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Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart I: Strategic Management InputsChapter 1: Strategic Management andStrategic Competitiveness2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,inwhol
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart I: Strategic Management InputsChapter 2: The External Environment:Opportunities, Threats,Industry Competition andCompetitor Analysis2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart II: Strategic Actions:Strategy FormulationChapter 4: Business-Level Strategy2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,inwholeorinpart.The
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePartII:StrategicActions:StrategyFormulationChapter5:CompetitiveRivalryandCompetitiveDynamics2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,inwholeo
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart II: Strategic Actions:Strategy FormulationChapter 7: Merger and AcquisitionStrategies2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,inwholeori
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart III: Strategic Actions:Strategy ImplementationChapter 10: Corporate Governance2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,inwholeorinpart.T
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart III: Strategic Actions:Strategy ImplementationChapter 11: Organizational Structureand Controls2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,i
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart III: Strategic Actions:Strategy ImplementationChapter 12: Strategic Leadership2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,inwholeorinpart.T
Troy - MGT - 4476
StrategicManagement:ConceptsandCases9ePart III: Strategic Actions:Strategy ImplementationChapter 13: Strategic Entrepreneurship2011CengageLearning.AllRightsReserved.Maynotbescanned,copiedorduplicated,orpostedtoapubliclyaccessiblewebsite,inwholeorinp
Troy - IS - 3331
Essentials of MIS, 9E Laudon & Laudon Lecture Files by Barbara J. Ellestad Chapter 1 Business Information Systems in Your CareerComputers continue to change every aspect of our lives from entertainment to shopping, from the work we do and where we do it,
Troy - IS - 3331
Essentials of MIS, 9E Laudon & Laudon Lecture Files by Barbara J. EllestadChapter 2 Global E-Business and CollaborationAs we discussed in Chapter 1, the "digital firm" means more than just plunking down computers that have all the latest bells and whist
Troy - IS - 3331
Essentials of MIS, 9eLaudon & LaudonLecture Files by Barbara J. EllestadChapter 3 Achieving Competitive Advantage with Information SystemsThe changes that have taken place in computing have affected the business environment in a big way. Over40 perce
Troy - IS - 3331
Essentials of MIS, 9ELaudon & LaudonLecture Files by Barbara J. EllestadChapter 4 IT Infrastructure: Hardware and Software4.1 IT Infrastructure: Computer HardwareBecause information is becoming such a valuable resource of the digital firm, the infras
Troy - IS - 3331
Essentials of MIS, 9ELaudon & LaudonLecture Files by Barbara J. EllestadChapter 5 Foundations of Business Intelligence: Database and InformationManagementInformation is becoming as important a business resource as money, material, and people. Just be
Troy - IS - 3331
Essentials of MIS, 9ELaudon & LaudonLecture Files by Barbara J. EllestadChapter 6 Telecommunications, the Internet and Wireless TechnologyAnytime, anywhere, anyway, is the mantra of many computer users. Improved telecommunicationstechnologies, the pr
Troy - FIN - 3331
SolutionstoEndofChapterProblems71Withyourfinancialcalculator,enterthefollowing:N=10;I/YR=YTM=9%;PMT=0.08 1,000=80;FV=1000;PV=VB=?PV=$935.82.72VB=$985;M=$1,000;Int=0.07 $1,000=$70.a. N=10;PV=985;PMT=70;FV=1000;YTM=?SolveforI/YR=YTM=7.2157% 7.22%.b
Troy - FIN - 3331
SolutionstoEndofChapterProblems91D0=$1.50;g13=7%;gn=5%;D1throughD5=?D1=D0(1+g1)=$1.50(1.07)=$1.6050.D2=D0(1+g1)(1+g2)=$1.50(1.07)2=$1.7174.D3=D0(1+g1)(1+g2)(1+g3)=$1.50(1.07)3=$1.8376.D4=D0(1+g1)(1+g2)(1+g3)(1+gn)=$1.50(1.07)3(1.05)=$1.9294.D5=D0(1
Troy - FIN - 3331
SolutionstoEndOfChapterProblems101rd(1T)=0.12(0.65)=7.80%.102Pp=$47.50;Dp=$3.80;rp=?rp =103DpPp=40%Debt;60%Commonequity;rd=9%;T=40%;WACC=9.96%;rs=?WACC0.09960.09960.078rs104$3.80=8%.$47.50=(wd)(rd)(1T)+(wc)(rs)=(0.4)(0.09)(10.4)+(0.6)
Troy - FIN - 3331
Chapter3FinancialStatements,CashFlow,andTaxes31323335363839310
Troy - FIN - 3331
81 =(0.1)(50%)+(0.2)(5%)+(0.4)(16%)+(0.2)(25%)+(0.1)(60%)r=11.40%.2=(50%11.40%)2(0.1)+(5%11.40%)2(0.2)+(16%11.40%)2(0.4)+(25%11.40%)2(0.2)+(60%11.40%)2(0.1)2=712.44;=26.69%.CV=8226.69%=2.34.11.40%Investment$35,00040,000Total $75,000Beta0.
