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CarbohydratesI

Course: CHEM 8902, Spring 2011
School: LSU Alexandria
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Palleros Carbohydrates 1. Carbohydrates 1 Daniel Making Rings with Sugars 2. Haworth Projections 3. Going from the Fischer to the Haworth Projection 4. Going from the Haworth Projection to the Chair Conformation 5. Definition of and Anomers 6. Chair Conformations 7. Drawing Furanose Rings 8. Rotating Sugars 9. The Anomeric Effect 10. The Many Forms of Sugars 11. L sugars 12. Epimerization and Isomerization of...

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Palleros Carbohydrates 1. Carbohydrates 1 Daniel Making Rings with Sugars 2. Haworth Projections 3. Going from the Fischer to the Haworth Projection 4. Going from the Haworth Projection to the Chair Conformation 5. Definition of and Anomers 6. Chair Conformations 7. Drawing Furanose Rings 8. Rotating Sugars 9. The Anomeric Effect 10. The Many Forms of Sugars 11. L sugars 12. Epimerization and Isomerization of Sugars 13. Other Important Carbohydrates 14. Biological Glycosides 14.1 Alcoholic glycosides 14.2 Phenolic glycosides 14.3 Couma rin glycosides 14.4 Cyanogenic glycosides 14.5 Cardiac glycosides 14.6 Flavonoid glycosides 14.7 Sa ponins 15. N-glycosides 16. Shorthand Notation of Sugars Additional Problems Answers to Additional Problems Carbohydrates 2 Daniel Palleros Carbohydrates Carbohydrates are essential biomolecules that provide the fuel that makes life possible. They are also the building blocks of structural elements such as the cell wall of bacteria and the exoskeleton of insects and crustaceans. Carbohydrates are also used by Nature to increase the solubility of other biomolecules that get attached to them. This increase in solubility facilitates their transport and excretion in the organism. You will encounter carbohydrates repeatedly in biochemistry and medicinal chemistry. The goal of this chapter is to provide you with a deeper understanding of these important compounds. When we are finished, you should be able to take any monosaccharide and draw it with ease in the Fischer and Haworth projections, chair conformations, furanose and pyranose forms and view it from different perspectives. You will also get familiar with some biological aspects of their chemistry, including isomerization reactions, biological glycosides and N-glycosides. To get started, you should first review the following concepts discussed in Chemistry 108B: aldoses, ketoses, pentoses, hexoses, Fischer projection, chair conformations, sugar tree (conformation of aldohexoses), D and L sugars, anomers, pyranoses, furanoses, hemiacetals and glycosidic bonds (sections 25.1-25.6 in McMurrys Organic Chemistry, 7th ed.) You should then proceed to the supplemental material discussed here (sections 1-16). The following sections in McMurrys Organic Chemistry (7th ed.) must also be read: 25.7 The Eight Essential Monosaccharides 25.8 Disaccharides 25.9 Polysaccharides and Their Synthesis 25.10 Some Other Important Carbohydrates Carbohydrates 3 Daniel Palleros 1. Making Rings with Sugars When one molecule of an alcohol reacts with one molecule of an aldehyde or a ketone, a hemiacetal is formed. The reaction is reversible and usually (but not always) requires the addition of an acid catalyst, HA. Under normal conditions the equilibrium is shifted toward reactants. O R-OH an alcohol + R' C R" HA R' OH C R" + H2O OR a hemiacetal an aldehyde or a ketone When the carbonyl group of a sugar reacts with one of the sugars hydroxyl groups, a cyclic hemiacetal is obtained. Only five- and six-membered rings are stable enough to be formed; they are called furanoses and pyranoses, respectively. In fact these cyclic hemiacetals are so stable that the reaction is shifted toward products; furthermore, no added catalyst is needed. For aldoses, if the OH on carbon 4 reacts with the carbonyl, a furanose is obtained; if the OH on carbon 5 reacts instead, a pyranose is obtained. This is illustrated below with D-aldohexoses and D-aldopentoses. For clarity, some of the C-H bonds have been omitted. To make it general, the stereochemistry of some of the carbon atoms was left undetermined and represented by squiggly bonds. Aldoses closed Fischer projections anomeric carbon H 1 2 3 4 5 O H OH OH OH OH 1 OH H 1 OH 2 3 4 5 OH OH O OH 2 3 4 5 OH OH OH O 6 CH2OH a D-aldohexose 6 CH2OH furanose of a D-aldohexose 6 CH2OH pyranose of a D-aldohexose closed Fischer projections anomeric carbon H 1 2 3 4 O 1 H OH OH OH 1 OH H OH 2 3 4 OH OH O 2 3 4 OH OH OH 5 CH2OH 5 CH2OH 5 CH2O a D-aldopentose furanose of a D-aldopentose pyranose of a D-aldopentose Carbohydrates 4 Daniel Palleros For 2-ketohexoses, such as fructose, if the OH on carbon 5 reacts, a furanose is obtained; if the OH on carbon 6 reacts instead, a pyranose is obtained. 