) AK (n 1) AK (n) a(n) a(n 1) , if AK (t) = K a(t). a(n 1) C. Weng (c2weng@uwaterloo.ca) p. 27/3 Simple and Compound Discount Rates Simple discount rate Lender makes use of $(1 td)X and repay $X , where d is called (e.g., annual) simple discount rate 1 equivalently, a(t) = . 1 td Compound discount rate Lender makes use of $(1 d)t X and repay $X , where d is called (e.g., annual) compound discount rate equivalently, a(t) = X (1d)t . Equivalence: Rates of interest and discount are equivalent if any given amount of principle invested for any period accumulates to the same sum. C. Weng (c2weng@uwaterloo.ca) p. 28/3 Example Example 1.16. What an annual rate of compound interest is equivalent to a rate of compound discount of 6% per year for, respectively, (a) t = 2 and (b) t = 4? C. Weng (c2weng@uwaterloo.ca) p. 29/3 Some Facts Facts under equivalence principle: (1 + i)(1 d) = 1 d+v =1 d=iv C. Weng (c2weng@uwaterloo.ca) p. 30/3 Example Example 1.17. What an annual rate of compound interest is equivalent to a rate of simple interest at 6% per year effective for, respectively, (a) t = 2 and (b) t = 4? C. Weng (c2weng@uwaterloo.ca) p. 31/3 Nominal rate of interest (p43) In name only, not the real interest rate Interest of 4% per 0.5 year is expressed as an annual rate of 8%. But it equivalent to (1 + 4%)(1 + 4%) 1 = 8.16% In this case, we say: 8% is the annual nominal rate of interest convertible (or payable, or compounded) semi-annually notation: i (2) i(2) 1 = 0.08 per year effective 2 2 1+ i(2) 2 2 1 per year effective C. Weng (c2weng@uwaterloo.ca) p. 32/3 Example Example 1.18. If i = 10%, whats i(2) ? C. Weng (c2weng@uwaterloo.ca) p. 33/3 Nominal Rate of Interest (p46-47) (payable, or compounded) m times per year i(m) 1 (m) is denoted by i and is equivalent to an effective rate per years. m m If i is the equivalent annual effective rate of interest, then Nominal rate of interest convertible 1+i= 1+ e.g., m = 4: i (m) m m C. Weng (c2weng@uwaterloo.ca) p. 34/3 Nominal Rate of Interest(p46-47) i= 1+ i(m) m m 1 & i(m) = m (1 + i)1/m 1 Find the accumulated value of $5,000 invested for 5 years at a rate of i(4) = 5%. Example 1.19. C. Weng (c2weng@uwaterloo.ca) p. 35/3 Nominal Rate of Discount(p46-47) Nominal rate of discount convertible (payable, or compounded) m times per year d(m) 1 (m) is denoted by d and is equivalent to an effective rate per years. m m If d is the equivalent annual effective rate of discount, then d(m) 1 m which is the PV of $ in 1 year. e.g., m = 4: m = 1 d = v, C. Weng (c2weng@uwaterloo.ca) p. 36/3 Nominal Rate of Interest i(m) d=1 1 m Example 1.20. m & d(m) = m 1 (1 d)1/m Suppose interest is credited at an annual discount rate of 8% compounded quarterly. Find (1) Find AV of $5,000 invested for 5 years. (2) Find the PV of $1,000 due in 3 years. C. Weng (c2weng@uwaterloo.ca) p. 37/3 Nominal Rate of Interest Example 1.21. Given i(4) . Find the equivalent i, d and d(4) . Given the value of i. How to nd d(4) ? Relation i(m) between d(m) ? C. Weng (c2weng@uwaterloo.ca) p. 38/3 Force of Interest (p54) Force of Interest