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16 Pages

### The Heavenly Messenger_ Mas..

Course: ENG 259, Winter 2011
School: University of Calgary
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Word Count: 5359

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Heavenly The Messenger: Mastering Physics Solutions Use Wisely http://rocketscient1st.blogspot.com/2009/01/mastering-physics-solutions-... Share Report Abuse Next Blog Create Blog Sign In The Heavenly Messenger Tuesday, January 27, 2009 Mastering Physics Solutions Use Wisely [ Item View ] The Electric Field of a Ball of Uniform Charge Density A solid ball of radius r_bhas a uniform charge density rho....

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M arijuana should not be legalized because: There are more than thousands of scientific research studies that verify marijuana is a dangerous, unsafe, and addictive drug that impair the cognitive ability of learning and memory. According to recent studies
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
4. cfw_r rrr i tr (,rlii(I t , f : t r . , f ' l \ 4 - i - L -7 C t cfw_ [ r ( c r u , 7 [t q '.rt.Il''.t,L l e t r ' I i ' - 1 , . , , ri tl':Le:' Z c r , ' r lD i lIc lrr i -c r rc,4( ( t l,5( t,1ii Cr\s Ceotcfw_ i l c . - - 7Z C t '
University of Minnesota Crookston - CE - 3101
5'5' T he f ollowing d atah aveb eeno btained i n a B oD t estt hat i s m adet o d etermine how w ell a w astewaterreatment lant t p i s o peratrng:InitialD O (mdL)UntreatedVolume wastewaterVolume dilution ater w (mL)(A) w hat p ercentagef t he B oD
University of Minnesota Crookston - CE - 3101
6.4gravityof 1'4 anda diameter (a) what is the terminalsettlingvelocityof a particlewith a specific C of 0 .010m m i n 2 0o w ater? basingwith a width i r o (b) Would particles f the sizein part (a) be completely emovedn a settling 7,500m3/d? of 10.0m, a
University of Minnesota Crookston - CE - 3101
University of Minnesota Crookston - CE - 3101
QUIZ #1 (2/5/09) (more on back) Name: Write a mass balance equation for a substance C in which there is degradation of C (first order), an input flow, two output flows, and the system is NOT at steady state. Assume that the system is well-mixed and can be
University of Minnesota Crookston - CE - 3101
