Exam 1-solutions physics
11 Pages

Exam 1-solutions physics

Course Number: PHYSICS 303L-MI, Spring 2011

College/University: University of Texas

Word Count: 2749

Rating:

Document Preview

Version 066 Exam 1 chiu (57460) This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points A lightweight metal ball hangs from a thread, to the right of an plastic rod. (See Figure 1.) Both are initially uncharged. 1 Statement III : IIIa. The induced dipole moment for a conductor occurs over a macroscopic length...

Unformatted Document Excerpt
Coursehero >> Texas >> University of Texas >> PHYSICS 303L-MI

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

066 Version Exam 1 chiu (57460) This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points A lightweight metal ball hangs from a thread, to the right of an plastic rod. (See Figure 1.) Both are initially uncharged. 1 Statement III : IIIa. The induced dipole moment for a conductor occurs over a macroscopic length scale. IIIb. The induced dipole moment for a conductor occurs over an atomic length scale. 1. Ib, IIa, IIIb 2. Ia, IIb, IIIa correct 3. Ia, IIa, IIIb 4. Ib, IIa, IIIa 5. Ia, IIa, IIIa 6. Ia, IIb, IIIb 7. Ib, IIb, IIIa 8. Ib, IIb, IIIb Explanation: Answer to statement I: The excess negative charge at the left end leads to the alignment of induced dipoles in the interior of the insulator rod. For the metal rod case, free electrons are on the surface of the rod. Ia is correct. Answer to statement II: Since electrons are free to move along the surface of a conductor, the average location of the free electrons in the conductor is closer to the average location of the induced negative charges in in the ball than is the case for the insulator. So the former gives a stronger attraction. IIb is correct. Answer to statement III: The induced dipole moment for the conductor is distributed throughout the conductor. Hence, the dipole moment induced is across a macroscopic length scale. IIIa is correct. 002 (part 1 of 2) 10.0 points Suppose you want to create an electric eld = 2, 2, 0 N /C at the origin located at 0, 0, 0 . Where would you place an electron to create this eld? Denote the coordinate vector of the electron by r = r r Determine r The plastic (insulator) case: You rub the left end of the plastic rod with wool, depositing charged molecular fragments whose total negative charge is that of 1 109 electrons. The metal (conductor) case: You perform a similar experiment with a conducting metal rod. You touch the left end of the rod with a charged metal object, depositing the same excess electrons to the left end. You then remove the object. Statement I : Consider two cases below: (i). There are polarized dipoles inside of the rod. (ii). There are electrons at the surface. Ia. (i) is applicable for the insulator. (ii) is applicable for the conductor. Ib. (ii) is applicable for the insulator. (i) is applicable for the conductor. Statement II : Compare the attraction between the rod and the ball IIa. The insulator rod has more attraction. IIb. The conductor rod has more attraction. Version 066 Exam 1 chiu (57460) 1. 1, 1, 0 1, 1, 0 2 1, 1, 0 3. 2 1, 1, 0 correct 4. 2 2. 5. 1, 1, 0 6. 2 1, 1, 0 7. 2 1, 1, 0 1, 1, 0 2 Explanation: The electron has a negative charge. The direction of the vector should along the direction of the electric eld. 8. E =E= r E 1 = 2, 2, 0 r 8 1 = 1, 1, 0 r 2 003 (part 2 of 2) 10.0 points Find the magnitude r (in units of m). 1. 2.26 107 m 2. 0.000452 m 3. 2.26 105 m correct 4. 0.000226 m 5. 2.26 106 m 6. 0.00226 m 7. 0.000678 m 8. 1.13 106 m 2 The magnitude of E is given by |E | = E = 2 2. But, we also know that E= r= ke r2 ke = 2.26 105 m E 004 10.0 points A wire 3 m long lying on the X-axis has a nearly uniform charge. The electric eld at location 0.02, 0.01, 0 m is 0, 66000, 0 N /C . What is the total charge on the wire? 1. -1.57e-07 2. -1.27e-07 3. -1.75e-07 4. -1.68e-07 5. -2.5e-07 6. -2.28e-07 7. -1.01e-07 8. -1.6e-07 9. -2.35e-07 10. -2.46e-07 Correct answer: 2.46 107 C. Explanation: Since the E-eld is negative, the charge generating it must also be negative. The distance r is given by r= x2 + y 2 + z 2 = 0.02236 m The magnitude of the electric eld is given by the formula E 1 2(Q/L) 4 0 r Hence the charge is given by Q = 2 0E L r = 2.46 107 C Explanation: 005 10.0 points A large, thin plastic disk with radius R = 1.6 m meter carries a uniformly distributed negative charge of Q = 7.7 105 C as shown in the Figure below. A circular piece of aluminum foil is placed d = 3 mm from the Version 066 Exam 1 chiu (57460) disk, parallel to the disk. The foil has a radius of r = 4 cm and a thickness t = 1 mm. The foil is neutral. Plastic disk R = 1. 