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Course: CHEM 122, Fall 2010
School: Simon Fraser
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LECTURE: Electrochemistry "The L,\.TODAY'S study of the interchange of chemical and electrical enerry" "Electrochemistry" (Chapter 11) l) > Reduction-Oxidation (Redox) Reactions (rxns involving the transfer of electrons) Galvanic Cells -> 2 Processes 2) Standard Reduction Potentials 3) Standard Hydrogen Electrode O the generation of an electric current...

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LECTURE: Electrochemistry "The L,\.TODAY'S study of the interchange of chemical and electrical enerry" "Electrochemistry" (Chapter 11) l) > Reduction-Oxidation (Redox) Reactions (rxns involving the transfer of electrons) Galvanic Cells -> 2 Processes 2) Standard Reduction Potentials 3) Standard Hydrogen Electrode O the generation of an electric current from chemical reaction a @ the use of electric current to produce chemical change Important applications: . . . Batteries Corrosion prevention Commercial electrolyticprocesses 2 Redox processes 1) Separate For the redox reaction: zr{A> . two half reactions\-, 2) Link metals (electrodes) + Ct}*(aq) -+ Zr**(aq1 + J- Current @- flow) Cri'1s) Znmetal Oxidation reaction: Zn(s) half -+ Generating Gurrent Cu Metal Z**(aq) + 2e- (loss of electrons) + Increase oxidation number . Reduction half reaction: Ct*(aq)+ 2e-+ Cu(s) (gainof + . electrons) Reduced oxidation number Spontaneous reaction: Put Ztncmetalrn CrP* solution -+ coppermetal Zn: reducing ZnSOu(aq) solution CuSOo(aq) solution -+Znz* + -+ SO42- (1M) Cu2+ Oxidation occurs at Reduction occurs at (Zn electrode) Anode Cathode (Cu electrode) Zn(s) -+ Zr*+(aq) + 2e- A**@q) + 2e- -+ Cu(s) Electrons flow from anode agent (reduces Cu2*) Cu2*: oxidizing agent (oxidizes Zn) + SO42- (lM) + But only for an instant! Charge builds up on each side cathode
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Simon Fraser - CHEM - 122
l)Stop charge build-up+=(Half-cel I potentials)complete circuitPorous Disk or Salt BridgeZ* =measure of how easily species isreduced or oxidisedI atm, 1 M)@ standard conditions (25"C,Al :Zf -+ Ztf* + 2; ;Cu2*+ 2e- -++2) Measure driving for
Simon Fraser - CHEM - 122
Standard Hydrogen Electrode.Standard Reduction Potentialsoih.ta9-?-?6qi?ol-qarFl-ooCan't measure potentials of individualelectrodes directly=Need:Fql-l. -FFlin?de iocioooi tllllttro ioiJeicj?;ii -,'.,.,r.F.:reference for standard reductio
Simon Fraser - CHEM - 122
f'lhtcfw_ 19 +/1'L cLcfw_fl"ryfwtnnu.z^Lr?r" E": - 0-16ft1tt + )e- Fo= - I'6b+ >e;rt(3t,i + >nL*0,te,rvil 3ztf, I 2Al.->E"*t4=Eca+t*417 - E c a'*4*1o.26- (t-66) = +o'JVOOvJnox:-nFL@A = -bx1b+y7" 0"1 = -5>l h-t/rt"tulnr,*t = -nFtrt'l
Simon Fraser - CHEM - 122
Lz+Electrical WorkTODAY'S LECTURE:Galvanic cell reaction"Electrochemistry"=Work is doneBecause: Electric charges (e-s) are movedThe total amount of work done depends on:.1) Work done on each electronElectrical Work:.Cell Potential and Free E
Simon Fraser - CHEM - 122
