Chapter 08
57 Pages

Chapter 08

Course Number: FIN 3604, Spring 2010

College/University: USF

Word Count: 18284

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Chapter 8Segmenting and Targeting Markets TRUE/FALSE 1. Fisher-Price developed a line of toys for infants in China. Babies make up the market for these products. ANS: F Infants cant make purchases and, therefore, cannot be called a market. Their parents would constitute a market. PTS: 1 REF: 117 OBJ: 08-1 TYPE: App TOP: AACSB Reflective Thinking | TB&E Model Customer 2. Fisher-Price is identifying Asian...

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Chapter 8Segmenting and Targeting Markets TRUE/FALSE 1. Fisher-Price developed a line of toys for infants in China. Babies make up the market for these products. ANS: F Infants cant make purchases and, therefore, cannot be called a market. Their parents would constitute a market. PTS: 1 REF: 117 OBJ: 08-1 TYPE: App TOP: AACSB Reflective Thinking | TB&E Model Customer 2. Fisher-Price is identifying Asian markets that are interested in their line of talking toys. Fisher-Price is engaged in the process of market segmentation. ANS: T PTS: 1 REF: 118 OBJ: 08-1 TYPE: App TOP: AACSB Reflective Thinking | TB&E Model Strategy 3. Until the 1990s, few firms practiced market segmentation. ANS: F Firms practiced market segmentation after the 1960s. PTS: 1 REF: 118 OBJ: 08-1 TYPE: Comp TOP: AACSB Reflective Thinking | TB&E Model Strategy 4. A market segment is deemed to have substantiality if it contains a large number of potential customers. ANS: F Substantiality of a segment refers to a segment being large enough to warrant developing and main- taining a special marketing mix. This does not necessarily require large numbers of potential custom- ers. PTS: 1 REF: 118 OBJ: 08-3 TYPE: Comp TOP: AACSB Reflective Thinking | TB&E Model Customer 5. A segmentation plan must produce segments that exhibit responsiveness, which means all segments re- sponse similarly to a marketing mix. ANS: F Responsiveness means one market segment responds to a marketing mix differently from other seg- ments. PTS: 1 REF: 119 OBJ: 08-3 TYPE: Comp TOP: AACSB Reflective Thinking | TB&E Model Customer 6. Geography, psychographics, and benefits sought are examples of possible segmentation variables used by marketers. ANS: T PTS: 1 REF: 119 OBJ: 08-4 TYPE: Def TOP: AACSB Reflective Thinking | TB&E Model Strategy 7. U.S. paint manufacturers traditionally use different formulae for developing paint to be used in the hu- mid Southeast, the frigid Midwest, and the hot and dry Southwest. This is an example of how demo-mid Southeast, the frigid Midwest, and the hot and dry Southwest.

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USF - FIN - 3604
Chapter 9Decision Support Systems and Marketing ResearchTRUE/FALSE 1. A marketing decision support system is an interactive, flexible computerized information system that bypasses information-processing specialists and gives managers access to useful inf
USF - FIN - 3604
Chapter 10Product ConceptsTRUE/FALSE 1. A product may be defined as everything, both favorable and unfavorable, that a person receives in an exchange. ANS: T PTS: 1 REF: 153 TOP: AACSB Reflective Thinking | TB&E Model Product OBJ: 10-1 TYPE: Def2. An el
USF - FIN - 3604
Chapter 11Developing and Managing ProductsTRUE/FALSE 1. A product must be a discontinuous innovation to be considered a new product. ANS: T There are six categories of new products, only one of which is new-to-the-world discontinuous innovative products.
