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Course: FIN 101, Spring 2011
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of Foundations Financial Management Midterm Examination, SIFT Fall 2003 Chinese name ___________ Register number _______________ Marks ___________ Attention: Exam time: 120 minutes. Show all your work, all the formulas. Marks will only be assigned for problems for which complete methodology, formulas, and the process is shown. Peeking, copying or duplicating others' work will be considered as...

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of Foundations Financial Management Midterm Examination, SIFT Fall 2003 Chinese name ___________ Register number _______________ Marks ___________ Attention: Exam time: 120 minutes. Show all your work, all the formulas. Marks will only be assigned for problems for which complete methodology, formulas, and the process is shown. Peeking, copying or duplicating others' work will be considered as "cheating" And such students will be asked to leave the examination room immediately. 1.Match the following: (12 marks) a. balance sheet i. marginal corporate tax rate b. current cost accounting j. net worth or book value c. earnings per share k. P/E ratio d. historical cost accounting l. shareholders' equity e. income statement m statement of changes in financial position f. liquidity n. cash flows from operation . g. cash flow from financing o. cash flows from investing h. amortization p. free cash flow ____ 1) All the assets of the firm minus the liabilities and preferred stock ____ 2) A financial statement that indicates what the firms owns, and how these assets are financed in the form of liabilities or ownership interest. ____ 3) Changes accrual-based information from income statement and balance sheet to cash based information ____ 4) The relative convertibility of short-term assets into cash. ____ 5) The tax expressed as a percentage that applies to each new dollar of taxable income ____ 6 ) The multiplier applied to income per share to determine current value. ____ 7) The income available to common shareholders divided by the number of common shares outstanding. ____ 8) A financial statement that measures the profitability of the firm over a period of time. ____ 9) Represents the net cash flow that results from changes in the amount of a firm's long-term assets. ____ 10) The total ownership position of preferred and common shareholders. ____ 11) Traditional method of accounting using original costs minus amortization. ____ 12) Represents the net cash flow that results from a firm's production and sales activities. ____ 13) One method of inflation-adjusted accounting where statements are adjusted to the present using current cost date. ____ 14) Cash flow that is generated ( or reduced ) from the sale or repurchase of securities or the payment of dividends. ____ 15) The allocation of the initial cost of an asset over its useful life. ____ 16) Cash flows from operations minus working capital minus dividends payments 1 2.Identify each of the following as increasing ( + ) or decreasing ( -- ) cash flows from operating activities ( O ), investing activities ( I ), or financing activities ( F ). (EXAMPLE: the sale of plant and equipment would increase cash flows from investing activities, and the correct answer would be ( +I ). (12 marks ) ___ 1) Decrease in accounts receivable ___ 2) Decrease in inventory ___ 3) Net income from operations ___ 4) Payment of dividends ___ 5) Sale of preferred stock ___ 6) Increase in accrued expenses ___ 7) Purchase of new equipment ___ 8) Increase in accounts receivable ___ 9) Decrease in notes payable ___ 10) Increase in long-term liabilities ___ 11) Increase in investments ___ 12) Decrease in marketable securities ___ 13) Repurchase of common share outstanding ___ 14) Increase in prepaid expense ___ 15) Decrease in income tax payable ___ 16) Retirement of long-term bonds payable 3.The following is the December 31,1998 balance sheet for the Epic corporation. Assets Liabilities 100,000 120,000 300,000 520,000 Cash 70,000 Accounts payable Accounts receivable 150,000 Notes payable Inventory 280,000 Bonds payable Total current assets 500,000 Total liabilities Plant and equipment Less: Accum. Amort. Net plant and equipment 1,250,000 Equity 250,000 Common stock 1,000,000 Retained earnings Total equity 980,000 Total Liab. & Equity 500,000 480,000 Total assets 1,500,000 1,500,000 Sales for 1999 were $2,000,000, with the cost of goods sold being 55% of sales. Amortization Expense was 10% of the gross plant and equipment at the beginning the year. Interest expense was 9% on the notes and payable 11% on the bonds payable. Selling, general and administrative expenses were $200,000 and the firm's tax rate is 40%. a) Prepare an income statement. ( 7 marks ) b) If the dividend payout ratio for Epics is 35%, what is the value of the retained earnings Account on December 31, 1999 ( 3 marks ) 2 4.The following is the balance sheet for 1999 for Marbell Inc. Assets Liabilities & Shareholder's Equity 90,000 30,000 7,500 127,500 75,000 22,500 Cash 15,000 Accounts payable Accounts receivable 90,000 Notes payable Inventory 60,000 Accrued expenses Current assets 165,000 Current liabilities Capital assets 60,000 Common stock Retained earnings Total assets 225,000 Total Liab. & Equity 225,000 Sales for 1999 were $300,000. Sales for 2000 have been projected to increase by 20%. Assuming That Marbell Inc. is operating below capacity ,calculate the amount of new funds required to finance this growth. Marbell has an 8% return on sales and 70% is paid out as dividends.(8 marks) 5.Complete the following balance sheet for the Range Company using the following information: Sales = 1,625,000 Debt to Assets = 60 percent Quick Ratio = 1.1 Assets Turnover = 5 x Capital Assets Turnover = 12 .037 x 3 Current Ratio = 2 Average Collection Period = 17.0708 days Cash Receivables Inventory Total current assets Plant and equipment Total assets Current liabilities Bonds payable Total liabilities Net worth (11 marks ) Total liabilities & net worth 6. Heister Corporation produces class rings to sell to college and high school students. These Rings sell for $75 each, and cost $35 each to produce. Heister has fixed costs of $50,000. a) Calculate Heister's break-even point. (4 marks ) b) How much profit ( loss ) will Heister have if it sells 1,000 rings? 8,000 rings ?(4marks) c) Heister's president, J.R. D'Angelo, expects an annual profit of $100,000. How many Rings must be sold to attain this profit? ( 4marks ) 7. Christensen & Assoc. Is developing an asset financing plan. Christensen has $500,000 In current assets, of which 15% are permanent, and $700,000 in fixed assets. The current long-term rate is 11%, and the current short-term rate is 8.5%. Christensen 's tax rate is 40%. (16 marks ) a) construct two financing plans----one conservative, with 80 of assets financed by long-term sources, and the other aggressive, with only 60% of asstes financed by long-term sources. b) If Christensen 's earnings before interest and taxes are $235,000, calculate net income Under each alternative. c) what are some of the risks associated with each plan ? d) Which plan would you recommend to Christensen ? Why ? 4 8. The Milling Corp. has developed a new type of widget. The local distributor expects to Increase his sales by 20% over the past year due to this new development. Last year's sales Were $50,000 at a selling price of $100 per unit. The manager would like to cut costs as Much as possible and comes to you for advice. (12 marks ) Relevant cost information includes: Warehouse space $2.50 / unit Material handling expense $1.50 / unit Insurance premium $1.00 / unit Total ordering cost $100.00 / per order a) What is the economic order quantity ? b) What is the amount of average inventory ? c) How many orders will be made per year ? d) What is the total cost of this inventory decision? 