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CameronMastersspreadsheet

Course: ENG 317, Spring 2012
School: University of Maine
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Masters 1/31/2012 $96,000 4 Cameron .80% 12 300 $550.08 $69,023.13 1-Jul-28 Apr 1 2032 100 Unpaid Balance principle $96,000.00 $95,833.92 $95,667.18 $95,499.77 $95,331.70 $95,162.94 $94,993.52 $94,823.42 $94,652.63 $94,481.17 $94,309.01 $94,136.17 $93,962.64 $93,788.41 $93,613.49 $93,437.87 $93,261.54 $93,084.51 $92,906.77 $92,728.32 $92,549.16 $92,369.28 $92,188.68 $92,007.36 $91,825.31 $91,642.53 $91,459.03 $91,274.78 $91,089.81 $90,904.09 $90,717.63 $90,530.42 $90,342.47 $90,153.76 $89,964.30 $89,774.08 $89,583.10 $89,391.35 $89,198.84 $89,005.56 $88,811.50 $88,616.67 $88,421.06 $88,224.67 $88,027.49 $87,829.52 $87,630.76 $87,431.21 $87,230.86 $87,029.70 $86,827.75 $86,624.98 $86,421.40 $86,217.01 $86,011.80 $85,805.77 $85,598.92 $85,391.24 $85,182.72 $84,973.38 $84,763.19 $84,552.17 $84,340.30 $84,127.59 $83,914.02 $83,699.60 $83,484.32 $83,268.18 $83,051.18 $82,833.30 $82,614.56 $82,394.94 $82,174.44 $81,953.06 $81,730.80 $81,507.65 $81,283.60 $81,058.66 $80,832.81 $80,606.07 $80,378.41 $80,149.85 $79,920.37 $79,689.98 $79,458.66 $79,226.42 $78,993.25 $78,759.14 $78,524.10 $78,288.12 $78,051.20 $77,813.32 $77,574.50 $77,334.72 $77,093.98 $76,852.28 $76,609.61 $76,365.98 $76,121.36 $75,875.77 $75,629.20 $75,381.64 $75,133.09 $74,883.54 $74,633.00 $74,381.45 $74,128.90 $73,875.34 $73,620.77 $73,365.17 $73,108.55 $72,850.91 $72,592.24 $72,332.53 $72,071.78 $71,809.99 $71,547.16 $71,283.27 $71,018.32 $70,752.32 $70,485.25 $70,217.12 $69,947.91 $69,677.62 $69,406.26 $69,133.80 $68,860.26 $68,585.63 $68,309.89 $68,033.05 $67,755.11 $67,476.05 $67,195.88 $66,914.59 $66,632.17 $66,348.62 $66,063.94 $65,778.11 $65,491.15 $65,203.04 $64,913.77 $64,623.35 $64,331.77 $64,039.02 $63,745.10 $63,450.00 $63,153.72 $62,856.26 $62,557.61 $62,257.76 $61,956.71 $61,654.46 $61,351.01 $61,046.33 $60,740.44 $60,433.33 $60,124.98 $59,815.40 $59,504.59 $59,192.53 $58,879.22 $58,564.66 $58,248.84 $57,931.76 $57,613.41 $57,293.79 $56,972.89 $56,650.70 $56,327.23 $56,002.46 $55,676.39 $55,349.02 $55,020.34 $54,690.34 $54,359.03 $54,026.39 $53,692.42 $53,357.11 $53,020.46 $52,682.46 $52,343.12 $52,002.41 $51,660.35 $51,316.91 $50,972.10 $50,625.91 $50,278.34 $49,929.37 $49,579.01 $49,227.25 $48,874.09 $48,519.50 $48,163.51 $47,806.08 $47,447.23 $47,086.94 $46,725.21 $46,362.04 $45,997.41 $45,631.32 $45,263.77 $44,894.75 $44,524.25 $44,152.27 $43,778.80 $43,403.84 $43,027.38 $42,649.41 $42,269.93 $41,888.93 $41,506.41 $41,122.36 $40,736.77 $40,349.64 $39,960.96 $39,570.73 $39,178.94 $38,785.57 $38,390.64 $37,994.12 $37,596.02 $37,196.33 $36,795.04 $36,392.14 $35,987.63 $35,581.51 $35,173.76 $34,764.37 $34,353.35 $33,940.69 $33,526.38 $33,110.41 $32,692.77 $32,273.46 $31,852.48 $31,429.81 $31,005.46 $30,579.40 $30,151.64 $29,722.17 $29,290.98 $28,858.07 $28,423.42 $27,987.04 $27,548.91 $27,109.03 $26,667.39 $26,223.98 $25,778.80 $25,331.84 $24,883.09 $24,432.54 $23,980.20 $23,526.04 $23,070.07 $22,612.27 $22,152.64 $21,691.18 $21,227.86 $20,762.70 $20,295.67 $19,826.78 $19,356.01 $18,883.36 $18,408.81 $17,932.37 $17,454.02 $16,973.76 $16,491.58 $16,007.47 $15,521.42 $15,033.43 $14,543.49 $14,051.58 $13,557.71 $13,061.87 $12,564.04 $12,064.22 $11,562.40 $11,058.57 $10,552.72 $10,044.86 $9,534.96 $9,023.02 $8,509.04 $7,993.00 $7,474.89 $6,954.72 $6,432.46 $5,908.11 $5,381.67 $4,853.11 $4,322.45 $3,789.66 $3,254.74 $2,717.69 $2,178.48 $1,637.12 $1,093.59 $547.89 $0.00 interest $166.08 $384.00 $166.74 $383.34 $167.41 $382.67 $168.08 $382.00 $168.75 $381.33 $169.43 $380.65 $170.10 $379.97 $170.78 $379.29 $171.47 $378.61 $172.15 $377.92 $172.84 $377.24 $173.53 $376.54 $174.23 $375.85 $174.92 $375.15 $175.62 $374.45 $176.33 $373.75 $177.03 $373.05 $177.74 $372.34 $178.45 $371.63 $179.16 $370.91 $179.88 $370.20 $180.60 $369.48 $181.32 $368.75 $182.05 $368.03 $182.78 $367.30 $183.51 $366.57 $184.24 $365.84 $184.98 $365.10 $185.72 $364.36 $186.46 $363.62 $187.21 $362.87 $187.96 $362.12 $188.71 $361.37 $189.46 $360.62 $190.22 $359.86 $190.98 $359.10 $191.74 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$234.26 $317.08 $233.00 $318.35 $231.73 $319.62 $230.45 $320.90 $229.18 $322.19 $227.89 $323.47 $226.60 $324.77 $225.31 $326.07 $224.01 $327.37 $222.71 $328.68 $221.40 $330.00 $220.08 $331.32 $218.76 $332.64 $217.44 $333.97 $216.11 $335.31 $214.77 $336.65 $213.43 $338.00 $212.08 $339.35 $210.73 $340.70 $209.37 $342.07 $208.01 $343.44 $206.64 $344.81 $205.27 $346.19 $203.89 $347.57 $202.50 $348.96 $201.11 $350.36 $199.72 $351.76 $198.32 $353.17 $196.91 $354.58 $195.50 $356.00 $194.08 $357.42 $192.65 $358.85 $191.22 $360.29 $189.79 $361.73 $188.35 $363.18 $186.90 $364.63 $185.45 $366.09 $183.99 $367.55 $182.53 $369.02 $181.06 $370.50 $179.58 $371.98 $178.10 $373.47 $176.61 $374.96 $175.12 $376.46 $173.62 $377.97 $172.11 $379.48 $170.60 $381.00 $169.08 $382.52 $167.56 $384.05 $166.03 $385.59 $164.49 $387.13 $162.95 $388.68 $161.40 $390.23 $159.84 $391.79 $158.28 $393.36 $156.72 $394.93 $155.14 $396.51 $153.56 $398.10 $151.98 $399.69 $150.38 $401.29 $148.79 $402.90 $147.18 $404.51 $145.57 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$526.44 $23.63 $528.55 $21.53 $530.66 $19.41 $532.79 $17.29 $534.92 $15.16 $537.06 $13.02 $539.21 $10.87 $541.36 $8.71 $543.53 $6.55 $545.70 $4.37 $547.89 $2.19 $550.08 $0.00 7/1/2012 8/1/2012 9/1/2012 10/1/2012 11/1/2012 12/1/2012 1/1/2013 2/1/2013 3/1/2013 4/1/2013 5/1/2013 6/1/2013 7/1/2013 8/1/2013 9/1/2013 10/1/2013 11/1/2013 12/1/2013 1/1/2014 2/1/2014 3/1/2014 4/1/2014 5/1/2014 6/1/2014 7/1/2014 8/1/2014 9/1/2014 10/1/2014 11/1/2014 12/1/2014 1/1/2015 2/1/2015 3/1/2015 4/1/2015 5/1/2015 6/1/2015 7/1/2015 8/1/2015 9/1/2015 10/1/2015 11/1/2015 12/1/2015 1/1/2016 2/1/2016 3/1/2016 4/1/2016 5/1/2016 6/1/2016 7/1/2016 8/1/2016 9/1/2016 10/1/2016 11/1/2016 12/1/2016 1/1/2017 2/1/2017 3/1/2017 4/1/2017 5/1/2017 6/1/2017 7/1/2017 8/1/2017 9/1/2017 10/1/2017 11/1/2017 12/1/2017 1/1/2018 2/1/2018 3/1/2018 4/1/2018 5/1/2018 6/1/2018 7/1/2018 8/1/2018 9/1/2018 10/1/2018 11/1/2018 12/1/2018 1/1/2019 2/1/2019 3/1/2019 4/1/2019 5/1/2019 6/1/2019 7/1/2019 8/1/2019 9/1/2019 10/1/2019 11/1/2019 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Business Data Network & Telecommunication (ITT730)Master in Information Technology (CS770)University Technology MARA (UiTM) Shah AlamPROJECT TITLE: MONITORING NETWORK PERFORMANCE BY USED NAGIOS.1.0BACKGROUNDNetwork performance is the most effected t