2-Ketoses closed Fischer projections anomeric carbon 1 CH2OH 2 3 4 5 O OH OH OH 1 CH2OH 2 3 4 5 OH OH OH O 1 CH2OH 2 3 4 5 OH OH OH OH 6 CH2OH a D-2-ketohexose 6 CH2OH 6 CH2O furanose of a D-2-ketohexose pyranose of a D-2-ketohexose Note that rings drawn in the Fischer projection (called closed Fischer projection) look awkward as one of the C-O bonds has been unrealistically stretched to close the ring. For this reason, chemists prefer to represent rings in the chair conformation or the Haworth projection (discussed in the next section) rather than in the closed Fischer projection. Some structural features of furanoses and pyranoses are worth remarking: the ring begins at the anomeric carbon, which can be carbon 1 (aldoses) or carbon 2 (2-ketoses); the anomeric carbon is easily identifiable by virtue of being the only carbon simultaneously attached to an OH group and the oxygen of the ring. Note that in aldoses, the anomeric carbon has also a hydrogen atom attached but in ketoses there is a CH2OH group (carbon 1) instead. These groups have been circled in the above structures. Other groups that are also dangling from the ring, but at the end of the chain rather than at the beginning, have been boxed in the above structures (terminal CH2OH and terminal CHOH-CH2OH). Also note that some pyranoses lack the terminal CH2OH group, such as those of aldopentoses and 2-ketohexoses. In principle, a carbohydrate can exist in both the pyranose and the furanose forms; it has been found experimentally that a given sugar exists in a particular and unique proportion of both forms in normal aqueous solutions. This will be discussed in section 10. 2. Haworth Projections The Haworth projection is a convenient but simplified way of representing six-membered rings. In this projection the ring is represented as being planar and the substituents are either up or down. There are no axial or equatorial positions. D-glucose in the chair conformation and the Haworth projection is shown below. Carbohydrates 5 Glucose Daniel Palleros Haworth Projection OH H 6 CH2OH 4 HO HO 6 5 H O 5 H O H OH H H 1H 3 H H 4 OH 1 OH 2 OH OH H 3 2 OH Note that the Haworth projection retains the same information as the chair about the substituents being above or below the plane but it does not say if the substituents are axial or equatorial. Thus, the OH group on carbon 1 is down (and axial) in the chair and down in the Haworth projection. The H atom on the same carbon is up (and equatorial) in the chair and up in the Haworth projection, and so on. Like with the chair conformation, drawing the H atoms attached to carbon is optional and oftentimes those hydrogens are omitted. The thick lines that indicate bonds closer to the viewer are also often omitted, see below. Glucose CH2OH O OH OH OH OH OH OH OH OH CH2OH O Haworth projections 3. Going from the Fischer to the Haworth Projection In this section you will learn how to transform an aldohexose from the Fischer to the Haworth projection. The steps outlined here can easily be generalized to transform any pyranose, not just an aldohexose, from the Fischer to the Haworth projection. Step 1. Draw the molecule in the Fischer projection. D-glucose in the Fischer projection is shown below. Recall that in this projection, horizontal bonds are coming towards the viewer and vertical bonds are going away. Therefore, if we look directly at any of the carbons, the rest of the molecule will be curling inside the page, away from us. Carbohydrates 6 D-Glucose Fischer projection 1 CHO 1 CHO OH H OH H HO Daniel Palleros H HO H H 2 3 4 2 3 1 CHO OH H H 2 HO OH H 4 H H OH 3 6 H OH 5 OH 5 OH HOH2C H 4 5 OH 6 CH2OH 6 CH OH 2 Step 2. Take the Fischer projection and turn it on its side by rotating the whole molecule 90o, so that all the C atoms lie in the same plane, perpendicular to the page. 1 CHO H 2 HO OH H turn on its side by rotating 90o 4 5 OH 6 CH2OH 3 6 H OH OH CHO 1 2 OH HOH2C H 4 5 OH OH 3 down Figure 1 The OH groups on the right in the Fischer projection go down when the molecule is turned on its side. The OH groups on the left in the Fischer projection go up. The mnemonic If it is left up to me, I would be down right angry may help you remember this. Note that the OH on the farthest stereogenic carbon (the OH that defines the D series), C5, is pointing down when the molecule is turned on its side (this will be important later). For clarity, the C-H bonds have been omitted. Step 3. By rotating the appropriate carbon-carbon bond, place the OH that will form the hemiacetal (the OH on C5 in the case of aldohexoses) in the same plane as the carbon atoms and pointing toward the carbonyl group. In the case of D-glucose we do this by a 90o counterclockwise rotation of the C4-C5 bond. This puts the OH on C5 in the same plane as C1-C5 and also moves C6 up, above the plane of the molecule. 