Homework 2-solutions
7 Pages

Homework 2-solutions

Course Number: CHEM 302, Spring 2011

College/University: University of Texas

Word Count: 1935

Rating:

Document Preview

sung (es24394) Homework 2 vanden bout (51640) This print-out should have 28 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points Both ammonia and phosphine (PH3 ) are soluble in water. Which is least soluble and why? 1. ammonia; it is too small to be hydrated by water molecules. 2. ammonia; it does not form hydrogen bonds with water...

Unformatted Document Excerpt
Coursehero >> Texas >> University of Texas >> CHEM 302

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

(es24394) sung Homework 2 vanden bout (51640) This print-out should have 28 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points Both ammonia and phosphine (PH3 ) are soluble in water. Which is least soluble and why? 1. ammonia; it is too small to be hydrated by water molecules. 2. ammonia; it does not form hydrogen bonds with water molecules. 3. phosphine; the PH bonds are so strong that they cannot break to enable phosphine to hydrogen-bond with water. 4. phosphine; it does not form hydrogen bonds with water molecules. correct 5. ammonia; the NH bonds are so strong that they cannot break to enable the ammonia to hydrogen-bond with water. Explanation: PH3 is least soluble because it cannot form hydrogen bonds with water. 002 10.0 points Some distilled water is added to an empty beaker. A gram of copper(II) nitrate is added to the beaker with stirring. After a few minutes, what is in the beaker? 1. nitrogen gas, copper atoms, electrons, and water 2. a sticky material of copper hydronitrite 3. solid copper(II) nitrate and water 4. solid copper, nitrate ions, and water 5. copper ions, nitrate ions, and water correct Explanation: 1 All nitrates are soluble in water, so the copper(II) nitrate dissolves. Soluble ionic compounds are strong electrolytes, so the copper(II) nitrate also dissociates into its cation and anion parts: Cu+ and NO . 2 3 003 10.0 points Which is the best representation of the solvation of a sodium cation in water? oxygen hydrogen Na+ ion 1. 2. sung (es24394) Homework 2 vanden bout (51640) 2 (chloroethane), H2 O (water), C2 H5 F (uoroethane), C9 H20 (nonane). 1. C2 H5 Cl > C2 H5 F > H2 O > C9 H20 2. C2 H5 F > H2 O > C9 H20 > C2 H5 Cl 3. 3. H2 O > C9 H20 > C2 H5 Cl > C2 H5 F 4. C9 H20 > C2 H5 Cl > C2 H5 F > H2 O correct Explanation: Octane is a non-polar solvent and thus ranking in terms of decreasing miscibility requires ranking in terms of decreasing nonpolar character, i.e. from least to most polar. 006 10.0 points Octane (C8 H18 ) is a major component of gasoline. Which of the following would you expect to be the LEAST soluble in gasoline? 1. candle wax 2. motor oil 3. table salt correct correct Explanation: Since the water molecule has a partial negative charge on the O atom, it will orient itself to the O atom closest to the positively charged cation. 004 10.0 points When we put sugar in water it melts. 1. False correct 2. True Explanation: Sugar dissolves in water and melts when its temperature is raised above its melting point. 005 10.0 points Rank the following in terms of decreasing miscibility in C8 H18 (octane): C2 H5 Cl 4. table sugar 5. diesel fuel Explanation: Octane is a non-polar compound so it would be less likely to dissolve polar or ionic substances. 007 10.0 points Calculate the number of moles of oxygen that will dissolve in 45 L of water at 20 C if the partial pressure of oxygen is 0.21 atm. Henrys mol . constant for oxygen is 0.0013 L atm 1. 0.28 mol 2. 0.0062 mol 3. 0.00027 mol 4. sung (es24394) Homework 2 vanden bout (51640) 4. 0.0013 mol Correct answer: 4.2344 mol. 5. 