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Topic 13

Course: STAT 502, Fall 2011
School: Purdue University -...
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13 Topic Random Effects Background Reading: Parts of Chapters 17 and 19 1 Reading Summary Section 17.1 (particularly page 422) Section 17.6 (pages 438-440) Section 19.7 (pages 538-541) 2 Random Effects So far we have really only dealt with fixed effects we set the levels (or they are at least predetermined) and are only interested in those particular levels. Often we have factors with lots of...

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13 Topic Random Effects Background Reading: Parts of Chapters 17 and 19 1 Reading Summary Section 17.1 (particularly page 422) Section 17.6 (pages 438-440) Section 19.7 (pages 538-541) 2 Random Effects So far we have really only dealt with fixed effects we set the levels (or they are at least predetermined) and are only interested in those particular levels. Often we have factors with lots of levels, and to get observations at all of them would be inconvenient if we could do it at all. So we take a random sample of levels hence random effects. 3 Fixed vs. Random Recall: A factor is fixed if the levels under consideration are the only ones of interest. Selected by a nonrandom process. (e.g. gender, hair color) A factor is random if the levels under consideration may be regarded as a sample from a larger population. Want to draw inference on this larger population of levels. (e.g. subject / person) 4 Why care about fixed/random? Affects the expected mean squares on which F-tests are based. No major differences for 1-way ANOVA. For ANOVA with multiple factors and interactions, we will see that different ratios of mean squares will be needed for the significance tests. The denominator will no longer always be the MSE. Affects interpretations as well (we wouldnt do multiple comparisons for a random factor). 5 CLG Discussion For each of three examples: 1. Identify the response variable and factors involved in each study. 2. Identify a research question of interest. 3. Determine the number of levels for each factor, and decide whether each factor is fixed or random. 6 Example 1 Auto manufacturer wants to study the effects of differences between drivers (A) and differences between cars (B) on gasoline consumption. Four drivers were selected at random, and additionally five cars of the same model with manual transmissions were randomly taken from the assembly line. Each driver drove each car twice over a 40-mile test course and the MPG were recorded. 7 Example 1 Response: Research Question: Factor Levels Fixed/Random 8 Example 2 A researcher studied the sodium content of six brands of U.S. beers sold in a metropolitan area. For each beer, both the regular and light versions were examined. 9 Example 2 Response: Research Question: Factor Levels Fixed/Random 10 Example 3 Twelve job applicants were rated by each of the three personnel officers for a company. Each applicant was rated by each officer. We want to explore whether there are differences among the personnel officers. 11 Example 3 Response: Research Question: Factor Levels Fixed/Random 12 Random Effects - Variances When we have random effects, we have multiple variances: Variance associated with the effect itself (e.g. subject there is a variance associated to the population of subjects from which we sample a few) Variance associated with taking an observation (otherwise known as error). 13 Random Effects - Variances In two factor model, we have 3 possibilities: Fixed (both factors fixed) Random (both factors random) Mixed (one fixed and one random) If we have three or more factors, the number of possibilities grows even more. Well examine the two-factor model in depth, but also learn what to use SAS for three or more factors. 14 One-factor Random Model Model (use capital English letters to denote a random component in a model): Yij = + Ai + ij Independent { i = 1, 2, ..., k j = 1, 2, ..., n = grand mean 2 DIFFERENCE! Ai ~ N 0, A IID 2 ~ N 0, ijk ( ) () 15 One-factor Random Model Expected Mean Squares (balanced design) E ( MSA ) = E ( ) 2 n ( Yi2 ) NY2 = n A + 2 E ( MSE ) = 2 We want to test whether there is a treatment effect. There is one if and only if we have variability among the treatments. The null: 2 H0 : A = 0 16 One-factor Random Model (2) Variances are never negative, so we test against the one-sided alternative: 2 Ha : A > 0 Under the null hypothesis, the of MSA to MSE is 1. Such a ratio provides the F-test, and we note that it is the exact same F-test that we would have if the treatment was fixed. 