pointsAll 1.5/5 Submissions NotesQuestion: ZumChemP6 9.E.015.
Consider the accompanying diagram. Ball A is allowed to fall and strike ball B. Assume that all of ball A's energy is transferred to ball B, at point I, and that there is no loss of energy to other sources. What is the kinetic energy and the potential energy of ball B at point II? The potential energy is given by PE = mgz, where m is the mass in kilograms, g is the gravitational constant (9.8 m/s ), and z is the distance in meters.
2
kinetic energy 78.4 118 J J potential energy
2.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.020.
Calculate the internal energy change for each of the following. (a) One hundred seventeen (117) joules of work are required to compress a gas. At the same time, the gas releases 23 J of heat. 94 J
(b) A piston is compressed from a volume of 8.30 L to 2.80 L against a constant pressure of 1.90 atm. In the process, there is a heat gain by the
system of 352 J. 1410 J
(c) A piston expands against 1.19 atm of pressure from 11.2 L to 29.1 L. In the prcess, 1037 J of heat is absorbed. 1120 J <INPUT TYPE=\ submit VALUE= Practice Another Version NAME= Practice1 > MACROBUTTON HTMLDirect
3.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.022.
Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 30. cm . If the combustion of this mixture releases 1125. J of energy, to what volume will the gases expand against a constant pressure of645. torr if all the energy of combustion is converted into work to push back the piston? 13.1 L <INPUT TYPE=\ submit VALUE= Practice Another Version NAME= Practice2 > MACROBUTTON HTMLDirect
4.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.026.
3
Are the following processes exothermic or endothermic? (a) the combustion of gasoline in a car engine <INPUT TYPE=\ radio NAME= RC_822993_3_0_829767 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect exothermic<INPUT TYPE=\ radio NAME= RC_822993_3_0_829767 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect endothermic (b) CO2(s) CO2(g) <INPUT TYPE=\ radio NAME= RC_822993_3_1_829767 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect exothermic<INPUT TYPE=\ radio NAME= RC_822993_3_1_829767 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect endothermic
<INPUT TYPE=\ submit VALUE= Practice Another Version NAME= Practice3 > MACROBUTTON HTMLDirect
5.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.029.
The overall reaction in a commercial heat pack can be represented in the reaction given below. 4 Fe(s) + 3 O2(g) 2 Fe2O3(s) O2? 1690 kJ H = -1652 kJ (a) How much heat is released when 4.09 mol iron is reacted with excess
(b) How much heat is released when 1.24 mol Fe2O3 is produced? 1020 kJ
(c) How much heat is released when 1.24 g iron is reacted with excess O2? 9.17 kJ
(d) How much heat is released when 12.4 g Fe and 2.48 g O2 are reacted? 42.7 kJ <INPUT TYPE=\ submit VALUE= Practice Another Version NAME= Practice4 > MACROBUTTON HTMLDirect
6.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.032.
For the following reactions at constant pressure, predict if H > E, H < E, H = E. (a) 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) <INPUT TYPE=\ radio NAME= RC_822997_5_0_829771 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect H > E<INPUT TYPE=\ radio NAME= RC_822997_5_0_829771 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect H < E <INPUT TYPE=\ radio NAME= RC_822997_5_0_829771 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect H = E
(b) 2 HF(g) H2(g) + F2(g) <INPUT TYPE=\ radio NAME= RC_822997_5_1_829771 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect H > E<INPUT TYPE=\ radio NAME= RC_822997_5_1_829771 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect H < E <INPUT TYPE=\ radio NAME= RC_822997_5_1_829771 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect H = E
7.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.034.
Calculate q, w, E, and H for the process in which 86.0 g of nitrous oxide gas (N2O) is cooled from 167C to 57C at constant pressure of 5.00 atm. (See the table)
q 8.32 w 1.79 H 8.32 E kJ kJ kJ
6.53
kJ
8.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.036.
Consider a sample containing 2.00 mol of a monatomic ideal gas that undergoes the following changes.
For each step, assume that the external pressure is constant and equals the final pressure of the gas for that step. Calculate q, w, E, and H for each step and for the overall change from state A to state D. Step 1 q w E H 12.7 5.07 7.61 12.7 kJ kJ kJ kJ Step 2 7.61 0 kJ kJ kJ kJ Step 3 101 40.5 60.9 101
1 1
Total 96 35.4 60.9 101 kJ kJ kJ kJ
kJ kJ kJ kJ
7.61 12.7
9.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.038.
The specific heat capacity of silver is 0.24 J C g . (a) Calculate the energy required to raise the temperature of 120.0 g Ag from 273 K to 297 K. 690 J
(b) Calculate the energy required to raise the temperature of 1.0 mol Ag by 1.0C (called the molar heat capacity of silver). 26 J/molC
(c) It takes 1.15 kJ of energy to heat a sample of pure silver from 12.0C to 15.9C. Calculate the mass of the sample of silver. 1200 g
10.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.040.
A 150.0g sample of a metal at 75.0C is added to 150.0 g of H2O at 15.0C. The temperature of the water rises to 18.1C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water. .23
HW 2
JC g
1
1
1.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.044.
In a coffeecup calorimeter, 1.90 g of NH4NO3 is mixed with 73.0 g of water at an initial temperature of 25.00C. After dissolution of the salt, the final temperature of the calorimeter contents is 23.33C. Assuming the solution has a heat capacity of 4.18 J/Cg and assuming no heat loss to the calorimeter, calculate the enthalpy change for the dissolution of NH4NO3 in units of kJ/mol. 21.9 kJ/mol
2.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.050.
Calculate w and E when one mole of a liquid is vaporized at its boiling point (91C) and 1.00 atm pressure. Hvap for the liquid is 27.9 kJ mol
1
at 91C. 3030 J
w
E 25.0 kJ
3.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.054.
Consider the following data. Fe2O3(s) + 3 CO(g) 23 kJ 3 Fe2O3(s) + CO(g) 39 kJ Fe3O4(s) + CO(g) +18 kJ Calculate H for the following reaction. FeO(s) + CO(g) 11 kJ Consider the following data. P4(s) + 6 Cl2(g) P4(s) + 5 O2(g) PCl3(g) + Cl2(g) PCl3(g) + /2 O2(g) Calculate H for the following reaction. P4O10(s) + 6 PCl5(g) 610.1 kJ 10 Cl3PO(g)
1
2 Fe(s) + 3 CO2(g) H = 2 Fe3O4(s) + CO2(g) H = 3 FeO(s) + CO2(g) H =
Fe(s) + CO2(g)
4.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.058.
4 PCl3(g) H = 1225.6 kJ P4O10(s) H = 2967.3 kJ PCl5(g) H = 84.2 kJ Cl3PO(g) H = 285.7 kJ
5.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.064.
The reusable booster rockets of the space shuttle use a mixture of aluminum and ammonium perchlorate as fuel. A possible reaction is given below. 3 Al(s) + 3 NH4ClO4(s) Al2O3(s) + AlCl3(s) + 3 NO(g)
+ 6 H2O(g) Calculate H for this reaction. 2677 kJ
6.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.068.
