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Course: CHEM 1212, Fall 2011School: Kennesaw
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1212
Rate CHEM Law Practice
For a reaction of:
2 H2 + C2H2 C2H6
You have the following experimental data:
Rate
0.150
2.400
2.400
[H2]
0.0100
0.0100
0.0300
[C2H2]
0.0100
0.0400
0.0400
1. Determine a rate law for the above reaction including a value k.
2. for Which chemical in the reaction does the term rate describe?
3. Solve for the units of k?
4. Solve for the rate of the reaction if [H2] = 0.250 M and [C2H2] = 0.250.
5. What is the initial rate of H2 under the conditions in problem 4?
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Kennesaw - CHEM - 1212
Reaction Mechanism Practice1. Determine if the reaction mechanism below is plausible for the overall reaction: A + 3 B CB + B D [slow]A+DEB+ECGiven the following experimental data: The elementary steps do add up to the overall reaction mechanism (D
Kennesaw - CHEM - 1212
D ue:2l4ll0Chapter1 6 P ractice. Usethe folRate(mol/L-s)rq 0.0800.720t,2.880vt t/0.080t,3.6000.160Ztt.,Seco.ri'fnrrnqfinntH2l(mol/L)0.01r0.010.01 I^I0.02v0.010.02q rate l* td e r r e l n n a r c t e l c aw[CoHr+](mol/L)0.02r,
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CHEM 1212Review of Chem 1211 material:1. How many moles are in 21.3 g of O2?21.3 g * (1 mol / 32 g) = 0.666 mol of O22. Balance the chemical reaction:Al + O2 Al2O3What is the mass of O2 needed to react 72 g of Al? What is the mass of Al2O3 formed?4
Kennesaw - CHEM - 1212
Chem 1212Test 1Form APERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
Chem 1212Test 1Form BPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
CHEM 1212Test 2Form CPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA18VIIIA1H2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
CHEM 1212Test 2Form DPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA18VIIIA1H2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
CHEM 1212Units of Concentration / Colligative Properties1. For a solution that has 28 g of FePO4 dissolved in water, the total mass of solution is 1.350 kg.What is the molality of this solution?2. Assume the above solution has a density of 1.10 g/mL.
Kennesaw - CHEM - 1212
Vapor Pressure Calculations1. Given that a substance has a vapor pressure of 85 torr at 15 Celsius, solve for the vaporpressure at -15 Celsius. The Hvap = 65 kJ/mol for this substance.ln (P2 / 85) = (65000 / 8.314) * (1 / 258.15 1 / 288.15)ln (P2 / 85
Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
1C hapter 8 R eactionsiabof orWriter eactions e ach f t he f ollowing ehavingsa n a cido r a b ase n w ater:CH3NH2B n'n( gtilHrn+ c H-ufirNrlr+H^A-CeHsCOOH(rH, C ooH+-?L 1r0( rHurco-+ l -li7r,4r,JCa(OH)zneedt o w rite t wo r eactions][C
Kennesaw - CHEM - 1212
C HEM 2I2LpH p ractice ndw eaka cidsa1.A s olutionsf oundt o h ave[ HgO.J2 .5* ] .0-10. olveor t he [ OHl, p Ha ndp OHo f=iSft hiss olution.thiss olution cidic r b asic?ao= l '/o-tLonl= Y o-"12't'[o-olaH= ( -qo=F H ? 'aa2' W hen L 2.5
Kennesaw - CHEM - 1212
C hapter1 8 P ractice=HCN( Ka 6 .2 * 1 0-10)(C6H5NH2Ku= 4 .0 * 1 0-10)1. S olveor t he p Ho f a 0 .0160 s olution f H CN.fMo*H(Al H,o+H.o+ c ilaoo,0l 6-x+X0.olb-/xxtx2. S olveor t he p Ho f a 0 .0160 s olution f N aCN.fMoCIV-*Hzo > H
Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
H arder cidB aseP roblemsA=1(Kb CSH5N) .7 cfw_ ' 1 0-s1s orverorthe* "i:";:,ii;:j:ii[:r"J'iiTz':rt - / ./o'*^A'7=;J;vr ,or : ( 5/.rvc/ [ r; r ,af_0 ",6'-' c, l s M + H ro.l r, -o'c , ,1,-;o .o2i/6o5oos -sy)./oi . .#;ooio'knt5.6il./o-"
Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
CHEM 1212Test 3Form APERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
Chem 1212Test 3FormAPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.0
Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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Kennesaw - CHEM - 1212
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