UT Quest #1 Solutions
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UT Quest #1 Solutions

Course Number: PHYSICS 101, Fall 2012

College/University: Midwestern State...

Word Count: 3365

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mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 This print-out should have 55 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points What would equal 5 meters? 4. [T] 5. 1/[T] 6. [L]/[T]2 7. 1/[T]2 1. 50 dm correct 8. [T]/[L] 2. 50 dam 9. [L] 3. 50 mm 10. [L]/[T] correct 4. 50 cm Explanation: 5....

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(nm22898) mostow Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 This print-out should have 55 questions. Multiple-choice questions may continue on the next column or page nd all choices before answering. 001 10.0 points What would equal 5 meters? 4. [T] 5. 1/[T] 6. [L]/[T]2 7. 1/[T]2 1. 50 dm correct 8. [T]/[L] 2. 50 dam 9. [L] 3. 50 mm 10. [L]/[T] correct 4. 50 cm Explanation: 5. 0.5 km s = c1 t s c1 = t [s] [c1 ] = = [L]/[T] [ t] 6. 0.5 hm Explanation: (50 dm) 1m =5m 10 dm 002 10.0 points What unit of measure would you use for mass? 1. None of these 004 (part 2 of 5) 10.0 points Find the dimension for the quantity c2 in the expression s = c2 t2 . 2. liters 1. [T] 3. cubic centimeters 2. 1/[T] 4. grams correct 3. [T]2 /[L] Explanation: Liters and cubic centimeters are units of measure for volume. 4. [L] 003 (part 1 of 5) 10.0 points s is a distance with unit [L], t is a time with unit [T] and is an angle in radians. Find the dimension for the quantity c1 in the expression s = c1 t. 6. 1/[L] 1. 1/[L] 5. [L]/[T] 7. [L]/[T]2 correct 8. 1/[T]2 9. None of these 2. None of these 10. [T]/[L] 3. [T]2/[L] Explanation: mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 1 mL = 1 cc. s t2 [s] [c2 ] = 2 = [L]/[T]2 [ t] c2 = 010 10.0 points An electron travels 1.37 m in 5.89 108 s. How fast is it traveling? 005 (part 3 of 5) 10.0 points WITHDRAWN Correct answer: 2.32598 107 m/s. Explanation: 006 (part 4 of 5) 10.0 points WITHDRAWN Let : s = 1.37 m and t = 5.89 108 s . 007 (part 5 of 5) 10.0 points WITHDRAWN 008 10.0 points How many (whole number of) 90 kg people can safely occupy an elevator that can hold a maximum mass of exactly 1 metric ton? A metric ton is 1.000 103 kg. Correct answer: 11 people. v= s 1.37 m = t 5.89 108 s = 2.32598 107 m/s . 011 10.0 points Convert an acceleration of 5.7 mi/h/s to m/s2 . Correct answer: 2.54758 m/s2 . Explanation: Explanation: Let : 1 ton = 1.000 103 kg R = 90 kg/person . and Let : a = 5.7 mi/h/s . Using dimensional analysis, 1 person n = 1.000 10 kg 90 kg = 11.1111 persons 3 Note that the numerical answer 11.1111 must be rounded down to 11 people because of overload considerations. 009 10.0 points What is equivalent to a cubic centimeter? 1. centiliter 2. milliliter correct a= 5.7 mi 1.609 km 1000 m 1h hs 1 mi 1 km 3600 s = 2.54758 m/s2 . 012 10.0 points Convert 47.7 mi/h to m/s. 1 mi = 1609 m. Correct answer: 21.3193 m/s. Explanation: 1 mi = 1609 m (47.7 mi/h) 1 h = 3600 s 1609 m 1 h = 21.3193 m/s . 1 mi 3600 s 3. liter 4. deciliter Explanation: 013 10.0 points The average mass of an automobile in the United States is about 1.409 106 g. mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 Express this mass in kilograms. 015 (part 1 of 4) 10.0 points Use signicant gures to nd the sum of the measurements 759 g, 37.8 g, 0.87 g, and 2.8 g. 1. 1.409 1012 kg 2. 1.409 106 kg 1. Whole number (800 g) correct 3. 1.409 109 kg 2. Hundredths (800.47 g) 4. 1.409 109 kg 3. Tenths (800.5 g) 5. 1.409 1012 kg 4. Three signicant gures (800 g) 6. None of these 5. Tens (800 g) 7. 1.409 100 kg 6. One signicant gure (800 g) 8. 1.409 103 kg 7. None of these 9. 1.409 103 kg correct Explanation: 1 kg = 1 103 g , 8. Two signicant gures (800 g) so m = 1.409 106 g 1 kg 1 103 g = 1.409 103 kg . 014 10.0 points 1 Suppose your hair grows at the rate of inch 23 per day. Find the rate at which it grows in nanometers per second. Correct answer: 12.7818 nm/s. Explanation: R= 1 day 1h 1 inch 23 day 24 h 3600 s 9 nm 2.54 cm 10 1 in 100 cm Explanation: For addition/subtraction: measurement least precise 759 g + 37.8 g + 0.87 g + 2.8 g = 800.47 g The least precise measurement is a whole number of grams. 