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Purdue - CIVIL ENGI - CE 297
MechanicsPhysical science on the behavior of bodies under the action of forces.I. Rigid Bodies1. Statics (bodies at rest)2. Dynamics (bodies in motion)II. Deformable Bodies - Strength of materialsIII. Fluids1. Hydraulics (incompressible uids)2. Co
Purdue - CIVIL ENGI - CE 297
Scalars and VectorsscalarA physical quantity having only magnitude, not direction.For example, time, distance between two points, mass,speed, kinetic energy, temperature, density and volume.vectorA physical quantity having magnitude and direction.F
Purdue - CIVIL ENGI - CE 297
External and internal forcesExternal forcesThe action of other bodies on the rigid body under consideration.Internal forcesThe forces which hold together the particles formingthe rigid body.CE 2972Principle of transmissibilityA force may be consi
Purdue - CIVIL ENGI - CE 297
Equilibrium of a rigid bodyA body is said to be in equilibrium when the external forces acting on itform a system of forces equivalent to zero.R = F = 0M R = M = (r F) = 0Awhere A is an arbitrary point.In component form, Fx = 0 Fy = 0 Fz = 0 M
Purdue - CIVIL ENGI - CE 297
Center of gravity of a two-dimensional bodyGravitational attraction of the earth on a rigid body, a distributedforce, can be represented by a single equivalent force W applied atthe center of gravity.CE 2972Center of gravity of a two-dimensional bod
Purdue - CIVIL ENGI - CE 297
Analysis of structures Structures are made of several interconnected parts. The total structure and any part of the structure is in equilibrium. Determine reactions Determine internal forces From Newtons third law, the internal forces between two par
Purdue - CIVIL ENGI - CE 297
Laws of dry or Coulomb friction"The physical cause of the resistance offered by friction to the motionof surfaces which slide on each other can be explained either by supposingan interlocking of the roughness of the surfaces, which cannot be separated
Purdue - CIVIL ENGI - CE 297
Moment of inertia of an areaFor linearly-varying distributed loads,Resultant forceR= ky dA = k Ay dA = k Q xAThe first moment of the area about the x -axisQx =y dAAThe first moment of the area about the y -axisQy =Ax dACE 2972Moment of i
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - CIVIL ENGI - CE 297
Purdue - STAT - 511
Homework1_2011Page 1Homework1_2011Page 2Homework1_2011Page 3Homework1_2011Page 4
Purdue - STAT - 511
79. Let A1 = older pump fails, A2 = newer pump fails, and x = P(A1 A2). Then P(A1)= .10 + x, P(A2) = .05 + x, and x = P(A1 A2) = P(A1) P(A2) = (.10 + x)( .05 + x) . Theresulting quadratic equation, x2 - .85x + .005 = 0, has roots x = .0059 and x = .8441
Purdue - STAT - 511
The question about |X| : note that |X| is always non-negative and cannot be symmetric; thisautomatically means that it cannot be normally distributed.
Purdue - STAT - 511
Homework6Page 1Homework6Page 2Homework6Page 3
Purdue - STAT - 511
Homework7Page 1Homework7Page 2Homework7Page 3Homework7Page 4Homework7Page 5Homework7Page 6Homework7Page 7
Purdue - STAT - 511
Homework8Page 1
Purdue - CIVIL ENGI - 398
PIPE IDAVFLOWMNTCEGRADEMATRLACIDITYDURBLTYP 1591611.0312.250.070014.55P 160913.4830.060152.58P 160993.1440.06014.68P 1656315.172.630.0501P 1000110.9432.50.07019.35P 100188.32.50.020115.6530.060013.75.9
Purdue - CIVIL ENGI - 398
Random number from a normal distributionRandom Number between 0 and 1Random Number between 0 and 10Random Number between 5 and 10with mean 100 and std dev 100.268489844.5609751955.60972944481.601403770.0397747135.9956192558.69709545388.7233436
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesQ uestion 1 .(a) Ais defined as a collection of interacting and interrelated objects and rules.(b) Systems monitoring may be described(c) A probab
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesQUESTION 1.(a) A System is defined as a collection of interacting and interrelated objects and rules.(b) Systems monitoring may be described as the
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesQ uestion 1.SOLUTIONS(a) Identify any civil engineering system at any location on campus.(b) Name any 3 performance measures you would use to moni
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesSOLUTIONSQUESTION 1.(a) Identify any civil engineering system at any location on campus.The CityBus public transportation system(b) Name any 3 per
Purdue - CIVIL ENGI - 398
iFORMULA SHEET - C E 398 Fall 2010Please note: You may not need all the formula on this sheet.Basic Probability Formula: p(S) = n(S)/n(U)Application of Set Theory to Probability: p(A u B) = p(A) + p(B) p(A n B)Mutuall y Exclusive Events: p(A u B ) =