Unformatted Document Excerpt
Coursehero >>
California >>
Cal Poly >>
BUS 438
Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
to Solutions Chapter 18 Data Case
All numbers except per share data in millions
St. Price
Mar-06
108.9
Year
FCF's
1c
0
(1,500)
2
Mar-05
74.38
Mar-04
74.5
Mar-03
44.95
1
220
10%
2
242
3
266
Mar-05
65,907.00
Mar-04
55,177.00
Mar-03
47,123.00
77,575.16
Growth
3
3aii YTM--Cost of Debt
5%
4
280
5
293
6
308
7
324
8
340
9
357
10
375
5.267%
3b
3b 10-year Bond
3bii Beta
4.52%
0.56
3biii Cost of Equity
7.0400%
3c
3ci
Net Debt
Mar-06
74,994.00
3cii Equity
177,150.90
122,581.96 126,243.23
3ciii Enterprise Value
252,144.90
188,488.96
3civ Debt to Value
Target Debt
3d
Tax Rate
3e
Levered WACC
4 NPV-WACC
5 Unlevered WACC
Unlevered Value
Levered Value
Debt Capacity
181,420.23 124,698.16
0.2974242227 0.34965974 0.30413918 0.37789652
33.23%
36.64%
5.81%
$674.39
6.45%
$2,104
2,174
723
PV Tax Shield
1,807
601
1,633
543
1,434
477
1,209
402
956
318
672
223
354
118
36.41
13.34
34.30
12.57
31.63
11.59
28.57
10.47
25.10
9.20
21.16
7.76
16.73
6.13
11.76
4.31
6.20
2.27
$70.69
Levered Value
1,960
651
38.05
13.94
Interest Pmts
Interest Tax Shield
2,081
691
$2,174.39
NPV--APV
$674.39
FCF Valuation
After-tax Interest Pmts
24.1097658 23.0710632 21.7280792 20.038743 18.103681
15.90124 13.4081383 10.599353 7.44800334 3.925218
Net Borrowing
723
(31)
(40)
(51)
(58)
(66)
(75)
(84)
(94)
(106)
(118)
FCF to Equity
(777)
165
179
194
201
209
218
226
235
244
253
NPV
674.39
Income Statements
All amounts in millions except per share amounts.
Operating Revenue
T otal Revenue
Adjustment to Revenue
Cost of Sales
Cost of Sales with Depreciation
Gross Margin
Mar-06
Mar-05
Mar-04
Mar-03
(TTM)
(TTM)
(TTM)
(TTM)
179,083.00 172,749.00 163,637.00 128,965.00
179,083.00 172,749.00 163,637.00 128,965.00
0
0
133,938.00 129,178.00 122,061.00
0
0
95,404.00
144,249.00 138,469.00 131,238.00 102,647.00
R&D
SG&A
Advertising
Operating Profit
0
0
0
0
45,145.00
43,571.00
41,576.00
33,561.00
0
Gross Operating Profit
0
0
0
18,844.00
18,709.00
16,627.00
15,739.00
0
0
0
0
15,990.00
15,571.00
15,772.00
10,579.00
Operating Profit before Depreciation (EBITDA)
26,301.00
24,862.00
24,949.00
17,822.00
Depreciation
10,311.00
9,291.00
9,177.00
7,243.00
Depreciation Unreconciled
0
0
0
0
Amortization
0
0
0
Amortization of Intangibles
0
0
0
0
15,990.00
15,571.00
15,772.00
10,579.00
800
629
526
438
Earnings from Equity Interest
1,399.00
Other Income, Net
Operating Income After Depreciation
Interest Income
0
1,299.00
1,138.00
439
1,163.00
316
605
-559
Income Acquired in Process R&D
0
0
0
0
Interest Restructuring and M&A
0
0
0
Other Special Charges
0
0
0
0
19,352.00
17,815.00
18,041.00
10,897.00
184
177
196
253
19,168.00
17,638.00
17,845.00
10,644.00
6,769.00
6,126.00
6,446.00
4,301.00
718
605
404
96
Preferred Securities of Subsidiary Trust
0
0
0
0
Net Income from Continuing Operations
11,681.00
10,907.00
10,995.00
6,247.00
Total Income Avail for Interest Expense (EBIT)
Interest Expense
Income Before Tax (EBT)
Income Taxes
Minority Interest
Net Income from Discontinued Ops.