0.012 mol correct Explanation: 008 10.0 points A decrease in temperature usually (increases, decreases, does not change) the solubility of common salts in water. 1. does not change 2. increases 3. decreases correct Explanation: Most common salts dissolve endothermically in water and therefore their solubility will increase with an increase in temperature. 009 10.0 points Which of the following is a restatement of Henrys Law? 1. As the partial pressure of a gas above a liquid increases, the gass solubility in that liquid also increases. correct 2. A mixture of two liquids will have a vapor pressure that isnt equal to either of the pure liquids vapor pressures. 3. Adding a non-volatile solute to a liquid will lower its vapor pressure. 4. Heating a solution will decrease the solubility of gases dissolved in it. Explanation: Henrys law, formulated by William Henry is 1803 states: At a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid. 010 (part 1 of 2) 10.0 points How many moles of ions are contained in 1.58 L of a 1.34 M solution of KCl? Explanation: solute = KCl HO KCl(s) K+ (aq) + Cl (aq) 2 3 n=? Ions produced = 1 mol K+ + 1 mol Cl = 2 mol 011 (part 2 of 2) 10.0 points How many moles of ions are contained in 1.58 L of a 1.34 M solution of Mg(NO3 )2 ? Correct answer: 6.3516 mol. Explanation: solute = Mg(NO3 )2 n=? HO Mg(NO3 )2 (s) Mg2+ (aq) + 2NO (aq) 2 3 Ions produced = 1 mol Mg2+ + 2 mol NO 3 = 3 mol 012 10.0 points Raising the temperature of a sample of water will typically (decrease/increase) the solubility of (all/some) dissolved gases. 1. increase, some 2. increase, all 3. decrease, some 4. decrease, all correct Explanation: Because the dissolution of most all gases is an exothermic process, Le Chateliers principle suggests that all gases will become less soluble as the temperature of the solvent is raised. sung (es24394) Homework 2 vanden bout (51640) 4. 510 torr 013 10.0 points Theoretically, it would be harder to dissolve (NaCl/Al2S3 ) in water because the (higher/lower) the charge density, the lower the solubility. 1. Al2 S3 , higher correct 2. NaCl, higher 3. Al2 S3 , lower 4. NaCl, lower Explanation: Al2 S3 has a higher charge density (Al3+ , 2 S ) than NaCl (Na+ , Cl ). High charge density corresponds to high lattice energy and thus much more endothermic (i.e. less spontaneous) dissolution. 014 10.0 points To increase the solubility of a gas in water, you should 1. increase the surface area of the particles. 2. increase the pressure of the gas. correct 3. decrease the pressure of the gas. 4. increase the temperature of the water. Explanation: 015 10.0 points If acetic acid has a pure vapor pressure of 20 torr at 30 C and acetaldehye has a pure vapor pressure of 1000 torr at 30 C, a mixture of 1 moles of acetic acid and 4 moles of acetaldehyde would have what total vapor pressure? 1. 816 torr 1. III only 2. 804 torr correct 2. II only correct 3. 216 torr 3. I and III 5. 204 torr Explanation: Ptotal = a Pa + b Pb + ... Ptotal = 0.2 20 torr + 0.8 1000 torr Ptotal = 804 torr 4 016 10.0 points What is the vapor pressure the of solvent in an aqueous solution at 25 C of 0.05 m urea (CO(NH2 )2 ), a nonelectrolyte? The vapor pressure of water at 25 C is 23.76 Torr. Correct answer: 23.7386 Torr. Explanation: Pvp = 23.76 Torr T = 25 C MW = 18.02 g/mol A 0.05 m solution will contain 0.05 mol urea per 1000 g H2 O, so the number of moles of H2 O is 1000 g nH 2 O = = 55.4939 mol 18.02 g/mol xH 2 O = nH 2 O nH2 O + nurea 55.4939 mol = 55.4939 mol + 0.05 mol = 0.9991 . P = xsolvent Ppure solvent = 0.9991 (23.76 Torr) = 23.7386 Torr . 017 10.0 points Which of the following would raise the vapor pressure of a sample of aniline in a closed container? I) increasing the size of the container II) increasing the temperature of the sample III) increasing the applied pressure sung (es24394) Homework 2 vanden bout (51640) 1. 