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Lecture.Packet.4.Wetting

Course: CEE 440, Spring 2011
School: University of Illinois,...
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INTERFACIAL 3.3 TENSION, CONTACT ANGLE, AND DENSITY Interfacial tension (ab , a is one phase and b is another) can be thought of as the force per unit length (or energy per unit area) acting at a liquidliquid or liquid-solid interface. Interfacial tension - arises because of unbalanced cohesional forces on molecules at the interface. The tension causes the interface between the two fluids to contract and form an...

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INTERFACIAL 3.3 TENSION, CONTACT ANGLE, AND DENSITY Interfacial tension (ab , a is one phase and b is another) can be thought of as the force per unit length (or energy per unit area) acting at a liquidliquid or liquid-solid interface. Interfacial tension - arises because of unbalanced cohesional forces on molecules at the interface. The tension causes the interface between the two fluids to contract and form an area that is as small as possible. If one phase is liquid and the other vapor, then we use the term surface tension denoted by . e.g. CEE 440 Water bugs, rain drops, Goretex, oil slick 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 1 Consider a soap film stretched across a wire frame with one movable side. L The work done in extending the movable member dx is: Work = E = dA= L dx (3.58) E = change in energy = surface tension (force/length = N/m; energy/area = J/m2) L = length (m) dA = change in area (m2) dx = change in length CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 2 Alternatively we could think of an expanding soap bubble: dR R the surface tension of the soap film results in stable, spherical bubble The free energy of the soap bubble surface is initially: Einit = ______ 4 R2 (3.59) If the radius of the soap bubble is increased by dR, then the final free energy is: Efinal = 4 (R+dR)2 CEE 440 (3.60) 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 3 It follows that the change in surface free energy or the work required to expand the soap bubble is: Work = E = Efinal Einit = (4 R2 + 8 R dR + 4 dR2) 4 R2 (3.61) E = 8 R dR + 4 dR2 ~ 8 R dR (3.62) Since increasing the soap bubble radius increases the surface free energy, the tendency to do so must be balanced by a pressure difference across the film P. Hence, fluid on the concave side of the interface (i.e., inside the soap bubble) is at a higher pressure. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 4 The work against this pressure difference is given as follows: Work = E = P * Area * Distance Distance = Rfinal Rinit = R + dR R = dR (3.63) E = P 4 R2 dR (3.64) This work equals the work required to expand the bubble by dR. P 4 R2 dR = 8 R dR (3.65) Rearranging: P = 2 / R (Young-Laplace Equation) (3.66) So as the bubble gets larger the pressure difference decreases and vice versa. This example also demonstrates that interfacial tension results in curved surfaces between phases. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 5 Consider the following configuration: Patm = R3 R2 Valve 1 Valve 2 What happens when valve 1 and valve 2 are opened? R2=R3 R3 Valve 3 P2>P3 so the bubble on the left will stop shrinking when R2=R3 CEE 440 R2 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 6 In general surfaces are not perfectly spherical: R2 R1 As a result, we use the more general form of the Young-Laplace equation: P = (1/R1 + 1/R2) CEE 440 (3.67) 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 7 What about if we have three phases present, say a solid surface, and two fluids, or three immiscible fluids: gas air liquid solid oil water Interfacial tension between the gas-liquid (gl), between the gas-solid (gs), and between the liquid-solid (ls) can cause fluids to form a curved interface with a contact angle () between them. The contact angle indicates which fluid has a higher affinity for the surface. If <90o, liquid wets and has greater affinity for surface (=0o for perfectly liquid wetting) If >90 o, gas wets and has greater affinity for surface (=180o for perfectly gas wetting) CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 8 In some cases the interfacial tensions of the spreading liquid are not great enough to allow a contact angle to form; therefore, the liquid spreads without limit. This can be assessed with the spreading coefficient: Fs = gs - (gl + ls) g=gas, l=liquid, s=solid OR Fs = aw - (ao + ow) (3.68) a=air, o=organic, w=water If Fs>0, the liquid spreads. If Fs<0, the liquid forms a pool. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 9 How would changes in the spreading coefficient affect NAPL migration? As Fs increases there is less residual NAPL, and more free NAPL available for migration ow ao aw pentane hexane heptane octane decane dodecane tetradecane hexadecane 49 51.1 50.2 50.81 52 52.8 52.2 53.3 15.5 18.4 19.66 21.62 23.83 24.91 26.56 26.95 72.21 72.4 72.59 72.66 72.74 72.74 72.7 71.83 halogenated aliphatics carbon tetrachloride bromoform chloroform methylene chloride perchloroethylene trichloroethylene 45 40.85 32.8 28.31 47.48 34.5 27.04 45.53 27.32 27.84 31.74 28.8 72.74 0.7 72.75 -13.63 72.56 12.44 72.12 15.97 72.75 -6.47 72.69 9.39 alkanes Fs 7.71 2.9 2.73 0.23 -3.09 -4.97 -6.06 -8.42 Demond and Lindner, ES&T, 1993 CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 10 The interfacial forces between two fluids and a solid also give rise to a phenomenon known as capillarity. Capillarity causes mercury to rise in a thermometer. gas r Consider a circular capillary tube inserted into liquid: P=0 liq u i d h We want to calculate how far in the tube the liquid will rise. Upward capillary forces exert pressure on the liquid; downward gravity is exerting pressure on the liquid. These two pressures (or forces) must be equal when the liquid interface is static. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 11 gas r P=0 Capillary pressure acting on the liquid is expressed with the Young-Laplace equation: Pc = P = 2 / R = 2 cos () / r liq u i d h (3.69) Gravity pressure acting on the liquid is: P = g h = l g (3.70) = density g= gravity Setting these pressures equal to each other: R r P = Pg Pl = 2 cos / r = g h (3.71) h = 2 cos / (r g) (3.72) cos()=r/R R=r/cos() CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 12 P=0 What happens if we replace the wetting liquid with oil, which has a contact angle greater than 90o with the capillary wall. h = 2 cos / (r g) gas r h liquid What happens if we have a sloped capillary tube shown below: gas r P=0 gas liq u i d + R r h P=0 liq u i d h For the case of a sloped capillary tube we simply include the slope of the wall in the capillary calculations: P = Pg Pl = 2 cos (+) / r = g h CEE 440 (3.73) 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 13 3.4. EXTENDING CAPILLARY PHENOMENON TO NAPL ENTRAPMENT Non-aqueous phase liquids (NAPLs) migrate into the subsurface and move down through the soil matrix toward the water table. As they move through the soil matrix small liquid globules become trapped inside small pore spaces between soil grains and are left behind the main infiltrating mass of NAPL. Migration continues until all NAPL has become trapped, until lighter than water NAPLs (LNAPLs) reach the water table and float, and/or until denser than water NAPLs (DNAPLs) reach an impermeable barrier. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 14 In 1975, Friedrich Schwille at the Bundesanstalt fr Gewsserkunde started with some bench-scale lab experiments to investigate the behavior of chlorinated solvents in the subsurface Dichloromethane released into water saturated glass beads CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 15 Infiltration of chlorinated hydrocarbons into a sandy media <10 min 30 min 1 hour 2 hour Infiltration of 23 liters of PCE (dyed in red) over two hours in a tank with a height of 1.60 m. (simulation of a leaking pipe) Two layers of sand with a K of 8 x 10-4 (m/s) (upper part) and 32 x 10-4 (m/s) (lower part) Experiment by Schwille (1984) CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 16 Water Outlet Inject DNAPL Residual NAPL is trapped in individual pore spaces so the individual blobs are much smaller than the main NAPL body. Glass Wool Imaging Region I.D.= 1cm Length=1cm For a NAPL to penetrate a porous matrix the sum of viscous and buoyant pressures must exceed capillary pressure. Pc < Pv + Pb (3.74) Th e im ag e ca nn ot be di sp la ye d. Yo ur co m pu ter m ay DNAPL, water and silica sand Glass Wool Water Inlet The extent of residual NAPL can be inferred from several key equilibrium parameters. dgrain=1 mm CEE 440 dgrain=0.5mm 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 17 The magnitude of the capillary pressure can be defined by the Laplace equation (Note: equation shown is for idealized spherical interface): Pc = Po P w = 2 ow cos () / r (3.75) This equation can be used to approximate the threshold value of the capillary pressure that must be exceeded for DNAPL to pass through a pore throat of radius r. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 18 Pore Diameter E.g., In the pore below, describe the change in capillary pressure as the NAPL migrates from left to right. dmin 1.6 advancing receeding y water front dmax 0.8 NAPL front 1.2 x 0.4 0 0 0.5 1 1.5 2 PORE LENGTH This illustration indicates there should exist a relationship between capillary pressure and the relative amounts of NAPL and water in a porous medium. This is the case, but the complex geometry and wettability of natural pore spaces precludes direct computation of the relationship - ERGO, it must be measured. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 19 The measured relationship is the capillary pressure-saturation function or capillary pressure curve illustrated in the figure below (Note: this macroscopic function is defined only for volume elements of a porous medium that are large relative to the volume of individual grains): PCE H2O N2 Source: Pankow and Cherry CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 20 BYPASSING AND DEAD-END PORE WATER TRAPPING MECHANISMS WATER SATURATED NAPL FLOW CEE 440 NAPL SATURATED WITH RESIDUAL WATER 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 21 In the previous figure, PCE DNAPL advanced into previously water saturated porous media. This is known as drainage. Once the PCE source is exhausted, the PCE DNAPL will continue to migrate away from the source and it will be replaced by water. Now we get increasing water saturation but decreasing capillary pressure. This is known as wetting. Shown below is a draining-wetting capillary pressure curve: Note that water saturation at any particular capillary pressure is less during wetting than during drainage. This is known as hysteresis. Source: Pankow and Cherry? CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 22 SNAP-OFF AND BYPASSING NAPL TRAPPING MECHANISMS WATER SATURATED WITH RESIDUAL NAPL NAPL SATURATED WATER FLOW CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 23 Definitions Sw = Vw/Vv = wetting phase saturation Snw = Vnw/Vv = nonwetting phase saturation Vw = volume of wetting phase Vnw = volume of nonwetting phase Vv = volume of void (or pore) space 1 = Sw + Snw Swr = residual wetting phase Snwr = residual nonwetting phase Pd = displacement pressure = minimum capillary pressure required to initiate invasion of a water saturated porous media by DNAPL, also known as bubbling pressure Pcb DNAPL What causes hysteresis? -Variable pore dimensions -Contact angle aging Water DNAPL Water CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 24 Several relationships empirical are available to calculate the relationship between capillary pressure and saturation. Two of these are shown below: Brooks-Corey (1966) equation Se = (Pc/Pd)-, Pc>=Pd (3.76) Se = 1, (3.77) Se = normalized wetting-uid saturation or effective saturation Se=(Sw-Swr)/(Sm-Swr) Sm = maximum water saturation is unity when DNAPL is invading water and 1-Snwr when water displaces DNAPL Swr = wetting uid saturation Sw = saturation of wetting uid = pore size distribution index Pd and are t from the data CEE 440 14 12 decreases 10 Pc/Pd Pc<Pd 8 6 4 2 0 0 0.2 0.4 0.6 0.8 1 Se 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 25 van-Genuchten equation Se = (1+(Pc/(g))n)-m (3.78) hc = Pc/(g) (3.79) , n, and m are tting parameters, typically it is assumed that m=1-(1/n) 70 70 60 60 50 alpha decreases 40 hc hc 50 30 30 20 20 10 10 0 0 0 0.5 Se CEE 440 n decreases 40 1 0 0.5 1 Se 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 26 ii. Frictional Pressure Water moving past the particle (i.e. moving groundwater) imparts a pressure through frictional force which serves to displace the globule: Pv w hw L w = density of water hw = hydraulic gradient in the displacing water (dhw/dz) L = length of globule (function of grain size) CEE 440 (3.80) L 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 27 iii. Buoyant Pressure Buoyancy pressure arises from density differences between NAPL and water: Pb g L sin() -For DNAPLs in groundwater, buoyancy hinders the upward displacement and aids downward displacement. -For LNAPLs in groundwater, buoyancy hinders the downward displacement and aids the upward displacement. CEE 440 (3.81) L g 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 28 EXAMPLE OF BUOYANCY VERSUS CAPILLARY PRESSURE FOR NAPL POOL Consider a DNAPL release from storage containers. The DNAPL has leaked into the subsurface, penetrated the groundwater table, and is perched on an aquitard (low permeability layer) as a pool. How can we determine if the DNAPL has penetrated the aquitard. Z=vertical coordinate measured upward W=distance between bottom residual of pooled DNAPL and DNAPL saturated zone water table W Z T=distance between bottom T pooled DNAPL of pooled DNAPL and top of pooled DNAPL aquitard unsaturated zone CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 29 Z=vertical c measure W=distance residual of poole DNAPL saturated zone water tab W Z T=distance b T pooled DNAPL of poole top of po aquitard unsaturated zone From basic hydrology we know that water pressure increases with depth below the water table according to the following equation: Pw = - w g Z + C1 (3.82) (note: we could evaluate C1 by setting Pw=0 at Z=W) We know that the pressure of the nonwetting phase increases similarly with depth below the top of the pooled DNAPL: Pnw = - nw g Z + C2 (3.83) Subtracting these two equations we can solve for the buoyancy pressure: Pb = Pnw Pw = - (nw - w) g Z + (C2 C1) = - g Z + C CEE 440 (3.84) (3.85) 