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Course: MATH 321, Spring 2011
School: Boğaziçi University
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322 MATH Final Examination Name: Surname: Signature: Question 1 2 3 4 June 2, 2001 9:0012:00 TB 120 Score /10 points /15 points /5 points /5 points 5 6 7 8 9 /5 /5 /10 /15 /10 points points points points points 10 Bonus Question /20 points /20 points Total /100 points 1. Express the symmetric polynomial x3 + y 3 + z 3 + xyz over Z in terms of the elementary symmetric polynomials. (10 points) 1 2. Let A...

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322 MATH Final Examination Name: Surname: Signature: Question 1 2 3 4 June 2, 2001 9:0012:00 TB 120 Score /10 points /15 points /5 points /5 points 5 6 7 8 9 /5 /5 /10 /15 /10 points points points points points 10 Bonus Question /20 points /20 points Total /100 points 1. Express the symmetric polynomial x3 + y 3 + z 3 + xyz over Z in terms of the elementary symmetric polynomials. (10 points) 1 2. Let A := a c b d Mat22 (C) : a c b d 0i 11 = 0 1 i 1 a c b d Mat22 (C). Is A a vector space over R? Over C? (15 points) 2 3. Let K be a eld. Give the denition of the characteristic of K . 3 (5 points) 4. Let K be a eld of characteristic p = 0. Prove that : K K , a a p is a eld homomorphism. (5 points) 4 5. Find the multiplicative inverse of 2 + 3 5 in the eld F7 ( 5). 5 (5 points) 6. Let E/K be a eld extension and let D be integral an domain such that K D E . Prove that, if E is algebraic over K , then D is a eld. (5 points) 6 7. Find the number of monic irreducible polynomials of degree 72 over F 5 . (10 points) 7 8. Let E/K be a eld extension and let L be an intermediate eld. If L is (K, E )-stable, prove that L is (K, E )-stable, too. (15 points) 8 9. Find an algebraic eld extension that is not separable. 9 (10 points) 2i 10. Let := e 12 C and E := Q( ). Find all subgroups of G := AutQ E , all intermediate elds of E/Q, and a primitive element for each of the intermediate elds. Describe the Galois correspondence by Hasse diagrams of groups and intermediate elds. (20 points) 10 Bonus question. Tell about the contribution to algebra of one of the following mathematicians: Gauss, Cauchy, Abel, Liouville, Klein, Kronecker, Dedekind, Heinrich Weber, Artin. 11
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Boğaziçi University - MATH - 321
Math 322 Final ExaminationName :Signature :May 31, 19999:0012:00(1) Show that a polynomial f (x) Z[x] is irreducible in Z[x] if and only if f (x + 1)is irreducible in Z[x]. Using this, prove that for any odd prime number p, the pthcyclotomic polyno
Boğaziçi University - MATH - 321
Math 322 First Midterm ExaminationName :April 8, 1999Signature :9:0010:30(1) Is 3x6 4x + 6 irreducible in Z[x] ?(10 points)(2) Does there exist a polynomial f in Z[x] such that f (0) = 1, f (1) = 2, f (2) = 3,f (3) = 2 ?(20 points)Name :Surname
Boğaziçi University - MATH - 331
Math 322 Second Midterm ExaminationName :May 18, 1999Signature :9:3011:00(1) Is Q( 3 + 5 + 7) = Q( 3, 5, 7)? Why or why not?(10 points)(2) Find |Q( 3 + 5) : Q( 3)|. Justify your answer.(15 points)Name :Surname :(3) Find the number of irreducibl
Boğaziçi University - MATH - 332
T. LiggettMathematics 131C Final Exam SolutionsJune 7, 2010(25) 1. (a) State Fatous Lemma.See Royden, page 86.(b) State the Bounded Convergence Theorem.See Royden, page 84.(c) Use Fatous Lemma to prove the Bounded Convergence Theorem.Suppose |fn |