016 (part 2 of 4) 10.0 points 3. 3 m . Find the quotient 3.566 s 1. One signicant gure (0.9 m/s) 2. Hundredths (0.93 m/s) 3. Two signicant gures (0.93 m/s) correct 4. Tenths (0.9 m/s) 5. Three signicant gures (0.925 m/s) = 12.7818 nm/s . 6. Thousandths (0.925 m/s) The distance between atoms in a molecule is on the order of 0.1 nm, so this suggests how rapidly atoms are assembled in this protein synthesis. 7. Four signicant gures (0.9254 m/s) 8. None of these mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 Explanation: For multiplication/division: least signicant gures in measured quantities 3. 3 m = 0.925407 m/s 3.566 s The least number of signicant gures is 2. 7. Two signicant gures (24 s) 8. Tenths (24.0 s) correct 9. One signicant gure (20 s) Explanation: 017 (part 3 of 4) 10.0 points Find the product of 5.07 mm and . 1. Thousandths (15.928 mm) 27.57 s 3.6 s = 23.97 s The least precise measurement is a tenth of a second. 2. Two signicant gures (16 mm) 3. Five signicant gures (15.928 mm) 4. Four signicant gures (15.93 mm) 5. Hundredths (15.93 mm) 6. Three signicant gures (15.9 mm) correct 019 (part 1 of 3) 10.0 points You measure a distance to be 3 miles. Convert to the proper SI unit using signicant gures. 1. 4.83 km 2. 1.87 km 3. 2 km 7. Whole number (16 mm) 4. 1.9 km 8. None of these 5. 5 km correct 9. Tenths (15.9 mm) Explanation: 6. 4.8 km (5.07 mm)( ) = 15.9279 mm 7. 4.827 km The least number of signicant gures is 3 ( is a constant, not a measured quantity). 8. 1.865 km 018 (part 4 of 4) 10.0 points Find the dierence of 27.57 s and 3.6 s. Explanation: The measurement of 3 miles has only one signicant gure, so the results should be expressed in only one signicant gure: 1. Whole number (24 s) 2. Hundredths (23.97 s) 3. Four signicant gures (23.97 s) 4. Three signicant gures (24.0 s) (3 mi) 1.609 km = 4.827 km , 1 mi which should be rounded to 5 km. 020 (part 2 of 3) 10.0 points WITHDRAWN 5. Tens (20 s) 6. None of these 021 (part 3 of 3) 10.0 points A marathon is 26.3 miles. mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 Convert to centimeters using appropriate signicant gures. 6 8. None of these 9. 1 m 1. 42.310 cm 6 2. 410 cm 3. 4.232106 cm 4. 4.2106 cm 5. 0.423103 cm 10. 7 m Explanation: Since its nal position is the same as its initial position, the displacement is 0. 023 (part 2 of 2) 10.0 points What is the distance traveled? 6. 4.0106 cm 1. 7 m 7. 42.3167106 cm 2. 4 m 8. 4.23106 cm correct 3. 3 m Explanation: The measurement of 26.3 miles has three signicant gures, so the results should be expressed in three signicant gures: 1.609 km 100 cm 1000 m (26.3 m) 1 mi 1m 1 km = 4.23167 106 cm , which should be rounded to 4.23 106 cm. 022 (part 1 of 2) 10.0 points A physics book is moved once around the perimeter of a table of dimensions 1 m by 3 m. If the book ends up at its initial position, what is the magnitude of its displacement? 1. 8 m 4. 1 m 5. 6 m 6. None of these 7. 5 m 8. 2 m 9. 8 m correct 10. 0 m Explanation: The distance traveled is the perimeter of the table: d = 2 + 2 w = 2 (1 m) + 2 (3 m) = 8 m. 2. 5 m 6. 2 m 024 10.0 points An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel 1530 m/s in seawater. How deep is the water directly below the vessel if the time delay of the echo to the ocean oor and back is 7 s? 7. 0 m correct Correct answer: 5355 m. 3. 4 m 4. 3 m 5. 6 m Explanation: mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 Let : v = 1530 m/s and t = 7 s. Correct answer: 23.5 m/s. Explanation: The sound takes 3.5 s to reach the ocean oor (and 3.5 s to return), so Let : v0 = 14 m/s , t = 10 s , and a = 1.9 m/s2 . d = v t = (1530 m/s) (3.5 s) = 5355 m . v = v0 + a t, and 025 (part 1 of 2) 10.0 points A cyclist maintains a constant velocity of 6.3 m/s headed away from point A. At some initial time, the cyclist is 252 m from point A. What will be his displacement from his starting position after 42 s? Correct answer: 264.6 m. v= v0 + v v0 + (v0 + a t) 2 v0 + a t = = 2 2 2 2 (14 m/s) + (1.9 m/s2 ) (10 s) 2 = 23.5 m/s . = Explanation: Let : v = 6.3 m/s and t = 42 s . The distance is d = v t = (6.3 m/s) (42 s) = 264.6 m . 026 (part 2 of 2) 10.0 points What will be his position from point A after that time? Correct answer: 516.6 m. Explanation: Let : d0 = 252 m . The position is d = d0 + d = 252 m + 264.6 m = 516.6 m . 