uptoChem13regKine1 (1)
26 Pages

uptoChem13regKine1 (1)

Course Number: HUMANITIES EPS 202, Spring 2011

College/University: NJIT

Word Count: 4116

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***Warm up Basic Homework*** Review of attempt 3 Started on Tuesday, 18 January 2011, 08:49 PM Completed on Tuesday, 18 January 2011, 08:49 PM Time taken 49 secs Marks 7/7 Grade 2 out of a maximum of 2 (100%) Question1 Marks: 1 Which of the following statements are true? (When you see a brief statement on the right in maroon (red), you can click on it for additional help.) Help: Multiple choice questions...

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up ***Warm Basic Homework*** Review of attempt 3 Started on Tuesday, 18 January 2011, 08:49 PM Completed on Tuesday, 18 January 2011, 08:49 PM Time taken 49 secs Marks 7/7 Grade 2 out of a maximum of 2 (100%) Question1 Marks: 1 Which of the following statements are true? (When you see a brief statement on the right in maroon (red), you can click on it for additional help.) Help: Multiple choice questions Choose at least one Register to View AnswerTaking the time to enjoy success in problem solving is more likely if you don't wait until the last minute and have to rush. b. The disciple to do your work early is a good habit to acquire. However, lik all good habits, it takes effort to acquire. c. Repeatingly doing what does not work eventual leads to success. d. It is beneficial for students to wait to the last minute to do homework. e. Being on time in class and forcing yourself to pay attention make it easie to get a good grade. Correct Marks for this submission: 1/1. Question2 Marks: 1 Which of the following statements are true? Choose at least one Register to View AnswerParticipation points are lost if I come late to class or leave early. b. All errors must be fixed immediately after they occur. In particular, test err must be corrected by the Thursday following the test. c. I can always do extra credit if I need more points. d. There is no credit for participation points if I use a cell phone or computer during lecture. e. I can fix attendance or test errors at any time, including after the final has been taken. f. There is no late homework in this course. This means I should do my work early in case unexpected events occur. Correct Marks for this submission: 1/1. Question3 Marks: 1 Which of the following statements are correct? Choose at least one Register to View AnswerIt is a good idea to help each other understand the homework. However, it is cheating to simply give another person the answers. b. Cheating is acceptable. It does not hurt others. It does not hurt me. It does not hurt NJIT. c. A true friend will not ask me to help him cheat. d. If I have 2 i-clickers in class, it means I am cheating. I and the other person will lose all participation points for the semester. e. I need the self respect and integrity to say, "No" when someone asks me to cheat. Correct Marks for this submission: 1/1. Question4 Marks: 1 The following questions are easier if you first read the chapter on MOODLE HOMEWORK INSTRUCTIONS found in the Important Information book. John is 76 inches tall. His brother is 53 inches tall. How much taller is John than his brother? Help: Do not include units in calculations Answer: Correct Marks for this submission: 1/1. Question5 Marks: 1 How do you enter 3:1 or 3/1 in Moodle? Help: Ratios and fractions Answer: Correct Marks for this submission: 1/1. Question6 Marks: 1 What is 0.5/6.451? Help: Significant figures Answer: Correct Marks for this submission: 1/1. Question7 Marks: 1 What is 4.8/6.0x1023? Help: Significant figures Answer: Correct Marks for this submission: 1/1. Chapter 13 Basic Homework: Review of Graphing Review of attempt 7 Started on Tuesday, 25 January 2011, 11:49 AM Completed on Tuesday, 25 January 2011, 11:50 AM Time taken 49 secs Marks 15/15 Grade 3 out of a maximum of 3 (100%) Question1 Marks: 1 For the reaction A + B C, the data in the table below give the concentration in M (mol/L) for A as a function of time. When graphing time versus concentration, what is the best choice for the axes range if you want to easily tell how much A is left? Choose one Register to View AnswerX axis: 0 to 100 sec Y axis: 0 to 10 M b. X axis: 0 to 50 sec Y axis: 0 to 2 M c. X axis: 0 to 50 sec Y axis: 0 to 5 M d. X axis: 0 to 50 sec Y axis: 1 to 2 M e. X axis: 0 to 50 sec Y axis: 0 to 1 M Correct Marks for this submission: 1/1. Question2 Marks: 1 When graphing time versus concentration in the above example, what is the best choice for the axes range to get the most accurate reading of the concentration of A? Choose one Register to View AnswerX axis: 0 to 100 sec Y axis: 0 to 10 M b. X axis: 0 to 50 sec Y axis: 0 to 2 M c. X axis: 0 to 50 sec Y axis: 0 to 5 M d. X axis: 0 to 50 sec Y axis: 1 to 2 M e. X