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Exam 3-solutions

Course: MATH 305G, Spring 2011
School: University of Texas
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370 Version Exam 3 laude (51635) This print-out should have 40 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 6.0 points The Ostwald process is used to produce which of the following? 1. NH3 2. HNO3 correct 3. Al 4. H2 S 6. 289, 456 C Explanation: This is a 3 electron process. 002 6.0 points Which of the following is not commonly used to...

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370 Version Exam 3 laude (51635) This print-out should have 40 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 6.0 points The Ostwald process is used to produce which of the following? 1. NH3 2. HNO3 correct 3. Al 4. H2 S 6. 289, 456 C Explanation: This is a 3 electron process. 002 6.0 points Which of the following is not commonly used to protect the world from rust? 1. oxide coatings 2. galvanization 3. salt washings correct 4. sacricial electrodes Explanation: Salt washings would actually accelerate oxidative processes. 003 6.0 points How many Coulombs of charge are needed to create 19.7 g of Au(s) from Au3+ (aq)? 1. 0.1 C 2. 96, 485 C 3. 0.3 C 4. 9, 649 C 5. 28, 945 C correct 1 mol 197 g (19.7 g Au(s)) = 0.1 mol Au(s) 4 hr = 14, 400 s It = np Ne F Q = np Ne F = 0.1 3 96, 485 = 28946 C 004 5. H2 SO4 Explanation: 1 6.0 points Consider the reaction mechanism below: Step 1 2 overall Reaction NO2 + F2 NO2 F + F NO2 + F NO2 F 2NO2 + F2 2NO2 F Which species is a catalyst and which is an intermediate, respectively? 1. none, F correct 2. NO2 , NO2 3. NO2 F, F 4. none, NO2 F 5. NO2 , F Explanation: The reactants that precede the slowest forward step will appear in the rate law for a reaction. 005 6.0 points In a catalytic converter, one of the general . sets of reactions is a reduction. It is 1. incomplete combustion products being converted to carbon dioxide. Version 370 Exam 3 laude (51635) 2. nitrogen oxides being converted to nitrogen gas. correct 3. carbon dioxide being converted into methane. 5. 2.64 amp Explanation: mCu = 50 g The half equation of interest is 4. carbon monoxide being converted to carbon dioxide. Explanation: The catalytic substrate in catalytic converters accelerates severl reactions. These include the reduction of various nitrogen oxides (Nx Oy ) to nitrogen gas (N2 ). 006 6.0 points The a term for this question is 1. A second-order reaction has a rate constant of 1.25 M1 s1 . If the initial reactant concentration is 1.0 M, calculate the time required for 90% reaction. 1. 17 s 2. 7.2 s correct 3. 0.13 s 4. 1.3 s Find the moles of Cu dissolved: (50 g Cu) Colombs = amp second Coulomb amp = second 1h 1 min 1.51835 105 C = 24 h 60 min 60 s = 1.75735 C/s = 1.75735 A 008 2. 13.00 amp 3. 111.85 amp 4. 1.76 amp correct 6.0 points What is ratio of [Co2+ ] /[Ni2+ ] when a battery built from the two half reactions below reaches equilibrium? Cu(s) | Cu2+ (aq) || Fe3+(aq) | Fe(s) 1. 42.17 amp 1 mol Cu = 0.786832 mol Cu 63.546 g Cu Find the amount of charge carried by the electrons: 2 mol e 96485 C (0.786832 mol Cu) 1 mol Cu 1 mol e = 1.51835 105 C Find the average current in 24 hours: Explanation: electrochemical cell if 50 g of Cu(s) are used up in a 24 hour period? Cu2+ + 2 e Cu E = +0.22 V red 3+ Fe + 3 e Fe E = 0.04 V red t = 24 h Cu(s) Cu2+ (aq) + 2 e 5. 0.89 s 007 6.0 points What is the average current generated in the 2 Half reaction Ni2+ Fe Co2+ Co 1. 0.10 2. 0.31 3. 10.23 correct 4. 3.20 Explanation: E = +0.04 E 0.25 0.28 Version 370 Exam 3 laude (51635) 0.05916 log Q Ne [Co2+ ] 0.05916 log 0 = 0.03 2 [Ni2+ ] [Co2+ ] log = 1.01 [Ni2+ ] [Co2+ ] = 101.01 2+ ] [Ni = 10.23 Ecell = E cell 009 6.0 points A certain reaction has an activation energy (Ea ) of 0.8314 kJ mol1 and a rate constant (k ) of 2.718 s1 at -73 C. At 173 C, which expression for the rate constant is correct? 1. ln k2 = 0.5 correct 2. ln k2 = 0.5 3. ln k2 = 0 4. ln k2 = 1.5 3 011 6.0 points How many total structural isomers would the hydrocarbons of formula C3 H8 through C6 H14 have? 1. 