5 OH 6 CH2OH OH CH2OH 6 rotate C4-C5 bond CHO 1 2 OH 5 4 OH OH OH 4 OH by 90o CHO 1 2 OH 3 3 Figure 2 Carbohydrates 7 Daniel Palleros Step 4. We close the ring by reacting the OH with the carbonyl to form the cyclic hemiacetal. The hemiacetal OH that results from the reaction, called the anomeric OH, can point up or down. Two anomers are formed. Anomers are discussed in section 5. Haworth projections of D-g lucose CH2OH 6 5 4 OH OH OH 6 CH2OH form hemiacetal between 4 CHO 1 OH on C5 and C1 2 OH OH 6 CH O H 2 O HO 5 HO 4 5 HO O + 1 2 HO OH 1 2 HO OH 3 3 3 anomeric C with two possible configurations Figure 3 Note that the Haworth projections of D-glucose have C1, C2, C3, C4, C5 and the oxygen atom all in the same plane. By convention, the oxygen atom usually occupies the topright corner and C1 is drawn on the right. The molecule can, of course, be rotated and represented from different perspectives (this is discussed in section 8) but the standard representation is the one shown in Figure 3 with the oxygen in the top-right corner and carbon 1 on the right. In this representation, D-aldohexoses have the terminal CH2OH group (C6) pointing up and L-aldohexoses have the terminal CH2OH group pointing down as indicated in the figure below (L sugars are discussed in section 11.) Scaffolds for D and L-aldohexoses in the Haworth projections 6 5 4 1 3 D 2 CH2OH O 5 4 6 3 L CH2OH O 1 2 Figure 4 In summary, to go from the Fischer projection to the Haworth projection for any pyranose we follow step 1 though step 4. For aldohexoses, we can take a shortcut. We first decide if the aldohexose is D or L. For D-aldohexoses we draw the scaffold as shown in Figure 4, left, and for L-aldohexoses we draw the scaffold as shown on the right. Then, to place the OH groups on carbons 2-4, we follow the rule: right in the Fischer projection, down in the Haworth projection; left in the Fischer projection, up in the Haworth projection. For C1, the anomeric C, two configurations are possible giving rise to two anomers. Carbohydrates 8 Daniel Palleros Example I, D-galactose: Fischer projection 1 CHO Haworth projections H HO HO H 2 3 4 5 OH H 4 6 CH2OH O OH 1 2 6 OH 5 HO 3 CH2OH O 1 2 OH 5 4 H OH HO 3 OH OH OH 6 C H 2O H anomers of D-galactose D-galactose Example II, L-mannose: Fischer projection 1 CHO Haworth projections H H HO HO 2 3 4 5 OH OH OH 4 5 6 C H 2O H 3 O OH 1 2 OH 5 4 6 CH2OH 3 O 1 2 H H HO OH OH HO OH 6 CH2OH anomers of L-mannose L-mannose 4.Going from the Haworth Projection to the Chair Conformation The carbon atoms in a saturated six-membered ring are never in the same plane as the Haworth projection shows, but rather alternate above and below an imaginary plane in a conformation known as the chair. To go from the Haworth projection to the chair, move C4 up and C1 down. Move the atoms adjacent to those carbons in the opposite direction: C3 and C5 (adjacent to C4) down, and C2 and the oxygen (adjacent to C1) up. 6 CH2OH 5 H O H OH OH H 6 CH2OH H 4 OH 4 H 1 2 H 5 2 O HO HO 1 OH 3 H H OH H 3 H OH Carbohydrates 9 Daniel Palleros To draw the perfect chair keep these ideas in mind: All axial bonds must be perfectly vertical. The axial bonds follow the carbons: if the carbon points up, the axial bond points up; if the carbon points down, the axial bond points down. An equatorial bond points in the opposite direction to the axial bond: if the axial bond points down, the equatorial bond attached to the same carbon points up, and vice versa. All equatorial bonds are slanted and should not be drawn inside the ring. To place the substituents in the chair, follow the simple rule: if a substituent is up in the Haworth projection, it must be up in the chair (it can be axial or equatorial, depending on the carbon); if a substituent is down in the Haworth projection, it must be down in the chair (it can be axial or equatorial depending on the carbon). 5. Definition of and Anomers The general definition and of anomers says that an anomer has the anomeric OH and the oxygen on the farthest stereogenic carbon (C5 in the case of hexoses) on the same side in the Fischer projection. Conversely, the anomer has the anomeric OH and the oxygen on the farthest stereogenic carbon on opposite sides in the Fischer projection. This definition applies to both D and L sugars. The two anomers of D-glucose in the closed Fischer projection are shown below. Anomers of D-glucose in the closed Fischer projection 1 2 3 4 5 1 HO H HO H H H H H HO H H OH OH H OH O 2 3 4 5 OH H OH O 6 C H 2O H same side: " 6 C H 2O H opposite sides: ! Since sugars are hardly ever represented in the closed Fischer projection, to actually apply this definition we must be able to transform the closed Fischer projection into Haworth projections, back and forth. To go from a closed Fischer projection to the Haworth projection we follow the steps outlined in section 3. For aldohexoses, we first draw the