axis: 0 to 50 sec Y axis: 0 to 1 M Correct Marks for this submission: 1/1. Question3 Marks: 1 A table of fictitious data is graphed. The line gives the best fit to the data. What is the predicted number of homes for a population of 900 persons? Answer: Correct Marks for this submission: 1/1. Question4 Marks: 1 What is the predicted number of homes for a population of 300 persons? Answer: Correct Marks for this submission: 1/1. Question5 Marks: 1 The slope is y/x. When calculating the experimental slope, use 2 points on the line far away from each other to minimize experimental error. For example, use the points for the answers to questions 3 and 4. Even better, use the points for a population of 100 and 1000. Answer: Correct Marks for this submission: 1/1. Question6 Marks: 1 What are the units of the slope? Choose one Register to View AnswerNo units b. homes c. persons d. homes/person Correct Marks for this submission: 1/1. Question7 Marks: 1 What is the slope of the line which fits the experimental data of the mass versus volume? Hint, for accuracy, use horizontal marked lines for 155 and 735. (Note, for accuracy, values far apart have been chosen.) Answer: Correct Marks for this submission: 1/1. Question8 Marks: 1 What are the units of the slope? Choose one Register to View AnswerNo units b. g c. cm3 d. g/cm3 Correct Marks for this submission: 1/1. Question9 Marks: 1 What physical quantity do the units represent? Choose one Register to View AnswerNone b. Density c. Mass d. Volume e. Speed Correct Marks for this submission: 1/1. Question10 Marks: 1 Suppose the y-axis represents distance from your home. Which of the following statements are correct? (Most are correct.) Choose at least one Register to View AnswerThe slope gives a rate of change. b. In this graph the rate of change is distance per time, that is, the slope is the speed. c. A positive slope means you are moving away from your home. d. A negative slope means you are moving toward your home. e. The slope between two points gives the average rate of change between these points. f. The average speed for two points close together approximates the instantaneous rate of change or speed. g. The slope (or tangent) at a point gives the instantaneous rate of change speed. h. The units of the slope are the product of the y units and the x units. Recall, the units of the slope are the y units divided by the x units. Correct Marks for this submission: 1/1. Question11 Marks: 1 At which of the following times are you moving the fastest? Choose one Register to View Answer1 hr b. 2 hr c. 3.5 hr d. 6 hr e. 7 hr Correct Marks for this submission: 1/1. Question12 Marks: 1 At which of the following times are you moving the slowest? Choose one Register to View Answer1 hr b. 2 hr c. 3.5 hr d. 6 hr e. 7 hr Correct Marks for this submission: 1/1. Question13 Marks: 1 What is the average speed for the first 5 hrs in km/hr? Answer: Correct Marks for this submission: 1/1. Question14 Marks: 1 What is the instantaneous speed at 2 hrs in km/hr? Answer: Correct Marks for this submission: 1/1. Question15 Marks: 1 Study the example of linearization presented below before matching each equation with the procedure to produce a linear plot (straight line). NOTE: the answers are written in the following format: x^0.5 = x0.5 y = 4x3 -4 ln( y ) = -12t +17 y = -3x0.5 + 7 1/y =5x +2 1/y2 = 0.6z2 +0.76 Correct Marks for this submission: 1/1. You are logged in as Nayankumar Rana (Logout) 2011S-CHEM126-Gilbert 1.565676 secsRAM: 3.9MBRAM peak: 4MBIncluded 80 filesDB queries 196Log writes 1ticks: 156 user: 13 sys: 1 cuser: 0 csys: 0Load average: 1.32R Chapter 13 Basic Homework: Kinetics I Review of attempt 2 Started on Sunday, 30 January 2011, 01:39 PM Completed on Sunday, 30 January 2011, 02:22 PM Time taken 43 mins 6 secs Marks 26/26 Grade 4 out of a maximum of 4 (100%) Question1 Marks: 1 For the reaction: 3BrO-(aq) --> BrO3-(aq) + 2Br-(aq) [BrO- ]initial is 0.70 M. 24 seconds later [BrO- ] is 0.17 M. What is the rate of change of [BrO - ] in M/s? (The brackets, [ ], indicate concentration, that is, molarity (M) or moles/liter.) Help: Rate of change defined Answer: Notice that the rate of change of a reactant is negative because it is being used up. Correct Marks for this submission: 1/1. Question2 Marks: 1 Under a different set of conditions, the initial concentration of Br - is 0.00 M. 21 seconds later it is 0.61 M. What is the rate of change of Br - in M/s? Answer: Notice that the rate of change of a product is positive because it is being produced. Correct Marks for this submission: 1/1. Question3 Marks: 1 Under a different set of conditions, the initial concentration of BrO 3- is 0.20 M. 56 seconds later it is 0.90 M. What is the rate of change of BrO 3- in M/s? Answer: Notice that the rate of change of a product is positive because it is being produced. Correct