Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

ECE 201 Spring 2010Homework 5 SolutionsProblem 26Since V2 = 60 V , the current through 60 branch is 1 A. The resistors 90 and 180 are in parallel. Their equivalent resistance is90 18090 + 180= 60Req =Now 60 and 60 are in series. Thus the voltage

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

ECE 201 Spring 2010Homework 9 SolutionsProblem 37(a)The following loop equation can be written,(I1 0.75)200 300I1 (I1 + 0.1)500 = 0 I1 = 0.1 AP = VIPs1 = 200(0.75 0.1)0.75= 97.5 WPs2 = 500(0.1 + 0.1)0.1= 10 W(b)Again, writing the loop equatio

Purdue - IE - 370

=9t.lV PtM"'V'wr6)-.,C; I (VO tot1. \,.o'IOtA'": I.-/\)/Vio\ lvu-rcfw_f):c)' i V, +t [10J:I. +I,) ;:, JA( lot)J - Y (.;2) :6.) (VOkJ/)0_ .JI5", J,G,t)+; )"'10:((lb-t."r :,':.k1 " " :< cfw_V/"/ <#A .214

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

ECE 201 Spring 2010Homework 13 SolutionsProblem 9(a)2R and 6R in series gives 8R. 8R and 8R in parallel gives 4R. Thus 12R is inseries with Vs in the simplied circuit. Thus the Thevenin voltage is givenbyVs1 6R12R 2Vs=4= 30 VVoc =To nd the

Purdue - IE - 370

Purdue - IE - 370

1086iout(t) (mA)420-2-4-6-8-1000.0050.010.015t(s)1009080W L(t) (nJ)70605040302010000.0050.01t(s)0.015

Purdue - IE - 370

Purdue - ECE - 201

ECE 201 Spring 2010Homework 17 SolutionsProblem 27(a)Let V be the common voltage across C1 and C2 . ThusdVdtdVC2dt(C 1 + C 2 )= is (t)= iC 2 (t) iC 2 (t) =C2is (t)C1 + C2(b)Using KVL across the second loop and relation from part (a), we

Purdue - IE - 370

Purdue - IE - 370

20181614Vc (t)(V)12108642002468t(s)108t(s)1012141610987Vc (t)(V)654321002461214160.20.180.160.14iL(t)(A)0.120.10.080.060.040.02000.001 0.002 0.003 0.004 0.005 0.006 0.007 0.008 0.009t(s)0.010.00

Purdue - IE - 370

III8-20 (d) Vc(t)8-20 (d) Vc(t)8-20 (d) Vc(t)151010II5Vc (t) (V)15Vc (t) (V)2010I2015Vc (t) (V)2055000-5-5-500.10.20.30.400.1t (s)0.20.30.40I0.20.30.4t (s)II8-20 (d) c (t)I8-20 (d) c (t)I8-20 (d) c (t)I0

Purdue - IE - 370

ECE 201 Spring 2010Homework 21 SolutionsProblem 31(a)Using voltage division,20RV050R= 0.4V0vC (0) == vC (0+)(b)The Thevenin equivalent is given byR3R3 + (R1 |R2 )= 0.8V0Voc = V0Rth = R1 |R2 |R3= 4R(c)vC () = 0.8V0vC (0+) = 0.4V0 vC (

Purdue - IE - 370

Purdue - IE - 370

21.5Vc (t) (V)10.50-0.5-101234t(s)567810987Vc (t)(V)654321000.20.40.60.81t(s)1.21t(s)1.21.41.61.820-0.05-0.1iL(t)(A)-0.15-0.2-0.25-0.3-0.35-0.400.20.40.60.81.41.61.821210Vc (t)(V)8642

Purdue - IE - 370

Purdue - IE - 370

ECE 201 Spring 2010Homework 25 SolutionsProblem 43(a)To nd the initial conditions at t=0-, we can write the following KVL equations,20 + 40iL (0) 60(0.1 iL (0) = 0 iL (0) = iL (0+) = iC (0+) = 0.14 A vC (0+) = vC (0) = 20 0.14 40= 14.4 VAfter t=0

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

ECE 201 Spring 2010Homework 29 SolutionsProblem 40(a)The following dierential equation can be written using KCL at the invertingterminal of the op amp and using the virtual ground concept,vs (t) vout (t)dvout (t)++C=0R1R2dtvs (t) = 100u(t)=