215 grams 4. II and III 2. 3.9 grams 5. I, II and III 3. 8.0 grams 6. I only 4. 4.0 grams 7. I and II Explanation: Because evaporation is always an endothermic process, a substances vapor pressure is always directly proportional to its temperature. Adding a non-volatile solute to any substance will decrease its vapor pressure. Factors such as sample size and container size do not inuence he vapor pressure. 018 10.0 points What will be the boiling point of a solution of 8 moles of sodium dichromate (Na2 Cr2 O7 ) dissolved in 8 kg of water? Use the following values: Kb = 0.512 K m1 Kf = 1.86 K m1 1. 380.1 K 4. 105.6 C correct 2. 378.6 K 5. 95.9 C 3. 373.8 K 6. 101.5 C 4. 377.6 K 5. 374.5 K correct Explanation: 8 moles me = 3 = 3 mol kg1 8 kg Tb = Kb me boiling point = 374.5 K 019 10.0 points Your friend decides to decrease cooking time for spaghetti noodles by adding table salt to 2.0 L water. How much table salt (NaCl) must be added to the water in order to raise the boiling point by 4.0 C? (Kf = 1.86 C/m, Kb = 0.512C/m) 5. 460 grams correct 5 Explanation: There are 15.625 moles of particles in the solution, which corresponds to 7.8125 moles of NaCl, or 456.6 grams NaCl. 020 10.0 points Over what temperature range would a 4 m solutiond of NaCl remain a liquid? (for water kb = 0.512 and kf = 0.186) 1. 104.1 C 2. 94.4 C 3. 98.5 C Explanation: Pure water will remain a liquid between 0 C and 100 C. A 4 m NaCl solution would have a freezing point depression of 2 4 0.186 = 1.488 C, and a new freezing point of 1.488 C. It would have a boiling point elevation of 2 4 0.512 = 4.096 C, and a new boiling point of 104.096 C. The solution would thus be stable from 104.096 to 1.488 C, a range of 105.6 C. 021 10.0 points Which of the following has the lowest freezing point? Assume that all the species are mixed as shown and are completely dissociated. 1. 1.5 m lithium sulfate sung (es24394) Homework 2 vanden bout (51640) 2. 1.0 m magnesium phosphate 3. 2.0 m sodium perchlorate 4. 1.5 m aluminum nitrate correct 5. 1.0 m potassium phosphate Explanation: The aluminum nitrate has an ideal vant Ho factor (i) of 4 which will scale the stated molality (1.5) up to a 6.0 for the eective molality. This eective molality is the highest in the group and therefore will have the lowest fp, the highest bp, and the maximum osmotic pressure. 022 10.0 points The freezing point of seawater is about 1.85C. If seawater is an aqueous solution of sodium chloride, calculate the molality of seawater. The kf for water is 1.86 K/m. 1. 0.995 m 2. 3.70 m 3. 1.99 m 4. 3.44 m 5. 0.497 m correct Explanation: 023 10.0 points How many moles of CO(NH2 )2 are present in 150 g of water, if the freezing point of the solution is 4.02 C? kf (water) = 1.86 K kg/mol. 1. 0.313 mol 2. 0.324 mol correct 3. None of these 4. 0.249 mol 5. 0.259 mol Tf = kf m nCO(NH2 )2 = kf msolvent Tf msolvent nCO(NH2 )2 = kf (4.02 K) (0.15 kg) = 1.86 K kg/mol = 0.324194 mol . 6. 0.27 mol Explanation: kf = 1.86 K kg/mol Tf = 4.02 C = 4.02 K msolvent = 150 g = 0.15 kg 6 024 10.0 points Rank the following aqueous solutions from lowest to highest boiling point: 0.5 m NaCl, 1 m KCl, 0.5 m BaCl2, 1 m Ba(NO3 )2 ). 1. Ba(NO3 )2 < 0.5 m NaCl < 0.5 m BaCl2 < 1 m KCl 2. 0.5 m NaCl < 0.5 m BaCl2 < 1 m KCl < 1 m Ba(NO3 )2 correct 3. 0.5 m BaCl2 < 1 m KCl < 1 m Ba(NO3 )2 < 0.5 m NaCl 4. 1 m KCl < 1 m Ba(NO3)2 < 0.5 m NaCl < 0.5 m BaCl2 Explanation: All of the solutions ( 0.5 m NaCl, 1 m KCl, 0.5 m BaCl2, 1 m Ba(NO3 )2 ) are composed of strong electrolytes and thus their vant Ho coecients must be taken into account. These are 2, 2, 3 and 3, respectively. Their eective molalities are then 1, 2, 1.5 and 3, respectively. 