9. Mountain Home Systems Inc. is a well-known and reputable supplier of integrated circuits to manufacturers of telecommunications devices. The firm is currently debating whether to expand its sales to car-telephone manufacturers. While the firm expects an extra $2 million in sales if it enters this market, it also knows that 15% of its sales will ultimately be uncollectible. In addition, collection costs will be 2% on all new sales and the firm's production costs are 72% of sales. Selling expenses are 8% of sales and Mountain Home has an opportunity cost of funds ( before tax ) of 20%. Mountain Home can turn is receivables 4 5 times per year. Should Mountain Home Systems Co. Enter the car-telephone manufacturer market ? ( 7 marks ) 6
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Amherst - ACCOUNTING - 101
9-4. TRANS. FUND NO. OR ACTIVITY 1. GFCITY OF LYNNWOOD ACCOUNT TITLE ESTIMATED REVENUES APPROPRIATIONS BUDGETARY FUND BALANCE AMOUNTS Debits Credits 2,000,000 1,990,000 10,000 1,940,000 9,000 1,931,000 1,940,000 9,000 1,931,000 25,000 25,000 25,000 300,0
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13.54AnswerDetails=Fy=Solve for N.Cancel m. associate the terms.Solve for v.Now. this is v MAXIMUM. I know, I know, I should learn to read theproblem. But this is an easy fix. Switch the signs in the numerator anddenominator to get vminimum: =So d
Passaic County Community College - CHEM - 112
CH 111 - General Chemistry I Exam Answers Version 01B 08a 1. E, B, G, D, F or C, A 2. [(22 x 1)/342.30] x 100 = 6.43 % 3. 3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O 4. Symbol Protons neutrons electrons charge I 8 10 10 74 54 +2 Nb Ca 205. (3 x 137.327) + (2 x
Passaic County Community College - CHEM - 112
PassaicCountyCommunityCollege CH112GeneralChemistryIIHomeworkAnswersChapterThirteen13.14 (a) Forthesamesolute,NaCl,indifferentsolvents,solutesoluteinteractions( H 1 )arethesame. Becausewaterexperienceshydrogenbondingwhilebenzenehasonlydispersionforces,s
Passaic County Community College - CHEM - 112
CH 111 - General Chemistry IExam Answers Version 01B 08a1. E, B, G, D, F or C, A2. [(22 x 1)/342.30] x 100 = 6.43 %3. 3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O4. Symbol I Nb Ca Protons 8 20 neutrons 10 74 electrons 10 54 charge +2 5. (3 x 137.327)
Passaic County Community College - CHEM - 111
CH 111 - General Chemistry 1 Exam 2 Version A Brown 08 Answers 1. a). redox b). acid-base c). precipitation2. Reversing the second reaction and adding the enthalpies gives 110.5 kJ. 3. The equation is products minus reactants. The answer is 167.7 kJ/mol.
Passaic County Community College - CHEM - 111
CH 111 - General Chemistry 1 Exam 2 Version B Brown 08 Answers 1. There are too many answers for this to type them all. 2. 1 atm, 198 K 3. a). Complete Molecular: Mg(NO3)2 + K2SO4 -> MgSO4 (s) + 2KNO3 There is no net ionic. Both products are soluble. b).
Passaic County Community College - CHEM - 111
CH 111 - General Chemistry I Exam 3 Brown 08 Version A Answers 1. a). 6.626 x 10-26 2. p and d 3. B-F 4. This one was on the board. 5. N=3, l=2, ml = -2,-1,0,1,2 6. a). [Ar] 4s13d5 b). [Ar] b). 390 m7. N>Co>Sc>Be>Na 8. a). -5.52 x 10-35 9. Ba>Ca>Na 10. N
Passaic County Community College - CHEM - 111
C H 111 - General Chemistry I Exam 3 Brown 08 Version B Answers 1. a). 5.10 x 10-28 b). 390 m 2. d and p 3. O-Cl 4. This one was on the board. 5. N=4, l=2, ml = -2,-1,0,1,2 6. a). [Ar] 4s13d10 b). [Ar] 7. N>Co>Sc>Be>Na 8. a). 1.39 x 10-34 b). absorbed 9.