6 m t = 1 mm r= d = 3 mm Close-up of foil 3 point indicated by the x-symbol, Enet Edisk + Ef oil Q 1q 1 + 2 0 Adisk 0 Af oil Q Af oil | q |= 2 Adisk =0 =0 =0 Q r2 = 2 R2 7.7 105 C = 2 = 2.41 108 C . 4 cm (0.04 m)2 (1.6 m)2 Calculate the magnitude q of the induced charge on the left circular face of the foil. 1. 6.94e-09 2. 2.44e-09 3. 2.23e-08 4. 1.13e-08 5. 3.84e-08 6. 2.41e-08 7. 9.94e-09 8. 1.4e-08 9. 3.25e-08 10. 1.44e-08 Your answer must be within 2.0% Correct answer: 2.41 108 C. Explanation: 006 10.0 points Consider the following two objects. A: a uniformly charged disk. B: a uniformly charged ring. Choose the correct pair of statements. When z R, the E eld is approximately constant for Ia. A only Ib. B only Ic. A and B When z R, the E eld is approximately proportional to z 2 for IIa. A only IIb. B only IIc. A and B 1. Ic, IIa 2. Ic, IIb 3. Ia, IIb 4. Ib, IIb 5. Ic, IIc 6. Ib, IIa Let : R = 1.6 m , r = 4 cm = 0.04 m , d = 3 mm , Q = 7.7 105 C t = 1 mm . and 7. Ia, IIc correct 8. Ia, IIa 9. Ib, IIc Explanation: In the gure, within the enlarged foil, at the Version 066 Exam 1 chiu (57460) Ia. For z R, the E eld of the ring rises linearly but the E eld of the disk is approximately constant. Ering = 1 qz 4 0 (R2 + z 2 )3/2 Q/A 20 4 Edisk = IIc. All nite charge distributions resemble a point charge when viewed from afar. 007 10.0 points A positive and a negative particle of equal magnitude of charge e are equidistant from a point C. The two particles and C are all collinear, and the two particles produce an E eld pointing north at C. If the particles are replaced by new particles 11 times farther away from C, what magnitude of charge must these new particles have in order to produce the same E eld at C? (Express your answer in units of Coulombs.) 1. 7.056e-17 2. 4.624e-17 3. 4.096e-17 4. 7.744e-17 5. 3.136e-17 6. 2.56e-18 7. 1.936e-17 8. 1.6e-17 9. 5.76e-18 10. 7.84e-18 Correct answer: 1.936 1017 C. Explanation: The eld due to the two particles is Ec = 1 2q 4 0 r 2 Two dipoles are oriented as shown in the gure above. Each dipole consists of two charges +q and -q, held apart by a rod of length s, and the center of each dipole is a distance d from location A. The dipole moment is given by p = qs. The magnitude and the direction of the dipole eld vector contributed by the lower-left dipole only is given by kp , up correct d3 kp 2. 3 , down d kp 3. 2 , up d 2kp 4. 2 , up d kp 5. 2 , down d 2kp 6. 3 , down d 2kp 7. 3 , up d 2kp 8. 2 , down d Explanation: At A the bottom one has a contribution of kp in the upwards direction. d3 1. 009 (part 2 of 2) 10.0 points Determine the magnitude of the resultant eld vector contributed by both dipoles. 1. 008 (part 1 of 2) 10.0 points 4kp d3 From this formula, observe that that if E is held xed, q is proportional to r 2 . Hence the value of q is q = e (11)2 = 1.936 1017 C Version 066 Exam 1 chiu (57460) 2. 3. 4. 5. 6. 7. 8. 9. 5kp d3 3kp correct d3 kp d3 kp 5d3 kp 3d3 kp 4d3 2kp d3 kp 2d3 5 the same direction and a negative ratio implies that they are pointing in the opposite direction. Determine this ratio. 1. 2 2. 2 3. - 3 4. - 2 correct 5. 3 6. 1 7. - 8 8. -2 9. -1 10. 