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9 Pages

Make up Test 3-solutions

Course: MATH 305G, Spring 2011
School: University of Texas
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Word Count: 3182

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095 Version Make up Test 3 laude (50995) This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 6.0 points You set up a bomb calorimetry experiment using 1 liter of water as your heat sink and combusting a 4.409 g sample of propane (C3 H8 ). If the initial and nal temperature are 24.90 C and 77.96 C respectively, what...

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095 Version Make up Test 3 laude (50995) This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 6.0 points You set up a bomb calorimetry experiment using 1 liter of water as your heat sink and combusting a 4.409 g sample of propane (C3 H8 ). If the initial and nal temperature are 24.90 C and 77.96 C respectively, what is the molar enthalpy of combustion of ethene? (Assume the calorimeter itself absorbs no heat. Assume the density of water is 1 g mL) 1. 222.0 kJ mol1 2. 22, 200 kJ mol1 3. 22.20 kJ mol1 4. 2, 220 kJ mol1 correct 5. 222, 000 kJ mol1 Explanation: T = Tf Ti = 77.96 C 24.90 C = 53.06 C = 53.06 K 1000 mL 1.00 g = 1000 g L mL 1mol n = 4.409 g propane = 0.1 mol 44.09 g propane m=1L Hcal mcT Hrxn = = n n n 4.184 J 1000 g gK 53.06 K = 0.1 mol = 2, 220 kJ mol 002 1 1 G if it is performed under standard conrxn ditions. H f S kJ J species ( mol ) ( molK ) HNO3 () NO2 (g) HNO3 () H2 (g) 285.8 33.2 174.1 0 70 240 156 131 1. 85 kJ mol1 2. 6, 200 kJ mol1 3. 85 kJ mol1 correct 4. 6, 200 kJ mol1 Explanation: Hrxn = Hf,products Hf,reactants = (285.8 kJ mol1 + 33.2 kJ mol1 )(174.1 kJ mol1 )= 78.5 kJ mol1 Srxn = Sm,products Sm,reactants = (70 J mol1 K1 + 1 1 1 1 240 J mol K )(156 J mol K + 131 J mol1 K1 )= 23 J mol1 K1 = 0.023 kJ mol1 K1 G = rxn Hrxn T Srxn = 78.5 kJ mol1 (273 K)(0.023 kJ mol1 K1 )= 85 kJ mol1 003 6.0 points What is the change in entropy for iodine melting? The standard molar entropy for I2 (s) and I2 () are 116.14 J mol1 K1 and 260.69 J mol1 K1 , respectively. 1. 376.83 J mol1 K1 2. 144.55 J mol1 K1 6.0 points 3. 376.83 J mol1 K1 Consider the reaction below: HNO3 () + H2 (g) H2 O() + NO2 (g) Using the provided table values, calculate 4. 144.55 J mol1 K1 correct Explanation: The change in entropy for condensation Version 095 Make up Test 3 laude (50995) of water can be described by the equation I2 (s) I2 (). Smelting = Sm,liquid Sm,solid = 260.69 J mol1 K1 116.14 J mol1 K1 = 144.55 J mol1 K1 004 6.0 points Ammonia (the common name for NH3 , the odor of windex and cat urine), has a Hvap = 23.35 kJ mol1 and a Svap = 97.43 J mol1 K1 . What is the normal boiling point of ammonia expressed in centigrade? 1. 273 C 2. 0.2 C 3. 238.7 C 2 2. 1, 124 kJ mol1 correct 3. 1, 124 kJ mol1 4. 562 kJ mol1 Explanation: Hrxn = Hf,products Hf,reactants = (2 20.63 kJ mol1 + 3 0) (2 285.83 kJ mol1 +2 296.83 kJ mol1 )= 1, 124 kJ mol1 006 6.0 points Which of the following statements is/are true concerning the rst law of thermodynamics? I) The internal energy (U ) of the universe is conserved. II) The internal energy of a system plus that of its surroundings is conserved. III) The change in internal energy (U ) of a system and its surroundings can have the same sign. 4. 33.3 C correct Explanation: Because boiling is an equilibrium process, G = 0 = Hvap T Svap . vap And so T Svap = Hvap and T = Hvap /Svap = 23, 350J mol1 /97.43 J mol1 K1 = 238.7 K = 33.3 C 005 6.0 points Based on enthalpy of formation data calculate Hrxn for the following: 2H2 O() + 2SO2 (g) 2H2 S(g) + 3O2 (g) species H f kJ ( mol ) H2 S(g) O2 (g) H2 O() SO2 (g) 20.63 0 285.83 296.83 1. 