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### ME211_sol3

Course: ME ME211, Fall 2010
School: Michigan
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Michigan - ME - ME211
Michigan - ME - ME211
Michigan - ME - ME211
Michigan - ME - ME211
3fl_i.rs(p.,III1\_IIS4I-_)-c.,.ItvC,HCiil-,39--/-p41s.x4_p8-62. The guy wire AB of a building frame is originallyunstretched. Due to an earthquake, the two columns ofthe frame tilt U = 2. Determine the approximate
Michigan - ME - ME211
____2tfJci2*9.20. The support consists of threerigid plates, which areconnected together using two symmetricallyplaced rubberpads. If a vertical force of 50 N is appliedto plate A,determine the approximate vertical displacement of thisplate
Michigan - ME - ME211
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Michigan - ME - ME211
Michigan - ME - ME211
14-5. TWo hemispheres having an inner radius of 2 ft andwall thickness of 0.25 in. are fitted together,and the insidegauge pressure is reduced to 10 psi. If thecoefficient ofstaticis p. = 0.5 between the hemispheres,determine (a) the torque Tneede
Michigan - ME - ME211
4--bHI)4\4-I+C.,&amp;1--cr-.-iicJkd,.,U,cnOCt,LI)(*15.20. The wooden beam is subjected to a load of 12 kN.If grains of wood in the beam at point A make an angle of25 with the hothontal as shown, determine the normal andshear stress
Michigan - ME - ME211
1 -102. The smooth rigid-body cavity is 1Ied with liquid061-T6 aluminum. When cooled it is 0012 in. from thetopof the cavity. If the top of thecavity is not covered andtemperature is increased bythe200 F, determine thestracomponents e, e, and e
Michigan - ME - ME211
_16-35. The A-36 steel beam has a depth of 10 in. and issubjected to a constant moment M which causes the,0stress at the outer fibers to become u = 36 ksi.Determine the radius of curvature of the beam and themaximum slope and deflection.BNALPro
Michigan - ME - ME211
4.65.OadGPFigure 1We rst draw a free-body diagram of the half cylinder as shown in Figure 2.OadGNWPFFigure 2The normal reaction force N must be perpendicular to the plane and hence to the tangent atthe point P. This force must therefore
Michigan - ME - ME240
)Lc,h:=J, ( 1 -.; J )/'1,47( i)~. ~.I- 2.-: /o;l ~= / .;)h2.z:-.(2-P-)JIf ( I -h= (ho o if-) cfw_ 2)71( JfJD):2.-/vJ J;~ )h2.2zRz~ (21&lt;.)- 3-.IIL -td.ACen&gt;GoNoJletlc.t.cfw_ovrnt ~J t&gt;~C .oftVlx:,-1 )S h61JVlJ-&gt;1 rc
Michigan - ME - ME240
ME 240 13th (and final) Homework Assignment. Due Monday 12/13/10Textbook problems:8.438.628.688.798.89No. 6. Problem contributed by Prof. Scott:The bar shown is undergoing small motions ( &lt; 1) in a horizontal plane (gravity doesnot enter this pro
Michigan - ME - ME240
Michigan - ME - ME240
Dowling, ME 240, Fall 2010ME 240, Practice Midterm Exam #2 (100 pts total)You may use the textbook, a dictionary, class notes, homework, homework solutions, a simplecalculator (no symbolic manipulation or differential equation solving capabilities), an