8 Explanation: Notice that at A, E1 is perpendicular to E3 . The magnitude of E13 is given by E13 = where E1 = 2 2 E1 + E3 = 2kp At A the top dipole contributes 3 in the d upwards direction. Hence, the resulting total 3kp eld is 3 . d 010 10.0 points Explanation: 2E1 kq , and by symmetry E3 = E1 . a2 By inspection the magnitude of E2 is k (2q ) kq E2 = = 2 = E1 2 a ( 2a ) Consider the setup shown in the gure, where charges Q1, Q2 and Q3 and the point A occupy four corners of a square with the length a at each side. Given that Q1 = Q3 = q > 0 and Q2 = 2q . The resultant electric eld at A contributed by charges Q1 and Q3 is labeled as E13 . The electric eld at A contributed by Q2 is labeled as E2 . Verify that the vectors E13 and E2 are aligned along a same line. Such an E13 alignment implies that the ratio may be E2 represented by a number. Here, a positive ratio implies two that vectors are pointing in E13 and E2 are aligned along the same line and are pointing in the opposite direction. E13 The ratio is a negative number. So, we E2 have E13 2E 1 = E1 E2 E13 E2 011 = 2 10.0 points Version 066 Exam 1 chiu (57460) 6 A neutral copper block is polarized as shown in the above gure, due to an electric eld made by external charges (not shown). Consider the following statements: By inspection of the gure the correct answer is Ib, IIa, IIIa. The applied eld is responsible for having the positive surface charge at the bottom. So the applied eld is downward (Ib). The dipole eld direction runs from positive charge (the source) to the negative charge (the sink). So the eld goes up (IIa). Within the conducting medium, there are abundant free electrons. At equilibrium Enet at B must be zero. Otherwise free electrons will be moving. It will no longer in equilibrium.(IIIa) 012 10.0 points Ia. The applied external eld is pointing upward. Ib. The applied external eld is pointing downward. IIa. The dipole eld due to the surface charges is pointing upward. IIb. The dipole eld due to the surface charges is pointing downward. IIIa. At equilibrium, the magnitude of the net eld at B is zero. IIIb. The magnitude of the net eld at B is not zero even at equilibrium. 1. Ib, IIb, IIIa 2. Ib, IIa, IIIb 3. Ia, IIa, IIIb 4. Ia, IIb, IIIb 5. Ia, IIa, IIIa 6. Ib, IIa, IIIa correct 7. Ia, IIb, IIIa 8. Ib, IIb, IIIb Explanation: This problem concerns the two cases shown in the gures above. The top gure shows a positively charged glass sphere surrounded by a plastic shell while the bottom gure shows a positively charged glass sphere surrounded by a metal shell. Choose the correct pair of statements. If the magnitude of the E eld at the points Version 066 Exam 1 chiu (57460) is designated EP,p and EP,m for the plastic and metal cases, respectively, then Ia. EP 1,p > EP 1,m Ib. EP 1,p < EP 1,m Ic. EP 1,p = EP 1,m and IIa. EP 2,p > EP 2,m IIb. EP 2,p < EP 2,m IIc. EP 2,p = EP 2,m 1. Ib, IIb 2. Ic, IIb 3. Ib, IIa 4. Ia, IIa 5. Ia, IIb 6. Ia, IIc correct 7. Ib, IIc 8. Ic, IIa 9. Ic, IIc 7 Explanation: Ia. When exposed to an external E eld, the E eld inside of a conductor is zero, but the E eld inside of an insulator is not. IIc. Neither shell aects the E eld at P2 . For the conductor, the inner and outer surface charges produce canceling E elds at P2 . Likewise, for an insulator the radially symmetric distribution of dipoles produces a canceling E eld at P2 . 013 10.0 points The diagrams in Figure 1 show a sequence of events described below, which involves a small lightweight solid metal ball that is suspended from a cotton thread. (a) You touch the ball briey with your ngers then release it. (b) A block of metal that is known to be charged is now moved near the ball. (c) The ball briey touches the charged metal block. Then the ball swings away from the block and hangs motionless at an angle as shown in diagram 5 of Figure 1. (d) Finally the block is moved far away. A negatively charged rod is brought near the ball. The ball is repelled by the charged rod shown in diagram 6 of Figure 1. Among distributions E through N shown in Figure 2, which of the diagrams best shows the distribution of charge in the ball in slide 3 of Figure 1? Version 066 Exam 1 chiu (57460) 8 A plastic hollow sphere, which is uniformly charged with negative charge on its surface, is placed near the center of a horizontal plastic rod, which is uniformly charged with negative charge. What is the direction of the electric eld vector at P due to the charges on the plastic sphere alone? 