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Final_2010

Course: IE 370, Spring 2011
School: Purdue
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May 4 2010 IE330 Spring 2010 Final Exam Part 1: Mandatory (Chapters 15 and 16) No calculators, closed book, closed notes. Do not tear off any pages. 1 1. CHAPTER 15 - True/False questions (3 points each, 15 points total) a. (TRUE or FALSE) In a sign test, the effect size is computed by dividing the difference in means by the standard error of the estimator. b. (TRUE or FALSE) For a Wilcoxon rank-sum test, tied...

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May 4 2010 IE330 Spring 2010 Final Exam Part 1: Mandatory (Chapters 15 and 16) No calculators, closed book, closed notes. Do not tear off any pages. 1 1. CHAPTER 15 - True/False questions (3 points each, 15 points total) a. (TRUE or FALSE) In a sign test, the effect size is computed by dividing the difference in means by the standard error of the estimator. b. (TRUE or FALSE) For a Wilcoxon rank-sum test, tied values are discarded. c. (TRUE or FALSE) Comparisons between levels of the factor cannot be made when using a Kruskal-Wallis test. d. (TRUE or FALSE) If the data is symmetric but not normally distributed, the Wilcoxon signed-rank test is preferred over the sign test. e. (TRUE or FALSE) Non-parametric tests should not be used when there are many outliers in the data that cannot be removed. 2. CHAPTER 15 - Multiple choice questions (3 points each, 15 points total) a. Which of the following is useful for testing the stability of an alloy deformed by four different methods if the residuals are not normally distributed? i. Z-test ii. Sign test iii. Kruskal-Wallis test iv. Wilcoxon signed-rank test v. None of the above b. You have collected data on customer transaction times using one of two ATM display layouts. For each customer, you have a time when using display 1 and display 2, and you are interested in the effect of layout on the time it takes the customer to complete their transaction. The populations are not normally distributed. Which of the following tests could you use? i. Paired test ii. Sign test iii. Wilcoxon rank-sum test iv. Wilcoxon signed-rank test v. None of the above c. You are testing whether the mean of a population is equal to zero or not, but the data is not normally distributed. (The population is continuous.) Which of the following tests could you use for this purpose? i. 22 factorial test ii. Simple linear regression iii. Kruskal-Wallis test iv. Wilcoxon rank-sum test v. None of the above 2 d. In running a simple linear regression, you find that the residuals have nonconstant variance, which cannot be stabilized using transformations. Which of the following non-parametric methods can be used instead? i. Wilcoxon signed-rank test ii. Wilcoxon rank-sum test iii. Sign test iv. Kruskal-Wallis test v. None of the above e. Which of the following are true concerning the Wilcoxon signed-rank test (choose all that are true)? i. The test compares the data against a hypothesized median (if its mean then its correct) ii. The data should be free of outliers iii. The counts of values above and below the median are compared. iv. The data should come from a uniform distribution v. None of the above 3. CHAPTER 16 - True/False questions (3 points each, 15 points total) a. (TRUE or FALSE) During the baseline process, it is recommended that 25-50 subgroups are used. b. (TRUE or FALSE) While monitoring a process using statistical process control, the process must be free of special causes of variation for the analysis to be valid. c. (TRUE or FALSE) It is recommended that subgroup sizes be increased during the monitoring process. d. (TRUE or FALSE) A centered process is one where the process mean is centered between the upper and lower control limits. e. (TRUE or FALSE) If the process is free of special causes of variation, one should never see an out-of-control point. 