scaffold for the sugar (D or L) as shown in Figure 4 and then position the OH groups following the usual rule: right in the Fischer projection, down in the Haworth projection; left in the Fischer projection, up in the Haworth projection. This also applies to the anomeric OH. Carbohydrates 10 Anomers of D-glucose in the Haworth projection 6 5 H CH2OH O H OH H H H Daniel Palleros 6 CH O H 2 5 1 OH O H OH H OH 4 OH 4 OH 1 2 H H 3 ! anomer 2 OH H 3 down " anomer OH Note that in agreement with the general definition of anomers, the anomer has the anomeric OH pointing down in the Haworth projection like the OH on the farthest stereogenic center, C5, was in the Fischer projection turned on its side (right structure in Figure 1, page 6). As precise as the general definition of and anomers is, it is sometimes hard to apply because, as already mentioned, it requires transforming the sugar, from the Fischer to the Haworth projection. Thus, other definitions that can be directly applied to rings are often used. A second definition of and anomers that is found in many textbooks, including the 6th edition of McMurrys Organic Chemistry (but not in the 7th) and which can be considered a useful shortcut of the general definition, says that the anomer has the anomeric OH and the last CH2OH group trans to each other in the Haworth projection or chair conformation, and the anomer has the two groups cis. This definition is true for D and L sugars. D-glucose trans: ! anomer CH2OH H O H OH H OH H OH OH H OH H H CH2OH O H OH H cis: " anomer OH OH H ! anomer " anomer This definition is very useful for rings but has limitations because it relies on the presence of a terminal CH2OH group which may be absent in some sugars such as arabinopyranose (discussed below). There is a third definition of and anomers that can be used as long as the sugar is drawn in the standard representation with the oxygen atom in the top and carbon 1 on the right. According to this definition, the anomer of a D sugar has the anomeric OH pointing down and the anomer pointing up. Carbohydrates 11 Daniel Palleros Scaffold for D hexopyranoses CH2OH O CH2OH O OH pointing up OH ! anomer pointing down " anomer For L sugars, it is the opposite. Scaffold for L hexopyranoses pointing up O CH2OH OH C H 2O H OH O ! anomer " anomer pointing down An important application of the third definition is that it can be used for sugars that lack a terminal CH2OH group such as arabinopyranose. D-arabinopyranose is D-arabinose, a pentose, in which the six-membered ring is formed between carbon 1 and the oxygen on the last carbon (C5). The and anomers in the Haworth projections are shown below. Note the absence of a terminal CH2OH group. The anomer has the anomeric OH pointing down and the anomer pointing up. 5 4 OH OH O OH 1 4 OH 5 3 OH OH O OH OH 3 2 !-D-arabinopyranose down D series conventional representation 1 ! 2 up D series conventional represenation ! !-D-arabinopyranose A limitation of the third definition is that the sugar must be in the standard representation. If the molecule has been rotated (rotation of sugars is explained in section 8) this definition may not apply. When applied properly all three definitions must lead to the same result. Whether we apply one or the other should be a matter of convenience. For example, in the case of arabinopyranose we cannot apply the second definition because the molecule lacks a terminal CH2OH group but we can apply the first and the third definition, which lead to the same result. We have already seen the third definition in action with arabinopyranose, lets now apply the first. The farthest stereogenic carbon is carbon 4. In the anomer both the oxygen on the farthest stereogenic carbon and the anomeric OH point in the same direction as the general definition demands. In the anomer they point in opposite directions. Carbohydrates 12 !-D-arabinopyranose Daniel Palleros H HO H H 1 2 3 4 !-D-arabinopyranose HO OH H OH OH O 1 2 3 4 H H OH OH O 5 4 OH OH 3 O OH 1 OH HO H 5 4 OH OH 3 O OH OH 1 2 H 2 5 H 2C 5 H 2C same side: ! same side: ! opposite sides: ! opposite sides: ! All three definitions of and anomers also apply to sugars in the five-membered, furanose, rings (discussed in section 7). 