11 isomers correct 2. 14 isomers 3. 10 isomers 4. 13 isomers 5. 12 isomer Explanation: The formula C3 H8 would correspond only to n-propane (1 isomer). The formula C4 H10 would correspond to n-butane and methylpropane (2 isomers). The formula C5 H12 would describe n-pentane, methylbutane and tetramethyl-methane (3 isomers). The formula C6 H14 would describe nhexane, 2-methylpentane, 3-methylpentane, ethylbutane, 2,2-dimethylbutane and 2,3dimethylbutane (5 isomers). 5. ln k2 = 1 Explanation: Ea k2 = ln k1 R 1 1 T1 T2 010 6.0 points Proteins are polymers formed from what kinds of bonds? 012 6.0 points Borons 3 valence electrons make it dicult for it to achieve an octet. What famous allotrope of Boron enables it to achieve an octet? 1. B12 correct 1. Ether linkage 2. B2 2. Ester linkage 3. B6 3. Thioester linkage 4. B 4. Azide linkage 5. Amide linkage correct Explanation: The condensation of the carboxyl group of one amino acid with the amino group of another amino acids results in an amide linkage. Explanation: There are a variety if allotropes of boron, the most famous being B12 . It and numerous crystalline polymorphs are all arranged in interesting and complex lattices to help Boron achieve its octet. 013 6.0 points Which of the following gemstones was used Version 370 Exam 3 laude (51635) for reproong until it was discovered to be a potent carcinogen? 1. quartz 4 016 6.0 points The compounds of which alkaline earth metal are commonly used naturally and synthetically to add rigidity and strength to structures? 2. asbestos correct 1. Sr 3. diamond 2. Be 4. talc Explanation: Asbestos has useful ame retardant properties and also is an inhalation risk as prolonged exposure can lead to mesothilioma. 014 6.0 points Sulfuric acid is a remarkably versatile material but it cant do everything. Which of the following is not a common use? 3. Ca correct 4. Ba 5. Mg Explanation: Calcium is the primary component of bone, tooth enamel, and concrete. Its many and varied salts are often quite strong. 1. reducing agent correct 017 6.0 points 2. acidication 3. dehydrating agent Based on the plot below, what are the units of the rate constant for this reaction? 4. oxidizing agent Explanation: The highly oxidized sulfate anion serves as a good oxidizing agent in high concentrations. [A] (M) 015 6.0 points If the standard free energy change for combustion of 1 mole of CH4 (g) is 818 kJ mol1 , calculate the standard voltage that could be obtained from a fuel cell using this reaction. 1. + 0.53 V time (min) 2. + 8.48 V 3. + 1.06 V correct 1. M1 min1 4. 1.06 V 2. M min1 correct 5. + 4.24 V 3. s1 Explanation: 4. M1 s1 Version 370 Exam 3 laude (51635) Explanation: The y-axis is presented in units of concentration. This, together with the fact that the line has a constant slope, tells us that this is a zero order process. The x-axis tells us the time unit is minutes. 018 6.0 points Transition state theory predicts that a set of chemical species involved in a equilibrium will . spend the least time as 5 020 6.0 points The overall reaction: NO2 (g ) + CO(g ) CO2 (g ) + NO(g ) has an empirically determined rate law with a single bimolecular collision that doesnt involve CO. If k = 2.0 102 M1 s1 , [NO2 ] = 0.3 M and [CO] = 0.1 M, what is the observed rate? 1. reactants. 1. 18 M s1 correct 2. products. 2. 6 M s1 3. Transition state theory does not allow for such predictions. 4. a transition state correct Explanation: By denition a transition state is an energetic maximum on a reaction prole, and consequently is the least stable conguration. 019 6.0 points Which of the following is not true of alkali metals? 1. They are always assigned a +1 oxidation state in compounds. 2. They have one electron in their highest energy shell. 3. They are highly reactive toward halogens. 4. They form strong acids upon reacting with water. correct 5. They are not found in their elemental form in nature. Explanation: The reaction of an alkali metal with water forms a strong base. Example: 2 K + 2 H2 O H2 + 2 KOH 3. 60 M s1 4. 