QUIZ #2 (3/3/09) Name:1.Fill in the blanks below (4 pts)Alkalinity (mol/L) = _[HCO3-]_ + _2[CO32-]_ + _[OH-]_ - [H+] + [species that can accept an H+] [species that can donate an H+]2.Bacteria are (circle all that are correct): (3 pts) a. 65% water b
University of Minnesota Crookston - CE - 3101
QUIZ #3 (4/14/09) Name:1.List (i.e. no explanation, just the correct word) the 6 unit operations involved in treating surface water (as described in class). (3 pts)Screening, mixing flocculation, sedimentation, filtration, disinfection2.What are two
University of Minnesota Crookston - CE - 3101
CHAPTER 19 IONIC EQUILIBRIA IN AQUEOUS SYSTEMSFOLLOW-UP PROBLEMS 19.1 Plan: The problems are both equilibria with the initial concentration of reactant and product given. For part (a), set up a reaction table for the dissociation of HF. Set up an equilib
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CHAPTER 13 THE PROPERTIES OF MIXTURES: SOLUTIONS AND COLLOIDSFOLLOW-UP PROBLEMS 13.1 Plan: Compare the intermolecular forces in the solutes with the intermolecular forces in the solvent. The intermolecular forces for the more soluble solute will be more
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CHAPTER 17 EQUILIBRIUM: THE EXTENT OF CHEMICAL REACTIONSFOLLOW-UP PROBLEMS 17.1 Plan: First, balance the equations and then use the coefficients to write the reaction quotient as outlined in Equation 17.4. Solution: a) Balanced equation: 4 NH3(g) + 5 O2(
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CHAPTER 18 ACID-BASE EQUILIBRIAFOLLOW-UP PROBLEMS 18.1 a) Chloric acid, HClO3, is the stronger acid because acid strength increases as the number of O atoms exceeds the ionizable H atom. b) Hydrochloric acid, HCl, is one of the strong hydrohalic acids wh
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Problem 1 a) Find the current in each resistance in the circuit below, the battery has negligible internal resistance (10 points). b) If the battery is replaced by a charged 1F capacitance what fraction of the charge will remain after 1 sec (10 points)?3
University of Minnesota Crookston - CE - 3101
+qabA hollow, uncharged spherical conductor has inner radius a and outer radius b. A positive point charge +q is in the cavity at the center of the sphere. Assume that V=0 at r = . a) Find the potential V(r) for r b b) Find the potential V(r) for a r b
University of Minnesota Crookston - CE - 3101