025 10.0 points A semi-permeable membrane can withstand an osmotic pressure of 0.75 atm. What molarity of aqueous magnesium bromide solution would reach the limit for this membrane? (assume RT = 25 L atm mol1 ). sung (es24394) Homework 2 vanden bout (51640) 1. 0.01 mM 2. 0.03 mM 3. 1 M 4. 0.03 M 5. 0.01 M correct Explanation: Use the formula for osmotic pressure. Remember that magnesium bromide will dissociate into 3 particles, so there will be a Vant Ho factor of 3 for this calculation. 026 10.0 points Catalase (a liver enzyme) dissolves in water. A 16 mL solution containing 0.166 g of catalase exhibits an osmotic pressure of 1.2 Torr at 20 C. What is the molar mass of catalase? 1. 1.58 105 g/mol correct 2. 1.33 105 g/mol 3. 2.53 105 g/mol 4. 2.3 105 g/mol 5. 2.11 10 g/mol 6. 2.81 105 g/mol Explanation: V = 16 mL = 0.016 L T = 20 C + 273 = 293 K R = 0.08206 L atm/K/mol =n m = 0.166 g = 1.2 Torr 5 7 027 10.0 points Why is salting meat a good idea if you want your meat preserved? 1. Salting causes bacteria on meat to incorporate a dangerous amount of salt into their proteins. 2. Salting causes bacteria on meat to dehydrate. correct 3. Salting causes bacteria on meat to swell and burst with water. Explanation: 028 10.0 points Which of the following is a possible combination of values for Hlattice , Hhydration and Hsolution , respectively, for a salt whose dissolution is endothermic. 1. 450, +400, and 50 kJ mol1, 2. +550, 480, and + 1030 kJ mol1 , 3. +640, 620, and + 20 kJ mol1 , correct 4. 900, 900, and 1800 kJ mol1 , Explanation: Hsolution = Hlattice + Hhydration - the problem stipulates that Hsolution be positive (endothermic) and this limits the values the other two terms can have. RT m RT = V MW V mRT V (0.166 g) (0.08206 L atm/K/mol) MW = (0.016 L)(1.2 Torr) 760 Torr (293 K) 1 atm 5 = 1.57986 10 g/mol . M=

Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

University of Texas - CHEM - 302
sung (es24394) Homework 3 vanden bout (51640) This print-out should have 41 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points What is the main overall driving force for any sponta
University of Texas - CHEM - 302
sung (es24394) Homework 4 vanden bout (51640) This print-out should have 42 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points The relationship between the solubility s in water an
University of Texas - CHEM - 302
sung (es24394) Homework 5 vanden bout (51640) This print-out should have 31 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. No problems in Homework 5 require next weeks lecture to be solved. 00
University of Texas - CHEM - 302
sung (es24394) Homework 6 vanden bout (51640) This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points For a weak diprotic acid system (H2 A) which of the f
University of Texas - CHEM - 302
sung (es24394) Homework 7 vanden bout (51640) This print-out should have 29 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points Using the set of smallest possible integer coecients
University of Texas - CHEM - 302
Version 287 Exam 1 vanden bout (51640) This print-out should have 31 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 0.0 points An animal cell assumes its normal volume when it is placed in
University of Texas - CHEM - 302
Version 199 Exam 2 vanden bout (51640) This print-out should have 32 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points When mixed together which two solutions would yield a buer w
University of Texas - CHEM - 302
Today Galvanic Cells Spontaneous Electrochemistry Electrolytic Cells Backwards ElectrochemistryPrinciples of Chemistry II Vanden BoutBalancing Redox Reactions There is a method (actually several) Learn one (4.10-4.12) Practice (worksheet)Principles of
University of Texas - CHEM - 302