027 10.0 points A car is moving at a constant speed of 14 m/s when the driver presses down on the gas pedal and accelerates for 10 s with an acceleration of 1.9 m/s2 . What is the average speed of the car during the period? 028 (part 1 of 2) 10.0 points A person travels by car from one city to another. She drives for 25.2 min at 65.9 km/h, 9.92 min at 91.3 km/h, 36 min at 46.2 km/h, and spends 19.1 min along the way eating lunch and buying gas. Determine the distance between the cities along this route. Correct answer: 70.4929 km. Explanation: Let : t1 v1 t2 v2 t3 v3 = 25.2 min , = 65.9 km/h , = 9.92 min , = 91.3 km/h , = 36 min , and = 46.2 km/h . x = x1 + x2 + x3 = v1 t1 + v2 t2 + v3 t3 = (65.9 km/h)(25.2 min) + (91.3 km/h)(9.92 min) + (46.2 km/h)(36 min) = 70.4929 km . mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 Explanation: Let : tother = 19.1 min . The total time is t = t1 + t2 + t3 + tother = 25.2 min + 9.92 min + 36 min + 19.1 min = 1.50367 h , so vav = x 70.4929 km = = 46.8807 km/h . t 1.50367 h 030 10.0 points A race car is one lap behind the lead race car when the lead car has 59 laps to go in a race. If the speed of the lead car is 55.9 m/s, what must be the average speed of the second car to catch the lead car just before the end of the race (i.e., right at the nish line)? Assume 1 lap is 1.34 km. Correct answer: 56.8475 m/s. displacement (m) Correct answer: 46.8807 km/h. Displacement vs Time 10 8 029 (part 2 of 2) 10.0 points Determine the average speed for the trip. 6 4 2 0 2 4 6 8 10 02 46 8 10 12 14 16 18 20 time (s) What is the displacement at 10 s? 1. 2 m 2. 3 m 3. None of these 4. 1 m 5. 1 m 6. 3 m Explanation: 7. 2 m Let : n = 59 laps and v = 55.9 m/s . nx . The lead car nishes the race in t = t In the same amount of time, the trailing car must have an average speed of (n + 1) v (n + 1) x = t n (60 laps) (55.9 m/s) = (59 laps) 8. Unable to determine 9. 0 m 10. 4 m correct Explanation: Read the displacement from the graph. vavg = = 56.8475 m/s . 032 (part 2 of 2) 10.0 points What is the velocity at 10 s? 1. 1 m/s 2. 2 m/s 031 (part 1 of 2) 10.0 points Consider the following graph 3. 3 m/s mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 the magnitude v = |v| of this slope is the speed. The curve is steepest (in absolute magnitude) during the interval III and that is when the object had the highest speed. 4. 1 m/s 5. None of these 6. 3 m/s 034 (part 2 of 2) 10.0 points During which interval(s) did the velocity objects remain constant? 7. 4 m/s 8. 2 m/s 1. During none of the three intervals 9. Unable to determine 2. During interval II only 10. 0 m/s correct 3. During interval III only Explanation: At 10 s, the slope is 0. 4. During each of the three intervals correct 033 (part 1 of 2) 10.0 points Consider a moving object whose position x is plotted as a function of the time t. The object moved in dierent ways during the time intervals denoted I, II and III on the gure. x 4 Explanation: For each of the three intervals I, II or III, the x(t) curve is linear, so its slope (the velocity v) is constant. Between the intervals, the velocity changed in an abrupt manner, but it did remain constant during each interval. 035 (part 1 of 3) 10.0 points Consider the following graph of motion. 2 80 II 2 III 4 t 6 During these three intervals, when was the objects speed highest? Do not confuse the speed with the velocity. 50 r Ca 40 30 10 0 2. Same speed during each of the three intervals. rB a dC 60 20 1. During interval I 3. Same speed during intervals II and III C 70 an rA Ca 0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 Time (hr) How long does it take for the cars to be at the same position? 4. During interval III correct 1. 0.5 hr correct 5. During interval II 2. 0.3 hr Explanation: The velocity v is the slope of the x(t) curve; A Ca rB I Distance (km) 6 5. During interval I only 3. 1.4 hr mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 and car B traveled 4. 0.2 hr (80 km/hr) (0.4 hr) = 32 km , 5. 0.6 hr so after 0.4 hr they are 6. 0.4 hr (20 + 16 32) km = 4 km 7. 1.5 hr apart. 8. 0.1 hr Explanation: After 0.5 hr, both cars are at the same positon. 036 (part 2 of 3) 10.0 points How far apart are they after 0.4 h? 037 (part 3 of 3) 10.0 points Which car maintained a constant speed for the entire trip? 1. Car A correct 2. Both cars 1. 