Calculate H for each of the following reactions, which occur in the atmosphere. (a) C2H4(g) + O3(g) 361 199 227 112 kJ NO2(g) + O2(g) H2SO4(aq) 2 NO2(g) kJ kJ kJ (b) O3(g) + NO(g) (c) SO3(g) + H2O(l) (d) 2 NO(g) + O2(g) CH3CHO(g) + O2(g)
7.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 9.E.070.
The standard enthalpy of combustion of ethene gas, C2H4(g), is -1411.1 kJ/mol at 298 K. Given the following enthalpies of formation, calculate Hf for C2H4(g). CO2(g) -393.5 kJ/mol H2O(l) -285.9 kJ/mol 52.3 kJ/mol
8.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.016.
Which of the following involve an increase in the entropy of the system under consideration? (Select all that apply.) diffusion melting of a solid evaporation of a liquid separation freezing sublimation mixing
9.4.38/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.018.
Choose the compound with the greatest positional probability in each case. (a) 1 mol of N2O at STP 1 mol of H2 at STP Explain. I chose incorrectly. It would seem to me that both would have an equal positional probability because both are gases at under the same conditions. Thus their volumes would be equal and a mole any ideal gas could occupy the space in the same number of ways. (b) 1 mol of H2 at STP 1 mol of H2 at 100C and 0.5 atm Explain. the H2 at a higher temperature and a lower pressure will occupy a larger volume than the mol at STP. Therefore there are more ways for the same number of molecules to occupy that space, this is an increase in disorder/entropy/positional probability. (c) 1 mol of N2 at 100 K and 2.0 atm 1 mol of N2 at STP Explain. The N2 at a lower T and P will have a lower positional probability because it will occupy a smaller V than the N2 at STP. In a smaller volume, there are fewer ways for the molecules to occupy the space. (d) 1 mol of H2O(l) at 20C 1 mol of H2O(s) at 0C Explain. Solids have lower positional probability than liquids because the positions of the molecules in a solid are static.
10.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.020.
Entropy can be calculated by a relation proposed by Ludwig Boltzmanns, where kB = 1.38 10 J/K and is the number of ways a particular state can be obtained. (This equation is engraved on Boltzmann's tombstone.). S = kB ln Calculate S for the three arrangements of particles in the table below.
23
arrangement I 0 J/K J/K J/K arrangement II 1.91e23 arrangement III 2.47e23
HW 3
1.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.021.
Calculate the energy required to change the temperature of 1.00 kg of ethane (C2H6) from 25.0C to 73.9C in a rigid vessel. (Cv for C2H6 is 44.60 J K mol .) 72.6 kJ Calculate the energy required for this same temperature change at constant pressure. 86.1 processes. case 1 (constant volume) 72.6 72.6 kJ kJ
2.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.025.
1 1
kJ
Calculate the change in internal energy of the gas in each case of these
case 2 (constant pressure)
One mole of an ideal gas with a volume of 1.8 L and a pressure of 4.2 atm is allowed to expand isothermally into an evacuated bulb to give it a total volume of 3.9 L. Calculate w and q. Also, calculate qrev for this change of state. w 0 q 0 qrev 590 J
3.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.026.
J J
A cylinder with an initial volume of 11.4 L is fitted with a frictionless piston and is filled with 1.00 mol of an ideal gas at 25C. Assume that the surroundings are large enough so that if heat is withdrawn from or added to it, the temperature does not change. (a) The gas expands isothermally and reversibly from 11.4 L to 21.6 L. Calculate the work and the heat. work 1580 J heat 1580 J
(b) The gas expands isothermally and irreversibly from 11.4 L to 21.6 L as the external pressure changes instantaneously from 2.46 atm to 1.23 atm. Calculate the work and the heat. work 1270 J
4.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.038.
heat 1270 J
For each of the following pairs of substances, which substance has the greater value of S at 25C and 1 atm?
(a) Cdiamond(s) Cgraphite(s) (b) C2H5OH(g) C2H5OH(l) (c) CO2(g) CO2(s) (d) N2O(g) He(g) (e) HCl(g) HF(g)
5.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.044.
Ethanethiol (C2H5SH; also called ethyl mercaptan) is commonly added to
natural gas to provide the "rotten egg" smell of a gas leak. The boiling point of ethanethiol is 35C and its heat of vaporization is 27.5 kJ/mol. What is the entropy of vaporization for this substance? 89.3 J K mol
1 1
6.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.047.
For ammonia (NH3), the enthalpy of fusion is 5.65 kJ/mol and the entropy of fusion is 28.9 J K mol . (a) Will NH3(s) spontaneously melt at 200. K? Yes No (b) What is the approximate melting point of ammonia? 196 K
1 1
7.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.050.
From data in Appendix 4, calculate H, S, and G for each of the following reactions at 25C. (a) CH4(g) + 2 O2(g) CO2(g) + 2 H2O(g) H 802 S 4 G 801 kJ C6H12O6(s) + 6 O2(g) Glucose J/K kJ
(b) 6 CO2(g) + 6 H2O(l) H 2800 S 262 G J/K kJ
2880
kJ
(c) P4O10(s) + 6 H2O(l) 4 H3PO4(s) H 416 S 209 G 356 kJ J/K kJ
(d) HCl(g) + NH3(g) NH4Cl(s) H 176 S 284 G 91 kJ Consider the following data. 2 C6H6(l) + 15 O2(g) C(s) + O2(g)
1
kJ J/K
8.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.058.
12 CO2(g) + 6 H2O(l)
G = 6399 kJ G = 394 kJ G = 237 kJ
CO2(g) H2O(l) C6H6(l)
H2(g) + /2 O2(g)
Calculate G for the following reaction. 6 C(s) + 3 H2(g) 125 kJ
9.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.064.
Using thermodynamic data from Appendix 4, calculate G at 25C for the following process where all gases are at 1.00 atm pressure.
2 SO2(g) + O2(g) 2 SO3(g) 142 kJ Also calculate G at 25C for this same reaction but with all gases at 10.0 atm pressure. 148 kJ
10.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 10.E.066.
Calculate G for the reaction for the following conditions at 25C. 2 H2S(g) + SO2(g) PH2S = 1.0 10 atm PSO2 = 1.0 10 atm PH2O = 3.0 10 atm 50.
HW 4
1.3.42/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.018.
2 2 4
3 S(s) + 2 H2O(g)
kJ
Calculate
values for the following cells. Which reactions are spontaneous as written
(under standard conditions)? Balance the reactions. Standard reduction potentials are found in the table. (Use the lowest possible coefficients. Include statesofmatter under the given conditions in your answer.) (a) MnO4(aq) + I (aq) = .970.97 V spontaneous reaction 10I(aq) + 2MnO4(aq) + 16H+(aq) 2Mn2+(aq) + 8H2O(l) + 5I2(aq)
16 H+(aq) + 2 MnO
4
I2(aq) + Mn (aq)
2+
(aq) + 10 I(aq) 5 I2(aq) + 2 Mn2+(aq) + 8 H2O(l)
Correct. (b) H2(g) H (aq) + H (aq)
+
= 2.23 2.23V spontaneous reaction H2(g) H+(aq) + H(aq)
H2(g) H+(aq) + H(aq)
Correct. (c) Au (aq) + Ag(s) reaction Au3+(aq) + 3Ag(s) Au(s) + 3Ag+(aq)
Au3+(aq) + 3 Ag(s) Au(s) + 3 Ag+(aq)
3+
Ag (aq) + Au(s)
+
= .70 0.7 V spontaneous
Correct.