SEMO - HRM - 312
1Debbie MaingiProfessor Bill GloverHuman Resource Management7 March 2012Exercise 3.1.1: Zimpfer V. Palm Beach County1. Was Mr. Zimpfer a victim of illegal age discrimination according to the ADEA and case law?Explain your position. Cite relevant co
University of Malaya - DEPARTMENT - KEB
JABATAN KEJURUTERAAN MEKANIKUNIVERSITI MALAYASEM 2 SESI 2008/2009TERMODINAMIK BAHAN KMEB1202AMALI 1The thermodynamics of Potassium Nitrate (KNO3)PURPOSETo measure the solubility of potassium nitrate in different volume of water atelevated temperat
Clemson - PHYS - 221
1.1.Solve:1.2.Solve:1.3.Solve:1.4. Solve: (a) The basic idea of the particle model is that we will treat an object as if all its mass is concentrated into a single point. The size and shape of the object will not be considered. This is a reasonable
Clemson - PHYS - 221
2.1. Model: We will consider the car to be a particle that occupies a single point in space.Visualize:Solve:Since the velocity is constant, we have xf = xi + vx t. Using the above values, we getx1 = 0 m + (10 m/s)(45 s) = 450 mAssess: 10 m/s 22 mph a
Clemson - PHYS - 221
3.1.Visualize:Solve: (a) To find A + B , we place the tail of vector B on the tip of vector A and connect the tail of vector A with the tip of vector B. (b) Since A B = A + ( B) , we place the tail of the vector ( B ) on the tip of vector A and then con
Clemson - PHYS - 221
4.1.Solve:(a)(b) A race car slows from an initial speed of 100 mph to 50 mph in order to negotiate a tight turn. After making the 90 turn the car accelerates back up to 100 mph in the same time it took to slow down.4.2.Solve:(a)(b) A car drives up
Clemson - PHYS - 221
5.1. Visualize:Assess: walls.Note that the climber does not touch the sides of the crevasse so there are no forces from the crevasse5.2. Visualize:5.3. Visualize:5.4. Model: Assume friction is negligible compared to other forces.Visualize:5.5. Visu
Clemson - PHYS - 221
6.1.Model: Visualize:We can assume that the ring is a single massless particle in static equilibrium.Solve:Written in component form, Newtons first law is( Fnet ) x = Fx = T1x + T2 x + T3 x = 0 N ( Fnet ) y = Fy = T1 y + T2 y + T3 y = 0 NEvaluating
Clemson - PHYS - 221
7.1.Visualize:Solve: (a) The weight lifter is holding the barbell in dynamic equilibrium as he stands up, so the net force on the barbell and on the weight lifter must be zero. The barbells have an upward contact force from the weight lifter and the gra
Clemson - PHYS - 221
8.1.Model: The model rocket and the target will be treated as particles. The kinematics equations in two dimensions apply. Visualize:Solve:For the rocket, Newtons second law along the y-direction is( Fnet ) y = FR mg = maR aR = 1 1 15 N ( 0.8 kg ) (
Clemson - PHYS - 221