17 One-factor Random Model (3) So there is no difference in the actual test when we have only one variable. But there is a difference in the interpretation: FIXED: There is a significant effect of Factor A, and we may go on to further analyze this effect using multiple comparisons. RANDOM: There is variability in the response that may be attributed to differences in Factor A. No multiple comparisons here since not all levels of interest are involved in the study, multiple comparisons wont be relevant. 18 Two-factor Random Model Model: Yijk = + Ai + B j + ( AB ) ij + ijk = grand mean 2 Ai ~ N 0, A i = 1, 2, ..., a j = 1, 2, ..., b k = 1, 2, ..., n () B ~ N ( 0, ) ( AB ) ~ N ( 0, ) 2 DIFFERENCES! j B Independent 2 ij AB ~ N 0, 2 , independent ijk ( ) 19 Two-factor Random Model The first thing we must do is to consider Expected Mean Squares. For a balanced design, they are: 2 2 E ( MSA) = bn A + n AB + 2 E ( MSB ) = an + n 2 B 2 AB + 2 2 E ( MSAB ) = n AB + 2 E ( MSE ) = 2 20 Testing (Two Random Factors) EMS determine what MS to use in the denominator of our test. Suppose we want to test: 2 H0 : A = 0 We consider the expectation under the null: 0 2 2 E ( MSA ) = bn A + n AB + 2 Z = n 2 AB + = E ( MSAB ) 2 21 Testing (Two Random Factors) So to test the effect of Factor A, we must use the ratio: F = MSA / MSAB. The DF for this test come from the ANOVA table as well: Numerator: Associated to MSA Denominator: Associated to MSAB 22 Two-factor Random Model In general, EMS determine what MS to use in the denominator of our test. For the twofactor random model, the complete set of tests is: 2 H 0 : A = 0 F = MS A / MS AB H 0 : = 0 F = MS B / MS AB 2 B H0 : 2 AB = 0 F = MS AB / MS ERR 23 Two-factor Mixed Model Model (A fixed, B random): Yijk = + i + B j + ( B ) ij + ijk = grand mean i =0 ( i = 1, 2, ..., a j = 1, 2, ..., b k = 1, 2, ..., n SAME! ) 2 B j ~ N 0, B DIFFERENCES! ( AB ) ~ N 0, 2 Independent ij AB ~ N 0, 2 , independent ijk ( ( ) ) 24 Another Wrinkle When one factor is fixed and the other random, it is not clear how to treat the interaction. Two possibilities: Unrestricted Model Interaction is simply taken to be random (SAS employs this model) Restricted Model For the fixed component of the interaction, the following restriction is still made: a ( B) i =1 ij = 0 for any fixed j 25 Mixed Model(s) Depending on which model is chosen, the EMS will be slightly different. There are numerous high-level statistically based arguments as to why one is better than the other. We will tend toward the unrestricted model simply it because is the one utilized in SAS. This stuff gets even more complicated when a third variable is added! 26 Two-factor Mixed Model Unrestricted Model (PROC GLM) Expected Mean Squares E ( MSA ) = Q ( A ) + n 2 AB + 2 2 2 E ( MSB ) = an B + n AB + 2 2 E ( MSAB ) = n AB + 2 E ( MSE ) = 2 Tests similar to random effects model. Note: Q(A) just denotes the fixed effects for A (zero if no effect). 27 Two-factor Mixed Model Restricted Model Assume i ( AB ) ij = 0 for all j. Expected Mean Squares E ( MSA ) = Q ( A ) + n 2 AB 2 E ( MSB ) = an B + 2 E ( MSAB ) = n 2 AB + + 2 DIFFERENCE! 2 E ( MSE ) = 2 Factor B for this model will be tested over MSE the rest of the tests are the same. 28 Generalizing... With three or more factors, tests must be based on EMS. You look for a pair of EMS for which the ratio will be 1 under your null hypothesis. Fortunately, SAS will print a table of EMS (for the unrestricted model) when random effects are indicated. 29 Example (A Random, BC Fixed) Source A B A*B C A*C B*C A*B*C Type III Expected Mean Square Var(Error) + 4 Var(A*B*C) + 8 Var(A*C) + 12 Var(A*B) + 24 Var(A) Var(Error) + 4 Var(A*B*C) + 12 Var(A*B) + Q(B,B*C) Var(Error) + 4 Var(A*B*C) + 12 Var(A*B) Var(Error) + 4 Var(A*B*C) + 8 Var(A*C) + Q(C,B*C) Var(Error) + 4 Var(A*B*C) + 8 Var(A*C) Var(Error) + 4 Var(A*B*C) + Q(B*C) Var(Error) + 4 Var(A*B*C) 30 Mixed Model Multiple Comparisons Remember that for random factors, it would not be useful to do multiple comparisons because Only some of the possible levels for the random factor are involved in the study. We want the results to extend to all possible levels of the random factor. We may, however, want to consider multiple comparisons for the fixed factor. 