2.3.84/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.020.
Consider the following galvanic cells.
For each galvanic cell, give the balanced cell reaction and determine . Standard reduction potentials are found in the table. (Use the lowest possible coefficients. Include statesofmatter under SATP conditions in your answer.) (a) reaction Au3+(aq) + 3Cu1+(aq) Au(s) + 3Cu2+(aq)
Au3+(aq) + 3 Cu+(aq) Au(s) + 3 Cu2+(aq)
Correct. = 1.34 (b) reaction 2VO2 (aq) + 4H+(aq) + Cd(s) Cd2+(aq) + 2VO2+(aq) + 2H2O(l) + 2 VO2 (aq) + 4 H+(aq) + Cd(s) 2 VO2+(aq) + 2 H2O(l) + Cd2+(aq) Correct.
+
1.34 V
= 1.40
1.4 V
3.3.46/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.022.
The saturated calomel electrode, abbreviated SCE, is often used as a reference electrode in making electrochemical measurements. The SCE is composed of mercury in contact with a
saturated solution of calomel (Hg2Cl2). The electrolyte solution is saturated KCl.
SCE
is
+0.242 V relative to the standard hydrogen electrode. Calculate the potential for each of the following galvanic cells containing a saturated calomel electrode and the given halfcell components at standard conditions. In each case, indicate whether the SCE is the cathode or the anode. Standard reduction potentials are found in Table 11.1. (c) AgCl + e Cl Ecell .02 cathode 0.02V
Ag +
(a) Cu + 2 e Cu Ecell .10 0.1V anode
2+
(b) Fe + e Ecell .53
3+
Fe
2+
0.53 V anode
(d) Al + 3 e Al Ecell 1.901.9 V cathode
3+
(e) Ni + 2 e Ni Ecell .470.47V cathode
2+
4.0/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.024.
Using data from the table, place the following in order of increasing strength as oxidizing agents (all under standard conditions). (Use the appropriate <, =, or > symbol to separate substances in the list.) Cd , IO3, K , H2O, AuCl4, I2 K+ < IO3 < I2 < H2O < Cd2+ < AuCl4
K+ < H2O < Cd2+ < I2 < AuCl4 < IO3
2+ +
Your answer contains an improper oxidation state. Your answer contains an incorrect or incomplete chemical formula. A formula in your answer has an incorrect stoichiometry. The components in your answer are not in the expected order.
5.3.84/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.032.
The equation G = -nF Fe 85 Fe 10.
3+ 2+
also can be applied to halfreactions. Use standard
2+ 3+
reduction potentials to estimate Gf for Fe (aq) and Fe (aq). (Gf for e = 0.) 84.9 kJ 10.4 kJ
6.3.84/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.036.
Chlorine dioxide (ClO2), which is produced by the reaction below, has been tested as a disinfectant for municipal water treatment. 2 NaClO2(aq) + Cl2(g) 2 ClO2(g) + 2 NaCl(aq) (a) Using data from the table, calculate and G at 25C for the production of ClO2.
.41 0.41 J/C 79 G 78 kJ
(b) One of the concerns in using ClO2 as a disinfectant is that the carcinogenic chlorate ion (ClO3 ) might be a byproduct. It can be formed from the following reaction in the presence of water. ClO2(g) ClO3(aq) + Cl (aq) Balance the equation for the decomposition of ClO2. (Use the lowest possible coefficients. Include statesofmatter under the given conditions in your answer.) 6ClO2(g) + 3H2O(l) 5ClO3(aq) + Cl(aq) + 6H+(aq)
3 H2O(l) + 6 ClO2(g) 5 ClO3(aq) + Cl(aq) + 6 H+(aq)
Correct.
7.1.92/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.037.
The amount of manganese in steel is determined by changing it to permanganate ion. The steel is first dissolved in nitric acid, producing Mn ions. These ions are then oxidized to the deeply colored MnO4 ions by periodate ion (IO4) in acid solution. (a) Complete and balance an equation describing each of the above reactions. (Use the lowest possible coefficients. Include statesofmatter under SATP conditions in your answer.) (equation 1) Mn(s) + 2H+(aq) Mn2+(aq) + H2(g) 3 Mn(s) + 8 H+(aq) + 2 NO3 (aq) 2 NO(g) + 4 H2O(l) + 3 Mn2+(aq) Your answer contains an ambiguous or incomplete reaction equation. Check all the components on the reactantside of the equation. Check all the components on the product side of the equation. (equation 2) 3H2O(l) + 2Mn2+(aq) + 5IO4(aq) 2MnO4(aq) + 6H+(aq) + 5IO3(aq) Correct.
2+
(b) Calculate and G at 25C for each reaction. (equation 1) cell 2.41 2.14 V
G
(No Response) 1240 kJ
(equation 2) cell 0.09 0.09 V 86.8 86.8 kJ
G
8.3.2/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.038.
The overall reaction and equilibrium constant value for a hydrogenoxygen fuel cell at 298 K is given below. 2 H2(g) + O2(g) 2 H2O(l) K = 1.28 10
83
(a) Calculate and G at 298 K for the fuel cell reaction. = 1.23 G = 474 reaction. H positive S positive negative negative 1.23 V 475 kJ (b) Predict the signs of H and S for the fuel cell
(c) As temperature increases, does the maximum amount of work obtained from the fuel cell reaction increase, decrease, or remain the same? increase Explain. because dG = dH TdS, as the temperature increases the number of joules added to dG also increases. dG is a proxy measurement for the work potential of the fuel cell (with a more negative dG corresponding to more work potential), thus the maximum amount of output decreases. Key: G = wmax = H TS. Since S is negative, then as T increases, G becomes more positive (closer to zero). Therefore, wmax will decrease as T increases.
9.3.84/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.042.
decrease remain the same
Calculate the value of the equilibrium constant for the reaction of zinc metal in a solution of silver nitrate at 25C. 6.19e52 6.19e+52
10.3.84/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.044.
Calculate Ksp for iron(II) sulfide given the following data. FeS(s) + 2 e Fe(s) + S (aq) Fe (aq) + 2 e Fe(s) 5.15e20 5.10e20
2+ 2
= -1.01 V
= -0.44 V
11.3.84/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.048.
Consider the following galvanic cell at 25C. Pt | Cr (0.54 M), Cr (2.3 M) || Co (0.18 M) | Co The overall reaction and equilibrium constant value are given below. 2 Cr (aq) + Co (aq) conditions. .161 G31.1
12.3.08/3.84 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.050.
