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September 8, 2011 Physics for Scientists & Engineers 2, Chapter 22 1 Please register your iClicker at http://www.iclicker.com/support/ registeryourclicker/ Include the A when you enter your student ID! September 8, 2011 Physics for Scientists & Engineers 2, Chapter 22 2 Electric Field from an Electric Dipole A system of two oppositely charged point particles is called an electric dipole e vector sum of the electric eld from the two charges gives the electric eld of the dipole We have shown the electric eld lines from a dipole We will derive a general expression good anywhere along the dashed line and then get an expression for the electric eld a long distance away from the dipole September 8, 2011 Physics for Scientists & Engineers 2, Chapter 22 3 Electric Field from an Electric Dipole Start with two charges on the x-axis a distance d apart Put - q at x = - d /2 Put + q at x = + d /2 Calculate the electric eld at a point P a distance x from the origin September 8, 2011 Physics for Scientists & Engineers 2, Chapter 22 4 Electric Field from an Electric Dipole e electric eld at any point x is the sum of the electric elds from + q and q Replacing r + and r- we get the electric eld everywhere on the x-axis (except for x = d/2) Interesting limit far away along the positive x- axis ( x >> d ) E = E + + E ! = 1 4 "# q r + 2 + 1 4 "# ! q r ! 2 E = q 4 !" 1 x # 1 2 d ( ) 2 # 1 x + 1 2 d ( ) 2 $ % & & ' ( ) ) September 8, 2011 Physics for Scientists & Engineers 2, Chapter 22 5 Electric Field from an Electric Dipole We can rewrite our result as We can use a binomial expansion or a Taylor expansion So we can write E q 4 x 2 1 + d x 1 d x = q 4 x 2 2 d x = qd 2 x 3 E = q 4 x 2 1 d 2 x 2 1 + d 2 x 2 f... View Full Document

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