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Ten10.16 Using the relationship derived in Solution 10.15 for two liquids under the influence of gravity, (d h) 1 id = (d h) H g. At 752 torr, the height of an Hg barome
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter One1.12 (a) (b) (c) (d) 1.14 (a) (g) 1.18 homogeneous mixture heterogeneous mixture (particles in liquid) pure substance heterogeneous mixture C calcium (b) N (h) helium
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Two2.7 See Figure 2.22. yellow box: 1+ (group 1A); blue box: 2+ (group 2A) black box: 3+ (a metal in Group 3A); orange box: 2 (a nonmetal in group 6A); green box: 1 (a n
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Three3.12 (a) (b) (c) (d) (e) (f) (g) 3.14 (a) (b) (c) (d) 3.20 (a) (b) (c) (d) (e) 3.24 (a) 6Li(s) + N 2 (g) 2Li 3 N(s) La 2 O 3 (s) + 3H 2 O(l) 2La(OH) 3 (aq) 2NH 4 NO
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Four4.16 (a) (b) (c) (d) 4.22 MgI 2 (aq) Mg 2 +(aq) + 2I (aq) Al(NO 3 ) 3 (aq) Al 3 +(aq) + 3NO 3 (aq) HClO 4 (aq) H + (aq) + ClO 4 (aq) NaCH 3 CO O(aq) N a + (aq) + CH
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Five5.7 Cooling 1 kg H2O releases more heat than cooling 1 kg Al . Equal masses of H2O and Al are cooled by the same number of C. Under these circumstances, the amount o
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Six6.24 E = hAM : 6.62610 34 J sFM : 6.62610 34 J s101010 3 = 6.6910 28 J 1s98.310 6 = 6.5110 26 J 1sThe FM photon has about 100 times more energy than the AM photo
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Seven7.16 Mg < P < K < Ti < Rh. The shielding of electrons in the n = 3 shell by 1s, 2s and 2p core electrons in these elements is approximately equal, so the effective
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Eight8.18 (a) (b) (c) (d) (e) (f) 8.22 (a) Zn 2 +: [Ar]3d 1 0 Te 2 : [Kr]5s 2 4d 1 05p 6 = [Xe], noble-gas configuration Sc 3 +: [Ar], noble-gas configuration Rh 3 +: [K
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Nine9.16 Analyze/Plan. See Table 9.1. Solve. (a) (c) 9.20 trigonal planar trigonal bipyramidal (b) (d) tetrahedral octahedral(c)XXXtetrahedralbent9.22bent (b), l
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 General Chemistry IHomework Answers Chapter Eleven11.16 (a) (b) CH 3 OH experiences hydrogen bonding, but CH 3 SH does not. Both gases are influenced by London dispersion forces. The heavier the gas particles, the
Passaic County Community College - CHEM - 111
The Study of ChemistryAtomic and Molecular PerspectiveMatterChapter OneMatter and MeasurementP Solid P Liquid P Gas P Plasma P Condensed Einstonian Gas Elements Atoms MoleculesChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Pas
Passaic County Community College - CHEM - 111
The Atomic Theory of MatterAtom: indivisible Daltons Atomic TheoryChapter TwoAtoms, Molecules and IonsChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Community College Dr. Fred SafarowicP Each element is made of a
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Chemical Equations2 H2 + O2 2 H2OChapter ThreeStoichiometryReactantsProductsChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Community College Dr. Fred SafarowicCoefficients vs subscriptsBalancing EquationsCH4
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Electrolyte PropertiesElectrolyte: dissociates into ions in water and can carry an electric charge. Most ionic compounds.Chapter FourAqueous Reactions and SolutionsChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Co
Passaic County Community College - CHEM - 111
EnergyEnergy: ability to do workChapter FiveThermochemistryWork Potential EnergyHeatKinetic EnergyChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Community College Dr. Fred SafarowicE=12 mv 2What do we study?