0
0
0
0
0
11,681.00
10,907.00
10,995.00
6,247.00
Extraordinary Income/Losses
0
0
0
0
Income from Cum. Effect of Acct Chg
0
0
0
0
Income from Tax Loss Carryforward
0
0
0
Other Gains (Losses)
0
0
0
0
Total Net Income
11,681.00
10,907.00
10,995.00
6,247.00
Normalized Income
11,681.00
Net Income Available for Common
Net Income from Total Operations
0
10,907.00
10,995.00
6,247.00
11,681.00
10,907.00
10,995.00
6,247.00
Preferred Dividends
0
0
0
0
Excise Taxes
0
0
0
0
7.18
6.62
6.48
3.52
Per Share Data
Basic EPS from Continuing Ops.
Basic EPS from Discontinued Ops.
0
0
0
0
7.18
6.62
6.48
3.52
Basic EPS from Extraordinary Inc.
0
0
0
0
Basic EPS from Cum Effect of Accounting Chg
0
0
0
Basic EPS from Other Gains (Losses)
0
0
0
0
Basic EPS Total
7.18
6.62
6.48
3.52
Basic Normalized Net Income/Share
7.18
6.62
6.48
3.52
Diluted EPS from Continuing Ops.
7.18
6.62
6.48
3.52
Basic EPS from Total Operations
Diluted EPS from Discontinued Ops.
0
0
0
0
0
7.18
6.62
6.48
3.52
Diluted EPS from Extraordinary Inc.
0
0
0
0
Diluted from EPS Cum Effect of Accounting Chg
0
0
0
Diluted EPS from Other Gains (Losses)
0
0
0
0
Diluted EPS Total
7.18
6.62
6.48
3.52
Diluted Normalized Net Income/Share
7.18
6.62
6.48
3.52
Dividends Paid per Share
1.26
0.46
0.36
0.51
Basic Weighted Shares Outstanding
1,626.73
1,648.05
1,694.54
1,725.81
Diluted Weighted Shares Outstanding
1,627.25
1,648.38
1,694.69
1,725.81
Diluted EPS from Total Operations
0
Additional Data
All amounts in millions except per share amounts.
Mar-06
Mar-05
Mar-04
Mar-03
(TTM)
(TTM)
(TTM)
(TTM)
Balance Sheets
Assets
Cash and Equivalents
Restricted Cash
Marketable Securities
Accounts Receivable
13,332.00
13,843.00
16,367.00
13,245.00
0
0
0
5,821.00
5,661.00
4,891.00
5,498.00
16,826.00
15,080.00
14,492.00
12,278.00
Loans Receivable
0
Other Receivable
33,246.00
32,177.00
28,571.00
25,117.00
50,072.00
47,257.00
43,063.00
37,395.00
Raw Materials
0
0
1,468.00
1,127.00
Work In Progress
0
0
1,567.00
Purchased Components
0
0
0
0
Finished Goods
0
0
6,786.00
5,919.00
13,770.00
12,192.00
429
378
Receivables
Other Inventories
Inventories -Adj Allowances
Inventories
Prepaid Expenses
Current Deferred Income Taxes
Other Current Assets
T otal Current Assets
Gross Fixed Assets (Plant, Prop. & Equip.)