Boğaziçi University - MATH - 332
T. LiggettMathematics 131C Midterm SolutionsMay 5, 2010(25) 1. Consider solving the equationsu3 + xv y = 0v 3 + yu x = 0(1)for u, v in terms of x, y .(a) Show that there are dierentiable functions u(x, y ) and v (x, y ) denedin a neighborhood N o
Boğaziçi University - MATH - 332
Math 507/420: Measure Theory and Integration (2010) SOLUTIONSHomework Assignment #1Due: Friday, Sept. 24, at beginning of class.You may use any result from Chapter 0 or Sections 1.1., 1.2. or 1.3 of Folland or established in class.1. True or False (ju
Boğaziçi University - MATH - 332
MATH 467/MAST 669/837 Measure TheorySolutions to Assignment #11. (Ex. 6, page 34) Let A be the set of irrational numbers in the interval [0, 1]. Prove that m (A) = 1.Proof. Let B = Q [0, 1], the set of rational numbers in [0, 1], and note that B is cou
Boğaziçi University - MATH - 332
Bilkent University - MATH - 332
Cambridge University Press0521838037 - Measure Theory and Filtering: Introduction and Applications - Lakhdar Aggoun and RobertJ. ElliottExcerptMore informationPart ITheory Cambridge University Presswww.cambridge.orgCambridge University Press0521
Bilkent University - MATH - 332
Date: March 10, 2007, Saturday Time: 13:00-15:00 u Ozgler & Sertz o Math 206 Complex Calculus Midterm Exam I SolutionsQ-1) Find all the fourth roots of rectangular form. Answer: 3 i - 1 = 2 exp[i(3 i - 1. Write the resulting numbers in2 + 2n)], n Z. Th
Bilkent University - MATH - 332
Date: April 21, 2007, Saturday Time: 14:00-16:00 u Ozgler & Sertz oNAME:. STUDENT NO:.Math 206 Complex Calculus Midterm Exam II Solutions 1 2 3 4 TOTAL25252525100Please do not write anything inside the above boxes!PLEASE READ:Check that there ar
Bilkent University - MATH - 332
Date: May 18, 2007, FridayTime: 9:00-11:00uOzgler & SertzoNAME:.STUDENT NO:.Math 206 Complex Calculus Final Exam Solutions1234TOTAL25252525100Please do not write anything inside the above boxes!PLEASE READ:Check that there are 4 questi
Bilkent University - MATH - 332
Bilkent University - MATH - 332
Boğaziçi University - MATH - 224
(1)(a) (0.824-0.0058,0.824+0.0058)(b) (0.824-0.0077,0.824+0.0077)(2) (a) (4.38-0.0452,4.38+0.0452)(b) (4.38-0.0650,4.38+0.0650)(3) (a) Claim is not legitimate.(b) p 0.(4) (a) reject H0 .(b) accept H0 .(c) p=0.0124(5) (a) reject H0 .(b) p=0.0062
Boğaziçi University - MATH - 224
Boğaziçi University - MATH - 224
Math 118C Homework 3 SolutionsCharles MartinApril 21, 20099.19 Show that the system of equations3x + y z + u2 = 0x y + 2z + u = 02x + 2y 3z + 2u = 0can be solved in terms of x, in terms of y , in terms of z , but not in terms of u.For k = 1, 2, 3
Boğaziçi University - MATH - 224
PROJECTIVE GEOMETRYb3 course 2003Nigel Hitchinhitchin@maths.ox.ac.uk11IntroductionThis is a course on projective geometry. Probably your idea of geometry in the pasthas been based on triangles in the plane, Pythagoras Theorem, or something morean
Boğaziçi University - MATH - 224
Homework #01, due 1/20/10 = 9.1.2, 9.1.4, 9.1.6, 9.1.8, 9.2.3Additional problems for study: 9.1.1, 9.1.3, 9.1.5, 9.1.13, 9.2.1,9.2.2, 9.2.4, 9.2.5, 9.2.6, 9.3.2, 9.3.39.1.1 (This problem was not assigned except for study, but its usefulfor the next pr
Boğaziçi University - MATH - 224
Solutions to Homework 946. (Dummit-Foote 10.3 #2) Suppose Rn Rm . Let I be a maximal ideal of R, then Rn /IRnRm /IRm . By the exercise 12 of section 2, this implies that (R/I )n(R/I )m , and as these arevector spaces over the eld R/I , we have n = m.