6. Chair Conformations Sugars can exist in two chair conformations in equilibrium with one another (chair flip). In one of them carbon 1 is pointing down and in the other is pointing up. In the chair with carbon 1 pointing down, D-aldohexoses have the terminal CH2OH group equatorial. This chair conformation is called C1. The other chair with carbon 1 pointing up and the CH2OH group axial is called 1C. OH HO 46 equatorial 5 2 C1 chair pointing down O axial 6 5 1 O pointing up 1 4 3 3 2 1C chair The names C1 and 1C may seem confusing. To remember which one is each, the following phrase may help: 1 before is up, 1 after is down. This means that by placing the 1 before the C (1C) we represent the chair with carbon 1 pointing up, and by placing it after the C (C1), the chair with carbon 1 pointing down. Because a CH2OH group in the axial position reduces the stability of the chair, 1C chairs are usually (but not always) less stable than C1 chairs. Their stability ultimately depends on the position of all the substituents on the ring. As a result, D-glucopyranose exists almost exclusively in the C1 chair conformation because in this conformation all of the ring substituents occupy equatorial positions. HO 6 5 OH O OH !"D-glucopyranose 4 OH 6 5 2 3 O OH OH 1 2 OH HO HO 4 OH 3 1 1C chair C1 chair More stable Carbohydrates 13 Daniel Palleros For other sugars, such as D-idopyranose, the situation is different; D-idopyranose exists mainly in the 1C chair (see below). In the C1 chair, D-idopyranose has three of its OH groups (those on carbon 2, 3 and 4) in the least stable axial positions. By being in the 1C chair, those three OH groups occupy the more stable equatorial positions and this relieves the steric repulsion caused by the axial groups (terminal CH2OH and OH on carbon 1). !"D-idopyranose HO 6 5 O OH OH OH 1 4 OH 6 5 3 OH OH O OH HO 4 HO 3 2 2 1 1C chair More stable C1 chair 7. Drawing Furanose Rings As we discussed in previous sections, sugars in a five-membered ring are called furanoses. To draw a furanose ring beginning with a Fischer projection we follow similar steps to those outlined before when drawing the Haworth projection. Lets first consider D-talose, an aldohexose. To form a furanose ring, the OH on C4 must react with the carbonyl. 1 CHO these two groups must react HO HO HO H 2 3 4 5 H H H OH 6 CH2OH D-Talose We turn the molecule on its side by rotating it 90o. The OH groups that are on the left in the Fischer projection go up, and those on the right go down. 1 CHO HO 2 HO 3 HO 4 OH H H H turn on its side by rotating 90o 4 5 OH OH CH2OH OH OH 6 CHO 1 6 HOH2C H 3 2 5 D-Talose To form a five-membered ring, the carbonyl (C1) must react with the OH on C4 which must be in the same plane as C1, C2, C3 and C4. To that effect, the C3-C4 bond must be rotated clockwise 90o. This results in the C4-C5 bond moving down, below the plane. Carbohydrates 14 R 5 CH2OH OH OH Daniel Palleros 6 OH OH 4 2 3 CHO 1 rotate C3-C4 90o H HO OH 4 5 6 CH2OH OH OH CHO 1 3 2 R The configuration at C5 must be clearly (and correctly) shown once the C3-C4 bond is rotated. The best way to assure that the substituents on C5 are in the correct positions is to assign R/S configuration to this carbon before the rotation and stick to it after the C3-C4 bond has been rotated. The configuration of C5 is R. The anomer of D-talofuranose is shown below in four different representations. The first structure is the closed Fischer projection. Note that the anomeric OH and the OH on the last stereogenic carbon, C5, are both on the same side as it should be for an anomer. In the other structures the anomeric OH is pointing down in agreement with the third definition of anomers in the D series. Note that in all four structures, C5 is R. In the last structure, C5 (and only C5) is in the Fischer projection. 1 H OH HO HO O H 2 3 4 5 H H H HO H H O HO OH H H O HO OH H H O HO OH same side: ! H 4 5 1 OH 6 HOH2C 4 5 1 OH H 4 5 1 OH 3 OH 3 6 R CH2OH 2 3 2 OH 2 OH H CH2OH R !-D-talofuranose R 6 6 CH2OH R Lets now make the furanose ring of fructose, a ketohexose. To form a furanose, the OH on C5 must react with the carbonyl. 1 CH2OH 2 HO H H O H OH OH 3 4 5 these two groups must react 6 CH2OH D-Fructose We turn the molecule on its side by rotating it 90o. 1 C H 2O H O 2 HO H 6 turn on its side 5 OH CH2OH 3 6 H OH 1 CH2OH by rotating 90o 4 OH OH H O H 2C H 4 5 OH 3 2 O Carbohydrates 15 Daniel Palleros To form the five-membered ring, the carbonyl (C2) must react with the OH on C5, and thus we rotate the C4-C5 bond counterclockwise to put that OH in the same plane as C2, C3, C4 and C5. 5 OH 6 CH2OH 6 CH2OH 1 CH2OH rotate C4-C5 bond by 90o 4 OH 5 OH OH 1 CH2OH 4 OH OH 3 2 O 3 2 O The two anomers are shown below. Note that in this case, because the sugar is a ketose, the anomeric carbon is C2 instead of C1 and has a CH2OH group attached instead of an H. The anomer has the anomeric OH pointing down, like the OH on C5 in the Fischer projection turned on its side (see left structure above). The anomer has the OH on C2 pointing up. Also note that the anomer has the anomeric OH and the terminal CH2OH (C6) trans to one another. These two groups are cis in the anomer. This is in keeping with the second definition of anomers. 6 CH2OH 5 4 OH OH O 1 CH2OH 6 CH2OH 5 4 OH OH O cis: " OH 2 OH 2 1 CH2OH 3 ! anomer 3 " anomer trans: ! 8. Rotating Sugars Pyranoses are usually represented with the oxygen in the top-right corner, carbon 1 on the right, and carbon 4 on the left. This is what we call the standard representation. Consider, for example, -D-mannopyranose: c H 4 HO HO 3 H !