Marks for this submission: 1/1. Question4 Marks: 1 Still for the reaction: 3BrO-(aq) --> BrO3-(aq) + 2Br-(aq), what is the rate of reaction in M/s, if [BrO- ]/t = (-0.232) M/s? Help: Rate of reaction Answer: Note that the rate of reaction is always positive. Correct Marks for this submission: 1/1. Question5 Marks: 1 Under a different set of conditions [BrO3- ]/t = 0.024 M/s. What is the rate of reaction in M/s? Answer: Note that the rate of reaction is always positive. Correct Marks for this submission: 1/1. Question6 Marks: 1 Under a different set of conditions [Br - ]/t = 0.035 M/s. What is the rate of reaction in M/s? Answer: Note that the rate of reaction is always positive. Correct Marks for this submission: 1/1. Question7 Marks: 1 If [BrO3- ]/t = 0.038 M/s. What is [Br- ]/t in M/s? Reminder, the rate of change [BrO3- ] is [BrO3- ]/t. Help: Rate of change of reactants and products Answer: Correct Marks for this submission: 1/1. Question8 Marks: 1 If [BrO3- ]/t = 0.028 M/s. What is [BrO- ]/t in M/s? Answer: Correct Marks for this submission: 1/1. Question9 Marks: 1 The rate of change of [B] is (-0.041) M/min. What is the rate of reaction for the following reaction in M/min? 2A + 5B 3C + 7D Answer: Correct Marks for this submission: 1/1. Question10 Marks: 1 Under a different set of conditions, the rate of change of [C] is 0.068 M/min. What is the rate of change of [D] in M/min? Hint given in feedback Answer: Hint, if a = b and b = c, then a = c. Specifically, what is the rate of reaction using [C] and what is the rate using [D]? Set the rate using [C] = the rate using [D] and solve for the rate of change of [D]. Correct Marks for this submission: 1/1. Question11 Marks: 1 If the rate of change of [C] is 0.087 M/min. What is the rate of change of [A] in M/s? Hint given in feedback Answer: Hint. What is the rate of reaction using [C] and what is the rate using [A]? Set the rate using [C] = the rate using [A] and solve for the rate of change of [A]. Check: is the rate of change of [A] positive or negative? Finally, units for rate of change of [A] are M/s not M/min. (1/min) = (1/min)(1 min/60 s). Correct Marks for this submission: 1/1. Question12 Marks: 1 For the reaction 2A +3B C + 4D The rate of reaction = k[A]0.5[B]2 Which of the following statements are true? Help: Order of reaction Choose at least one Register to View AnswerThe reaction rate with respect to A is 0 order. b. The reaction rate with respect to A is one-half order. c. The reaction rate with respect to B is first order. d. The reaction rate with respect to B is second order. e. The overall reaction rate order is 1. f. The overall reaction rate order is 2. g. The overall reaction rate order is 2.5. Correct Marks for this submission: 1/1. Question13 Marks: 1 For a new reaction with reactant "A", suppose the rate of reaction is 0.04 M/sec when [A] = 0.23 M. The concentration of A is doubled to 0.46 M. Match the rate of reaction to the reaction order. Help: Rate of reaction and order Rate is still 0.04 M/s Rate is 0.04 x 20.5 = 0.057 M/s Rate is 0.04 x 21 = 0.08 M/s Rate is 0.04 x 22 = 0.16 M/s Correct Marks for this submission: 1/1. Question14 Marks: 1 For the reaction 2NO2(g) 2NO(g) + O2(g) the following experimental data was obtained for the rate: Ru [NO2] Rate n (M) (M/s) 1 0.16 0.27 2 0.32 1.08 3 0.64 4.32 What is the reaction rate order? Hint given in feedback. Choose one Register to View Answerzero-order b. one half-order c. first-order d. second order Hint, what happens to the reaction rate when the concentration reactant is doubled? Correct Marks for this submission: 1/1. Question15 Marks: 1 What is k? Hint given in feedback Answer: Substitute the data from one of the runs into the appropriate equation and solve for k. For zero-order, the rate of reaction = k[NO 2]0 = k. For first-order, the rate of reaction = k[NO 2]1 For one half-order, the rate of reaction = k[NO 2]0.5 For second-order, the rate of reaction = k[NO2]2 Correct Marks for this submission: 1/1. Question16 Marks: 1 What are the units of k? Help: Finding units of k Choose one Register to View AnswerM/s b. M0.5/s c. 1/s or s-1 d. 1/(Ms) or M-1s-1 e. unitless Correct Marks for this submission: 1/1. Question17 Marks: 1 What is the rate when [NO2] = 0.0932 M? Hint given in feedback Answer: Use the rate equation for the correct order with the k that you determined. Correct Marks for this submission: 1/1. Question18 Marks: 1 For the reaction 2H2O2(aq) 2H2O(l) + O2(g) the following experimental data was obtained for the rate: Ru [H2O2] Rate n (M) (M/s) 1 0.043 0.19 2 0.065 0.29 3 0.086 0.38 What is the reaction rate order? Hint given in feedback Choose one Register to View Answerzero-order b. one half-order c. first-order d. second order It is easiest to use the first and third run to determine the order. Correct Marks for this submission: 