Which has a higher Enthalpy?What in the world is Enthalpy? If somehow you have forgotten last semester, then you need to know that Enthalpy is essentially Energy Technically, the change in enthalpy H for a process at constant pressure is equal to the hea
University of Texas - CHEM - 302
Have you been reading my notesFree Energy Change What is the sign of the change in free energy for me dropping an eraser?! ! ! A.! ! B.! ! C.! ! D.! ! negative (free energy decreases) positive (free energy increases) zero (free energy is constant) it de
University of Texas - CHEM - 302
Mixtures What happens to the properties (phase changes) when we make a solution?Let's look at the following &quot;reaction&quot; water + salt -&gt; &quot;salt water&quot;Which has the higher entropy?! ! ! ! Principles of Chemistry II Vanden BoutA.! ! B.! ! C.! !The water
University of Texas - CHEM - 302
Chemical Equilibria Why do we care?!Principles of Chemistry II Vanden BoutPut stuff in a beaker and what do you get? We can use thermodynamics to predict the molecular concentrations at equilibrium (very powerful!)2H2O(g)2H2(g) + O2(g)rG = +113.4 kJ
University of Texas - CHEM - 302
Solubility Our start in adventures in Aqueous EquilibriaPrinciples of Chemistry II Vanden BoutSea Shells are essentially Calcium Carbonate crystals held together by proteinsGiven this information what do you think equilibrium constant will be for this
University of Texas - CHEM - 302
Acid Base Equilibria(if youve missed it biochemistry is mostly aqueous chemistry)H2O(l) H+(aq) + OH-(aq)Critical for most aqueous chemistryPrinciples of Chemistry II Vanden BoutFor this reaction which has a higher entropy? H2O(l) H+(aq) + OH-(aq)
University of Texas - CHEM - 302
If you know [H+] you know [OH-] Kw = [H+][OH-] log(Kw) = log([H+][OH-]) log(Kw) = log[H+]+ log[OH-]log(10-14) = log[H+]+ log[OH-] -14 = -pH - pOH 14 = pH + pOHPrinciples of Chemistry II Vanden BoutWeak Acid HA(aq) HA I C EKa =H+(aq) + A-(aq) H+ O +x
University of Texas - CHEM - 302
Neutralization Buffers TitrationPrinciples of Chemistry II Vanden BoutHA(aq)H+(aq) + A-(aq)How are we going to control this equilibrium? Add H+ shift to the &quot;reactants&quot;Remove H+ (Add OH-) shift to the &quot;products&quot;Principles of Chemistry II Vanden Bo
University of Texas - CHEM - 302
Today Titration determining something about an unknown by reacting it with a known solution Polyprotic AcidsPrinciples of Chemistry II Vanden BoutTitration Why do a titration. You have a solution with an unknown property Unknown Concentration? Unknown
University of Texas - CHEM - 302
Polyprotic Acids More than one acid/base groupPrinciples of Chemistry II Vanden BoutMonoprotic Acid Nitric AcidPrinciples of Chemistry II Vanden BoutPolyprotic Acid Phosphoric AcidPrinciples of Chemistry II Vanden BoutPolyprotic Acid Phosphoric A
University of Texas - CHEM - 302
Lets think about AcidsPrinciples of Chemistry II Vanden BoutWhat is in solution? Which of the following is amphiprotic? A. B. C. D. E. H3PO4 NaH2PO4K3PO4NaCl Na3PO4Principles of Chemistry II Vanden BoutWhat
University of Texas - PHYSICS - 303L-MI
sung (es24394) Reection 1 chiu (57460) This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 (part 1 of 7) 10.0 points14. A.vector= vector(3, 0, 0) B.vector= vector
University of Texas - PHYSICS - 303L-MI
sung (es24394) Reection 2 chiu (57460) This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 (part 1 of 6) 10.0 points What happens when you make both dipole charges
University of Texas - PHYSICS - 303L-MI
sung (es24394) Reection 3 chiu (57460) This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 (part 1 of 6) 10.0 points Looking in the direction of motion of the char
University of Texas - PHYSICS - 303L-MI
Version 066 Exam 1 chiu (57460) This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points A lightweight metal ball hangs from a thread, to the right of an pl