corresponding to a general accumulation function a(t) is dened as d 1 dat a (t) t = ln a(t) = = . dt a(t) dt a(t) Since da(t) = a(t + dt) a(t), the above display implies da(t) a(t + dt) a(t) = , t dt = a(t) a(t) which is the effective rate of interest on the innitesimal [t, t + dt]. Tow formulae a(t) v (t) = exp t 0 r dr t 0 = exp r dr C. Weng (c2weng@uwaterloo.ca) p. 39/3 Proof Proof of a(t) = exp t 0 r dr C. Weng (c2weng@uwaterloo.ca) p. 40/3 Constant Force of Interest (p54) In the compound interest world, a(t) = (1 + i)t . So ln a(t) = t ln(1 + i) and hence da(t) d t = = [t ln(1 + i)] = ln(1 + i), a constant. dt dt A fact: if i > 0 and m > 1, then i > i(m) > > d(m) > d; see p53. (p52) In fact, we have m lim i(m) = = lim d(m) . m t t2 Example 1.22. Given a(t) = a a nd t . C. Weng (c2weng@uwaterloo.ca) p. 41/3 Examples Example 1.23. given Calculate AV at time t=10 of $1,000 invested at time 0. You are 0.05, 0 < t 4; t = 0.06, 4 < t 10. C. Weng (c2weng@uwaterloo.ca) p. 42/3 Ination (58) Ination may be dened as the loss of purchasing power per dollar. Many measures. The most common one is Consumer Price Index (CPI) Suppose the index is Q(t) at time t. The rate of ination on period [t1 , t2 ] is dened by Q(t2 ) Q(t1 ) r[t1 ,t2 ] = Q(t1 ) e.g. Ination index Date Index Jan01,2006 121.5 June01,2006 125.3 Dec31,2006 142.7 r[0,1/2] r[1/2,1] = = 125.3 121.5 = 3.13% 121.5 142.7 125.3 = 13.89% 125.3 C. Weng (c2weng@uwaterloo.ca) p. 43/3 Example with Ination Let i be the effective annual rate of interest and r the annual ination rate. Then, the ination adjusted interest rate (the real interest rate) is dened as the value of j satisfying 1+i ir 1+j = , i.e., j = . 1+r 1+r Invest $1,000 for one year at an annual interest rate of 25% on Jan01,2006. The ination index is as in the previous slide. What is the real rate of interest over the 2006 year. Example 1.24. C. Weng (c2weng@uwaterloo.ca) p. 44/3
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Waterloo - MATH - 235/237
Chapter 2. Equations of Value and Yield RatesACTSC231 Mathematics of FinanceDepartment of Statistics and Actuarial Science University of Waterloo Fall 2010Instructor: Chengguo WengC. Weng (c2weng@uwaterloo.ca) p. 1/1Simple Eq. of ValueEq. of value
Waterloo - MATH - 235/237
t9&quot;/nT=TtA .(r)-1.6X,?&gt;+ft eJua4;vyg t- &lt; '=PZ.sJ- Va,/,u : &quot;;c We l'r&quot;.3ttl3,3^:c C i+t2;: &gt;) c : 3 r6 13, 3 &gt; ( / , o +)-t i $-.;_. da, d- .a -f'aoC- 4 ntl r t.rc&gt;= 467 ,V. v T =e .-&gt; ( t+;)- -( f fi)rx-/,o3:2 = n \P/.oT- - !_ -32469,V/=4o
Waterloo - MATH - 235/237
Solution to Problem Set 32 4Q1. P V = 100 exp 2 0t dt + 100 exp 0t dt4= 100 exp 0(0.05 + 0.01t)dt + 100 exp 0 2 t=0(0.05 + 0.01t)dt4 t=0= 100 exp 0.05t + 0.005t2+ 100 exp 0.05t + 0.005t2= 100 e0.12 + 100 e0.28 = 164.27. Q2. (i) A simple in
Waterloo - MATH - 235/237
Problem Set 4: ACTSC 231 Mathematics of Finance, Fall 2010 Q1. (a) Noticing formulae sn i+ 1 sn = i+i i(1 + i)n 1 1 vn = and an i = , we immediately have i i 1(1+i)n 1 i(1+i)ni [(1 + i)n 1] + i i(1 + i)n i = = = (1 + i)n 1 (1 + i)n 1 (1 + i)n 1 = 1 .
