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Course: BUS-MGT 330, Spring 2012
School: Ohio State
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5 Printfirst letterof your last name- CAPITAL (left LETTERS justify) OSUE-mailidentifier number(rightjustify) ) t t t tttt LastName(printed))ttt First Name(printed)t t t t Busineosluanagement Exam#3 330 A*ru)n* Kn A countdown timerwill be projected the screenin the frontof the classroom on duringthe exam. . You have90 minutes complete exam. to this r No "timechecks'willbe verbally givenby the...

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5 Printfirst letterof your last name- CAPITAL (left LETTERS justify) OSUE-mailidentifier number(rightjustify) ) t t t tttt LastName(printed))ttt First Name(printed)t t t t Busineosluanagement Exam#3 330 A*ru)n* Kn A countdown timerwill be projected the screenin the frontof the classroom on duringthe exam. . You have90 minutes complete exam. to this r No "timechecks'willbe verbally givenby the instructor duringthe exam. . Whenthe 90 minutes complete, writing cease. are all will . Any clarifications and/orcorrections examquestions of wilfbe postedbeneath countdown the clock. / Questions Answers . Please readeachquestion carefully directly and answer question is asked. the that . Placethe answer the question to askedin the boxprovided. . Points be deducted equations anything will for or otherthanthe answerin the box. . Points not be awarded answers Dlaced the box. will for not in o The rcquired number of decimal places for numeric answe6 ia in b,'a/cke'swithin the answer boxes, Calculators o Thereare no extrabatteries extracalculators lendto the students or to duringthe exam. . No instruction the useof the calculator its functions be givenduringthe exam. on or will . No sharing calculators permitted. of is The use of cell phones. PDAS.and iPods (HPg olaveB) durtno the exam are prchibited! No communication any kind(verbal, of non-verbal, written, electronic, etc.)is permitted duringthe courseof the exam. I have readthe exam instructionsaboveand undeBtand that any yiolation of the8eand other exam rules in the StudentCodeof Conductwill rsult in a suspectedcase of acadbmicmlsconduct. Signature: Date: Do notwritebelow this line Totalpoints quiz on Totalpoints missed 207 Percent correct Curved score 1. [36 Poinfs - 3 Points for each box] Usingthe regression equation Y-hati= 3.30- 0.10 Xi completethe tables below (onlythe bold bordered boxesare graded). x 3 5 Y 1 4 Y-bar Y-hat (Y - Y-bar)2 3 3 3 3,0 L,T 3,( 3,L V.oo l,oo {.oo o, Do /,op f O,OD nr (Y - Y-hat)2 2 1 4 5 3 2 3 3 L,1 Total X 3 5 Y 1 4 5 Y-bar Y-hat 3 3 3,o V.Do z.E 3,( 3,t ,,vv 3,b t O , o* 2 1 4 3 3 3 2 3 L,1 Total o,7 I 9,?o ftj X 3 5 2 1 4 Y 1 4 Y-bar Y-hat (Y-hat - Y-bar)2 3 3,o L,T o.oo o,oY o,o I 3 3 5 3 2 3,1 !,t 3 3 o,ov O,oI O,lO nl zn Total Do not write below this line 2 2. [25 Poinfs- 1 for each box in top tableand 2 for each box in bottom tablel Giventhe following results froman experiment, calculate missing the information. A 1 4 4 B 5 4 4 c 5 4 6 V} tlaTa rA 2 3 4 2 3 3 = 1(4 + *(v) + 3(s) = 3.83 IL 5 n; \-bar X-bar-bar J v) 2 tol tOl +rc, +rcr 3rc. Srcl 2 ss6 = , nUtRt_if 3,83 pl l,(=) SSc_ ANOVA table + Q -3J' r k-.