University of Texas - PHYSICS - 303L-MI
Version 104 Exam 2 chiu (57460) This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points = 2kqs 1 1 +2 2 2a 2b .1 (1)Multiplying eq(1) by the electronic c
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 1Name: _ Section:This assignment is due next week in your section. Please put your answers on a separate piece of paper with your name and section listed on the top. Required Problems: 1.) Which level of measurement (nomina
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 2 1.) The data below summarize results of a survey that asked teens and adults to identify the single top government research priority. (Business Week, December 6, 2004.) Research Area Alternative Energy Stem-cell research Wa
Cornell - AEM - 2100
AEM 2100 Spring 2011Name _ Section _ HOMEWORK #31.)Five applicants for real estate appraisal training, two from Oregon and three from Florida, have submitted their scores on different real estate appraisal aptitude exams. The two from Oregon had taken
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 4 1.)Name: _A group of financiers is attempting to acquire control over an airline and over a steel manufacturer. They feel that the probabilities are 0.27, 0.18, and 0.14 that they will win control over the airline, the st
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 5Name: _ Section:_This homework is not to be handed in. The answer key will be posted on the AEM 2100 Web page. 1.) Let X denote the response of a randomly selected person to the question, What is the ideal number of childr
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 6 1.)Name _ Section_Records indicate that the daily high January temperatures on a tropical island tend to have a uniform distribution over the interval from 75F to 90F. A tourist arrives on the island on a randomly selecte
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 7 1.)Name: _A study of drivers reveals that, when lost, 45% will stop and ask for directions, 30% will consult a map, and 25% will continue driving until the location has been determined. Suppose that a sample of 200 driver
Cornell - AEM - 2100
73.28 93.52 108.27 91.89 97.96 68.57 112.14 86.78 98.9 99.37 108.69 98.03 107.27 105.33 110.41 95.26 95.32 110.68 123.42 86 119.27 124.97 110.49 101.72 99.17 124.33 94.03 120.71 132.47 104.5 72.85 123.4 91.13 91.95 88.61 117.02 81.38 95.28 88.36 113.81 90
Cornell - AEM - 2100
Name(LastName,FirstName)SeatNumberAcres,Gavin(gpa25)| A3 ADITYA,MONA(ma478)|ma478 A5 Agunloye,Olufunmilayo(oca3)| A6 Ahmed,Shah(sga34)| A8 Ahn,Kristopher(ka277)| A10 Aker,Rebecca(rla66)| A12 Akker,Yuliya(ya59)| A14 Alabi,Shanique(sba43)| A16 Alvarez,Mig
Cornell - AEM - 2100
Lecture 10Non-tariff Trade Barriers (NTB's) Import quotas Voluntary export restraints (VER's) Export embargoes and controls Dumping Export subsidies and taxes Import subsidies Technical barriers to trade Sanitary and phyto-sanitary restrictionsAEM-ECON
Cornell - AEM - 2100
Type of Method of Customer Customer Items Net Sales Payment Gender 1 Regular 1 39.50 Discover Male 2 Promotional 1 102.40 Proprietary Card Female 3 Regular 1 22.50 Proprietary Card Female 4 Promotional 5 100.40 Proprietary Card Female 5 Regular 2 54.00 Ma
Cornell - AEM - 2100
AEM2100Prelim1is: Thursday,March10 KennedyAuditorium 7:309:30Itwillcoverchapters13(yellowpages),along withHomeworkandSections14.Bringyour calculator ,andaruler.TheMakeupexamis: Saturday,March12 Room:Warren345 Ifyouhaveadirectconflictwiththeexam,or makeu
Cornell - AEM - 2100
Results - AEM 2100 Prelim 1 Spring 201190 - 104 79 - 89 69 - 78 59 - 68 &lt;59 B C D F A (32%)(29%) (26%) (9%) (4%)Mean = 81.9, Median = 83, Std. Dev. = 12.8 Regrades: Please turn in your exam with a note explaining your concern to Dr. van Es after class.