Waterloo - MATH - 235/237
Problem Set 5-solution: ACTSC 231 Mathematics of Finance, Fall 2010 Q1. The present value of this perpetuity-due is 1, 000v n = 6, 561; a where v = 9/10 i.e. d = 1/10. We know that = 1/d = 10. Thus, a n= ln(6, 561/10, 000) = 4. ln 0.9Q2. We rst need to n
Waterloo - MATH - 235/237
Math 235 1. Short Answer ProblemsTerm Test 1 Solutions[2] a) By considering the dimension of the range or null space, determine the rank and p(0) the nullity of the linear mapping T : P2 R2 , where T (p(x) = . p(1) Solution: Range(T ) = R2 since T (1 x)
Waterloo - MATH - 235/237
Math 235 1. Short Answer ProblemsTerm Test 2 Solutions[2] a) Let B = cfw_v1 , . . . , vk be an orthonormal basis for a subspace S of an inner product space V . Dene projS and perpS . Solution: Let v V , then projS (v ) and perpS (v ) are the unique vec
Waterloo - MATH - 235/237
Math 235Assignment 0Due: Not To Be Submitted1. Determine projv x and perpv x where a) v = (2, 3, 2) and x = (4, 1, 3). b) v = (1, 2, 1, 3) and x = (2, 1, 2, 1). 2. Prove algebraically that projv (x) and perpv x are orthogonal. 3. Solve the system z1 (1
Waterloo - MATH - 235/237
Math 235Assignment 1Due: Wednesday, May 12th1. Let A be an m n matrix and B be an n p matrix. a) Prove that rank(AB ) rank(A). b) Prove that rank(AB ) rank(B ). c) Prove that if B is invertible, then rank(AB ) = rank(A). 2. Let T : V W be a linear mapp
Waterloo - MATH - 235/237
Math 235Assignment 1 Solutions1. Let A be an m n matrix and B be an n p matrix. a) Prove that rank(AB ) rank(A). Solution: Since the rank of a matrix is equal to the dimension of its column space, we consider the column space of A and AB . Observe that
Waterloo - MATH - 235/237
Waterloo - MATH - 235/237
Math 235Assignment 2 Solutions1. For each of the following linear transformations, determine a geometrically natural basis B and determine the matrix of the transformation with respect to B . a) perp(2,1,2) Solution: Pick v1 = (2, 1, 2). We want to pick
Waterloo - MATH - 235/237
Math 235Assignment 3Due: Wednesday, May 26th1. For each of the following pairs of vector spaces, dene an explicit isomorphism to establish that the spaces are isomorphic. Prove that your map is an isomorphism. a) P3 and R4 . b) The vector space P = cfw
Waterloo - MATH - 235/237
Math 235Assignment 3 Solutions1. For each of the following pairs of vector spaces, dene an explicit isomorphism to establish that the spaces are isomorphic. Prove that your map is an isomorphism. a) P3 and R4 . Solution: We dene L : P3 R4 by L(a3 x3 + a
Waterloo - MATH - 235/237
Math 235Assignment 4Due: Wednesday, Jun 2nd1. Prove that the product of two orthogonal matrices is an orthogonal matrix. 2. Prove that if R is an orthogonal matrix, then det R = 1. Give an example of a matrix A that has det A = 1, but is not orthogonal
Waterloo - MATH - 235/237
Math 235Assignment 4 Solutions1. Prove that the product of two orthogonal matrices is an orthogonal matrix. Solution: Let P and Q be orthogonal matrices. Then we have (P Q)T (P Q) = QT P T P Q = QT Q = I, since P T P = I and QT Q = I . Thus P Q is also
Waterloo - MATH - 235/237
Waterloo - MATH - 235/237
Math 235Assignment 5 Solutionsa) Use the Gram-Schmidt process to produce an orthonormal basis for S . 2 1 1 0 1 0 Solution: Denote the given basis by z1 = , z2 = , z3 = . Let w1 = z1 . 1 1 1 1 1 1, 1 2 1 1 1 0 1 3 z2 w1 Then, we get w2 = z2 projw1 (z2 )
Waterloo - MATH - 235/237
Waterloo - MATH - 235/237
Math 235Assignment 6 Solutions1. Show that the following are equivalent for a symmetric matrix A: (1) A is orthogonal (2) A2 = I (3) All the eigenvalues of A are 1 Solution: (1) (2) (2) (3) If A is orthogonal then I = AAT = AA, since A is symmetric. Av
Waterloo - MATH - 235/237
Math 235Assignment 7Due: Wednesday, June 30th1. For each quadratic form Q(x), determine the corresponding symmetric matrix A. By diagonalizing A, Write Q so that it has no cross terms and give the change of variables which brings it into this form. Cla
