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2 Pages

IRWIN 9e 2_28

Course: ESE 216, Spring 2012
School: UPenn
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Coursehero >> Pennsylvania >> UPenn >> ESE 216

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UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
12 mA
UPenn - ESE - 216
|12 mA
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UPenn - ESE - 216
UPenn - ESE - 216
12mA--'- ~Io11'210>12mA ^O|!>~n ~|-1-11>- 4.5m A
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
UPenn - ESE - 216
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R1
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R 2 = 12
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R eq ->
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o + + o -2 kW
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o + + o -
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2.88 Given I"=2 mA in the network in Fig. P2.88,find V.I'VA3v..1 kn+ VJ1 kfl't -Iq1 kfl~+-2kf!.,._I: :.~ ,2)C.KC,.L"1,). t I~.= I~VA :. -2,h - 2-D
UPenn - ESE - 216
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