+). r Crr_ r lv_v\. *f -vl' + g - s)' * _s)., lt- r)t r Cs G - 3. [14 Points- 2 points for each box] ln a completely randomized experimental design, nine observations madefor eachof the seven were groups. Complete the ANOVA tablebelow. d,ou Do not write below this line 3 4. [39 Poinfs-- 3 points for each box] Giventhe perform intermediate calculations below, the calculations needed determine to whether significant differences existsbetween population the means of thegroups. Statistic Group #1 5 5 Group#2 I 6 Group#3 7 4 1 Y n X-bar Variance(S2) sr(sl * e[c\ * -] (v) ZI rr = f,ro 3 2 a. State NullHypothesis: the 55.C1 Z nd(Id -i)' f,(lS,,of , q (s -r,(o)Lo I Cv*S,,o)z b. StatetheAlternative Hypothesis: F)or Ar. AL,rAn" &,;r* c. Completethe ANOVA table below. lt,t t 5sa 2l^u- ,)s6' ((a) + -E ( z ) r s C , ) 3.+ d) lf o = 0.05,what is Fsilhd? 4,ESS e) "Reject"/"Do Not Reject"He? Rel cr Do not write belowthis line 4 5. [25 Poinfs/ Using following the ANOVA table, test thesignificance the model of witha = 0.05. a. State nullandalternative the hypotheses. Ho: Hn: b. t -o t+o L'31 What is the value of F6d1;sa1? c. "Reject" "DoNotReject" nullhypothesis? / the &'-J6*cT d. ls the independent variable an effective X predictor the dependent for variable ("Yes" Y / "No")? \/s s Do not write belowthis line 5 7. [42 Points Total] a. [1 Pointper box] Complete following the table. x 3 5 Y 2 3 5 4 1 xx XY YY 1rc. V ,0, * r ' 7s rol lS ,0, ? r c j * | ,0, ,0, 2 1 4 l o r o r 75 rc1 '( ro, lb pt ( ror b,= n:-Y\/ - 2 v t y n a>y- :.x 2v l b r o r * ror {{,0, ?-QI':>@!e >-O,(aO Total Average l9 ror 6ror 3 ror 3 r c r 31 ror -5Tror b. [5 Points] Using least-squares the method, calculate slope. the r-= S- b.i rJorl : Y,?o -I -D,L n c. [5 Points] Usingthe least-squares method, calculate the intercept. ,t d. [5 Points] Calculatethe coefficient of determination. N 1-x\ - 1x ay f- 0,36 e. [5 Points] Calculate coefficient the of correlation. z*t4:nlxY r/6 LxKV_ sJ ) Cz95- (r) Ct -rx lYl - O:GO -- ltcEs)-o') (rs[ {sJ(r'l1 tl S(sr) - O,Loo f\, '(rF = (-o,go)L _ o,3V Do not write belowthis line 6 8. [40 Poinfs-- 10 points for each box] Matchthe fourANOVA parameters tables the population to of eachof the4 scenarios. ANOVA Table "A" Population for distributions eachscenario 1 2 Group Group Scenario 1 Fr=50 or=3 t\=20 Fr=50 or=5 t\=20 Fr=50 ot=5 t\=20 Pr=$g or=3 t\=20 Fz=50 oz=3 nz=20 Vz=45 oz=5 nz=20 Pz=50 C z =5 A z =2 0 V z =4 5 oz=3 tlz= 20 Group 3 Ps=50 oe=3 ng=20 Ps=50 og=5 4 Group Fq=50 o+=3 nq=20 P4=55 o+=5 llq = 20 Scenario 2 hs=20 Fa=50 os=5 ns=20 Pg=50 og=3 ng=20 ANOVA Table"B" Scenario 3 = Fr+ 50 oa=5 nq=20 = Fr+ 55 o+=3 nq=20 4 Scenario ANOVA Table "C" Match ANOVA the table(A, B, C, or D) to the correct (1 s c e n a r i o , 2 , 3 , r4 ) o Scenario1 g C A D B, [A, c, orD] [A,B,c, orD] [A,B,c, orD] [A,B,c, orDl ANOVA Table"D" Scenario 2 Scenario 3 Scenario 4 1818.07 Do not write belowthis line 7
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Ohio State - ECON - 200
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Ohio State - ECON - 200
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Colorado - MATH - 4430
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Repeated EigenvaluesRecallWe are now in the position that we can nd (at least) as many linearly-independent solutions tothe homogeneous equationy = Ayas there are distinct eigenvalues of A (real or complex). This is because for each real eigenvalue
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In[5]:=ListPlot0, 0 , 1, 3 , 3, 6 , 3, 9 , 3, 11 , 1, 12 ,6, 14 , 3, 17 , 3, 18 , 3, 19 , 6, 21 , AxesLabeld, En2015En10512345d6
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b)r(u0Sa Ctth:,c~)r.,.t'"--(-:~J[)v, ~.lG:-t't1&11 [r":(, if>A ,L ,\.lVW'ViOL).E.t; b"f'cfw_: iA-c,Jtlt- fl,\ \ s ;,'.Dcfw_.-(I/l),!)'1 lll.l; ) :;- ('3 I "3 J; I'Ii /1\.~~Oly"t+~\~Q;nI(]3)-:>"'Cf<:U\rt Sof'.tf Nt
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Colorado - PHYS - 3220
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