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 30 Z=vertical coo measured W=distance b residual of pooled DNAPL saturated zone water tabl ZW T=distance be T pooled DNAPL of pooled top of poo aquitard unsaturated zone Since Pb=0 at Z=T we can evaluate for C to get: Pb = g (T-Z), for Z<=T (3.86) Z Graphically we can illustrate this as: Pw W How might soil properties vary such that the capillary pressure-saturation curve changes and NAPL more easily penetrates the aquitard? CEE 440 Pb pressure Dra ina ge ca pilla ry pre ssure -sa tura tion curve s hc (cm water) Given the capillary pressure-saturation drainage curve for the aquitard, what conditions are necessary for the NAPL to migrate through this low permeability barrier? Pb > Pd = hd g Pnw T 70 60 50 40 30 20 10 0 0 0.5 1 Se 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 31 Example: A monitoring well which spans both the unsaturated and saturated zone detects high concentrations (near the solubility limit) of two different organic chemicals, perchloroethylene and jet fuel (PCE was used to spray the grease and dirt off jets) The specific gravity of the perchloroethylene is ~1.50. The specific gravity of the jet fuel is ~0.89 (Note: specific gravity is the density of the chemical divided by the density of water). In separate measurements, the interfacial tension of pechloroethylene/water and jet fuel/water is determined to be 36 dyne/cm and 35 dyne/cm, respectively (not statistically different). The organic/water contact angles are also determined to be not statistically different. Which chemical do you expect to find at higher residual saturation in the vadose zone? Which chemical do you expect to find at higher residual saturation in the saturated zone? CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 32 Solution The two organics have similar properties excluding density. Hence, lets consider buoyancy pressure: Pb g L sin() In the unsaturated zone the density difference between jet fuel and air is less than between PCE and air so more jet fuel will remain trapped. Jet fuel is less dense than water so the buoyancy force will prevent jet fuel from entering the saturated zone; only PCE will be found below the water table. This excludes, of course, the occurrence of water table fluctuations. CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 33 Soil Type Contaminant Spill for 7 years Permeability (mean value) 6.8e-11 m2 Hanford Coarse (12 m) Hanford Fine (13 m) 6.6e-12 m2 Upper Plio-Pleistocene (4.5 m) 1.7e-13 m2 Lower Plio-Pleistocene (6 m) 7.8e-12 m2 Ringold Formation (20 m) 1.3e-11 m2 1 order of magnitude lower than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. Mean CEE 440 34 Simulation Scenario CCl4 Infiltration Rates Water Infiltration Rates 1955 (6 mo) 0.062 m/yr 1956 0.277 m/yr 1957 0.277 m/yr 1958 0.264 m/yr 1959 0.283 m/yr 1960 0.286 m/yr 1961 0.379 m/yr 1962 (6 mo) 0.178 m/yr 1955 (6 mo) 3.04 m/yr 1956 2.47 m/yr 1957 2.95 m/yr 1958 3.92 m/yr 1959 3.07 m/yr 1960 4.42 m/yr 1961 4.23 m/yr 1962 (6 mo) 1.98 m/yr 1962 1993 over all areas Nov Feb 7.5 cm/yr Mar Oct 0.5 cm/yr CCl4 infiltration occurs one week per four weeks because of sporadic disposals Water infiltration occurs continuously CEE 440 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 35 1 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 36 2 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 37 3 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 38 4 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 39 5 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 40 6 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 41 7 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 42 8 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 43 9 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 44 10 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 45 11 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 46 12 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 47 13 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 48 14 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 49 15 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 50 16 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 51 17 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 52 18 yr Contaminant Spill for 7 years Mean CEE 440 Mea1norder of magnitude lower than mean f a gi t o g 1 or1doerrdeorf ommganntiuuddee lhiwheerr than mean than mean 1 order of magnitude higher than mean 2011 Charles J. Werth, University of Illinois at Urbana-Champaign. All rights reserved. 53
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Tom Piazza, author of 'Why New Orleans Matters,' was online to discuss theindispensable history and culture of his quintessentially American city.&quot;New Orleans is a city of elegance, beauty, and refinement,&quot; Tom Piazza writes in 'WhyNew Orleans Matters.