Quiz2 solutionProblem 2
University of Minnesota Crookston - CE - 3101
Multiple Choice Questions (5 points per question, Bubble sheet).1) The current in a wire along the x axis flows in the positive x direction. If a proton, located as shown in the figure, has an initial velocity in the positive z direction, it experiences
BUPT - CS - 343
4. H * )? GG k O * 13.12 @ 7 9.1 4 G O * v * O Gk @k a k( .k /2kk 13.12  abcdefghifdigbeab g h c 7. 8 13.13 b H * x * 13.13 . ab H* .* x f ied ? 8 * ?u1u2u3u4u5u6u3u7u6u2u7* u 8u1 k H E i * k bH |r *H b E i * c8 s | 13.1  d| s x * H * b *n 8 k
BUPT - CS - 343
3. (?acebcdabdbbv e H * *  G? (?? * ? (V1 a V2 a GV1 =cfw_acea bca daba dba be2 V2 = cfw_ a, b, c, d , e E =cfw_(vi ,vj ) v i V1,vj V2, v j 2 2 2 ( *? ace vi dabbcdbbea 2b M=cfw_c ace 2 a 2de bc 2 c 2 dab 2 b 2V1 a V2 ( ? 2 db2 d2 @
BUPT - CS - 343
166 X 6 ,R 6 X ) (2) r (t (R) ) = t(r(R) 6 26 X 6 a 6 R1 6 R2 R3 6 = 6 R1 R2 6 R1 R36 6 R2 R36 R1= 6 R2 R16 R3 R16 6 b6 (R IX) n= IX R R 2 R 3 R n 6 nX 6 n=1 6 (R IX) 1= IX R 6 X 6 n=k 6 6 (R IX) k= IX R R 2 R 3 R k 6 n=k+1, (R IX) k +1=(R IX) k (R IX) =
BUPT - CS - 343
1 2h. y h.y 3 AB h h h h h 4 * 5 * * *-* +=h. y 1 h. y [1 1 =11P ] T ~ + h . y * -* P]1 +X1 2 3 s1 R1 4 5+ 1X * 2 x( * * x(1*dom(R) 1 ran(R) 1 RS 1 R-1 1 r 1 R 1 t1 R1 x( u F + *8 W T8 @W * E N1 R1 11 ) y * 8 1 ) y * 8 W T8WT11 @ W T * 1
BUPT - CS - 343
12 (* 12 22 (* 32 2 42 2 52 2 62 2 222242 2 42 D232 ( 32 G @lx*iE2 22 2 D (*2 232 K4( ( G272 (*n2 m(m=n-12G2 82 (* 92 ( 100 EOr+$11 122 K 3,3 * 13 140 f cfw_*iE 15 G 1 2 G 2 3 2 * u * pV ~ G2 K6 G*2 2 G 22 G G * G*G G G n2 m2TG22 G BUPT - CS - 343 12 C 12 22 32 42 52 62 72 82 92 ()kd* () 2 42 32 22 32 .( ) 2 2 42 32 2 2 2 2 K4 () 2 D2 D * () 2 2 G * () * G 2 n2 m m=n-12 G 2 () C 22 () G () 108 () 11 () () () () G* 122 K 3,3 T D 1 2 2X K * 3 D T 10 4 2 n-1 5 2 k/2 62 2 2 12 D2 C 6 2 12 C D 2 2 BUPT - CS - 343 2003 g N 12g N22 12 2 BA=cfw_ ,cfw_a g o N D B. A A.cfw_a A 22C.cfw_ AD.a A R=cfw_&lt;1,1&gt;,&lt;1,2&gt; 2 A=cfw_1,2,3 C () A.R cfw_ C.R 2 B.R 2 D.R 32R 8DAcfw_ 8 y / [A.R R1=RB.R R1=RR1 C.R R1= 42 A.3 52 62 8 A.f cfw_ C.f cfw_ A.9 B.4 8 A=cfw_a,b,c,A o 6 BUPT - CS - 343 P151 P153111 ] 1 21 cfw_-31 2 1 41 cfw_51 61 71 81 91 101 111 121 131 141 15 21 ] 1 21 cfw_x| x 1 1 41 cfw_x| x * 10&lt; x&lt; 20 1 61 cfw_x| x=2k+11 kI * 31 * I p&gt; * 1 21 * 41I p&gt; * 1 6] 