1.8 M s1 Explanation: rate = k [NO2 ]2 = 2.0 102 M1 s1 [0.3]2 = 1.8 M s1 021 6.0 points If a battery is dropped into a beaker of salt water (NaCl solution), nearly all of the gas formed at the anode is which of the following? 1. Cl (g) 2. Cl2 (g) correct 3. H2 (g) 4. Na (g) 5. O2 (g) Explanation: Cl is attracted to the positive terminal of the battery, where it gets oxidized to form Chlorine gas, Cl2 . 022 6.0 points What is the activation energy for the forward reaction in the diagram below? Version 370 Exam 3 laude (51635) 6 3. 1-methyl-1-phenyleth-2-anoic acid E (kJ mol1) 80 T 4. 2-methyl-2-phenylethanoic Coordinate Explanation: Carbon acid 60 40 P R 20 0 Reaction number starts at the carboxyl carbon on account of its greater priority and the phenyl function group is attached to the second carbon in that three carbon chain. 024 6.0 points If the two half reactions below were used to make an electrolytic cell, what species would be consumed at the anode? Half reaction Au3+ (aq) + 3 e Au(s) I2 (s) + 2 e 2 I (aq) 1. 30 kJ mol1 2. 75 kJ mol1 1. I (aq) 3. 25 kJ mol1 2. Au3+ (aq) 4. 45 kJ mol1 correct 3. Au(s) correct 5. 20 kJ mol1 E +1.50 +0.53 4. I2 (s) Explanation: The dierence in energies between the transition state and the ground state reactants is 45 kJ mol1 . 023 6.0 points What is the name of the following molecule? 025 6.0 points Which of the following is the basis for collision theory? 1. string theory O H3 C Explanation: An electrolytic cell must have a negative standard cell potential and therefore the anodic reaction must consume Au(s). 2. kinetic molecular theory correct OH 3. molecular orbital theory 4. transition state theory 5. eld theory 1. 1-propanoylbenzene 2. 2-phenylpropanoic acid correct Explanation: Collision theory includes several theoretical considerations derived from KMT. Version 370 Exam 3 laude (51635) 026 6.0 points Consider the provided table of standard reduction potentials. Rank the following species from weakest to strongest reducing agent: Mn, H2 O2 , Pb, Na, Cl . 1. Pb < Cl < Na < H2 O2 < Mn 2. Cl < Na < Pb < Mn < H2 O2 3. Cl < H2 O2 < Pb < Mn < Na correct 4. Na < Cl < Mn < Pb < H2 O2 5. H2 O2 < Cl < Na < Pb < Mn Explanation: Cl appears as the product of the half reaction with the highest standard reduction potential, making it the weakest reducing agent, and Na appears as the product of the half reaction with the lowest standard reduction potential, making it the strongest reducing agent, The intermediate values are ranked accordingly. 027 6.0 points Which of the following is not a correct match of monomer and polymer? 1. Styrene is the monomer used to make polystyrene. 2. Adipic acid and hexamethylene diamine are the monomers used to make nylon. 3. Tetrauoroethane is the monomer used to make Teon. correct 7 2. Al2 O3 3. CO2 4. Al and CO2 correct Explanation: Oxidation of the carbon anode in the smelting process produces a steady amount of CO2 . Alumina is reduced to aluminum at the cathode. Side reactions of the molten cryolite produce HF. 029 6.0 points What functional group is very abundant in sugars? 1. carobyxl 2. alkyl 3. amine 4. ketone 5. hydroxyl correct Explanation: Sugars are typically highly substituted with hydroxyl (-OH) groups. 030 6.0 points Balance the reaction MnO + NO MnO2 + NO 4 2 3 in basic solution. What is the sum of the coecients? 1. 23 2. 15 4. Ethylene is the monomer used to make polyethylene. 3. 9 Explanation: 4. 13 correct 028 6.0 points What are the products of the Hall process? 5. 7 1. Al2 O3 and CO2 Explanation: The oxidation number of N changes from +3 to +5, so N is oxidized. The oxidation number of Mn changes from +7 to +4, so Mn is Version 370 Exam 3 laude (51635) reduced. We set up oxidation and reduction half reactions: Oxidation: NO1 NO1 2 3 Reduction: MnO MnO2 4 Mn and N atoms are balanced. In basic solution we use H2 O and OH to balance O and H atoms, adding the OH to the side needing oxygen: Oxid: 2 OH + NO1 NO1 + H2 O 2 3 Red: 2 H2O + MnO MnO2 + 4 OH 4 Next we balance the total charge by adding electrons. In the reduction reaction thus far there is a total charge of 1 in the left and 4 