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### Homework3_Fall2011_Solution

Course: STAT 511, Spring 2011
School: Purdue
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Purdue - STAT - 511
Purdue - STAT - 511
The question about |X| : note that |X| is always non-negative and cannot be symmetric; thisautomatically means that it cannot be normally distributed.
Purdue - STAT - 511
Homework6Page 1Homework6Page 2Homework6Page 3
Purdue - STAT - 511
Homework7Page 1Homework7Page 2Homework7Page 3Homework7Page 4Homework7Page 5Homework7Page 6Homework7Page 7
Purdue - STAT - 511
Homework8Page 1
Purdue - CIVIL ENGI - 398
PIPE IDAVFLOWMNTCEGRADEMATRLACIDITYDURBLTYP 1591611.0312.250.070014.55P 160913.4830.060152.58P 160993.1440.06014.68P 1656315.172.630.0501P 1000110.9432.50.07019.35P 100188.32.50.020115.6530.060013.75.9
Purdue - CIVIL ENGI - 398
Random number from a normal distributionRandom Number between 0 and 1Random Number between 0 and 10Random Number between 5 and 10with mean 100 and std dev 100.268489844.5609751955.60972944481.601403770.0397747135.9956192558.69709545388.7233436
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesQ uestion 1 .(a) Ais defined as a collection of interacting and interrelated objects and rules.(b) Systems monitoring may be described(c) A probab
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesQUESTION 1.(a) A System is defined as a collection of interacting and interrelated objects and rules.(b) Systems monitoring may be described as the
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesQ uestion 1.SOLUTIONS(a) Identify any civil engineering system at any location on campus.(b) Name any 3 performance measures you would use to moni
Purdue - CIVIL ENGI - 398
CE 398: Introduction to Civil Engineering Systems DesignSAMPLE II of the MID-TERM EXAMTime: 75 minutesSOLUTIONSQUESTION 1.(a) Identify any civil engineering system at any location on campus.The CityBus public transportation system(b) Name any 3 per
Purdue - CIVIL ENGI - 398
iFORMULA SHEET - C E 398 Fall 2010Please note: You may not need all the formula on this sheet.Basic Probability Formula: p(S) = n(S)/n(U)Application of Set Theory to Probability: p(A u B) = p(A) + p(B) p(A n B)Mutuall y Exclusive Events: p(A u B ) =
Purdue - CIVIL ENGI - 398
1CE398IntroductiontoCivilEngineeringSystemsDesign,Fall2011Homework3(BasicsofProbability forCESystemsDevelopment)Due:ThursdaySeptember15Name:SOLUTIONSQ.1Consider two events P and Q.a) Write the general formula used to calculate the probability that
Purdue - CIVIL ENGI - 398
CE 398 Introduction to Civil Engineering Systems Design, FALL 2011Homework 4. The Basic of StatisticsDue September 22, 2011Name: SOLUTIONSUse the lessons learned from watching the video to answer these questions.QUESTION 1. POPULATION AND SAMPLINGIn
Purdue - CIVIL ENGI - 398
CE 398 Homework 5 SolutionsQUESTION 1 (TEST OF HYPOTHESIS)For each problem, clearly show all steps and detailed calculations and provide a sketch of the graphassociated with your final answer.1. As the site engineer at a large construction site, you h
Purdue - CIVIL ENGI - 398
Year201520162017201820192020202120222023202420252026202720282029203020312032203320342035Year01234567891011121314151617181920Costs(in Millions)100.50.50.50.50.50.50.50.50.50.50.50.50.50.50.50.5
Purdue - CIVIL ENGI - 398
1CE 398 Introduction to Civil Engineering Systems Design, FALL 2011Homework 7. Due Thursday, October 20, 2011SOLUTIONSQUESTION 1 (Tools For Multi-Criteria Decision Making for the Task for Evaluation):As the Chief Metropolitan Engineer of the SunCity,
Purdue - CIVIL ENGI - 398
1CE 398 Introduction to Civil Engineering Systems Design,FALL 2011Homework 8. Due Thursday, October 27, 2011SOLUTIONSQUESTION 1. Consider the following constraint set:x1 - 2x2 2(1)2x1 + x2 9(2)-3x1 + 2x2 3(3)x1 is unrestricted in sign(4)(5)
Purdue - CIVIL ENGI - 398
Purdue - CIVIL ENGI - 398
1CE 398 Introduction to Civil Engineering Systems Design, FALL 2011Homework 10. The Phases of Needs Assessment and System PlanningDue Thursday, November 10, 2011Name: SOL U. TIONSQUESTION 1 Needs Asesssment for CE SystemsEngineer X has claimed that
Purdue - CIVIL ENGI - 398
PRACTICE QUESTIONSTESTS OF HYPOTHESISPlease practice solving these questions.QUESTION 2.Sam claims that the average Fall 09 CE 398 student is a fast eater. (Lets say fast eaters are those whospend less than 10 minutes dining at fast food restaurants)
Purdue - CIVIL ENGI - 398
Random Number between 0 and 1Random Number between 0 and 10Random Number between 5 and 15Random Number between 5 and 10Random number from a normal distribution with mean 100 and std dev 100.284806580.67493927212.14652317.4810682997.42280250.2223
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
hcFh
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
a V2 p + z = n = s n g gRnR
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