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

ECE 201 Spring 2010Homework 33 SolutionsProblem 30(a)11+R j Lj 0.25= 0.05 1Zin (j ) =Yin (j )j 20=5 + jYin (j ) =(b)Iin Zin (j )j L10(i + j )= 10 j 20 j /4= 5 2eIL = iL (t) = 10 cos(5t /4) mAProblem 40Let the impedances of R1 ,

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

11-2(a) Instantaneous Power p(t) and Average Power pave11-2(a) Instantaneous Current i(t)0.090.0060.080.0040.070.0020.06power (W)0.10.008current (A)0.010-0.0020.050.04-0.0040.03-0.0060.02-0.008Instantaneous PowerAverage Power0.01

Purdue - IE - 370

ECE 201 Spring 2010Homework 37 SolutionsProblem 5(a)For Figure (a),1 T2i (t) dtT0319 dt +=9025=3= 5/ 32Ief f = Ief f616 dt3For Figure (b),119 dt +40= 25/42Ief f =316 dt2 Ief f = 2.5(b)Current through RL is given by i(t)

Purdue - IE - 370

Purdue - IE - 370

Purdue - IE - 370

ECE 201 Spring 2010Homework 40 SolutionsProblem 30(a)Zth = (R1 |R2 ) j/ CVoc= (20 j 10) R2= VsR1 + R2= 20 VrmsFor maximum power transfer, ZL = Zth = (20 + j 10) .(b)2Voc4RL= 5WPavg =Problem 37(a)Here we cannot apply the maximum power t

Concordia AB - CHEM - 11

Acids / Base EquilibriumUnit IVI. Arrhenius acids and bases (1884)According to Arrhenius acids are substances that dissociate in water to produce Hydrogen ions (H+), andbases are substances that dissociate in water to produce hydroxide ions (OH-)Acid

Concordia AB - CHEM - 11

Bufferschemicals that resist changes in pHExample: The pH of blood is 7.4.Many buffers are present to keep pH stable.H1+ + HCO31H2CO3H2O + CO2hyperventilating: CO2 leaves blood too quickly[ CO2 ]shift right[ H1+ ]pH(more basic)alkalosis: bloo

Concordia AB - CHEM - 11

Name: _Acids and BasesIts a chemical world!Acids can be identified by theirchemical formulas The chemical formula for an acid willstart with hydrogen HNO3 is nitric acid; H 2SO4 is sulfuricacid; HCl is hydr ochloric acid; H3PO4 isphosphoric acid

Concordia AB - CHEM - 11

Acids and BasesAcids: The term acid, in fact, comes from the Latin termacere, which means sour. Acids taste sour, are corrosiveto metals, change litmus (a dye extracted from lichens)red, and become less acidic when mixed with bases.Bases: Bases (also

Concordia AB - CHEM - 11

Chemistry 112 Laboratory: Chemistry of Acids & BasesPage 43Chemistry of Acids and BasesThe chemistry of acids and bases is an area of fundamental importance inchemistry. In this experiment you will study acid-base equilibria by determining the pH of

Concordia AB - CHEM - 11

Chemistry 11Lab: Types of Chemical Reactions(April 5, 2008)Lab #5C:Types of Chemical ReactionsOBJECTIVES To observe a variety of chemical reactions To interpret and explain observations with balanced chemical equations To classify each reaction as

Concordia AB - CHEM - 11

Chemistry 11Lab: Solution Chemistry(April 14, 2008)Lab #10D:Solubility Trends and Precipitate FormationOBJECTIVES To mix several pairs of solutions together and then note whether any precipitates form To deduce, from the experimental results, which

Concordia AB - CHEM - 11

Chemistry 12Name:_, Blk:_Experiment 18A: Factors Affecting Reaction RatePurpose:_ To observe and record the effects of concentration, surface area, andtemperature on reaction ratesMaterials: As per pg. 192 of Heath Laboratory Experiments.Procedure:

Concordia AB - CHEM - 11

UMass Lowell Freshman Chemistry LabPage 1 of 4Experiment14Double Displacement ReactionsOverviewIn this experiment you ultimately want to try to identify two "unknown" solutions of ionic substances, bycomparing the reactions of the "unknown" substan