562 kJ mol1 1. I, III 2. II only 3. II, III 4. I only 5. I, II, III 6. I, II correct 7. III only Explanation: Statement I and II are true; the rst law states that the internal energy of the universe is conserved and since the system plus the surroundings is the universe, their sum is also conserved. Statement III is false; for example, if both the system and its surroundings had a positive change in internal energy, then the internal energy of the universe would have increased or decreasesed - in violation of the rst law. Version 095 Make up Test 3 laude (50995) 3 1. d < a < b < c 007 6.0 points 2. c < d < b < a Which of the following compounds is unstable under standard conditions? I) C8 H18 () II) H2 S(aq ) III) SF6 (g ) species C8 H18 () H2 S(aq ) SF6 (g ) G f kJ ( mol ) 6. 4 27.8 1105.3 1. I correct 2. I, II, III 3. I, II 4. III 5. II 3. a < c < b < d 4. b < c < d < a 5. d < b < a < c 6. c < b < d < a correct Explanation: Reaction c has a substantial decrease both in total moles and especially in moles of gas; Srxn will likely be a large negative number. Reaction b has no change in total moles, but does form a solid from a pair of aqueous species; Srxn will likely be a small negative number. Reaction d has no change in total moles or moles of gas; Srxn will be close to zero. Reaction a produces more total moles, and importantly evolves a gas; Srxn will likely be a large positive number. 009 6. II, III 7. All compounds are stable 8. I, III 6.0 points Which of the following reactions is an enthalpy of formation reaction 1. CH4 (g) Cgraphite + 2 H2(g) Explanation: Examine the standard free energies of formation of the compounds. Compounds with a negative free energy of formation are stable, whereas those with a positive free energy are unstable with respect to the elements that compose them. 008 6.0 points Rank the following reactions from most negative to most positive in terms of change in entropy (Srxn ): a) CaCO3 (s) CaO(s) + CO2 (g) b) AgNO3 (aq) + NaCl(aq) NaNO3 (aq) + AgCl(s) c) 4Fe(s) + 3O2 (g) 2Fe2 O3 (s) d) CH4 (g) + 2O2 (g) CO2 (g) + 2H2 O(g) 2. 2 Fe(s) + 3 O2 (g) Fe2 O3 (s) correct 2 3. NaOH(aq) + HCl(g) H2 O() + NaCl(aq) 3 1 N2 () + H2 (g) NH3 (g) 2 2 Explanation: Formation reactions describe production of exactly one mole of one product from stoichiometric quantities of elements in their standard states. 4. 010 6.0 points Which of the following is not a denition of enthalpy or change in enthalpy? 1. A state function that inuences the spon- Version 095 Make up Test 3 laude (50995) taneity of a reaction. 2. H = Hf inal Hinitial 3. H = U + P V 4. The heat transfer at constant volume. correct Explanation: The heat transfer at constant volume is equal to the change in internal energy, not the change in enthalpy. The other choices are all mathematical identities relating to enthalpy or change in enthalpy or prose restatements of these mathematical identities. 011 Ethane is C2 H6 . below: 6.0 points Consider the reaction C2 H6 (g) 2Cgraphite (s) + 3H2 (g) For a given reaction, if Hrxn is (neg ative/positive/either) and Srxn is (negative/positive/either), then the value of G rxn will always be negative, regardless of the temperature. 1. either, negative 2. either, positive 3. negative, positive correct 4. negative, either 5. positive, negative 6. positive, either Explanation: This can be intuited from the G = H T S formula. In order for G to always rxn be negative, Hrxn must always be negative and Srxn must always be positive. G = 7.86 kJ mol1 rxn The (formation/decomposition) of octane is (spontaneous/non-spontaneous) and therefore octane is (stable/unstable). 1. decomposition, non-spontaneous, stable correct 4 013 6.0 points Consider the reaction below and approximate the value of the work function at room temperature. C2 H4 (g) + 3O2 (g) 2CO2 (g) + 2H2 O() 2. formation, spontaneous, unstable 3. formation, non-spontaneous, unstable 1. 5 kJ 4. formation, non-spontaneous, stable 2. 