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### Rate%20Law%20Practice

Course: CHEM 1212, Fall 2011
School: Kennesaw
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Coursehero >> Georgia >> Kennesaw >> CHEM 1212

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1212 Rate CHEM Law Practice For a reaction of: 2 H2 + C2H2 C2H6 You have the following experimental data: Rate 0.150 2.400 2.400 [H2] 0.0100 0.0100 0.0300 [C2H2] 0.0100 0.0400 0.0400 1. Determine a rate law for the above reaction including a value k. 2. for Which chemical in the reaction does the term rate describe? 3. Solve for the units of k? 4. Solve for the rate of the reaction if [H2] = 0.250 M and [C2H2] = 0.250. 5. What is the initial rate of H2 under the conditions in problem 4?
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Kennesaw - CHEM - 1212
Reaction Mechanism Practice1. Determine if the reaction mechanism below is plausible for the overall reaction: A + 3 B CB + B D [slow]A+DEB+ECGiven the following experimental data: The elementary steps do add up to the overall reaction mechanism (D
Kennesaw - CHEM - 1212
D ue:2l4ll0Chapter1 6 P ractice. Usethe folRate(mol/L-s)rq 0.0800.720t,2.880vt t/0.080t,3.6000.160Ztt.,Seco.ri'fnrrnqfinntH2l(mol/L)0.01r0.010.01 I^I0.02v0.010.02q rate l* td e r r e l n n a r c t e l c aw[CoHr+](mol/L)0.02r,
Kennesaw - CHEM - 1212
CHEM 1212Review of Chem 1211 material:1. How many moles are in 21.3 g of O2?21.3 g * (1 mol / 32 g) = 0.666 mol of O22. Balance the chemical reaction:Al + O2 Al2O3What is the mass of O2 needed to react 72 g of Al? What is the mass of Al2O3 formed?4
Kennesaw - CHEM - 1212
Chem 1212Test 1Form APERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
Chem 1212Test 1Form BPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
CHEM 1212Test 2Form CPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA18VIIIA1H2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
CHEM 1212Test 2Form DPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA18VIIIA1H2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
CHEM 1212 PracticeThis is only to help you prepare for the upcoming test. Of course you should bereviewing and using all available resources for your preparation.1. Determine the rate law when given the following data (at 25 Celsius):3 A(aq) + 2 B(aq)
Kennesaw - CHEM - 1212
The Test 2 ReviewChapters 16 and 17ReviewGiven a reaction:H2 + Cl2 2 HClRate0.001150.001150.018400.01840H2 (mol/L)0.1480.1480.5920.592Cl2 (mol/L)0.2150.4300.2150.215Solve for the rate law including a value for k with the appropriate un
Kennesaw - CHEM - 1212
CHEM 1212Units of Concentration / Colligative Properties1. For a solution that has 28 g of FePO4 dissolved in water, the total mass of solution is 1.350 kg.What is the molality of this solution?28 g of FePO4 * ( 1 mol / 150.82 g) = 0.1857 molm = 0.18
Kennesaw - CHEM - 1212
CHEM 1212Units of Concentration / Colligative Properties1. For a solution that has 28 g of FePO4 dissolved in water, the total mass of solution is 1.350 kg.What is the molality of this solution?2. Assume the above solution has a density of 1.10 g/mL.
Kennesaw - CHEM - 1212
Vapor Pressure Calculations1. Given that a substance has a vapor pressure of 85 torr at 15 Celsius, solve for the vaporpressure at -15 Celsius. The Hvap = 65 kJ/mol for this substance.ln (P2 / 85) = (65000 / 8.314) * (1 / 258.15 1 / 288.15)ln (P2 / 85
Kennesaw - CHEM - 1212
Vapor Pressure Calculations1. Given that a substance has a vapor pressure of 85 torr at 15 Celsius, solve for the vaporpressure at -15 Celsius. The Hvap = 65 kJ/mol for this substance.2. In the above problem, solve the temperature (in Celsius) where th
Kennesaw - CHEM - 1212
Chapter 18 PracticeHCN (Ka = 6.2 * 1010)C6H5NH2 (Kb = 4.0 * 1010)1. Solve for the pH of a 0.0160 M solution of HCN.2. Solve for the pH of a 0.0160 M solution of NaCN.3. Solve for the pH of a 0.0160 M solution of C6H5NH24. Would a salt of C6H5NH3CN b
Kennesaw - CHEM - 1212
