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University of Illinois, Urbana Champaign - PHYS - 560
Screening (Electron-Electron Interaction) Classical pictureEextClassical metal Ein 0The internal field is zero. Electrons are free to move; a layer of charge (screening charge) accumulates at the surface. The external field is screened. Quantum picture
University of Illinois, Urbana Champaign - PHYS - 560
Electron Dynamics (of Semiconductors) Basic assumption: independent electron approximation (single-particle picture) Question: what happens to an electron under an external field (transport properties)? Bloch state nk e ik r uk r p nk i nk e ik r p k uk
University of Illinois, Urbana Champaign - PHYS - 560
Lattice Waves Thus far, static lattice model. In reality, atoms vibrate even at T 0 because of zero-point vibration. Monatomic Crystals Basis = 1 atom.r R R u R;t Lattice: R ni aiii 1,2,3Actual atomic position = lattice position + vibrationu 0rave
University of Illinois, Urbana Champaign - PHYS - 560
Lattice Specific Heat Classical: Equi-partition theorem:1 1 1 kx x2 mvx 2 kT 2 2 26 degrees of freedom each atom 3 each from kinetic energy and potential energy. Internal energy/volume u Volume specific heat CV 33NkT ; N = total number of atoms (includ
University of Illinois, Urbana Champaign - PHYS - 560
Anharmonic Effects Assume one atom per unit cell. Potential energy U r R UR u R U U 0 harmonic potential u 2 O u 3 O u 4 Terms O u 3 , O u 4 anharmonic effects or phonon-phonon interactions uR 1 Nks2 M s (k )aks + a-ks e s (k )eik RO u 3 . a a a
University of Illinois, Urbana Champaign - PHYS - 560
Neutron Scattering Counts E E' E Spectrum at a fixed scattering geometry: elastic peak caused by defect scattering (or Bragg diffraction) one-phonon emission peaks at lower energies (Stokes peaks) one-phonon absorption peaks at higher energies (anti-Stoke
University of Illinois, Urbana Champaign - PHYS - 560
Infrared Properties (of Ionic Crystals) Assume the system is nonmagnetic, 1 . Optical properties determined by the dielectric function, D E. Assume cubic symmetry. D E Assume no free charges. D 0 DEP ik E 0 E ik E 4 ( = bound charge density) Longitudinal
University of Illinois, Urbana Champaign - PHYS - 560
Magnetism B H 4 M H M = magnetizationBi Bo Bournday conditions: B 0 4 1 D H j 0 , assuming steady state and no free current c c tH i H oFerromagnetic Paramagnetic DiamagneticM 0 for B a 0 (zero applied field); generally nonlinear BH ~ constant ~ 1 + O
University of Illinois, Urbana Champaign - PHYS - 560
Ferromagnetism A simple picture: ferromagnetism arises from "atomic magnets" aligned in the same direction. What is the interaction to align them? Each atomic magnetic has a magnetic moment ~ g0 B . Dipolar interaction energy between neighboring atomic ma
University of Illinois, Urbana Champaign - PHYS - 560
Crystallographic restriction theorem See: http:/en.wikipedia.org/wiki/Crystallographic_restriction_theorem Problem: Consider rotational symmetry operations of a 2D periodic lattice with the rotation axis perpendicular to the lattice plane. Show that only
University of Illinois, Urbana Champaign - PHYS - 560
Physics 560 Homework problem set 1 1. A&M Problem 1, Chapter 1. 2. A&M Problem 2, Chapter 1. 3. A&M Problem 3, Chapter 1. 4. Recall 1 i 4 , where is the conductivity derived from the valence electrons.This expression was derived assuming that the posit
Rutgers - FINANCE - 250
March 27, 2012 Leasing versus buying a car You build no equity You are still responsible for maintenance and damages You are charged extra for o Too many miles (over 12,000 miles) o Ending the lease early will charge a penalty Buying a car . would you tak
Rutgers - FINANCE - 250
Government Health Care Plans Medicare Provides health insurance to people over age 65 Part A covers inpatient care in hospitals or nursing facilities and some home health Part B is optional coverage Part C is a combination of Part A and Part B provide
Rutgers - FINANCE - 250
Chapter 12: Health and Disability Insurance Health Insurance Health insurance: a type of insurance offered by private insurance companies or the government that covers health care expenses incurred by policyholders for necessary medical care Critical comp
University of Texas - PHY - 102M