2.5 kJ 5. decomposition, non-spontaneous, unstable Explanation: The reaction written above describes the decomposition of ethane and has a positive change in Gibbs free energy, i.e. is nonspontaneous, meaning octane must be thermodynamically stable. 012 6.0 points 3. 5 kJ correct 4. 0 kJ 5. 2.5 kJ Explanation: At room temperature ( 300 K), the product of the RT term in w = ngas RT is approximately 2.5 kJ. Since ngas is 2 for this reaction, the work function is approximately 5 kJ. Version 095 Make up Test 3 laude (50995) 014 6.0 points If an MP3 player does 500 kJ of work and releases 100 kJ of heat, what is the change in internal energy for the MP3 player? 1. 400 kJ 2. 400 kJ 3. 600 kJ correct 5 When calculating the maximum positional entropy of a system at absolute zero using the Boltzmann formula (S = k ln W ), which of the following statements is/are true? I) For a given compound, a 1 mol has a maximum positional entropy roughly 6.022 1023 times that of 1 molecule. II) The minimum value that W can have is 1. III) For the same number of molecules, the experimental value of W for NO is less than the experimental value for CO. 1. I, III 4. 600 kJ Explanation: U = q + w 2. I, II, III correct 3. II only = 500 kJ + 100 kJ = 600 kJ 4. II, III 015 points Which 6.0 of the following statements concerning calorimetry is/are true? I) Bomb calorimeters hold the volume of the system constant. II) In real calorimetry experiments, the calorimeter itself absorbs heat. III) H = q in a bomb calorimeter. 1. III only 2. I, II, III 3. I, III 4. I, II correct 5. II, III 6. II only 5. I, II 6. III only 7. I only Explanation: Statement I is true; when the exponent of the W term is some multiple of Avogadros number, it can be factored out and moved to the front of the expression, serving as a coecient. Statement II true; the natural log of a value less than one would result in a negative value for entropy, which would violate the third law. Statement III is true; both molecules have 2 orientations in theory, but both have IMF which will perturb this value toward 1, more so for NO because it has stronger IMF. 017 7. I only Explanation: Statements I and II are true. Statement II is falsewhen the volume is constant, the change in internal energy is equal to heat, not the change in enthalpy. 016 6.0 points 6.0 points Rank the following compounds by molar entropy, from least to greatest: O2 (), O2(g), O3 (g), O2(s). 1. O3 (g) < O2 () < O2 (s) < O2 (g) 2. O2 (s) < O2 () < O3 (g) < O2 (g) Version 095 Make up Test 3 laude (50995) 3. O3 (g) < O2 (s) < O2 () < O2 (g) 4. O2 (g) < O2 () < O2 (s) < O3 (g) 5. O2 (s) < O2 () < O2 (g) < O3 (g) correct Explanation: The three phases of O2 can be easily ranked, since phase changes have very predictable effects on molar entropy, typically increasing signicantly going from solid to liquid and again from liquid to gas. Comparing O2 (g) to O3 (g), simply require comparing number of bonds, with O3 (g) having greater molar entropy because it has more bonds. 018 6.0 points Given the data H2 SO4 () H2 S(g) + 2 O2 (g) H = +793 kJ mol1 H2 O(g) + SO3 (g) H2 SO4 () H = 176 kJ mol1 H2 O() + SO3 (g) H2 S(g) + 2 O2 (g) H = +661 kJ mol1 calculate H for the reaction 019 6 6.0 points If a system absorbs 545 J of heat from the surroundings at 272 C, what is change in entropy of the surroundings? 1. 545 J K1 correct 2. 2 J K1 3. 2 J K1 4. 545 J K1 Explanation: Heat absorbed by something which is always near equilibrium at constant temperature will increase its entropy by an amount equal to q/T . For most situations we consider, the surroundings can be assumed to meet this criterion, but the systems we consider usually do not. In this case 545J/1K = 545 J K1 . 020 H2 O() H2 O(g) 6.0 points How much energy would be associated with the rotational motion of 0.75 moles of N2 ? 1. 214 kJ mol1 2. 1278 kJ mol1 1. 2RT 3. 