Chapter 18 ReactionsWrite reactions for each of the following behaving as an acid or a base in water:CH3NH2C6H5COOHCa(OH)2 [need to write two reactions]NH4NO3KCH3COO
Kennesaw - CHEM - 1212
Acids and Bases18.1 18.3From Chem I Acids are anything that donates an H+ ionin waterThe H+ ion is usually stabilized by a water moleculeand is often written as H3O+ Bases are anything that donates an OHion in water Well be expanding these definit
Kennesaw - CHEM - 1212
Weak Acids/Bases18.4 18.6Last time General equations:HA(aq) + H2O(l) H3O+(aq) + A-(aq)KaFor weak basesB(aq) + H2O(l) BH+(aq) + OH-(aq)KbStrong bases are usually BOH B+ + OH-Weak acids and bases disassociate only partly,they reach equilibriumWe
Kennesaw - CHEM - 1212
Making Acids out of Nothing atAll18.7, 18.9From Chem 1 Salts are any ionic compound Cation Positive charge Metal (left side of periodic table) Or NH4+ Anion Negative charge Non-metal (right side of periodic table) Or polyatomic ions (SO42-, Cr
Kennesaw - CHEM - 1212
Name _Homework: More Acid-BaseHClO (Ka = 2.9 * 108)NH3 (Kb = 1.76 * 10-5)1. Identify the conjugate base of HClO.2. Solve for the pH of a solution that is 0.150 M of HClO.3. Solve for the pH of a solution that is 0.150 M of LiClO.4. Would a solution
Kennesaw - CHEM - 1212
Buffer Solutions18.9, 19.1, 19.2Recap of SaltsPossible situations:Probably GivenSalt isCation conj. of strong baseAnion conj. of strong acidNothingNeutralKb of the weak baseAcidic[turn Kb into Ka tosolve]Ka of the weak acidBasic[turn Ka in
Kennesaw - CHEM - 1212
Titrations19.219.2 Acid-Base titrationsIndicators: weak acids or bases thatchange color as they switch to theconjugate: HIndic IndicMost people use pH meters nowTitration curveStrong Acid w/Strong BaseTitration curvesIn a strong acid-strong base
Kennesaw - CHEM - 1212
Equilibrium goes to Solutions19.3 skip 19.419.3 Slightly Soluble Recall solubility rules These things are soluble, everything elseis insoluble Well, there is no completely insoluble, itsjust that very, very little dissolves Dissolution reaction (l
Kennesaw - CHEM - 1212
Harder Acid Base ProblemsKb (C5H5N) = 1.7 * 1091. Solve for the pH of 13.5 g of C5H6NCl dissolved in 4.5 L of water.2. If 2.5 g of KOH is added to the solution in question 1, determine the pH of the solution.3. If 5.0 g of KOH is added to the solution
Kennesaw - CHEM - 1212
CHEM 1212Name _pH practice and weak acids1. A solution is found to have [H3O+] = 2.5 * 1010. Solve for the [OH], pH and pOH of thissolution. Is this solution acidic or basic?2. When 12.5 g of NaOH are dissolved into a 5.00 L container, solve for [H3O
Kennesaw - CHEM - 1212
CHEM 1212Name _pH practice and weak acids1. A solution is found to have [H3O+] = 2.5 * 1010. Solve for the [OH], pH and pOH of thissolution. Is this solution acidic or basic?2. When 12.5 g of NaOH are dissolved into a 5.00 L container, solve for [H3O
Kennesaw - CHEM - 1212
PL Worksheet #918.1 Acids and Bases in Water1. Given the reaction below, if there is initially 0.500 M HBrO, solve for the concentration ofH3O+ at equilibrium.HBrO (aq) + H2O (l) H3O+ (aq) + BrO (aq)K = 2.3 * 1092. The pH of a solution is defined as
Kennesaw - CHEM - 1212
PL Worksheet #1018.2 pH scale1. For a sample of 0.35 kg of KOH, dissolved in 1.58 L of water. Solve for the [H3O+], [OH],pH and pOH of the resulting solution.2. What mass of HClO4 is needed to make an 825 mL solution that has a pH of 1.5?3. What mass
Kennesaw - CHEM - 1212
PL Worksheet #1118.3 &amp; 18.4 Conjugate Pairs and pH Calculations1. Solve for the pH of C6H5NH2 if 195 g are dissolved in 1.500 L of solution.Kb (C6H5NH2) = 4.0 * 10-102. Identify the conjugate acid of C6H5NH23. Solve for the Ka of this conjugate acid
Kennesaw - CHEM - 1212
PL Worksheet #1219.1 Buffers1. Solve for the pH of a solution that has 0.10 M of NH3 and 0.14 M of NH4Cl.The Kb(NH3) = 1.76 * 105.2. Solve for the pH of the solution once 2.5 g of KOH has been added to 1.00 L of the solutiondescribed in question 1.3
Kennesaw - CHEM - 1212
1C hapter 8 R eactionsiabof orWriter eactions e ach f t he f ollowing ehavingsa n a cido r a b ase n w ater:CH3NH2B n'n( gtilHrn+ c H-ufirNrlr+H^A-CeHsCOOH(rH, C ooH+-?L 1r0( rHurco-+ l -li7r,4r,JCa(OH)zneedt o w rite t wo r eactions][C