7.3 km 3. Unable to determine 2. 10.5 km 4. Car B 3. 11 km Explanation: Car A has a graph with a constant slope. 4. 3.0 km 5. 4 km correct 6. 1.5 km 038 10.0 points The plot shows x(t) for a train moving along a long, straight track. x 7. 2 km 8. 6.4 km 9. 9 km 10. 5 km Explanation: In 0.5 h, Car A traveled 20 km: vA = 20 km = 40 km/hr 0.5 hr and Car B traveled 40 km: 40 km = 80 km/hr . vB = 0.5 hr In 0.4 hr Car A traveled (40 km/hr) (0.4 hr) = 16 km t Which statement is correct about the motion? 1. The train at rst speeds up, then slows down. 2. The train in fact moves at constant speed along a circular path described by the x(t) curve. mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 3. The train continually slows down and comes to rest. correct v t 3. 4. The train continually speeds up. 5. The train at rst slows down, then speeds up. v t 4. 6. The train moves at constant velocity. correct Explanation: The slope of x(t) continually decreases to dx reach zero. Since vx (t) = is by denition dt the slope of x(t) at each t, the train continually slows down until it stops. 039 (part 1 of 4) 10.0 points v v t 6. The following 4 questions refer to a toy car which can move to the right or left along a horizontal line. The positive direction is to the right. Choose the correct velocity-time graph for each of the following questions. Assume friction is so small that it can be ignored. v t 7. car g t 5. v v t 8. + O Which velocity graph shows the car moving toward the right (away from the origin) at a steady (constant) velocity? v 9. v 1. 2. None of these graphs is correct. t t mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 v v t 10. t 6. Explanation: Since the velocity is constant, the graph is a straight line. Since the car is moving to the right the velocity is positive. v t 7. v t v t 8. 040 (part 2 of 4) 10.0 points Which velocity graph shows the car moving towards the right (away from the origin) reversing direction and then moving to the left? v t 9. v t 1. v t 10. 2. None of these graphs is correct. v t 3. Explanation: Since the car reverses its direction, the velocity is positive and then negative. v t 4. v t v 5. correct t 041 (part 3 of 4) 10.0 points Which velocity graph shows the car moving toward the left (toward the origin) at a steady (constant) velocity? mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 v v t 1. correct v v t 2. t 9. t 10. v t 3. Explanation: Constant velocity is a straight line; toward the left is negative velocity. 042 (part 4 of 4) 10.0 points Which velocity graph shows the car increasing its speed towards the right (away from the origin) at a steady (constant) rate? 4. None of these graphs is correct. v t 5. v t 1. v t 6. v t 2. v t 7. v t 3. v 8. t correct v 4. t mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 9 v 8 t 5. v t 6. velocity (m/s) 7 6 5 4 3 2 1 7. None of these graphs is correct. 0 1 v t 8. 2 1 2 3 4567 time (s) What is the position at 2 seconds? 8 9 Correct answer: 19 m. v t 9. Explanation: The initial position given in the problem is 10 m. 9 v 8 t 10. 7 6 5 Explanation: Since the cars speed is increasing at a constant rate, the slope of the graph is a constant. v velocity (m/s) 4 3 2 1 0 1 t 043 (part 1 of 3) 10.0 points Consider the plot below describing motion along a straight line with an initial position of x0 = 10 m. 1 2 3 456 time (s) 7 8 9 2 The position at 2 seconds is 10 meters plus the area of the triangle (shaded in the above plot) 1 x = 10 m + (2 s 0 s) 2 mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 (9 m/s 0 m/s) = 19 m ; however, it can also be calculated: 1 ( tf ti ) 2 2 = (10 m) + (0 m/s) (2 s 0 s) 1 + (4.5 m/s2 ) (2 s 0 s)2 2 = 19 m . x = xi + vi (tf ti ) + however, it can also be calculated 1 ( tf ti ) 2 2 = 49 m + (0 m/s) (8 s 6 s) 1 + (0.666667 m/s2 ) (8 s 6 s)2 2 = 47.6667 m . x = xi + vi (tf ti ) + 044 (part 2 of 3) 10.0 points What is the position at 6 seconds? 