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PRS questions for second exam

Course: BIO 301, Spring 2012
School: Cincinnati
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reaction 2/20/2012 A can run in a cell in spite of a positive G if 1. The substrate is added to high levels 2. The product is taken away 3. Either of the above 4. Neither of the above Glycolysis requires ATP 1. True 2. False 60% 94% 20% 16% 5% he .. . .. . 1. True 2. False 89% Fa l Tr ue Ne i Oxidation of glucose via glycolysis requires molecular oxygen se of t th e th er of er Eit h Th e Th...

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reaction 2/20/2012 A can run in a cell in spite of a positive G if 1. The substrate is added to high levels 2. The product is taken away 3. Either of the above 4. Neither of the above Glycolysis requires ATP 1. True 2. False 60% 94% 20% 16% 5% he .. . .. . 1. True 2. False 89% Fa l Tr ue Ne i Oxidation of glucose via glycolysis requires molecular oxygen se of t th e th er of er Eit h Th e Th e pr o du c su bs tra ti te s.. . .. . 6% Which molecule has less internal energy? 1. Methane 2. Carbon dioxide 60% 40% If the cell has a lot of ATP, the first step of glycolysis is shut down. 1. Yes 2. No 87% e ox id di bo n Ca r se Fa l Tr ue M et ha ne 11% At high ATP concentrations, phosphofructokinase is 1. actively producing fructose 1,6bisphosphate 2. not producing fructose 1,6bisphosphate 85% 15% .. in g. pr od uc no t ac t iv el No Ye s yp ro du . .. 13% 1 2/20/2012 Which site of phosphofructokinase has higher affinity for ATP? 1. Catalytic site 2. Regulatory site 61% Which is the oxidized form? 1. NAD+ 2. NADH 92% 39% The process of fermentation results in Reduction of NAD+ Reduction of NADH Oxidation of NAD+ Oxidation of NADH 67% 10% In the enzyme phosphofructokinase, the regulatory ATP site has a higher Km than the ATP catalytic site 99% rti a Te Se co nd a ry ry of N. .. da t io n da t Ox i 33% 8% io n of N. .. ... of N n tio Re du c tio n of N ... 8% Hydrolysis of the phosphate from PEP provides sufficient energy to make ATP from ADP 100% 1. True 2. False 0% se se Fa l Tr ue 1% Fa l 1. True 2. False Tr ue Re du c 1. Primary 2. Secondary 3. Tertiary Pr im ar y 15% Which aspect of protein structure would be most significantly affected by phosphorylation 58% Ox i 1. 2. 3. 4. NA DH NA D+ Re gu l Ca t aly at or tic ys it . .. sit e 8% 2 2/20/2012 The same enzymes are used for gylcolysis and gluconeogenesis in all but three steps. 99% In a FRAP experiment, the following results were seen. The two samples represented cells with different amounts of cholesterol, both at 37C. Which sample had more cholesterol? 85% 1. True 2. False Which of the following is not amphipathic? e# pl in in e in e 1. They are high in cholesterol 2. They are high in sphingolipids 3. They are wider than the standard membrane 4. They are detergent insoluble 3% 5. All of the above are true Ar g 61% 22% 11% e ar tru e re he ab ov ea ns ol . .. er ge n ti an w e ar de t id er th sp h in h Th ey of t go l.. . th e. .. 2% in es te ch ol in h hi g hi g e re ar Th ey se Fa l m Gl ut a Which if the following is not true of lipid rafts ro l 15% 3% Al l 85% Tr ue 1. True 2. False 8% Th ey ip id nt go l id ge Sp hi n De te r id e er Ph os ph ol ip lyc Tr ig At 37C cholesterol reduces membrane fluidity 17% c in e 9% 3% Lysine Leucine Glutamine Arginine Le u 16% 1. 2. 3. 4. e 72% Ly sin Triglyceride Phospholipid Detergent Sphingolipid Integral proteins have transmembrane helices which interact with the phosphilipids. Which of the following amino acids is likely to be in such helices 72% Th ey a 1. 2. 3. 4. Sa m Sa m Fa l Tr ue se pl e# 1 1% 2 15% 1. Sample #1 2. Sample #2 3 2/20/2012 Integral proteins may cross the bilayer multiple times 1. True 2. False Interactions between membrane proteins and networks can often be disrupted by changing salt concentration. What is most likely being distupted here? 97% 99% 1. 