4. CHAPTER 16 - Multiple choice questions (3 points each, 15 points total) a. We are tracking the specific gravity of the root beer we are producing, as the correct mixture has a particular specific gravity. Which of the following is the best control chart to use? (Pick one only.) i. x-bar and r chart ii. P-chart iii. NP-chart iv. U-chart v. C-chart vi. None of the above can be used 3 b. Which of the following are true regarding specifications (choose all that are true)? i. Specifications are used in computing the control limits. (Wrong!) ii. Specifications are used in computing the process capability ratio. iii. Specifications are engineering tolerances established by the customer. iv. Specifications are established by computing tolerance intervals. v. None of the above is true. c. We are tracking the number of defective welds on a part produced by an automated welding process. Which of the following attribute control charts should be used for statistical process control? (Choose all that can be used effectively.) i. s chart ii. P-chart (Wrong!) P-chart is tracking proportion! iii. NP-chart iv. U-chart v. C-chart vi. None of the above can be used d. During the monitoring phase of statistical process control, which of the following are true? (Select all that are true.) i. Whenever special causes of variation are found, the control limits should be re-computed. ii. 25-50 subgroups should be used. iii. During the monitoring phase, we are trying to identify when special causes of variation have been introduced into the process. iv. Specification limits should be plotted along with the control limits. v. The control limits should always be symmetric with respect to the process mean (3). vi. None of the above are true e. During the monitoring phase, we find a point outside our control limit on the s-chart. Which of the following might be an explanation? (Select all that could be true.) i. The mean of the process has shifted. ii. The standard deviation of the process has been reduced. iii. A special cause of variation has been introduced into the process. iv. It is due to normal random variation. v. None of the above could be true. 4 5. CHAPTER 15 Problem (20 points)1 The nickel content, in parts per thousand by weight, is measured for six welds. Due to two outliers, a t-test is not appropriate. It is desired to test H 0 : = 12 vs. H 0 : 12 . The data are as follows: Nickel content (ppt): 11.5 13.9 9.3 9.0 21.7 0.9 SummaryforNickelContent( ppt) AndersonDarlingNormality Test A Squared PV alue Mean StDev V ariance Skew ness Kurtosis N 0 5 10 15 0.26 0.574 11.050 6.812 46.407 0.16278 1.41153 6 Minimum 1stQ uartile Median 3rdQ uartile Maximum 20 0.900 6.975 10.400 15.850 21.700 95% ConfidenceI nterv alforMean 3.901 18.199 95% ConfidenceI nterv alforMedian 3.793 18.914 95% ConfidenceI nterv alforStDev 9 5 % Conf ide nce I nt e r v a ls 4.252 16.708 Mean Median 5.0 7.5 10.0 12.5 15.0 17.5 20.0 A Wilcoxon Signed-Rank test is performed, with the following results: Wilcoxon Signed Rank Test: Nickel Content (ppt) Test of median = 12.00 versus median not = 12.00 Nickel Content (ppt) N 6 N for Test 6 Wilcoxon Statistic 7.0 1 P 0.529 Estimated Median 11.30 Taken from Navidi, W. (2008). Statistics for Engineers and Scientists, 2nd Edition, New York: McGrawHill, pp. 444-445. 5 a. State the assumptions for using the Wilcoxon Signed-Rank test and the evidence you have for those assumptions being met. b. Why was the sign test not used? c. Based on the results, draw a conclusion about the hypothesis? (Explain your answer) d. In this case N for test is equal to N. Can you think of a case where these will not be equal? 