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Electromagnetic Spectrum Chapter SixElectronic Structure of AtomsChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Community College Dr. Fred SafarowicWavesQuantized EnergyHow are temp and color related? QuantumE =
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Chapter SevenPeriodic PropertiesDevelopment of PTArranged in columns of similar valenceMendelevMeyerChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Community College Dr. Fred SafarowicMoseley: atomic numberEffe
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Gas Characteristics Chapter TenGasesChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Community College Dr. Fred SafarowicPressure!Pressure UnitsPascals ! 1 Pa = 1 N/m2 Bar ! 1 bar = 105 Pa = 100 kPaP = F/A!Stan
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Matter Composition Chapter ElevenIntermolecular Forces Liquids and SolidsChemistry: The Central Science, 11th ed. CH 111 - General Chemistry I Passaic County Community College Dr. Fred SafarowicIntermolecular ForcesIon-Dipole ForcesBoiling PointMelt
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Passaic County Community College CH 103 - Introduction to Inorganic and Organic Chemistry Canceling Units - Dimensional Analysis Every unit is a combination of two parts, the number itself and a unit. The unit tells you what you actually have. For example
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Passaic County Community College CH 103 - Introduction to Inorganic and Organic Chemistry Entering an Exponent into Your Calculator There are a number of different ways to enter exponents into your calculator. This is the most common. Positive Exponent: E
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Passaic County Community College CH 103 - Introduction to Inorganic and Organic Chemistry Chemical Calculations This page has been created to help you with a summary of the types of calculations you will be expected to perform on exam #2. If I catch you w
Passaic County Community College - CHEM - 111
Passaic County Community College CH 103 - Introduction to Inorganic and Organic Chemistry Calculations Using Percentages I. To calculate the percentage of any item, the general formula is:Problem: Calculate what percent of a dollar is 33 pennies. (A doll
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Passaic County Community College CH 103 - Introduction to Inorganic and Organic Chemistry Atoms, Protons, Neutrons, Electrons and Other Stuff From Chapter 2I. The Periodic Table A typical entry in the Periodic Table is below:You must know what these num
Passaic County Community College - CHEM - 111
Passaic County Community College CH 111 - General Chemistry IName_ Sec: 01 02 Exam 4 - Version A Brown 2009 Answers1.(10 points) What are the shapes (planar etc) of the following molecular geometries: a). AB3E Trigonal Pyramid b). AB4 Tetrahedral c). A
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Intermolecular ForcesHydrationChapter ThirteenProperties of SolutionsSolvationChemistry: The Central Science, 11th ed. CH 112 - General Chemistry II Passaic County Community College Dr. Fred SafarowicSolution EnthaplyEnthalpy Change H so ln = H1 +
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Chemical Kinetics Chapter FourteenChemical KineticsStudy of the speed of a reaction P Physical state of Reactants P Concentration of Reactants P Temperature P Any catalystChemistry: The Central Science, 11th ed. CH 112 - General Chemistry II Passaic Co
Passaic County Community College - CHEM - 112
Chapter 15Chemical EquilibriumEventually, a reaction stops. But all the reactants are not necessarily converted to 100% products.Chemical EquilibiumWhen the rate of the reaction in one direction is the same as the rate if you reverse the reaction, the
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Acids/BasesChapter 16Acid-Base EquilibriaAcids: Produce H+ when put in water Bases: Produce OH- when put in waterChemistry: The Central Science, 11th ed. CH 112 - General Chemistry II Passaic County Community College Dr. Fred SafarowicH3O+ and H+ are
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Common-Ion Effect Chapter 17Additional Aspects of Aqueous EquilibriaThe dissociation of a weak electrolyte is decreased by adding to the solution a strong electrolyte that has an ion in common with the weak electrolyte.Exercise 17.1Chemistry:TheCentra
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Spontaneous Processes Chapter 19First Law of ThemodynamicsE = q + wEnergy does not predict if a process will occur. Spontaneous: occurs by itself, without outside helpChemistry:TheCentral Science, 11th ed. CH 112 - General Chemistry II Passaic Dr.Che
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Oxidation-Reduction RxNsOxidation: Loss of electronsCHAPTER 20ElectrochemistryReduction: Gain of electronsChemistry: The Central Science, 11th ed. CH 112 - General Chemistry II Passaic County Community College Dr. Fred SafarowicRelationship between
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RadioactivityNucleons: protons & neutronsChapter 21Nuclear ChemistryAtomic Number Mass Number: Isotope Abundances235 92Mass NumberUAtomic NumberChemistry:TheCentral Science, 11th ed. CH 112 - General Chemistry II Passaic Dr.RadionuclidesRadiois
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Complex Structure Coordination CompoundsChapter 24Coordination Compounds: Groups of atoms attached to a central transition metal atom. Atom groups are called: ligands Cordination Sphere: area where ligands are attached to metalChemistry:TheCentral Scie
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