Boğaziçi University - MATH - 224
1Draft: Life insurance mathematics in discrete timeTom FischerDarmstadt University of Technology, GermanyLecture at the METU Ankara, TurkeyApril 12-16, 20042A recent version of the lecture notes can be downloaded underwww.mathematik.tu-darmstadt.d
Boğaziçi University - MATH - 224
BU Department of MathematicsMath 344 First Midterm ExaminationSolution KeyDate: April 8, 2009Time: 17:00-18:00Full Name:Student Number:Signature:Q1Q2Q3Q4pts pts pts ptsTotal100 pts1) (5pts each) An urn contains m balls numbered 1, 2, . . .
Boğaziçi University - MATH - 224
Troy - BUS - 101
Chapter 5 Cross-Cultural Negotiation and Decision MakingMultiple Choice Questions1.Ignorance of _, more than any other single factor, accounts for Americas unimpressivesales efforts with Japan.a. native bargaining rituals (moderate, page 158)b. dome
Fresno City College - CADD - 398
#include <cstdlib>#include <iostream>using namespace std;void matrixTranspose(float *M, int n);int main(int argc, char *argv[])cfw_ float M[4][4] = cfw_ cfw_11,12,13,14, cfw_21,22,23,24, cfw_31,32,33,34, cfw_41,42,43,44 ; int i,j, n = 4; float * p
ASU - AL - 26
sWM Dx W m|Xcfw_ #include "stdafx.h"int _tmain(int argc, _TCHAR* argv[])cfw_return 0;m m |Xcfw_N~. . .
Korea University - EE - 111
ELEN3801 - Fall 2009 Homework 2Due Thursday September 24th at the beginning of class (Mudd 227 9:10am)1 Carefully justify ALL your answers2.1 - Find the energy of the signals sketched below. How does the energy change when transforming a signal by time-
Korea University - EE - 111
Korea University - EE - 111
ELEN3801 - Fall 2009Homework 3Due Thursday October 1st at the beginning of class(Mudd 227 9:10am)1Carefully justify ALL your answers3.1 - Let f (t) be a signal with energy Ef . Show that the energy of the signalsf (t), f (t) and f (t T ) where T R i
Korea University - EE - 111
Korea University - EE - 111
ELEN3801 - Fall 2009Homework 4Due Thursday October 8th at the beginning of class(Mudd 227 9:10am)1Carefully justify ALL your answers4.1 - Let H be a time-invariant (but not necessarily linear) system. Show thatthe systems response to a constant inpu
Korea University - EE - 111
Problem 6.a)function y=f(t)%This function computes the value of -t(u(t+1)-u(t)y=-t.*(t+1>=0)-(t>=0);Problem 6.b)t= -4:.01:4;subplot(3,2,1)plot(t,f(t)title($f(t)$,interpreter,latex,fontsize,14)grid onylim([-1/2 3/2])subplot(3,2,2)plot(t,f(-t)t
Korea University - EE - 111
Korea University - EE - 111
Korea University - EE - 111
Homework111.11. If f (x) has period p, show that f (ax), a = 0, is a periodic function of x of periodp/a.Sol. Let g (x) = f (ax). Since p is a period of f ,g (x + p/a) = f (a(x + p/a) = f (ax + p) = f (ax) = g (x).Thus g (x) = f (ax) is a periodic
Korea University - EE - 111
Homework111.71. Show that0 cos xw+w sin xw(a) 0dw =/21+w2 xe /2 sin w(b) 0 w cos xwdw =/40if x < 0if x = 0 .if x > 0if0x<1.ifx=1ifx>10 if x < 0Sol. (a) We nd the Fourier integral of f (x) =.ex if x > 01A(w) =1B (w) =11,
Korea University - EE - 111
Homework112.11. Solve the PDEs.(a) uxx = 4y 2 u,(b) uyy = 4xuySol. (a) If u = u(x), then u(x) = Ae2yx + Be2yx . Thus the solution of this PDE isu(x, y ) = A(y )e2yx + B (y )e2yx , where A(y ) and B (y ) are arbitrary.(b) Setting uy = p, we have py
Korea University - EE - 111
Homework14.11. EvaluateSol.C1Re z dz, where C is the parabola y = x2 from 0 to 1 + i.C : z (t) = t + t2 i, 0 t 1.1Re z dz =C2. EvaluateCzezt(1 + 2ti)dt = [02/2t2 2t3 1 1 2+i] = + i.230 23dz, where C is the path from i along the axes
Korea University - EE - 111
Homework124.11. (a) Represent the data403 399 398 401 400 401 401by a stem-and-leaf plot, a histogram, and a boxplot.(b) In(a), nd the mean and compare it with the median. Find the standard deviation and compare it with the interquartile range.Sol.