USF - FIN - 3604
Chapter 12Services and Nonprofit Organization MarketingTRUE/FALSE 1. Insurance companies are examples of service organizations. ANS: T PTS: 1 REF: 183 TOP: AACSB Reflective Thinking | TB&E Model Product OBJ: 12-2 TYPE: App2. Services tend to exhibit mor
USF - FIN - 3604
Chapter 13Marketing ChannelsMULTIPLE CHOICE 1. A _ is a business structure of interdependent organizations that reaches from the point of product origin to the consumer. a. facilitating agency or place member b. marketing mix intermediary c. selective di
USF - FIN - 3604
Chapter 14Supply Chain ManagementTRUE/FALSE 1. Supply chain management is completely producer-driven. ANS: F Supply chain management is completely customer-driven. PTS: 1 REF: 213 OBJ: 14-1 TYPE: Def TOP: AACSB Reflective Thinking | TB&E Model Distributi
USF - FIN - 3604
Chapter 15RetailingTRUE/FALSE 1. Retailing can be defined as all activities directly related to the sale of goods and services to the ultimate consumer for personal, nonbusiness use. ANS: T PTS: 1 REF: 227 OBJ: 15-1 TYPE: Def TOP: AACSB Reflective Thinki
USF - FIN - 3604
Chapter 16Integrated Marketing CommunicationsTRUE/FALSE 1. Promotion is communication by marketers that informs, persuades, and reminds potential buyers of a product in order to influence their opinion or elicit a response. ANS: T PTS: 1 REF: 245 TOP: AA
USF - FIN - 3604
Chapter 17Advertising and Public RelationsTRUE/FALSE 1. Spending on advertising varies by industry. ANS: T PTS: 1 REF: 261 TOP: AACSB Reflective Thinking | TB&E Model Promotion OBJ: 17-1 TYPE: Comp2. The advertising response function is a phenomenon in
USF - FIN - 3604
Chapter 18Sales Promotion and Personal SellingTRUE/FALSE 1. Sales promotion offers an incentive to buy. ANS: T PTS: 1 REF: 279 TOP: AACSB Reflective Thinking | TB&E Model Promotion OBJ: 18-1 TYPE: Comp2. Marketers find it much easier to evaluate the eff
USF - FIN - 3604
Chapter 19Pricing ConceptsTRUE/FALSE 1. Price is defined as the perceived value of a good or service that is exchanged for a certain dollar amount. ANS: F Price is not necessarily measured in terms of money. In bartering, other items of value may be exch
USF - FIN - 3604
Chapter 20Setting the Right PriceTRUE/FALSE 1. The first step in setting the right price for a new product is to estimate demand, costs, and profits. ANS: F The first step in setting the right price for a new product is to derive pricing goals from the f
USF - FIN - 3604
Chapter 21Customer Relationship Management (CRM)TRUE/FALSE 1. Customer relationship management (CRM) requires that organizations be organized around customer segments. ANS: T PTS: 1 REF: 329 TOP: AACSB Reflective Thinking | TB&E Model Customer 2. Technol
CSB-SJU - IS - 333
Ken Perry OrangeBasketSource Code;import java.util.Scanner;public class OrangeBasketcfw_ public static void main (String [] args) cfw_ int numberOfBaskets, orangesPerBasket, totalOranges, numberToRemove; String YourName = "Ken Perry"; numberToRem
Chippewa Valley - BS - 1
Database TestingTesting TableTest Number 1 Test Validation rule: New Cust_Title, customer details field. Enter of the word Sir. Is it possible to enter letters into the Card Number field in the customer details table? Is it possible to change the Order
Notre Dame - ACCT - 101
Chapter 10Standard Costs and the Balanced ScorecardSolutions to Questions10-1 A quantity standard indicates how much of an input should be used to make a unit of output. A price standard indicates how much the input should cost. 10-2 Ideal standards as
Minnesota - AEM - 2011
PROBLEM 2.5The 300-lb force is to be resolved into components along lines a-a and b-b. (a) Determine the angle by trigonometry knowing that the component along line a-a is to be 240 lb. (b) What is the corresponding value of the component along b-b?SOLU
Minnesota - AEM - 2011
PROBLEM 2.27The guy wire BD exerts on the telephone pole AC a force P directed along BD. Knowing that P must have a 120-N component perpendicular to the pole AC, determine (a) the magnitude of the force P, (b) its component along line AC.SOLUTION(a)P=
Minnesota - AEM - AEM2011
PROBLEM 2.41Determine (a) the required tension in cable AC, knowing that the resultant of the three forces exerted at Point C of boom BC must be directed along BC, (b) the corresponding magnitude of the resultant.SOLUTIONUsing the x and y axes shown:R
Minnesota - AEM - AEM2011