on the right. Three electrons are added to the left. Oxid: 2 OH + NO1 2 NO1 + H2 O + 2 e 3 Red: 3 e + 2 H2 O + MnO 4 MnO2 + 4 OH The number of electrons gained by Mn must equal the number of electrons lost by N. We multiply the oxidation reaction by 3 and the reduction by 2 to balance the electrons: Oxid: 6 OH + 3 NO1 2 3 NO1 + 3 H2 O + 6 e 3 Red: 6 e + 4 H2 O + 2 MnO 4 2 MnO2 + 8 OH Adding the half-reactions gives 6 OH + 3 NO1 + 4 H2 O + 2 MnO 2 4 3 NO1 + 3 H2 O + 2 MnO2 + 8 OH 3 Canceling like terms gives the overall balanced equation 3 NO1 + H2 O + 2 MnO 2 4 3 NO1 + 2 MnO2 + 2 OH 3 031 6.0 points The a term for this question is 1. What is the half-life of a reaction that has a rate constant of 280 s1 ? 1. 3.6 ms 2. 2.5 ms correct 3. 194 s 4. 404 ms 8 5. The concentration of the reactant is needed. Explanation: 032 6.0 points What was the electrolyte in the Pons/Fleishmann cell used to reportedly generate an excess of energy (cold fusion)? 1. 0.1 M LiOD correct 2. 0.1 M DCl 3. 0.1 M D2 SO4 4. 0.1 M Pd(OD)2 5. 0.1 M HCl Explanation: 033 6.0 points Consider the reaction mechanism below: Step 1 2 3 overall Reaction CH3 Br CH3 + + Br CH3 + + HCl CH3 Cl + H+ H+ + Br HBr CH3 Br + HCl CH3 Cl + HBr If step 3 is the slow step what is the rate law? 1. k [CH3 Br] 2. k [CH3 Br] [HCl] [CH3 Cl]1 correct 3. k [CH3 Br] [HCl] [Br ]1 4. k [CH3 Br] [HCl] Explanation: The reactants that precede the slowest forward step will appear in the rate law for a reaction. 034 6.0 points Which of the following monomers cannot Version 370 Exam 3 laude (51635) 9 undergo addition polymerization? H2 C CH2 ethene 3. I and III 4. II only 5. I, II and III H2 C Cl chloroethene 6. I and II only correct 7. III only H2 C CH3 propene F F Explanation: Graphite and fullerene are both electrically conducting on account of their sp2 hybridization. Diamond does not conduct electricity. 036 6.0 points What is the name of the following molecule? F F CH3 tetrauoroethene 1. ethene H2 N 2. All 4 can undergo addition polymerization correct 3. propene 1. 1-aminobutane 4. chloroethene 2. amidobutyne 5. tetrauoroethene 3. 4-butynamine Explanation: All four species can undergo addition polymerization reactions. They make, in order, polyethylene, PVC, Teon and polypropylene. 035 6.0 points Which of carbons allotropes conduct electricity? I) graphite II) fullerene III) diamond 1. II and III 2. I only 4. 1-amino 2-butyne correct 5. 1-amino 2-butene Explanation: The -amine group has higher priority than the -yne group, and so numbering starts from the amine carbon. The unsaturated carboncarbon bond begins at carbon 2. 037 6.0 points Which of the following is not true of uorine (F)? 1. Its anion is abundant in Earths oceans. correct Version 370 Exam 3 laude (51635) 10 2. It is a powerful oxidizing agent. 3. It is a diatomic gas at room temperature. 039 6.0 points Which of the following is not a way to x nitrogen? 4. It tends to form insoluble salts and minerals. 1. Pass nitrogen compounds over/through a catalytic converter. correct 5. Its anion has high charge density. Explanation: The high charge density of uorines anion tends to result in insoluble salts and minerals, and it is consequently not abundant in water. 038 6.0 points Consider the data below: [H2 O] [CO2 ] initial rate M M M s1 Exp 1 0.45 9. 4 4.84 102 Exp 2 0.45 4. 7 2.42 102 Exp 3 1.80 9. 4 9.68 102 Which of the following is a correct rate law for the reaction? 1. rate = k [H2 O]1/2 [CO2 ] correct 2. Use the Haber process to manufacture NH3 . 3. Rely on soil bacteria. 4. Rely on atmospheric reactions caused by lightning. Explanation: A catalytic converter actually takes xed oxidized nitrogen species and reduces them to to N2 . 040 6.0 points If the reduction of uorine gas to uoride ion were used as the reference electrode for determining the standard reduction potentials of half reactions, what would be the standard reduction potential of the hydrogen electrode? The reactions are: F2 (g) + 2e 2F 2. rate = k [H2 O]1/2 2H+ + 2e H2 (g) 3. rate = k [CO2 ] 1. -3.04 V 2 4. rate = k [H2 O] [CO2 ] 2. 3.04 V 5. rate = k [H2 O] [CO2 ] 3. 0 C Explanation: rate1 [CO2 ]1 = rate2 [CO2 ]2 x 2 9. 4 4.84 10 = 2.42 102 4. 7 x=1 [H2 O]3 rate3 = rate1 [H2 O]1 2 1. 8 9.68 10 = 2 4.84 10 0.45 y = 1/2 4. -2.87 V correct 5. 2.87 V y Explanation: Using the uorine electrode instead of the hydrogen electrode, i.e. dening the uorine electrode as zero, would result in the standard reduction potentials of all other half reactions decreasing by 2.87 volts. The hydrogen electrode normally having a standard reduction potential of 0 volts would then have -2.87 volts instead.