1/1. Question19 Marks: 1 What is k? Hint given in feedback Answer: Substitute the data from one of the runs into the appropriate equation and solve for k. For zero-order, the rate of reaction = k[H2O2]0 = k. For first-order, the rate of reaction = k[H2O2]1 For one half-order, the rate of reaction = k[H2O2]0.5 For second-order, the rate of reaction = k[H 2O2]2 Correct Marks for this submission: 1/1. Question20 Marks: 1 What are the units of k? Choose one Register to View AnswerM/s b. M0.5/s c. 1/s or s-1 d. 1/(Ms) or M-1s-1 e. unitless Correct Marks for this submission: 1/1. Question21 Marks: 1 What is the rate when [H2O2] = 0.049 M? Hint given in feedback Answer: Use the rate equation for the correct order with the k that you determined. Correct Marks for this submission: 1/1. Question22 Marks: 1 For the reaction 2A(g) + 3B(g) C(g) + 2D(g) the following experimental data was obtained for the rate: Ru [A] [B] Rate n (M) (M) (M/min) 1 0.01 0.2 2.2 2 0.01 0.4 4.4 3 0.02 0.4 8.8 The rate of reaction = kAxBy. What is x? Hint given in feedback Answer: Hint: Notice that in run #2 and #3 the concentration of B does not change. So, it does not change the rate. Therefore, you can use these runs to find the order of the reaction with respect to A. In what two runs is the concentration of A the same? Use these runs to find the order of the reaction with respect to B. Correct Marks for this submission: 1/1. Question23 Marks: 1 What is y? Answer: Correct Marks for this submission: 1/1. Question24 Marks: 1 What is k? Answer: Correct Marks for this submission: 1/1. Question25 Marks: 1 What are the units of k? Choose one Register to View AnswerM/min b. M0.5/min c. 1/min or min-1 d. 1/(Mmin) or M-1min-1 e. unitless Correct Marks for this submission: 1/1. Question26 Marks: 1 What is the rate when [A] = 0.057 M and [B] = 0.127 M? Hint given in feedback Answer: Use the rate equation for the correct order with the k that you determined. Correct Marks for this submission: 1/1. You are logged in as Nayankumar Rana (Logout) 2011S-CHEM126-Gilbert 1.208156 secsRAM: 4.2MBRAM peak: 4.3MBIncluded 80 filesDB queries 280Log writes 1ticks: 121 user: 12 sys: 3 cuser: 0 csys: 0Load average: 1.47 Chapter 13 Basic Homework: Kinetics II Review of attempt 1 Started on Sunday, 30 January 2011, 02:24 PM Completed on Sunday, 30 January 2011, 03:29 PM Time taken 1 hour 4 mins Marks 12/12 Grade 4 out of a maximum of 4 (100%) Question1 Marks: 1 For the first-order rate of reaction A --> B + C, what is the concentration of A (in M) after 14.0 s if [A]o = 0.70 M and k = 0.024 s-1? Help: First order rate of reaction Answer: Correct Marks for this submission: 1/1. Question2 Marks: 1 For a first-order reaction, the initial reactant concentration is 0.818 M. After 61.1 min, the concentration is 0.242 M. What is k in min-1? Help: First order rate of reaction Answer: Correct Marks for this submission: 1/1. Question3 Marks: 1 For a first order reaction, the initial reactant concentration, [A] o, is 0.93 M. After 12.2 s, the concentration is 0.70 M. What is [A] after 35 s? Hint given in feedback Answer: Do the problem in 2 steps. First find k and then the new concentration. Correct Marks for this submission: 1/1. Question4 Marks: 1 Suppose the rate of reaction is second order for A B + C. What is the concentration of A (in M) after 82.0 s if [A]o = 0.60 M and k = 0.042 M-1s-1 Help: Second order rate of reaction Answer: Correct Marks for this submission: 1/1. Question5 Marks: 1 For a second-order reaction, the initial reactant concentration is 0.86 M. After 79.5 min, the concentration is 0.31 M. What is k in M-1min-1? Help: Second order rate of reaction and k Answer: Correct Marks for this submission: 1/1. Question6 Marks: 1 For a second order reaction, the initial reactant concentration, [A] o, is 0.88 M. After 10.3 s, the concentration is 0.58 M. What is [A] after 65 s? Hint given in feedback Answer: Solve the problem in 2 steps. First fine k (like earlier problems) and then use the second order integrated rate equation to get the concentration. Correct Marks for this submission: 1/1. Question7 Marks: 1 For the zero-order rate of reaction A B + C, what is the concentration of A (in M) after 24.0 s if [A]o = 0.80 M and k = 0.016 Ms-1? Help: Zero order rate of reaction Answer: Correct Marks for this submission: 1/1. Question8 Marks: 1 For a certain reaction, when the natural log of the reactant concentration is plotted against the time in seconds a straight line is obtained. What is the reaction order? Help: Comparison of rate laws Choose one Register to View Answerzero-order b. first-order c. second-order Correct Marks for this submission: 1/1. Question9 Marks: 1 For the above reaction, the slope is -0.016. What are the units of the slope and what is k? Note, logs are unitless! Additional hint given in feedback. Choose at least one