Waterloo - MATH - 235/237
Math 235Assignment 7 Solutions1. For each quadratic form Q(x), determine the corresponding symmetric matrix A. By diagonalizing A, Write Q so that it has no cross terms and give the change of variables which brings it into this form. Classify each quadr
Waterloo - MATH - 235/237
Waterloo - MATH - 235/237
Math 235Assignment 8Due: Wednesday, July 14th1. Sketch the graph of 9x2 + 4xy + 6y 2 = 21 showing both the original and new axes. Solution: The corresponding symmetric matrix is polynomial is C ( ) = 9 2 = 2 15 + 50 = ( 10)( 5). 2 6 A 1 I = 1 2 1 2 . 2
Waterloo - MATH - 235/237
Math 235Assignment 9Due: Wednesday, July 21st1. Suppose that a real 2 2 matrix A has 2 + i as an eigenvalue with a corresponding 1+i eigenvector . Determine A. i 0 2 1 2. Determine a real canonical form of A = 2 2 1 and give a change of basis matrix 0
Waterloo - MATH - 235/237
Math 235Assignment 9 Solutions1. Suppose that a real 2 2 matrix A has 2 + i as an eigenvalue with a corresponding 1+i eigenvector . Determine A. i Solution: Since A is real, we know that A has real canonical form B = brought into this form by P = 11 . W
Waterloo - MATH - 235/237
Math 235Assignment 10 Not To Be Submitted 1+i 1i 1. Consider C3 with its standard inner product. Let z = 2 i , w = 2 3i. 1 + i 1 a) Evaluate z , w and w, 2iz . b) Find a vector in spancfw_z, w that is orthogonal to z . c) Write the formula for the proj
Waterloo - MATH - 235/237
Math 235Assignment 10 Solutions 1+i 1i 1. Consider C3 with its standard inner product. Let z = 2 i , w = 2 3i. 1 + i 1 a) Evaluate z , w and w, 2iz . Solution: We have z , w = (1 + i)(1 + i) + (2 i)(2 + 3i) + (1 + i)(1) = 2i 1 + 8i + 1 i = 9i w, 2iz =
Waterloo - MATH - 235/237
Math 235 - Final Exam Fall 2009NOTE: The questions on this exam does not exactly reect which questions will be on this terms exam. That is, some questions asked on this exam may not be asked on our exam and there may be some questions on our exam not ask
Waterloo - MATH - 235/237
Math 235Final F09 AnswersNOTE: These are only answers to the problems and not full solutions! On the nal exam you will be expected to show all steps used to obtain your answer. 1. Short Answer Problems 3 i i a) A = . 2 1 b) A is Hermitian since A = A, a
Waterloo - MATH - 235/237
Math 235 - Final Exam Spring 2009NOTE: The questions on this exam does not exactly reect which questions will be on this terms exam. That is, some questions asked on this exam may not be asked on our exam and there may be some questions on our exam not a
Waterloo - MATH - 235/237
Math 235Final S09 AnswersNOTE: These are only answers to the problems and not full solutions! On the nal exam you will be expected to show all steps used to obtain your answer. 1. a) A basis for the nullspace is cfw_x, hence the nullity of L is 1. Thus,
Waterloo - MATH - 235/237
Math 235Final Exam InformationThursday August 5, 9:00 AM - 11:30 AMLOCATION: PAC 1, 2, 3Material Covered: Entire Course, with an emphasis on material after term test 2. Information: - Surfaces in R3 are not covered. - Fourier Series are not covered. -
Waterloo - MATH - 235/237
Math 235 1. Short Answer ProblemsSample Term Test 1 - 1a) Give the denition of an inner product , on a vector space V . b) Let B = cfw_v1 , . . . , vn be orthonormal in an inner product space V and let v V such that v = a1 v1 + + an vn . Prove that ai
Waterloo - MATH - 235/237
Math 235Sample Term Test 1 - 1 AnswersNOTE: - Only answers are provided here (and some proofs). On the test you must provide full and complete solutions to receive full marks. 1. Short Answer Problems a) Give the denition of an inner product , on a vect
Waterloo - MATH - 235/237
Math 235 1. Short Answer ProblemsSample Term Test 1 - 2 1 0 0 1 a) Write a basis for the rowspace, columnspace and nullspace of A = 0 0 1 1 . 000 0 b) Let B = cfw_v1 , . . . , vn be orthonormal in an inner product space V and let v = a1 v1 + + an vn .