1 21 1 1 cfw_11 1 1 =cfw_ cfw_11 cfw_1 cfw_11 1 1 4 1 1 1 cfw_ cfw_a 1 BUPT - CS - 343 6 r o1r o X1 Y1 S11 11 X=cfw_01 11 21 Y=cfw_01 21 41 S=cfw_&lt; x1 y&gt;| x+yX Y 1 21 X=cfw_11 21 31 41 51 Y=cfw_11 21 31 S=cfw_&lt; x1 y&gt;| x=y21 xX1 yY 1 11 S=cfw_&lt; 01 0&gt; 1 21 S=cfw_&lt; 11 1&gt; 21 P=cfw_&lt; 11 2&gt; Q=cfw_&lt; 11 3&gt; 1 dom1 P1 1 &lt; 01 2&gt; &lt; 41 2&gt; &lt; 31 3&gt; &lt; BUPT - CS - 343 78 X4 X 8 dom 8 z &quot; 612 22 32fg8 * X f g f g x 1,y1 g y2f g domdom gg =dom =dom f8 x 1,y2 g f 8 Xff =g x 1dom gfx 1,y1 f f gx 1,y2 f f=gg8 * X =cfw_0 f2 f2 f3 1 x x x1 =f =x =x2 xX XX * 810 8 * X f1 f2 f3 f4 f5 f6 f7 f8 f9x x x x x x x BUPT - CS - 343 7( 1 f x =2| x| +1 + F x t D i * P 2P D i * 1 cfw_ x y | x yN x+y&lt; 10 23 cfw_ x y | x yR y=x2 33 cfw_ x y | x yR y2=x 13 3P D i * 2( 3@ 7 D k 3 1 cfw_ 1,2,3 ,2,3,4 ,3,1,4 ,4,1,4 2 cfw_ 1,2,3 ,2,3,4 ,3,3,2 3 cfw_ 1,2,3 ,2,3,4 ,1,2,4 4 cfw_ 1,2,3 ,2,2,3 BUPT - CS - 343 122 P n =1Sn n S1=1+2+3+n= Sn =1 mn(n + 1) 2m m * B ( m=1+2+3+n= P Sm1(1 + 1) =1 2n(n + 1) 21 =1+2+3+m=m(m + 1) 2PmS m +1 = m *H w E n(n + 1) m 2=1+2+3+m+m +1m(m + 1) m(m + 1) + 2(m + 1) (m + 1)(m + 1) + 1) = +m+1= 2 2 2Pm +1 n Sn =1+2+ BUPT - CS - 343 10 h 1.10.5 p E * 0 u1u * 8u1 u21 2 3 4 5 6 7 8 0 + 5 3u31u3+ 2u12u4+u5+ +u6 u7+ + + +u8+ + +3 3953u133 9 53 55u33+ 3u31 +9 96u6114 1411u55u1 000323653110 3. &lt;e,f&gt; 0u1 10.7u 8 h * E 0h * a =0 = TE a +3=3 b a b @(u BUPT - CS - 343 11 h B3. 11.3 h * 3 MM M 4 h u1 u4 u1 u4 u1 u4 u1,u4,u2 u3 u4 u4h u4h u4h 2u1 2 3 4 2 3 4u4 1 22,3,4 h / i u1,u2,u4 u1,u2,u3 u4 u1,u4,u2 u4 3 u1,u2,u3 u2 u4 u4,u2,u4 u4,u2,u3 u4 u4,u2,u3 u2 u4u4 h 2,3,4 h u1,u2u4,u2u41 1 2u4,u2 u4,u2 u40 0 M= BUPT - CS - 343 0 3. 3 ^ * M4 ^ 3 11.3 * ^ u4 ^ 3 2311 3 2,3,4 ^ M2 3 M3 3 u1,u2,u4 3 u1,u2,u3 3 u4 3u1 3 u4 3 2,3,4 * ^ 13 233 u1 3 u4 33 u1 3 u4 3 33 3 u1,u4,u2 3 u4 3 3 u1 3 u4 3 43 3 u1,u2 3 u4,u2 3 u4 3 3 u4 ^ 3 u4 ^ 3 u ^ 23 33 4333 u1,u2,u3 3 u2 3 u4 3 u1,u4, BUPT - CS - 343 12 7 E 1. T @ E 7 E 7 E 7 * 2 P 2 T ,*8 2 + 2 2. E J * E * , n-1 * E 9.1 T@ T E J * 2 T 12 1@ 1 E n E T T T n-2 2 2P*JE T 7 E * u2 P 2 T 7 E * T *JE P H u2 P 7 E * T + *JE P @ P 7 E * 12 12 u2 P2 2n-2&gt; 2n-2 E @ 3. @ 2 9.1 T @ 2 T * E n2 n-1 &gt; 2+2 T , * BUPT - CS - 343 12 K 31. 