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University of Texas - MATH - 305G
Version 208 Final rev2 laude (51635)This print-out should have 60 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001 5.0 pointsConsider the irreversible reaction13. I, II, III4. III only
University of Texas - MATH - 305G
Version 298 Final rev2 laude (51635)This print-out should have 60 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.13. III only4. I, II, III5. II, III001 5.0 pointsThe phase diagram for CO
University of Texas - MATH - 305G
Version PREVIEW HW 01 homan (57225)This print-out should have 9 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1which of the following could be the graph ofy = f (x + 2) 2 ?1.FuncPcwise01
University of Texas - MATH - 305G
Version PREVIEW HW 06 homan (57225)This print-out should have 12 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.3/21.dy3x=dx5y2.5dy= (xy )1/2dx33.dy5y=dx3xxy + 5x + 3x2 = 4
University of Texas - MATH - 305G
mandel (tgm245) HW11 Radin (56470)This print-out should have 17 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001143.210.0 points42242424242If f is a function on (4, 4) havi
University of Texas - MATH - 305G
mandel (tgm245) HW12 Radin (56470)This print-out should have 15 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.with C an arbitrary constant.00210.0 pointsFind the value of f (0) when10.0
University of Texas - MATH - 305G
mandel (tgm245) HW12 Radin (56470)This print-out should have 15 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1. f (0) = 32. f (0) = 13. f (0) = 210.0 points0011Find all functions g su
University of Texas - MATH - 305G
mandel (tgm245) HW13 Radin (56470)This print-out should have 20 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsA. False.B. False (f could be constant).C. True.002Consider
University of Texas - MATH - 305G
Version PREVIEW HW 13 homan (57225)This print-out should have 14 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.CalC7c44b001 (part 1 of 3) 10.0 points14. cooking time = 46 minutes5. cooki
University of Texas - MATH - 305G
Version PREVIEW HW 13 homan (57225)This print-out should have 14 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.CalC7c44b001 (part 1 of 3) 10.0 pointsJane wishes to bake an apple pie for de
University of Texas - MATH - 305G
mandel (tgm245) HW14 Radin (56470)This print-out should have 23 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001Rewrite5. x2 = 7Explanation:By exponentiation to the base 3,10.0 points
University of Texas - MATH - 305G
Version PREVIEW HW 14 homan (57225)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.5. limit = 2 correct6. limit =CalC7g04a001 10.0 pointsWhen f, g, F and G are
University of Texas - MATH - 305G
Version PREVIEW HW 14 homan (57225)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.CalC7g04a001 10.0 points1Determine the value oflimx0f ( x)g ( x)whenf (
University of Texas - MATH - 305G
mandel (tgm245) HW15 Radin (56470)This print-out should have 15 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001Find the value of f (1) when1f (x) = 2 tan1. f (1) =2x.4. limit =36
University of Texas - MATH - 305G
Version 079 Make up 1 laude (51635)This print-out should have 30 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.Constants R = 8.314 JK1 mol1[C]c[D]d[A]a [B]bG H TSQDenitionsKw [H+ ][OH
University of Texas - MATH - 305G
Version 139 Make up 2 laude (51635)This print-out should have 20 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001 6.0 pointsHint: You need to do the RICE diagram forthis one. The ratio of