Waterloo - MATH - 235/237
Math 235Sample Term Test 1 - 2 AnswersNOTE: - Only answers are provided here (and some proofs). On the test you must provide full and complete solutions to receive full marks. 1. Short Answer Problems 1 0 0 1 a) Let A = 0 0 1 1 . Write a basis for the R
Waterloo - MATH - 235/237
Math 235 1. Short Answer ProblemsSample Term Test 2 - 1a) Let S be a subspace of an inner product space V . What is the denition of S . b) State the Principal Axis Theorem. c) Determine the matrix for the quadratic form Q(x, y, z ) = 3x2 y 2 + z 2 2xy +
Waterloo - MATH - 235/237
Math 235Sample Term Test 2 - 1 AnswersNOTE: - Only answers are provided here (and some proofs). On the test you must provide full and complete solutions to receive full marks. 1. Short Answer Problems a) Let S be a subspace of an inner product space V .
Waterloo - MATH - 235/237
Math 235 1. Short Answer ProblemsSample Term Test 2 - 2a) State the Principal Axis Theorem. b) Let A be an m n matrix. Prove that AT A is symmetric. c) State the denition of a quadratic form Q(x) on Rn being negative denite. d) Consider the quadratic fo
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Math 235Sample Term Test 2 - 2 AnswersNOTE: - Only answers are provided here (and some proofs). On the test you must provide full and complete solutions to receive full marks. 1. Short Answer Problems a) State the Principal Axis Theorem. Solution: A mat
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Math 235Midterm InformationTuesday, June 8th, 4:30 - 6:20 p.mMaterial Covered: Sections 4-5, 4-6, 4-7, 7-4 (not including Fourier series), 7-1. You need to know: - All denitions and statements of theorems. - How to nd a basis of the rowspace, column sp
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Math 235Term Test 2 InformationTuesday, July 6th, 4:30 - 6:20 p.mRoom Assignments: MC 4059: A - G MC 4061: H - Lin MC 4045: Liu - P MC 4020: Q - Wang MC 4021 Wardell - Z Material Covered: Sections 7-2, 7-3, Triangularization, 8-1, 8-2. You need to know
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Math 235Tutorial: Term Test 1 Review1: State the denition of: a) One-to-one b) Onto c) An orthogonal matrix (what are 2 other equivalent denitions?) d) An inner product 1 0 1/2 1/2 1/2 1/2 , , 2 1 1/2 1/2 1/2 1/2 0 2 T under the inner product A, B = tr
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SOSMATH235MIDTERM2REVIEWPACKAGE HelloMATH235students,mynameisTaiCaiandIamtheSOStutorthistermforMATH235.This packageisdesignedtosupplementyourstudyingforthesecondmidtermonNovember16,2010. Wheneverpossible,Ihaveincludedexamplesthatarenotfromclassoryourtextb
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Math 235 1. Short Answer ProblemsTerm Test 1 Solutions[1] a) State the denition of the rank of a linear mapping L : V W . Solution: rank(L) = dim Range(L).[2] b) Let B = cfw_v1 , . . . , vn be a basis for a vector space V and let L : V W be an isomorp
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Math 235 31 5 2 1. Let A = 2 1 32 4 7 1 5 2 3 3 2Assignment 1Due: Wednesday, Sept 22nd 0 1 0 0 1 1 0 0 01 0 2 . 1 1 00 3 1 0 4 , then the RREF of A is R = 0 7 1 0a) Find rank(A) and dim(Null(A). b) Find a basis for Row(A). c) Find a basis for Null(A).