Accumulated Depreciation & Depletion
0
0
0
0
1,110.00
0
0
0
0
13,770.00
12,192.00
10,250.00
8,534.00
3,779.00
4,684.00
4,825.00
3,856.00
4,422.00
4,439.00
4,325.00
3,204.00
0
0
0
0
91,196.00
88,076.00
83,721.00
71,732.00
134,712.00 131,171.00 126,429.00 103,890.00
74,681.00
77,098.00
75,765.00
60,596.00
60,031.00
54,073.00
50,664.00
43,294.00
0
0
0
0
Cost in Excess
0
0
0
Non-Current Deferred Income Taxes
0
0
0
0
92,848.00
84,897.00
74,152.00
52,636.00
152,879.00 138,970.00 124,816.00
95,930.00
Net Fixed Assets
Intangibles
Other Non-Current Assets
T otal Non Current Assets
Total Assets
0
244,075.00 227,046.00 208,537.00 167,662.00
Liabilities
Accounts Payable
Notes Payable
17,726.00
17,324.00
16,173.00
12,741.00
0
0
0
0
Short Term Debt
40,410.00
32,961.00
31,358.00
25,946.00
Accrued Expenses
12,439.00
12,030.00
10,723.00
8,848.00
Accrued Liabilities
0
0
0
0
Deferred Revenues
0
0
0
Current Deferred Income Taxes
0
0
0
0
14,620.00
14,446.00
13,635.00
11,150.00
85,194.00
76,760.00
71,889.00
58,685.00
47,916.00
46,789.00
40,186.00
34,422.00
Other Current Liabilities
T otal Current Liabilities
Long Term Debt
Capital Lease Obligations
0
0
0
0
0
Deferred Income Taxes
9,285.00
7,573.00
7,366.00
3,086.00
Other Non-Current Liabilities
6,960.00
6,823.00
7,490.00
9,601.00
Minority Interest
2,625.00
5,008.00
4,710.00
4,223.00
Preferred Securities of Subsidiary Trust
0
0
0
Preferred Equity outside Stock Equity
0
0
0
0
69,169.00
65,895.00
59,265.00
49,734.00
T otal Non-Current Liabilities
Total Liabilities
0
154,364.00 142,656.00 131,154.00 108,419.00
Stockholder's Equity
Preferred Stock Equity
Common Stock Equity
Common Par
Additional Paid In Capital
Cumulative Translation Adjustment
Retained Earnings
T reasury Stock
Other Equity Adjustments
T otal Equity
T otal Capitalization
Total Liabilities & Stock Equity
0
0
0
0
89,711.00
84,389.00
77,383.00
59,243.00
3,373.00
3,704.00
3,757.00
3,303.00
4,207.00
4,625.00
4,685.00
4,108.00
0
0
0
0
88,856.00
87,069.00
78,780.00
60,747.00
-10,440.00 -10,257.00
-7,903.00
-3,888.00
3,715.00
-753
-1,936.00
-5,027.00
89,711.00
84,389.00
77,383.00
59,243.00
137,627.00 131,178.00 117,569.00
93,665.00
244,075.00 227,045.00 208,537.00 167,662.00
Additional Data
Cash Flow
21,992.00
20,198.00
20,172.00
13,490.00
Working Capital
6,001.00
11,315.00
11,832.00
13,047.00
Free Cash Flow
-4,259.00
2,630.00
6,214.00
3,029.00
137,627.00 131,178.00 117,569.00
93,665.00
Invested Capital
Share Data
Shares Outstanding Common Class Only
Preferred Shares
1,805.00
1,634.04
1,725.53
1,725.53
0
0
0
0
Total Ordinary Shares
3,610.00
3,268.08
3,451.06
3,451.06
Total Common Shares Outstanding
1,805.00
1,634.04
1,725.53
1,725.53
368.24
170.96
79.47
79.47
Treasury Shares
Tax Rate
0.353141 0.347318 0.361222 0.404077
Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more.
Course Hero has millions of course specific materials providing students with the best way to expand
their education.