Register to View Answerunits: M/s b. units: 1/s c. units: 1/(Ms) d. k = -0.016 M/s e. k = +0.016 M/s f. k = -0.016 1/s g. k = +0.016 1/s h. k = -0.016 1/(Ms) i. k = +0.016 1/(Ms) The slope is the change in y divided by the change in x. So, the units are the units of y divided by the units of x. Correct Marks for this submission: 1/1. Question10 Marks: 1 For the reaction D A + C when 1/[D] is plotted versus the time in seconds, a straight line is obtained whose slope is 0.020 M-1s-1. What is the concentration of D (in M) after 52.0 s if [D]o = 0.60 M? Hint given in feedback Answer: Hint, use the information given about the plot to determine the order of the reaction and k. Next use appropriate integrated rate equation to determine the concentration. Correct Marks for this submission: 1/1. Question11 Marks: 1 For the reaction A B + C when [A] is plotted versus the time in minutes a straight line is obtained whose slope is -0.020 M/min. What is the concentration of A (in M) after 10.00 min if [A]o = 0.70 M? Answer: Correct Marks for this submission: 1/1. Question12 Marks: 1 For the reaction A B + C, when the natural log of [A] is plotted versus the time in seconds a straight line is obtained whose slope is -0.024 s-1. What is the concentration of A (in M) after 55.0 s if [A]o = 0.30 M? Answer: Correct Marks for this submission: 1/1. Chapter 13 Regular Homework: Kinetics I Review of attempt 6 Started on Monday, 31 January 2011, 04:53 PM Completed on Monday, 31 January 2011, 04:54 PM Time taken 1 min 1 sec Marks 20/20 Grade 10 out of a maximum of 10 (100%) Question1 Marks: 2 Cyclobutane can decompose to form ethylene: C4H8(g) 2C2H4(g). The cyclobutane concentration can be measured as a function of time (shown below) by mass spectrometry . Which of the following is the rate of reaction? Choose at least one Register to View AnswerThe rate of change of cyclobutane b. -(The rate of change of cylcobutane) c. The rate of change of ethylene d. 2(The rate of change of ethylene) e. 0.5(The rate of change of ethylene) Correct Marks for this submission: 2/2. Question2 Marks: 1 Calculate the average rate of reaction between 11.0 and 43.0 s (units mol/L/s). Answer: Correct Marks for this submission: 1/1. Question3 Marks: 1 Calculate the instantaneous rate of reaction at 29 s (units mol/L/s). (It is a good idea to print the page in order to draw an accurate tangent line.) Answer: Correct Marks for this submission: 1/1. Question4 Marks: 1 Calculate the initial rate of reaction (units mol/L/s). Answer: Correct Marks for this submission: 1/1. Question5 Marks: 1 Calculate the instantaneous rate of formation of ethylene at 60.0 s (units mol/L/s). Answer: Correct Marks for this submission: 1/1. Question6 Marks: 1 Under certain conditions, biphenyl, C12H10, can be produced by the decomposition of cyclohexane, C6H12 (see below). The table represents part of the data obtained in kinetics experiments. What is the biphenyl concentration at 2.00 s? Answer: Correct Marks for this submission: 1/1. Question7 Marks: 1 What is the cyclohexane concentration when the biphenyl concentration is 0.068 M? Answer: Correct Marks for this submission: 1/1. Question8 Marks: 1 What is the hydrogen concentration when the biphenyl concentration is 0.064 M? Answer: Correct Marks for this submission: 1/1. Question9 Marks: 1 Estimate the instantaneous rate of reaction at 0.5 s, by calculating the average rate between 0.00 and 1.00 s? Answer: Remember the rate of reaction only = -(rate of change of reactant) if the coefficient is one. Correct Marks for this submission: 1/1. Question10 Marks: 1 Use the initial rate data in the next question to determine the rate law and rate constant for the gas-phase reaction of nitrogen monoxide and chlorine: 2NO(g) + Cl2(g) --> 2NOCl(g) Rate law: reaction rate = k[NO]x[Cl2]y What are x and y. Choose at least one Register to View Answerx =0 b. x = 0.5 c. x = 1 d. x = 2 e. y = 0 f. y = 0.5 g. y = 1 h. y = 2 Correct Marks for this submission: 1/1. Question11 Marks: 1 Given: What is K? Answer: Correct Marks for this submission: 1/1. Question12 Marks: 1 For the decomposition of reactant M, determine the order of the reaction from the concentration-time dependence given in the next question. Very useful help for this and the next few problems is found in Ch 13 Supplemental Materials (plotting for kinetics)Book (located below the Ch 13 Supplements). Answer: Correct Marks for this submission: 1/1. Question13 Marks: 1 Determine the rate constant from the concentration-time dependence: Time [Reactant] (s) (M) 0.0 0.0451 2.0 5.0 9.0 15 0.0421 0.0376 0.0316 0.0226 Use SI units, that is, seconds for time (not included in answer). Answer: units: mol/L/s Correct Marks for this submission: 1/1. Question14 Marks: 1 For the decomposition of reactant M, determine the order of the reaction from the concentration-time