31 Mixed Model Multiple Comparisons (2) The variance associated to the fixed effect 2 will generally not be any more. So MSE is the wrong estimate. E ( MSA ) = Q ( A ) + n 2 AB + 2 2 E ( MSAB ) = n AB + 2 The correct estimate for the above will be MSAB (except in cases where MSE is larger than MSAB then those two effects should be combined in an additive model) 32 Mixed Model Multiple Comparisons (3) The GLM procedure always uses MSE to compare LSMeans, unless you tell it to do different. If MSAB > MSE, then in the LSMeans statement you should specify E=A*B as an option. If MSE > MSAB, simply remove the interaction term from the model. The MIXED procedure (new) does make this change automatically. 33 Example (Gas Mileage) See CLG Handout for SAS coding and full output. Also SAS file with the data, etc. online. Goal of the example is to illustrate random effects using SAS GLM and MIXED procedures 34 Example (Gas Mileage) Response is Gas Consuption Two Random Factors Four Drivers Five Cars Two observations per Driver*Car combination. 35 SAS Code proc glm; class driver car; model gas=driver|car; random driver car driver*car /test; run; Note: You must include ALL random effects INCLUDING INTERACTIONS in the random statement for GLM. Failing to include the interaction term will mean that it will improperly be treated as fixed. 36 Output ANOVA output is similar but not all of the Type I/III F-tests will be valid. These tests assume all factors are fixed. After ANOVA table comes Expected Mean Squares. You should be able to use these to figure out the appropriate tests. After the EMS come the results of /test. These are the correct tests for each effect. 37 Output Source driver car driver*car Type III Expected Mean Square Var(Error) + 2 Var(driver*car) + 10 Var(driver) Var(Error) + 2 Var(driver*car) + 8 Var(car) Var(Error) + 2 Var(driver*car) Tests of Hypotheses for Random Model Analysis of Variance Source DF Type III SS driver 3 280.284750 car 4 94.713500 Error 12 2.446500 Error: MS(driver*car) Source DF driver*car 12 Error: MS(Error) 20 Type III SS 2.446500 3.515000 Mean Squar e 93.428250 23.678375 0.203875 Mean Square 0.203875 0.175750 F Value 458.26 116.14 F Value 1.16 Pr > F <.0001 <.0001 Pr > F 0.3715 38 Using the EMS Suppose you want to test the effect of driver. No effect if Var(driver) = 0 If no effect, then EMS(driver) = EMS(driver*car) Test statistic should be MS(driver) divided by MS(driver*car). Note that you could do this by hand using Type I SS; the results also come from the /test option. 39 Studying Main Effects Interaction was insignificant, so we want to study main effects. Note: MS(car*driver) > MSE Used as error term for main effects, so we should leave it in the model (though taking it out would simplify things a bit and in this case wouldnt change much). The factors are random, so instead of doing pairwise comparisons, we instead estimate and compare variance components. 40 Variance Components The EMS can be used to get estimates for 2 2 A and B . both 2 2 E ( MSdriver ) = s 2 + 2sdr *car + 10sdr 2 E ( MSdr * car ) = s + 2s 2 dr *car 2 dr 10s = E ( MSdriver ) - E ( MSdr * car ) 41 Estimated Driver Variance The actual MS are estimates for the EMS. So we may estimate the variance for the driver: MSdriver - MSdr * car s= 10 93.4 - 0.2 = = 9.32 10 2 dr 42 Estimated Car Variance We may also estimate the variance for car: s 2 car MScar - MSdr * car = 8 23.7 - 0.2 = = 2.93 8 43 Conclusions There are both car and driver effects, but no significant interaction. Based on the estimated variances, we see clearly that the driver has a greater effect on gas mileage than the car. So how do we save gas? Train drivers to drive economically. There is likely little we could do about the car effect, so thankfully it was small. 44 The MIXED procedure Very similar to PROC GLM in coding Quite different in output 45 PROC MIXED proc mixed; class driver car; model gas=; random driver car driver*car; run; Note: Only fixed effects appear in the model statement; random effects appear ONLY in the random statement. 46 Advantages to MIXED Will provide correct LSMeans output for a model that contains random effects. Not relevant to this example. Will provide estimates for the variance components. Theyll be exactly what we just calculated. 47 Variance Components Covariance Parameter Estimates Cov Parm driver car driver*car Residual Estimate 9.3224 2.9343 0.01406 0.1757 48 Variance Components (2) It is sometimes possible that the estimates for the variance components may be negative. Since negative variances are not possible, what can we do? It makes sense to estimate the variance by zero. We can effectively do this by removing the term from the model which is reasonable unless higher order terms are significant. 49 CLG Activities We now have three more examples. Please do them in small groups; then well discuss them as a class. 50
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