1278 kJ mol1 2. 2kT 4. 41 kJ mol1 3. 0.75kT 5. 41 kJ mol1 correct 4. 0.37kT Explanation: The rst two reactions need to be reversed: H2 SO4 () H2 S(g) + 2 O2 (g) H = 793 kJ mol1 H2 O(g) + SO3 (g) H2 SO4 () H = +176 kJ mol1 H2 O() + SO3 (g) H2 S(g) + 2 O2 (g) H = +661 kJ mol1 Hrxn = 44 kJ mol1 5. 0.37RT 6. 0.75RT correct Explanation: The energy associated with any motional mode is 0.5kT , which when multiplied by 2 rotational modes (N2 is linear) and 0.75 moles (i.e. 0.5 times Avogadros number), results in 0.75RT . Version 095 Make up Test 3 laude (50995) 021 6.0 points Assuming you have 1 mol of each of the following, rank them by the value of the term W in the Boltzmann equation, from greatest to least: HCl, HBr, HF. 7 II) 3CO2 (g) + 4H2 O(g) C3 H8 (g) + 5O2 III) 3Cgraphite + 4H2 (g) C3 H8 (g) 1. I only 2. I, III 3. III only 1. HCl > HF > HBr 4. II only 2. HF > HBr > HCl 5. none of the above correct 3. HBr > HF > HCl 6. I, II 4. HCl > HBr > HF correct Explanation: Since the strength of the IMF determines the extent of the perturbation of W from its ideal value, this problem essentially requires ranking by increasing IMF. The greater the IMF, the closer the value will be to unity. 022 6.0 points Which of the following is not a denition of internal energy or change in internal energy? 1. The change in enthalpy after correction for P V work. 2. The dierence between the nal and initial internal energy of a system. 3. The heat transferred at constant pressure. correct 4. U = q + w Explanation: All of the reactions consume gas, or have fewer mols of products than reactants, suggesting they all have a negative value for change in entropy and thus would become less spontaneous as the temperature increases. 024 6.0 points Which of the following statements concerning the second and third laws of thermodynamics is/are true? I) Gsystem /T = Suniverse II) In a perfect, pure crystal at absolute zero, entropy would be a small negative value. III) The entropy of the universe is always increasing. 1. I only 2. II only Explanation: Internal energy is not equal to heat at constant pressure. The other statements are all mathematical identities describing internal energy or prose restatements of the same. 023 7. II, III 6.0 points Which of the following reactions will likely become more spontaneous as you raise temperature? I) CO(g) + H2 (g) CH2 O() 3. III only correct 4. I, III 5. I, II 6. I, II, III 7. II, III Explanation: Statement I is false; Gsystem/T = Version 095 Make up Test 3 laude (50995) Suniverse . Statement II is false; the third law states that as the temperature of a system approaches absolute zero, the entropy of thee system approaches its minimum, which in the case of a perfect crystalline solid, is zero - moreover, entropy can never have a negative value. Statement III is true; the second law of thermodynamics states that the entropy of the universe is always increasing. 025 6.0 points Which if the following phrases corresponds to a positive change in a state function? I) non-spontaneous II) exothermic III) an increase in disorder 8 Explanation: Work quantitatively describes a transition between states and is thus a process quantity (path function), not a state function. 027 6.0 points Calculate Suniverse for the condensation of heavy water (D2 O) at 95 C if the Sm for D2 O(g) and D2 O() are 198 J mol1 K1 and 76 J mol1 K1 , respectively. Assume the standard boiling point of heavy water is 101 C and that Hsystem = 45.6 kJ mol1 . 1. 122 J mol1 K1 1. I, II 2. 124 J mol1 K1 2. I only 3. 122 J mol1 K1 3. II, III 4. 2 J mol1 K1 correct 4. I, II, III 5. 2 J mol1 K1 5. III only 6. 124 J mol1 K1 6. II only 7. I, III correct Explanation: Sign conventions dictate that an endothermic process has a positive change in gibbs free energy, that exothermic processes have a negative value for change in enthalpy, and that an increase entropy is positive. 