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6 Pages

Elementary Principles 100

Course: CHEMICAL E 312, Fall 2011
School: The University of Akron
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Word Count: 197

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(cont'd) Air 4.67 feed rate: n f = b. 207.0 kmol O 2 h 1 kmol air 0.21 kmol O 2 1.17 kmol air fed = 1153 kmol air h kmol air req. na = n f 2 x1 + 35x 2 + 5x 3 + 6.5x 4 1 + Pxs 100 1 0.21 . b gb gb g c. n f = aR f , (n f = 75.0 kmol / h, R f = 60) n f = 125R f . na = bRa , (na = 550 kmol / h, Ra = 25) na = 22.0 Ra xi = kAi x i i =k Ai A i i =1 k = A i 1 i xi = A i , i = CH 4 , C 2 H 4 ,...

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(cont'd) Air 4.67 feed rate: n f = b. 207.0 kmol O 2 h 1 kmol air 0.21 kmol O 2 1.17 kmol air fed = 1153 kmol air h kmol air req. na = n f 2 x1 + 35x 2 + 5x 3 + 6.5x 4 1 + Pxs 100 1 0.21 . b gb gb g c. n f = aR f , (n f = 75.0 kmol / h, R f = 60) n f = 125R f . na = bRa , (na = 550 kmol / h, Ra = 25) na = 22.0 Ra xi = kAi x i i =k Ai A i i =1 k = A i 1 i xi = A i , i = CH 4 , C 2 H 4 , C 3 H 8 , C 4 H 10 i Run 1 2 3 Run 1 2 3 Pxs 15% 15% 15% nf 77.5 103.8 135.0 Rf 62 83 108 x1 0.900 0.945 0.926 A1 248.7 305.3 294.2 x2 0.0715 0.0451 0.0523 A2 19.74 14.57 16.61 x3 0.0230 0.0079 0.0150 A3 2.56 6.35 4.78 x4 0.0054 0.0022 0.0066 A4 1.48 0.70 2.11 na 934 1194 1592 Ra 42.4 54.3 72.4 d. Either of the flowmeters could be in error, the fuel gas analyzer could be in error, the flowmeter calibration formulas might not be linear, or the stack gas analysis could be incorrect. C4H10 + 13/2 O2 4 CO2 + 5 H2O Basis: 100 mol C4H10 nCO2 (mol CO2) nH2O (mol H2O) nC4H10 (mol C4H10) nO2 (mol O2) nN2 (mol N2) 4.68 a. Pxs (% excess air) nair (mol air) 0.21 O2 0.79 N2 D.F. analysis 6 unknowns (n, n1, n2, n3, n4, n5) -3 atomic balances (C, H, O) -1 N2 balance -1 % excess air -1 % conversion 0 D.F. 4-59
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The University of Akron - CHEMICAL E - 312
4.66CO +1 O 2 CO 2 2H2 +1 O2 H 2O 2175 kmol/h 0.500 kmol N2/kmol x (kmol CO/mol) (0.500x) (kmol H2/kmol) 20% excess airNote: Since CO and H 2 each require 0 .5 mol O 2 / mol fuel for complete combustion, we can calculate the air feed rate without de
The University of Akron - CHEMICAL E - 312
4.64a.Basis: 1000 g gas Species C3H8 C4H10 H2O Total m (g) 800 150 50 1000 MW 44.09 58.12 18.02 n (mol) 18.145 2.581 2.775 23.501mole % (wet) 77.2% 11.0% 11.8% 100% 100% mole % (dry) 87.5% 12.5%Total moles = 23.50 mol, Total moles (dry) = 20.74 mol Ra
The University of Akron - CHEMICAL E - 312
4.63a.A balance on ith tank (input = output + consumption) v L min C A, i -1 mol L = vC Ai + kC Ai C Bi mol liter min V LbgbgE v, note V / v = bgbgC A , i -1 = C Ai + k C Ai C Bi B balance. By analogy, C B , i -1 = C Bi + k C Ai C Bi Subtract eq
The University of Akron - CHEMICAL E - 312
