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math102_hw03

Course: MATH 102, Spring 2011
School: UCSD
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UCSD - MATH - 102
UCSD - MATH - 102
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UCSD - MATH - 102
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UCSD - MATH - 102
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UCSD - MATH - 102
\ ! t c 4+h02 ' r \r,lmtccfw_&quot;0fcf |\avY\I,u t \$ 8;MT) d[-('hc L cfw_ \ r l z' E ) *'l'\u Lef rr)= = cfw_ 1,;]) i :li:)-lVt un f u\.e-\) =rq\ r ' t l o= ) ) l; )l iz &quot; .' =t(li:\ &gt;t i:i:J)d,L l ;)* , ,'.,i,j:) \ ',?,7!:, A 1 1 = ' / t t lt , | T
UCSD - MATH - 102
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UCSD - MATH - 102
* #ffi \,eJr!\4#fS \$nrrncwork l DbAnvltt nZlru1ffi4* f n Ft x , r y i * l + 4 cfw_ c o - - 5 x s l t 1 t + k y t*t ffi: cfw_ X,-,g il -# e t r#r y* * K * 4 i d '&amp;'K*'l#ffib*unLf*&quot;Ft-Ae d-xffi,4exI E4 t t u ,o )ffi=tv-bxcostf + l ?YL/'
UCSD - MATH - 102
Math 102 - Homework 4 (selected problems)David Lipshutz Problem 1. (Strang, 3.2: #14) What matrix P projects every point in R3 onto the line on intersection of the planes x + y + t = 0 and x t = 0? Proof. The line of intersection must satisfy, t = x and
UCSD - MATH - 102
Math 102 - Homework 5 (selected problems)David Lipshutz Problem 1. (Strang, 4.2: #2) If a 3 by 3 matrix has det A = 1, nd det( 1 A), det(A), det(A2 ), and det(A1 ). 2 Proof. 1 1 1 1 det( A) = det( I ) det(A) = ( )3 (1) = 2 2 2 8 det(A) = det(I ) det(A) =
UCSD - MATH - 102
Math 102 - Homework 6 (selected problems)David Lipshutz Problem 1. (Strang, 4.4: #14) Use Cramers Rule to solve for y . ax + by = 1 cx + dy = 0 ax + by + cz = 1 (b) dx + ey + f z = 0 gx + hy + iz = 0(a)Proof. (a) A= a c b d y= (b) a g b e h c 1 a 1 0 0
UCSD - MATH - 102
Math 102 - Homework 7 (selected problems)David Lipshutz Problem 1. (Strang, 5.2: #4) If a 3 by 3 upper triangular matrix has diagonal entries 1, 2, 7, how do you know it can be diagonalized? What is ? Proof. Its eigenvalues must be 1, 2 and 7 since A I w
UCSD - MATH - 102
Math 102 - Homework 8 (selected problems)David Lipshutz Problem 1. (Strang, 5.5: #14) In the list below, which classes of 01 0 0 A= 0 0 10 matrices contain A and which contain B ? 1111 00 1 0 and B = 1 1 1 1 1 1 1 1 1 4 0 1 00 1111Orthogonal, invertible
UCSD - MATH - 102
Math 102 - Homework 9/10 (selected problems)David Lipshutz Problem 1. (Strang, 6.2: #2) Decide for or against the positive deniteness of 2 1 1 2 1 1 1 , B = 1 A= 2 1 2 1 1 1 2 1 101 0 12252 2 21 , C = 1 2 2 1 = 2 1 0 2 5Proof. Since A is singu
UCSD - ECE - 108
ECE 108 Final ExamFriday, June 13 Spring 2008 You are reminded that academic dishonesty will NOT be tolerated. You have 3 hours to complete the exam. You may refer to 1 sheet of your own hand-written notes but no other reference material. You may also us
UCSD - ECE - 108
ESENER ECE108HW SET 2SPRING 2010Problem 1. An NMOS NOR gate with resistive load uses MOSFETs each with a threshold voltage =0.8 . =5 . a) With only one input high 1=5 , it is desired to obtain an output voltage =0.4 at a current flow from the power sup
UCSD - ECE - 108
DR=VOH/VOL
UCSD - ECE - 108
STUDENT NAME _ STUDENT ID _ ECE108 FINAL Spring 2001 Questions 1-8 are 1 points each. Question 9 is 2 points Please answer in the spaces belowESENER1. Describe why the drain current of a MOSFET saturates with increasing drain voltageWhen the drain volt
UCSD - ECE - 108
ECE 108- Problem set 5.EsenerShort channel CMOS circuit problemsProblem1: In this problem you are asked to estimate the characteristics of a CMOS digital integrated circuit containing 500 million transistors using a present day technology. For simplici