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 4 1.)Name: _ Section:A salesperson has seven products that he wishes to display at a national convention. He can display only four. The order in which he displays the product is immaterial. How many displays does he have to
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 7 1.)Name: _ Section:When confronted with an in-flight medical emergency, pilots and crew can consult staff physicians at MedAire, an emergency facility in Tempe, Arizona. If MedAire is called, there is a 4.8 percent chance
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 3 1.)Name: _ Section:A movie theater whose average monthly attendance was 12,000 persons, with a standard deviation of 2,000, increased its attendance in a certain month to 14,000 persons. An art museum whose average monthly
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 1 1.)Name: _ Section:A food products company is considering marketing a new snack food. To see how consumers react to the product, the company conducted a taste test using a sample of 100 randomly selected shoppers at a subu
Cornell - AEM - 2100
AEM 2100 Spring 2011 1.)Name: _ Section:Section 2 We are interested in describing two variables concerning the students in this section: &quot;Gender,&quot; and &quot;Season of Birth.&quot; Season of Birth is defined in the following manner: Fall - September, October, Nove
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 6 1.)Name _ Section _On average, 30-minute television sitcoms have 22 minutes of programming (CNBC, February 23, 2006). Assume that the probability distribution for minutes of programming can be approximated by a uniform dis
Cornell - AEM - 2100
AEM 2100, Spring 2011WEEK IN REVIEWJan 31 Feb 3SECTION 1Data: Values that are collected, analyzed, and summarized- the observed outcomes of random variables. Data Set: Collection of data for a particular study. Element: Entities on which data are coll
Cornell - AEM - 2100
AEM 2100, Spring 2011WEEK IN REVIEWFeb 7-10SECTION 2 * Be sure to use the appropriate measure!Descriptive Statistics: Concerned with the presentation, summarization, and description of data Classification of Data:Qualitative Tabular Descriptio n Meth
Cornell - AEM - 2100
75% 89% 94% AEM 2100, Spring 2011 WEEK IN REVIEW - 2 95% SECTION 3 + 2 100% - 3 + 3 Uses of the Mean and Standard Deviation: Z-Score: indicates the number of standard deviations a data value is from the mean (unitless). - 4 + 4Feb 14-17 (population) A
Cornell - AEM - 2100
AEM 2100, Spring 2011 .75+.25 C C )F) CFP(N)=.75 =.9+.1=1 (NP(N)P(F/N(.25)(.70) = .175.075675 P(NP(N/N(.75)(.10) = = . F FComplements .075 =.7+.3=1C)=.70 P(FP(F/N)=.10 = C)=.30C/N)=.90 (.25)(.30) = =P(F (.75)(.90) )=.25 )1 = =1CC CWEEK IN REVIEWFeb 21-
Cornell - AEM - 2100
AEM 2100, Spring 2011Random Variable: A random variable, X, associates one and only one numerical value to each sample event of an experiment Two types: 1.Discrete (countable, how many times did the event happen?) 2.Continuous (measurable, can take on an
Cornell - AEM - 2100
AEM 2100, Spring 2011WEEK IN REVIEWMarch 7-10x c d SECTION x 6 X ~ (40, 5) f(x) zCONTINUOUS PROBABILITY DISTRIBUTIONS Probability is analogous to area No probability at a point (i.e. P(X = x*) = 0)This is in contrast to discrete probability distribut
Cornell - AEM - 2300