4.62 (cont'd)i - C 4 H 10 balance around second mixing point 867.5 + n6 = 34,700 n6 = 33,800 kmol C 4 H 10 in recycle E Recycle E: Since Streams (D) and (E) have the same composition, n5 moles n - C 4 H 10 n2 n7 n14b g = n bmoles i - C H g n bmoles n -
The University of Akron - CHEMICAL E - 312
4.62a.i - C 4 H 10 + C 4 H 8 = C 8 H 18Basis: 1-hour operationDn 2 (n-C 4 H10 ) n 3 (i-C 4 H 10) n 1 (C 8 H18 ) m4 (91% H 2 SO4 ) EP F decanter n 1 (C 8 H18 ) n 2 (n-C 4 H10 ) n 3 (i-C 4 H 10)n 1 (C 8 H18 ) n 2 (n-C 4 H10 ) stillUnits of n: kmol U
The University of Akron - CHEMICAL E - 312
4.61 (cont'd) At mixing point:N2: (1-XI0)/4 + (1-yp)(1-fsp) n1 = n1 I: XI0 + (1-yp) n2 = n2 Total moles fed to reactor: nr = 4n1 + n2 Moles of NH3 produced: np = 2fspn1 Overall N2 conversion: (1 - X I0 ) / 4 - y p (1 - f sp )n 1 (1 - X I0 ) / 4 100%b.X
The University of Akron - CHEMICAL E - 312
4.60a.Basis: 100 mol feed/h. Put dots above all n's in flow chart.100 mol/h 32 mol CO/h 64 mol H 2 / h 4 mol N 2 / h n1 (mol /h) .13 mol N 2 /mol reactor cond. n3 (mol CH 3 OH / h) n2 (mol CH3OH/h)500 mol / h x1 (mol N 2 /mol) x2 (mol CO / mol) 1-x1-x
The University of Akron - CHEMICAL E - 312
4.59a.Basis: 100 mol fed to reactor/h 25 mol O2/h, 75 mol C2H4/hn1 (mol C 2H 4 /h) n2 (mol O 2 /h) n3 (mol C 2H 4O /h)reactor nC2H4 ( mol C 2H 4 /h) nO2 (mol O 2 /h) 75 mol C 2H 4 /h 25 mol O 2 /h n1 (mol C 2H 4 /h) n2 (mol O 2 /h) n3 (mol C 2H 4O /h)
The University of Akron - CHEMICAL E - 312
4.58a.Basis: 100 kmol reactor feed/hrn3 (kmol CH 4 /h) 100 kmol /h Reactor n1 (kmol CH 4 /h) 80 kmol CH4 /h n2 (kmol Cl 2 /h) 20 kmol Cl2 /h n3 (kmol CH 4 /h) n4 (kmol HCl /h) 5n5 (kmol CH 3Cl /h) n5 (kmol CH 2Cl 2 /h) Cond. n3 (kmol CH 4 /h) n4 (kmol
The University of Akron - CHEMICAL E - 312
4.57 (cont'd)n4 (mol/min)0.004 mol CH3OH(v)/mol x (mol CO/mol) (0.896 - x ) (mol H 2 / mol)350 mol/ minReactorn1 (mol CO/min) n2 (mol H2 / min)Cond.n3 (mol CH 3OH(l)/min)0.631 mol CH 3OH(v)/ mol0.274 mol CO/ mol CO + H 2 CH 3OH 0.0953 mol H / mol
The University of Akron - CHEMICAL E - 312
4.57 (cont'd)n4 (mol/min)0.004 mol CH3OH(v)/mol x (mol CO/mol) (0.896 - x ) (mol H 2 / mol)350 mol/ minReactorn1 (mol CO/min) n2 (mol H2 / min)Cond.n3 (mol CH 3OH(l)/min)0.631 mol CH 3OH(v)/ mol0.274 mol CO/ mol CO + H 2 CH 3OH 0.0953 mol H / mol
The University of Akron - CHEMICAL E - 312
4.56a.900 kg HCHO 1 kmol HCHO = 30.0 kmol HCHO / h h 30.03 kg HCHOn (kmol CH OH / h) 1 330.0 kmol HCHO / h n2 (kmol H 2 / h) n3 (kmol CH 3OH / h)% conversion:b.30.0 = 0.60 n1 = 50.0 kmol CH 3 OH / h n1n (kmol CH OH / h) 1 330.0 kmol HCHO / h n2 (
The University of Akron - CHEMICAL E - 312
4.56a.900 kg HCHO 1 kmol HCHO = 30.0 kmol HCHO / h h 30.03 kg HCHOn (kmol CH OH / h) 1 330.0 kmol HCHO / h n2 (kmol H 2 / h) n3 (kmol CH 3OH / h)% conversion:b.30.0 = 0.60 n1 = 50.0 kmol CH 3 OH / h n1n (kmol CH OH / h) 1 330.0 kmol HCHO / h n2 (
The University of Akron - CHEMICAL E - 312