Michigan - ME - ME382
The University of MichiganDepartment of Mechanical EngineeringME 320 - Sections 1 &amp; 2Exam I - October 31, 2011Problem 1 (17 points)Oil spills of various magnitudes may occur in ports where oil tankers are loaded or unloaded.The density o of oil is l
Michigan - ME - ME382
50&gt;pr-.(IIC,0tc-3C)r+3.AV.-.3%.c5. Ashby and Jones II() TLt1i.Jd.Appendix I, Probtem 2.8TrIt111r pin fir ,i 5ntOtn:-,truL11ifli t.uCflOSi1.3iS,Lir,P 1h.iTi. /\j.i4Il(I!C.dLIitOtt2511(E lIeS Iflthc 1% U 1itiitvrt,
Michigan - ME - ME382
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Michigan - ME - ME382
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Michigan - ME - ME382
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Michigan - ME - ME382
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Michigan - ME - ME382
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Michigan - ME - ME382
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Michigan - ME - ME382
Michigan - ME - ME382
ME 211 ADDITIONAL HOMEWORK QUESTIONS1. Figure P1 shows a solid cylindrical shaft of diameter 10 mm and length 1 in, which isbuilt into a wall at one end A. At the other end B, a load of 10 kN is applied at the topand perpendicular to the wall. Also, eq
Michigan - ME - ME382
LTL5\4.Cr:-2pra-c.-.-_,_j&gt;rUcIF(IPr3C?(iC)4?I-JJL4.I5CrniI1P(ji.(I-flIC?9C)(NThCLc- \d.icC(_3c5-z0C;!19,U9?pC)?\3Lcfw_\0DpDelta LDStressStrainTrue StressTrue StrainTrue Plasti
Michigan - ME - ME320
ME 211 INTRODUCTION TO SOLID MECHANICSPractice Final ExaminationAttempt all questionsMULTIPLE CHOICE QUESTIONS1. (2 points). Three strain gages are attached to a body with 0o , 120o , and 240o orientationrelative to the x-direction (i.e. gage (a) is
Michigan - ME - ME320
The University of MichiganDepartment of Mechanical EngineeringME 320 - Sections 1 &amp; 2Homework #1 - Due September 21, 2011Problem 1: Problems 1.11, 1.12 and 1.13 of Munson, Young, Okiishi, Huebsch, 6th edition(hereafter referred to as the text)Proble
Michigan - ME - ME320
The University of MichiganDepartment of Mechanical EngineeringME 320 - Section 1 &amp; 2Homework #2 - Due September 28, 2011Problem 1: Problems 2.7 and 2.9 of the text.Problem 2: Problems 2.14 and 2.15 of the text.Problem 3: Problems 2.36 and 2.37 of th
Michigan - ME - ME320
The University of MichiganDepartment of Mechanical EngineeringME 320 - Sections 1 &amp; 2Homework #3 - Due October 5, 2011Problem 1: Problems 2.56, 2.60 and 2.72 of the text.Problem 2: Problems 2.83, 2.87 and 2.94 of the text.Problem 3: Problems 2.89, 2
Michigan - ME - ME320
The University of MichiganDepartment of Mechanical EngineeringME 320 - Sections 1 &amp; 2Homework #4 - October 12, 2011Problem 1: problems 4.13, 4.16 and 4.19 of the text.Problem 2: Problems 4.32, 4.35 and 4.49 of the text.Problem 3: Problems 3.35 and 3
Michigan - ME - ME320
Michigan - ME - ME320