-D-mannopyranose b 6 CH2OH 5 OH O a H 2 H 1 OH H Out of necessity, it is often required to view a sugar molecule from a different perspective. This can be done by rotating it along one of its many axes. An axis is a line that passes through the center of the molecule as shown in the figure above. A common rotation is along the horizontal axis contained on the C1-C4 plane (plane of the page, axis a). A 180o rotation yields the following structure. Carbohydrates 16 Daniel Palleros H 4 HO HO 6 CH2OH 5 H H H OH O rotate 180o around the axis on the C1-C4 plane OH 3 HO HO H 2 OH H 1 H a 3 2 H H 1 OH 4 H 5 6 CH2OH O As a result of this rotation, C1 and C4 stay in the same plane. The carbons that were closer to us (C2 and C3) move away from us and the ones farther away (C5, C6 and the oxygen) move closer to us. Substituents that were pointing up, now point down, and vice versa. Note that substituents that were axial stay axial and substituents that were equatorial stay equatorial. Another useful rotation is a 180o rotation along the axis that cuts through the C2-C3 and C5-O bonds (axis b). H 6 CH2OH b OH O rotate 180o around the axis that goes through C2-C3 and C5-O bonds H H H 4 HO HO 5 H H OH 1 O H H 5 6 CH2OH OH 3 2 1 OH 2 OH 3 OH H 4 As a result of this rotation, C3, C4, C5 and C6 move to the right and C1, C2 and the oxygen move to the left. The carbons that were closer to us (C2 and C3) stay closer to us. Substituents that were up, are now down and vice versa; axial stays axial and equatorial stays equatorial. Another useful rotation is that along the vertical axis (axis c). A clockwise 120o rotation is shown below. In this rotation, up stays up, down stays down, equatorial stays equatorial and axial stays axial. Only the absolute position of the atoms changes and, as a result, C1 moves to the left and the oxygen moves from the top-right corner to the bottom-right corner, and so on. c H 4 HO HO 6 CH O H 2 OH OH O rotate 120o along the verical axis H H H H HO 5 H H 2 H 3 O H 4 OH 3 2 5 H CH2OH 1 OH 1 OH 6
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Chapter/Scene SummaryFunction 1.1Notes The Pontelliers (wealthy French Creoles from New Orleans) rent a cottage from Madame Lebrun to spend their vacation in the Grand Isle, where it turns out that Leonce Pontellier is bothered by the distractions from
University of Texas - ENG - 316K
Chapter/Scene1:1 SummaryNotes Okonkwo at the age of 18 became famous for defeating Amalinze the Cat, who has never been defeated by anyone from the nine villages for over seven years. Defeating Amalinze the Cat function to show the reader Okonkwo's comi
University of Texas - ENG - 316K
Evening Hawk by Robert Penn Warren In the Evening Hawk, Robert Penn Warren makes extensive use of figurative language and imagery to describe the unforgiving passage of time. Warren uses a variety of language devices in order to convey a portentous feelin
University of Texas - ENG - 316K
Chapter/Scene SummaryFunction 1.1Notes The narrator begins the story by stating, I became what I am today at the age of twelve. The setting of the novel starts off in San Francisco, California, where the narrator receives a call from an old friend, Rahi
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Chapter/Scene SummaryFunction 1.1Notes The protagonist, Masuji Ono, opens the novel by speaking about the unsual process he had to come across when buying his house (screening and investigations) . Originally, the house had been built and owned by a Jap
CSU Chico - POLS - 155
Jump to Navigation Frame Your location: Assessments Attempt View Attempt 1 of 2 Title: IRAT 3 Started: February 14, 2010 1:42 PM View All Submissions ViewSubmitted: February 14, 2010 1:49 PM Time spent: 00:07:29 Total score: 17/20 = 85% Total score adjus
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Jump to Navigation Frame Your location: Assessments Attempt View All Submissions ViewView Attempt 2 of 2Title: Started: Submitted: Time spent: Total score: IRAT 13 May 2, 2010 6:39 PM May 2, 2010 6:44 PM 00:04:04 19/20 = 95% Total score adjusted by 0.0
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JumptoNavigationFrame Yourlocation:Assessments Attempt ViewAllSubmissions ViewView Attempt 1 of 2Title: Started: IRAT9 April4,20104:20PMSubmitted: April4,20104:30PM Time spent: Total score: 00:09:2519/20=95% Totalscoreadjustedby0.0 Maximumpossiblescor
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JumptoNavigationFrame Yourlocation:Assessments Attempt ViewAllSubmissions ViewView Attempt 1 of 2Title: Started: IRAT10 April11,20102:36PMSubmitted: April11,20102:43PM Time spent: Total score: 00:07:0916/20=80% Totalscoreadjustedby0.0 Maximumpossibles