9.1. Model: Model the car and the baseball as particles.Solve:(a) The momentum p = mv = (1500 kg ) (10 m/s ) = 1.5 104 kg m/s.(b) The momentum p = mv = ( 0.2 kg )( 40 m/s ) = 8.0 kg m/s.9.2. Model: Model the bicycle and its rider as a particle. Also m
Clemson - PHYS - 221
10.1. Model: We will use the particle model for the bullet (B) and the running student (S).Visualize:Solve:For the bullet,1 1 2 K B = mBvB = (0.010 kg)(500 m/s) 2 = 1250 J 2 2 For the running student, 1 1 2 KS = mSvS = (75 kg)(5.5 m/s) 2 = 206 J 2 2 T
Clemson - PHYS - 221
11.1. Visualize: Please refer to Figure EX11.1. Solve: (a) A B = AB cos = (4)(5)cos 40 = 15.3.(b) (c)C D = CD cos = (2)(4)cos120 = 4.0. E F = EF cos = (3)(4)cos90 = 0.11.2. Visualize: Please refer to Figure EX11.2. Solve: (a) A B = AB cos = (3)(4)cos11
Clemson - PHYS - 221
12.1.Model: A spinning skater, whose arms are outstretched, is a rigid rotating body.Visualize:Solve: The speed v = r , where r = 140 cm/2 = 0.70 m. Also, 180 rpm = (180)2 /60 rad/s = 6 rad/s. Thus, v = (0.70 m)(6 rad/s) = 13.2 m/s. Assess: A speed of
Clemson - PHYS - 221
13.1.Model: Model the sun (s) and the earth (e) as spherical masses. Due to the large difference between your size and mass and that of either the sun or the earth, a human body can be treated as a particle. GM s M y GM e M y and Fe on you = Solve: Fs on
Clemson - PHYS - 221
14.1. Solve: The frequency generated by a guitar string is 440 Hz. The period is the inverse of the frequency,henceT=1 1 = = 2.27 103 s = 2.27 ms f 440 Hz14.2. Model: The air-track glider oscillating on a spring is in simple harmonic motion.Solve: Th
Clemson - PHYS - 221
15.1. Solve: The density of the liquid is=Assess:0.240 kg m 0.240 kg = = = 960 kg m3 V 250 mL 250 103 103 m3The liquids density is near that of water (1000 kg/m3 ) and is a reasonable number.15.2. Solve: The volume of the helium gas in container A is
Clemson - PHYS - 221
16.1. Model: Recall the density of water is 1000 kg/m3. Solve: The mass of lead mPb = PbVPb = (11,300 kg m3 ) ( 2.0 m3 ) = 22,600 kg . For water to have the samemass its volume must beVwater =Assess:mwater water=22,600 kg = 22.6 m3 1000 kg m3Since
Clemson - PHYS - 221
17.1. Model: Assume the gas is ideal. The work done on a gas is the negative of the area under the pV curve.Visualize: The gas is compressing, so we expect the work to be positive. Solve: The work done on the gas isW = p dV = ( area under the pV curve )
Clemson - PHYS - 221
18.1. Solve: We can use the ideal-gas law in the form pV = NkBT to determine the Loschmidt number(N/V):(1.013 105 Pa ) = 2.69 1025 m3 N p = = V kBT (1.38 1023 J K ) ( 273 K )18.2. Solve: The volume of the nitrogen gas is 1.0 m3 and its temperature is 2
Clemson - PHYS - 221
19.1.Solve: (a) The engine has a thermal efficiency of = 40% = 0.40 and a work output of 100 J per cycle. The heat input is calculated as follows:=Wout 100 J 0.40 = QH = 250 J QH QH(b) Because Wout = QH QC , the heat exhausted isQC = QH Wout = 250 J
Clemson - PHYS - 221
20.1.Model: The wave is a traveling wave on a stretched string. Solve: The wave speed on a stretched string with linear density is vstring = TS / . The wave speed if thetension is doubled will be vstring = 2TS = 2vstring = 2 ( 200 m/s ) = 283 m/s20.2.