4.55 (cont'd) c.mP 4850 4850 4850 4850 4850 4850 4850 4850 4850 mP 2450 2450 2450 2450 2450 2450 2450 2450 2450xRA 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10 xRA 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10mA0 3327 3022 2870 2778 2717 2674 2641 2616
The University of Akron - CHEMICAL E - 312
4.55 (cont'd) c.mP 4850 4850 4850 4850 4850 4850 4850 4850 4850 mP 2450 2450 2450 2450 2450 2450 2450 2450 2450xRA 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10 xRA 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10mA0 3327 3022 2870 2778 2717 2674 2641 2616
The University of Akron - CHEMICAL E - 312
4.54 (cont'd)ITER = 4 X1A, X2A = 0.05437 ITER = 5 X1A, X2A = 0.05931 ITER = 6 X1A, X2A = 0.059300.02213 0.02086 0.02083YA, YB, YC, YD, YE =2.0270E - 01 2.9501E - 010.20 0.20X1C, X2C = 0.05931 X1C, X2C = 0.05930 X1C, X2C = 0.059301.1197 E - 01 3.931
The University of Akron - CHEMICAL E - 312
4.54 (cont'd)ITER = 4 X1A, X2A = 0.05437 ITER = 5 X1A, X2A = 0.05931 ITER = 6 X1A, X2A = 0.059300.02213 0.02086 0.02083YA, YB, YC, YD, YE =2.0270E - 01 2.9501E - 010.20 0.20X1C, X2C = 0.05931 X1C, X2C = 0.05930 X1C, X2C = 0.059301.1197 E - 01 3.931
The University of Akron - CHEMICAL E - 312
4.54 (cont'd)2 FORMAT('0', 15X, 'NA0, NB0, NC0, ND0, NE0 *', 5F6.2/) NTO = NA0 + NB0 + NC0 + ND0 + NE0 NMAX = 10 X1 = 0.1 X2 = 0.1 DO 100 J = 1, NMAX NA = NA0 X1 X1 NB = NB0 + X1 + X1 NC = NC0 + X1 X2 ND = ND0 X2 NE = NE0 + X2 + X2 NAS = NA * 2 NBS = NB
The University of Akron - CHEMICAL E - 312
4.54 (cont'd)2 FORMAT('0', 15X, 'NA0, NB0, NC0, ND0, NE0 *', 5F6.2/) NTO = NA0 + NB0 + NC0 + ND0 + NE0 NMAX = 10 X1 = 0.1 X2 = 0.1 DO 100 J = 1, NMAX NA = NA0 X1 X1 NB = NB0 + X1 + X1 NC = NC0 + X1 X2 ND = ND0 X2 NE = NE0 + X2 + X2 NAS = NA * 2 NBS = NB
The University of Akron - CHEMICAL E - 312
4.54a.2CO 2 2CO + O 2 O 2 + N 2 2NO2A 2B + C C + D 2En A = n A 0 - 2 e1 nB nC nD nEyA = = n B 0 + 2 e 2 yB = = nC 0 + e1 - e 2 y C = = n D0 - e2 yD = = n E 0 + 2 e 2 yE =bn bn bn bn bnA0 B0- 2 e1 + 2 e1C0D0E0+ e1 - e 2 nT 0 + e1 - 1 e 2 nT 0 +
The University of Akron - CHEMICAL E - 312
4.54a.2CO 2 2CO + O 2 O 2 + N 2 2NO2A 2B + C C + D 2En A = n A 0 - 2 e1 nB nC nD nEyA = = n B 0 + 2 e 2 yB = = nC 0 + e1 - e 2 y C = = n D0 - e2 yD = = n E 0 + 2 e 2 yE =bn bn bn bn bnA0 B0- 2 e1 + 2 e1C0D0E0+ e1 - e 2 nT 0 + e1 - 1 e 2 nT 0 +
The University of Akron - CHEMICAL E - 312
4.53a.C 6 H 6 + Cl 2 C 6 H 5 Cl + HCl C 6 H 5 Cl + Cl 2 C 6 H 4 Cl 2 + HCl C 6 H 4 Cl 2 + Cl 2 C 6 H 3 Cl 3 + HCl Convert output wt% to mol%: Basis 100 g output species C6 H 6 C 6 H 5 Cl C 6 H 4 Cl 2 C 6 H 3 Cl 3 g 65.0 32.0 2.5 0.5 Mol. Wt. 78.11 112.5
The University of Akron - CHEMICAL E - 312
4.53a.C 6 H 6 + Cl 2 C 6 H 5 Cl + HCl C 6 H 5 Cl + Cl 2 C 6 H 4 Cl 2 + HCl C 6 H 4 Cl 2 + Cl 2 C 6 H 3 Cl 3 + HCl Convert output wt% to mol%: Basis 100 g output species C6 H 6 C 6 H 5 Cl C 6 H 4 Cl 2 C 6 H 3 Cl 3 g 65.0 32.0 2.5 0.5 Mol. Wt. 78.11 112.5
The University of Akron - CHEMICAL E - 312