Troy - FIN - 3331
Chapter1IntroductiontoFinancialManagement11121314
Troy - FIN - 3331
Chapter2FinancialMarketsandInstitutions21Figure212225Figure2326
Troy - FIN - 3331
Chapter6InterestRatesCostofMoneyandInterestRateLevelsDeterminantsofInterestRatesTheTermStructureandYieldCurvesUsingYieldCurvetoEstimateFuture61InterestRatesWhatfourfactorsaffectthelevelofinterestrates?ProductionopportunitiesTimepreferencesf
Troy - FIN - 3331
Chapter7BondsandTheirValuation KeyFeaturesofBonds BondValuation MeasuringYield AssessingRisk71Whatisabond?Alongtermdebtinstrumentinwhichaborroweragreestomakepaymentsofprincipalandinterest,onspecificdates,totheholdersofthebond.72BondMarketsPr
Troy - FIN - 3331
Chapter8RiskandRatesofReturn StandAloneRisk PortfolioRisk RiskandReturn:CAPM/SML81InvestmentReturnsTherateofreturnonaninvestmentcanbecalculatedasfollows:(Expectedendingvalue Cost)Return=CostForexample,if$1,000isinvestedand$1,100isreturnedafte
Troy - FIN - 3331
Chapter9StocksandTheirValuation FeaturesofCommonStock DeterminingCommonStockValues PreferredStock91FactsaboutCommonStockRepresentsownershipOwnershipimpliescontrolStockholderselectdirectorsDirectorselectmanagementManagementsgoal:Maximizethestock
Troy - FIN - 3331
TIME VALUE OF MONEY1.Which of the following statements is CORRECT?a.b.c.A time line is not meaningful unless all cash flows occur annually.Time lines are useful for visualizing complex problems prior to doing actual calculations.Time lines cannot
American University in Cairo - ACCT - 305
Accounting and Auditing of Financial Derivatives:(The Case of Maridive & Oil Services (MOSDr Mohamed Hegazy & Karim HegazyExecutive SummaryThis case studies accounting and auditing implications resulting from the disputeamong auditors and the managem
American Internation College - ECON - 102
My career planMy Burnout Skills/My Boreout Skills: What does this mean in terms of job choices?My major burnout skill in my opinion is organization and structuring of an archive. I used todo it a lot during my practical experience and I feel that this
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
UT Arlington - PHYS - 303
University of Florida - PHY - 1020
Nuclear Physics13-1measure mass in energy equivalent of rest masse. g. for electron m = 9.1 (10)-31 kgmc2= 9.1 (10)-31 kg [3 (10)8 m/s ]2= 8.19 (10)-14 Jormc2= 8.19 (10)-14 J [1.602 (10)-19 J/eV = 0.511 MeVm 0.511 MeVmatter energyNuclear Physics
University of Florida - PHY - 1020
4 Fundamental ForcesForceRelative StrengthRangeStrong11 fmElectromagnetic102Infinite (1/r2)Weak106103 fmGravitational1043Infinite (1/r2)14.1Hadrons (Heavy particles)AntiparticlesymbolRest energy (MeV)Lifetime (s)ParticleParticle sym
University of Florida - PHY - 1020
Problem 2.1: A car is traveling at 6.70 m/s (15 miles/h) when the driver applies the brakes.The car decelerates at a constant rate of 4.00 m/s2 until coming to a halt. Calculate thea) distance of the car travels while deceleratingb) distance required t