Korea University - EE - 111
Homework125.21. (a) Find a maximum likelihood estimate for = p in the case of the binomialdistribution.(b) Extend (a) as follows. Suppose that m times n trials were made and in the rstn trials A happened k1 times, in the second trials A happened k2
Korea University - EE - 111
Homework19.8 9.91. Find the divergence and the curl of the vector functionF(x, y, z ) = (x2 + y 2 + z 2 )3/2 (xi + y j + z k).Sol. LetF1 =xyz, F2 = 2, F3 = 2.(x2 + y 2 + z 2 )3/2(x + y 2 + z 2 )3/2(x + y 2 + z 2 )3/2Notice that13x2y 2 +
Korea University - EE - 111
Homework113.11.(a) Show that multiplication by i (z iz ) is geometrically a counterclockwiserotation through .2(b) Show that multiplication by = cos + i sin (z z ) is geometrically acounterclockwise rotation through .Sol. (a) Let z = x + iy (= 0).
Korea University - EE - 111
2010 2 (4) -CSE .1: 9.8,9.9,10.1,10.4,10.6,10.7: 9 13()2: 10.8,10.9,13.1,13.2,13.3: 9 27()3: 13.4,13.5,13.6,13.7: 10 4()4: 14.1,14.2,14.3,14.4: 10 14()5: 11.1,11.2,11.3,11.4: 11 1()6: 11.6,11.7,11.9: 11 12()7: 12.1,12.3,12.4,12.5,12.6: 11 2
Korea University - EE - 111
: 2007. 9/101. I.2064115601 1., . 1-1.R2() 1-2[DC]0-50R2()[AC]0--50-100-100-1K6.021K6.255K10.045K10.4610K10.9510K11.4420K11.4720K11.9840K11.740K12.360K11.8560K12.38100K11.92100K12.46. R1 = 3K, R2
Korea University - EE - 111
: 2007. 9/102. II.2064115601 1., ( 2-6 300 200 300 3k, 470 5k 200 2k .) 2-1.RLVLILVLIL470 []0.683 [V]1.459 [mA]0.676064 [V]1.438435 [mA]1 [k]1.296 [V]1.3 [mA]1.282051 [V]1.282051 [mA]2 [k]2.156 [V]1.07 [mA]2.127659 [V]1.06
Korea University - EE - 111
: 2007. 9/102. II.2064115601, . (Thevenins Equivalent Circuit) 1883 M. L. Thevenin . (Voc) (Rt) . . (Nortons Equivalent Ci
Korea University - EE - 111
: 2007. 9/173. .20641156013[k]4.7[k]10[k]20[k] 1. ) DC AC 3-1 (a)R21.385 V1.918 V3.00 V4.00 V V0 [V]1.43 V1.96 V3.12 V4.09 V3.2491 %2.1898 %4%2.2500 %1.385 V1.918 V3.00 V4.00 V1.42 V1.92 V3.03 V4.01 VV0 [V][%]2.527
Korea University - EE - 111
: 2007. 9/173. .2064115601 .(1) , , 3 3 . CRT . , , 3 . 3
Korea University - EE - 111
: 2007. 10/014. .2064115601 1. 4-1 (VAK 0.7V : 3.3V)VAKID 20.7 V5.586 mA125.3133 3,43.37 V0A5: ?: X10RB: 5.2607( 5 . .) 4-2 6 7 VAK [V]ID [mA]VAK [V]ID [A]0000.0030.10.0004-50.600.20.0006-101.180.30.002
Korea University - EE - 111
: 2007. 10/14. .2064115601 ? , , . 3 , , . . .