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1.Jump to Navigation Frame Your location: Assessments Attempt View All Submissions ViewView Attempt 2 of 21. over sight 100 %2. polic ing3. stack ing the deck4. bure aucr atic driftScore: 1/118.Despite widespread public support for the New Deal,
CSU Chico - POLS - 155
Jump to Navigation Frame Your location: Assessments View All Submissions View AttemptView Attempt 1 of 2Title: IRAT 6 Started: March 7, 2010 2:13 AM Submitted: March 7, 2010 2:18 AM Time spent: 00:04:40 Total score: 17/20 = 85% Total score adjusted by 0
CSU Chico - POLS - 155
JumptoNavigationFrame Yourlocation:AssessmentsViewAllSubmissionsViewAttemptView Attempt 1 of 2Title: Started: A p r i l 2 5 , 2 Submitted: April25,20105:18PM 0 1 0 5 : 1 2 P M Time spent: Total score: 00:05:35 IRAT1220/20=100%Totalscoreadjustedby0.0Max
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JumptoNavigationFrame Yourlocation:AssessmentsViewAllSubmissionsViewAttemptView Attempt 1 of 2Title: Started: IRAT12 April25,20105:12PMSubmitted: April25,20105:18PM Time spent: Total score: 00:05:3520/20=100% Totalscoreadjustedby0.0 Maximumpossiblesco
CSU Chico - POLS - 155
1.Which of the following was NOT a source of significant conflict at the Constitutional Convention?3. whether or not the Declaration of Independence needed to be thrown out or amended2.The most significant economic differences among the framers of the
CSU Chico - POLS - 155
CSU Chico - POLS - 155
Title: IRAT4 Started:Submitted:::1. Whichofthefollowingdirectdemocracydevicesallowsvoterstoapproveorrejectstatutesoramendments passedbythelegislature?StudentResponse 1. referendumValue 100%CorrectAnswer Feedback 2. initiative 3. recall 4. nonpar
Palmer Chiropractic - PHYS - 339
Cardiovascular Physiology Cardiovascular disease is #1 cause of death Major underlying cause is ischemia due to:atherosclerosis (plaquing) white thrombus red thrombus artery spasm It ain't what you don't know that gets you into trouble. It's what you k
Palmer Chiropractic - PHYS - 339
Systemic circulation is similar to a parallel circuit by designCirculation The main function of the systemic circulation is to deliver adequate oxygen, nutrients to the systemic tissues and remove carbon dioxide & other waste products from the systemic
Palmer Chiropractic - PHYS - 339
Pulmonary Physiology Respiratory neurons in brain stem sets basic drive of ventilation descending neural traffic to spinal cord activation of muscles of respirationMechanoreceptorsRespiratory Control System Cerebral Cortex Respiratory center-Medulla N
Palmer Chiropractic - PHYS - 339
Cardiovascular disease is #1 cause of death. Major underlying cause is ischemia due to: atherosclerosis white thrombus red thrombus artery spasm (plaquing) Connective Tissue Ordinary Loose connective tissue (areolar tissue) Dense ordinary connective tissu
Palmer Chiropractic - PHYS - 339
Sample questions unit one4/5/11 11:31 PMSample questions for unit one 1. Platelets help in the repair of a damaged vessel wall by releasing which of the following substances? a. thyroxin b. myosin c. Thromboxane A2 d. growth factor 2. Normally what prev
Palmer Chiropractic - PHYS - 339
The Main Function of Systemic Circulation deliver adequate O2 and nutrients to systemic tissues remove CO2 & other waste products from systemic tissues conduit for hormone and other substances so they can act at a distant site from their production Functi
Palmer Chiropractic - PATH - 1
Granulocytes Neutrophils Polymorphonuclear Cells Nucleus can take on many lobular shapes. Granules are neither acidic or alkaline. Primary activity is through phagocytosis Production rate is about 1011 per day Survival in blood stream 6-12 hours Survival
Palmer Chiropractic - PATH - 1
1 Human Defense Mechanisms Innate and Acquired Immunity There are two types of human defense: innate resistance, which includes natural barriers, the inflammatory response, and the adaptive (acquired) immune system. Components of Innate Immunity Cellu
Palmer Chiropractic - PATH - 1
Palmer Chiropractic - PATH - 1
Palmer Chiropractic - PATH - 1
1 Pregnancy and the Hygiene Hypothesis Both the placenta and the chorionic villi are entirely fetal tissue. Maternal blood "spills" from open endometrial arteries (the spiral arteries) into the intervillous space, and
Palmer Chiropractic - PATH - 1
1 Specific or Acquired Immunity Innate Review Types of immunity. Immunity may be broadly classified as innate or acquired. Innate immunity is present from birth. It consists of numerous types of nonspecific factors that operate during times of disease
Palmer Chiropractic - PATH - 1
Immunology, Exam 1 Human Defense Mechanisms / Innate & Acquired Immunity Components/Molecules of Innate & Acquired Immunity First Line of Defense Second Line of Defense1Human Defense Mechanisms / Innate & Acquired Immunity There are 2 types of human def
Palmer Chiropractic - BIO - 1