IMSciences - IMS - 1
The Emerald Research Register for this journal is available athttp:/www.emeraldinsight.com/researchregisterJMP18,8764The current issue and full text archive of this journal is available athttp:/www.emeraldinsight.com/0268-3946.htmPolitics and image
HCCS - PHIL - 2306
PHIL 2306 Summer 2010Instructor: Francesca BrunoKhoa PhanRead the &quot;Debate over Utilitarianism&quot; handout, available in the Unit 3 folder, and answer thequestions below. This assignment is worth 3 participation points.1) What is the definition of Utilit
HCCS - PHIL - 2306
1AQUINASS VIRTUES OF ACKNOWLEDGED DEPENDENCE:A NEW MEASURE OF GREATNESSRebecca Konyndyk DeYoungThis paper compares Aristotles and Aquinass accounts of the virtue ofmagnanimity specifically as a corrective to the vice of pusillanimity. Afterdefining
HCCS - PHIL - 2306
Etext of Meno, by Plato1Etext of Meno, by Plato*The Project Gutenberg Etext of Meno, by Plato* #14 in our series by PlatoCopyright laws are changing all over the world, be sure to check the copyright laws for your country beforeposting these files!P
HCCS - ARTS - 1303
If Christian meditation is thought, emotion, and imagination that leads to prayer, to conversationwith God, then one way to approach it is not a book, but a work of art. Fine art will engagedifferent senses, and it will communicate. It was used for cent
HCCS - ARTS - 1303
Compare to the artwork painted by Cimabue, the VIRGIN AND CHILD ENTHRONED(Figure 17-7, page 563) of the same topic painted by Giotto di Bondone has many differentcharacteristics showing a shift in style. Using Italo-Byzantine, Cimabue might have attempt
HCCS - ARTS - 1303
The definition of Style is the combination of form and composition that makes a work (ofart) distinctive. Medium or mediums (in plural form) refers to the materials from which a workof art is made.The art work that Im interested in is the Wall Painting
HCCS - ARTS - 1303
Discussion #3Read this entire document before you begin.Objective:The objective of this assignment is to interact with your classmates in a discussion of Europeanart from the Early Medieval through the Late Gothic Periods.Technical How-to? Eventuall
HCCS - ARTS - 1303
Discussion #2Read this entire document before you begin.Objective:To interact with your classmates in a discussion about art and religion.Technical How-to?Eventually you will cut from an MS word document and paste anessay into the Discussion #2 topi
HCCS - ARTS - 1303
Discussion #1Read this entire document before you begin.Objectives:Flip through your whole textbook and pick any work of art you like. Applythe terms &quot;Style&quot; and &quot;Medium&quot; to the one work of art, using the definitionsfound in your textbook on Starter
HCCS - ARTS - 1303
What is art? This is a very difficult question to answer. Volumes and volumes have been written on the subject, yet itseems that each generation struggles with the question of what exactly is art. Perhaps there is not a definitive answer, butit seems to
HCCS - SPCH - 1315
SPCH 1315, Fall semesterProfessor Tonia R PopeKhoa PhanKEY TERMS Chapter 6 15Chapter 61. Audience analysis: the process of gathering and analyzing demographic and psychologicalinformation about audience members with the explicit aim of adapting your