University of Texas - MATH - 305G
Version 095 Make up Test 3 laude (50995)This print-out should have 30 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0016.0 pointsYou set up a bomb calorimetry experiment using 1 liter of w
University of Texas - MATH - 305G
Version 367 Quiz 1 laude (51635)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1EquationsP2H 11ln=P1RT1 T2 = M RTTb = iKb m
University of Texas - MATH - 305G
Version 180 Quiz 1 Laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.Equations = cp = mv[particle]hcE = h =h=phx p 4K.E. = h 0015.0 points
University of Texas - MATH - 305G
Version 376 Quiz 2 laude (51635)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1Denitions[C]c [D]dQ[A]a [B]bEquationsG = H T SG
University of Texas - MATH - 305G
Version 278 Quiz 2 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1largest to smallest: Cl , K+ , Ca2+ , Ar, S2 .1. Ar, K+ , Ca2+ , S2 , Cl2. Ca2+
University of Texas - MATH - 305G
Version 126 Quiz 3 laude (51635)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0015.0 points200 mL of a 2 M solution of sodium chlorite(NaClO2) is titrated wit
University of Texas - MATH - 305G
Version 350 Quiz 3 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001 5.0 pointsPredict the electron arrangement in IF+ .411. 2; 6.2. 6; 0.3. 6
University of Texas - MATH - 305G
Version 340 Quiz 4 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001 5.0 pointsRank the following gases in terms of decreasing ideality: Cl2 , H2,
University of Texas - MATH - 305G
Version 445 Quiz 4 laude (51635)1This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.pH=8 means that pOH=6 and [OH ]=106Ksp = [Zn2+ ][OH ]2 (solve for Zn2+ )[Zn2+ ]
University of Texas - MATH - 305G
Version 483 Quiz 5 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1RT 2.5 kJ mol1(at STP)H f productsH fproducts5.
University of Texas - MATH - 305G
Version 081 Quiz 6 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1= k NAk = 1.381 1023 J K112. I only3. II only4.
University of Texas - MATH - 305G
to (aqt73) Section 2.2 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0013. limit = 34. limit does not exist5. limit = 410.0 pointsDetermine
University of Texas - MATH - 305G
to (aqt73) Section 2.3 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsDetermine the value of2 f ( x) g ( x)2 f ( x) 5 g ( x)Det
University of Texas - MATH - 305G
to (aqt73) Section 3.1 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 points14. y + 7x + 1 = 05. y + 7x + 3 = 06. y 7x + 3 = 0Consid
University of Texas - MATH - 305G
to (aqt73) Section 3.3 isaacson (55826)This print-out should have 7 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the value of f (a) whenf ( t) =1. f (a) =Find the x-
University of Texas - MATH - 305G
troyer (lmt836) Section 3.3 isaacson (55826)This print-out should have 7 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsButcfw_2(a + h) + 3(a + 5)= 2h(a + 5) + (2a + 3)(a +
University of Texas - MATH - 305G
to (aqt73) Section 3.4 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1Find the derivative off ( x) =cos x.5x 4 sin x1. f (x) =4 + 5(x cos
University of Texas - MATH - 305G
troyer (lmt836) Section 3.4 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the derivative of g wheng (x) = x3 cos x .4. x-i
University of Texas - MATH - 305G
to (aqt73) Section 3.5 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the derivative off (x) = 3x sin 2x +3cos 2x .22. f
University of Texas - MATH - 305G
troyer (lmt836) Section 3.5 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0014. f (x) =5. f (x) =10.0 points6. f (x) =Find the derivative of
University of Texas - MATH - 305G
to (aqt73) Section 3.5 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0014. f (x) =5. f (x) =10.0 points6. f (x) =Find the derivative off (x
University of Texas - MATH - 305G
troyer (lmt836) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001003Findxy + 3x + 4x2 = 1 .10.0 pointsdywhendxtan(xy ) = 2x y
University of Texas - MATH - 305G