dependence given in the next question. Answer: Correct Marks for this submission: 1/1. Question15 Marks: 1 Determine the rate constant from the concentration-time dependence: Time [Reactant] (s) (M) 0.0 0.0350 10 0.0223 20 0.0142 50 0.0037 70 0.0015 Use SI units, that is, seconds for time (not included in answer). Answer: Correct Marks for this submission: 1/1. Question16 Marks: 1 Determine the order of the reaction from the concentration-time dependence given in the next question. (If needed, a hint is given in the general feedback.) Answer: Hint, (1) print the graph and draw a smooth curve through the data. (2) Construct a table of time and concentration. (3) You are now at the starting point for a procedure you have already used. Correct Marks for this submission: 1/1. Question17 Marks: 1 Determine the rate constant from the concentration-time dependence. Answer: units: L/mol/s Correct Marks for this submission: 1/1. Question18 Marks: 1 Calculate the half-life (in s) of a first-order reaction if the concentration of the reactant is 0.0796 M 27.4 s after the reaction starts and is 0.0324 M 78.4 s after the reaction starts. Answer: Correct Marks for this submission: 1/1. Question19 Marks: 1 Suppose the half-life is 13.7 s and the reactant concentration is 0.0466 M 15.6 s after the reaction starts. How many seconds after the start of the reaction does it take for the reactant concentration to decrease to 0.0139 M? Answer: Correct Marks for this submission: 1/1.

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English HL 2 IB 12 October 2009 Hamlet's Conflicting Obligations to his Father and to his Country In Shakespeare's well known play, Hamlet, young prince Hamlet's mind is being pulled in several conflicting directions. His greatest internal struggle is one
Saddleback - ENG - 101
English HL 1 IB, Period 2 11 September 2008 An Ambition for Equality Alex Haley's The Autobiography of Malcolm X is a work that is known worldwide which includes rhetorical strategies and symbols to draw the reader into the unobstructed view of the life o
Saddleback - ENG - 101
English HL 1 IB Paul's Forewarning to Americans Martin Luther King is a black civil rights activist who is extremely famous today for his grand impact on society and segregation, his wiliness to fight for what he believed in, and especially for his speech
Saddleback - ENG - 101
English HL 2 IB 11 November 2009Title: "Portrait of a Lady" Year Published: 1910 Theme: There is an uncertainty of how to live one's life until it becomes too late.Two separate but distinct tones: The author has both a tone of sadness, and a trusting to
Saddleback - ENG - 101
English HL 2 IB, Period 6 17 December 2009 Participation Outline: Group 6 For our group we decided to organize our presentation by stanza. Once we had divided the stanzas so that no stanzas with enjambment were separated; we assigned each group member a s
Saddleback - ECON - 101
The Best Way to Show Economic Improvement in a Recession Period 3 15 October 2009Word Count: 683 The article that I researched for this economics extract was an article that I found in the Los Angeles Times online database. The topic of this article incl
Saddleback - ECON - 101
Macroeconomics 4 December 2009 U.S. Government Unit The Constitution: Fixed or Flexible 1) The Supreme Court judges, along with all other judges have the job of interpreting the vaguely worded phrases in the constitution. They must interpret these sentenc
Saddleback - ECON - 101
Which is Better: Extremely High or Low Inflation? Period 3 7 January 2010Word Count: 748 The article that I researched for the second economics extract was an article from an online data base called Inflation Data. This article discussed inflation in the
Saddleback - ECON - 101
The Future Economy for Southern California Period 3 18 February 2010Word Count: 659 For my third Macroeconomics extract commentary I looked at the LA Times which I receive at my house to find an update on the economy. I found an article that I really enj
Saddleback - ECON - 101
Oil Falls to Near $81 in Europe as Traders Eye Stronger US Dollar Period 3 23 March 2010Word Count: 664 The article that I researched for our last economics extract was an article that I found in the Los Angeles Times online database. The topic of this a
Saddleback - SPAN - 101
30 October 2009 Heath Ledger Heath Ledger fue un actor muy famoso hasta que muri de forma inesperada. Naci en Australia en 1979. Estaba en diez a quince pelculas de alto presupuesto y convertirse en un afer actor bien conocido de dos de ellos. Algunas de
Saddleback - SPAN - 101
Mrs. Dyer Spanish 4, Period 4 22 Marzo 2010 Diego Velzquez Velzquez fue un pintor muy talentoso, que naci en Sevilla en mil cinco cientos noventa y nueve. Fue educado como un nio, pero su inters en el arte. Velzquez empez a hacer prcticas con otros artist
