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Oregon Tech - HIST - 2882
Modern Era1750-19141. Which of the following was not a characteristic of the Industrial Revolution? a) capitalism replaces mercantilism as dominant political philosophy b) mass production of goods due to advancement in machinery c) civilizations replace
Oregon Tech - HIST - 2882
Unit 5 Take-Home Exam1. Which of the following was not a characteristic of Western modernization in the 20th century? a) postindustrial economies that emphasize services, consumerism and cutting-edge technology b) hesitance to support social welfare prog
Oregon Tech - HIST - 2882
1914 to Present1914Present Major Developments I. Questions of periodization A. Continuities and breaks 1. Most tumultuous eras in world history a. age of extremes 1. Tons of democracies vs. extremist dictatorships 2. Unprecedented prosperity vs. total po
Oregon Tech - HIST - 2882
600 C.E.1450I. Questions of periodization A. Nature and causes of changes in the world history framework leading up to 600 C.E. 1450 as a period B. Emergence of new empires and political systems C. Continuities and breaks within the period (e.g., the imp
UT Arlington - GEOL - 4320
Aquifer Tests Lecture 8(Max) Qinhong Hu Hydrogeology (GEOL 4320 and 5328) Fall 2009Outline Water flow in confined aquifers Water flow in unconfined aquifers flow in unconfined aquifers Steady radial flow to a well Unsteady radial flow in a confined aq
UT Arlington - GEOL - 4320
Slug Tests and Others Lecture 9(Max) Qinhong Hu Hydrogeology (GEOL 4320 and 5328) Fall 2009Outline Slug tests Confined aquifers Unconfined aquifersWell flow near aquifer boundaries Multiple well systems well systems Partially penetrating wells Desig
UT Arlington - GEOL - 4320
Hydraulic Conductivity Lecture 4(Max) Qinhong Hu Hydrogeology (GEOL 4320 and 5328) Fall 2009Outline Hydraulic conductivity Approaches to measuring hydraulic co conductivity Examples of porosity and conductivity of some rocks Heterogeneity and anisotro
UT Arlington - GEOL - 4320
Aquifers Lecture 5(Max) Qinhong Hu Hydrogeology (GEOL 4320 and 5328) Fall 2009Outline Aquifers Aquifer materials and particle-size di distribution Major aquifers of the United States aq of the United States2Aquifer Latin origin; aqua (water) and fe
UT Arlington - GEOL - 4320
Groundwater Movement Lecture 6(Max) Qinhong Hu Hydrogeology (GEOL 4320 and 5328) Fall 2009Potential Field Trip (Geology, Hydro, Geochem) With students in Environ Geochem class E Nov. 5 - 12 Leave on Thur. night, back in a week Day 1: 15-hr drive to ea
UT Arlington - GEOL - 4320
Students Name: GEOL 4320/5328 Hydrogeology Fall 2009Homework Problem Set #3 (15 points)(Due: Sep. 30, 2009)1. (3 points) The hydraulic conductivity of medium-sized sand was measured as 11.2 m/day in a laboratory test with water at 25C. (A) What is the
UT Arlington - GEOL - 4320
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CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 1: Introduction Dr. Pengfei Zhang Introduction The Woburn SiteAberjona RiverFigure 1-1. Aerial photo showing the locations of Well G, Well H, Beatrice Foods, and W. R. Grace (Courtesy of Scott Bair).1-1The city
CUNY City - EAS - 44600
EAS44600 Groundwater Hydrology Lecture 2: The Hydrologic Cycle Dr. Pengfei Zhang Water Water exists in three phases: liquid, solid, and vapor. On the phase diagram (Figure 2-1), the point at which vapor, solid, and liquid all exist in equilibrium is calle
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 4: Porosity and Permeability Dr. Pengfei Zhang Porosity of Earth Materials The porosity of earth materials is defined as the part of rock or soil that is void space, often expressed as a percentage: V n= v (4-1) VT
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 5: Hydraulic Head and Fluid Potential Dr. Pengfei Zhang Darcys Experiment The first studies of the movement of water through rock and sediment were performed by the French engineer Henry Darcy. Darcy used a column f
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 6: Darcys Law and Hydraulic Conductivity Dr. Pengfei Zhang Darcys Law We discussed Darcys experiment in last lecture and now let us go back to Darcys law:h h dh Q = KA a b = KA L dl (6-1)The quantity dh represent