046 10.0 points When Maggie applies the brakes of her car, the car slows uniformly from 14.4 m/s to 0 m/s in 2.13 s. How far ahead of a stop sign must she apply her brakes in order to stop at the sign? Correct answer: 49 m. Correct answer: 15.336 m. Explanation: The position is 19 m plus the area of the trapezoid from 2 s to 6 s Explanation: Let : 1 (6 s 2 s) 2 (6 m/s + 9 m/s) x = 19 m + = 49 m ; however, it can also be calculated: 1 ( tf ti ) 2 2 = (19 m) + (9 m/s) (6 s 2 s) 1 + (0.75 m/s2 ) (6 s 2 s)2 2 = 49 m . x = xi + vi (tf ti ) + 045 (part 3 of 3) 10.0 points What is the position at 8 seconds? Correct answer: 47.6667 m. Explanation: The position is 49 m minus the area of the triangle from 6 s to 8 s 1 (8 s 6 s) 2 (1.33333 m/s 0 m/s) x = (49 m) + = 47.6667 m ; vi = 14.4 m/s , vf = 0 m/s , and t = 2.13 s . The equation simplies to vi + vf 1 t = vi t 2 2 1 = (14.4 m/s) (2.13 s) 2 = 15.336 m . x = 047 (part 1 of 2) 10.0 points A speeder passes a parked police car at a constant speed of 25.2 m/s. At that instant, the police car starts from rest with a uniform acceleration of 2.16 m/s2 . How much time passes before the speeder is overtaken by the police car? Correct answer: 23.3333 s. Explanation: Let : v = 25.2 m/s , a = 2.16 m/s2 , as = 0 , and v0p = 0 . mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 1 x = vi t + a t2 2 Under constant acceleration, 2 2 vf = vi + 2 a x = 0 xs = xp 1 v t = a t2 2 0 = a t2 2 v t 0 = (a t 2 v ) t 2 (25.2 m/s) 2v = = 23.3333 s . t= a 2.16 m/s2 048 (part 2 of 2) 10.0 points How far does the speeder travel before being overtaken by the police car? Correct answer: 588 m. Explanation: The distance may be obtained with either car: d = v t = (25.2 m/s) (23.3333 s) = 588 m or vi 2 2 x (266 km/h)2 1000 m = 2 (1150 m) 1 km a= 1h 3600 s 2 2 = 2.37373 m/s2 . 050 10.0 points An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer rst sees the car, the locomotive is 350 m from the crossing and its speed is 23 m/s. If the engineers reaction time is 0.54 s, what should be the magnitude of the minimum deceleration to avoid an accident? Correct answer: 0.783518 m/s2 . Explanation: 121 2.16 m/s2 (23.3333 s)2 at = 2 2 = 588 m . d= 049 10.0 points The French National Railroad holds the worlds speed record for passenger trains in regular service. A TGV (tres grand vitesse, or very great speed) train traveling at a speed of 266 km/h requires 1.15 km to come to an emergency stop. Find the braking acceleration for this train, assuming constant acceleration. Correct answer: 2.37373 m/s2 . Explanation: Let : d = 350 m , v = vi = 23 m/s , t = 0.54 s . and While the engineer reacts, the train moves d = v t = (23 m/s) (0.54 s) = 12.42 m forward, so it now has to decelerate to rest within a displacement of x = dd = 350 m12.42 m = 337.58 m , 2 2 vf = vi + 2 a x = 0 2 vi (23 m/s)2 = 2 x 2 (337.58 m) = 0.783518 m/s2 , a= Let : vi = 266 km/h , vf = 0 m/s , and x = 1.15 km = 1150 m . which has a magnitude of 0.783518 m/s2 . and mostow (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 Applying kinematics, 051 (part 1 of 2) 10.0 points A plane landing on a small tropical island has just 69 m of runway on which to stop. If its initial speed is 41 m/s, what is the maximum acceleration of the plane during landing, assuming it to be constant? Explanation: 2 v= s = 69 m and v0 = 41 m/s . 2 v0 + 2as = 0 2 v0 (41 m/s)2 a= = 2s 2(69 m) = 12.1812 m/s2 . 052 (part 2 of 2) 10.0 points How long does it take for the plane to stop with this acceleration? Correct answer: 3.36585 s. Explanation: v = v0 + a t = 0 41 m/s v0 = t= a 12.1812 m/s2 = 3.36585 s . 053 10.0 points A car traveling initially at 9.9 m/s accelerates at the rate of 0.675 m/s2 for 2.79 s. What is its velocity at the end of the acceleration? Correct answer: 11.7832 m/s. Explanation: Let : v0 = 9.9 m/s , a = 0.675 m/s2 , t = 2.79 s . = 9.9 m/s + (0.675 m/s2 )(2.79 s) = 11.7832 m/s . 054 (part 1 of 2) 10.0 points An electron has an initial speed of 1.97 105 m/s. If it undergoes an acceleration of 2.9 1014 m/s2 , how long will it take to reach a speed of 6.8 105 m/s? Correct answer: 12.1812 m/s2 . Let : vf = v0 + at and Correct answer: 1.66552 109 s. Explanation: Let : v0 = 1.97 105 m/s , a = 2.9 1014 m/s2 , v = 6.8 105 m/s . and v = v0 + a t v v0 t= a 6.8 105 m/s 1.97 105 m/s = 2.9 1014 m/s2 = 1.66552 109 s . 055 (part 2 of 2) 10.0 points How far has it traveled in this time? Correct answer: 0.000730329 m. Explanation: 12 at 2 = (1.97 105 m/s) (1.66552 109 s) 1 + (2.9 1014 m/s2 ) 2 (1.66552 109 s)2 x = x0 + v0 t + = 0.000730329 m .