4.51 (cont'd) b. (1) n1 = 46.08 mol C 2 H 6(3) n2 = 47.4 mol H 2 O (4) n3 = 9.3 mol I % conversion of C2H4:U | Reactor feed contains 44.8% C H , 46.1% H O, 9.1% I V | W2 6 246.08 - 43.3 100% = 6.0% 46.08If all C2H4 were converted and the second react
The University of Akron - CHEMICAL E - 312
4.51 (cont'd) b. (1) n1 = 46.08 mol C 2 H 6(3) n2 = 47.4 mol H 2 O (4) n3 = 9.3 mol I % conversion of C2H4:U | Reactor feed contains 44.8% C H , 46.1% H O, 9.1% I V | W2 6 246.08 - 43.3 100% = 6.0% 46.08If all C2H4 were converted and the second react
The University of Akron - CHEMICAL E - 312
4.50a.Design for low conversion and feed ethane in excess. Low conversion and excess ethane make the second reaction unlikely. C2H6 + Cl2 C2H5Cl + HCl, C2H5Cl + Cl2 C2H4Cl2 + HCl Basis: 100 mol C2H5Cl producedn1 (mol C2H6) n2 (mol Cl2) 100 mol C2H5Cl n
The University of Akron - CHEMICAL E - 312
4.50a.Design for low conversion and feed ethane in excess. Low conversion and excess ethane make the second reaction unlikely. C2H6 + Cl2 C2H5Cl + HCl, C2H5Cl + Cl2 C2H4Cl2 + HCl Basis: 100 mol C2H5Cl producedn1 (mol C2H6) n2 (mol Cl2) 100 mol C2H5Cl n
The University of Akron - CHEMICAL E - 312
4.48 (cont'd)CON = EKPI/YA0 WRITE (6, 3) YA, YB, YC, CON STOP WRITE (6, 5) INMAX, EKPI FORMAT (' YA YB YC CON', 1, 4(F6.3, 1X) FORMAT ('DID NOT CONVERGE IN', I3, 'ITERATIONS',/, * 'CURRENT VALUE = ', F6.3) END $ DATA 0.5 0.5 0.0 423. 2. RESULTS: YA = 0.5
The University of Akron - CHEMICAL E - 312
4.48 (cont'd)CON = EKPI/YA0 WRITE (6, 3) YA, YB, YC, CON STOP WRITE (6, 5) INMAX, EKPI FORMAT (' YA YB YC CON', 1, 4(F6.3, 1X) FORMAT ('DID NOT CONVERGE IN', I3, 'ITERATIONS',/, * 'CURRENT VALUE = ', F6.3) END $ DATA 0.5 0.5 0.0 423. 2. RESULTS: YA = 0.5
The University of Akron - CHEMICAL E - 312
4.48 (cont'd)(For this particular set of initial conditions, we get a quadratic equation. In general, the equation will be cubic.). b g c2 - 2b0156gh y = 0.500 y = c1 - 2b0156gh c2 - 2b0156gh y = 0.408 . . y = b0 + 0156g c2 - 2b0156gh y = 0.092 . . n -n
The University of Akron - CHEMICAL E - 312
4.48 (cont'd)(For this particular set of initial conditions, we get a quadratic equation. In general, the equation will be cubic.). b g c2 - 2b0156gh y = 0.500 y = c1 - 2b0156gh c2 - 2b0156gh y = 0.408 . . y = b0 + 0156g c2 - 2b0156gh y = 0.092 . . n -n
The University of Akron - CHEMICAL E - 312
4.47(cont'd) d.T (K) 1223 1123 1023 923 823 723 623 673 698 688 1123 1123 1123 1123 x (CO) 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.2 0.4 0.3 0.5 x (H2O) 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.4 0.2 0.3 0.4 x (CO2) 0 0 0 0 0 0 0 0 0 0 0.1 0.1 0 0 Ke
The University of Akron - CHEMICAL E - 312
4.47(cont'd) d.T (K) 1223 1123 1023 923 823 723 623 673 698 688 1123 1123 1123 1123 x (CO) 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.2 0.4 0.3 0.5 x (H2O) 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.4 0.2 0.3 0.4 x (CO2) 0 0 0 0 0 0 0 0 0 0 0.1 0.1 0 0 Ke