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Math 235 31 5 2 1. Let A = 2 1 32 4 7 1 5 2 3 3 2Assignment 1 Solutions 3 1 0 4 , then the RREF of A is R = 0 7 1 0 0 1 0 0 1 1 0 0 01 0 2 . 1 1 00a) Find rank(A) and dim(Null(A). Solution: rank(A) = 3 and dim(Null(A) = 5 3 = 2 b) Find a basis for Row(A
Waterloo - MATH - 235/237
Waterloo - MATH - 235/237
Math 235Assignment 2 Solutions1. For each of the following linear transformations, determine a geometrically natural basis B and determine the matrix of the transformation with respect to B . a) The projection proj(3,2) : R2 R2 onto the line x = t Solut
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Math 235Assignment 3Due: Wednesday, Oct 6th1. For each of the following pairs of vector spaces, dene an explicit isomorphism to establish that the spaces are isomorphic. Prove that your map is an isomorphism. a) M (2, 2) and P3 . b) The vector space P
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Math 235Assignment 3 Solutions1. For each of the following pairs of vector spaces, dene an explicit isomorphism to establish that the spaces are isomorphic. Prove that your map is an isomorphism. a) M (2, 2) and P3 . Solution: We dene L : M (2, 2) P3 by
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Math 235Assignment 4Due: Wednesday, Oct 13th1. Prove that the product of two orthogonal matrices is an orthogonal matrix. 2. Observe that the dot product of two vectors x, y Rn can be written as x y = xT y. Use this fact to prove that if an n n matrix
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Math 235Assignment 4 Solutions1. Prove that the product of two orthogonal matrices is an orthogonal matrix. Solution: Let P and Q be orthogonal matrices. Then we have (P Q)T (P Q) = QT P T P Q = QT Q = I, since P T P = I and QT Q = I . Thus P Q is also
Waterloo - MATH - 235/237
Waterloo - MATH - 235/237
Math 235Assignment 5 Solutions1. On M (2, 2) dene the inner product &lt; A, B &gt;= tr(B T A) and let S = Span 10 01 1 1 , , 01 10 01 .a) a) Use the Gram-Schmidt procedure to produce an orthonormal basis for S . 10 and 01 are already orthogonal. Then 2 1 1 v
Waterloo - MATH - 235/237
Waterloo - MATH - 235/237
Math 235 1 1. Let A = 2 4 diagonalizes A 2 2 2 andAssignment 6 Solutions 4 2. Find an orthogonal matrix P that 1 the corresponding diagonal matrix.Solution: The characteristic polynomails is 1 2 4 1 2 4 2 2 = det 2 2 2 C () = det(A I ) = det 2 4 2 1 3 0
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Math 235Assignment 7Due: Wednesday, Nov 10th1. For each quadratic form Q(x), determine the corresponding symmetric matrix A. By diagonalizing A, Write Q so that it has no cross terms and give the change of variables which brings it into this form. Clas
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Math 235Assignment 7 Solutions1. For each quadratic form Q(x), determine the corresponding symmetric matrix A. By diagonalizing A, Write Q so that it has no cross terms and give the change of variables which brings it into this form. Classify each quadr
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MATH237: EXAM-AID SOSNIALL W. MACGILLIVRAY (EDITOR); VINCENT CHAN (WRITER)1.October 31st, 2010 ScalarFunctions(1.1 1.2)DEFINITION 1.1. Suppose A and B are sets. A function f is a rule that determines how a subset of A is associated with a subset of B