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 7: Heterogeneity and Anisotropy Dr. Pengfei Zhang Heterogeneity and Anisotropy Hydrologic properties (hydraulic conductivity, specific storage, etc.) may vary through space within a geological formation. The spatial
CUNY City - EAS - 44600
EAS44600 Groundwater Hydrology Lecture 8: Storage Properties of Aquifers Dr. Pengfei Zhang Moisture Content Recall that the porosity (n) of earth materials is the ratio of the volume of the voids (Vv) to the total volume (VT) of the sample. The volume of
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 9: Flow Nets Dr. Pengfei Zhang Specific Discharge and Average Linear Velocity Recall Darcys law:h h dh Q = KA a b = KA L dl (9-1)It states that the flow (discharge) will be proportional to the hydraulic gradient
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 10: Equations of Groundwater Flow Dr. Pengfei Zhang Equations of Groundwater Flow Groundwater flow can be described by partial differential equations where the spatial coordinates, x, y, z, and time, t, are the inde
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 11: Regional Groundwater Flow Dr. Pengfei Zhang Steady Regional Groundwater Flow in Unconfined Aquifers A groundwater basin is defined as a three-dimensional closed system through which groundwater flows from areas
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 12: Well Hydraulics 1 Dr. Pengfei Zhang Radial Flow to a Well The exploitation of a groundwater basin leads to water-level declines that limit the yields of the basin. Therefore, one of the primary goals of groundwa
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 13: Well Hydraulics 2 Dr. Pengfei Zhang Determining Aquifer Parameters from Time-Drawdown Data In the past lecture we discussed how to calculate drawdown if we know the hydrologic properties of the aquifer. These hy
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 14: Water Chemistry 1 Dr. Pengfei Zhang Concentration Units Molar concentration (M) defines the number of moles of a chemical species in one liter of solution (mol/L). One mole (mol) of a substance is its formula we
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 15: Water Chemistry 2 Dr. Pengfei Zhang Carbonate Chemistry In non-urban, non-industrial areas, the pH of rain and melted snow falls in the range between 5 and 6. This pH results from equilibration of precipitation
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 16: Solute Transport in Saturated Media Dr. Pengfei Zhang Introduction In this lecture we will discuss the transport of dissolved solutes in groundwater, the so-called mass transport or solute transport. The transpo
CUNY City - EAS - 44600
EAS 44600 Groundwater Hydrology Lecture 17: Contaminant Hydrology 1 Dr. Pengfei Zhang Types of Groundwater Contaminants A wide variety of contaminants have been found in groundwater. These include inorganic cations (e.g., heavy metals), inorganic anions (
UT Arlington - CHEM - 1442
1442 Answers to final review 1. 11M = 11 moles/L of solution H2SO4 = 11(98.1) = 1079.1 g/ L of solution 1 L of solution has a mass of : (1000ml)(1.59 g/ml) = 1590g per Liter of solution Mass% H2SO4 = Part/whole X 100 = 1079.1 g/1590g X 100 = 67.9 % 2. I.
UT Arlington - CHEM - 1442
Answers Test 1 Chapters 12 & 13 Intermolecular Attractions and Properties of Solutions (Silberburg) 1. (a) Hydrogen Bonding (b) London Dispersion (c) ion-ion (d) dipole-dipole (e) London 2. (d) the only one that is non-polar. CH4 is non-polar. Likes disso
UT Arlington - CHEM - 1442
1442 Test 2 Chapters 16 & 17 Kinetics and Keq website: http:/dipowell1.home.mindspring.com ( last item after powell is the number one)1.[ratio M]a [ratio M]b = ratio of rates Using experiment 1 & 2 : [.1M/.1M]a [.2M/.3M]b = 0.004 M/s/0.0135 M/s Since th
UT Arlington - CHEM - 1442
Answers: 1442 Test 3 Chapters 18 and 19 1. pH = -log[H+] 3.4 = - log[H+] -3.4 = log[H+] [H+] = 3.98 X 10-4 ( enter -3.4 and hit 2nd log on the calculator) pOH = -log[OH] = -log[1.2 X 10-6] = 5.9 pH + pOH = 14 pH + 5.92 = 14 pH = 8.08 3. 4. 5. HBr H+ + Br-
UT Arlington - CHEM - 1442