The University of Akron - CHEMICAL E - 312
4.46 (cont'd) Product gas n A = 170.6 - 70 = 100.6 molnB = 10 mol nC = 70 mol nD = 70 mol ntotal = 250.6 mold.U y | y | V y | y | WA B C D= 0.401 mol CH3OH mol = 0.040 mol CH3COOH mol = 0.279 mol CH3COOCH 3 mol = 0.279 mol H 2O molCost of reactants,
The University of Akron - CHEMICAL E - 312
4.46 (cont'd) Product gas n A = 170.6 - 70 = 100.6 molnB = 10 mol nC = 70 mol nD = 70 mol ntotal = 250.6 mold.U y | y | V y | y | WA B C D= 0.401 mol CH3OH mol = 0.040 mol CH3COOH mol = 0.279 mol CH3COOCH 3 mol = 0.279 mol H 2O molCost of reactants,
The University of Akron - CHEMICAL E - 312
4.46a.A + B = C + D nA = nA - 0nB = nB - 0 0y A = n A - nT0nC = n C + nD = nD + 0yB yC yDnI = nI Total nT = niAt equilibrium:0e = en = en = enB0C0 + D0j - j n j n + j nTT TnC0 + c nD0 + c yC y D = = 4.87 ( nT 's cancel) y A yB n A0 - c
The University of Akron - CHEMICAL E - 312
4.46a.A + B = C + D nA = nA - 0nB = nB - 0 0y A = n A - nT0nC = n C + nD = nD + 0yB yC yDnI = nI Total nT = niAt equilibrium:0e = en = en = enB0C0 + D0j - j n j n + j nTT TnC0 + c nD0 + c yC y D = = 4.87 ( nT 's cancel) y A yB n A0 - c
The University of Akron - CHEMICAL E - 312
4.45a.Plot C (log scale) vs. R (linear scale) on semilog paper, get straight line throughd R = 10, C11= 0.30 g m 3 andiFH R2= 48, C2 = 2.67 g m 3IKln C = bR + ln a C = ae br b= ln 2.67 0.30b48 - 10 C = 0169e 0.0575 R .g = 0.0575 , ln a = ln
The University of Akron - CHEMICAL E - 312
4.45a.Plot C (log scale) vs. R (linear scale) on semilog paper, get straight line throughd R = 10, C11= 0.30 g m 3 andiFH R2= 48, C2 = 2.67 g m 3IKln C = bR + ln a C = ae br b= ln 2.67 0.30b48 - 10 C = 0169e 0.0575 R .g = 0.0575 , ln a = ln
The University of Akron - CHEMICAL E - 312
4.43 (cont'd)O 2 : n3 = 0.21 160.7 - N 2 : n41 b g 2 = 12.5 mol O = 0.79b160.7g = 127 mol N22Cl 2 : n5 = = 42.5 mol Cl 2 H 2 O: n6 = = 42.5 mol H 2 O These molar quantities are the same as in part (a), so the mole fractions would also be the same. Us
The University of Akron - CHEMICAL E - 312
4.43 (cont'd)O 2 : n3 = 0.21 160.7 - N 2 : n41 b g 2 = 12.5 mol O = 0.79b160.7g = 127 mol N22Cl 2 : n5 = = 42.5 mol Cl 2 H 2 O: n6 = = 42.5 mol H 2 O These molar quantities are the same as in part (a), so the mole fractions would also be the same. Us
The University of Akron - CHEMICAL E - 312
4.43a.2HCl +1 O 2 Cl 2 + H 2 O 2Basis: 100 mol HCl fed to reactor100 mol HCln1 mol airbg0.21 mol O 2 / mol 0.79 mol N 2 / mol 35% excess2b g n b mol O g n b mol N g n b mol Cl g n b mol H Ogn2 mol HCl3 2 4 2 5 2 6 2 2mol O bO gstoic = 100 mo
The University of Akron - CHEMICAL E - 312
4.41 (cont'd)e.10 5 45 0.0119 76.5 - 0.0605 - = 53.9 mV 7 7 7 5 nc = 53.9 + = 127.4 kmol / h 3 3 Faulty sensors, computer problems, analyzer calibration not linear, extrapolation beyond range of calibration data, system had not reached steady state yet.