Clemson - PHYS - 221
21.1. Model: The principle of superposition comes into play whenever the waves overlap.Visualize:The graph at t = 1.0 s differs from the graph at t = 0.0 s in that the left wave has moved to the right by 1.0 m and the right wave has moved to the left by
Clemson - PHYS - 221
Visualize: The interference pattern looks like the photograph of Figure 22.3(b). It is symmetrical with the m = 2 fringes on both sides of and equally distant from the central maximum. Solve: The bright fringes occur at angles m such that22.1. Model: Two
Clemson - PHYS - 221
23.1. Model: Light rays travel in straight lines.Solve: (a) The time ist= x 1.0 m = = 3.3 109 s = 3.3 ns c 3 108 m/s(b) The refractive indices for water, glass, and cubic zirconia are 1.33, 1.50, and 1.96, respectively. In a time of 3.33 ns, light will
Clemson - PHYS - 221
24.1. Model: Each lens is a thin lens. The image of the first lens is the object for the second lens.Visualize:The figure shows the two lenses and a ray-tracing diagram. The ray-tracing shows that the lens combination will produce a real, inverted image
Clemson - PHYS - 221
25.1. Model: Balmers formula predicts a series of spectral lines in the hydrogen spectrum.Solve: Substituting into the formula for the Balmer series,=91.18 nm 91.18 nm = = 410.3 nm 11 1 1 2 2 2 22 6 2 n where n = 3, 4, 5, 6, and where we have used n =
Clemson - PHYS - 221
26.1. Model: Use the charge model.Solve: (a) In the process of charging by rubbing, electrons are removed from one material and transferred to the other because they are relatively free to move. Protons, on the other hand, are tightly bound in nuclei. So
Clemson - PHYS - 221
27.1.Model: The electric field is that of the two charges placed on the y-axis. Visualize: Please refer to Figure EX27.1. We denote the upper charge by q1 and the lower charge by q2. Because both the charges are positive, their electric fields at P are d
Clemson - PHYS - 221
28.1. Visualize:As discussed in Section 28.1, the symmetry of the electric field must match the symmetry of the charge distribution. In particular, the electric field of a cylindrically symmetric charge distribution cannot have a component parallel to th
Clemson - PHYS - 221
29.1. Model: The mechanical energy of the proton is conserved. A parallel-plate capacitor has a uniformelectric field. Visualize:The figure shows the before-and-after pictorial representation. The proton has an initial speed vi = 0 m/s and a final speed
Clemson - PHYS - 221
30.1. Solve: The potential difference V between two points in space isV = V ( xf ) V ( xi ) = Ex dxxi xfwhere x is the position along a line from point i to point f. When the electric field is uniform,V = Ex dx = Ex x = (1000 V/m )( 0.30 m 0.10 m ) =
Clemson - PHYS - 221
31.1. Solve: The wires cross-sectional area is A = r 2 = (1.0 103 m ) = 3.1415 106 m 2 , and the electron2current through this wire is i = 31.3, the drift velocity isvd =Ne = 2.0 1019 s 1 . Using Table 31.1 for the electron density of iron and Equatio
Clemson - PHYS - 221
32.1. Solve:From the circuit in Figure EX32.1, we see that 50 and 100 resistors are connected in series across the battery. Another resistor of 75 is also connected across the battery.32.2. Solve: In Figure EX32.2, the positive terminal of the battery i
Clemson - PHYS - 221
33.1. Model: A magnetic field is caused by an electric current.Visualize: Please refer to Figure EX33.1. Solve: The magnitude of the magnetic field at point 1 is 2.0 mT and its direction can be determined by using the right-hand rule. Grab the current ca
Clemson - PHYS - 221
34.1.Visualize:To develop a motional emf the magnetic field needs to be perpendicular to both, so lets say its direction is into the page. Solve: This is a straightforward use of Equation 34.3. We havev=Assess:E 1.0 V = = 2.0 104 m/s lB (1.0 m ) ( 5.