Question 14 out of 4 pointsRead the derivation for acceleration of the 2 objects in Atwood machine system in your manual. If we have m1=150g, m2=155g, what's the acceleration (m1 goes up and m2 goes down)? Answer Selected Answer: 0.161m/(s^2)Question
University of Texas - PHY - 102M
Question 13 out of 3 pointsLook at Fig. 4-1 in your manual, let's say PEtot is the total potential energy of masses m1 and m2 (m1<m2). After m1 goes up by a distance d, and m2 goes down the same distance. The change in PEtot is (when something goes up
University of Texas - PHY - 102M
Question 13 out of 3 pointsPick the right descriptions for inelastic collision Answer Selected Answers:Question 23 out of 3 pointsPick the right descriptions for completely elastic collision Answer Selected Answers:Question 33 out of 3 pointsIf m
University of Texas - PHY - 102M
Question 13 out of 3 pointsWhen considering rotational motion there are similarities between rotational motion and translational motion. Look at the table, answer question 1&2 Translational D (displacement) V (velocity) A (acceleration) F (force) P (mo
University of Texas - PHY - 102M
Question 13 out of 3 pointsWhat are the necessary conditions for objects in translational and rotational equilibrium? is torque on the object(s), F is the force on the object(s), v is the translational velocity of the object(s), and is the angular velo
University of Texas - PHY - 102M
Question 13 out of 3 pointsOn graph paper draw a vector from the origin of a graph 8 cm at 0 degrees from the x-axis. Now add a vector at 90 degrees and 6 cm long to the first vector. What is the length of the addition calculated? What is the direction
Columbia State Community College - FREN - 1200
MBG*2040 Foundations in Molecular Biology and GeneticsMock Midterm Exam Winter 2012 It is most beneficial to you to write this mock midterm UNDER EXAM CONDITIONS. This means: Complete the midterm in an hour and 15 minutes. Work on your own. Keep your not
Columbia State Community College - FREN - 1200
STAT*2040 TERM TEST II PRACTICE PACKAGEWinter 2012DISCLAIMERThis resource is not designed to be used independently of the SLG Session listed above. Please use this resource for referral only it is supplemental review and is not meant to be a substitute
Columbia State Community College - FREN - 1200
University of Ottawa - BIO - 3170
Bio 1540 ; questions de rvision : signalisation cellulaire8.1 Communication cellulaire1- Quelles sont les tapes de la signalisation cellulaire ? 1. rception 2.transduction 3. rponse 2- Quand est-ce que des molcules sont scrtes pour envoyer un message ce
University of Ottawa - BIO - 3170
Bio 1540 ; questions de rvision : signalisation cellulaire8.2 Rception cellulaire1- Classez en ordre en numrotant les tapes de la rception cellulaire : Entre des molcules (ex: ions) dans la cellule 4 Massager primaire circulant ou membranaire 1Changeme
University of Ottawa - BIO - 3170
Bio 1540 ; questions de rvision : Gnome I9.1 Structure des acides nucl iques 1- Le nucloside est compos d'un nuclotide et d'un groupement phosphate V ou F 2- Le groupement phosphate reprsente l'extrmit 5' et le groupement OH reprsente l'extrmit 3'. V ou
University of Ottawa - BIO - 3170
Cytosquelette II : Les muscles Une cellule d'un muscle est constitue d'un grand nombre de cellules embryonnaires fusionnes ensemble et a donc, plusieurs noyaux. Un muscle consiste de longues fibres qui sont chacun un assemblage de myofibrilles. Une myofib
University of Ottawa - BIO - 3170
Nom d'tudiant: Nicolas Charron Numro d'tudiant: 6390078 Nom et numro d'tudiant du partenaire: Katherine Noah 6377440 Nom du dmonstrateur: Sarah Ouanounou Date : 19 janvier 2012REMARQUE:Si l'information demande ci-dessus n'est pas CLAIRE ou n'est pas DON
University of Ottawa - BIO - 3170
Cher membre du jury, enseignent, parents, lve et amis Bonjours, comment mon optimiste m'aide surmonter mes obstacles, pour moi c'tait quand j'avais perdu mon chien aux Qubec. Sa toute commencer quand ont rapportait toute nous chose d'an dehors dans le cha
University of Ottawa - BIO - 3170
Fidle ou non!Il y a plusieurs roman et livre comme Harry-Potter qui sont fidles leur film, mais il y a aussi plusieurs romans et livre comme le voleur de foudre qui ne sont pas fidle a leur film ce qui m'amne a pos la question : Est-ce que la production
University of Ottawa - BIO - 3170