Answers Test 4 Chapters 20 and 21 Silberberg 1. 2. c (1g CH4/1)( 1 mol CH4/ 16g)(891 kJ/ 1 mole CH4)* = 55.7 kJ The conversion factor 891 kJ/ 1 mole comes from the coefficient in the balanced equation. You will notice that the answer is usualy expressed a
UT Arlington - CHEM - 1442
1442 Final Reviewwebsite: http:/dipowell1.home.mindspring.com The final review will be different from previous reviews. You need to work the problems and come with questions. There will be no lecture, just questions answered. If you need to know the date
UT Arlington - CHEM - 1442
1442 Text One Chapters 12 & 13 Intermolecular Forces, Properties of Solutions (Silberberg) website: http:/dipowell1.home.mindspring.com R = 0.08206 L.atm/mol.K = 8.314 J/mol.K 1 atm = 760 torr = 760 mm HgUseful Information:Psoln = (Psolv) (Xsolv) Tf = i
UT Arlington - CHEM - 1442
1442 Test 2 Chapters 16 & 17 Kinetics and Equilibrium (Silberberg) website: http:/dipowell1.home.mindspring.com Useful Information: ln [A]o / [At] = kt 1st order 1 / [A]t 1 / [A]o = kt 2nd order t 12 = ln 2 k t 12 = 1 k[A]oln k2 / k1 = - Ea /R (1 / T2 1
UT Arlington - CHEM - 1442
1442 Test 3 Chapters 18 and 19 Silberberg Website: http:/dipowell.home.mindspring.com pH = -log [H+] pOH = -log [OH] pH + pOH = 14 [H+][OH-] = 1 x 10-14Ka X Kb = 1 X 10-14 Simple pH problemspH = pKa + log [base] / [acid]_1. PH = 3.4, H+ =_ (3.98 X 10-4
UT Arlington - CHEM - 1442
1442 Review Test 4 Chapters 20 and 21 Website: http:/dipowell1.home.mindspring.com Equations: Hreaction = H products - H reactants ( Also works for S and G) G = H - TS G = Go + RT lnQ G = -RT lnK ( R = 8.314 J/mol.K) Ecell = E oxidation + E reduction logK
UT Arlington - CHEM - 1442
Cut to the Chase: Acid, Base, and Buffer Problems When working Acid, base, and buffer problems, approach it as if there are only two types of problems. PROBLEM TYPE I means there will be no X in the problem. It is a limiting reactant problem. It is easy t
UT Arlington - CHEM - 1442
Cut to the Chase: Balancing Redox Equations Rules for Balancing Redox Equations 1. 2. 3. 4. 5. 6. 7. Write the two half-reactions Balance all elements except O and H Balance O with waters Balance H with H+ Balance the charge with electrons (e-1) Multiply
UT Arlington - CHEM - 1442
Cut to the Chase Equilibrium Problems When teaching equilibrium problems, consider teaching it as if there are only two types of problems. Some problems have X in them and you solve for X. Some problems will have no X in them. In both cases you start the
UT Arlington - CHEM - 1442
Cut to the Chase: Intermolecular Attractions I. Intermolecular attractions from strongest to weakest A. Ion-Ion- Ionic compounds (metal/non-metal) B. Hydrogen Bonding- Compounds containing H attached to N, O, or F C. Dipole-Dipole- polar compounds D. Lond
UT Arlington - CHEM - 1442
Cut to the Chase: Kinetics I. Derive the rate Law A. By definition, the rate law for the reaction : 2 A + 3 B 5 C is: Rate = k [ A] a [ B] b Where a and b are called orders of reaction. Note that rate laws are written using the reactants. The orders of re
UT Arlington - CHEM - 1442
Cut to the Chase: Ksp Dissolving Participates When deciding if a solvent will make a precipitate dissolve, you should use LeChateliers Principle to answer the question. One of two situations will exist. Either the solvent will have a common ion with the p
UT Arlington - CHEM - 1442
Kinetics: Consistent Mechanism and Intermediates Consider the following reaction: H2(g) + 2ICl(g) 2HCl(g) + I2(g) The rate law for this reaction was determined to be R = k [H2][ICl]. Is the following proposed mechanism consistent with the above data? H2(g
UT Arlington - CHEM - 1442
Cut to the Chase: Predicting Products of Chemical Reactions When trying to predict the products of a chemical reaction, remember that many of them will be first year equations and will fit into the neat categories: displacement, double displacement, synth
UT Arlington - CHEM - 1442
Cut to the chase: Quantitative Electrolysis Problems One Faraday is a mole of electrons. If you think of it this way, then electrolysis problems will be very simple. Example: A current of 2.5 amps is run through a solution containing Cu2+ ions for 50 minu