to (aqt73) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001xy + 3x + 4x2 = 5 .2. y =y + 3 + 8xxy + 3 + 4xx3. y = y + 3 + 8x
University of Texas - MATH - 305G
troyer (lmt836) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.3.dydx4.dydx(4, 1)5.dydx(4, 1)6.xy + 3x + 4x2 = 1 .y + 3 +
University of Texas - MATH - 305G
to (aqt73) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1.dydx2.dydx3.dydx(5, 1)4.dydx(5, 1)y + 3 + 8xx5.dydx(5,
University of Texas - MATH - 305G
to (aqt73) Section 3.7 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsA storm system is headed towards Austin.The Weather Service
University of Texas - MATH - 305G
to (aqt73) Section 3.8 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001In the right-angled triangle10.0 points1. speed = 24 sq. ft/sec2. spe
University of Texas - MATH - 305G
to (aqt73) Section 3.8 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0011the base of the pole when he is 14 feet fromthe pole?1. tip speed =
University of Texas - MATH - 305G
to (aqt73) Section 3.9 isaacson (55826)This print-out should have 3 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001002110.0 pointsFind the dierential, dy , ofy = f (x) = tan(4x2 ) .1
University of Texas - MATH - 305G
to (aqt73) Section 4.1 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 points7. x = 55, 0,66 28. x = ,33003Find all the critic
University of Texas - MATH - 305G
to (aqt73) Section 4.1 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind all the critical points of f whenf ( x) =x2x.+ 25
University of Texas - MATH - 305G
to (aqt73) Section 4.2 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsHow many real roots does the equationx5 + 5 x + 8 = 0have?
University of Texas - MATH - 305G
troyer (lmt836) Section 4.2 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsHow many real roots does the equationx5 + 2 x + 6 = 0
University of Texas - MATH - 305G
troyer (lmt836) Section 4.3 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001002110.0 pointsUse the graph10.0 pointsThe derivative of a fun
University of Texas - MATH - 305G
to (aqt73) Section 4.4 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsDetermine if the limit2x + 1lim2 3x + 2x xexists, and i
University of Texas - MATH - 305G
to (aqt73) Section 4.5 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001143.210.0 points42242424242If f is a function on (4, 4)
University of Texas - MATH - 305G
to (aqt73) Section 4.7 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsA rectangular dog pound with three kennelsas shown in the g
University of Texas - MATH - 305G
to (aqt73) Section 4.9 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00112. F (x) = 7 sin x + 9 cos x + C3. none of these10.0 pointsFind the
University of Texas - MATH - 305G
to (aqt73) Section 7.1 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFive functions are dened by the tablex123456f ( x)3
University of Texas - MATH - 305G
to (aqt73) Section 7.3 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the value of x when1x = 6 log2+ 9 log3 27 .82. ln
University of Texas - MATH - 305G
to (aqt73) Section 7.4 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001Find the derivative off (x) = ln10.0 points1. f (x) = Find the deriv
University of Texas - MATH - 305G
to (aqt73) Section 7.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsf (x) = 5 sin1 x + tan1 x .742. f (1) =1543. f (1) =1
University of Texas - MATH - 305G
to (aqt73) Section 7.8 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0014. A and B only5. B only10.0 points6. A onlyDetermine ifx3 + 6 x2 +
University of Texas - MATH - 305G
CH301Worksheet 0Doing Math Without a Calculator(Hint: It is amazing how much math you can do with a pencil and paper, like long division!, or, moreimportant, by estimating and approximating. For example, watch an experimental scientist at work using jus
University of Texas - MATH - 305G
CH301 Fall 2009 Worksheet 21. Calculate wavelength from the following frequencies.a) 625 kHzb) 734 MHzc) 8.4 E14 Hzd) 92 GHz2. Given the following energies, calculate the frequencies of the photons.a) 17 kJb) 564 E-25 Jc) 98 pJd) 230 J3. Rank t