1. L 2. K 3. E 4. F 5. G 6. J 7. H 8. M 9. N correct 10. I 1. direction 2 2. Zero magnitude correct 3. direction 4 4. direction 7 5. direction 5 Explanation: From the nal slide, we know the sphere is negatively charged. The only way it could have obtained this negative charge is from contact with the box, which therefore also must have been negatively charged. In slide 3, the sphere has a net charge of zero, but polarizes such that the positive side is closer to the negatively charged box. 014 (part 1 of 2) 10.0 points 6. direction 3 7. direction 1 8. direction 6 9. direction 8 Explanation: Since the charge distribution on the surface is uniform, the eld at P due to the charges on the sphere alone is 0. Version 066 Exam 1 chiu (57460) 015 (part 2 of 2) 10.0 points What is direction of the resultant eld vector contributed by the rod plus the sphere? 9 1. direction 5 correct 2. direction 6 3. direction 7 4. Zero magnitude 5. direction 1 6. direction 4 7. direction 8 8. direction 2 9. direction 3 The center of the spherical metal ball of radius R, carrying a negative charge -Q is located at a distance r from A. The point A is the center of a short, thin neutral copper wire of length L. The induced charges at the two ends of the wire is q . Using the condition that the eld at A due to -Q cancels the eld at A due to the induced dipole in the copper wire, one nds that: q= QL 8r 2 Determine the polarizability of the wire segment which has a length L = 0.0075 m. 1. 1.389e-17 2. 3.814e-18 3. 5.859e-18 4. 2.4e-17 5. 4.234e-17 6. 2.112e-17 7. 1.736e-18 8. 1.608e-17 9. 1.849e-17 10. 3.417e-17 Your answer must be within 2.0% Correct answer: 5.859 1018 . Explanation: The polarizability is given by = Explanation: The E eld due to the charged shell is 0 and the E eld due to the rod points downward. By the principle of superposition the correct answer is that the E-eld points in direction 5. 016 10.0 points qL p = kQ E r2 Using the value of q given above = (Q/8)(L/r )2 L kQ r2 L3 = 5.859 1018 = 8k Version 066 Exam 1 chiu (57460) 017 10.0 points 10 Two small, negatively charged plastic spheres are placed near a neutral iron block, as shown in the above gure. Which choice (a to j) in the gure best indicates the direction of the net electric eld at location A? 1. d 2. e 3. g 4. a 5. j 6. f correct 7. c 8. i 9. b 10. h Explanation: At A there is no net eld due to the negative charge pair. The elds contributed by the pair are equal and opposite and they cancel each other. There are induced charges at the left and lower surfaces of the iron cube which are symmetrically distributed by the 45 line and they are positive. There are also negative charges symmetrically distribution about the 45 line far away. The nearside charges dominate. By inspection f is the correct direction. 018 10.0 points A negatively charged iron block is placed in a region where there is an electric eld downward (in the y direction due to charges not shown). Which of the diagram in the gure above best describes the charge distribution in and/or on the iron block? (Caution: You should bubble your numerical choice, NOT the letter label of the diagram) 1. d 2. f 3. b 4. e 5. c correct 6. a Explanation: For present problem, the following 3 conditions must be satised: (i) Conductor medium: Net charges can only be at the surface. (ii) Net charge is negative. (iii) E is downward, negative charge moves upward. More negative charge in the upper surface is expected. Only diagram c satises all three conditions. a violates (ii) b violates (ii) d violates (iii) e violates (i) f violates (iii) 019 10.0 points Version 066 Exam 1 chiu (57460) Which is the correct integral formulation for the electric eld on the axis of a uniformly charged disk of total charge Q and radius R? 2 11 1. Ez = 0 1 4 0 Q R2 (R 2 z d + z 2 )3/2 2. Ez = 0 3. Ez = correct 4. Ez = Q z 1 d 4 0 2 (R2 + z 2 )3/2 R 1 Q z r dr 2 2 + z 2 )3/2 R (r 0 20 Q z 1 r dr R2 (R2 + z 2 )3/2 0 20 R Q z 1 5. Ez = r dr 2 + z 2 )3/2 2 ( r 0 20 2 Q z 1 d 6. Ez = 4 0 2 (R2 + z 2 )3/2 0 R Q z 1 r dr 7. Ez = 2 + z 2 )3/2 2 ( R 0 20 Q z 1 d 8. Ez = 2 2 + z 2 )3/2 R (R 0 4 0 Explanation: The electric eld of a uniformly charged thin ring is given by 1 qz E= 4 0 (R2 + z 2 ) 3/2 A disk can be divided into a sequence of concentric rings. The only non-vanishing component of the electric eld will be in the z direction. 1 q z E z = 4 0 (r 2 + z 2 ) 3/2 Now, we evaluate q and it is given by 2r r q = Q R2 For an innitesimal ring, we have 1Q z r dr dEz = 22 2 0 R (r + z 2 ) 3/2 Thus, the value of Ez is R R Ez = 0 1 20 Q R2 z r dr (r 2 + z 2 )3/2

Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

University of Texas - PHYSICS - 303L-MI
Version 104 Exam 2 chiu (57460) This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points = 2kqs 1 1 +2 2 2a 2b .1 (1)Multiplying eq(1) by the electronic c
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 1Name: _ Section:This assignment is due next week in your section. Please put your answers on a separate piece of paper with your name and section listed on the top. Required Problems: 1.) Which level of measurement (nomina
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 2 1.) The data below summarize results of a survey that asked teens and adults to identify the single top government research priority. (Business Week, December 6, 2004.) Research Area Alternative Energy Stem-cell research Wa
Cornell - AEM - 2100
AEM 2100 Spring 2011Name _ Section _ HOMEWORK #31.)Five applicants for real estate appraisal training, two from Oregon and three from Florida, have submitted their scores on different real estate appraisal aptitude exams. The two from Oregon had taken
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 4 1.)Name: _A group of financiers is attempting to acquire control over an airline and over a steel manufacturer. They feel that the probabilities are 0.27, 0.18, and 0.14 that they will win control over the airline, the st
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 5Name: _ Section:_This homework is not to be handed in. The answer key will be posted on the AEM 2100 Web page. 1.) Let X denote the response of a randomly selected person to the question, What is the ideal number of childr
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 6 1.)Name _ Section_Records indicate that the daily high January temperatures on a tropical island tend to have a uniform distribution over the interval from 75F to 90F. A tourist arrives on the island on a randomly selecte
Cornell - AEM - 2100
AEM 2100 Spring 2011 Homework 7 1.)Name: _A study of drivers reveals that, when lost, 45% will stop and ask for directions, 30% will consult a map, and 25% will continue driving until the location has been determined. Suppose that a sample of 200 driver
Cornell - AEM - 2100
73.28 93.52 108.27 91.89 97.96 68.57 112.14 86.78 98.9 99.37 108.69 98.03 107.27 105.33 110.41 95.26 95.32 110.68 123.42 86 119.27 124.97 110.49 101.72 99.17 124.33 94.03 120.71 132.47 104.5 72.85 123.4 91.13 91.95 88.61 117.02 81.38 95.28 88.36 113.81 90
Cornell - AEM - 2100
Name(LastName,FirstName)SeatNumberAcres,Gavin(gpa25)| A3 ADITYA,MONA(ma478)|ma478 A5 Agunloye,Olufunmilayo(oca3)| A6 Ahmed,Shah(sga34)| A8 Ahn,Kristopher(ka277)| A10 Aker,Rebecca(rla66)| A12 Akker,Yuliya(ya59)| A14 Alabi,Shanique(sba43)| A16 Alvarez,Mig
Cornell - AEM - 2100
Lecture 10Non-tariff Trade Barriers (NTB's) Import quotas Voluntary export restraints (VER's) Export embargoes and controls Dumping Export subsidies and taxes Import subsidies Technical barriers to trade Sanitary and phyto-sanitary restrictionsAEM-ECON
Cornell - AEM - 2100
Type of Method of Customer Customer Items Net Sales Payment Gender 1 Regular 1 39.50 Discover Male 2 Promotional 1 102.40 Proprietary Card Female 3 Regular 1 22.50 Proprietary Card Female 4 Promotional 5 100.40 Proprietary Card Female 5 Regular 2 54.00 Ma
Cornell - AEM - 2100
AEM2100Prelim1is: Thursday,March10 KennedyAuditorium 7:309:30Itwillcoverchapters13(yellowpages),along withHomeworkandSections14.Bringyour calculator ,andaruler.TheMakeupexamis: Saturday,March12 Room:Warren345 Ifyouhaveadirectconflictwiththeexam,or makeu
Cornell - AEM - 2100
Results - AEM 2100 Prelim 1 Spring 201190 - 104 79 - 89 69 - 78 59 - 68 &lt;59 B C D F A (32%)(29%) (26%) (9%) (4%)Mean = 81.9, Median = 83, Std. Dev. = 12.8 Regrades: Please turn in your exam with a note explaining your concern to Dr. van Es after class.
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 4 1.)Name: _ Section:A salesperson has seven products that he wishes to display at a national convention. He can display only four. The order in which he displays the product is immaterial. How many displays does he have to