(v n,L (!rU&'ot^)rylrf\^4.( iS*eAAE = E'-llcd t ).oA)lCt,p,^,*JP'"$?l^-t,A^At-lrCa+hsat-Ivtczh, Wt tL'0 A[ofu"to F"w^4Ld lC+e-)b )vI" c'.2E"=to<zN-) \'u t,n n=Z ?, ->.r.lv->t z6[q1r-t2-hthgcfw_->foVcfu00.5>- C->.iJ) =
Simon Fraser - CHEM - 122
Galculation of EquilibriumGonstants for Redox Reactions.Concentration CellsSame components on each sideNernst equation:Euu= E"-:BUT different concentrationt926rgn@2s"c=: max potential before any current flowsCurrent flows?.=eT flow to eq
Simon Fraser - CHEM - 122
cto;@r+ e- )6G,+-O-O" @2 -)h-L f>tlaL+>.t- o.V'Y>/J'C; +&L,o-(4F== ".'t5lo-blV_\-/lrlo-oto1(:lZ *rl6=:Qlrlryti"eaL:\5.Eew:f rf) -)W -'fn* f W h7,c.)('P- -FluA - o'v>7 VU/,(l-Edrulo'\Y = o.fitf /]r,l -xlo-fu*,nt Ye(
Simon Fraser - CHEM - 122
L*TBatteriesStore chemical energFTODAY'S LECTURE:"Electrochemistryl'..Batteries+ release electrical enerry when needed.Based on Galvanic cell:" 2 electrodes" Appropriate electrolye.(conducting medium)Several cells in series:Etotut: X (E f
Simon Fraser - CHEM - 122
Car Battery. 5lcrd-=ilaelb in seriesb-)6 x 2.02 V:12Dry Cell BatteriesVNon-liquid electrolyte-.SM6mh^cfw_zire inmrcas)Leclanch6 cell.Mncfw_)'t,2NH4+flows from Battery to Starter MotorEcertxSponmeous Galvanic cell reaction:Pb+Ptoz+ 2II
Simon Fraser - CHEM - 122
Car Battery. 5lcrd-=ilaelb in seriesb-)6 x 2.02 V:12Dry Cell BatteriesVNon-liquid electrolyte-.SM6mh^cfw_zire inmrcas)Leclanch6 cell.Mncfw_)'t,2NH4+flows from Battery to Starter MotorEcertxSponmeous Galvanic cell reaction:Pb+Ptoz+ 2II
Simon Fraser - CHEM - 122
Gorrosion of lronCorrosionRustingCorrosion = oxidation of a metal:Electrochemical process(not direct oxidation)Electrochemical processzP:O2+2H2O + 4e- -+ 4OH-+0.40vEasity corroded metals: E"(metal) < F(Oz)Nonuniformity in metal ->Anodic regi
Simon Fraser - CHEM - 122
Steel Gorrosion PreventionSteel: alloy: Fe + C (0.02 -TODAY'S LECTURE:"Electrochemistry".ElectrolysisRusting of steel = rusting of ironFe _+._8":Fd* + 2e-_(_0.44 V)Methods for preventing steel corrosion:..Corrosion prevention.1.7%) + Mg,
Simon Fraser - CHEM - 122
Electrolysis andElectroplatingElectrolysis+Production of AluminumAluminumCan't use aqueous solution of Al3*E:-t.66VAl3*+3e-+Al- which "plates out" first?4HrO + 2e' -> 2Hz+E :0.80VAg*+t-+Agcu2*+2t+cu E:0.34YZn2* +?n- -+7a, E :4.76V=otherme
Simon Fraser - CHEM - 122
Topics and Textbook SectionsMark AssignmentsChemical Kinetics: Chapter l5-Whole chapterTotalChemical Equilibrium: Chapter 6-NOT6.9Solubility Products: One part of Chapter-Only 8.8-8up to and including "Common Ion Effect"Acids and Bases: Cha
Simon Fraser - CHEM - 122
Acids and BasesMain problems: ( Fr- 1t't tu / e'Eguilibrium. pH calculations:Main problems:. Calculating Q, K and K,. Equilibrium calculations t Approx.. Le Ch6teliers principle. Kro calculations- Strong acid/base- Weak acid,/base- Polyprotic a
Simon Fraser - CHEM - 122
Acids and BasesMain problems: ( Fr- 1t't tu / e'Eguilibrium. pH calculations:Main problems:. Calculating Q, K and K,. Equilibrium calculations t Approx.. Le Ch6teliers principle. Kro calculations- Strong acid/base- Weak acid,/base- Polyprotic a
Simon Fraser - CHEM - 122