The University of MichiganDepartment of Mechanical EngineeringME 320 - Sections 1 &amp; 2Homework #6 - Due Friday October 28, 2010 by 5:00pmProblem 1: Problems 5.48, 5.66 and 5.70 of the text.Problem 2:(a) Problem 5.60 of the text.(b) The results of a
Michigan - ME - ME320
The University of MichiganDepartment of Mechanical EngineeringME 320 - Sections 1 &amp; 2Homework #7 - Due November 9, 2011Problem 1: Problems 6.15, 6.21 and 6.22 of the text.Problem 2: Problems 6.24 and 6.26 of the text.Problem 3: Problem 6.20 of the t
Michigan - ME - ME320
The University of MichiganDepartment of Mechanical EngineeringME 320 - Sections 1 &amp; 2Homework #8 - Due November 16, 2011Problem 1: Problems 6.90 and 6.93 of the text.Problem 2: Problems 6.99 and 6.102 of the text.Problem 3: Problems 6.106 and 6.107
Michigan - ME - ME320
ME382-00l Mechanical Behavior of MaterialsFall 2011Midterm IOctober 10, 2011Attempt all questions. Only clear, unambiguous marks will he counted. Show all calculations for full credit. Nopartial credit ill be given for free-body diagrams or sketches
Michigan - ME - ME382
ME382Fall2011Midterm1Monday,October10th,2011Thisisaclosedbookexam;studentsareallowedanunmarkedcopyoftheME382databook.Showallcalculationsforfullcredit.Ifyouneedmorepaper,stapleittothebackofthisexam.T
Michigan - ME - ME382
GENERAL-PURPOSEAIR VELOCITY TRANSDUCERSFMA-900-V Series822$All modelsOptionalUp to 1.5% AccuracyRemote Probe Model Availablewith 4.6 m (15') CableEach Unit Individually CalibratedDurable Fast-ResponsePlatinum SensorsCompact Solid-State Electr Michigan - ME - ME382 Homework 1 Solutions1.Solution:Solution:Solution:Solution:ME 382 Fall 2010 HW1 Solutions2.Solution:Solution:Solution:Page 2ME 382 Fall 2010 HW1 SolutionsPage 3ME 382 Fall 2010 HW1 Solutions3.[TypeSolution:aquotefromthed Michigan - ME - ME382 ME 382 Fall 2011 HW02 Solutions = 400 106 = 1000 106 = 800 106 = = = 0From Table 5.2: E = 70.3 GPa and =0.345.Problem 1: Dowling 5.163D Hookes Law: =Plugging in known values: =1 + 1 ( + ) 0.004(70,300 ) = 0.3450.0010(70,300 ) = 0.345So Michigan - ME - ME382 VyCI00b.NU04.3(-jIc-.c-NJ--CsCl-cC-I)j1rri.3IIILHIIpLf5)(a-ai0a-qIc5rjIS.xI04NIIriIwS0,c00-IdC9-0p-.4.0SV:1kr0I0C-;*&gt;CiI00I.4-&gt;-_,f-r,)c&gt;%_2)I\JIJ*4-Cd91 Michigan - ME - ME382 Homework 3 Solutions1.Solution:ME 382 Fall 2010 HW3 Solutions2.Solution:Page 2ME 382 Fall 2010 HW3 Solutions3.Solution:Page 3ME 382 Fall 2010 HW3 Solutions4.Solution:Page 4ME 382 Fall 2010 HW3 Solutions5.Solution:Solution:Solution:Page Michigan - ME - ME382 ME 382 Fall 2011 HW04 SolutionsProblem 1: Dowling 7.8Given: = 150 = 30 = 45 SF=3.0 2 + 2 + 1 , 2 = 22Plugging in given values gives:1 = 165 , 2 = 15 , 3 = 0 (a) Tresca (maximum shear stress) criterion: = max(|1 2 |, |2 3 |, |3 1 |)|1 Michigan - ME - ME360 Lab 7: Scaling Laws and ME395, Fall 2011 Prof. Kenn Oldham 11/14/11 Scaling Laws Virtually all physical phenomena depend on dimensional scaling, with respect to length, mass, and Kme. Boeing 747 F16 Beech Bonan Michigan - ME - ME360 