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 7 1.)Name: _ Section:When confronted with an in-flight medical emergency, pilots and crew can consult staff physicians at MedAire, an emergency facility in Tempe, Arizona. If MedAire is called, there is a 4.8 percent chance
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 3 1.)Name: _ Section:A movie theater whose average monthly attendance was 12,000 persons, with a standard deviation of 2,000, increased its attendance in a certain month to 14,000 persons. An art museum whose average monthly
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 1 1.)Name: _ Section:A food products company is considering marketing a new snack food. To see how consumers react to the product, the company conducted a taste test using a sample of 100 randomly selected shoppers at a subu
Cornell - AEM - 2100
AEM 2100 Spring 2011 1.)Name: _ Section:Section 2 We are interested in describing two variables concerning the students in this section: &quot;Gender,&quot; and &quot;Season of Birth.&quot; Season of Birth is defined in the following manner: Fall - September, October, Nove
Cornell - AEM - 2100
AEM 2100 Spring 2011 Section 6 1.)Name _ Section _On average, 30-minute television sitcoms have 22 minutes of programming (CNBC, February 23, 2006). Assume that the probability distribution for minutes of programming can be approximated by a uniform dis
Cornell - AEM - 2100
AEM 2100, Spring 2011WEEK IN REVIEWJan 31 Feb 3SECTION 1Data: Values that are collected, analyzed, and summarized- the observed outcomes of random variables. Data Set: Collection of data for a particular study. Element: Entities on which data are coll
Cornell - AEM - 2100
AEM 2100, Spring 2011WEEK IN REVIEWFeb 7-10SECTION 2 * Be sure to use the appropriate measure!Descriptive Statistics: Concerned with the presentation, summarization, and description of data Classification of Data:Qualitative Tabular Descriptio n Meth
Cornell - AEM - 2100
75% 89% 94% AEM 2100, Spring 2011 WEEK IN REVIEW - 2 95% SECTION 3 + 2 100% - 3 + 3 Uses of the Mean and Standard Deviation: Z-Score: indicates the number of standard deviations a data value is from the mean (unitless). - 4 + 4Feb 14-17 (population) A
Cornell - AEM - 2100
AEM 2100, Spring 2011 .75+.25 C C )F) CFP(N)=.75 =.9+.1=1 (NP(N)P(F/N(.25)(.70) = .175.075675 P(NP(N/N(.75)(.10) = = . F FComplements .075 =.7+.3=1C)=.70 P(FP(F/N)=.10 = C)=.30C/N)=.90 (.25)(.30) = =P(F (.75)(.90) )=.25 )1 = =1CC CWEEK IN REVIEWFeb 21-
Cornell - AEM - 2100
AEM 2100, Spring 2011Random Variable: A random variable, X, associates one and only one numerical value to each sample event of an experiment Two types: 1.Discrete (countable, how many times did the event happen?) 2.Continuous (measurable, can take on an
Cornell - AEM - 2100
AEM 2100, Spring 2011WEEK IN REVIEWMarch 7-10x c d SECTION x 6 X ~ (40, 5) f(x) zCONTINUOUS PROBABILITY DISTRIBUTIONS Probability is analogous to area No probability at a point (i.e. P(X = x*) = 0)This is in contrast to discrete probability distribut
Cornell - AEM - 2300
AEM 2300/ECON 2300Section #4February 21/ 22, 20111) Given below are the domestic supply and demand schedules (under autarky) for televisions in Portugal. Price of TV 350 300 250 200 150 100 50 0 Quantity Demanded 0 150 300 450 600 750 900 1050 Quantity
Cornell - AEM - 2300
AEM 2300/ECON 2300: International Trade and FinanceProfessor David Lee Dyson School of Applied Economics and Management 441 Warren HallProf. David LeeAEM/ECON 2300The New York Times, Jan. 16, 2011Prof. David LeeAEM/ECON 23002 ofThe Financial Times
Cornell - AEM - 2300
Lecture 3BASIC DEFINITIONS (2)Production Possibility Frontier (PPF): curve showing all possible combinations of outputs of two products that a producer (or economy) can produce with resources fully employed and the best available technology Marginal Rat
Cornell - AEM - 2300
BASIC DEFINITIONSAbsolute advantage: producing a product more (most) efficiently lowest absolute cost e.g. at compared to other countries or producers.Opportunity cost: the number of units of one good you must sacrifice to get one additional unit of ano
Cornell - AEM - 2300
Lecture 4BASIC DEFINITIONS (2 - contd): DEMAND SIDEIndifference Curve (IC): curve showing all possible points of consumption of two goods which yield an equal level of utility or satisfaction. Marginal Rate of Substitution (MRS): the amount of one produ