CHEM 122 Practice Questions for Final examKineticsl.The reaction of (CH3)3CBr with hydroxide ion proceeds with the formation of (CH3)3COH.(CH3[CBr(aq)+ OH-(aq) -+ (CHr),COH (aq) + Br(aq)The following data were obtained at 55"C.[cfw_CH3)3CBr]sExp.I
Simon Fraser - CHEM - 122
kfonlt/Fi[* lffi"rr (R = 8 3I4 J/mor' K )ffi:ll:l il:1"ffi'il:;a; li:' r*:nH:T:lllnTtrilsl;]ffi"T iffi:frifiJ45.6a) S.OOe) 18.3c\,RrT[ForqelOl(g) =: 2H20tgfIt'uiitthe reaction Zttz(e)+o^y,RT)T?+K andthe relationship between?fl:ri,t
Simon Fraser - CHEM - 122
0r$-tolv'Acid Base9. A monoprotic weak acid when dissolved in water is 0.92o/oCalculate K" of the acid.-bwrr)dissociated and produces a solutionpHwithHt+ A-HAc',& =Si:itj0.Dt&410.A 0.10-mol sample ofK"2 is 1.0u) t.o*lo-5Mc) 0.40 r+ H-
Simon Fraser - CHEM - 122
AE=c w'1/15. rn an isothermal process, the pressure on oneto 100.0 afrnat25"C.-or. oru.da&n*"*"i" *rffii"lil*.5;-cfw_*fv, -v) =I)-vi)Calculate w.LV nvt=>( (n nf)*;,'*c)od) -23.5 kJe) 23.5 kJ4'00 atmmole of an ideal monatomic gas suddenly
Simon Fraser - CHEM - 122
aQ"=-Fcfw_.e.&P l-scfw_1,21. For a particular reaction the equilibrium constant is 1.50 x l0-2 at 370'C and AI1" is +16.0kJ at 25"C. AssumingAFl' and l^9' are temperaturealculare A,s' for th.a) -18.8 J/Kin6ffi;".;.(B)-ro.o ln<tJ-n-flAIc = -&)
Simon Fraser - CHEM - 122
25. The reduction potentials for Au3* and Ni2* are as follows:: +1.50 VE :4.23 YAunN +U- i2* 2e- -+ NiRAur* + 3e- -++t = t.\-L'o't)E"t.Jz",t.Calculate AGo (at 25'C) for tre reaction:3Ni-+ 3Ni2* + 2Au2Au3* +b= -nFE"rd),D0"a)-2l40kJb) +5.
Simon Fraser - CHEM - 122
25. The reduction potentials for Au3* and Ni2* are as follows:: +1.50 VE :4.23 YAunN +U- i2* 2e- -+ NiRAur* + 3e- -++t = t.\-L'o't)E"t.Jz",t.Calculate AGo (at 25'C) for tre reaction:3Ni-+ 3Ni2* + 2Au2Au3* +b= -nFE"rd),D0"a)-2l40kJb) +5.
Simon Fraser - CHEM - 122
Answers:1.a2.a3.d4.a5.e6.c7-c8.d9.410. d11. d12.a13. c14. a15. a16. d17.b18. d19. c20. b2t.b22.b23.24.25.26.27.bacda
Simon Fraser - CHEM - 122
.$-eaker bondK.=HFHCIFIBri0rHIl0e10.108stronger acid=1:c'BondSrei:e:h LengthBondDissociationEnersr| |t 1tl i Ilvv L,Bond Polarity.Acid strength also correlates to bond polarityIncreasing acid strengthcH, NH3 HrO ItrIncreasing bo
Simon Fraser - CHEM - 122
i-*r.i\'a l,\Y l'i--1-59oc)sdo=Ed.$,O1r-fIttoor. IoES?',6\J.: t!r6l.L/ rrHilOHqoa'Pt:,')otou!oU$.609JH)p"l:EH.gcfw_"390.iC'F ?I-:-lo-qt\.-. o\trcfw_-1\'-sAJt).(|J/r rNooll5('(_\,\I't'll
Simon Fraser - CHEM - 122
$ltr-l'l\Iti\lnI l-\l^f\ |/\ I.o.to+-.ol\16l-.alrXsesol'E,2vIllgE,,aIE.'I,^t^F'1u.9oHrg<(-;xxvY\o_i-.:$aI'<l-I\)-lN:d'11"-s!a'a./','l/q<t!g'V=x'lxJurJlr3r;1/'tESJs.'=f9odN97tsi-+r6l
Simon Fraser - CHEM - 122
Chem L22 Fall-0g Trtorial 4Question 1-: For the gas phase reaction wO(S)+Or(g) - NOz(S)+Or(S),the following experimental values for the temperature dependance wereobtained:p= O ,-Ea/RITemperature (K) ll 195 na 260 298 396k(x10eL.mol-ls-l)ll1.08
Simon Fraser - CHEM - 122
c) What is k at?:50K?B -+ 3 D' the activationn 2z For the uncatal yzed reaction A + catalyst was added, theQuestiokJ. when aenergy was determined to bL 25what is the ratio of the rate constantactivation energy became 20 kJ.uncatalyzed' reaction?