International Pumping Systems313 Heinz Rd., Dearborn, MI 48124To:B. Franklin, P.E., Consulting Division ManagerInternational Pumping Systems313 Heinz Rd., Dearborn, MI 48124From: L.A. Larson, Project ManagerDate: 11/14/2011Re:Motor Sizing for Oxy Michigan - ME - ME360 International Pumping Systems313 Heinz Rd., Dearborn, MI 48124To:From:Subject:Date:Dist:L.A. Larson, Project Manager, First Response Technologies91 Greentree Dr., Suite 1A, Chicago, IL 60613Joshua DeBoer, EngineerFlow properties and recommended Michigan - ME - ME360 Model: PX653-25D5VRange: 0-25 in-H2O Michigan - ME - ME360 H)H2&amp;H70I;5:11(IrcII112VIIc.IIIH0bIIIiHcDc-HC,I-Cr-;,(ccICc-vsrdIN\J1t)--14v)0)-IIUD(Oci/_C)0CD3H/Th-4c-I)0S.)c-i z2C;Oj)C-4-cJUI)c-C)vi0-D-c--C)2(%)N-I--IN Michigan - ME - ME360 Pc )ler\cw\Ac.cSsoM/4-c,cCoC(\4LLk-.q.-c4ftQVcc1c rzc.)-/4ev\ 10e Src2,.e,Lv\s%_b,el vwtvX Sx)thaciA(i1pmDP1WJLI-/-Cj.,ILL C)c)c7--4-L.:ccLe:1Lo-L_ -c4 .4-LkLcs-iv5 +YO-C1Cx-CVV\MeL-r\sYVS:X Michigan - ME - ME360 r--r--14_+(1(4Y-q_\(J-J%JIQ:,cq--N.%J4fl%l.JJrri+pt-\_)Ii-pq:*-(_+)-IV\J0c-)q)0rif1I)Ctv(;-1&gt;0(/1HJ-4H41Mc1Ce)3(cH&gt;CIji0I!i.:?:rcHI,HIC_,-+,G(,141k,!0a,(3- Michigan - ME - ME360 tJ (QS&amp;Lf .d_o9i L-Os-t\4YC;o)c_i: o.7pILy\ZyO,;-(a(.tO1b7OZ7SC1(O//IS(,&amp;.4t4k scsfC:100C.cAC,-1-C,NIJf19)0iIcrI-CI,IU%J9-)x,-&gt;E,fl1)\UU04-t41JV.t/-,kcj00N3,-xL5I?_fl%q11 Michigan - ME - ME360 cLEc_)f2t1?-R;L4c:0XZ-vs C r-L:N11qEIf\Sis44L;fYLet4CL t-iC-s L-o);=rAFiey14A_oz:pDbV:-e) Lc.-vsLJ$Fc:L-)o1) TLc-(J0V\k-4-CsVs-.-/IraF2L ri-1(s;i.Lelr-c7(J0/L/-Cs(\Jo)-\J_v -V sV
Michigan - ME - ME360
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Michigan - ME - ME360
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Michigan - ME - ME360
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Michigan - ME - ME360
o14RC 3s-:\it)_-(iTC57Z ;pssifczt:&amp;5(e .);kv;;(z)=1gL (A s4f)=fL?,M(4zA,-1o\e4s4LLAks44-e.I)2hL-_-S+SZJ F-ciVcv\LA(.iIq10Pv;4CD(L.-Z1l4Sc1-r cj4So-o:-:uL)c,:L-soQ(C)cO74(cyD.zz
Michigan - ME - ME360
ME 360Fall 2011NameQuiz 0 (Not for credit)For the system at right, find a differential equation with x(t) as output andF(t) as input.
Michigan - ME - ME360
ME 360Fall 2011NameQuiz 1For the system at right, find differential equations with outputsx1(t) and x2(t), and inputs F1 and F2. There are two dampers withdamping b, and one spring with stiffness k.Notes:By flipping x1 horizontally, the displaceme
Michigan - ME - ME360
ME 360Fall 11 9/13/11NameQuiz 2Consider the differential equation + 5 x + 6 x = 6 1( t ) , with a unit step input and initial conditionsx()()x 0 = 0 , x 0 = 0 . (Unit step is zero for t &lt; 0 , and one for t 0 .)a. Find the solution to the differen
Michigan - ME - ME360
ME 360Fall 11 9/20/11NameQuiz 3The system at right consists of two masses and two dampers and av1v2prescribed velocity as input.a. Find a differential equation for the system, with prescribedM1M2velocity v2(t) as input, and velocity v1 as outpu