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What is macroeconomics? What role does macroeconomics play in your personal financialdecisions and the decisions that your organization makes? What are the resources that areavailable to you in your efforts to understand current macroeconomic conditions
University of Phoenix - CRT - 205
Appendix BPSY/210 Version 41Associate Level Material-Shannon GreenwoodAppendix BComplete the following chart. The first column shows the name of a researchmethod used in psychology. In the second column, write a brief description of thatresearch me
University of Phoenix - CRT - 205
Associate Level MaterialAppendix DContingency Theory of LeadershipDescription of workenvironmentI will use my current work environment. I work for a smallfamily owned produce broker and shipper. I do allbookkeeping and other office duties such as f
University of Phoenix - CRT - 205
Associate Level MaterialAppendix BRoles and BehaviorsDescription of CompanyMy fictional company is a daycare. It is a small daycare thattakes care of children ages 6 weeks to 4 years. It has 5different classrooms. The infant room has 2 employees tha
University of Phoenix - CRT - 205
Running head: ARGUMENT EVALUATION1ARGUMENT EVALUATIONShannon GreenwoodGEN 205January 15, 2015Shannon ShawARGUMENT EVALUATION2ARGUMENT EVALUATIONThe first argument that I found in the article was that terrorists were extraordinarilysuccessful in
University of Phoenix - CRT - 205
Running head: CAPSTONE CHECKPOINT1Capstone CheckPointShannon GreenwoodCRT/205January 26, 2012Shannon ShawCAPSTONE CHECKPOINT2Capstone CheckPointIn the future I think that thinking critically will influence the way that I read because Inow have
University of Phoenix - CRT - 205
Shannon GreenwoodATTACHMENT 5.2 - MATRIX: CATEGORIZING FALLACIESFallacy Types:Ad HominemArgument from PopularityArgument from OutragePost HocGroup ThinkFallacy StatementIt's disgraceful that a member of the Elks Lodge would goout to fast food re
University of Phoenix - CRT - 205
Author Name: MooreSite Name: Critical ThinkingChapter: Chapter 7Quiz: Argument Quiz IStudent Name: ShannonStudent eMail Address: jbo@ordille.comSection ID:Results ReporterOut of 3 questions, you answered 3 correctly with a final grade of 100%3 co
University of Phoenix - CRT - 205
Author Name: MooreSite Name: Critical ThinkingChapter: Chapter 12Quiz: Moral Reasoning Quiz IStudent Name: ShannonStudent eMail Address: jbo@ordille.comSection ID:Results ReporterOut of 9 questions, you answered 9 correctly with a final grade of 1
University of Phoenix - CRT - 205
Exercise 7-9Given the premises, discuss whether the conclusion of each argument that follows is (a) truebeyond a reasonable doubt, (b) probably true, or (c) possibly true or possibly false. You shouldexpect disagreement on these items, but the closer y
University of Phoenix - CRT - 205
Associate Level MaterialAppendix ECritical Analysis FormsFill out one form for each source.Source 1 Title and Citation:1Identify the principal issuepresented by the source.2Identify any examples ofbias presented by theauthor. If none exist, exp
University of Phoenix - CRT - 205
Shannon GreenwoodExercise 6-6Identifying Fallacies2. Letter to the editor: Andrea Keenes selective morality is once again showingthrough in her July 15 letter. This time she expresses her abhorrence of abortion. Buthow we see only what we choose to s
University of Phoenix - CRT - 205
Running head: TAKING A POSITION1Taking a PositionShannon GreenwoodCRT/205November 17, 2011Shannon ShawTAKING A POSITION2Taking a PositionThe key issue from the comic strip is whether or not Anita should ignore what her coworker is doing and get
University of Phoenix - CRT - 205
Jamie GreenwoodFebruary 4, 2011Appendix C:Leaders and Legislation of the Civil Rights and Black Power MovementsIdentify leaders of the Civil Rights and Black Power movements and their contributions to theirrespective causes. How did these social pion
University of Phoenix - CRT - 205
Axia College MaterialAppendix DUnited States-Centric Views ComparisonConsider this question: What are an average Americans perceptions about Muslim/ArabAmerican and Christian American groups?Copy each descriptor from the paragraph below and paste it
University of Phoenix - BUS - 210
Associate Level Material-Shannon GreenwoodAppendix EHardware/Software ComponentsIn your own words, describe the following hardware/software componentsLegacy systemsA legacy system is the actual computers and the computerprograms that a company choos
University of Phoenix - BUS - 210
Running head: BUSINESS ORGANIZATION1Business OrganizationShannon GreenwoodBUS 210November 24, 2011Eva Cruz MorelBUSINESS ORGANIZATION2Business OrganizationA joint-stock company is a company which has the capital of its members pooled into acomm