Below is a small sample set of documents:
Maryland - PHYSICS - PHYS270
Ray OpticsThe Ray Model of lightLight travels in straight line is the basis of the ray model of light.We define light ray as a line in the direction along which light energy isflowingReflectionSpecular reflection from a flat, smoothsurface. The la
Maryland - PHYSICS - PHYS270
Wave OpticsWave Optics Water wave passing though an opening Sharp shadow The wave nature of light is needed toexplain various phenomena Interference Diffraction The particle nature of light was the basisfor ray (geometric) opticsInterference of
Maryland - ELECTRICAL - ENEE241
2010Signals and SystemsSignal Processing and Control SystemsG. BlankenshipElectrical and Computer Engineering DepartmentUniversity of Maryland College Park9/1/2010Table of ContentsPreface . xiii1.Introduction to Signals . 141.1.1.2.Time as th
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Discussion Quiz 2September 9, 20111. Griffiths Problem 2.6: Find the electric field a distance z above the center of a circulardisk of radius R which carries a uniform surface charge . (Hint: Use the result inProblem 2.5 for the ele
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Discussion Quiz 8October 21, 20111. A grounded spherical conducting shell of radius R1 is enclosed by a charged thinspherical shell of radius R2 with surface charge density o cos . The spherical shells areconcentric.a) Write the ge
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Discussion Quiz 5September 30, 20111. Griffiths Problem 3.6: Find the force on the charge +q in the figure below. (The xy planeis the grounded conductor)2. A circular wire of radius R and uniform line charge density is placed above
Maryland - ELECTRICAL - ENEE380
Problem 1We assume +q and q on each plate respectively. The surface density: = /Using Gausss Law, we obtain that between two conductor the electric field: = = Potential difference = = Then the capacitance = =Problem 2Set up Cartesian coordin
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Discussion Quiz 3September 16, 20111. Calculate the electric potential inside a uniformly charged spherical shell of radius R andsurface charge density .2. Two charges (+q and q) are situated at the corners of an equilateral triangl
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Discussion Quiz 12 September 2011Note: This is an assessment test on vector calculus. It is not a graded quiz. Answer as manyproblems as you can.1. Find the angle between the body diagonals of a cube. (Hint: Determine the vectorsco
Maryland - ELECTRICAL - ENEE380
Problem 1a) Boundary conditions include continuity of potential and electrical eld(derivative of potential) at x = 0, and continuity of electrical eld at x = xpand x = xn , namely1. Vp (0) = Vn (0)2.x Vp (0)3.x Vp (xp )4.x Vn (xn )=x Vn (0)=0
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Sample Exam ProblemsDecember 6, 20111. a) Determine the vector potential a distance s from an infinite straight wire carrying acurrent I.b) Find the magnetic vector potential inside the wire, if it has radius R and the current isun
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Sample Exam ProblemsOctober 30, 20111. A one-dimensional device consisting of a linear dielectric with dielectric constant r ischarged with a charge density given by o x a . If E 0 at x 0 and V 0 atx a , find V x and E x . Determine
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Sample Exam ProblemsSeptember 30, 20111. Two concentric thin spherical shells with radii a and b (a > b) are charged with surfacecharge densities and -, respectively.a) Calculate the electric potential at all regions.b) Determine t
Maryland - ELECTRICAL - ENEE380
Generated by CamScanner
Maryland - ELECTRICAL - ENEE380
Generated by CamScanner
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Discussion Quiz 10November 11, 20111. Calculate the magnetic field a distance z above the center of a circular loop of radius Rwhich carries a steady current I.2. Using Amperes law, calculate the magnetic field a distance r from an