Saddleback - SPAN - 101
Me llamo Kelly. Tengo dieciocho aos. Yo soy italiano y europeo. Tengo los ojos cafs y el pelo moreno. Soy ambicioso porque mi padre es muy ambicioso tambin. Me gusta los gatos, pero no me gusta perros. Me gustara perros, porque tengo tres, pero creo que o
Saddleback - MATH - 101
Women in Art throughout the AgesMath Studies IB SL
Saddleback - MATH - 101
Women in Art throughout the AgesMath Studies IB SLCriterion A: IntroductionWomen in Art throughout the AgesFor my IB project I am going to look at women in art throughout the years. I will pick five famous pictures containing women from all different
Saddleback - MATH - 101
Work Cited Hurley, Terry. "Golden Ratio in a Face." LoveToKnow. 29 Oct. 2009. Web. 9 Dec. 2010. <http:/feng-shui.lovetoknow.com/Golden_Ratio_in_a_Face>. "Project Management's Golden Ratio." Virtual Project Consulting. 2009. Web. 9 Dec. 2010. <http:/www.go
Saddleback - MATH - 101
Criterion B: Information/Measurement Golden Ratio= 1.618 Determining if a person is perfectly proportioned will rely on how similar their measurements are to 1.618. The experiment is measured using units of centimeters. None of the measurements have been
Saddleback - MATH - 101
Criterion D: Interpretation of Results Overall my results have led me to a conclusion that was not the same as my hypothesis. My hypothesis was that every art work, regardless of the era, would show some relevance to the golden ratio. The women in the fiv
Saddleback - MATH - 101
Criterion C: Mathematical Processes There are three ratios I chose to find out if the golden ratio was present for each era in art. Golden Ratio Factions: a b 1. Top of head Width of head 2. Tip of nose to chin Lips to chin 3. Length of Lips Width of Nose
Saddleback - MATH - 101
Criterion A: IntroductionWomen in Art throughout the AgesFor my IB project I am going to look at women in art throughout the years. I will pick five famous pictures containing women from all different eras in art. With these pictures I will calculate th
Saddleback - MATH - 101
Criterion E: Validity I used a variety of mathematical processes to determine the golden ratios for a variety of different types of art. In finding the Golden Ratio I was able to see the changes in how artists depicted the female body throughout each era.
Saddleback - MATH - 101
Women in Art throughout the AgesIn my project, my task is to research famous paintings of women that were created in different time periods and eras. The art will be collected and all of the women will be measured out so that all of their golden ratios c
Saddleback - SOCIOLOGY - 101
Mr. Schumacher, Sociology Period 2 5 March 2010A Night at the MoviesPlan of Action:Our plan for altering the social norm was to go to the movies on a crowded Friday night to a new and popular show and talk on our cell phones the whole time. We are plan
Saddleback - PHYS - 101
Period 7 Physics Mr. Waldrep 19 April 2010 Resistors in Series and Parallel Analysis Questions 2. The three resistors added together equal the value of Req. My lab group calculated Req to be 29,690 Ohms. The total resistance of the three resistors in seri
Saddleback - CHEM - 101
Chemistry Honors 2nd Semester Exam Study Guide Exothermic any process that gives off heat/ heat given off by the system to the surroundings/ solidification, condensation Endothermic heat has to be supplied to the system by the surroundings/ heat absorbed
Saddleback - CHEM - 101
Chemistry Honors Thermochemistry Study Guide thermochemistry: the study of hear change in chemical reactions exothermic process: any process that gives off heat transfers thermal energy to the surroundings endothermic process: heat has to be supplied to t
University of Phoenix - IT 240 - IT 240
Application LayerPresentation LayerSession LayerTransport LayerNetwork LayerData Link LayerPhysical LayerThe application layer interacts with software applications that implement components. The application layer controls the interactions between t
University of Phoenix - IT 240 - IT 240
Pat is the network engineer for the Acme Corporation, a nationwide bank. He needs to design a wide area network (WAN) that will connect offices in Dallas, San Francisco, Denver, and Tallahassee. The WAN that Pat designs should provide redundancy to ensure
University of Phoenix - IT 240 - IT 240
Workstation B and Workstation C Have the same IP address. All the devices must have a unique IP address in order to function properly. Both computers being assigned the same IP address will cause a network conflict and those two particular hosts will have
University of Phoenix - IT 240 - IT 240
I would start by deciding on a desirable website name, then checking the availability of the website using "whois.net". This will give me a list of available domains I could purchase or it would send me to a site where I could purchase the desired domain