Kennesaw - CHEM - 1212
C HEM 2I2LpH p ractice ndw eaka cidsa1.A s olutionsf oundt o h ave[ HgO.J2 .5* ] .0-10. olveor t he [ OHl, p Ha ndp OHo f=iSft hiss olution.thiss olution cidic r b asic?ao= l '/o-tLonl= Y o-&quot;12't'[o-olaH= ( -qo=F H ? 'aa2' W hen L 2.5
Kennesaw - CHEM - 1212
C hapter1 8 P ractice=HCN( Ka 6 .2 * 1 0-10)(C6H5NH2Ku= 4 .0 * 1 0-10)1. S olveor t he p Ho f a 0 .0160 s olution f H CN.fMo*H(Al H,o+H.o+ c ilaoo,0l 6-x+X0.olb-/xxtx2. S olveor t he p Ho f a 0 .0160 s olution f N aCN.fMoCIV-*Hzo &gt; H
Kennesaw - CHEM - 1212
C HEMI 2I2Straight-forward BuffersEquationspH: - l og [ H3O*]p Ku: - l ogK u/ a- \p H = p K, + l oglH A J- [ :. I&quot;Consider 1 .0L b uffers olution hati s 0 .10M H NOza nd0 .10M N Ozat* 1 0-aTheK uo f H NOzi s 4 .51. B eginb y l abeling he w ea
Kennesaw - CHEM - 1212
H arder cidB aseP roblemsA=1(Kb CSH5N) .7 cfw_ ' 1 0-s1s orverorthe* &quot;i:&quot;;:,ii;:j:ii[:r&quot;J'iiTz':rt - / ./o'*^A'7=;J;vr ,or : ( 5/.rvc/ [ r; r ,af_0 &quot;,6'-' c, l s M + H ro.l r, -o'c , ,1,-;o .o2i/6o5oos -sy)./oi . .#;ooio'knt5.6il./o-&quot;
Kennesaw - CHEM - 1212
CHEM 1212Straight-forward BuffersEquations A pH = pK a + log HA Consider a 1.0 L buffer solution that is 0.10 M HNO2 and 0.10 M NO2The Ka of HNO2 is 4.5 * 10-41. Begin by labeling the weak acid and the conjugate base:pH = - log [H3O+]pKa = - log
Kennesaw - CHEM - 1212
CHEM 1212Test 3Form APERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
Chem 1212Test 3FormAPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA1H18VIIIA2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.0
Kennesaw - CHEM - 1212
CHEM 1212Test 3Form BPERIODIC TABLE OF THE ELEMENTS1IA2IIA3IIIB4IVB5VB6VIB7VIIB8-9VIIB10-11IB12IIB13IIIA14IVA15VA16VIA17VIIA18VIIIA1H2He1.0084.0033Li4Be5B6C7N8O9F10Ne6.9419.01210.8112.0114.
Kennesaw - CHEM - 1212
Test 3 PracticeStrong Acids1. Solve for the [H3O+] and pH of 0.45 M NaOH.Weak Acids2. Solve for the pH of 0.23 M HClO with Ka= 2.9 * 1083. Solve for the 0iss aboveBuffers4. Solve for the pH of a buffer made of 1.00 L of 0.10 M HNO2 and 0.10 M NO2.
Kennesaw - CHEM - 1212
CHEM 1212 Test 3 ReviewStrong Acids- HCl, HBr, HI, HClO4,HNO3 and H2SO4-Solve for pH-Negligible conjugate baseWeak Acids-Have Ka-Solve for pH-Solve for % diss.-Has a conjugate base(Kb = Kw/Ka)Buffers-weak acid with conjugatebase-solve for p
Kennesaw - CHEM - 1212
Test 3 TopicsChpts 18 and 19Solubility and common ion effectGiven the following Ksp values, providethe order that Sr2+, Ca2+ and Ag+ willprecipitate out of solution when IO3- isadded to the solution?Ksp valuesSr(IO3)2 = 3.3 * 10-710-7AgIO3 = 3.1
Kennesaw - CHEM - 1212
Write a neutralization reaction for HClO with NH3HClO (aq) + NH3 (aq) -&gt; NH4+ (aq) + ClO- (aq)It helps to identify what the acid is and what the base is in the reactants to determine theproducts. Once the acid is identified, just have it give the H+ t
Georgia Perimeter - HIST - 1112
Quiz#1 WHist Chptr 14 (1112-200 Spring 2010)Name_True/False each is worth (1) pointIndicate whether the sentence or statement is true or false._F_ 1. Portugal called itself the Celestial Kingdom._F_ 2. Spain was the first European Country to begin th
Georgia Perimeter - HIST - 1112
Quiz#2 Chptr 18 1112-200 Spring 2010Name_True/False: each is worth (1) point total 10Indicate whether the sentence or statement is true or false._T_ 1. The overall influence of the Enlightenment was limited as rulers liked the ideas but the political
Georgia Perimeter - HIST - 1112
Quiz#3 Chapter 20 Whist1112-200 Spring 2010Name_True/False: each true false is worth (1) point each total (5) pointsIndicate whether the sentence or statement is true or false._T_1. The Crimean War 1854-1856 involved Turkey (Ottoman Empire) and Russi
Georgia Perimeter - HIST - 1112
Quiz#4 Chptr 27 1112-200 Spring 2010Name_True/False: each is worth (1 point) total 10 points.Indicate whether the sentence or statement is true or false._F_ 1. After Josip Tito died Yugoslavia maintained its strong united federation to the present tim