Simon Fraser - CHEM - 122
Question 4: The following partial pressures were observed for the reac-tion at50OK:2 NH3 (g)*N, (*)'PNH'atm0.01*3H, (*)PNz0.03(3)Puzatm0.01 atma) Calculate the value of K, and the total pressure at 50O K.tr= fry'Pll'IpNHl'-cfw_,+4 f
Simon Fraser - CHEM - 122
Question 5: For the reactionNH4OCONH, (")*-'2 NH3(r)*CO,(*)(5)at 25 oC, the equilibrium constant in terms of activity is 0.03. A certainamount of NH'OCONH, is allowed to come to equilibrium with theabove products. Calculate the total pressure.
Simon Fraser - CHEM - 122
Chem 122 Fa11-09 Week 6, Tutoriall.5Calculate the value of K fbrOz(e)* O(*)<)O:G)given thatNOzG)NO19*O(e)Or(g)* NO(e)K=6.8x10-aeNO21g)* Oz(e)9 +N,t: = lV,Oz tl^lz = r.tC a JgK=5.8x10-34t. cfw_ o x ,"*1-)K = "y, tit' )2. Calculate the va
Simon Fraser - CHEM - 122
3. Consider the decomposition of HOCI at298K2HOCl6y)H2O19 +ClzOlr;K = 0.090If l.200atm of HOCI, 6.000atm of H2O and 5.500atm of CL2O are placedin a vessel and allowed to equilibrate what would be the o/o change in theamount of HOCI?,4"l,z, H0l
Simon Fraser - CHEM - 122
4. Given the reaction<)Fe3'1"4 * A8(.)Fe2.1ud* Ag.(uq)K=1.10x10-2a*'^tCalculate the amount of Ag'("d in moVL in solution if 0.60 M ofand 0.50 M Fe2t1"q; are put into solution with Agt,l.Jc-rXo-JtXc-xE o'6-xoxO.L/(6'r *x) xk=l.lo y /D
Simon Fraser - CHEM - 122
,Ar 1'fFyt?c$'ll* -tucfw_al^r= o'zb1q) =at* -t" -LhPcrcfw_u(1) + U->t!)cfw_ ^i,pe4bwe;Eaccfw_r41n1*l1i*;"^t9W-iX+^'"t2.oo ab^)nx c- 'j-,fdt +CtPalsJr"o()C-XKxtQ-xY=xn-x JYrk- 2.oo?r=-xPv=nKT-)n="ffCr( r.v7q+-)'
Simon Fraser - CHEM - 122
5. consider the followingon'reaction.,-' ta&A e BGl * 2ctt.-b/'fvYkt'"'/.- l^tl^ *t[v^'l#1" * *ihcfw_,/NIIL'"?org)fl;ft,,i14+yrygvo+,l,wn,uFor each of the followiig sets of initiat conditions, a! 25"C, in whichdirection will the reaction p
Simon Fraser - CHEM - 122
+:.EilCiii;E?E=i!=EI9-E. E -e =.t.J ZG o.-6<-_z,. _iti=2 oS.?Y=ao?+il=ts;=*= " F?f3 gfF=+f; f:;?Etafr ziir?:;4=E *li iAn=37;tiEiri?u ? ^:I=*iii+;*'q06=-J'-FII-IqLIFll-l?iI"rT I:;EA I!i ll|c,:lglglI z-"'"r-=1
Simon Fraser - CHEM - 122
\cba\Z,.Nen\ Fos.?fila(E,FtrFo=tf;'=.=C\C\FIE6=E,|lYr?\r-r/-oIrF.()Exdb ._=oq.Sr^-.,OSXo-.EgEEo.=.=88=FEL-'IJJ=I--'FJr(JJ.o-r+.l-Ja.Fcfw_IJJtra'lJ-3=IFzIYJIu=lC)a4>cfw_l-cfw_63r-1odt1>cfw
Simon Fraser - CHEM - 122
&._3$.r-toorl]X-IaJ-AHN)F(D(Dr-tLrlw5F ? 8?8 J6 | ? 5 r.E os.ZFoNg303'P +og -o;a6d.Aii;FI0)rdiatIo3oa,ECLIJg,Ez+iI36'av)\-/-Ecfw_JEIEagsEO)EhEUiJ[B$ IsP.vE'GF;s'8 x s-9lpc)ev) SodX
Simon Fraser - CHEM - 122
(fCoKnrratio.s (ml/L)tJzbJsaJI'JozzzP-OOAld_=.IIo5orh+goF+II0a='!N)ilililooobbbooo3EoaN]oaAAzoNoFA)iltDFtv0qolliivirl.t!doi+cfw_CD(DJr+tiJCDoiJov)CD)(+H.Hi)CDFr.HiJPO\0H.(+
Simon Fraser - CHEM - 122