http:/aix1.uottawa.ca/~ybourg/mat1730/mat1730.html Argumentation-Editoriale PDV: engage - subjectif (perspective, opinion, jugement) phase argumentatif distancie- neutre, objective/ phase explicative Arg. : cause, consequence comparaison, autorite, valeur
University of Ottawa - BIO - 3170
29 fvrier 2011 Laboratoire # 3 : Rduction de la 3-nitroactophnoneIntroduction La raction quilibre de la raction du 3-nitroactophnone est prsente ci-contre : C8H7NO2 + NaBH4 + H2O + HCl H2 + NaCl + BH3 + C8H8NO2Le mcanisme simplifi de la raction d'oxydo-
University of Ottawa - BIO - 3170
tat de condensation des chromosomes lors de la la division cellulaire est maximal lors de la mitose ET MIOSE V ou F - j'avais oubli de spcifi seulement lors*Chromatine est une molcule monocatnaire d'ADN associe des protines V ou FDans le euchromatine le
University of Ottawa - BIO - 3170
tat de condensation des chromosomes lors de la la division cellulaire est maximal lors de la mitose V ou F Chromatine est une molcule monocatnaire d'ADN associe des protines V ou F Dans le euchromatine lequel de ces noncs est faux : Liaisons non-covalente
University of Ottawa - BIO - 3170
1. Pour sparer un mlange d'acide benzoque et du naphtalne, qui sont tous les deux insolubles dans l'eau, je ferai les tapes suivantes : - Ajouter le mlange dans une ampoule dcanter - Les deux composs sont organiques et vont tre solubles dans l'ther. (solu
University of Ottawa - ANP - 1105
Rapport de laboratoire Nicolas Charron (No 6390078) 1) Mise en situation : Bob est sous la douche 5 C pendant 2 heures Les donnes dmontrent que prendre une douche 5 C pendant deux heures peut causer une diminution de la frquence cardiaque, de 72 60 battem
University of Ottawa - ANP - 1105
Rapport de laboratoire Nicolas Charron (No 6390078) 1) Mise en situation : Bob est sous la douche 5 C pendant 2 heures Les donnes dmontrent que prendre une douche 5 C pendant deux heures peut causer une diminution de la frquence cardiaque, de 72 60 battem
University of Ottawa - ANP - 1105
Rapport de laboratoire Nicolas Charron (No 6390078) 1) Mise en situation : Bob est sous la douche 5 C pendant 2 heures Les donnes dmontrent que prendre une douche 5 C pendant deux heures peut causer une diminution de la frquence cardiaque, de 72 60 battem
University of Ottawa - ANP - 1105
ANP 1505APhysiologie cellulaire, et anatomie et physiologie des systmes cardiovasculaire, lymphatique et respiratoirePlan de cours: Automne 2011Tl.: 562-5800 x 8388ENSEIGNANTS: Michel DsiletsPavillon Guindon, local 3143 mdesilet@uottawa.caIrma Berna
University of Ottawa - ANP - 1105
Rle : Sang en contact troit avec les alvoles pour l'change gazeux. Elle ne sert pas directement en besoins mtaboliques pour les tissus pulmonaires. Tronc pulmonaire : contient le sang pauvre en oxygne et monte 8cm avant de se diviser dans l'artre pulmonai
University of Ottawa - ANP - 1105
Fonctions principales : Drainer le surplus de liquide interstitiel: le liquide interstitiel est rcupr par les vaisseaux lymphatiques et retourn au sang. Transporter les lipides alimentaires: les vaisseaux lymphatiques transportent jusque dans le sang les
University of Ottawa - ANP - 1105
1) En observant mon graphique je peux observer que la Kalmia augustifolia a t vue dans plus ou moins dans l'cotone et le plus observ dans la tourbire comparativement dans le champ, la fort et le marais qui semble avoir environ le mme nombre faible d'obser
University of Ottawa - ANP - 1105
Recombinaison:Populations sexues: miose (brassage gntique) variations propices l'adaptation. *pas source de variations, mcanisme du gnome (erreur du miose). Accouplement au hasard: panmixie (maintien H.W.); pas d'volution, rare chez les animaux, pas de ch
University of Ottawa - ANP - 1105
Cladogramme initial. Aucune rsolution La mchoire (caractre 1) et l'estomac (caractre 12) sont prsents chez toutes les espces excluant la lamproie connue sous l'acronyme GF. Les tissus squelettiques osseux (caractre 8) et les poumons/drivs (caractre 5) son
University of Ottawa - ANP - 1105
cologie: tude des organismes entre eux et entre l'environnement. Ils sont affects par les facteurs abiotiques (chimique, physique) et biotique (entre espce-prdations et proies = pression slectives). Les populations varient dpendant de l'environnement (kan
UGA - CLAS - 1020