2+ 2+ 2+ 3+ 2+
2 Cr (aq) + Co(s) K = 2.79 10
3+
7
Calculate the cell potential, , for this galvanic cell and G for the cell reaction at these 0.161V 31.0 kJ
The nernst equation can be applied to halfreactions. Calculate the reduction potential at 25C of each of the following halfcells. (The halfreaction is Cu + 2 e
+ 2+
Cu.)
(The halfreaction is MnO4 + 8 H + 5 e (a) Cu/Cu (0.26 M) = .32 (b) Cu/Cu (2.6 M)= .35
2+ 4 2+ 2+ 2+ 2+
Mn + 4 H2O.)
2+
0.32 V 0.35V 0.22 V 1.24 V 1.42 V
cell
(c) Cu/Cu (1.1 10 M) = .46
(d) MnO4 (0.26 M)/Mn (0.018 M) at pH = 3.00 = 1.24 (e) MnO4 (0.11 M)/Mn (0.028 M) at pH = 1.00 = 1.42
13.0/3.92 pointsAll Submissions NotesQuestion: ZumChemP6 11.E.046.
Calculate the pH of the cathode compartment for the following reaction given
3+ 3+ 2 7
= 3.01 V
when [Cr ] = 0.15 M, [Al ] = 0.30 M, and [Cr2O ] = 0.55 M. (Do not round intermediate steps.) 2 Al(s) + Cr2O7 (aq) + 14 H (aq) 2 Al (aq) + 2 Cr (aq) + 7 H2O(l) 5.42 0.0288
2 + 3+ 3+
HW 5
1.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.022.
Consider the following waves representing electromagnetic radiation.
Which wave has the longer wavelength? wave a wave b they are the same Calculate the wavelength. wave a 4.0e4 wave b 2.0e4 m Which wave has the higher frequency and larger photon energy? higher frequency wave a wave b they are the same larger photon energy wave a wave b they are the same Calculate these values. higher frequency 1.6e12 9.9e22 s J
1
m
larger photon energy
Which wave has the faster velocity? wave a wave b they are the same What type of electromagnetic radiation is illustrated? infrared
2.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.024.
A photon of ultraviolet (UV) light possesses enough energy to mutate a strand of human DNA. What is the energy of a single UV photon having a wavelength of 17 nm? 1.2e17 J
What is the energy of a mole of UV photons having a wavelength of 17 nm? 7.0e6 J
3.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.026.
One type of electromagnetic radiation has a frequency of 101.2 MHz, another type has a wavelength of 2.12 10 m, and another type of electromagnetic radiation has photons with energy equal to 1.67 10 J/photon. Identify each type of electromagnetic radiation. Convert 101.2 MHz to m. 2.962 m gamma rays X rays ultraviolet visible infrared microwaves FM radio shortwave radio AM radio 2.12 10 m gamma rays X rays ultraviolet visible infrared microwaves FM radio shortwave radio AM radio
10 24 10
Convert 1.67 10 24 J/photon to m.
.119 m gamma rays X rays ultraviolet visible infrared microwaves FM radio shortwave radio AM radio
Place them in order of increasing photon energy and increasing frequency. 1st (least) 101.2 MHz 2.12 10 m 1.67 10 J/photon 2nd 101.2 MHz 2.12 10 m 1.67 10 J/photon 3rd (greatest) 101.2 MHz 2.12 10 m 1.67 10 J/photon
4.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.027.
10 24 10 24 10 24
It takes 208.4 kJ of energy to remove one mol of electrons from the atoms on the surface of rubidium metal. If rubidium metal metal is irradiated with 254nm light, what is the maximum kinetic energy the released electrons can have? 4.36e19 J
5.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.030.
Calculate the de Broglie wavelength for each of the following. (a) an electron with a velocity 14% of the speed of light 0.017 nm
(b) a tennis ball (56 g) served at 35 m/s (~80 mi/h) 3.4e25 nm
6.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.032.
Calculate the velocities of electrons with de Broglie wavelengths of 2.6 10 nm and 2.6 nm, respectively. 2.6 10 nm 2800 m/s
2
2
2.6 nm 2.8e5 m/s
7.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.036.
What is the maximum wavelength of light capable of removing an electron from a hydrogen atom in the energy states characterized by n = 1 and n = 3? n = 1 91.5 n = 3 820 nm
8.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.037.
nm
An electron is excited from the ground state to the n = 3 state in a hydrogen atom. Which of the following statements are true? Correct any false statement. (For statements that are true, enter NR in the essay answer box.)
(a) It takes more energy to ionize (remove) the electron from n = 3 state than in the ground state. true false
it takes less energy to remove an e from the 3rd orbital than from the ground state. (b) The electron is farther from the nucleus on average in the n = 3 state than in the ground state. true false true (c) The wavelength of light emitted if the electron drops from n = 3 to n = 2 is shorter than the wavelength of light emitted if the electron falls from n = 3 to n = 1. True false E and W are inversely related to one another and W is related to the INVERSE of the difference between the square of each orbital. (d) The wavelength of light emitted when the electron returns to the ground state from n = 3 is the same as the wavelength of light absorbed to go from n = 1 to n = 3. true false true
(e) The first excited state corresponds to n = 3. true false in H n=1 is the ground state. All others are excited states, including n=2, which is the first excited state. 9.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.038.
Does a photon of visible light ( 400 to 700 nm) have sufficient energy to excite an electron in a hydrogen atom to make each of the following energy state transitions? n = 1 to n = 5 Yes No n = 2 to n = 6 Yes No
10.5/5 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.042.
Calculate the energy (in kJ/mol) required to remove the electron in the ground state for each of the following oneelectron species using the Bohr model.
(a) H
1310 (b) He 5250 kJ/mol
HW kJ/mol
+
6
1.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.046.
Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with n = 5 in a onedimensional box 47.3pm in length. .308 nm
2.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.056.
How many orbitals in an atom can have the following designation? 5p = 3 3dz = 1 4d = 5 n = 5 = 25 n = 4 =16
2
3.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.065.
What is the maximum number of electrons in an atom that can have the following quantum numbers? (a) n = 4 32 (b) n = 5, m = +1 8
(c) n = 5, ms = +1/2 25
(d) n = 3, = 2 10
(e) n = 2, = 1 6
(f) n = 0, = 0, m = 0 0
(g) n = 2, = 1, m = 1, ms = 1/2 1
(h) n = 3 18
(i) n = 2, = 2 0
(j) n = 1, = 0, m = 0 2
4.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.068.
Write the expected electron configurations for each of the following atoms. Te W Ir [Kr]5s2 4d10 5p4 Correct. [Xe]6s2 4f14 5d4 Correct. [Xe]6s2 4f14 5d7 Correct.
Cr Am Fr
[Ar] 4s1 3d5 Correct. [Rn] 7s2 5f7 Correct. [Rn]7s1 Correct.
5.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.070.
Write the expected groundstate electron configuration for the following. (a) the noble gas with electrons occupying 4f orbitals [Xe] 6s2 4f14 5d10 6p6 (b) the element with one unpaired 5p electron that forms a covalent compound with fluorine [Kr]5s2 4d10 5p5Correct.