Maryland - ELECTRICAL - ENEE380
Generated by CamScanner
Maryland - ELECTRICAL - ENEE380
Maryland - ELECTRICAL - ENEE380
Generated by CamScanner
Maryland - ELECTRICAL - ENEE380
Maryland - ELECTRICAL - ENEE380
Maryland - ELECTRICAL - ENEE380
Maryland - ELECTRICAL - ENEE380
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Homework 9 (Due: December 13, 2011 in class)December 6, 20111. A square loop of side a recedes with a uniform velocity uo a y from an infinitely long wirecarrying current I along az . Assuming that the side of the loop closest to the
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Homework 8 (Due: December 6, 2011 in class)November 29, 20111. Griffiths Problem 6.122. Griffiths Problem 6.173. Griffiths Problem 6.184. Griffiths Problem 6.26 (Ignore the question on the comparison with Eq. 4.68)
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Homework 7 (Due: November 29, 2011 in class)November 20, 20111. Griffiths Problem 5.222. Griffiths Problem 5.233. Griffiths Problem 5.264. Griffiths Problem 5.295. Show that the inductance per unit length of two parallel wires eac
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Homework 6 (Due: November 17, 2011 in class)1. Griffiths Problem 5.92. Griffiths Problem 5.103. Griffiths Problem 5.134. Griffiths Problem 5.145. Griffiths Problem 5.15November 9, 2011
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Homework 3 (Due: October 4, 2011 in class)September 27, 20111. A semiconductor pn-junction is formed by doping a pure semiconductor p-type (withmobile positive charges called holes) on one side and n-type (with mobile negativeelectr
Maryland - ELECTRICAL - ENEE380
ENEE 380 Fall 2011Homework 2 (Due: September 22, 2011 in class)September 15, 20111. Griffiths Problem 2.252. Griffiths Problem 2.363. Griffiths Problem 2.39: Calculate the capacitance bya) Assuming positive and negative charges on each conductor and
Maryland - ELECTRICAL - ENEE322
1:(a)Is:ti(i)I). I 11(0the()Iirl(r1I_v ()X(jw) iIiaiistuiiiiI)JWl(/fI)-2(t [)Jdt)tjw)X(iw)(h) let.is as slvu iu Ligure S4.ilion the Fourier raiisIorni XUw)i:(t)Xis:Lt 1I(: JwLdt(jw)J-2([)e /(2 +-1(:IV (j)I Is as shownif :r
Maryland - ELECTRICAL - ENEE322
2.i:fHSince the Fourier series coefficients repeat every N = 10, we have amore, since x[nJ is real and even, aj is also real and even. Therefore,also given that==5. Further= 5. We areLx[n1II.lsing Parsevals relation,:z(V +(1=502IkI2Uk1
Maryland - ELECTRICAL - ENEE322
FC)VCD.:.AiicCCACC343F)F)4.4C4CoCCV-43aemra4.-Th4T\IV V.4AC\03.ACC)VemC.4V44.r14V444cC4em,c.:4(I4V41emCtIVVaCC.V.cC)Cmj Vj$:aCVii.r3CCVF)CC)LVrCF)3C-43,CLCfoS
Maryland - ELECTRICAL - ENEE322
3L\JJTh\vv.JNsis eq. (3.38),Using the Fourier series synthe=:v(t)=2_2/T)ta12)t2j(2/7)t+(2T)3aeJ+ (L32) +j3(2/8)t4_i(2w/s)t+2 +(ir8sin(-t)=4cos(jt)=4cos(t) + 8cos(t +cmV.4rFIlegiven signal is2+x(t)=j(21r/3)t42(26
Maryland - ELECTRICAL - ENEE322
(IIt11c;4-(I&(IIl(I4pg-ezII,II0r<I i L]r44-qF+I)-Q-k0iiI.I1>1-3gpISL1-II0LI1-L)El01100II1a11I4/1F,IrtgcciLJ-4-(ItiI,4&&IIN)Li7LJI-1-LJ(1+C:,LJLiLJC:IiLLJcf0E
Maryland - ELECTRICAL - ENEE322
__I3.E_Th4t!2.17.L(a) We know that y(t) is the sum of the particular anti homogeneous solutions to thegiven (lllfcrdntlalequation We first determine the particular soliitloii j (t) by usinthe Imthod spc( iflcd in Example 2 14 Sim C we re ,iven
Maryland - ELECTRICAL - ENEE322
GStCIcUl zos)?,2?e21j\ :L)yLnZf3It(1J4@ O)j1jCfl yEn) (11 tl0c-,n31xiiiyitet)=Zx,Cnjj0)fF x,fa. n>9Ca)z0S;.,2Jfl1AaJ0y,Cv-nCn-klo)1Lx;ntatran&ctn3tnSo jLn3: xcnlSntnI)ittx(.-noJXLA)cfw_2a-1 )c,Cfl flo)jztn)r
Maryland - ELECTRICAL - ENEE322
not periodic because it is zero for t(t) is(a)ii(b)(ril2r<0.1 for all n. Therefore, it is periodic with a fundamental period of 1.=(c) x is as shown in the Figure S1.6.[nj3pl.1.Figure S1.6Ilierefore, it is periodic with a fundamental per