6 6. CHAPTER 16 Problem (20 points) You are tracking the wait time for patients who are getting a flu shot at your clinic. During a baseline phase, you found the mean wait time to be 7 minutes and the standard deviation to be 4 minutes. Assume C4 = 1. XbarRChartofWaitTime( min) + 3SL= 13 Sa m p l e M e a n 12 + 2SL= 11 9 + 1SL= 9 _ _ X= 7 6 1SL= 5 3 0 2SL= 3 3SL= 1 1 2 3 4 5 6 7 8 Sa m ple 9 10 11 12 13 14 15 Sa m p l e R a n g e 20 + 3SL= 18.79 15 + 2SL= 15.27 10 + 1SL= 11.75 _ R= 8.24 5 1SL= 4.72 0 2SL= 1.20 3SL= 0 1 2 3 4 5 6 7 8 Sa m ple 9 10 11 12 13 14 15 a. Is the process in control? Why or why not? (Use the Western Electric rules shown on the last page, and circle any out of control points on the chart.) b. What is the subgroup size? 7 c. If our goal is to have people wait no more than 10 minutes, what is the process capability ratio of this process? (Approximate, there is no need to be precise.) d. How many people out of 100 would have to wait more than 10 minutes? 8 4 May 2010 IE330 Spring 2010 Final Exam Part 2: Optional (cumulative Chapters 8 - 14) No calculators, closed book, closed notes. Do not tear off any pages. 9 1. Chapter 8 (2 points each, 6 points total) a. Which of the following is not a measure of location? i. Quartile ii. Mode iii. Inter-quartile range iv. Median b. (TRUE or FALSE) In choosing n observations from N ( , ) , a larger would result in a wider confidence interval on population mean if all else is equal. c. Suppose I will choose a number at random from a standard normal distribution. (Call that number x.) Which of the following is the probability that the number chosen is greater than a number z, where z = x2 2 0? (The standard normal distribution is one whose PDF is F ( x ) = e .) 2 x2 z P ( x > z ) = 0.5 i. e2 ii. this is correct P( x > z) = 2 if the limit is from z to infinity x2 iii. 2 ze z2 iv. P( x > z) = e2 z 2 P( x > z) = 2 2. Chapter 9 (2 points each, 6 points total) a. Suppose you are evaluating which of two processes results in the greatest productivity. The populations of the productivity from the two processes are N ( 1 , 1 ) and N ( 2 , 2 ) where 1 2 , and you know the value of both standard deviations. Which of the following could be the appropriate test statistic? (Choose all that are possibly correct given the information above.) i. iv. X X 2 0 X X 2 0 T0 = 1 Z0 = 1 2 2 11 1 2 Sp + + n1 n2 n1 n2 v. ii. P P2 X X 2 0 1 Z0 = T0 = 1 2 2 s1 s2 1 1 + P 1 P + n1 n2 n1 n2 D 0 vi. None of the T0* = iii. above. SD / n ( 10 ) b. (TRUE or FALSE) Power is the probability of rejecting the null hypothesis given that it is false. c. Given that the two-sided 95% confidence interval on a mean is [9.25, 12.75], which of the following can we say are true (select all that are true)? i. The population mean is between and 9.25 12.75. ii. If we used the same sample to create a 95% upper one-sided confidence bound, the bound would be lower than 12.75 iii. The sample mean is 11. (?) isnt this right??? iv. If we used the same sample to conduct a hypothesis test of H0: = 8 vs. H1: 8, the null hypothesis would be rejected for = 0.05. 