PROBLEM 2.44Two cables are tied together at C and are loaded as shown. Determine the tension (a) in cable AC, (b) in cable BC.SOLUTIONFree-Body Diagram Force TriangleLaw of sines: (a) (b)TAC T 500 N = BC = sin 60 sin 40 sin 80 TAC = TBC =500 N sin 6
Minnesota - AEM - AEM2011
PROBLEM 2.57For the cables of Problem 2.45, it is known that the maximum allowable tension is 600 N in cable AC and 750 N in cable BC. Determine (a) the maximum force P that can be applied at C, (b) the corresponding value of .SOLUTIONFree-Body Diagram
Minnesota - AEM - AEM2011
PROBLEM 2.65A 160-kg load is supported by the rope-and-pulley arrangement shown. Knowing that = 20, determine the magnitude and direction of the force P that must be exerted on the free end of the rope to maintain equilibrium. (Hint: The tension in the r
Minnesota - AEM - AEM2011
PROBLEM 2.68Solve Parts b and d of Problem 2.67, assuming that the free end of the rope is attached to the crate. PROBLEM 2.67 A 600-lb crate is supported by several rope-and-pulley arrangements as shown. Determine for each arrangement the tension in the
Minnesota - AEM - AEM2011
PROBLEM 2.74A horizontal circular plate is suspended as shown from three wires that are attached to a support at D and form 30 angles with the vertical. Knowing that the z component of the force exerted by wire BD on the plate is 32.14 N, determine (a) t
Minnesota - AEM - AEM2011
PROBLEM 2.83A force F of magnitude 210 N acts at the origin of a coordinate system. Knowing that Fx = 80 N, z = 151.2, and Fy < 0, determine (a) the components Fy and Fz, (b) the angles x and y.SOLUTION(a)Fz = F cos z = (210 N) cos151.2= 184.024 NFz
Minnesota - AEM - AEM2011
PROBLEM 2.93Knowing that the tension is 425 lb in cable AB and 510 lb in cable AC, determine the magnitude and direction of the resultant of the forces exerted at A by the two cables.SOLUTIONAB = (40 in.)i (45 in.) j + (60 in.)k AB = (40 in.) 2 + (45 i
Minnesota - AEM - AEM2011
PROBLEM 2.109A transmission tower is held by three guy wires attached to a pin at A and anchored by bolts at B, C, and D. If the tension in wire AB is 630 lb, determine the vertical force P exerted by the tower on the pin at A.SOLUTIONFree Body A :F =
Minnesota - AEM - AEM2011
PROBLEM 2.121A container of weight W is suspended from ring A. Cable BAC passes through the ring and is attached to fixed supports at B and C. Two forces P = Pi and Q = Qk are applied to the ring to maintain the container in the position shown. Knowing t
Minnesota - AEM - AEM2011
PROBLEM 3.3A 300-N force is applied at A as shown. Determine (a) the moment of the 300-N force about D, (b) the smallest force applied at B that creates the same moment about D.SOLUTION(a)Fx = (300 N) cos 25= 271.89 N Fy = (300 N) sin 25 = 126.785 N
Minnesota - AEM - AEM2011
PROBLEM 3.10It is known that a force with a moment of 960 N m about D is required to straighten the fence post CD. If d = 2.80 m, determine the tension that must be developed in the cable of winch puller AB to create the required moment about Point D.SO
Minnesota - AEM - AEM2011
PROBLEM 3.21A 200-N force is applied as shown to the bracket ABC. Determine the moment of the force about A.SOLUTIONWe have whereM A = rC/A FC rC/A = (0.06 m)i + (0.075 m) j FC = (200 N) cos 30 j + (200 N)sin 30kTheni j k 0.075 0 M A = 200 0.06 0 co
Minnesota - AEM - AEM2011
PROBLEM 3.39Consider the volleyball net shown. Determine the angle formed by guy wires AB and AC.SOLUTIONFirst noteAB = (6.5)2 + (8)2 + (2) 2 = 10.5 ft AC = (0) 2 + (8) 2 + (6)2 = 10 ftandAB = (6.5 ft)i (8 ft) j + (2 ft)k AC = (8 ft) j + (6 ft)kBy
Minnesota - AEM - AEM2011
PROBLEM 3.55The frame ACD is hinged at A and D and is supported by a cable that passes through a ring at B and is attached to hooks at G and H. Knowing that the tension in the cable is 450 N, determine the moment about the diagonal AD of the force exerte
Minnesota - AEM - AEM2011
PROBLEM 3.61A sign erected on uneven ground is guyed by cables EF and EG. If the force exerted by cable EF at E is 46 lb, determine the moment of that force about the line joining Points A and D.SOLUTIONFirst note that BC = (48) 2 + (36) 2 = 60 in. and
Minnesota - AEM - AEM2011
PROBLEM 3.79If P = 20 N, replace the three couples with a single equivalent couple, specifying its magnitude and the direction of its axis.SOLUTIONWe have wherei jk M1 = rG/C F1 = 0.3 0 0 N m = (5.4 N m)j 0 0 18 i j k F2 = .15 .08 0 141.421 N m .15 .0