UCSD - ECE - 108
ECE108HW6 on interconnectsEsenerProblem 1: An Aluminum wire on silicon has the following parameters r=0.075ohms/um and c=110aF/um. Given that the propagation delay of an RC limited line is 0.38RC calculate the propagation delay for a 10cm line Solution
UCSD - ECE - 108
A design problemc) How big is the PLA character generator if the unit cell is 11x15um2Solution000 001 010 011 100 101 110 111x xyyzzabcdfgeC)
UCSD - ECE - 108
ECE108 Additional Problems for Finals 2003 Dynamic Circuit Design In a DRAM circuit the leakage current per storage cell is measured to be 1nA. Assuming that the storage cell capacitance Cs = 10fF, that the voltage across the storage capacitor is allowed
UCSD - ECE - 65
UCSD - ECE - 65
UCSD - ECE - 65
Solution of ECE65 Final (Fall 2009)Notes: 1. For each problem, 20% of points is for the correct nal answer. 2. Messy, incoherent papers lose point! Explain what you are doing! 3. Use the following information only in designing circuits: NPN Si transistor
UCSD - ECE - 65
ECE65 (Fall 2009), Quiz 2 Name:Notes: 1. Write your answers on these three sheets. 2. For each problem, 20% of points are alloacted for the correct nal answer.Problem 1. Consider NMOS circuit below with k (W/L) = 0.8 mA/V2 , Vt = 2 V, RD = 1 K and VDD =
UCSD - ECE - 65
ECE65 (Fall 2009), Quiz 2Notes: 1. Write your answers on these three sheets. 2. For each problem, 20% of points are alloacted for the correct nal answer.Problem 1. Consider NMOS circuit below with k (W/L) = 0.8 mA/V2 , Vt = 2 V, RD = 1 K and VDD = 12 V.
CSU Long Beach - IS - 300
CHAPTER5 5.1NetworkApplications Discoveryviatheinternetpermitsyoutoaccessinformationlocatedindatabasesall overtheworldbutyouneedtorealizethatthereisnoqualityassuranceoninformation ontheWeb.(userbeware) Searchenginesacomputerprogramthatsearchersforspecific
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Antigone Essay Holt Norman Monday, December 6, 2010 In the United States, the issue of religion, and its role in government has long been a cause of conflict and disparate opinions. Although this country was founded by people of fervent religious beliefs,
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J. M. Mendel Spring 2010EE 364 Midterm # 2Closed Book Two 81/2X11 sheet of notes (both sides) permitted Calculator required Tables A.1, A.2 and A.3 required To receive full credit you must carry out all of the numericsx1. (20 points) For parts a and b
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USC - EE - 364
USC - EE - 364
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Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science 6.002 Electronic Circuits Fall 2000 Final Exam Please write your name in the space provided below, and circle the name of your recitation instructor and the t
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Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science 6.002 Circuits &amp; Electronics Spring 2007 Final Exam 21 May 2007Name: There are 31 pages in this nal, including this cover page. Please check that you have
USC - EE - 357
EE 357 Homework 5Name: _Solutions_ Due: Note: Attach all work to receive full credit Performance 1) Exercise 1.3 (1.3.1-1.3.6) in CO&amp;D, 4th Ed. page 59. a) 1.3.1: Exec. Tim = IC * CPI * Clock Period = IC * CPI * 1/ClockFreq. Perf. = 1 / Exec. Time. EXECU
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EE 357 Homework 6Solutions Name: _Solutions_ Due: Note: Attach all work to receive full credit Score: _1.) A certain memory controller connects a processor with a 32-bit address bus (A31-A0) and 64-bit data bus to a memory system consisting of 2 SIMMs (