2. 3. 4. Covalent linkages Ionic linkages Hydrogen bonding Hydrophobic interactions 1% 1% 1% Which of the following can influence protein mobility in a membrane? 95% Temperature Cytoskeleton Extracellular matrix All of the above in .. . . Hy dr op ho bi c bo nd i.. n og e ... ly c ive ne ga t Fa l se 3% Tr ue se A iv po sit A 97% 8% Fa l Hy dr ol e lm ut ra ne A Water enters the cell if the cell is placed in a hypotonic solution 1. True 2. False 92% Tr ue el yc . .. ... ab ov e m at r ix ll o A hypotonic solution has a lower solute concentration than the cell 1. True 2. False 23% 12% ft he le to n la r ke llu yt os 1% 0% tr ac e 1. A neutral molecule 2. A positively charged ion 3. A negatively charged ion Ex C Te m pe ra tu re 4% If the [internal]/[external] is the same, the G for __________ will be the most negative 65% A 1. 2. 3. 4. Io ni c Co va l Fa ls e Tr ue en tl lin ka g in ka ... es 2% 4 2/20/2012 Looking at an enzyme activity, we see a Vmax because 1. Substrate is limiting 2. Enzyme is limiting (turnover number) 87% The internal concentration of glucose in a red blood cell is always lower than the blood concentration (hint: red blood cells have the glycolytic enzymes) 1. True 2. False 13% 0% 10 se Fa l Tr ue En zy m e Su bs tra is te is lim l.. . i. . . 0% Countdown A scientist makes a preparation of red blood cell ghosts resealed with 1mM glucose inside. These are put into a solution of 1mM glucose. Which way will the glucose go? 1. From outside in 2. From inside out 18% t ou ls e Tr ue Fr om in s 10 Fa id e id e ou ts Fr om 82% 1. True 2. False 0% in 0% Given the same concentration gradient, an anion would have a more negative DG than a neutral molecule Countdown All eukaryotic cells have aquaporins 1. True 2. False 93% When an acetylcholine receptor opens 1. Sodium ions rush into the cell 2. Sodium ions rush out of the cell 72% 28% ru ... ns io m So di u m So di u ls e Fa Tr ue io ns ru ... 7% 5 2/20/2012 When a voltage gated potassium channel opens 1. Potassium ions rush into the cell 2. Potassium ions rush out of the cell 88% The internal concentration of glucose in a red blood cell is always lower than the blood concentration (hint: red 69% blood cells have the glycolytic enzymes) 31% 1. True 2. False ns ... io The immediate source of energy for glucose transport into intestinal cells is ATP 78% 1. True 2. False 18% ou t in 22% Blocking ATP production can block glucose uptake into intestinal cells se Fa l Fr om Tr ue in s id e id e ou ts Fr om Fa l Tr ue A scientist makes a preparation of red blood cell ghosts ( no glycolytic enzymes left) resealed with 1mM glucose inside. These are put into a solution of 82% 1mM glucose. Which way will the glucose go? 1. From outside in 2. From inside out se siu m Po ta s Po ta s siu m io ns ... 12% In the Na,K ATPase cycle, the protein is open ___________ as a result of :10 phosphorylation. 50% 51% 50% 1. To the inside 2. To the outside 1. True 2. False th e To To se Fa l Tr ue th e in s ou ts id e id e 49% 6 2/20/2012 Inhibiting ATP synthesis directly inhibits glucose uptake from the intestinal lumen10 50% 1. True 2. False 50% Inhibiting ATP production eventually blocks glucose uptake from the lumenal side of 10 50% 50% the intestine If the internal concentration were to go down from 140mM to 50 mM (external stays the same), what would 50% 50% happen to the membrane potential? Fa ls e Tr ue Fa ls e Tr ue 1. False The True 2. resting membrane potential is closer to 1. Sodium equilibrium potential 2. Potassium equilibrium potential 50% 50% . siu m eq ui m Po ta s 50% ch an siu m Po ta s 0 of 5 m ch a nn el ... 50% So di u Po ta s siu m ch an nn el ch a m 10 :10 The acetylcholine receptor is a ligand activated _______ 1. Sodium channel 2. Potassium channel 50% ... 