Cornell - AEM - 2300
Lecture 5So what determines Comparative Advantage? Cost structure of an industry (increasing, decreasing?) National and international product prices Are marginal (opportunity) costs of production covered by prices? Consumer demands Another determinant
Cornell - AEM - 2300
Lecture 6International Trade EquilibriumP P ESA SA P* EDB PA DA Q A1 QA2 QA Q*International marketPSBPBDBQTQB1QB2QBExporting countryImporting countryES At (P*, A = excess supply = SA1-=DA B2 QB1 Q*): Q* = QA2 QA QEDB = excess demand = DB -
Cornell - AEM - 2300
Lecture 7Tariffs a tax on importsProfessor David LeeAEM/ECON 23001 ofLecture 7Tariffs a tax on importsPurposes: 1. Raise government revenuesProfessor David LeeAEM/ECON 23002 ofLecture 7Tariff revenues as a percentage of government revenues, 20
Cornell - AEM - 2300
Lecture 8T.F. Siems: Beyond the Outsourcing Angst (Ch. 6) Outsourcing is nothing new; part of a process of pursuing comparative advantage, greater production efficiencies and taking advantage of globalization opportunities Outsourcing today now applies
Cornell - AEM - 2300
Lecture 9Midterm Exam 1 7:30-9:00pm, Tuesday, March 8 A - Geiger: Goldwin Smith 132 Geiszler Seet: Rockefeller 201 Segal - Z: Goldwin Smith G76 Students with pre-approved special arrangements (exam conflicts, extra time), see email from Carol Thomson sen
Cornell - AEM - 2300
Discussion Section 1 Week of January 31st to February 4th 1. Globalization and Current Events 2. Ricardos Model of TradeAn Example The following hypothetical example is a twocountry, twog
Cornell - AEM - 2300
!&quot;#$%#&quot;&amp;'()*$+&quot;&amp;'(,( !&quot;#$%&amp;$'&quot;()*+),$-./$.%$'&quot;()*+),$00./$ $ 01$234+)5%67$8%5&quot;9$%&amp;$:)+5&quot;;&lt;=%./&quot;)$&gt;?+@A9&quot;$ !&quot;#$%&amp;'&amp;()*+$&quot;,-&amp;.&quot;#.)/0'$#102-'#$)3$0$.(&amp;4/&amp;5*.6,7$.(&amp;4+&amp;8$(&amp;6'8$)*$(&quot;)/&quot;$'09&amp;6$)3$ .&quot;#$&amp;*',$)*-5.$.&amp;$-6&amp;85/.)&amp;*:$!&quot;#$%&amp;'&amp;()*+$.09'#$3&quot;&amp;(3$.&quot;#$02&amp;5*
Cornell - AEM - 2300
Country 1GoodATrade MarketGoodACountry 2ProductionGoodBGoodB PriceB PriceBSupply / DemandPriceBGoodB GoodAGoodB GoodAGoodBConsumptionGoodBGoodBCountry 1GoodATrade MarketGoodACountry 2ProductionGoodBGood
Cornell - AEM - 2300
Welfare of TradeJoel R. Landry AEM 2300International Trade and Finance, Spring 2011 Prof. David Lee Spring 2011 March 3, 2011This handout is intended as a complement to the graphical analysis presented in class and section, not as a substitute. If you t
Shanghai Jiao Tong University - ME - ME461
BullwhipEffect 3 + TheImpactofBullwhipEffectUndoubtedly, the observation and explanation of Bullwhip Effect help manufacturing enterprisesaswellasretailcompaniesmodifytheirsupplychaintoeliminatetheside effectofBullwhipasmuchaspossible.However,notonlythos
Shanghai Jiao Tong University - ME - ME461
MEMSinMedicineABSTRACTMEMS, or Micro-Electro-Mechanical Systems are chips that are made in semiconductor fabs that combine electronic functions and mechanical actions. MEMS devices can sense and control making them valuable for numerous applications.But
Shanghai Jiao Tong University - ME - ME461
LOGOMEMS in MedicineChuanqi Wei 5078056012 F0802009Wei ChuanqiContents1 2 3 4What is MEMS? How does MEMS work? Applications of MEMS in medicine ConclusionWei ChuanqiWhat is MEMS?The first computer in the world ENIAC(1944)IBM SAGE-computer(1954)
Shanghai Jiao Tong University - ME - ME461
* @ p + $ Z ~ T D @ p + $ Z ~ ) D @ @ p + $ Z ~ O D @ @ D @ @ @ p + $ Z ~ N D p + $ Z ~ u D @ @ p + $ Z ~ D @ @ p + $ Z ~ D @ @ @ @ p + $ Z ~ L D @ @ p + $ Z ~ s D @ @ 4 H H 4 $ @ D@ ~ D p + $ Z K @ D@ ~ D p + $ Z X$ W+ $@ @ D ~ D p + $ Z X$ W+ s@ D ~ @
Shanghai Jiao Tong University - ME - ME461
5080209017 1 2 3 1 2 3MinitabExcel 4 GDP GDP 1978 1979 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 GDP() 272.81 286.43 311.89 324.76 337.07 351.81 390.85 466.75
Shanghai Jiao Tong University - ME - ME461
15 2008 2 7 / v v v v v 2009 :P+ ? 5.12 t * d * d * d * d * d k * * * * ** i i i i i i @* A A A A A A20 1 ? ? ? ? ? ? d * ? ?H0 H H H H5 0 0 0 0P+ * * * * *@ h h h h h* * * * * 2 ? 7 v* v* Y, v* ZF P+ d* d* d* v* H0 * i H0 H0 = * * d* h*v* i