TheogonyI. Hesiod A. C750 BC (Contemporary of Homer) B. Earliest extant greek literature C. Poetry D. Theogony D.1. = birth of the Gods D.2. Hesiod's goal: to impose order on a chaotic mass of inherited oral material regarding the pantheon (=all of the g
UGA - CLAS - 1020
Heroes and Heroic JourneysI. Hero = demigod A. Perseus B. Hercules C. Theseus D. Jason II. Heroic motifs A. Extraordinary birth and childhood B. Ambition: quest or journey B.1. Separation from ordinary reality into a region of supernatural forces B.2. Ka
UGA - CLAS - 1020
The Argonautica & MedeaI. Intro A. B. C. D. Group adventure Jason evolves as an antihero Late; eclectic List of stops on journey: D.1. Iolcus (Greece) D.2. Lemnos D.3. Cyzicus D.4. Cius Bebryces Phineus Symplegades Island of Ares Colchis Aea Sirens Scyll
UGA - CLAS - 1020
Trojan War (Troy Saga)I. Homer a. Circa 750 BC b. Illiad & Odyssey c. Contemporary with Hesiod d. Accepted by ancients as factual history e. Illiad tells only a small part of the Trojan War (CP 108109) f. Other poets describe other phases of the war, inc
Coast Guard Academy - CHEM - 222
ACS Review Spectroscopy1. Which of the following has only a single peak in its proton NMR spectrum?A. B. C. D. 2.only I only II I and II I, II, and IIIA compound is either cyclononane or cyclodecane. Which of the following is the most useful technique
Iowa State - STAT - 101
SECTION 15.2: Conservative Fields811Exercises 15.1In Exercises 18, sketch the given plane vector field and determine its field lines.11. v(x, y, z) = yi - xj + kxi + yj (1 + z 2 )(x 2 + y 2 ) 13. v(x, y, z) = x zi + yzj + xk1. F(x, y) = xi + xj 3. F
Iowa State - STAT - 101
916CHAPTER 17 Ordinary Differential Equations(a) Show that the solution of (B) remains between the solutions of (A) and (C) on any interval [0, X] where solutions of all three problems exist. Hint: We must have u(x) 1, y(x) 1, and v(x) 1 on [0, X]. (Why
Iowa State - STAT - 101
SECTION 16.3: Green's Theorem in the Plane8653 18.Suppose div F = 0 in a domain D any point P of which can by joined to the origin by a straight line segment in D. Let r = t xi + t yj + t zk, (0 t 1), be a parametrization of the line segment from the o
Iowa State - STAT - 101
SECTION 17.5: Linear Differential Equations with Constant Coefficients919Exercises 17.41. Show that y = e x is a solution of y - 3y + 2y = 0, andfind the general solution of this DE. y (x) 1 . y(x) = . , . yn (x) a (x)112. Show that y = e-2x is a so
Iowa State - STAT - 101
820CHAPTER 15 Vector Fields19. Show that the gradient of a function expressed in terms ofpolar coordinates in the plane is 1 ^ ^ r+ . r r (This is a repeat of Exercise 16 in Section 12.7.) (r, ) = ^ ^ 21. Show that F = r sin 2 r + r cos 2 is conservati
Iowa State - STAT - 101
824CHAPTER 15 Vector FieldsExercises 15.31. Show that the curve C given byr = a cos t sin t i + a sin2 t j + a cos t k, lies on a sphere centred at the origin. FindC12. Find the centroid of the curve in Exercise 11.(0 t z ds.3 14. 2 ), 3 13.Find
Iowa State - STAT - 101
SECTION 17.6: Nonhomogeneous Linear Equations923The corresponding powers x r can be expressed in real form in a manner similar to that used for constant coefficient equations; we have x i = e(i) ln x = e ln x cos( ln x) i sin( ln x) = x cos( ln x) i x s
Iowa State - STAT - 101
930CHAPTER 17 Ordinary Differential Equations17.7 Series Solutions of Differential EquationsIn Section 17.5 we developed a recipe for solving second-order, linear, homogeneous differential equations with constant coefficients: ay + by + cy = 0 and Eule
Iowa State - STAT - 101
Chapter 1414.1 Vector Fields14.1.1 14.1.2 A vector field describes the motion of the air as a vector at each point in the room.14.1.3At each point B C , the B-coordinate of the vector is given by 0 B C ; the C-coordinate by 1 B C .14.1.4 The gradient
Iowa State - STAT - 101
SECTION 16.5: Stokes's Theorem87516.5 Stokes's Theorem^ If we regard a region R in the x y-plane as a surface in 3-space with normal field N = k, the Green's Theorem formula can be written in the form C F dr =R^ curl F N d S.Stokes's Theorem given b
Iowa State - STAT - 101
832CHAPTER 15 Vector Fields23. Review Example 5 in Section 15.2 in which it was shown that y -y x 2 + y2 = x x x 2 + y2 ,the other. As in Example 5 of Section 15.2, it happens that = - x y i+ 2 j. x 2 + y2 x + y2for all (x, y) = (0, 0). Why does this