Concordia AB - CHEM - 11

Exp 20A: Acid RainExperiment 20A: Formal Lab Write-upInclude ALL Questions and Follow-up QuestionsNote: you will need the following information to complete the follow-up questionsSolution A = NaOHSolution B = HClSolution C = HNO3Solution D = Ca(OH)

Concordia AB - CHEM - 11

Qualitative AnalysisPage 139 156Pre-lab, pages 143-144, AND 153-154Post Lab, page 156, all questionsIntroduction to Qualitative Analysis Qualitative analysis is used to separate and detectcations and anions in a sample substance. Qualitative analys

Concordia AB - CHEM - 11

Chemistry 12 Unit 4Introduction: (Post Lab Discussion)Operational Definitions: Describe what acids or bases doeg:Bases turn red litmus blueeg:Acids react with magnesiumConceptual Definitions: Define acids or bases in terms of their molecularstru

Concordia AB - CHEM - 11

Unit 11: Equilibrium / Acids and Basesreversible reaction:RPandPRAcid dissociation is a reversible reaction.2 H1+ + SO41H2SO4Rate at whichRate at which=RPPRequilibrium:- looks like nothing is happening, however- system is dynamic, NOT s

Concordia AB - CHEM - 11

Common AcidsStrong Acidshydrochloric acid:HClH1+ + Cl1- stomach acid; pickling: cleaning metals w/conc. HCl2 H1+ + SO42H2SO4sulfuric acid:- #1 chemical; (auto) battery acidnitric acid:H1+ + NO31HNO3- explosives; fertilizerWeak Acidsacetic a

Concordia AB - CHEM - 11

Various Definitions of Acids and BasesArrhenius acid:yields H1+ in solne.g., HNO3Arrhenius base:H1+ + NO31yields OH1 in solne.g., Ba(OH)2Ba2+ + 2 OH1Lewis acid:e pair acceptorLewis base:e pair donorTOPIC FORFUTURE CHEM.COURSESBronsted-Lowr

Concordia AB - CHEM - 11

pH CalculationsRecall that the hydronium ion (H3O1+) is the speciesformed when hydrogen ion (H1+) attaches to water (H2O).OH1 is the hydroxide ion.For this class, in any aqueous soln,[ H3O1+ ] [ OH1 ] = 1 x 1014( or [ H1+ ] [ OH1 ] = 1 x 1014 )If h

Concordia AB - CHEM - 11

Acid-Dissociation Constant, KaFor the generic reaction in soln:A+B[ PRODUCTS ][ REACTANTS ]KaKaFor strong acids, e.g., HClHClH1++ Cl[ H1 ] [ Cl1- ][ HCl ]Ka1" BIG."C+D[C][D][ A ][B ]Assume 100%dissociation;Ka notapplicable forstron

Concordia AB - CHEM - 11

Indicatorschemicals that change color, dependingon the pHTwo examples, out of many:litmusred in acid, blue in basephenolphthalein.clear in acid, pink in baseMeasuring pHlitmus paperBasically, pH < 7 or pH > 7phenolphthaleinpH paper- contains a

Concordia AB - GEOGRAPHY - 12

Weather and ClimateWordAbsorptionDefinition(1) Process of taking in and being made part ofan existing amount of matter.(2) Interception of electromagnetic radiation orsound.Advection FogFog generated when winds flow over a surfacewith a differen

Concordia AB - GEOGRAPHY - 12

Depletion of Ozone LayerIV.Geography 12DEPLETION OF OZONE LAYERWhat is depletion of ozone layer?Ozone depletion occurs when the natural balance betweenthe production and destruction of stratospheric ozone istipped in favour of destruction.Observat

Concordia AB - GEOGRAPHY - 12

Acid RainVII.Geography 12ACID RAINWhat is acid rain?When sulfur dioxide (SO2) and oxides of nitrogen (NOx)react with moisture in the air, they become sulfuric acidand nitric acid, respectively. The sulfuric and nitric acidspollute the rain (which

Concordia AB - GEOGRAPHY - 12

DeforestationIII.Geography 12DEFORESTATIONWhat is deforestation?The clearing of forests across the Earth has been occurringon a large scale basis for many centuries. This process,known as deforestation, involves the cutting down,burning, and damag