Georgia Perimeter - HIST - 1112
Test#2 WHist1112-200 Chapter 23 Spring 2010Name_True/False: Each is worth (2 points) total 10 pointsIndicate whether the sentence or statement is true or false._T_ 1. The reason for the outbreak of War in 1914 was not the assassination of Archduke Fer
Georgia Perimeter - HIST - 1112
Test#3 Chptr 25 1112-200 Spring 2010Name_True/False: each worth (4)points total 20 points.Indicate whether the sentence or statement is true or false._T_ 1. Hitler looked up to Mussolini until the outbreak of W.W. II when Hitler eclipsed Mussolinias
Georgia Perimeter - HIST - 1112
Test#1 Chapter 19 W.HIST1112-200 Spring 2010Name_True/False: each is worth (2) points total 20 pointsIndicate whether the sentence or statement is true or false._T_ 1. Napoleon with a group of officers overthrew the Directory; he was declared 1st Cons
Georgia Perimeter - HIST - 1112
The Scientific Revolution and its role in Europe.History 1112 200January 20, 2010Juan D. TorresMr. Allan R. JonesHerbert Butterfield stated that, &quot;Since the Scientific Revolutionoverturned the authority in science not only of the middle ages but of
Georgia Perimeter - HIST - 1112
The Columbian Exchange: the best and worst of globalization.History 1112 200January 20, 2010Juan D. TorresMr. Allan R. JonesEven though very important exchanges processes have occurred throughoutworlds history, the Columbian Exchange was, without do
Georgia Perimeter - HIST - 1112
European AbsolutismHistory 1112 200February 10, 2010Juan D. TorresMr. Allan R. Jones&quot;L'tat c'est moi.&quot; The well-known maxim of Louis XIV of France resumesthe essence of absolutism: a political system in which a person, the sovereign,exercised an ab
Georgia Perimeter - HIST - 1112
A monarchy in the strict sense of the term is a state ruled by a single absolutehereditary ruler. A constitutional monarchy, however, is a state headed by a sovereignwho rules according to the constitution. Such constitution must be written and codified
Georgia Perimeter - POLS - 1101
Juan TorresExtra Credit PaperOn February 11th I assisted to a conference about peace building on theDunwoody Methodist church. On that conference, the speaker focused on developingall the main concepts peace building implies. The first concept the spe
Georgia Perimeter - POLS - 1101
1. The show I watched was msnbc January 29th Hardball with Chris Matthews. Host ChrisMatthews invited two political analysts, Michelle Bernard from msnbc and Anne Kornblut fromThe Washington post.2. The journalist analyzed Obamas visit to the republica
Georgia Perimeter - POLS - 1101
1.Who they are: The Federation for American Immigration Reform (FAIR) is a national,nonprofit, public-interest, membership organization of concerned citizens who share a commonbelief that immigration policies must be reformed to serve the national inte
Georgia Perimeter - POLS - 1101
1. The bill I choose is the Foreign Relations Authorization Act, Fiscal Years 2010 and2011 sponsored by Rep. Howard Berman. It was introduced to the House ofRepresentatives in May 14, 2009. This bill had 27 proposed amendments before beingpassed by the
Georgia Perimeter - POLS - 1101
TV Series:&quot;CSI: Miami&quot; 28 April 2003 (Season 1, Episode 21)It is Spring break time in South beach. Miami is full of students looking for fun without mindingthe rules much and without mending the law at all. After a huge beach pool party, two studentsw
Georgia Perimeter - POLS - 1101
1. The issues that inspired this cartoon are the recognition and later apologize ofthe Republican Party members such as Mark Sanford, David Vitter, JohnEnsign or Larry Craig to their Republican colleagues for the extramaritalaffairs all of them have r
Georgia Perimeter - POLS - 1101
1. You know that in the United States the 10 smallest, by population, control 32 electoralvotes. It means that those 10 states have the 6% of the votes in the Electoral College, yettheir population is 7.6 million, or 2% of the national total. Therefore,
Georgia Perimeter - POLS - 1101