480 ftel. 98 ft12ball valveel. 96 ftel. 90 ft120 ft180 fts pump180 ft2.5 psiel. 100 ftpipe diameter, 4-in throughoutcast iron (ks = 0.00085 ft)el. 88 ftppV2 V 2 fL Q 2H 1 + ( h p ) sys = + z + + ( h p ) sys
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
FhFh = pAproj = hc Aproj = 62.0 lbf/ft 3 (11 ft + 2 ft ) ( 4 ft ) = 3.2 kips/ft y ycp y =( 4 ft ) / 12I xcbh 3 / 12h 2 / 12==== 0.1 ft yA ( H h / 2 )( bh ) H h / 2 15 ft 4 ft/22h = 4 ft
Purdue - CIVIL ENGI - 340
Purdue - CIVIL ENGI - 340
Date: 28 Sept. 2010CE340 Test 1Last Name: SOLUTION KEYWrite your name on each sheet of paper that you hand in.Read all questions very carefully. If the problem statement is not clear, you shouldask the proctors present to clarify if possible the ques
Purdue - CIVIL ENGI - 340
Date: 27 Oct. 2010CE340 Test 2Last Name:First Name:COVER PAGEWrite your name on each sheet of paper that you hand in.Read all questions very carefully. If the problem statement is not clear, you shouldask the proctors present to clarify if possible
Purdue - INDUSTRIAL - 343
HomeworkAssignment#1SolutionsPU R D U E U N I V E RSI T YH om e w o r k A ssign m e n t #1I E 343 : E n gi n e e r i n g E con om i csA ssign e d : 27 A u g 2010F a l l 2010D u e : 3 Se p t 2010I nst r u c to r : A . C a p pon iP r ob l e m 1Text
Purdue - INDUSTRIAL - 343
HomeworkAssignment#2SolutionsPU R D U E U N I V E RSI T YH om e w o r k A ssign m e n t #2I E 343 : E n gi n e e r i n g E con om i csA ssign e d : 3 Se p t 2010F a l l 2010D u e : 10 Se p t 2010I nst r u c to r : A . C a p pon iI n st r u c t ion
Purdue - INDUSTRIAL - 343
HomeworkAssignment#3SolutionsPU R D U E U N I V E RSI T YI E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iH om e w o r k A ssign m e n t #3A ssign e d : 10 Se p t 2010D u e : 17 Se p t 2010Missing name on t
Purdue - INDUSTRIAL - 343
HomeworkAssignment#4SolutionsPU R D U E U N I V E RSI T YI E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iMissing name on the top of each page submittedNot stapled together 2Not completed on the correct temp
Purdue - INDUSTRIAL - 343
HomeworkAssignment#5SolutionsPU R D U E U N I V E RSI T YI E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iH om e w o r k A ssign m e n t #5A ssign e d : 24 Se p t 2010D u e : 01 O c t 2010Missing name on th
Purdue - INDUSTRIAL - 343
HomeworkAssignment#6SolutionsPU R D U E U N I V E RSI T YI E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iH om e w o r k A ssign m e n t #6A ssign e d : 01 O c t 2010D u e : 08 O c t 2010Missing name on the
Purdue - INDUSTRIAL - 343
HomeworkAssignment#7SolutionsPU R D U E U N I V E RSI T YI E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iMissing name on the top of each page submittedNot stapled together 2Not completed on the correct temp
Purdue - INDUSTRIAL - 343
Homework#8SolutionsPU R D U E U N I V E RSI T YH om e w o r k A ssign m e n t #8I E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iMissing name on the top of each page submittedNot stapled together 2Not compl
Purdue - INDUSTRIAL - 343
Homework#9SolutionsP U R D U E U N I V E RSI T YI E 343 : E ngi n e e r i ng E conom i csF a l l 2010I nst r u c to r : A . C a p pon iMissing name on the top of each page submittedNot stapled together 2Not completed on the correct template 10H om
Purdue - INDUSTRIAL - 343
Homework#11SolutionsPU R D U E U N I V E RSI T YI E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iH om e w o r k A ssign m e n t #11A ssign e d : 29 N ov 2010D u e : 5 D e c 2010P r ob l e m 1(10 points)T
Purdue - INDUSTRIAL - 343
Homework#12SolutionsPURDUEUNIVERSITYHomeworkAssignment#12I E 343 : E n gi n e e r i n g E con om i csF a l l 2010I nst r u c to r : A . C a p pon iA ssign e d : 3 D e c 2010D u e : 10 D e c 2010(10 points)P r ob l e m 1T e x t b oo k p r ob l e
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HLTH 101Fall, 2011T OPIC 9: INTRODUCTION TO CANCERThis lecture will serve as our introduction to cancer. We will begin bydiscussing the current status of cancer as a disease: its incidence andprevalence, mortality and morbidity. Well see that the det
Waterloo - HLTH - 101
September 23rd, 2011- In the developed world, higher infant mortality lots of spending on health care- Doctors large population factor- Infant mortality is NOT due to doctors but SOCIAL FACTORS.*Depends on the amount of money spent on womens education
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HLTH 101F a ll, 2 0 1 1TOPIC 2: CHANGES IN HUMANHEALTH STATUSIn order to fully understand the nature of health and disease,we ned to try to understand the history of human health. We mayhear people say that were less healthy now than weve been forh
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HLTH 101Fall, 2011TOPIC 3. CAUSES OF CHANGES IN HUMAN HEALTHSTATUSIn the previous topic, we established that health status among humanpopulations can change over time, thus establishing the first of our firstprinciples of health research and practic
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