The University of Akron - CHEMICAL E - 312
4.41 (cont'd) b.nc =3.00 10 2 kmol 0.85 kmol H 2 S 1 kmol SO 2 = 127.5 kmol SO 2 / h h kmol 2 kmol H 2 Sc.C a lib r a t io n C u r v e1 .2 0 1 .0 0 X (mol H 2 S/mol) 0 .8 0 0 .6 0 0 .4 0 0 .2 0 0 .0 0 0 .0 2 0 .0 4 0 .0 6 0 .0 8 0 .0 1 0 0 .0R a (m
The University of Akron - CHEMICAL E - 312
4.41 (cont'd) b.nc =3.00 10 2 kmol 0.85 kmol H 2 S 1 kmol SO 2 = 127.5 kmol SO 2 / h h kmol 2 kmol H 2 Sc.C a lib r a t io n C u r v e1 .2 0 1 .0 0 X (mol H 2 S/mol) 0 .8 0 0 .6 0 0 .4 0 0 .2 0 0 .0 0 0 .0 2 0 .0 4 0 .0 6 0 .0 8 0 .0 1 0 0 .0R a (m
The University of Akron - CHEMICAL E - 312
4.39 (cont'd) b. nH 2nC2 H2. = 15 < 2.0 H 2 is limiting reactant. . 15 mol H 2 fed 10 mol C 2 H 2 fed 0.75 mol C 2 H 2 required (theoretical) . 10 mol fed - 0.75 mol required % excess C 2 H 2 = . 100% = 333% 0.75 mol requiredc.4 106 tonnes C 2 H 6 1
The University of Akron - CHEMICAL E - 312
4.38 (cont'd)Solvent m f 1: balance: m f 2: balance: m f 3: balance:b g 3300 = 495 + F U 015b495 + F g = C . | 495 + F = C + F | V 015b2720 + C g = C | . 2720 + C = F + C | W015 3300 = C1S .1S 3S 2S 3S 2S 2S 2S 3S 2S 3S 3SC1S = 495 kg S F1S = 2805 kg
The University of Akron - CHEMICAL E - 312
4.37(cont'd)b g around the filter b m , m , x g , but the tub only involves 2 b m , m g and 2 balances areBalances around the mixing point involve 3 unknowns m3 , m6 , x , as do balances4 6 3 4allowed for each subsystem. Balances around tub m3 , m4 B
The University of Akron - CHEMICAL E - 312
4.37(cont'd)b g around the filter b m , m , x g , but the tub only involves 2 b m , m g and 2 balances areBalances around the mixing point involve 3 unknowns m3 , m6 , x , as do balances4 6 3 4allowed for each subsystem. Balances around tub m3 , m4 B
The University of Akron - CHEMICAL E - 312
4.36(cont'd) Extractor S balance: 87.0 kg S = x2 m2Extractor oil balance: 13.0 kg oil = y2 m2 Filter S balance: 87.0 kg S = 0.75m3 Filter mass balance: m2 kg = m3 + m4 Oil / hexane ratio in filter cake:b gy3 0.25 - y3=y2 1 - x2 - y2Filter oil balan
The University of Akron - CHEMICAL E - 312
4.36(cont'd) Extractor S balance: 87.0 kg S = x2 m2Extractor oil balance: 13.0 kg oil = y2 m2 Filter S balance: 87.0 kg S = 0.75m3 Filter mass balance: m2 kg = m3 + m4 Oil / hexane ratio in filter cake:b gy3 0.25 - y3=y2 1 - x2 - y2Filter oil balan
The University of Akron - CHEMICAL E - 312
4.35 (cont'd)Total molar flow rate of liquid feed to stripper and mole fraction of CO2: n3 n3 + n4 = 680 mol / h, x3 = = 0.0478 mol CO 2 / mol n3 + n4e.Scale up to 1000 kg/h (=106 g/h) of product gas:. . bn g = d10 10 g / hib16.28 g / molg = 6142 10 m