University of Florida - PHY - 1020
1D Motionin generalxv= x = v ttva=v = a ttx dxv = Limt 0 tdtx = area under v(t) curvev(t) = slope of x(t) curvea(t) = slope of v(t) curveFor constant acceleration (a=constant) [Important special case]ACTUALLY WILL OFTEN USE y NOT x(vf +
University of Florida - PHY - 1020
2-Da = constant motiont=0v0 (v 0x , v 0y )a (ax ,ay ) constantr0 (x0 , y 0 )Most General Form (actually rarely necessary) v x = v0x + ax tt2 x = x0 + v 0x t + ax 2t2 y = y 0 + v 0y t + ay 2(v 0x + v 0x )t x = v x t =2v x 2 - vox 2 = 2ax (x
University of Florida - PHY - 1020
1Defining the system/systems to efficiently attack specifice questions in coupled massNewtons Law problems.Annotated lecture notes by M. Croft-This figure illustrates the typical approach to a2interacting object problem. Namely, Newtons law foreach
University of Florida - PHY - 1020
7.5Nma 0.798 2(1.3 3.2 4.9) kgsFa(m1 m 2 m3 )F=(m1+m2+m3)aF12m1m2Find F21 and F23I first find a+F32F21 Fm3237.5Nma 0.798 2(1.3 3.2 4.9) kgsFa(m1 m 2 m3 )F=(m1+m2+m3)aF12m1m2+F32F21 Fm323F32 m3aF32 4.9(.798) kg m/s2
University of Florida - PHY - 1020
F=matotalFx =maxFy =mayFtotal = Findividual+Sign convention choice!P Free body diagramm2m1System choiceForce reaction force pairm2TTm1Psystem cuts at point of internal force actionCONSISTANT sign convention choicearound corners!4-0.1Ff
University of Florida - PHY - 1020
5a-1Circular MotionNotes: F and a alwayspoint toward the center.4b-05-1a F V all have constantmagnitude, but change indirection.4b-05-2Car on Flat Curve (static friction holds car on curve)Important: want to find maximum v (car) and minimum R (r
University of Florida - PHY - 1020
dvv2=gdtLdx=vdtCan solve with calculus with luck : can solve numerically for sureEXTRA MATERIAL- NOT REQUIRED FOR PHYS 2034e-1EXTRA MATERIALNOT REQUIRED FOR PHYS 2034e-2solutiondvv2=gdtLdy=v withdty(0)=0v(0)=0EXTRA MATERIAL-NOT REQU
University of Florida - PHY - 1020
Isaac Newton -background born Christmas Day 1642 ( a few months after Galileo died) -1727in Woolsthorpe England (father died a few months before)Mother remarried, raised by grandmother Cambridge University bachelors degree 1665 1665-1667 spent two ye
University of Florida - PHY - 1020
Kinetic Energy (energy of motion) E or KE112222K = m v = m(v x + v y + v z )22exampleUnitsm2[kg 2 ] Js(Joule)baseball m=0.15 kgpitched atv = 69 mph = 36.5 m/s112K = mv = (0.15)(36.5)2 [kg (m/s)2 ]22K = 100 Jv = 69 mphv = 100 mph
University of Florida - PHY - 1020
Mass ConservationMomentum ConservationRecall Newtons Law:F=m aInitialMi = mk= m1 + m2 + m3 + (m v)F = tFinalp=0tConservationof Masswritten differentlyOR pi = pfEm = c2Conservation of (Mass + Energy)= Newtons LawThenp = 0No change i
University of Florida - PHY - 1020
Center of Mass DefinitionsRecall P conservationM = m j = tot. mass1-dimension( m j v j )initial = ( m j v j )finaljjv CM = m j v j / Mj( m j v j )initialjxCM = m jx j / MjMjixCM = m jx j / Mjy CM = m j y j / MjjMMomentum conservation