50% So di u 0 of 5 So di u :10 The acetylcholine receptor is a ligand activated _______ 1. Sodium channel 2. Potassium channel eq ui .. lib .. . be co m . .. ou ld It w It w ou ld be co m . .. 1. It would become more negative 2. It would become less negative 10 7 2/20/2012 Inhibition of the sodium-potassium ATPase results in 1. The potassium equilibrium potential 2. The sodium equilibrium potential 82% eq u. .. m ... of e In 1. Oxidized 2. Reduced 86% 14% ed Re du c d di ze Ox i Tr an sp or t er m e. .. iff us i.. . ed m em br an ito ch M NAD+ is _________ to produce NADH 6% pl so di u yt op la s 94% Sim lm at rix 8% C ... Pr io rh yp er po l. . Pr . io rd ep ola r i. Tw .. o of th e ab o. .. What is the most likely means of getting pyruvate into a mitochondrion? 1. Simple diffusion 2. Transporter mediated process 20% ne r 1% 0% 71% 1. Cytoplasm 2. Mitochondrial matrix 3. Inner membrane of the mitochondrion m 5% Where in a eukaryotic cell are the glycolytic enzymes located? fv ol ag . .. olt ng o ng v ni Op en i Op e 68% Th e Th e De cr e po t as ed as siu Ca + m +. .. ... ++ Ca se d ea In cr The depolarization phase of the action potential is based on 1. Opening voltage gated sodium channels 2. Opening of voltage gated potassium channels 3. Prior hyperpolarization due to 26% AchReceptors 4. Prior depolarization based on AchReceptors 5. Two of the above 5% . .. 18% 95% on dr ia 1. Increased Ca++ in cardiac cells 2. Decreased Ca++ in cardiac cells During an action potential, the membrane potential approaches 8 2/20/2012 During glycolysis, when NAD+ is converted to NADH, NAD+ is acting as Which side has the lower pH? ... ge ga ng in izi re du c ox id 0 of 5 10 A Th e in te rm 10 Countdown In the process of glucose oxidation, CO2 is produced in the cytoplasm 1. True 2. False 50% a. .. 50% br ... em m Th e 0 of 5 1. An oxidizing agent 2. A reducing agent 50% at r ix 50% An 1. The matrix 2. The intermembrane space Countdown Conversion of pyruvate to acetyl CoA releases CO2 1. True 2. False 77% 99% 23% During the Krebs cycle CO2 is produced NAD+ is produced H2O is produced Acetyl CoA is produced 5. Two of the above are correct se Fa l Tr ue Fa l Tr ue se 1% Which side has the lower pH? 1. 2. 3. 4. 81% 1. The matrix 2. The intermembrane space 73% 27% 15% 2% rm em br ... at r ix in te Th e m Th e is pr od uc e. .. Ac et yl Co A is Tw .. . o of th e ab o. .. 1% . H2 O od uc .. pr is is CO 2 NA D+ pr od u ce ... 1% 9 2/20/2012 During glycolysis, when NAD+ is converted to NADH, NAD+ is acting as 1. An oxidizing agent 2. A reducing agent Which is the strongest reducing agent? 68% 80% 16% 11% 2 DH DH ge N FA A A N ... a. .. A An re du c ox id in izi ga ng D 5% D+ 20% NAD+ NADH FAD FADH2 FA 1. 2. 3. 4. Which is the strongest oxidizing agent? The more negative the redox potential, the stronger the reducing agent 65% 1. True 2. False Pyruvate Lactate Oxygen Water 21% 16% 11% r ls e n. .. 11% M ot e m ic a he em br an e lp po te ... e te rm em br an In at rix 38% 89% 1. Membrane potential aspect of PMF 2. Chemical potential aspect of PMF C 1. Matrix 2. Intermembrane space Using a chloride ionophore disrupts the n. .. 62% Fa W As a result of electron transport, one side of the membrane has a pH of 7 and the other 8. Which side is pH 8? M Tr ue at e ge n O La ru v Py xy ct at e 2% at e 1. 2. 3. 4. 84% 10 2/20/2012 13% . a. NADH FADH2 Pyruvate Two of the above All of the above An sw er s1 an d . .. NA D+ 43% 7% 1% id e 0% in s id e 60% 1. O 2. L 3. T e he of t Al l of t o Tw In what conformation of the ATP synthase is ATP actually made from ADP and Pi? ab ov e at e ab ov Py ru v he FA DH 2 NA DH pH pH 8 7 on on th e th e in s an d s1 er An sw Th e Th e H. . ,p 49% 1. 2. 3. 4. 5. 35% . .. 5% 2% Py ru v H+ c br a em m 24% An appropriate substrate for submitochondrial particles in this experiment would be Submitochondrial particles will make ATP if 65% an artificial pH gradient is established with 1. pH 8 on the inside, pH 7 on the outside 2. pH 7 on the inside and pH 8 on the outside Pyruvate NADH NAD+ Answers 1 and 2 Answers 1 and 3 on ce ne nt .. . p. .. 