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P2829key(2)

Course: ENGR 111, Fall 2009
School: Texas A&M
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Word Count: 225

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28 FBD: P 2 pts 8 ft = 2.438 m Ma = 0 14kN 2.438m + 36kN 2.438m Cy 3 2.438m = 0 Cy = 14kN 2.438m + 36kN 2.438m 3 2.438m Cy = 16.67 kN 3 pts Fy = 0 Cy 14kN + A sin( 135deg) = 0 16.67kN 14kN + A sin( 135deg) = 0 A= 2.67 kN sin( 135.0 deg) A = 3.78 kN 3 pts Fx = 0 Cx 36 kN + A cos( 135deg) = 0 Cx 36 kN + ( 3.78 kN) cos( 135deg) = 0 Cx = 36.0 kN + 3.78 kN cos( 135 deg) Cx = 33.33 kN 3 pts Alternate...

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28 FBD: P 2 pts 8 ft = 2.438 m Ma = 0 14kN 2.438m + 36kN 2.438m Cy 3 2.438m = 0 Cy = 14kN 2.438m + 36kN 2.438m 3 2.438m Cy = 16.67 kN 3 pts Fy = 0 Cy 14kN + A sin( 135deg) = 0 16.67kN 14kN + A sin( 135deg) = 0 A= 2.67 kN sin( 135.0 deg) A = 3.78 kN 3 pts Fx = 0 Cx 36 kN + A cos( 135deg) = 0 Cx 36 kN + ( 3.78 kN) cos( 135deg) = 0 Cx = 36.0 kN + 3.78 kN cos( 135 deg) Cx = 33.33 kN 3 pts Alternate version: FBD 2 pts Fx = 0 Ma = 0 Cx 36 kN = 0 14kN 2.438m + 36kN 2.438m Cy 3 2.438m = 0 Cy = 14kN 2.438m + 36kN 2.438m 3 2.438m Cx = 36kN 3 pts Cy = 16.67 kN 3 pts Fy = 0 Cy 14kN + Ay = 0 16.67kN 14kN + Ay = 0 Ay = 14kN 16.67kN Ay = 2.67 kN 3 pts P 29 Assume that the unknowns are in tension! cos( 22deg) = 0.927 cos( 35deg) = 0.819 sin( 35deg) = 0.574 sin( 22deg) = 0.375 FBD: 2 pts Fx = 0 Fab 35deg) cos( Fbc cos( 22deg) = 0 Fab 0.819 Fbc 0.927 = 0 Fab = 1.132 Fbc Fy = 0 500 lbf Fab sin( 35deg) Fbc sin( 22deg) = 0 500 lbf ( 1.132 Fbc ) 0.574 Fbc 0.375 = 0 500 lbf + 0.650 Fbc 0.375 Fbc = 0 500 lbf + ( 0.650 0.375) Fbc = 0 0.275 Fbc = 500lbf Fbc = 1818 lbf Fab = 1.132 Fbc Fab = 2058 lbf Fab = 2058 lbf (C) 3 pts Fbc = 1818 lbf (T) 3 pts 1lbf = 4.448 N 500lbf = 2224 N Metric: Fbc = 8.087 kN Fab = 9.154 kN P 29 Typical error (500 lb * 9.8 m/s = 4900 lbf) FBD 2 pts Should be: 500 lbm * g = 500 lbf (-1/2 point) Fx = 0 Fab cos( 35deg) Fbc cos( 22deg) = 0 Fab = Fbc cos( 22 deg) cos( 35 deg) Fy = 0 500 lbf sin( 22 deg) Fbc = 1821 lbf Fab = Fbc cos( 22 deg) cos( 35 deg) Fab = 20196 lbf (C) 3 pts cos( 22 deg) sin( 35 deg) cos( 35 deg) Fbc = 1821 lbf (T) 3 pts Fbc = Fab = 2061 lbf
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