Ncfw_ILUDecomposition ofTODAY,S LECTURE:2NO2(g) -+ 2NO(g) + Oztg)*REACTION KINETICS'.Instantaneous Rates.NO2Rate LawstDetermining the Rate Law!:o.quMethod of Initial Rateslnstantaneous RatesRate of Product FormationInstantaneous rate of
Simon Fraser - CHEM - 122
Method of lnitial RatesMethod of lnitial RatesExperimental data: Initial, instantaneous ratesWhat if the reaction rate depends on morethan one reactant?Concentration (M)RunRate (decreaseof[No]olHzln[NO]) mol L-r s-rMethod of initial rates:#t
Simon Fraser - CHEM - 122
Lcfw_\The lntegrated Rate LawT.DAY,S LE,CTURE:..,REACTION KINETICS"Differential Rate LawHow rate changes with concentration.lntegrated Rate LawThe Integrated Rate LawHow concentration changes with timeFirst Order Rate LawsFirst-order Rate Proc
Simon Fraser - CHEM - 122
Example: 1"t Order Rate Law2N2O5Questionl:-++ 024NO2.Is this a First-Order Reaction?Question 2: What is the rate constant?Answer: We can't tell without an experiment!+Half-life of lst Order Reactions.Measure how concentration varies with tim
Simon Fraser - CHEM - 122
2ndOrder lntegrated Rate LawSecond-Order Rate Processes1laA + productsDifferential rate law:Rste:-(Ddt4ldt=tAI-[A]oIf [A]o andkareknown, [A] canbe= klAf'calculated at any later timeRearranging,Second-order Integrated Rate Law: equation
Simon Fraser - CHEM - 122
.!rIZero-Order Rate ProcessesTODAY'S LECTURE,REACTION KINETIGS"I.Differential rate law+aAproductsIIiRate.Zero Order Reactions.Rate Law for >1 Reactant.The Isolation Method.- M:klAfo-kdtReaction MechanismslAl:-frr+[A]o_"v2 [A]
Simon Fraser - CHEM - 122
What lf We Have > 1 Reactant?Summary: Kinetics for Reactionsof the TYPe: aA + ProductsFor more complex reactions such as:5\^RaE:lawfRate =klAlRate =vtlAI2l,t!=-rt+lt\ r[z],=-tr+t'['a] k=".frIntegratedRate LawPlot need togive astraight li
Simon Fraser - CHEM - 122
Reaction MechanismsReaction Mechanism:series of steps that make upthe overall chemical reactionGOAL: To determine the reaction mechanism fromexperimental kinetic data that we have measuredOverall mechanism: composed ofa sequenceof"elementary rea
Simon Fraser - CHEM - 122
Rates and Molar RatiosL5ToDAY,S LECTURE:Reaction rate oC-.REACTION KINETICS'..Number of molecules consumedor produced by each reaction stepExample: For the first order reaction2A-+28+CRates and Molar RatiosdTCl.Rates and equilibrium.dtPr
Simon Fraser - CHEM - 122
Pre-equilibriumIn reactions with a fast initial equilibrium step:FastSlowk'k,A+B -i- lntermediate-a>k_rExample: Pre-Equilibrium.Decomposition of Ozone2ot@) -+ProductsExperimentally determined Rate Law:FastRate:DeterminingltcO *, and *-,
Simon Fraser - CHEM - 122
Steady-State Approxi mati ontL$ T.DAY,S LECTURE:Inmultiple step reaction:k,k,A+B _-i* Intermediar"t.REACTION KINETICS'IaproductsCan't choose a rate determining step?Steady-state approxim ation+Temperature Dependence ofReaction Ratesuse"S