University of Phoenix - BUS - 210
Running head: CODE OF ETHICS1Code of EthicsShannon GreenwoodBUS 210December 2, 2011Eva Cruz MorelCODE OF ETHICS2Code of EthicsI believe that a businesss code of ethics depends on the nature of this business so forpurposes of this assignment I a
University of Phoenix - BUS - 210
Associate Level MaterialAppendix CThe Four Functions of ManagementDescription of EventWell being a single mother I have been in charge ofmanaging every party she has had so far(Not many beingthat she is only two!) I will choose to discuss her 2nd bi
University of Phoenix - BUS - 210
IT Applications PresentationShannon GreenwoodBUS 210January 18, 2012Eva Cruz MorelTransaction ProcessingSystems The backbone of a companys informationtechnology (IT) department. Keeps track of day-to-day operations. Managers use the information
University of Phoenix - BUS - 210
Building Blocks Daycare is committed to providing safe, affordable, highquality child care for people of the community. We provide a cognitively basedprogram for children ages six weeks to 4 years. We provide a home likeenvironment where children are e
University of Phoenix - BUS - 210
Running head: JOB FAIR BROCHURE1Job Fair BrochureShannon GreenwoodBUS 210January 8, 2012Eva Cruz MorelJOB FAIR BROCHURE2Job Fair BrochureThe hypothetical company that I have created is called Building Blocks Daycare. On thebrochure that is loca
University of Phoenix - BUS - 210
Running head: SWOT ANALYSIS1SWOT AnalysisShannon GreenwoodBUS 210December 11, 2011Eva Cruz MorelSWOT ANALYSIS2SWOT AnalysisThe company model that I chose to perform a SWOT analysis on is called Jollys Javaand Bakery (JJB). It is a start-up coff
University of Phoenix - ETH - 125
Shannon GreenwoodNovember 4, 2011Axia College MaterialAppendix EStatistic 1Statistic 2Statistic 3CulturalMakeup5.1 million Asianpopulation inCalifornia.3.62 million of Asianpopulation are ofChinese descent.Income11.8% poverty rate forsing
University of Phoenix - ETH - 125
Axia College MaterialAppendix FTime Management LogName: _Shannon Greenwood_ Day: _Wednesday_Date: _October 19, 2011_TimeActivities6:00 a.m.Sleep6:30 a.m.Wake Up7:00 a.m.Personal Care7:30 a.m.Personal Care8:00 a.m.Personal Care8:30 a.m.Wa
University of Phoenix - ETH - 125
Axia College MaterialAppendix GSQ3R WorksheetSelected Reading: Pages 175-182SurveySkimmed over the document reading anythingthat was bolded in blue to get an idea of whatthe reading was going to be about.Question How would I evaluate an argument?
University of Phoenix - ETH - 125
Running head: CHARACTERISTICS OF ORIENTALISM, PREJUDICE, AND1Characteristics of Orientalism, Prejudice, and DiscriminationShannon GreenwoodETH 125October 13, 2011Mercedes Doris RuizCHARACTERISTICS OF ORIENTALISM, PREJUDICE, AND2Muslim and Arabs a
University of Phoenix - ETH - 125
Running head: DEFINING RACE AND ETHNICITY1Defining Race and EthnicityShannon GreenwoodETH/125September 13, 2011Mercedes Doris RuizDEFINING RACE AND ETHNICITY2Defining Race and EthnicityTo me race is something that you cant help. It is simply the
University of Phoenix - ETH - 125
Running head: CHECKPOINT IMPLICIT ASSOCIATION TEST1CheckPoint Implicit Association TestShannon GreenwoodETH/125September 23, 2011Mercedes Doris RuizCHECKPOINT IMPLICIT ASSOCIATION TEST2CheckPoint Implicit Association TestWhen I was prompted to s
University of Phoenix - ETH - 125
Running head: LEGISLATION LEGACY1Legislation LegacyShannon GreenwoodETH 125October 21, 2011Mercedes Doris RuizLEGISLATION LEGACY2Legislation LegacyThe current issue between Native Americans and the federal government that I chose todiscuss is d
University of Phoenix - ETH - 125
Muslims hail from many parts of the world whereas Arabs are necessarily from the Middle East regionssuch as Iran, Iraq, Saudi Arabia and Syria. Since the Muslims come from different parts of the world theyare in large numbers in terms of population. Com
University of Phoenix - ETH - 125
Running head: UNITED STATES CENTRIC VIEWS COMPARISON1United States Centric Views ComparisonShannon GreenwoodETH 125October 16, 2011Mercedes Doris RuizUNITED STATES CENTRIC VIEWS COMPARISON2United States Centric Views ComparisonI completed the ta
University of Phoenix - GEN - 105
Running head: READING AND COMPREHENSION1Reading and ComprehensionShannon GreenwoodGEN 105October 26, 2011Carol JacksonREADING AND COMPREHENSION2Reading and ComprehensionSummaryFind something interesting that will captivate your audience. Look f
University of Phoenix - GEN - 105
Running head: SETTING GOALS1Setting GoalsShannon GreenwoodGEN 105October 14, 2011Carol JacksonSETTING GOALS2Setting GoalsLong-Term Goal #1Graduate College With A Bachelors DegreeI think this goal will be somewhat difficult. It will require har
University of Phoenix - GEN - 105