HCCS - SPCH - 1315
Tung PhamVy TrieuHa NguyenChristina GonzalezHang LeAbortion in ChinaAttention Getter: Did you know, According to New York Times more than 13 million abortions areperformed each year in China; far more than any other country in the world.Specific P
HCCS - SPCH - 1315
+ABORTI ON I NCH I NABy: H ang L e, Son Nguyen, Vy Tr ieu, H ung Pham,Chr ist ina GonzalezPr ofessor Goodie-Pope+I NTRODUCTI ON+STAGES OF ABORTI ON I NCH I NATYPES OFA BORTI ON1.RU-482.SUCTI ON-ASPI RATI ON3.DI L ATI ON ANDCURETTAGE (D
HCCS - SPCH - 1315
Main points of Campaigns and Battles- First Battle in 1861, Confederate open fire upon Union.- First Stage in 1862 with Western and Eastern Theaters.- Second Stage: Year of Decision in 1863.- Last Stage from 1864 to 1865, with the surrender of Confede
HCCS - SPCH - 1315
Khoa PhanSPCH 1315 Fall semesterUsing Online Function Grapher1Using Online Function GrapherKhoa PhanAttention Getter: Have you ever taken a math course? Im sure you have. Sooner or later, youwill have to deal with problem of plotting the graph of f
HCCS - SPCH - 1315
Khoa PhanKey TermsSPCH 1315 Fall 09Key Terms A Speakers guidebook (3rd ed)Chapter 11. Dyadic communication- Communicate between two people, as in a conversation.2. Small group communication- A group that consists between three and twenty people aso
HCCS - SPCH - 1315
Introduction SpeechSPCH 1315 Fall 09Khoa PhanIntroduction SpeechUlysses S. Grant(Intro)Good evening ladies and gentlemen. Welcome to the 2009 American Union Commemoration.My name is Khoa Phan.(Attention Getter)Have you ever wondered how all Ameri
HCCS - MATH - 2304
Khoa PhanCalculus II MTWR, 9.00 AM 12.15 PMProfessor Chuen HuangOnlineFunction GrapherWritten entirely in JavaScriptBy Walter ZornHow to UseGo to website: http:/www.walterzorn.com/grapher/grapher_e.htm1Khoa PhanCalculus II MTWR, 9.00 AM 12.15 P
HCCS - MATH - 2304
InstructorTONIARPOPEStudentKHOAPHANIntroductionWrittenentirelyinJavaScriptByWalterZornWebsite:http:/www.walterzorn.com/grapher/grapher_e.htmRequirementsAcomputercanconnecttotheinternetAninternetconnectionStep1:PreparationStartthecomputerConn
HCCS - MATH - 2304
UsingOnlineFunctionGrapherKHOAPHANCalculusIIProfessorCHUENHUANGWrittenentirelyinJavaScriptByWalterZornWebsite:http:/www.walterzorn.com/grapher/grapher_e.htmPlottheGraphofFunctionGotothewebsitehttp:/www.walterzorn.com/grapher/grapher_e.htmInserta
HCCS - BCIS - 1405
Exp_Com_Concepts.qxd7/3/0712:35 PMPage 1O bjectivesAfter you read this chapter, you will be able to:1. Understand computer components and computer types (page 3).2. Acquire a computer (page 6).3. Evaluate security software (page 8).4. Understand
HCCS - BCIS - 1405
Exp_Com_Con_Multiple_Choice.qxd7/3/078:24 PMPage 49Multiple Choice Answer KeyComputing Concepts, Chapter 11. d2. a3. b4. a5. c6. b7. d8. a9. b10. a11. d12. d13. b14. a15. b16. d17. b18. a19. cMultiple Choice Answer Key49Exp_Com_
HCCS - BCIS - 1405
Exp_Com_Con_Gloss.qxd7/3/078:24 PMPage 47GlossaryAll key terms appearing in this book (in bold italic) are listedalphabetically in this Glossary for easy reference. If you wantto learn more about a feature or concept, use the Index tofind the term
HCCS - BCIS - 1405