6.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.080.
Which of the following electron configurations correspond to an excited state? (Select all that apply.) XI. 1s 2s 3p XII. 1s 2s 2p III. 1s 2s 2p 3s XIV. [Ar]4s 3d 4p
2 2 1 2 2 6 2 2 4 1 2 5 1
Identify the atoms and write the ground state electron configuration where appropriate. (Enter the given electron configuration if it is already in the ground state.) element element I 2 2 1 (1s 2s 3p ) element II 2 2 6 (1s 2s 2p ) element III 2 2 4 1 (1s 2s 2p 3s ) element IV name groundstate configuration
Boron
1s2 2s2 2p1 Correct.
Ne
1s2 2s2 2p6 Correct.
F
1s2 2s2 2p5 Correct.
Fe
[Ar]4s2 3d6 Correct.
([Ar]4s 3d 4p )
2
5
1
7.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.088.
In each of the following sets, which atom or ion has the smallest radius? (b) (a) Na XNa Na
+
Xelement 117 (c) element X He Xe 120 Ne element 119
(e) (d) X Cl In Se
X Li K Na
8.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.090.
Rank the elements C, Li, Ne, O, N in order of increasing first ionization energy. (Use the appropriate <, =, or > symbol to separate substances in the list.) Li<C<O<N<Ne
9.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.094.
Order the atoms in each of the following sets from the least exothermic electron affinity to the most. (Use the appropriate <, =, or > symbol to separate substances in the list.) (a) F, Cl, Br, I I < Br < F < Cl (b) N, O, F N < O < F Correct.
10.4.54/4.54 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.096.
Which has the more negative electron affinity, the oxygen atom or the O ion? O oxygen
11.4.6/4.6 pointsAll Submissions NotesQuestion: ZumChemP6 12.E.104.
Cesium was discovered in natural mineral waters in 1860 by R. W. Bunsen and G. R. Kirchhoff, using the spectroscope they invented in 1859. The name comes from the Latin word caesius, meaning "sky blue," which describes the prominent blue line observed for this element at 455.5 nm. Calculate the frequency and energy of a photon of this light. frequency 6.59e14 s
1
energy 4.36e19 J
1.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.014.
Without using Fig. 13.3, predict which bond in each of the following groups is the most polar. (a) <INPUT TYPE=\ radio NAME= RC_825573_0_ 0_828688 VALUE= 0 DISABLED> MACROBUTTO N HTMLDirect CF<INPUT TYPE=\ radio NAME= RC_825573_0_ 0_828688 VALUE= 1 CHECKED> MACROBUTTO N HTMLDirect GeF <INPUT TYPE=\ radio NAME= RC_825573_0_ 0_828688 VALUE= 2 DISABLED> MACROBUTTO (b) <INPUT TYPE=\ radio NAME= RC_825573_0 _1_828688 VALUE= 0 DISABLED> MACROBUTT ON HTMLDirect S Cl<INPUT TYPE=\ radio NAME= RC_825573_0 _1_828688 VALUE= 1 CHECKED> MACROBUTT ON HTMLDirect P Cl (c) <INPUT TYPE=\ radio NAME= RC_825573_0_2_82 8688 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect S F<INPUT TYPE=\ radio NAME= RC_825573_0_2_82 8688 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect SBr < INPUT TYPE=\ radio NAME= RC_825573_0_2_82 8688 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect SCl
N HTMLDirect SiF (d) <INPUT TYPE=\ radio NAME= RC_825573_0_ 3_828688 VALUE= 0 DISABLED> MACROBUTTO N HTMLDirect SiCl<INPUT TYPE=\ radio NAME= RC_825573_0_ 3_828688 VALUE= 1 DISABLED> MACROBUTTO N HTMLDirect GeCl <INPUT TYPE=\ radio NAME= RC_825573_0_ 3_828688 VALUE= 2 CHECKED> MACROBUTTO N HTMLDirect TiCl (e) <INPUT TYPE=\ radio NAME= RC_825573_0 _4_828688 VALUE= 0 CHECKED> MACROBUTT ON HTMLDirect SnH<INPUT TYPE=\ radio NAME= RC_825573_0 _4_828688 VALUE= 1 DISABLED> MACROBUTT ON HTMLDirect SiH <INPUT TYPE=\ radio NAME= RC_825573_0 _4_828688 VALUE= 2 DISABLED> MACROBUTT ON HTMLDirect C (f) <INPUT TYPE=\ radio NAME= RC_825573_0_5_82 8688 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect Al Br<INPUT TYPE=\ radio NAME= RC_825573_0_5_82 8688 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect InBr < INPUT TYPE=\ radio NAME= RC_825573_0_5_82 8688 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect Ga Br<INPUT TYPE=\ radio NAME= RC_825573_0_5_82 8688 VALUE= 3 CHECKED> MACROBUTTON HTMLDirect TlBr
H
2.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.022.
Write electron configurations for each of the following. (a) the cations: Mg , Sn , K , Al , Tl , As Mg
2+ 2+ 2+ + 3+ + 3+
Sn
2+
chemPad Help
chemPad Help
[Ne] <INPUT TYPE=\ text NAME= RB_1208426_1_0_1211541 VALUE= [Ne] Correct.
[Kr] 4d10 5s2 <INPUT TYPE=\ text NAME= RB_1208426_1_1_1211541 VALUE= [Kr] Correct.
K chemPad Help
+
Al chemPad Help
3+
[Ar] <INPUT TYPE=\ text NAME= RB_1208426_1_2_1211541 VALUE= [Ar] Correct.
[Ne] <INPUT TYPE=\ text NAME= RB_1208426_1_3_1211541 VALUE= [Ne] Correct.
Tl chemPad Help
+
As chemPad Help
3+
[Xe] 4f 5d 6s <INPUT TYPE=\ text NAME= RB_1208426_1_4_1211541 VALUE= [Xe]
14 10 2
Correct.
[Ar] 3d10 4s2 <INPUT TYPE=\ text NAME= RB_1208426_1_5_1211541 VALUE= [Ar] Correct.
(b) the anions: N , O , F , Te N chemPad Help
3
3
2
2
O
2
chemPad Help
[Ne] <INPUT TYPE=\ text NAME= RB_120842 6_1_6_1211 541 VALUE= [Ne] Correct.
[Ne] <INPUT TYPE=\ text NAME= RB_120842 6_1_7_1211 541 VALUE= [Ne] Correct.
F chemPad p Hel
Te chemPad Help
2
[Ne] <INPUT TYPE=\ text NAME= RB_120842 6_1_8_1211
[Xe] <INPUT TYPE=\ text NAME= RB_120842 6_1_9_1211
541 VALUE= [Ne] Correct.
541 VALUE= [Xe] Correct.
(c) the most stable ion formed by: Be, Rb, Ba, Se, I Be chemPad Help
Rb chemPad Help
[He] <INPUT TYPE=\ text NAME= RB_120842 6_1_10_121 1541 VALUE= [He] Correct.
[Kr] <INPUT TYPE=\ text NAME= RB_120842 6_1_11_121 1541 VALUE= [Kr] Correct.