Minnesota - AEM - AEM2011
PROBLEM 3.92A rectangular plate is acted upon by the force and couple shown. This system is to be replaced with a single equivalent force. (a) For = 40, specify the magnitude and the line of action of the equivalent force. (b) Specify the value of if the
Minnesota - AEM - AEM2011
PROBLEM 3.81The tension in the cable attached to the end C of an adjustable boom ABC is 560 lb. Replace the force exerted by the cable at C with an equivalent forcecouple system (a) at A, (b) at B.SOLUTION(a) Based on orM A : M A = (T sin 50)(d A ) =
Minnesota - AEM - AEM2011
PROBLEM 3.101A 4-m-long beam is subjected to a variety of loadings. (a) Replace each loading with an equivalent forcecouple system at end A of the beam. (b) Which of the loadings are equivalent?SOLUTION(a)(a)We haveFy : 400 N 200 N = Raor andM A :
Minnesota - AEM - AEM2011
PROBLEM 3.113A truss supports the loading shown. Determine the equivalent force acting on the truss and the point of intersection of its line of action with a line drawn through Points A and G.SOLUTIONWe haveR = F R = ( 240 lb)(cos 70i sin 70 j) (160
Minnesota - AEM - AEM2011
PROBLEM 4.4For the beam and loading shown, determine (a) the reaction at A, (b) the tension in cable BC.SOLUTIONFree-Body Diagram:(a)Reaction at A:Fx = 0 : Ax = 0MB = 0 : (15 lb)(28 in.) + (20 lb)(22 in.) + (35 lb)(14 in.) + (20 lb)(6 in.) Ay (6 in
Minnesota - AEM - AEM2011
PROBLEM 4.15Two links AB and DE are connected by a bell crank as shown. Knowing that the tension in link AB is 720 N, determine (a) the tension in link DE, (b) the reaction at C.SOLUTIONFree-Body Diagram:M C = 0 : FAB (100 mm) FDE (120 mm) = 0 FDE = 5
Minnesota - AEM - AEM2011
PROBLEM 4.33Neglecting friction, determine the tension in cable ABD and the reaction at C when = 60.SOLUTIONM C = 0 : T (2a + a cos ) Ta + Pa = 0 T= Fx = 0 : C x T sin = 0 C x = T sin = P sin 1 + cos P 1 + cos (1)Fy = 0 : C y + T + T cos P = 0 C y =
Minnesota - AEM - AEM2011
PROBLEM 4.43An 8-kg mass can be supported in the three different ways shown. Knowing that the pulleys have a 100-mm radius, determine the reaction at A in each case.SOLUTIONW = mg = (8 kg)(9.81m/s 2 ) = 78.48 N(a)Fx = 0 : Ax = 0 Fy = 0 : Ay W = 0 M A
Minnesota - AEM - AEM2011
PROBLEM 4.61Determine the reactions at A and B when a = 180 mm.SOLUTIONReaction at B must pass through D where A and 300-N load intersect.240 180 = 53.13Free-Body Diagram: (Three-force member)BCD :tan =Force triangleA = (300 N) tan 53.13 = 400 N
Minnesota - AEM - AEM2011
PROBLEM 4.67Determine the reactions at B and D when b = 120 mm.SOLUTIONSince CD is a two-force member, line of action of reaction at D must pass through C and D Free-Body Diagram: (Three-Force body) .Reaction at B must pass through E, where the reacti
Minnesota - AEM - AEM2011
PROBLEM 4.94Two transmission belts pass over sheaves welded to an axle supported by bearings at B and D. The sheave at A has a radius of 2.5 in., and the sheave at C has a radius of 2 in. Knowing that the system rotates at a constant rate, determine (a)
Minnesota - AEM - AEM2011
PROBLEM 4.101Two steel pipes AB and BC, each having a mass per unit length of 8 kg/m, are welded together at B and supported by three wires. Knowing that a = 0.4 m, determine the tension in each wire.SOLUTIONW1 = 0.6mg W2 = 1.2mgM D = 0: rA/D TA j + r
Minnesota - AEM - AEM2011
PROBLEM 4.106A 2.4-m boom is held by a ball-and-socket joint at C and by two cables AD and AE. Determine the tension in each cable and the reaction at C.SOLUTIONFree-Body Diagram: Five Unknowns and six Eqs. of equilibrium. Equilibrium is maintained (MA
Minnesota - AEM - AEM2011
PROBLEM 4.132The uniform 10-kg rod AB is supported by a ball-and-socket joint at A and by the cord CG that is attached to the midpoint G of the rod. Knowing that the rod leans against a frictionless vertical wall at B, determine (a) the tension in the co
Minnesota - AEM - AEM2011
PROBLEM 5.2Locate the centroid of the plane area shown.SOLUTIONDimensions in mmA, mm 2x , mmy , mmx A, mm3y A, mm31 21200 540 174010 3030 3612000 16200 2820036000 19440 55440ThenX= Y= x A 28200 = A 1740 y A 55440 = A 1740X = 16.21 mm Y =
Minnesota - AEM - AEM2011
PROBLEM 5.7Locate the centroid of the plane area shown.SOLUTIONA, in.2x , in.y , in.x A, in.3y A, in.31 22(38)2 = 2268.20 1016.1277 80 3200 320036581 2560 3402120 16 = 3201948.23 xA 3200 = A 1948.23 y A 34021 = A 1948.23ThenX= Y=X = 1.