Exploring MicrosoftOffice 2007Computing ConceptsRobert Grauer, Lynn Hogan, Keith MulberyChanges made by Anci Shah @ HCCCommitted to Shaping the Next Generation of IT Experts.1Copyright 2008 Pearson Prentice Hall. All rights reserved.ObjectivesUnd
HCCS - BCIS - 1405
Exploring MicrosoftOffice 2007Computing ConceptsRobert Grauer, Lynn Hogan, Keith MulberyCopyright 2008 Pearson Prentice Hall. AllNextCommitted reserved.to Shaping the rightsGeneration of IT Experts.1ObjectivesUnderstand computer concepts andcom
HCCS - BCIS - 1405
HCCS - BCIS - 1405
From: &quot;Saved by Windows Internet Explorer 7&quot;Subject: Course ContentDate: Mon, 30 Nov 2009 15:41:46 -0600MIME-Version: 1.0Content-Type: multipart/related;type=&quot;multipart/alternative&quot;;boundary=&quot;-=_NextPart_000_000A_01CA71D3.9FE71480&quot;XX-MimeOLE: Prod
Purdue - ME - 509
Purdue - ME - 509
Purdue - ME - 509
Purdue - ME - 509
Purdue - ME - 509
Practice Problems on the Linear Momentum EquationsCOLM_01A frequently used hydraulic brake consists of a movable ram that displaces water from a slightly larger cylinder, asshown in the figure. The cross-sectional area of the cylinder is Ac and the cro
Purdue - ME - 509
Notes on Fluid Mechanics and Gas DynamicsCarl Wassgren, Ph.D.School of Mechanical EngineeringPurdue Universitywassgren@purdue.edu16 Aug 2010Chapter 01:Chapter 02:Chapter 03:Chapter 04:Chapter 05:Chapter 06:Chapter 07:Chapter 08:Chapter 09:C
Purdue - ME - 509
Practice Problems on Fluid Staticsmanometry_01Compartments A and B of the tank shown in the figure below are closed and filled with air and a liquid with aspecific gravity equal to 0.6. If atmospheric pressure is 101 kPa (abs) and the pressure gage rea
Purdue - ME - 509
Practice Problems on Conservation of MassCOM_01Construct from first principles an equation for the conservation of mass governing the planar flow (in the xy plane)of a compressible liquid lying on a flat horizontal plane. The depth, h(x,t), is a functi
Purdue - ME - 509
Practice Problems on Pipe Flowspipe_02A homeowner plans to pump water from a stream in their backyard to water their lawn. A schematic of the pipesystem is shown in the figure.sprinklerinlet pipe-to-pump3 m coupling1 m streamhose-to-hose coupling
Purdue - ME - 509
Purdue - ME - 509
Purdue - ME - 509
172Chapter 3 Integral Relations for a Control VolumeEXAMPLE 3.19A hydroelectric power plant (Fig. E3.19) takes in 30 m3/s of water through its turbine and discharges it to the atmosphere at V2 2 m/s. The head loss in the turbine and penstock system is
Purdue - ME - 509
1. In fluid mechanics, it is the ratio of the area of the vena contracta to the area of the smaller pipe.Answer: A. Contraction coefficient2. When the Reynolds number of a fluid flow is 3500, the flow isAnswer: C. Intermediate between turbulent or lami
Purdue - ME - 509
LECTURE NOTES ONINTERMEDIATE FLUID MECHANICSJoseph M. PowersDepartment of Aerospace and Mechanical EngineeringUniversity of Notre DameNotre Dame, Indiana 46556-5637USAlast updatedSeptember 7, 20082Contents1 Governing equations1.1 Philosophy of
Purdue - ME - 509
CHAPTER 3FLOW PAST A SPHERE II: STOKES LAW, THEBERNOULLI EQUATION, TURBULENCE, BOUNDARYLAYERS, FLOW SEPARATIONINTRODUCTION1 So far we have been able to cover a lot of ground with a minimum ofmaterial on fluid flow. At this point I need to present to
Purdue - ME - 509