026 6.0 points Which of the following is a not state function? 1. internal energy 2. temperature 3. enthalpy 4. Gibbs free energy 5. work correct Explanation: Since the system in this case is condensing heavy water, D2 O(g) D2 O() Ssystem = Sm,products Sm,reactants = 76 J mol1 K1 198 J mol1 K1 = 122 J mol1 K1 Hsystem = T Ssystem = 374 K 122 J mol1 K1 = 45, 628 J mol1 Since the only process during a phase change is heat exchange, Ssurroundings = Hsystem/Tsurroundings = 45, 628 J mol1 /368 K = 123.98 J mol1 K1 Suniverse = Ssystem + Ssurroundings = 122 J mol1 K1 + 124 J mol1 K1 = 2 J mol1 K1 Version 095 Make up Test 3 laude (50995) 9 (2)(743 kJ mol1 ) + (2)(2)(463 kJ mol1 ) 028 6.0 points What is the maximum positional entropy of 3 mol of CHCl3 at absolute zero? 030 6.0 points Which of the following would require the most energy to raise its temperature by 1 K? 1. 11.53 J K1 2. 5.74 1023 J K1 1. 10 grams of water correct 3. 34.58 J K1 correct 2. 1 gram of water 4. 1.91 1023 J K1 Explanation: CHCl3 has 4 possible orientations. k ln(4n ) = 3R ln 4 = 34.58 J K1 029 3. 1 0 grams of iron metal S= 6.0 points Using bond enthalpy data, calculate the change in enthalpy for the following reaction. CH4 (g) + 2O2 (g) CO2 (g) + 2H2 O(g) bond C O C O Bond enthalpy (kJ mol1) H O O H = 698 kJ mol1 412 496 743 463 1. 698 kJ mol1 correct 2. 203 kJ mol1 3. 1420 kJ mol1 4. 203 kJ mol1 5. 1420 kJ mol1 6. 698 kJ mol1 Explanation: Hrxn = BEreactants BEproducts = (4)(412 kJ mol1 ) + (2)(496 kJ mol1 ) 4. 1 gram of iron metal Explanation: Heat capacity is an extensive property, that reects the amount of energy required to raise the temperature of an object. Because water has a much higher heat capacity than metals (to some extent a consequence of stronger IMF), and because 10 grams is more than 1 gram, the 10 gram smaple of water would require the greatest amount of enegy to raise its temperature by 1 K.
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University of Texas - MATH - 305G
Version 367 Quiz 1 laude (51635)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1EquationsP2H 11ln=P1RT1 T2 = M RTTb = iKb m
University of Texas - MATH - 305G
Version 180 Quiz 1 Laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.Equations = cp = mv[particle]hcE = h =h=phx p 4K.E. = h 0015.0 points
University of Texas - MATH - 305G
Version 376 Quiz 2 laude (51635)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1Denitions[C]c [D]dQ[A]a [B]bEquationsG = H T SG
University of Texas - MATH - 305G
Version 278 Quiz 2 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1largest to smallest: Cl , K+ , Ca2+ , Ar, S2 .1. Ar, K+ , Ca2+ , S2 , Cl2. Ca2+
University of Texas - MATH - 305G
Version 126 Quiz 3 laude (51635)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0015.0 points200 mL of a 2 M solution of sodium chlorite(NaClO2) is titrated wit
University of Texas - MATH - 305G
Version 350 Quiz 3 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001 5.0 pointsPredict the electron arrangement in IF+ .411. 2; 6.2. 6; 0.3. 6
University of Texas - MATH - 305G
Version 340 Quiz 4 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001 5.0 pointsRank the following gases in terms of decreasing ideality: Cl2 , H2,
University of Texas - MATH - 305G
Version 445 Quiz 4 laude (51635)1This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.pH=8 means that pOH=6 and [OH ]=106Ksp = [Zn2+ ][OH ]2 (solve for Zn2+ )[Zn2+ ]
University of Texas - MATH - 305G
Version 483 Quiz 5 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1RT 2.5 kJ mol1(at STP)H f productsH fproducts5.
University of Texas - MATH - 305G
Version 081 Quiz 6 laude (50995)This print-out should have 8 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.ConstantsR = 8.314 J K1 mol1= k NAk = 1.381 1023 J K112. I only3. II only4.