University of Phoenix - IT 240 - IT 240
Statement (b) categorizes the proposed solution. In my opinion the 1000Base LX seems to be the best choice for the proposed solution. While the 1000Base LX does not meet the length requirement to connect the two buildings it does however, achieve the two
University of Phoenix - IT 240 - IT 240
The following terms illustrate the standard hardware devices utilized in basic network communications. Define each of these terms and provide at least one example of that device utilizing the internet (example; Network Card Broadcom NetExtreme Gigabit Con
FGCU - 4255 - 435
APPLICATIONDeadline to Apply: Monday, February 6, 2012 4:00PM(Please print clearly) Contact Information Today's Date _Name _ Drexel Student ID#_ Permanent Address _ City _ State _ Zip _ Telephone _ Drexel Email _@drexel.edu Academic Profile Are you cur
FGCU - GERG - 5425
A.P. Biology: Chapter 12 & 13 Test1. The centromere is a region in which a. chromatids are attached to one another. b. metaphase chromosomes become aligned. c. chromosomes are grouped during telophase. d. the nucleus is located prior to mitosis. e. new s
FGCU - BIO - 102
Stanford and Kabnick Fall 2011 Exam I Learning Objectives Discover the best ways for you to engage and learn course materials Know: Unique features of prokaryotic cells What Archaea are that both plants and animals are made up of eukaryotic cells, though
FGCU - BIO - 102
Stanford and Kabnick Fall 2011 BIO 122: Cells and Genetics Recitation Week 4 Goals: 1. Review any questions you have about HW#3 2. Discuss important concepts from Week 3's lectures Prior to Recitation: Make sure you submit your homework assignment by 11:5
FGCU - BIO - 102
Stanford Exam II Learning Objectives Discover the best ways for you to engage and learn course materials Know: Unique features of prokaryotic cells What Archaea are that both plants and animals are made up of eukaryotic cells, though these cells differ in
FGCU - BIO - 102
Stanford and Kabnick Fall 2011Rubric for Report on SDH Activity Due Week 5 at the Beginning of Lab You must write a double-spaced report that includes the following parts: Title: The title should be descriptive. It should explain the question being addre
FGCU - BIO - 102
Stanford and Kabnick Fall 2011 BIO 122: Cells and Genetics Recitation Week 5 Goals: 1. Review any questions you have about HW#4 2. Discuss important concepts from Week 4's lectures Prior to Recitation: Make sure you submit your homework assignment by 11:5
FGCU - BIO - 102
Stanford and Kabnick Fall 2011Bio 122: Week 2 Lab Goals:1. 2. 3. 4.Learn how to use a micropipettor Use a blender and centrifuge to isolate your cell fractions for the SDH assays Aliquot your mitochondrial and crude cell fractions for use over the next
FGCU - BIO - 102
Stanford and Kabnick Fall 2011Bio 122: Week 3 Lab Goals: Bradford Assay: 1. To gain practice with conducting the Bradford Assay 2. To use a dilution series of BSA in a Bradford assay to generate a Standard Curve 3. To use Excel to plot Concentration v. A
FGCU - BIO - 102
Stanford and Kabnick Fall 2011Bio 122: Week 4 Lab Goals: 1. To repeat the SDH assay using a second aliquot of the mitochondrial fraction 2. To test your group's hypothesis about your assigned reagent Preparing for Lab: Review the protocol for the SDH ass
FGCU - BIO - 102
Stanford Exam II Learning Objectives Discover the best ways for you to engage and learn course materials Know: Unique features of prokaryotic cells What Archaea are that both plants and animals are made up of eukaryotic cells, though these cells differ in
FGCU - BIO - 102
Week 6 Types of reporuction Asexual is identical genetics. One cell becomes two cells. Mostly identiacal Too types binary fission in prokaryotes Mitosis in eukarotes Reason why always not identical. Because mutation can happen. 1 parent SexualWhy meiosis
FGCU - BIO - 102
Week 7 Chromosome are llots and lot of dna. Dna is important because it incodes genes and genes incode proteins and that . each chormoomes has genes on it which has prtein on it. Gene loci has genes in it If protehn does not work right you may be sickled
FGCU - BIO - 102
It always out from origin of replicaion. Helicase unwinds it Ssb relives tension. Low error rate. Polymerase can proofread and repair or remove it. ]Key enzyemes Dna helixase Ssb toposimerase Dna primase Dna polemarse 1 2 3 Dna ligase Other nuclear for r
FGCU - BIO - 102
Conclusion Our results showed the phenotypes to include three white to one red (Fig. 3). This proved our hypothesis which also three white to 1 red (Fig. 2).
FGCU - BIO - 102
Harpreet Singh, Chris Sutera, Tony Tran, Carlos November 30, 2011 Biology Lab Report Introduction For the experiment, we crossed two saccharomyces cerevisiae haploid strains Haploid strains appears during Meiosis I creating spores The spores become eith