Palmer College of Chiropractic Syllabus Spring Trimester 2011 Life Sciences Chairperson: Mr. Craig Mekow Pathology 61416 Microbiology Lab 0 credit hours Tuesday, Wednesday, Thursday,& Friday Classroom C 225 Instructor Henry Brockington, III, M.S., D.C. Ro
Palmer Chiropractic - BIO - 1
"""" " " " #$%&'()$*"+&,-./0(" " " " " " " " " " "1$234.%&" 56"'56785978:*0;<=>?@=A*/=5;<BCD*E7?8FA*%GGB;=*E7?8F777777777776668" " !5H=I?J*'56F* * 556"'56785978:*/7JB;F*5C>*+FFBDCK=C9F77777777777777777777669" " 5556"%8B=C959B7CA*"C987>?;9B7CA*5C>*,585F
Palmer Chiropractic - BIO - 1
MicrobiologyLecture NotesMedical Microbiology, 5th EditionBy: Murray, Rosenthal, Kobayashi, and Pfaller 2009 By: Irene N. Paulavicius Bacteriology section contributed by Bonnie SmithTo AccompanyP a r as i tol ogy : T h e s t u d y of p r oto zoa & h
Palmer Chiropractic - BIO - 1
How we obtain a virus:1st-Cell must have receptor for virus 2nd-Once in cell virus must be uncoated 3rd-Viral DNA enters nucleus 4th-Golgi makes new protein coat-Capsid (Nucleic Acid genome lodges for protection) 5th-Pick up envelop from host cell membra
Palmer Chiropractic - BIO - 1
P A L M E R C O L L E G E O F C H I R O P R A C T I C S Y L L A B US Spring Trimester 2011 L i f e Sc i e n c e s D i v i s i o n Director: Mr. Craig L. Mekow, M.S. M i c r ob i ol ogy P A T H 61416, 5 c r e d i t hou r s Course meets: 1:55-2:45 M-H in M
Palmer Chiropractic - BIO - 1
How we obtain a virus: 1 Cell must have receptor for virus nd 2 Once in cell virus must be uncoated rd 3 Viral DNA enters nucleus th 4 Golgi makes new protein coatCapsid (Nucleic Acid genome lodges for protection) th 5
Palmer Chiropractic - BIO - 1
History of Bacteriology Leeuwenhock first to see bacteria (animalcules), thought bacteria came about through spontaneous generation Jenner first used the word vaccination, used cowpox to produce immunity to smallpox Semmelwei
Palmer Chiropractic - BIO - 1
1 Bacillus anthracis Anthrax zoonotic disease that effects herbivores Humans are infected through infected animal tissues or can be used as biological warfare spore former found in soil (Malachite greenspecial spore stain
Palmer Chiropractic - BIO - 1
Microbiology Exam 1 Material Parasitology Protozoa Single cell organism (Eurkaryotes), No eggs (reproduce by fission) Can either Incyst or Excyst Transmission: fecaloral route, insect vector, direct contact Vector carrier
Palmer Chiropractic - BIO - 1
Microbiology Exam 2 Spring 2006Bacterial DNA PiecesNicole M. Schmidt Palmer CollegeDNA pieces which exist separately from the chromosome transfer to other bacterial cells may result in new strains or strains with new traits 2 Types: 1. Plasmids 2. Tran
Palmer Chiropractic - BIO - 1
Viruses before theyre in a host are a nucelocaspid = genome + capsid (protein coat). In order to be a virus (divide, live) they must have a live cell to multiply in. Capsid From host cell membrane or nuclear material Virion Completely assembled virus outs
Palmer Chiropractic - BIO - 1
This is missing the hepatitis chart* make sure to look at someones who went to class and study those notes! Viruses before theyre in a host are a nucelocaspid = genome + capsid (protein coat). In order to be a virus (divide, live) they must have a live ce
Palmer Chiropractic - PHYS - 3
Weapons in neurophysiologist s armory Recording Individual neurons Gross potentials Brain scansCerebral Cortex Every cubic inch of cerebral cortex has about 10,000 miles of nerve fibers in it The number of neurons in the brain is about 30 X greater th
Palmer Chiropractic - PHYS - 3
Reticular excitatory area General area/system for control of the overall level of excitation of the brain in reticular formation of pons & midbrainReticular Excitatory Area If inactivated the brain activity reduced (coma is likely) stimulated by: per
Palmer Chiropractic - PHYS - 3
Sleep Physiology-basic mechanisms of sleep & arousal In 1940 s Moruzzi & Magoun found that electrically + certain areas in the brain and brainstem produced cortical activation arousal states appear to be determined by an interaction among the brainstem,
Palmer Chiropractic - PHYS - 3
Advanced Neurophysiology Exam 1 Spring 2006Weapons in Neurophysiologists ArmoryNicole M. Schmidt Palmer College1. Recording a. individual neurons b. gross potentials c. brain scans 2. Stimulation 3. Lesions experimental and natural 1. Pyramidal cells -
Brescia - BIOL - 101
Violet Maka Ecology and Evolution Toepfer August 21, 2009Ecology and Evolution The current case study pertaining to finches and iguanas relates to how organisms in their environment are affected by outside factors and how they adapt to altering condition
Brescia - BIOL - 300
Maka1Antibiotic Resistance in Developing CountriesSocioeconomic and behavioral antecedents have escalated the spread of antibiotic resistance. These include the misuse of antibiotics by health professionals, unskilled practitioners, and laypersons; poor