Korea University - EE - 111
: 2007. 10/85.Battery Tester and Charging .2064115601Economical Battery Tester Economical Battery tester , . 39 33 10n Capacitor 0.1F Capacitor .( ) Economical battery tester . Economical Battery tester LED . LED Analog 4.5V . (PSPI
Korea University - EE - 111
: 2007. 10/85.Battery Tester and Charging .2064115601Economical battery tester Economical battery tester .Battery tester . Battery tester . LED , . LED D1 C1 . S1 T1 C1 R3LED . R1/R2
Korea University - EE - 111
: 2007. 10/156. Audio Amplifier 20641156016. 6-1 Power Supply for an Audio Amplifier. PSPICE PSPICE , . 6-6 .< 6-6> 6-7 ripple .<C1 = 0.001uF><C1 = 10uF><C1 = 100uF><C1=2200uF> Voltage regulator . Ripple ?Ripple . 6-11 transistor Volt
Korea University - EE - 111
: 2007. 10/86. Auto Amplifier .2064115601Power Supply for an audio amplifier Power Supply . . power transformer. power transformer . N1 1 120V N2 2
Korea University - EE - 111
: 2007. 10/297. .2064115601 7-3 AND ABAB000010100111ABA+B000011101111 7-4 OR 7-5 NOT AA0110 7-6 NAND AB(AB)001011101110 7-7 NOR AB(A+B)001010100110 13: XYSCout000001
Korea University - EE - 111
: 2007. 10/297. .2064115601 . . Base-Emitter Saturation Ground Collector 1 Volt 0 . Transistor AND GateTransistor OR GateTransistor NAND GateTransistor NOR Gate (Double Transistor)Transistor NOR Gate (Single Transistor)XOR 2 AND, OR, NAND
Korea University - EE - 111
: 2007. 10/298. .2064115601 2X1 4X1 , 8X1 8X1 2X1 1 4X1 2 . .S2S1S0F000I0001I1010I2011I3100I4101I5110I6111I7 a+cd+bd+bd+bce .Input a=1 1 32 input I1
Korea University - EE - 111
: 2007. 10/298. .2064115601 .2 X 1 / 4 X 1 (MUX : Multiplexer): n 4 X 1 : 4 F = S1S2I0+S1S0I1+S1S0I2+S1S0I32 X 1 : 2 Z = S0A+ S0B2n . (Encoder): 2n n ,
Korea University - EE - 111
: 2007. 11/059. .2064115601 .(1) Sign and Magnitude ( ) Signand Magnitude . 0 (+), 1 (- ) . 1 byte 7bit 0 127 (0000000~1111111) . -127~127 . 0 00000000 10000000
Korea University - EE - 111
: 2007. 11/1910. .2064115601Master / Slave J-K verilog HDL .module MS_JK_FF(J, K, clk, Q, Qn);inputJ, K, clk;outputQ, Qn;regP, Pn;regQ, Qn;always@(posedge clk)beginif( (J = 1'b1) & (K = 1'b0) )P = 1'b1;else if( (J = 1'b0) & (K = 1'b1
Korea University - EE - 111
. : 2007. 12/0313. II.2064115601 1. .- , .- , . - : .- : .