Ba chemPad
Se chemPad
Help
Help
[Xe] <INPUT TYPE=\ text NAME= RB_120842 6_1_12_121 1541 VALUE= [Xe] Correct.
[Kr] <INPUT TYPE=\ text NAME= RB_120842 6_1_13_121 1541 VALUE= [Kr] Correct.
I chemPad Help
[Xe] <INPUT TYPE=\ text NAME=
RB_120842 6_1_14_121 1541 VALUE= [Xe] Correct.
3.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.024.
Which of the following ions have noble gas electron configurations? (Select all that apply.) (a) Fe , Fe , Sc , Co
2+ 3+ 3+ 3+
<INPUT TYPE=\ checkbox NAME= RS_825785_2_0_828900 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect Fe <INPUT TYPE=\ checkbox NAME= RS_825785_2_0_828900 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Co <INPUT TYPE=\ checkbox NAME= RS_825785_2_0_828900 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect Fe <INPUT TYPE=\ checkbox NAME= RS_825785_2_0_828900 VALUE= 3 CHECKED> MACROBUTTON HTMLDirect Sc (b) Tl , Te , Cr
+ 2 3+ 3+ 3+ 2+
3+
<INPUT TYPE=\ checkbox NAME= RS_825785_2_1_828900 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect Cr <INPUT TYPE=\ checkbox NAME= RS_825785_2_1_828900 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Tl <INPUT TYPE=\ checkbox NAME= RS_825785_2_1_828900 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect Te
4+ 4+ 2 + 3+
(c) Pu , Ce , Ti
4+
<INPUT TYPE=\ checkbox NAME= RS_825785_2_2_828900 VALUE= 0
DISABLED> MACROBUTTON HTMLDirect Pu <INPUT TYPE=\ checkbox NAME= RS_825785_2_2_828900 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect Ti <INPUT TYPE=\ checkbox NAME= RS_825785_2_2_828900 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect Ce
2+ 2+ 4+ 4+
4+
(d) Ba , Pt , Mn
2+
<INPUT TYPE=\ checkbox NAME= RS_825785_2_3_828900 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect Ba <INPUT TYPE=\ checkbox NAME= RS_825785_2_3_828900 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Pt <INPUT TYPE=\ checkbox NAME= RS_825785_2_3_828900 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect Mn
2+ 2+ 2+
4.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.026.
Which compound in each of the following pairs of ionic substances has the most exothermic lattice energy? Justify your answers. (a) compound <INPUT TYPE=\ radio NAME= RC_825642_3_0_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect LiF <INPUT TYPE=\ radio NAME= RC_825642_3_0_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect CsF justification <INPUT TYPE=\ radio NAME= (b) compound <INPUT TYPE=\ radio NAME= RC_825642_3_2_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect NaBr<INPUT TYPE=\ radio NAME= RC_825642_3_2_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect NaI justification <INPUT TYPE=\ radio NAME=
RC_825642_3_1_828757 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect Cation is larger.<INPUT TYPE=\ radio NAME= RC_825642_3_1_828757 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect Cation is smaller.
RC_825642_3_3_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect Anion is smaller.<INPUT TYPE=\ radio NAME= RC_825642_3_3_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Anion is larger.
(c) compound <INPUT TYPE=\ radio NAME= RC_825642_3_4_828757 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect BaCl2<INPUT TYPE=\ radio NAME= RC_825642_3_4_828757 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect BaO justification <INPUT TYPE=\ radio NAME= RC_825642_3_5_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect Anion has greater charge.<INPUT
(d) compound <INPUT TYPE=\ radio NAME= RC_825642_3_6_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect CaSO4<INPUT TYPE=\ radio NAME= RC_825642_3_6_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Na2 SO4 justification <INPUT TYPE=\ radio NAME= RC_825642_3_7_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect Cation has greater charge.<INPUT TYPE=\ radio NAME=
TYPE=\ radio NAME= RC_825642_3_5_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Anion has smaller charge.
RC_825642_3_7_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Cation has smaller charge.
(e) compound <INPUT TYPE=\ radio NAME= RC_825642_3_8_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect K2 O<INPUT TYPE=\ radio NAME= RC_825642_3_8_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect KF justification <INPUT TYPE=\ radio NAME= RC_825642_3_9_828757 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect Anion has greater charge.<INPUT TYPE=\ radio NAME= RC_825642_3_9_828757 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect Anion has smaller charge.
f) compound <INPUT TYPE=\ radio NAME= RC_825642_3_10_828757 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect Na2 S<INPUT TYPE=\ radio NAME= RC_825642_3_10_828757 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect Li2 O justification <INPUT TYPE=\ radio NAME= RC_825642_3_11_828757 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect Ions are larger.<INPUT TYPE=\ radio NAME= RC_825642_3_11_828757 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect Ions are smaller.
5.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.030.
Use the following data to estimate Hf for magnesium fluoride. Mg(s) + F2(g) lattice energy first ionization energy of Mg second ionization energy of Mg electron affinity of F bond energy of F2 enthalpy of sublimation of Mg 1129 kJ/mol MgF2(s) 2957 kJ/mol 735 kJ/mol 1445 kJ/mol 328 kJ/mol 154 kJ/mol 150. kJ/mol
6.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.040.
Use bond energies to predict H for the combustion of ethanol. C2H5OH(l) + 3 O2(g) H = 1276 kJ 2 CO2(g) + 3 H2O(g)
7.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.068.
Order the following species with respect to carbonoxygen bond length (longest to shortest). (CH3OH exists as H3C--OH. Use the appropriate <, =, or > symbol to separate substances in the list.) CO, CO2, CO3 , CH3OH chemPad Help
2
CH3OH > CO
2 3
> CO2 > CO <INPUT TYPE=\ text NAME= RB_1208434_6_0_1211549 VALUE= CH_3OH > CO_3^2 > CO_2 > CO DISABLED> MACROBUTTON HTMLDirect Correct. What is the order from the weakest to the strongest carbonoxygen bond? chemPad Help
CH3OH < CO
2 3
< CO2 < CO <INPUT TYPE=\ text NAME= RB_1208434_6_1_1211549 VALUE= CH_3OH < CO_3^2 < CO_2 < CO DISABLED> MACROBUTTON HTMLDirect Correct.
8.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.052.