UT Arlington - CHEM - 1442
Chapter 3 Stoichiometric Problems Titration Problems: If it takes 30 ml of .3 M NaOH to exactly neutralize 50 ml of H3PO4, what is the M of the acid? Rather then dimensional analysis, consider just multiplying M X V to get moles. Then change moles of NaOH
UT Arlington - CHEM - 1442
Colligative Properties: vant Hoff Factor The equation for freezing point depression and boiling point elevation contains the letter i. i stands for the vant Hoff Factor. T = imKf Since freezing point depression and boiling point elevation depend only on t
UT Arlington - CHEM - 1442
Cut to the Chase: Writing Reactions for Acid, Base, and Buffer Problems 1. 2. the Buffer problem: weak acid and conjugate base. Begin with weak acid. HF H+ + FA buffer to which a strong acid or base has been added. If a strong acid is added, base part of
UT Arlington - CHEM - 1442
X.Liquids, Solids, and Intermolecular AttractionsUse the following answers to answer questions 1 and 3. (A) A network solid with covalent bonding (B) A molecular solid with zero dipole moment (C) A molecular solid with hydrogen bonding (D) an ionic soli
UT Arlington - CHEM - 1442
XI. Solutions, M, m, and Colligative Properties1. The molality of the glucose in a 1.0-molar glucose solution can be obtained by using which of the following? (A) volume of the solution (B) temperature of the solution (C) solubility of glucose in water (
UT Arlington - CHEM - 1442
XII. Thermodynamics1. CH4(g) + 2 O2(g) CO2(g) + 2H2O(l) Ho = -889.1 kJ Hfo H2O(l) = -285.8 kJ Hfo CO2(g) = -393.3 kJ What is the standard heat of formation of methane, Hfo CH4(g), as calculated from the data above? (A) -210.0 kJ/mole (B) 107.5 kJ/mole (C
UT Arlington - CHEM - 1442
XIII. Kinetics1. For the reaction whose rate law is given below, a plot of which of the following is a straight line? Rate=k[X] (A) [X] versus time (B) ln[X] versus time (C) 1/[X] versus time (D) [X] versus 1/time (E) ln[X] versus 1/time Answer: B For th
UT Arlington - CHEM - 1442
XIV. Equilibrium1. Cu(s) + 2Ag+ Cu2+ + 2Ag(s) If the equilibrium constant for the reaction above is 3.7x1015, which of the following correctly describes the standard voltage, Eo and the standard free energy change, Go, for this reaction? (A) Eo is positi
UT Arlington - CHEM - 1442
XV. Electrochemistry, RedoxUse the following answers for questions 1 4 (A) voltage increases (B) voltage decreases but remains above zero (C) voltage becomes zero and remains at zero (D) no change in voltage occurs (E) Direction of voltage change cannot
UT Arlington - CHEM - 1442
Nuclear Chemistry Worksheet Chapter 30Do problems 26 and 32 before trying the problems below. Questions 1-7 below are from old AP Exams. 1. When 214/84 Po decays, the emission consists consecutively of an particle, the two particles, and finally another
UT Arlington - CHEM - 1442
XVII.1.Descriptive Chemistry, Lab Procedures and MiscellaneousA 0.1 M solution of which of the following ions is orange? (A) Fe(H2O)42+ (B) Cu(NH3)42+ (C) Zn(OH)42+ (D) Zn(NH3)42+ (E) Cr2O72Answer: E The addition of an oxidizing agent such as chlorine
UT Arlington - CHEM - 1442
XVIII.1.Organic ChemistryThe alkenes are compounds of carbon and hydrogen with the general formula CnH2n. If 0.561 g of any alkene is burned in excess oxygen, what number of moles of water is formed? (A) 0.04 (B) 0.06 (C) 0.08 (D) 0.4 (E) 0.8 Answer: A
UT Arlington - CHEM - 3302
Chapter 13: Molarity, % Mass, and Dilution Problems Molarity ( M ) _1. What is the M of a solution made by mixing 60 g of NaCl and enough water to make the total volume 390 ml? (2.6)_2. How many grams of NaOH are contained in a 400 ml of 3 M NaOH? (48)_
UT Arlington - CHEM - 3302
Answers to ChemActivity 1 The Nuclear Atom- Chapter 5 1. 2. 3. 4. 6 6,7,7 6,6,7 (a) neutral same e and p, ion different e and p (b) assign +1 to each proton and -1 to each electron and take the difference. If more -1 it is a negative ion, if more +1 it is
UT Arlington - CHEM - 3302
Beanium Using various beans, determine the atomic mass of the new element Beanium. Solving the problem: If a student counts 39 red beans (mass number 35) and 102 white beans (mass number 39) the calculation is as follows. % of red = 39 / 141 X 100 = 28% %