3. Chapter 10 (2 points each, 6 points total) a. (TRUE or FALSE) In a two-sample test of means, I should pool the variances of the samples if I believe that the population variances are different. b. A scientist reports that a null hypothesis of H 0 : 1 2 = 0 vs. H1 : 1 2 0 is rejected at =0.01 and with = 0.20. What is the chance that this conclusion is incorrect? i. < 5% iv. < 10% ii. < 2.5% v. < 1% iii. < 20% i. None of the above 11 c. Which statements are true regarding paired t-tests (select all that are true)? i. For the paired t-test, we compute the mean of each sample, then compare whether these means are the same or not. ii. Use paired t-tests when specific observations in each sample can be matched. iii. Use paired t-tests whenever you have the same number of observations in each sample. iv. Paired t-tests may not be more powerful than a two-sample t-test if the variances of the two populations are small. v. None of the above is true. 4. Chapter 11 (2 points each, 6 points total) a. (TRUE or FALSE) In a simple linear regression, the residuals must be normally distributed, which can be checked by examining the normal probability plot of the residuals. b. Suppose a 95% confidence interval on the coefficient of the predictor variable is [-1.7, 9.8]. Which of the following are true? (Choose all that are true.) i. The regression is not significant. ii. If we took a large number of samples and did regressions on each, 95% of the coefficients for the predictor would be in the interval. (Wrong!) iii. The actual coefficient of the predictor is close to 4.05. iv. The R2 value is 5%. v. None of the above is true. c. (TRUE or FALSE) In a simple linear regression model (one predictor), the p-value of the ANOVA is always equal to the p-value of the coefficient of the predictor. 5. Chapter 12 (2 points each, 6 points total) a. To check the normality assumption in a regression analysis, which of the following plots can be used (choose all that are true)? i. Residuals versus fits plot ii. Boxplot iii. Normal probability plot iv. Residuals versus order plot v. All of them can be used b. (TRUE or FALSE) In multiple linear regression, at least one of the coefficients must be significantly different than zero for the regression to be significant. c. (TRUE or FALSE) In a multiple linear regression model, the value of R2 (adj) must be equal to or lower than the value of R2. 12 6. Chapter 13 (2 points each, 6 points total) a. (TRUE or FALSE) The results of a one factor ANOVA where the factor has exactly two levels will be the same as a two factor t-test on the same data. b. Which are valid interpretations of a low (< 0.05) p-value for a one-factor ANOVA (choose all that are correct)? i. The factor has an effect on the response. ii. The treatment effects are all zero. iii. The response is different at each of the different levels of the factor. iv. At least one treatment mean is different than zero. v. None of the above is correct. c. (TRUE or FALSE) In a one factor ANOVA, the variance of the residuals must be the same at all levels of the factor. 7. Chapter 14 (2 points each, 6 points total) a. Which of the following ANOVA models can be used to analyze the results of a 23-1 fractional factorial experiment? (Choose all that could be used.) Yijkl = + i + j + k + ijkl i. ii. Yijkl = + i + j + k + ( ) ij + ijkl iii. Yijkl = + i + j + k + ( ) ij + ( ) ik + ijkl iv. v. Yijkl = + i + j + k + ( ) ijk + ijkl None of the above are correct b. (TRUE or FALSE) In a two-way factorial experiment, one can always test if the interaction is significant. c. (TRUE or FALSE) A balanced factorial experiment is one where the variances are constant across the different factors. 13 8. Chapter 10 problem (19 points) Conduct a hypothesis test (=0.05) for H0: 1- 2 = 0 vs. H1: 1- 2 0, given that the variances of the two populations are unknown but equal. You have samples from both populations, each containing 32 observations. For sample 1, the mean is 26.7 with a variance of 0.8, and sample 2 has a mean of 25.7 with a variance of 1.2. 