Select a Lewis structure that obeys the octet rule for each of the following molecules and ions. In each case the first atom listed is the central atom. (a) NF3 <INPUT TYPE=\ <INPUT <INPUT TYPE=\ <INPUT TYPE=\
radio NAME= RC_826054_7_0 _829169 VALUE= 0 DISABLED> MACROBUTTO N HTMLDirect
TYPE=\ radio NAME= RC_826054_7_ 0_829169 VALUE= 1 CHECKED> MACROBUTTO N HTMLDirect
radio NAME= RC_826054_7_ 0_829169 VALUE= 2 DISABLED> MACROBUTTO N HTMLDirect
radio NAME= RC_826054_7_0 _829169 VALUE= 3 DISABLED> MACROBUTTO N HTMLDirect
(b) SO4
2
<INPUT TYPE=\ radio NAME= RC_826054_7_1_8 29169 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect
<INPUT TYPE=\ radio NAME= RC_826054_7_1_8 29169 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect
<INPUT TYPE=\ radio NAME= RC_826054_ 7_1_829169 VALUE= 2 DISABLED> MACROBUT TON HTMLDirect
<INPUT TYPE=\ radio NAME= RC_826054_ 7_1_829169 VALUE= 3 DISABLED> MACROBUT TON HTMLDirect
(c) ClO3 <INPUT TYPE=\ radio NAME= RC_826054_7 _2_829169 VALUE= 0 DISABLED> MACROBUTT ON HTMLDirect <INPUT TYPE=\ radio NAME= RC_826054_ 7_2_829169 VALUE= 1 DISABLED> MACROBUTT ON HTMLDirect <INPUT TYPE=\ radio NAME= RC_826054_7_2_ 829169 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect
<INPUT TYPE=\ radio NAME= RC_826054_7_2_ 829169 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect
<INPUT TYPE=\ submit VALUE= Practice Another Version NAME= Practice7 > MACROBUTTON HTMLDirect
9.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.076.
Predict the molecular structure (including bond angles) for each of the following. shape (a) SeO3 <INPUT TYPE=\ radio NAME= RC_825826_8_0_828941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect linear<INPUT TYPE=\ radio bond angle <INPUT TYPE=\ radio NAME= RC_825826_8_1_82 8941 VALUE= 0 DISABLED>
NAME= RC_825826_8_0_828941 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect square planar <INPUT TYPE=\ radio NAME= RC_825826_8_0_828941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect tetrahedral<INPUT TYPE=\ radio NAME= RC_825826_8_0_828941 VALUE= 3 CHECKED> MACROBUTTON HTMLDirect trigonal planar<INPUT TYPE=\ radio NAME= RC_825826_8_0_828941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect trigonal pyramidal<INPUT TYPE=\ radio NAME= RC_825826_8_0_828941 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect Vshaped
MACROBUTTON HTMLDirect 90<INP UT TYPE=\ radio NAME= RC_825826_8_1_82 8941 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect < 109.5 <INPUT TYPE=\ radio NAME= RC_825826_8_1_82 8941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect 109.5<I NPUT TYPE=\ radio NAME= RC_825826_8_1_82 8941 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect < 120<INPUT TYPE=\ radio NAME= RC_825826_8_1_82 8941 VALUE= 4 CHECKED> MACROBUTTON HTMLDirect 120<IN PUT TYPE=\ radio NAME=
RC_825826_8_1_82 8941 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect 180 (b) SeO2 <INPUT TYPE=\ radio NAME= RC_825826_8_2_828941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect linear<INPUT TYPE=\ radio NAME= RC_825826_8_2_828941 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect square planar <INPUT TYPE=\ radio NAME= RC_825826_8_2_828941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect tetrahedral<INPUT TYPE=\ radio NAME= RC_825826_8_2_828941 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect trigonal planar<INPUT TYPE=\ radio NAME= RC_825826_8_2_828941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect trigonal pyramidal<INPUT TYPE=\ radio NAME= RC_825826_8_2_828941 <INPUT TYPE=\ radio NAME= RC_825826_8_3_82 8941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect 90<INP UT TYPE=\ radio NAME= RC_825826_8_3_82 8941 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect < 109.5 <INPUT TYPE=\ radio NAME= RC_825826_8_3_82 8941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect 109.5<I NPUT TYPE=\ radio NAME= RC_825826_8_3_82 8941 VALUE= 3 CHECKED> MACROBUTTON
VALUE= 5 CHECKED> MACROBUTTON HTMLDirect Vshaped
HTMLDirect < 120<INPUT TYPE=\ radio NAME= RC_825826_8_3_82 8941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect 120<IN PUT TYPE=\ radio NAME= RC_825826_8_3_82 8941 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect 180 <INPUT TYPE=\ radio NAME= RC_825826_8_5_82 8941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect 90<INP UT TYPE=\ radio NAME= RC_825826_8_5_82 8941 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect < 109.5 <INPUT TYPE=\ radio NAME= RC_825826_8_5_82
(c) PCl3
<INPUT TYPE=\ radio NAME= RC_825826_8_4_828941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect linear<INPUT TYPE=\ radio NAME= RC_825826_8_4_828941 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect square planar <INPUT TYPE=\ radio NAME= RC_825826_8_4_828941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect tetrahedral<INPUT TYPE=\ radio NAME= RC_825826_8_4_828941
VALUE= 3 DISABLED> MACROBUTTON HTMLDirect trigonal planar<INPUT TYPE=\ radio NAME= RC_825826_8_4_828941 VALUE= 4 CHECKED> MACROBUTTON HTMLDirect trigonal pyramidal<INPUT TYPE=\ radio NAME= RC_825826_8_4_828941 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect Vshaped
8941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect 109.5<I NPUT TYPE=\ radio NAME= RC_825826_8_5_82 8941 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect < 120<INPUT TYPE=\ radio NAME= RC_825826_8_5_82 8941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect 120<IN PUT TYPE=\ radio NAME= RC_825826_8_5_82 8941 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect 180 <INPUT TYPE=\ radio NAME= RC_825826_8_7_82 8941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect 90<INP
(d) SCl2
<INPUT TYPE=\ radio NAME= RC_825826_8_6_828941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect linear<INPUT TYPE=\ radio NAME= RC_825826_8_6_828941
VALUE= 1 DISABLED> MACROBUTTON HTMLDirect square planar <INPUT TYPE=\ radio NAME= RC_825826_8_6_828941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect tetrahedral<INPUT TYPE=\ radio NAME= RC_825826_8_6_828941 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect trigonal planar<INPUT TYPE=\ radio NAME= RC_825826_8_6_828941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect trigonal pyramidal<INPUT TYPE=\ radio NAME= RC_825826_8_6_828941 VALUE= 5 CHECKED> MACROBUTTON HTMLDirect Vshaped
UT TYPE=\ radio NAME= RC_825826_8_7_82 8941 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect < 109.5 <INPUT TYPE=\ radio NAME= RC_825826_8_7_82 8941 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect 109.5<I NPUT TYPE=\ radio NAME= RC_825826_8_7_82 8941 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect < 120<INPUT TYPE=\ radio NAME= RC_825826_8_7_82 8941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect 120<IN PUT TYPE=\ radio NAME= RC_825826_8_7_82 8941 VALUE= 5
DISABLED> MACROBUTTON HTMLDirect 180 (e) SiF4 <INPUT TYPE=\ radio NAME= RC_825826_8_8_828941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect linear<INPUT TYPE=\ radio NAME= RC_825826_8_8_828941 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect square planar <INPUT TYPE=\ radio NAME= RC_825826_8_8_828941 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect tetrahedral<INPUT TYPE=\ radio NAME= RC_825826_8_8_828941 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect trigonal planar<INPUT TYPE=\ radio NAME= RC_825826_8_8_828941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect trigonal pyramidal<INPUT TYPE=\ radio NAME= RC_825826_8_8_828941 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect <INPUT TYPE=\ radio NAME= RC_825826_8_9_82 8941 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect 90<INP UT TYPE=\ radio NAME= RC_825826_8_9_82 8941 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect < 109.5 <INPUT TYPE=\ radio NAME= RC_825826_8_9_82 8941 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect 109.5<I NPUT TYPE=\ radio NAME= RC_825826_8_9_82 8941 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect < 120<INPUT TYPE=\
Vshaped
radio NAME= RC_825826_8_9_82 8941 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect 120<IN PUT TYPE=\ radio NAME= RC_825826_8_9_82 8941 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect 180
10.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.080.