AEM 2300/ECON 2300Section #4February 21/ 22, 20111) Given below are the domestic supply and demand schedules (under autarky) for televisions in Portugal. Price of TV 350 300 250 200 150 100 50 0 Quantity Demanded 0 150 300 450 600 750 900 1050 Quantity
Cornell - AEM - 2300
AEM 2300/ECON 2300: International Trade and FinanceProfessor David Lee Dyson School of Applied Economics and Management 441 Warren HallProf. David LeeAEM/ECON 2300The New York Times, Jan. 16, 2011Prof. David LeeAEM/ECON 23002 ofThe Financial Times
Cornell - AEM - 2300
Lecture 3BASIC DEFINITIONS (2)Production Possibility Frontier (PPF): curve showing all possible combinations of outputs of two products that a producer (or economy) can produce with resources fully employed and the best available technology Marginal Rat
Cornell - AEM - 2300
BASIC DEFINITIONSAbsolute advantage: producing a product more (most) efficiently lowest absolute cost e.g. at compared to other countries or producers.Opportunity cost: the number of units of one good you must sacrifice to get one additional unit of ano
Cornell - AEM - 2300
Lecture 4BASIC DEFINITIONS (2 - contd): DEMAND SIDEIndifference Curve (IC): curve showing all possible points of consumption of two goods which yield an equal level of utility or satisfaction. Marginal Rate of Substitution (MRS): the amount of one produ
Cornell - AEM - 2300
Lecture 5So what determines Comparative Advantage? Cost structure of an industry (increasing, decreasing?) National and international product prices Are marginal (opportunity) costs of production covered by prices? Consumer demands Another determinant
Cornell - AEM - 2300
Lecture 6International Trade EquilibriumP P ESA SA P* EDB PA DA Q A1 QA2 QA Q*International marketPSBPBDBQTQB1QB2QBExporting countryImporting countryES At (P*, A = excess supply = SA1-=DA B2 QB1 Q*): Q* = QA2 QA QEDB = excess demand = DB -
Cornell - AEM - 2300
Lecture 7Tariffs a tax on importsProfessor David LeeAEM/ECON 23001 ofLecture 7Tariffs a tax on importsPurposes: 1. Raise government revenuesProfessor David LeeAEM/ECON 23002 ofLecture 7Tariff revenues as a percentage of government revenues, 20
Cornell - AEM - 2300
Lecture 8T.F. Siems: Beyond the Outsourcing Angst (Ch. 6) Outsourcing is nothing new; part of a process of pursuing comparative advantage, greater production efficiencies and taking advantage of globalization opportunities Outsourcing today now applies
Cornell - AEM - 2300
Lecture 9Midterm Exam 1 7:30-9:00pm, Tuesday, March 8 A - Geiger: Goldwin Smith 132 Geiszler Seet: Rockefeller 201 Segal - Z: Goldwin Smith G76 Students with pre-approved special arrangements (exam conflicts, extra time), see email from Carol Thomson sen
Cornell - AEM - 2300
Discussion Section 1 Week of January 31st to February 4th 1. Globalization and Current Events 2. Ricardos Model of TradeAn Example The following hypothetical example is a twocountry, twog
Cornell - AEM - 2300
!&quot;#$%#&quot;&amp;'()*$+&quot;&amp;'(,( !&quot;#$%&amp;$'&quot;()*+),$-./$.%$'&quot;()*+),$00./$ $ 01$234+)5%67$8%5&quot;9$%&amp;$:)+5&quot;;&lt;=%./&quot;)$&gt;?+@A9&quot;$ !&quot;#$%&amp;'&amp;()*+$&quot;,-&amp;.&quot;#.)/0'$#102-'#$)3$0$.(&amp;4/&amp;5*.6,7$.(&amp;4+&amp;8$(&amp;6'8$)*$(&quot;)/&quot;$'09&amp;6$)3$ .&quot;#$&amp;*',$)*-5.$.&amp;$-6&amp;85/.)&amp;*:$!&quot;#$%&amp;'&amp;()*+$.09'#$3&quot;&amp;(3$.&quot;#$02&amp;5*