14 9. Chapter 12 problem (19 points) Your supervisor has asked you, the companys star industrial engineer, to produce information on the effect of water temperature and corn syrup content on the specific gravity of the root beer that you produce. You decide to conduct a multiple linear regression on data collected over the past 6 months. The following is the result of that regression: ResidualPlotsforSpecificgravity NormalProbabilit yPlot VersusFit s 99.99 0.0050 90 Re sidua l Pe r cent 99 50 10 1 0.0025 0.0000 0.0025 0.0050 0.01 0.008 0.004 0.000 Residual 0.004 0.008 1.010 Hist ogram 1.020 1.025 FittedValue 1.030 VersusOrder 150 0.0050 100 Re sidua l Fr eque ncy 1.015 50 0.0025 0.0000 0.0025 0.0050 0 0.006 0.004 0.002 0.000 Residual 0.002 0.004 0.006 1 00 00 00 00 00 00 00 00 00 00 00 00 1 2 3 4 5 6 7 8 9 10 11 12 Obser vationOr der Regression Analysis: Specific gravity versus Water Temp (C), Corn Syrup Content (grams per liter) The regression equation is Specific gravity = 0.870 + 0.000015 Water Temp (deg C)+ 0.000997 Corn Syrup Content (g/l) Predictor Constant Water Temp (deg C) Corn Syrup Content (g/l) S = 0.00197442 Coef 0.870141 0.00001511 0.00099685 R-Sq = 79.7% SE Coef 0.002542 0.00005837 0.00001454 T 342.32 0.26 68.58 P 0.000 0.796 0.000 R-Sq(adj) = 79.7% Analysis of Variance Source Regression Residual Error Total DF 2 1197 1199 SS 0.0183386 0.0046663 0.0230049 MS 0.0091693 0.0000039 F 2352.11 P 0.000 a. Do you believe that the regression is valid? Why or why not? Be as specific and complete as possible. 15 b. Do you believe there a relationship between either or both of the factors on the specific gravity of the root beer? Why or why not? c. What do the R-sq and R-sq (adj) values tell you about the regression? d. The target specific gravity for the root beer is 1.02. Show that the regression equation produces a value close to this for a water temperature of 20C and a corn syrup content of 150 grams per liter. e. How precisely (approximately) does the regression suggest we need to be in terms of corn syrup content (i.e. what in grams per liter) to stay between a specific gravity of 1.015 and 1.025, assuming a constant water temperature of 20C? 16 10. Chapter 13 problem (20 points) Three different types of polyethylene sockets can be used for hip replacement, but it is believed that they have different wear rates. Thirty observations of each type are taken in lab experiments, and an ANOVA is run, with the following results: One-way ANOVA: Wear rate (mm per year) versus Plastic type Source Plastic type Error Total DF 2 87 89 S = 0.04096 R-Sq = 23.89% Level A B C N 30 30 30 Mean 1.0125 0.9937 0.9581 SS 0.04582 0.14599 0.19181 StDev 0.0481 0.0359 0.0378 MS 0.02291 0.00168 F 13.65 P 0.000 R-Sq(adj) = 22.14% Individual 95% CIs For Mean Based on Pooled StDev ---+---------+---------+---------+-----(-----*-----) (----*-----) (-----*-----) ---+---------+---------+---------+-----0.950 0.975 1.000 1.025 Pooled StDev = 0.0410 Tukey 95% Simultaneous Confidence Intervals All Pairwise Comparisons among Levels of Plastic type Individual confidence level = 98.06% Plastic type = A subtracted from: Plastic type B C Plastic type B C Lower -0.04403 -0.07962 Center -0.01882 -0.05442 Upper 0.00638 -0.02921 +---------+---------+---------+--------(-----*------) (-----*------) +---------+---------+---------+---------0.080 -0.040 0.000 0.040 Plastic type = B subtracted from: Plastic type C Plastic type C Lower -0.06080 Center -0.03559 Upper -0.01039 +---------+---------+---------+--------(-----*-----) +---------+---------+---------+---------0.080 -0.040 0.000 0.040 17 a. Explain, as specifically and completely as possible, what the ANOVA results above tell you about whether wear is different between plastic types A, B, and C. Be sure to indicate which you think is best. 18 b. What is the expected difference in wear between type A and type C? c. Identify the assumptions you need to check to confirm the ANOVA is valid and your conclusions based on