University of Texas - MATH - 305G
to (aqt73) Section 2.2 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0013. limit = 34. limit does not exist5. limit = 410.0 pointsDetermine
University of Texas - MATH - 305G
to (aqt73) Section 2.3 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsDetermine the value of2 f ( x) g ( x)2 f ( x) 5 g ( x)Det
University of Texas - MATH - 305G
to (aqt73) Section 3.1 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 points14. y + 7x + 1 = 05. y + 7x + 3 = 06. y 7x + 3 = 0Consid
University of Texas - MATH - 305G
to (aqt73) Section 3.3 isaacson (55826)This print-out should have 7 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the value of f (a) whenf ( t) =1. f (a) =Find the x-
University of Texas - MATH - 305G
troyer (lmt836) Section 3.3 isaacson (55826)This print-out should have 7 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsButcfw_2(a + h) + 3(a + 5)= 2h(a + 5) + (2a + 3)(a +
University of Texas - MATH - 305G
to (aqt73) Section 3.4 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1Find the derivative off ( x) =cos x.5x 4 sin x1. f (x) =4 + 5(x cos
University of Texas - MATH - 305G
troyer (lmt836) Section 3.4 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the derivative of g wheng (x) = x3 cos x .4. x-i
University of Texas - MATH - 305G
to (aqt73) Section 3.5 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the derivative off (x) = 3x sin 2x +3cos 2x .22. f
University of Texas - MATH - 305G
troyer (lmt836) Section 3.5 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0014. f (x) =5. f (x) =10.0 points6. f (x) =Find the derivative of
University of Texas - MATH - 305G
to (aqt73) Section 3.5 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0014. f (x) =5. f (x) =10.0 points6. f (x) =Find the derivative off (x
University of Texas - MATH - 305G
troyer (lmt836) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001003Findxy + 3x + 4x2 = 1 .10.0 pointsdywhendxtan(xy ) = 2x y
University of Texas - MATH - 305G
to (aqt73) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001xy + 3x + 4x2 = 5 .2. y =y + 3 + 8xxy + 3 + 4xx3. y = y + 3 + 8x
University of Texas - MATH - 305G
troyer (lmt836) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.3.dydx4.dydx(4, 1)5.dydx(4, 1)6.xy + 3x + 4x2 = 1 .y + 3 +
University of Texas - MATH - 305G
to (aqt73) Section 3.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.1.dydx2.dydx3.dydx(5, 1)4.dydx(5, 1)y + 3 + 8xx5.dydx(5,
University of Texas - MATH - 305G
to (aqt73) Section 3.7 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsA storm system is headed towards Austin.The Weather Service
University of Texas - MATH - 305G
to (aqt73) Section 3.8 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001In the right-angled triangle10.0 points1. speed = 24 sq. ft/sec2. spe
University of Texas - MATH - 305G
to (aqt73) Section 3.8 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0011the base of the pole when he is 14 feet fromthe pole?1. tip speed =
University of Texas - MATH - 305G
to (aqt73) Section 3.9 isaacson (55826)This print-out should have 3 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001002110.0 pointsFind the dierential, dy , ofy = f (x) = tan(4x2 ) .1
University of Texas - MATH - 305G
to (aqt73) Section 4.1 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 points7. x = 55, 0,66 28. x = ,33003Find all the critic
University of Texas - MATH - 305G
to (aqt73) Section 4.1 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind all the critical points of f whenf ( x) =x2x.+ 25
University of Texas - MATH - 305G
to (aqt73) Section 4.2 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsHow many real roots does the equationx5 + 5 x + 8 = 0have?
University of Texas - MATH - 305G
troyer (lmt836) Section 4.2 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsHow many real roots does the equationx5 + 2 x + 6 = 0
University of Texas - MATH - 305G
troyer (lmt836) Section 4.3 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001002110.0 pointsUse the graph10.0 pointsThe derivative of a fun
University of Texas - MATH - 305G
to (aqt73) Section 4.4 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsDetermine if the limit2x + 1lim2 3x + 2x xexists, and i
University of Texas - MATH - 305G
to (aqt73) Section 4.5 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001143.210.0 points42242424242If f is a function on (4, 4)
University of Texas - MATH - 305G
to (aqt73) Section 4.7 isaacson (55826)This print-out should have 4 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsA rectangular dog pound with three kennelsas shown in the g
University of Texas - MATH - 305G
to (aqt73) Section 4.9 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00112. F (x) = 7 sin x + 9 cos x + C3. none of these10.0 pointsFind the