Predict the molecular structure and the bond angles for each of the following.
(a) XeCl4 molecular structure <INPUT TYPE=\ radio NAME= RC_826156_9_0_8 29271 VALUE= 0 DISABLED> MACROBUTTON
(b) SeCl6 molecular structure <INPUT TYPE=\ radio NAME= RC_826156_9_2_8 29271 VALUE= 0 DISABLED> MACROBUTTON
(c) PF5 molecular structure <INPUT TYPE=\ radio NAME= RC_826156_9_4_8 29271 VALUE= 0 DISABLED> MACROBUTTON
HTMLDirect linear<I NPUT TYPE=\ radio NAME= RC_826156_9_0_8 29271 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect octahedral <INPU T TYPE=\ radio NAME= RC_826156_9_0_8 29271 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect see saw<INPUT TYPE=\ radio NAME= RC_826156_9_0_8 29271 VALUE= 3 CHECKED> MACROBUTTON HTMLDirect square planar<INPUT TYPE=\ radio NAME= RC_826156_9_0_8 29271 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect square
HTMLDirect linear<I NPUT TYPE=\ radio NAME= RC_826156_9_2_8 29271 VALUE= 1 CHECKED> MACROBUTTON HTMLDirect octahedral <INPU T TYPE=\ radio NAME= RC_826156_9_2_8 29271 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect see saw<INPUT TYPE=\ radio NAME= RC_826156_9_2_8 29271 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect square planar<INPUT TYPE=\ radio NAME= RC_826156_9_2_8 29271 VALUE= 4 DISABLED> MACROBUTTON
HTMLDirect linear<I NPUT TYPE=\ radio NAME= RC_826156_9_4_8 29271 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect octahedral <INPU T TYPE=\ radio NAME= RC_826156_9_4_8 29271 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect see saw<INPUT TYPE=\ radio NAME= RC_826156_9_4_8 29271 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect square planar<INPUT TYPE=\ radio NAME= RC_826156_9_4_8 29271 VALUE= 4 DISABLED> MACROBUTTON HTMLDirect square
pyramid<INPUT TYPE=\ radio NAME= RC_826156_9_0_8 29271 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect trigonal bipyramid<INPUT TYPE=\ radio NAME= RC_826156_9_0_8 29271 VALUE= 6 DISABLED> MACROBUTTON HTMLDirect T shaped bond angles (Select all that apply.) <INPUT TYPE=\ checkbox NAME= RS_826156_9_1_8 29271 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect 90<IN PUT TYPE=\ checkbox NAME= RS_826156_9_1_8 29271 VALUE= 1 DISABLED>
HTMLDirect square pyramid<INPUT TYPE=\ radio NAME= RC_826156_9_2_8 29271 VALUE= 5 DISABLED> MACROBUTTON HTMLDirect trigonal bipyramid<INPUT TYPE=\ radio NAME= RC_826156_9_2_8 29271 VALUE= 6 DISABLED> MACROBUTTON HTMLDirect T shaped bond angles <INPUT TYPE=\ checkbox NAME= RS_826156_9_3_8 29271 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect 90<IN PUT TYPE=\ checkbox NAME= RS_826156_9_3_8 29271 VALUE= 1 DISABLED>
pyramid<INPUT TYPE=\ radio NAME= RC_826156_9_4_8 29271 VALUE= 5 CHECKED> MACROBUTTON HTMLDirect trigonal bipyramid<INPUT TYPE=\ radio NAME= RC_826156_9_4_8 29271 VALUE= 6 DISABLED> MACROBUTTON HTMLDirect T shaped bond angles <INPUT TYPE=\ checkbox NAME= RS_826156_9_5_8 29271 VALUE= 0 CHECKED> MACROBUTTON HTMLDirect 90<IN PUT TYPE=\ checkbox NAME= RS_826156_9_5_8 29271 VALUE= 1 DISABLED> MACROBUTTON
MACROBUTTON HTMLDirect 109.5 <INPUT TYPE=\ checkbox NAME= RS_826156_9_1_8 29271 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect 120<I NPUT TYPE=\ checkbox NAME= RS_826156_9_1_8 29271 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect 180
MACROBUTTON HTMLDirect 109.5 <INPUT TYPE=\ checkbox NAME= RS_826156_9_3_8 29271 VALUE= 2 DISABLED> MACROBUTTON HTMLDirect 120<I NPUT TYPE=\ checkbox NAME= RS_826156_9_3_8 29271 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect 180
HTMLDirect 109.5 <INPUT TYPE=\ checkbox NAME= RS_826156_9_5_8 29271 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect 120<I NPUT TYPE=\ checkbox NAME= RS_826156_9_5_8 29271 VALUE= 3 DISABLED> MACROBUTTON HTMLDirect 180
<INPUT TYPE=\ submit VALUE= Practice Another Version NAME= Practice9 > MACROBUTTON HTMLDirect
11.4.16/4.16 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.082.
Which of the following molecules have net dipole moments (are polar)? (Select all that apply.) <INPUT TYPE=\ checkbox NAME= RS_864026_10_0_867141 VALUE= 0 DISABLED> MACROBUTTON HTMLDirect SeCl6<INPUT TYPE=\ checkbox NAME= RS_864026_10_0_867141 VALUE= 1 DISABLED> MACROBUTTON HTMLDirect PCl5<INPUT TYPE=\ checkbox NAME= RS_864026_10_0_867141 VALUE= 2 CHECKED> MACROBUTTON HTMLDirect ICl3<INPUT TYPE=\ checkbox NAME= RS_864026_10_0_867141 VALUE= 3 CHECKED> MACROBUTTON
HTMLDirect ICl5 <INPUT TYPE=\ submit VALUE= Practice Another Version NAME= Practice10 > MACROBUTTON HTMLDirect
12.4.24/4.24 pointsAll Submissions NotesQuestion: ZumChemP6 13.E.090.
Which of the following molecules have dipole moments? (Select all that apply.) (a) CHCl3 CH2Cl2 CCl4 (b) N2O CO2 (c) PH3 NH3
For the molecules that are polar, indicate the polarity of each bond and the direction of the net dipole moment of the molecule. (Do this on paper. Your instructor may ask you to turn in this work.)