the plots below. ResidualPlotsforWearrate( mmperyear) NormalProbabilit yPlot VersusFit s 99.9 0.10 90 0.05 Residua l P e r ce nt 99 50 10 1 0.1 0.10 0.05 0.00 Residual 0.05 0.00 0.05 0.10 0.10 0.960 0.975 Hist ogram 1.005 1.020 VersusOrder 0.10 15 0.05 Residua l 20 Fr e que ncy 0.990 FittedValue 10 5 0 0.08 0.04 0.00 0.04 Residual 0.08 0.12 19 0.00 0.05 0.10 1 10 20 30 40 50 60 70 Obser vationOr der 80 90 Helpful formulas: Confidence intervals x z / 2 / n x t / 2, n 1s/ n ( n 1) s 2 2 ( n 1) s 2 2 / 2,n 1 p z / 2 2 1 / 2,n 1 p (1- p) p p + z / 2 n p(1- p) n Prediction intervals x t / 2,n 1s 1 + 1 1 X n +1 x + t / 2,n 1s 1 + n n Tolerance intervals x ks Single sample tests X 0 Z0 = / n X 0 T0 = s/ n 0 2 ( n 1) S 2 = Z0 = 02 X np0 np0 (1 p0 ) Two sample tests Z0 = X1 X 2 0 or T0 = 12 22 + n1 n2 X1 X 2 0 S12 S 22 + n1 n2 X X 2 0 T0 = 1 11 Sp + n1 n2 or T0 = D 0 SD / n 20 2 where S p S12 F= 2 S2 ( n1 1) S12 + ( n2 1) S22 = n1 + n2 2 Z0 = P P2 1 1 1 P 1 P + n1 n2 ( ) Process control PCR = USL LSL 6 USL LSL PCRk = min , 3 3 Western Electric rules Any point outside of the control limits 2 out of 3 consecutive points beyond a 2 sigma limit 4 out of 5 consecutive points beyond a 1 sigma limit 9 consecutive points on one side of centerline 21 22 23 24 25 26
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Purdue - IE - 370
Name: _7 May 2009IE330 Spring 2009Final Exam APart 1: MandatoryNo calculators, closed book, closed notes.Do not tear off any pages.1 of 24Name: _1. CHAPTER 15 - True/False questions (3 points each, 15 points total)a. (TRUE or FALSE) To conduct a
Purdue - IE - 370
Name: _16 December 2008IE330 Fall 2008Final Exam #1Part 1: MandatoryNo calculators, closed book, closed notes.Do not tear off any pages.1 of 30Name: _1.CHAPTER 14 - True/False questions (3 points each, 9 points total)a.(TRUE or FALSE) When sho
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
ECE 201 Spring 2010Homework 5 SolutionsProblem 26Since V2 = 60 V , the current through 60 branch is 1 A. The resistors 90 and 180 are in parallel. Their equivalent resistance is90 18090 + 180= 60Req =Now 60 and 60 are in series. Thus the voltage
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
ECE 201 Spring 2010Homework 9 SolutionsProblem 37(a)The following loop equation can be written,(I1 0.75)200 300I1 (I1 + 0.1)500 = 0 I1 = 0.1 AP = VIPs1 = 200(0.75 0.1)0.75= 97.5 WPs2 = 500(0.1 + 0.1)0.1= 10 W(b)Again, writing the loop equatio
Purdue - IE - 370
=9t.lV PtM&quot;'V'wr6)-.,C; I (VO tot1. \,.o'IOtA'&quot;: I.-/\)/Vio\ lvu-rcfw_f):c)' i V, +t [10J:I. +I,) ;:, JA( lot)J - Y (.;2) :6.) (VOkJ/)0_ .JI5&quot;, J,G,t)+; )&quot;'10:((lb-t.&quot;r :,':.k1 &quot; &quot; :&lt; cfw_V/&quot;/ &lt;#A .214
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
ECE 201 Spring 2010Homework 13 SolutionsProblem 9(a)2R and 6R in series gives 8R. 8R and 8R in parallel gives 4R. Thus 12R is inseries with Vs in the simplied circuit. Thus the Thevenin voltage is givenbyVs1 6R12R 2Vs=4= 30 VVoc =To nd the
Purdue - IE - 370
Purdue - IE - 370
1086iout(t) (mA)420-2-4-6-8-1000.0050.010.015t(s)1009080W L(t) (nJ)70605040302010000.0050.01t(s)0.015
Purdue - IE - 370
Purdue - ECE - 201
ECE 201 Spring 2010Homework 17 SolutionsProblem 27(a)Let V be the common voltage across C1 and C2 . ThusdVdtdVC2dt(C 1 + C 2 )= is (t)= iC 2 (t) iC 2 (t) =C2is (t)C1 + C2(b)Using KVL across the second loop and relation from part (a), we
Purdue - IE - 370
Purdue - IE - 370
20181614Vc (t)(V)12108642002468t(s)108t(s)1012141610987Vc (t)(V)654321002461214160.20.180.160.14iL(t)(A)0.120.10.080.060.040.02000.001 0.002 0.003 0.004 0.005 0.006 0.007 0.008 0.009t(s)0.010.00
Purdue - IE - 370