Running head: USING THE PROPER TONE1Using the Proper ToneShannon GreenwoodGEN 105September 23, 2011Carol JacksonUSING THE PROPER TONE2Using the Proper ToneTone is very important part of written communication. It will provide your audience witha
University of Phoenix - GEN - 105
Shannon Greenwood
University of Phoenix - GEN - 105
o List the steps you would take to access OLSGo to the student website and log in. Select your class. From there you can go into discussions,view class materials, submit assignments and check your grades.o How do you access the Main forum?Once you are
University of Phoenix - GEN - 105
Goal Action Plan TemplateSelect a goal, and use this template to create an action plan for that goal. Then,post the action plan to the Week 2 Assignment 1 link on your student website athttps:/ecampus.phoenix.edu.Goal Action PlanYour goal action plan
University of Phoenix - GEN - 105
Time Log TemplateMake a list of all activities you accomplish in one day. Be as specific as possible,and include a scheduled time for study. This log may be used in future courses toschedule time for study and course work.Time6:00 a.m.6:30 a.m.7:00
University of Phoenix - XECO - 212
Running head: CHECKPOINT A NEW HOUSE-READINESS1CheckPoint A New House-ReadinessShannon GreenwoodXECO 212February 3, 2012Phillip PostCHECKPOINT A NEW HOUSE-READINESS2CheckPoint A New House-ReadinessI am currently renting a studio apartment with m
University of Phoenix - XECO - 212
Running head: HISTORICAL EXAMPLE OF LABOR SUPPLY AND DEMAND1Historical Example of Labor Supply and DemandShannon GreenwoodXECO/212February 17, 2012Phillip PostHISTORICAL EXAMPLE OF LABOR SUPPLY AND DEMAND2Historical Example of Labor Supply and De
University of Toronto - RSM - 333
Introduction to Corporate Finance, Second EditionBooth, ClearyChapter 12: Options Multiple Choice Questions 1. Section: 12.1 Call Options Learning Objective: 12.1 Level of Difficulty: Easy Solution: B A call option is in the money if the asset price is
University of Toronto - RSM - 333
Introduction to Corporate Finance, Second EditionBooth, ClearyChapter 20: Cost of Capital Multiple Choice Questions 1. Section: 20.1 Financing Sources Learning Objective: 20.1 Level of difficulty: Medium Solution: D Invested capital = all interest-beari
University of Toronto - RSM - 333
Introduction to Corporate Finance, Second EditionBooth, ClearyChapter 21: Capital Structure Decisions Multiple Choice Questions 1. Section: 21.2 Determining Capital Structure Learning Objective: 21.2 Level of difficulty: Medium Solution: D Recall WACC =
University of Toronto - RSM - 333
Introduction to Corporate Finance, Second EditionBooth, ClearyChapter 11: Forward, Futures, and SwapsMultiple Choice Questions1. Section: 11.1 Forward ContractsLevel of difficulty: MediumSolution: BIf a Canadian firm has to pay US dollars in the fu
University of Toronto - RSM - 333
Introduction to Corporate Finance, Second EditionBooth, ClearyChapter 15: Mergers and AcquisitionsMultiple Choice Questions1. Section: 15.1 Types of TakeoversLearning Objective: 15.1Level of difficulty: MediumSolution: BIn mergers, the approval of
University of Toronto - RSM - 333
Introduction to Corporate Finance, Second EditionBooth, ClearyChapter 22: Dividend PolicyMultiple Choice Questions1. Section: 22.3 Modigliani and Millers Dividend Irrelevance TheoremLearning objective: 22.3Level of difficulty: EasySolution: B2. Se
University of Toronto - ECO - eco364
University of Toronto - ECO - eco364
ECO 364 - Topic 4The Heckscher-Ohlin ModelKunal DasguptaDasgupta (UofT)HO model1 / 36Road map1Motivation2The Model3Trade and factor prices4EvidenceDasgupta (UofT)HO model2 / 36MotivationThe Ricardian model emphasized dierences in techno
University of Toronto - ECO - eco364
ECO 364 - Topic 2The Ricardian ModelKunal DasguptaDasgupta (UofT)Ricardian model1 / 30Road map1Historical context2Autarky3Trade equilibrium4EvidenceDasgupta (UofT)Ricardian model2 / 30Historical contextEconomic backdropDuring the late
University of Toronto - ECO - eco364
University of Toronto - ECO - 365
UNIVERSITY OF TORONTOFaculty of Arts and ScienceMID-TERM (WINTER 2011)ECO365H1 (L0101)Instructor - Prof. Kunal DasguptaDuration - 1.5 hoursExamination Aids - Only calculatorsTotal points : 100Read every question carefully. Answers should be to the
University of Toronto - ECO - 365
UNIVERSITY OF TORONTOFaculty of Arts and ScienceMID-TERM (WINTER 2011)ECO365H1 (L0101)Instructor - Prof. Kunal DasguptaDuration - 1.5 hoursExamination Aids - Only calculatorsTotal points : 100Read every question carefully. Answers should be to the
University of Toronto - ECO - 365
UNIVERSITY OF TORONTOFaculty of Arts and ScienceMID-TERM (WINTER 2011)ECO365H1 (L0201)Instructor - Prof. Kunal DasguptaDuration - 1.5 hoursExamination Aids - Only calculatorsTotal points : 100Read every question carefully. Answers should be to the