Shanghai Jiao Tong University - ME - ME461
*q* _ . D_zE N u+ @ @E p N z D@E N uuE@ _z pz + D_zE N u@ @ pE +z D_E N@ @ u p + z q* *. _ F0802009 5080209276 F0802009 5078056012 1630q* . * _ M athmatica z *EI D_zE @ N uKE pz + @ @ @ @ D_zE @ N uE pz @ + r _ + ME @ @ z * r _ +.1630 D_z N u+z pE sE
Shanghai Jiao Tong University - ME - ME461
*F 0802009 5078056012 pE E E PE h0 * h0 * E @ E h0 * h0 * 1 q + E @ E h0 * h0 * 1 q + E @ E h0 * h0 * 1 q + @ E 7@ 20 M* E @ E 7@ p E E E P E h 0 * h 0 * E @ E h0 * h 0 * 1 q + E @ E h0 * h 0 * 1 q + E @ E h0 * h 0 * 1 q + E @ E h0 * h 0 * 1 q + E @ E h0
Shanghai Jiao Tong University - ME - ME461
F0802009 u 7 (u C 0 ( 2 7p3 : 2 C * ; 2 2 2 7p 3 ; ? 2F 7 p 3 ; &lt; 7 2 ; 2 LV ; F 3F @ pI *5078056012 . + p 7 + @ @ D D * 9 F * 9 F * * * F D 2 D @ ` 7p3 D F * i v &gt; * &gt; * ? ? ? * 0 ? 0 ? 0 ? F * 0 0 ? ? @7 D + u + * 7 (u @7 . + F * F + v * @ F F F *
Shanghai Jiao Tong University - ME - ME461
XF0802009 x * 5078056012 H * h * 5 D c + / V D @ D p D D P D 8 g , 8 g , 1 H c + p D D D 1 H c + p D D D ( 1 H c + p D D D xU * D @ D 8 g , * 8 g , * 1 D c + @ @ @ D 1Hc+p D p D D
Shanghai Jiao Tong University - ME - ME461
* 7 7 @ p + % E g k * @ p + u E g k E g k @ 7 @ p + % E g k @ M E g k @ p + u E g k @ p + E g k @ p + E g k 7 E g k @ @ p + E g k @ p + ? E g k g k p + E h @ p + E g k O x E g i* ` @ p + % E g k @ p + L E g k @ p + t E g kI BT * I BT E g i * I BT 100 j
Shanghai Jiao Tong University - ME - ME461
U*7.5 .E I 0 7 E 7 X 8 * A S S @ o@ k * @ E @ E @ E @ E @ E 22 j R + @E S S 32 1 S S S S S + + p + p + p + p p E E E E E p E + + p p E E + p p E E E @ + @ @ E 7 U * R L7 p E S. @o@2010 2 3 2 20 n @ E E @m R7 W6 S7.5 @o@ @o@ 0 @o@ @o@ X 8 * @o@ @o@ @
Shanghai Jiao Tong University - ME - ME461
xxx xx xx x 1 1 2 3 4 5 6 7 8 9 10 6 5 9 7 3 2 7 3 950780560120 g [ )1 E5 6 8 6 5 7 1 5 7 3 6 8 6 1 2 8 8 5 3 7 7 3 1 9 8 2 7 5 9 410 x x 22 2 Bektas (2006) ) x2 5 6 2 6 8 2 6 4 4 3 8 6 5 7 2 4 7 3 9 4 9 2 4 3 8 4 7 2 9W ) OPL 8 1 9 6 1 3 3 5 6 3
Shanghai Jiao Tong University - ME - ME461
LOGOO 42 25078056012 5078056007 5078053012 5078052031 5078053028 www.1ppt.com@ * t0H H H H 8 $ * * * * * *h S h S h S h S F* * * *c c c cwww.1ppt.com * F1.2. 2.* 2 8 2 *F3. 3.Fwww.1ppt.com08 * F 13786 2 4140 2 Mwww.1ppt.comw
Shanghai Jiao Tong University - ME - ME461
*5F* F* 9 9 9 : 9 9 9 9 @ F* 9 9 : 9 9 9 9 9 W* 9 9 9 9 9 : 9 9 9 9 9 9 9 : 9 9 9 9 9 F * * * * * * * * * @ ; E * * * * * * * * 9 E * * * * * * * * * * * * * * * * * * * F * 6 1948 o W &gt; * p;5078056012 F0802009 5* E &gt; * 9E p; E 9E 9E `9 9E v* v* v* v*
Shanghai Jiao Tong University - ME - ME461
L/O/G/OOVERVIEWCONTENTSThe problem of the food chosenThis presentation majors in the problem of choosing suitable diet and sports programs in order to reduce the maximum calories within the limited time!The Problem of the Sports chosenLOGOFood chos
Shanghai Jiao Tong University - ME - ME461
Dieting Plan: Objective: to minimize the amount of fat taken in. Constraints: 1 .He or she must choose at least one and only one kind of food from each category, Staple food, Meet and Fruits &amp; Vegetables. 2. The amount of protein taken in should more than
Shanghai Jiao Tong University - ME - ME461
per 100 g Staple Food Name Rice Mantou Bread Noodle PorridgeTotal Energy KCal Protein g Fat g 116 2.6 0.3 221 7 1 312 8 5 284 8 1 46 1 0.3Meet Pork Beef Chicken Fish143 106 181 11020.3 20.2 16 176 2.3 13 5Fruits&amp;Vegatables Apple Watermelon Tomato Mu
Shanghai Jiao Tong University - ME - ME461
0-10 6 15 8 6 13 10 11 6 920 0 0 0 0 0 0 0 0Y0 20 30 20 20 35 -100 45 20 1 2 3 4 5 6 7 890 0
Shanghai Jiao Tong University - ME - ME461
WEIGHT LOSING PLANL/O/G/OWEIGHT LOSING PLANHow to lose weight?The problem of the food selectionThis presentation majors in the problem of choosing suitable diet and sports programs in order to reduce the maximum calories within the limited time!The
Shanghai Jiao Tong University - ME - ME461
W *HpRE RE RE H @ RE @ RE SWOT * RE W W RE*F0802009 5078056012 FPRE W* W* * X W* 5 3 3 W* W* pE* 2 pE* 2 *ISWOT WStrengthsH * 1 ) S @ @ H ) H* @ @ @ R E 3 H * ( 7 H* @ pRE @ RE @RE K RE ` p RE Q RE H* p RE RE ` H* H* H* RE pRE pRE pRE RE R E RE