III8-20 (d) Vc(t)8-20 (d) Vc(t)8-20 (d) Vc(t)151010II5Vc (t) (V)15Vc (t) (V)2010I2015Vc (t) (V)2055000-5-5-500.10.20.30.400.1t (s)0.20.30.40I0.20.30.4t (s)II8-20 (d) c (t)I8-20 (d) c (t)I8-20 (d) c (t)I0
Purdue - IE - 370
ECE 201 Spring 2010Homework 21 SolutionsProblem 31(a)Using voltage division,20RV050R= 0.4V0vC (0) == vC (0+)(b)The Thevenin equivalent is given byR3R3 + (R1 |R2 )= 0.8V0Voc = V0Rth = R1 |R2 |R3= 4R(c)vC () = 0.8V0vC (0+) = 0.4V0 vC (
Purdue - IE - 370
Purdue - IE - 370
21.5Vc (t) (V)10.50-0.5-101234t(s)567810987Vc (t)(V)654321000.20.40.60.81t(s)1.21t(s)1.21.41.61.820-0.05-0.1iL(t)(A)-0.15-0.2-0.25-0.3-0.35-0.400.20.40.60.81.41.61.821210Vc (t)(V)8642
Purdue - IE - 370
Purdue - IE - 370
ECE 201 Spring 2010Homework 25 SolutionsProblem 43(a)To nd the initial conditions at t=0-, we can write the following KVL equations,20 + 40iL (0) 60(0.1 iL (0) = 0 iL (0) = iL (0+) = iC (0+) = 0.14 A vC (0+) = vC (0) = 20 0.14 40= 14.4 VAfter t=0
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
ECE 201 Spring 2010Homework 29 SolutionsProblem 40(a)The following dierential equation can be written using KCL at the invertingterminal of the op amp and using the virtual ground concept,vs (t) vout (t)dvout (t)++C=0R1R2dtvs (t) = 100u(t)=
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
ECE 201 Spring 2010Homework 33 SolutionsProblem 30(a)11+R j Lj 0.25= 0.05 1Zin (j ) =Yin (j )j 20=5 + jYin (j ) =(b)Iin Zin (j )j L10(i + j )= 10 j 20 j /4= 5 2eIL = iL (t) = 10 cos(5t /4) mAProblem 40Let the impedances of R1 ,
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
11-2(a) Instantaneous Power p(t) and Average Power pave11-2(a) Instantaneous Current i(t)0.090.0060.080.0040.070.0020.06power (W)0.10.008current (A)0.010-0.0020.050.04-0.0040.03-0.0060.02-0.008Instantaneous PowerAverage Power0.01
Purdue - IE - 370
ECE 201 Spring 2010Homework 37 SolutionsProblem 5(a)For Figure (a),1 T2i (t) dtT0319 dt +=9025=3= 5/ 32Ief f = Ief f616 dt3For Figure (b),119 dt +40= 25/42Ief f =316 dt2 Ief f = 2.5(b)Current through RL is given by i(t)
Purdue - IE - 370
Purdue - IE - 370
Purdue - IE - 370
ECE 201 Spring 2010Homework 40 SolutionsProblem 30(a)Zth = (R1 |R2 ) j/ CVoc= (20 j 10) R2= VsR1 + R2= 20 VrmsFor maximum power transfer, ZL = Zth = (20 + j 10) .(b)2Voc4RL= 5WPavg =Problem 37(a)Here we cannot apply the maximum power t
Concordia AB - CHEM - 11
Acids / Base EquilibriumUnit IVI. Arrhenius acids and bases (1884)According to Arrhenius acids are substances that dissociate in water to produce Hydrogen ions (H+), andbases are substances that dissociate in water to produce hydroxide ions (OH-)Acid
Concordia AB - CHEM - 11
Bufferschemicals that resist changes in pHExample: The pH of blood is 7.4.Many buffers are present to keep pH stable.H1+ + HCO31H2CO3H2O + CO2hyperventilating: CO2 leaves blood too quickly[ CO2 ]shift right[ H1+ ]pH(more basic)alkalosis: bloo
Concordia AB - CHEM - 11
Name: _Acids and BasesIts a chemical world!Acids can be identified by theirchemical formulas The chemical formula for an acid willstart with hydrogen HNO3 is nitric acid; H 2SO4 is sulfuricacid; HCl is hydr ochloric acid; H3PO4 isphosphoric acid
Concordia AB - CHEM - 11
Acids and BasesAcids: The term acid, in fact, comes from the Latin termacere, which means sour. Acids taste sour, are corrosiveto metals, change litmus (a dye extracted from lichens)red, and become less acidic when mixed with bases.Bases: Bases (also
Concordia AB - CHEM - 11
Chemistry 112 Laboratory: Chemistry of Acids &amp; BasesPage 43Chemistry of Acids and BasesThe chemistry of acids and bases is an area of fundamental importance inchemistry. In this experiment you will study acid-base equilibria by determining the pH of
Concordia AB - CHEM - 11