24% 1. 2. 3. 4. 5. at e 1. The membrane potential generated by electron transport 2. The H+ concentration gradient generated by electron transport Which of the following would work as a substrate for this experiment (isolated vesicles) 56% NA DH Pi uptake by occurs in the presence of a Cl- ionophore. That means that Pi uptake depends on 76% Moving electrons from H2O to NADP+ is a thermodynamically spontaneous process 86% 1. True 2. False 24% ls e Fa Tr ue T 14% L O 16% 11 2/20/2012 What would we see if RDG tripeptide is added to the experiment? 1. Cells would lyse 2. Cells would adhere normally 3. Cells would not adhere 93% Adherens junctions are like _____ because both connect to actin 1. hemidesmosomes 2. focal adhesions 77% 23% 4% re os om he m id fo ca la es m ls Ce l w ls Ce l Malate Dehydrogenase will be active in a broken mitochondrial preparation 1. True 2. False dh es io ns es no ta ou ld w ou ld Ce l ad ls he r w e ou ld no r dh e ... ly se 3% The tripeptide RGD plays a key role in binding fibronectin to integrin. This peptide is part of the sequence of 75% 71% 1. Integrin 2. Fibronectin 25% ne c Fib ro In te se Fa l th e o of es ab ov es e 1% Tw ju n ct io ct io ns ns s ct io n 1% A dh Ti er e ns gh t ju n ab o. .. he Al l of t o Tw of t he bu l glo m un o Im ab o. .. in . .. in s s tin he r Se le c Ca d 1% 1% D 5% ju n 6% 97% ap 27% Tight junctions Adherens junctions Gap junctions Desomsomes Two of the above G 1. 2. 3. 4. 5. 58% 6% Which of the following junctions use cadherins om so m Tr ue Which of the following attachments is heterophilic? 1. Selectins 2. Cadherins 3. Immunoglobulin super family 4. Two of the above 5. All of the above t in gr in 29% 12 2/20/2012 Which of the following interactions involve actin on the intracellular side of the membrane? 26% 27% Desomsomes Hemidesmosomes Adherens Junctions Focal adhesions Two of the above 23% 16% 1. True 2. False 7% e s io n ab ov es th e of Fa l se o Tw Tr ue ct io ns la dh ca Fo ns Ju n m os er e dh A es D em id es om so m es om es 14% H 1. 2. 3. 4. 5. Once a ribosome has made a protein through the membrane-bound route, it will continue to make only 86% membrane bound proteins 13
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University of Wisconsin-Madison - ENGLISH - 100
Arenson 1Haley ArensonSharon Yam- English 100On December 17th, 1903 was the first day that Orville Wright took the craft, that him andhis brother, Wilbur, designed, for a 12 second flight. By 1904 Wilbur Wright was able to fly forthe first time for m
University of Wisconsin-Madison - ENGLISH - 100
Haley ArensonDraft 1Sharon Yam- English 100Immigration is not something many Americans praise. Many think, why should we idolize aprocess that causes so much harm and hardship for not only the country but for all the people thatsuffer on their journe
University of Wisconsin-Madison - ENGLISH - 100
Draft 21Haley ArensonSharon Yam- English 100Immigration is not something many Americans praise. Many think, why should we idolize aprocess that causes so much harm and hardship for not only the country but for all the people thatsuffer on their jour
University of Wisconsin-Madison - ENGLISH - 100
Haley ArensonDraft 1Sharon Yam- English 100Immigration is not something many Americans praise. Many think, why should we idolize aprocess that causes so much harm and hardship for not only the country but for all the people thatsuffer on their journe
University of Wisconsin-Madison - ENGLISH - 100
Arenson 1Haley ArensonSharon YamEnglish 100The topic I have decided to write about is airport security in America. Id like to explore thepros and cons of the many security methods and the way in which it affects the customers, theemployees, and the