2 T 3 2 h3 1 3 u2 h4 2 12 P h3 * 12 P 2 T h3 * 2 *E 4 u 2 P h3 * P T p*E 4 T h3 * P 2 T h3 P u u2 P T *E 42. *E 3 U*3 T *E M T 2 n-2 * 3 T2 2 2 n-1 2 2 2+2 2 n-2 2 2 3 * 2n-2&gt; 2n-2 3 11 1 3 T 22 T2 n 9.1 2 Tn-1 * 3 22u *E T3. 2 22 2 + * 2 2 BUPT - CS - 343 13 ' 3. ' G ' ' * ) 5 1G E J * ' 3.1 2 '* G ) 5 G1G ' G G '* 2 ) G '1 G ' G '1 * G'2 * G ( ' 2 '* G1 G1 G G )2(( ' * 2 ' * ' * G ) 1 ' 2  4. '* ( '* ) 5 E J * 9.1 4 + 3 G k '( G * u 3.1 G ' k E J * ' )? 13.125 ) E J * u G1 G + 3 1 2, ' * '2 ,G BUPT - CS - 343 9 (m 6. 6 f * f * . * D b 7. 6 f * n3 + 1 n6 n 6 .0 * D b 1S c ? * (n2) 9.26 f G1 6 G2 6 n . n (* D b 0 6 1 6 2 6 6 n-1 6 0 6 nn6 G1 6 G2 6 3 f 3 * f (n2)f 26 36 3612. e x* e x e x* 9 (*bD 1+ 2 3 2 1+3 2 1+3 P e x*D *bD 1 D (*bD 9 6 e x6 6 6 117. i X BUPT - CS - 343 R 6 1 X1 Y1 S1 Y=cfw_0 1 2 1 4 1 1 1 1 X=cfw_0 1 1 1 2 S=cfw_&lt; x 1 y&gt; | x+y X Y 1 2 1 X=cfw_1 1 2 1 3 1 4 1 5 1 Y=cfw_1 1 2 1 3 1 S=cfw_&lt; x 1 y&gt; | x=y2 1 x X 1 y Y 1 1 1 1 S=cfw_&lt; 0 1 0&gt; 1 2 1 S=cfw_&lt; 1 1 1&gt; 0 1 2&gt; 4 1 2&gt; 2 1 0&gt; 21 dom 1 P Q 1 =dom 1 BUPT - CS - 343 6 1 X1 Y1 S11 11 X=cfw_01 11 21 Y=cfw_01 21 41 S=cfw_&lt; x1 y&gt;| x+yX Y 1 21 X=cfw_11 21 31 41 51 Y=cfw_11 21 31 S=cfw_&lt; x1 y&gt;| x=y21 xX1 yY 1 11 S=cfw_&lt; 01 0&gt; 1 21 S=cfw_&lt; 11 1&gt; 21 P=cfw_&lt; 11 2&gt; Q=cfw_&lt; 11 3&gt; 1 dom1 P1 1 &lt; 01 2&gt; &lt; 41 2&gt; &lt; 31 3&gt; &lt; 41 2&gt; BUPT - CS - 343 P 1. . (1)| ( A B ) ( B C ) ( A C ) | ( A ( B C ) ( B ( A C ) | A A | A A | ( A B ) (B A) | A (B ( A B) | A A B | A B A | A B A | A B BA B AB AB AB AB BC BC BC BC BCA(2)(3)(4)(5)(6)(7)(8)(9)(10).(1)| AA| A B | B | B C | CAAA 3 * | BUPT - CS - 343 2. * :2 ( r+1) G2 r* ()G* Gz 8n = ( r + 1) 2 n nm = 2r ( r + 1) = 2r 2 + 2rk = r 2 +1 n2n m + k = ( r + 1) ( 2r 2 + 2r ) + r 2 + 1= r 2 + 2r + 1 2r 2 2r + r 2 + 1 =2 2 G H 4. H H m=122 H * H * H 8 2 E 2 7. @ * 3 2 2 15.16 3H 15.16 2 BUPT - CS - 343 1. &gt; * (1) p q , p r |= p q r (2) p rq r |= p q r(3) p q r |= ( p q ) ( p r ) (4) p q r |= ( p r ) (q r ) (5) p q rp r |= q r(6) ( p q ) ( p r ) |= p (q r ) (1)pq,pr( p q r ) &gt; * p q p q p r p r ( p q r ) (p (q r ) p (q r ) &gt; (2)cfw_p q , p r , BUPT - CS - 343 +5.1 e 5.2 a B 5.3 5 5.4 e 5.5 *e 5.6 * 5.70 * 15.1 X X H*3* H : X * 2,* * F cfw_* 5 * * H H * N * Q * ( 5 0) 5 R * I (Z) * F1875 (5 @ : @ )53 * * Y a5 b5 * 5 15 5 25 (3) * H * a5 A5 b5 A5 0 A A : a A 5 b A 5 : :cfw_ Y42: A = cfw_a, e, i, BUPT - CS - 343 12 a 2 22 cfw_-32 2 2 42 cfw_52 