Chemistry 11Lab: Types of Chemical Reactions(April 5, 2008)Lab #5C:Types of Chemical ReactionsOBJECTIVES To observe a variety of chemical reactions To interpret and explain observations with balanced chemical equations To classify each reaction as
Concordia AB - CHEM - 11
Chemistry 11Lab: Solution Chemistry(April 14, 2008)Lab #10D:Solubility Trends and Precipitate FormationOBJECTIVES To mix several pairs of solutions together and then note whether any precipitates form To deduce, from the experimental results, which
Concordia AB - CHEM - 11
Chemistry 12Name:_, Blk:_Experiment 18A: Factors Affecting Reaction RatePurpose:_ To observe and record the effects of concentration, surface area, andtemperature on reaction ratesMaterials: As per pg. 192 of Heath Laboratory Experiments.Procedure:
Concordia AB - CHEM - 11
UMass Lowell Freshman Chemistry LabPage 1 of 4Experiment14Double Displacement ReactionsOverviewIn this experiment you ultimately want to try to identify two &quot;unknown&quot; solutions of ionic substances, bycomparing the reactions of the &quot;unknown&quot; substan
Concordia AB - CHEM - 11
Exp 20A: Acid RainExperiment 20A: Formal Lab Write-upInclude ALL Questions and Follow-up QuestionsNote: you will need the following information to complete the follow-up questionsSolution A = NaOHSolution B = HClSolution C = HNO3Solution D = Ca(OH)
Concordia AB - CHEM - 11
Qualitative AnalysisPage 139 156Pre-lab, pages 143-144, AND 153-154Post Lab, page 156, all questionsIntroduction to Qualitative Analysis Qualitative analysis is used to separate and detectcations and anions in a sample substance. Qualitative analys
Concordia AB - CHEM - 11
Chemistry 12 Unit 4Introduction: (Post Lab Discussion)Operational Definitions: Describe what acids or bases doeg:Bases turn red litmus blueeg:Acids react with magnesiumConceptual Definitions: Define acids or bases in terms of their molecularstru
Concordia AB - CHEM - 11
Unit 11: Equilibrium / Acids and Basesreversible reaction:RPandPRAcid dissociation is a reversible reaction.2 H1+ + SO41H2SO4Rate at whichRate at which=RPPRequilibrium:- looks like nothing is happening, however- system is dynamic, NOT s
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Common AcidsStrong Acidshydrochloric acid:HClH1+ + Cl1- stomach acid; pickling: cleaning metals w/conc. HCl2 H1+ + SO42H2SO4sulfuric acid:- #1 chemical; (auto) battery acidnitric acid:H1+ + NO31HNO3- explosives; fertilizerWeak Acidsacetic a
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Various Definitions of Acids and BasesArrhenius acid:yields H1+ in solne.g., HNO3Arrhenius base:H1+ + NO31yields OH1 in solne.g., Ba(OH)2Ba2+ + 2 OH1Lewis acid:e pair acceptorLewis base:e pair donorTOPIC FORFUTURE CHEM.COURSESBronsted-Lowr
Concordia AB - CHEM - 11
pH CalculationsRecall that the hydronium ion (H3O1+) is the speciesformed when hydrogen ion (H1+) attaches to water (H2O).OH1 is the hydroxide ion.For this class, in any aqueous soln,[ H3O1+ ] [ OH1 ] = 1 x 1014( or [ H1+ ] [ OH1 ] = 1 x 1014 )If h
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Acid-Dissociation Constant, KaFor the generic reaction in soln:A+B[ PRODUCTS ][ REACTANTS ]KaKaFor strong acids, e.g., HClHClH1++ Cl[ H1 ] [ Cl1- ][ HCl ]Ka1&quot; BIG.&quot;C+D[C][D][ A ][B ]Assume 100%dissociation;Ka notapplicable forstron
Concordia AB - CHEM - 11
Indicatorschemicals that change color, dependingon the pHTwo examples, out of many:litmusred in acid, blue in basephenolphthalein.clear in acid, pink in baseMeasuring pHlitmus paperBasically, pH &lt; 7 or pH &gt; 7phenolphthaleinpH paper- contains a
Concordia AB - GEOGRAPHY - 12
Weather and ClimateWordAbsorptionDefinition(1) Process of taking in and being made part ofan existing amount of matter.(2) Interception of electromagnetic radiation orsound.Advection FogFog generated when winds flow over a surfacewith a differen