University of Texas - MATH - 305G
to (aqt73) Section 7.1 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFive functions are dened by the tablex123456f ( x)3
University of Texas - MATH - 305G
to (aqt73) Section 7.3 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsFind the value of x when1x = 6 log2+ 9 log3 27 .82. ln
University of Texas - MATH - 305G
to (aqt73) Section 7.4 isaacson (55826)This print-out should have 5 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.001Find the derivative off (x) = ln10.0 points1. f (x) = Find the deriv
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to (aqt73) Section 7.6 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.00110.0 pointsf (x) = 5 sin1 x + tan1 x .742. f (1) =1543. f (1) =1
University of Texas - MATH - 305G
to (aqt73) Section 7.8 isaacson (55826)This print-out should have 6 questions.Multiple-choice questions may continue onthe next column or page nd all choicesbefore answering.0014. A and B only5. B only10.0 points6. A onlyDetermine ifx3 + 6 x2 +
University of Texas - MATH - 305G
CH301Worksheet 0Doing Math Without a Calculator(Hint: It is amazing how much math you can do with a pencil and paper, like long division!, or, moreimportant, by estimating and approximating. For example, watch an experimental scientist at work using jus
University of Texas - MATH - 305G
CH301 Fall 2009 Worksheet 21. Calculate wavelength from the following frequencies.a) 625 kHzb) 734 MHzc) 8.4 E14 Hzd) 92 GHz2. Given the following energies, calculate the frequencies of the photons.a) 17 kJb) 564 E-25 Jc) 98 pJd) 230 J3. Rank t
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CH301 Fall 2010 Worksheet 2: From EMR to QM to EC and Beyond1. Relate Electromagnetic radiation to physical phenomenaGamma rays, X-rays, UV, Visible, infrared, microwave, radio, televisionphenomenonElectromagnetic radiationCooks food by heating water
University of Texas - MATH - 305G
CH301 Fall 2010 Worksheet 2: From EMR to QM to EC and BeyondAnswer Key1. Relate Electromagnetic radiation to physical phenomenaGamma rays, X-rays, UV, Visible, infrared, microwave, radio, televisionphenomenonElectromagnetic radiationCooks food by hea
University of Texas - MATH - 305G
CH301 Fall 2009 Worksheet 3 Answer Key on Electronic Configuations and Periodic Table Trends 1. Write the electron configuration of gallium (Ga) in long notation and in short notation. 2 2 6 2 6 2 10 1 1s 2s 2p 3s 3p 4s 3d 4p 2 10 1 [Ar] 4s 3d 4p 2. Write
University of Texas - MATH - 305G
CH301 Fall 2010 Worksheet 3 Answer Key: Electron Configurations and Periodic Trends1. Match the following elements with their corresponding electron configurations2. Write the electron configuration of arsenic (As) in long notation and in short (noble g
University of Texas - MATH - 305G
CH301 Fall 2010Worksheet 4 Answer Key1. For each element below, indicate the ion(s) it is most likely to form.a) Na Na+b) Ca Ca2+c) IrIr+, Ir3+d) Pb Pb2+, Pb4+e) Cl Clf) SS22. Write balanced unit formulas for the salts formed by the following pair
University of Texas - MATH - 305G
CH301 Fall 2010 Worksheet 5 Answer Key: Drawing Lewis Structures1. Draw the Lewis structure of the following compounds:a . NaClb . CaBr2c . K2Sd . Cs3P2. Draw all correct Lewis structures for the following compounds:a . O3b . NO3-c . SO42-d . HP
University of Texas - MATH - 305G
CH302 Worksheet 1 Answer Key for Physical Equilbria Problems from Lectures 1 through 3For Questions 1-4, use the Phase diagram below.1. What is a good general definition of the term triple point? How many triple points are found int hephase diagram for
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CH302 Worksheet 2Colligative PropertiesAll of this is intended to be done without the aid of a calculator. All of the calculations are designed suchthat approximating should be straight-forward and produce a correct result.1. Based on the physical cons
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CH302 Worksheet 2 Colligative PropertiesAll of this is intended to be done without the aid of a calculator. All of the calculations are designed suchthat approximating should be straight-forward and produce a correct result.1. Based on the physical con
University of Texas - MATH - 305G
CH302 Worksheet 3Introduction to Chemical Equilibria1. Write a mass action quotient (aka mass action expression) for the general equation below:aA + bB cC + dD2. What sort of mathematical relationship exists between G and K? Which of these terms shoul
University of Texas - MATH - 305G
CH302 Worksheet 3Introduction to Chemical Equilbria Answer Key1. Write a mass action quotient (aka mass action expression) for the general equation below:aA + bB cC + dDQ = [C]c[D]d / [A]a[B]b2. What sort of mathematical relationship exists between G
Air Force Academy - ECON - 101