62 72 82 92 102 112 122 132 142 15 22 a 2 22 cfw_x| x 2 2 42 cfw_x| x * 8 10&lt; x&lt; 20 2 62 cfw_x| x=2k+12 kI * 4. F*4 1 2 5. P 2 a 6a 2 22 cfw_12 2 =cfw_ cfw_12 cfw_2 cfw_12 2 4 2 cfw_ cfw_a 2 cfw_ 2 =cfw_ cfw_ 2 cfw_a 2 cf BUPT - CS - 343 P151 P153111 8 1 21 cfw_-31 2 1 41 cfw_51 61 71 81 91 101 111 121 131 141 15 21 8 1 21 cfw_x| x 1 1 41 cfw_x| x 8* 1 61 cfw_x| x=2k+11 kI * 31 8 *x XC~* 1 61 * 41  x XC~* 1 68 1 21 1 1 cfw_11 1 1 =cfw_ cfw_11 cfw_1 cfw_11 1 1 4 1 1 1 cfw_ cfw_a 1 cfw_ BUPT - CS - 343 91 8' 2h h 3 AB 48' * 58' * 1 G' * * ** +=h 1 h T ~ + h * + + 1 1 =11* *891 2h 0 3 * z0 z01*h 0 dom(R) 1 ran(R) 1 RS 1 R-1 1 r 1 R 1 1 s1 R1 t1 R1 4 z0h0 *189 * 2 z0 r' *+ 1 ' * E N1 R1 r'11 r' * m r ' * 2 _ * E E (n,m) *+ E E 21 @E @E r BUPT - CS - 343 2004 S / H /H 12D32 15 2 /H A=cfw_ ,cfw_a B 2A.cfw_a A 22B. A C.cfw_ AD.a A R=cfw_&lt;1,1&gt;,&lt;1,2&gt; 2 A=cfw_1,2,3 (C) A.R A C.R 2 B.R 2 D.R x 32A=cfw_a,b,c,A S y D B.512 A C.27 D.8 c B 2A.9 42A=cfw_1,2,3 2 C 2 A.3 52 B.4 c A 2 B * B 2 C.5 A-B= D.6 BUPT - CS - 343 12 H( * 12 22 32 42 52 62 7 2 ( 8 2 ( 92 H* H w a a 10, 11n 122 13 8F ( ( 1 2 ( ( * 2 * ! 3 140 * y 1522 * H( 2 2 22 * H( G H( H( H( G2 222 2 G K * n2 mH( m=n-12 G2 222 , K 3,3 P ( * G*2 2 (G (* G*( ( (G ( K6T23 G23 40 y 8F * n2 m2 G2 G2 G2 ( BUPT - CS - 343 1 b C1 2 3 4 5 6 ? 9 *     *  G 2 G9 ? ? () ( ) ()K 3,3 P ?() ( ) .( ) ( G E J * n m ( ) ( ) m=n-1 ) () G ( )7  C b 8 ` b 9109$ + 3 11G + 3 12 13 14C E J 15 d b 1 d b 2 3 10 * M* T 2 3 3 4* E J K6 15 4 G* bG C d ( d C b () () G* bd ) bG d
BUPT - CS - 343
13 3 4. / X* E@= /X h*0 E E *0 h 9.1 ( %* G h E *0 G G3 (/ X* &gt; 8*0 k E )? 3 G3 13.12 3ab c S *( a 313.12 E *0 habcdefghifdigbea abg hf iecd7. 3 13.13 S ( c *a . ?+ x*0 &gt; E 3 13.13 3 3 3 * . 3 b( %* 3 4 S ( c *a 3 V1 3 3 b c aS ( c *a ?3b3 p(G
BUPT - CS - 343
6. . p cfw_ - 0. * . A. * ,* * G.@E &amp;* n. E G( h G cfw_ G cfw_ - * * . ( D cfw_ G cfw_A7 9@-* - Uu+ G D cfw_ -G.D. AT . h&amp;*( A cfw_-*A(G) . D ..G * 1. D cfw_ - A cfw_ - * 0 1cfw_ - * 0 * . . . 1 . D cfw_ - * . D . n-1 cfw_ cfw_ - G. n-1 cfw_ cf
BUPT - CS - 343
* B 4 14 3 1 15 2 3 1 2 1 cfw_x| x 1 1 4 1 cfw_x| x 4 B* * 4. (= 1*4 10&lt; x&lt; 20 I1 2 1 cfw_-3 1 2 4 1 cfw_5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 11 6 1 cfw_x| x=2k+1 1 k I5. 4 E 1 1 2 1 1 1 cfw_1 1 cfw_2 1 3 1 cfw_1 1 cfw_2 1 3 1 4 1 1 1 cfw_ 1 6