The University of Akron - CHEMICAL E - 312
4.35 (cont'd)Total molar flow rate of liquid feed to stripper and mole fraction of CO2: n3 n3 + n4 = 680 mol / h, x3 = = 0.0478 mol CO 2 / mol n3 + n4e.Scale up to 1000 kg/h (=106 g/h) of product gas:. . bn g = d10 10 g / hib16.28 g / molg = 6142 10 m
The University of Akron - CHEMICAL E - 312
4.35a.Overall objective: Separate components of a CH4-CO2 mixture, recover CH4, and discharge CO2 to the atmosphere. Absorber function: Separates CO2 from CH4. Stripper function: Removes dissolved CO2 from CH3OH so that the latter can be reused. The top
The University of Akron - CHEMICAL E - 312
4.35a.Overall objective: Separate components of a CH4-CO2 mixture, recover CH4, and discharge CO2 to the atmosphere. Absorber function: Separates CO2 from CH4. Stripper function: Removes dissolved CO2 from CH3OH so that the latter can be reused. The top
The University of Akron - CHEMICAL E - 312
4.34 (cont'd)Overall mass balance: m1 = 175 + 10m2 + m2 Overall K balance: . 0196m1 = 10m2 + 0.400m2 Production rate of crystals = 10m2U | V | W45% evaporation: 175 kg evaporated min = 0.450m5 W balance around mixing point: 0.804m1 + 0.600m3 = m5 Mass
The University of Akron - CHEMICAL E - 312
4.34 (cont'd)Overall mass balance: m1 = 175 + 10m2 + m2 Overall K balance: . 0196m1 = 10m2 + 0.400m2 Production rate of crystals = 10m2U | V | W45% evaporation: 175 kg evaporated min = 0.450m5 W balance around mixing point: 0.804m1 + 0.600m3 = m5 Mass
The University of Akron - CHEMICAL E - 312
4.33 (cont'd)m 1 vs. x 60.03500 0.03000 0.02500 0.02000 0.01500 0.01000 0.00500 0.00000 0 2000 4000 6000 8000 10000 12000x 6 (kg Cr/kg)m 1 (kg/h)d.Cost of additional capacity installation and maintenance, revenue from additional recovered Cr, antici
The University of Akron - CHEMICAL E - 312
4.33 (cont'd)m 1 vs. x 60.03500 0.03000 0.02500 0.02000 0.01500 0.01000 0.00500 0.00000 0 2000 4000 6000 8000 10000 12000x 6 (kg Cr/kg)m 1 (kg/h)d.Cost of additional capacity installation and maintenance, revenue from additional recovered Cr, antici
The University of Akron - CHEMICAL E - 312
4.33a.m4 kg Cr / hbgm1 kg / hbgm2 kg / hbgTreatment Unit0.0515 kg Cr / kg 0.9485 kg W / kg0.0515 kg Cr / kg 0.9485 kg W / kgb g x b kg Cr / kgg 1 - x b kg W / kggm5 kg / h5 5b g x b kg Cr / kgg 1 - x b kg W / kggm6 kg / h6 6m3 kg / hb
The University of Akron - CHEMICAL E - 312
4.33a.m4 kg Cr / hbgm1 kg / hbgm2 kg / hbgTreatment Unit0.0515 kg Cr / kg 0.9485 kg W / kg0.0515 kg Cr / kg 0.9485 kg W / kgb g x b kg Cr / kgg 1 - x b kg W / kggm5 kg / h5 5b g x b kg Cr / kgg 1 - x b kg W / kggm6 kg / h6 6m3 kg / hb