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Mohawk - COMP - EE367
Plot the transfer curve for VGS and ID when Vgs off = -2.7V and IDSS = 6.0 mA. . Draw the load line on the transfer characteristic curve. Label all important points on the curve and load line. Find the gain of this amplifier. VDD = 20 Vdc. R1= 4.7 M, R3 =
Mohawk - COMP - EE367
TLM access, Use a current version of internet explorer Use check browser settings to ensure the TLM will function properly. -WEB ADDRESShttp:/142.222.80.41/tlm40/ use student number without leading zeros as your user name and password to login.
Mohawk - EE - 367
Chapter 10 Amplifier Frequency ResponseObjectives Discuss frequency response of an amplifier Express the gain of an amplifier in decibels (dB) Analyze the frequency response of a BJT amplifier Analyze the frequency response of an FET amplifier Analyze t
Mohawk - EE - 367
Chapter 11 Thyristors And Other Devices Describe the basic structure and operation of the Shockley diode Describe the basic structure and operation of a silicon controlled rectifier and applications of an SCR Describe the basic operation of the SCS Descr
Mohawk - EE - 367
Chapter 8 Field Effect TransistorsObjectives Explain the operation and characteristics of junction field effect transistors (JFET). Understand JFET parameters Discuss and analyze how JFETs are biased Explain the operation and characteristics of metal ox
Mohawk - EE - 367
Chapter 9 FET AmplifiersObjectives Explain the operation and amplification properties of FET amplifiers Explain and analyze the operation of commonsource, commondrain, and commongate amplifiers Troubleshoot FET amplifiersIntroductionFET amplifiers are
Mohawk - EE - 367
FIGURE 12-1Op-amp symbols and packages.Thomas L. Floyd Electronic Devices, 6e and Electronic Devices: Electron Flow Version, 4eCopyright 2002 by Pearson Education, Inc. Upper Saddle River, New Jersey 07458 All rights reserved.FIGURE 12-2Basic op-amp
Mohawk - EE - 367
FIGURE 13-1The op-amp as a zero-level detector.Thomas L. Floyd Electronic Devices, 6e and Electronic Devices: Electron Flow Version, 4eCopyright 2002 by Pearson Education, Inc. Upper Saddle River, New Jersey 07458 All rights reserved.FIGURE 13-2Nonze
Mohawk - EE - 367
FIGURE 18-1 certain limits).Line regulation. A change in input (line) voltage does not significantly affect the output voltage of a regulator (withinThomas L. Floyd Electronic Devices, 6e and Electronic Devices: Electron Flow Version, 4eCopyright 2002
Mohawk - EE - 367
MOHAWK COLELGE OF APPLIED ARTS AND TECHNOLOGY Department of ElectrotechnologyA) IDENTIFICATION ITEMS EE362COURSE NAME COURSE CODE PROGRAM NAMEINTRODUCTION TO TELECOMMUNICATIONS LAB EE362 Computer Electronics Engineering Technology Electronics Engineeri
Mohawk - EE - 367
Course Outline 1.0 IDENTIFICATIONCOURSE INFORMATION Course Name Course Code Course Classification Course Type Program Code and Name Total Course Hours Credit Value Development School Department Academic Year Approving Associate Dean Electronic Circuit
Mohawk - EE - 369
EE 369 Industrial Automation Solutions to Delta problems from pg. 19 of lab manual1.a) 208Vb) 27.76Ac) Ignore2.a) 39.26Ab) 22.73Ac) 10kVAd) Ignore3.a) Ignoreb) 6.94Ac) 4.01A4.a) 9.36kVAb) 8.48kWc) 25.98Ad) 208V5.a) 600Vb) 33.3kVAc) 3
Mohawk - EE - 369
EE 369 Industrial Automation Solutions to WYE problems from pg. 18 of lab manual1.a) 433Vb) 13.3A2.a) 150Ab) 211.7Vc) 122.2Vd) 18.3kVA3.a) 8.4kVAb) 207.8Vc) 23.3Ad) 23.3A4.a) 137.2kVAb) 45.7kVAc) 120.7kWd) 180A5.a) 571.6Vb) 62.7Ac) 6
Mohawk - EE - 369
EE369 Industrial Automation Delta System ExamplesTHREE PHASE DELTA BALANCED LOADSPer phase impedance=50 80 Line voltage: 480 Volts Frequency: 60 Hz Phase sequence: ABC Reference is VBC Calculate phase currents, line currents, and total apparent power. a
Mohawk - EE - 369
EE369 Industrial Automation 3-phase Wye System basics THREE PHASE BALANCED Y-CIRCUIT Given loads: Phase (A)=25 0 Phase (B)=25 0 Phase (C)=25 0 Line voltage = 600 Volts Phase sequence: ABC Using VBC as the reference, calculate all the voltages and currents
Mohawk - EE - 369
EE369 Industrial Automation 3-Wire Edison Distribution Transformer Example Refer to the following diagram and calculate the currents I1, I2, I3 and In. Also determine the total secondary side (load) power.Solution: Vs1 = (208/2) / 4 = 26V Vs2 = (208/2) /
Mohawk - EE - 369
EE369 Industrial Automation Counters Practice Problems 1. Write a PLC program that controls three lights as follows: Pressing a N.O. pushbutton PB1 once turns L1 on and keeps it on Pressing PB1 twice turns L2 on and keeps it on Pressing PB1 three times tu
Mohawk - EE - 369
Mohawk College of Applied Arts and Technology Electrical and Computer Engineering Technology Department EE369 / 370 Industrial Automation T01 (Mon, Tue, Fri) This document shows the updated schedule for the lectures and the labs. The instructors shall att