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of TechnologyA. James Clark School of EngineeringENEE 244 Homework Set 12(Due: Class 29, Mon., May 9, 2011)Dr. Charles B. Sili
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of TechnologyA. James Clark School of EngineeringDr. Charles B. Silio, Jr.Telephone 301-405-3668Fax 301-314-9281silio@umd.edu
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of TechnologyA. James Clark School of EngineeringDr. Charles B. Silio, Jr.Telephone 301-405-3668Fax 301-314-9281ENEE 244 Home
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE 244 Problem Set 9(Due: Class 21, Mon., Apr. 11
Maryland - ELECTRICAL - ENEE244
1.2.3.4.5.6.7.8.9.10.Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE 244 Problem Set
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE 244 Problem Set 7(Due: Class 17, Mon., Mar. 28
Maryland - ELECTRICAL - ENEE244
1.2.3.4.5.6.7.8.9.10.11.12.13.14.Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE 244 Problem Set 5(Due: Class 11, Mon., Feb. 28
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE 244 Problem Set 4(Due: Class 9, Mon., Feb. 21,
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE 244 Problem Set 3(Due: Class 7, Mon., February
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of Technology A. James Clark School of Engineering Dr. Charles B. Silio, Jr.ENEE 244 Problem Set 2(Due: Class 5, Mon., Feb. 7,
Maryland - ELECTRICAL - ENEE244
Electrical and Computer Engineering DepartmentUniversity of MarylandCollege Park, MD 20742-3285Glenn L. Martin Institute of TechnologyA. James Clark School of EngineeringENEE 244 Problem Set 1(Due: Class 3, Mon., January 31, 2011)Dr. Charles B. Si
Maryland - ELECTRICAL - ENEE244
Maryland - ELECTRICAL - ENEE244
Maryland - ELECTRICAL - ENEE244
Maryland - ELECTRICAL - ENEE244
_1_2_3_45
Maryland - ELECTRICAL - ENEE150
ENEE 150: Intermediate Programming Conceptsfor EngineersSpring 2011Handout #22Project #3: Bank Transaction ProcessingDue Date: April 15, 11:59p.m.In this project, you will build a program that processes bank transactions. Your programwill maintain
Maryland - ELECTRICAL - ENEE150
ENEE 150: Intermediate Programming Conceptsfor EngineersSpring 2011Handout #18Project #2: Recipe Database: Due March 30 at 11:59pmInitial Functional Decomposition Due March 16 at 11:59pmIn this project, you will build a program that parses a recipe
Maryland - ELECTRICAL - ENEE150
ENEE 150: Intermediate Programming Conceptsfor EngineersSpring 2011Handout #7Project #1: Chess: Due Feb 23 at 11:59pmIn this project, you will build a program that allows two human players to play chess.The program will keep track of the chess board
Maryland - ELECTRICAL - ENEE150
A pointer is a variable that stores the address of another variable=>Provides another way to re fu to a variable, through its address ratger tgab its symbolicname-Declarationint *p;Setting Pointers:int a, *p, *g;p = &a; / & means 'address of int',
Maryland - ELECTRICAL - ENEE150
I. Scriptsa. A script is a full-fledged piece of code, but instead of C, it uses Shell.b. Scripts are not compiled. They are interpreted.b.i. First line is always comment and always has to say what shell yourerunning. Ex. #!/bin/cshb.ii. Any unix scr
Maryland - ELECTRICAL - ENEE150
I. Pointersa. Pointers have to do with naming variables.b. They access variables not by symbolic names but location in memory.c. Location/address is a number. You can compute on it, thats why its powerful.You cant compute on a symbol. It allows you to
Maryland - ELECTRICAL - ENEE150
I. Multiple Modulesa. A module is a .c file.b. We can build the program in multiple .c files. This is another way of groupingthings.c. Group related functions in the same .c file.d. When compiling, list all .c files.d.i. Ex. gcc chess.c board.c chec
Maryland - ELECTRICAL - ENEE206
LABORATORY 10Thevenin Equivalent Circuits and Nonideal SourcesLab Goals1. Gain practical experience of working with simpleresistive circuits2. Construct and characterize a 4-bit D/A converter3. Characterize non-ideal voltage sources at variousfrequ