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EE 357 MidtermFall 10 Annavaram Name: _ Lecture:11.00-12.20 Closed Book / 90 minutes Perfect Score: 100 / 100 Score: _ 1. Short Answer (12 pts.) a. Briefly explain the advantage of using ADDQ.L #1,D0 rather than ADDI.L #1,D0? ADDQ.L doesnt use extensions
USC - EE - 357
Problem 7 Cache mapping schemes (BONUS POINTS) A byte addressable computer has 20-bit memory address space (i.e. 20-bit addresses). The processor has a cache capable of storing 512 words with a block size of 32 words. (Assume word is 2 bytes long as in 68
USC - EE - 357
EE 357 PracticePerformance and Cache Name: _Solutions_ Score: _ 1. Performance Consider a processor P1 running @ 2 GHz and its corresponding compiler C1 along with another processor P2 running @ 4 GHz and its compiler C2. There are 4 types of instruction
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USC - EE - 357
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USC - EE - 357
Components of an ISA1. Data and Address Size 8-, 16-, 32-, 64-bitEE 357 Unit 11MIPS ISA2. Which instructions does the processor support SUBtract instruc. vs. NEGate + ADD instrucs.3. Registers accessible to the instructions Faster than accessing d
USC - EE - 357
Performance AnalysisWhich of the following airplanes has the best performance?Passengers 101 470 132 146 Range (mi) 630 4150 4000 8720 Speed (mph) 598 610 1350 544EE 357 Unit 12Performance ModelingAirplane Boeing 737-100 Boeing 747 Concorde Douglas D
USC - EE - 357
10/12/10The Memory Wall Problem: The Memory WallEE 357 Unit 13Memory System Overview SRAM vs. DRAM DMA &amp; Endian-ness Processor speeds have been increasing much faster than memory access speeds (Memory technology targets density rather than speed) Lar
USC - EE - 357
USC - EE - 357
11/11/10CPU Organization Scope We will build a CPU to implement our subset of the MIPS ISAEE 357 Unit 15Single-Cycle CPU Datapath and Control Memory Reference Instructions: Load Word (LW) Store Word (SW) Arithmetic and Logic Instructions: ADD, SUB
USC - EE - 357
11/12/10Single-Cycle CPU Datapath Multi-Cycle CPU OrganizationDatapath and ControlAddr.+4AB[31:26]ControlMemRead &amp; MemWrite ALUOp[1:0] MemtoReg RegDst ALUSrcSh. Left 2 Branch+[25:21]PCSrcRegWrite Read Reg. 1 # Read Reg. 2 # Write Reg. # Wri
USC - EE - 357
11/22/10Single &amp; Multi-Cycle PerformanceSingle-Cycle CPU Multi-Cycle CPU CPI = n, Short clock cycle Sharing resources allows for compact logic design but in modern design we can afford replicated structures if needed Each instruction still requires sev
USC - EE - 357
ColdFire Family Programmers Reference ManualDocument Number: CFPRM Rev. 3 03/2005How to Reach Us:Home Page: www.freescale.com E-mail: support@freescale.com USA/Europe or Locations Not Listed: Freescale Semiconductor Technical Information Center, CH370
USC - EE - 357
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USC - EE - 357
Learning Objectives EE 357 Unit 2aMultiplication Techniques Perform by hand the different methods for unsigned and signed multiplication Understand the various digital implementations of a multiplier along with their tradeoffs Sequential add and shift m
USC - EE - 357
USC - EE - 357
Floating Point Used to represent very small numbers (fractions) and very large numbersEE 357 Unit 3IEEE 754 Floating Point Representation Floating Point Arithmetic Avogadros Number: +6.0247 * 1023 Plancks Constant: +6.6254 * 10-27 Note: 32 or 64-bit i
USC - EE - 357
9/28/10Instruction Set Architecture (ISA) Defines the software interface of the computer system Instruction set is the vocabulary that the HW can understand and that SW is composed with 2 approaches CISC = Complex instruction set computer (Coldfire/M68
USC - EE - 357