Mohawk - EE - 369
EE369 Midterm 1 Practice Problem Solutions1. a) b)ZT = 220.2 -74.4 Assuming source voltage is 120V: Vr = 27.2 74.4 V Vc = 144.5 -15.6 V VL=29.4 154.4 V The voltage phasor diagram should be drawn as a closed loop to indicate KVLholds. 2. a) b) c) Ratio
Mohawk - EE - 369
EE369 Industrial Automation Quiz 11 PLC Applications Name: _ Date: _Develop a program that will display a 1 minute count-down sequence on a 2-digit 7segment LED display that is wired to an 8-point output card (O:003) when a N.O. pushbutton `Start' is pre
Mohawk - EE - 369
EE370 Industrial Automation Lab PLC Lab #2 This is a modification to the "Boiler System" problem in PLC lab #2 in the lab manual. Please follow this procedure instead of the one in the lab manual. 1 BOILER SYSTEM Hot water boiler systems commonly have saf
Mohawk - EE - 369
Create ladder logic to implement this project on the PLC5. A machine is used in an automotive plant to install tires onto rims to make finished wheels. The operation is as described below: An operator ensures that the correct style of rim and tire are in
Mohawk - EE - 369
Using the PLC5 system at your station, design the logic to solve the following problem: Access to a parking lot is to be controlled by a PLC. The parking lot can only hold 50 cars maximum. Agate at the entrance and another gate at the exit control the acc
Mohawk - EE - 369
Allen-Bradley1785 PLC-5 Programmable ControllersAddressing Reference ManualImportant User InformationBecause of the variety of uses for the products described in this publication, those responsible for the application and use of this control equipment
Mohawk - EE - 369
Allen BradleyClassic 1785 PLC 5 Family Programmable Controllers(Cat. No. 1785 series)Hardware Installation ManualImportant User InformationBecause of the variety of uses for the products described in this publication, those responsible for the applic
Mohawk - EE - 369
1785 PLC-5 Programmable Controllers Quick ReferenceStatus Bits. 3-1 Relay. 3-2 Timer . 3-5 Counter . 3-7 Compare . 3-9 Compute . 3-12 Logical . 3-22 Conversion . 3-24 Bit Modify and Move. 3-26 File . 3-28 Diagnostic . 3-30 Shift Register. 3-32 Sequencer
Mohawk - EE - 369
page 0FS = first scanT1 = ST2 AST1A T1C*B T3 T4 ST2 C+BST3T2 = ST1 B T3 = ST3 ( C B ) T4 = ST2 ( C + B ) ST1 = ( ST1 + T1 ) T2 + FS ST2 = ( ST2 + T2 + T3 ) T1 T4 ST3 = ( ST3 + T4 T1 ) T3BT2ST2A T1ST1Automating Manufacturing Systems T2C BBS
Mohawk - EE - 369
EE369 Industrial Automation PLC Practice Problems1. Develop a 24-hour digital clock that keeps track of hours, minutes and seconds. (Hint. Increment a counter every 60 seconds and another counter every minute.)2. When a motor is turned off because of an
Mohawk - EE - 369
EE369 Industrial Automation PLC references1. PLC-5 hardware installation manual:-Ch 1 pgs 1-1 to 1-6 Ch 8 pgs 8-1 to 8-5 Ch9 Ch 10 pgs 10-1 to 10-3 Ch 11 - troubleshooting2. PLC-5 quick instruction manual3. PLC-5 addressing reference manual:-pg 2 m
Mohawk - EE - 369
EE369 Industrial Automation PLC Sequential Practice Problem (Container example) A container is loaded with 50 items at a loading dock. The loading chute only opens if the container is at the loading dock. Once full, the container is moved forward by a con
Mohawk - EE - 369
POWER FACTOR CORRECTIONExisting installation208 Volts 60 Hz75 HP Motor PF=0.75P=75 HP x 746 W = 55.950 kW S=55.950 kW/0.75 = 74.600 kVA Q=74.600 kVA x sin 41.41 deg. = 49.3426 kVAR'sAfter PF correction What value of capacitor is needed to increase th
Mohawk - EE - 369
EE369 Industrial Automation Module 1 Single Phase Review Problems1. For figure 1, find the currents through the inductor and thecapacitor.Figure 1 2. For figure 2, find the current through the resistor.Figure 23. For figure 3, find the currents thoug
Mohawk - EE - 369
EE369 Industrial Automation Combo RLC Problem: A series-parallel circuit is shown below. Calculate the total circuit impedance Zt and the voltage across the resistor, VR. E = 90V @ 60Hz R = 600 C1 = 470F C2 = 200FSolution: Zt = 18.9 - 89.1 VVR = 63.13
Mohawk - EE - 369
EE369 Industrial Automation Complex numbers Problems: 1. Convert into rectangular coordinates:a) b)220 240120 552. Convert into polar coordinates: a) 50-15j b) -25+25j 3. Solve the following:a) b)35 - 90 + 25 - 90 70 80 / 100 - 30Solutions: 1. a) -
Mohawk - EE - 369
EE369 Industrial Automation Parallel RLC Problem: A parallel circuit is shown below. Calculate the total circuit impedance Zt and the current through the inductor, IL. E = 120V @ 60Hz R = 40 L = 100mH C = 200FSolution: Zt = 18.22 IL = 3.18 - 62.91 - 90
Mohawk - EE - 369
EE369 Industrial Automation Series RLC Problem: A series circuit is shown below. Calculate the total circuit impedance Zt and the voltage across the capacitor, Vc. E = 28V @ 60Hz R = 40 L = 10mH C = 20FSolution: Zt = 134.9 Vc = 27.52 - 72.75 - 17.25 V