Simon Fraser - CHEM - 122
Testing the Rate LawExperimentallySteady-State Approxi mationStep-by-StepVary reactant concentrations -+GOAL: To write the rate law without including anyintermediatesDoes rate law predict experiment result?O High tHzlk2lH2l=>O Write reaction m
Simon Fraser - CHEM - 122
Ghemical ExampleBiological ExampleThermal decomposition of acetaldehydeCH3CHO -+ CFL + CORare = _dtcH_3_cHolDatak) vs 1000I'\700t6mol-t stl0.01l -y7300.0357ffi0_1057m0338100-7E9840t4s 419x llTo>FgU,Yio]Goolrj201000L2-t7
Simon Fraser - CHEM - 122
Gollision Model for KineticsActivation Energyi/7 TODAY'S LECTIJRE:IIINO + NrO -+ NO, +ry.REACTION KINETIGS"IIiI-s,ffi. Collision Model for Kinetics4h\Reaction ProfilesIn this reaction N-O bond must be brokenTransition StatesN-O bond d
Simon Fraser - CHEM - 122
Reaction Profiles andTransition StatesMulti-Step Reaction Profiles. Rate of reaction determined by activationRate of reaction determined by activation energy, Euenergy, E o (and frequency factor, A)(and frequency factor, A).Fgr single step reactio
Simon Fraser - CHEM - 122
EnzymesEnzyme example: GatalaseEnzymes = biological catalystsVery efficient catalysis under bioloeical conditionsDecomposition of hydrogen peroxide (toxic)2HrO, -+ 2H2O + 02Example: Conversion of N, to NH,:Humans: Haber processNatureN2+3H2#flb2N
Simon Fraser - CHEM - 122
Question 3: An "exothermic reaction follows the two step mechanism:A+B -+ CC+D-+E(1)(2)The activation energy for the first step is L25 kJ /mol an for the secondstep is 200 kJ/mol.a) Draw a rough sketch of the reaction profile on the provided graph.
Simon Fraser - CHEM - 122
Relationship between K and KpEquilibrium ExpressionsFor Gases.To describe equilibria involving gases can use:To describe equilibria involving gases usually usepartial pressures instead of concentrationsPartial pressure:independent pressure exerte
Simon Fraser - CHEM - 122
Heterogeneous EquilibriaReactants and/or products in difrerent phasesFrom experiment:Position of heterogeneous equilibria do notdepend on the amounts of pure liquids or solidsWhy? Activities of pure solids & liquids =Example:CaCO3(s)=-CaO(s) + CO
Simon Fraser - CHEM - 122
Equilibrium GalculationsExample 1, Continued.Equilibrium CalculationsExample I6Define change to get to equilibrium and writeexpressions for equilibrium conc.st.O Write balanced equation for reaction:Hr(s)+ rz@) :2HI (g)Lt.c.B.O Write equilibr
Simon Fraser - CHEM - 122
Approximation Method forSmall Equilibrium Constants2NzG)+OzG).= Simpliff:2N2O(g)terrrs in denominator:(0.0482-2x) = 0.0482 (0.0933-x) = 0'0933Q'+t)-' "':l:)&>)-. o.cl3)'.ffisubsurute@checkvalue2X/o-rriro-)ru'is correctdLlsA=g-gygv-ZX