Minnesota - AEM - AEM2011
PROBLEM 5.29Member ABCDE is a component of a mobile and is formed from a single piece of aluminum tubing. Knowing that the member is supported at C and that l = 2 m, determine the distance d so that portion BCD of the member is horizontal.SOLUTIONFirst
Minnesota - AEM - AEM2011
PROBLEM 5.36Determine by direct integration the centroid of the area shown. Express your answer in terms of a and h.SOLUTIONFor the element (EL) shownAtx = a, x=y = h : h = ka3or k =h a3Thena 1/3 y h1/3NowdA = xdy = xEL yELa 1/3 y dy h1/3 1 1
Minnesota - AEM - AEM2011
PROBLEM 5.45A homogeneous wire is bent into the shape shown. Determine by direct integration the x coordinate of its centroid.SOLUTIONFirst note that because the wire is homogeneous, its center of gravity coincides with the centroid of the correspondin
Minnesota - AEM - AEM2011
PROBLEM 5.46A homogeneous wire is bent into the shape shown. Determine by direct integration the x coordinate of its centroid.SOLUTIONFirst note that because the wire is homogeneous, its center of gravity coincides with the centroid of the correspondin
Minnesota - AEM - AEM2011
PROBLEM 5.57Verify that the expressions for the volumes of the first four shapes in Figure 5.21 on Page 253 are correct.SOLUTIONFollowing the second theorem of Pappus-Guldinus, in each case a specific generating area A will be rotated about the x axis
Minnesota - AEM - AEM2011
PROBLEM 5.62The escutcheon (a decorative plate placed on a pipe where the pipe exits from a wall) shown is cast from brass. Knowing that the density of brass is 8470 kg/m3, determine the mass of the escutcheon.SOLUTIONThe mass of the escutcheon is give
Minnesota - AEM - AEM2011
PROBLEM 5.66For the beam and loading shown, determine (a) the magnitude and location of the resultant of the distributed load, (b) the reactions at the beam supports.SOLUTION1 (150 lb/ft) (9 ft) = 675 lb 2 1 RII = (120 lb/ft) (9 ft) = 540 lb 2 R = RI +
Minnesota - AEM - AEM2011
PROBLEM 5.76Determine the reactions at the beam supports for the given loading when 0 = 150 lb/ft.SOLUTIONWe have1 (18 ft)(450 lb/ft) = 4050 lb 2 1 RII = (18 ft)(150 lb/ft) = 1350 lb 2 RI = Fx = 0 : Cx = 0M B = 0 : (44,100 kip ft) (2 ft) (4050 lb) (8
Minnesota - AEM - AEM2011
PROBLEM 5.85A freshwater marsh is drained to the ocean through an automatic tide gate that is 4 ft wide and 3 ft high. The gate is held by hinges located along its top edge at A and bears on a sill at B. If the water level in the marsh is h = 6 ft, deter
Minnesota - AEM - AEM2011
PROBLEM 5.97Determine the y coordinate of the centroid of the body shown.SOLUTIONFirst note that the values of Y will be the same for the given body and the body shown below. ThenVy 1 h 4 1 b 2 yV 1 a 2 h2 12 1 22 a b 8Cone Cylinder12 a h 3 1 a b