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ENG106W12_HW1-solution

Course: ENGIN 106, Spring 2012
School: Laney College
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#1 ENG106 Homework Solution Winter 2012 Question 1. Youve decided to buy a Toyota Prius because of the (recently) high price of gasoline. Like every car, a Prius wears as it ages, providing less in psychological benefits and costing more for maintenance and repair in future years. Therefore youd like to determine the optimal length of time to keep the Prius before buying a new one. a) What might be one or more...

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#1 ENG106 Homework Solution Winter 2012 Question 1. Youve decided to buy a Toyota Prius because of the (recently) high price of gasoline. Like every car, a Prius wears as it ages, providing less in psychological benefits and costing more for maintenance and repair in future years. Therefore youd like to determine the optimal length of time to keep the Prius before buying a new one. a) What might be one or more possible objectives (wants) Minimize average yearly cost Maximize years of use Maximize resale value Minimize initial and annual CO2 emissions b) List three or more possible constraints (needs) Needs warranty throughout ownership period Needs to be sold prior to major depreciation period Availability during ownership period Repair costs during ownership period c) What are the decision variables for this problem? How long to keep before buying a new Prius. (years) d) List at least five pieces of information you might need in order to make a rational decision. The yearly price costs under owning or leasing schemes. The prices (and availability) of hybrid repair shops in the area The trade in or selling value of the car The average maintenance costs, with respect to year. The average repair costs for hybrids, with respect to year. e) Track down a reputable source for one of the five bits, and report the value. List complete reference/contact information for the source. The total price (including taxes and shipping) for a Toyota Prius in year 2000 reference dollars is $19,746. Source: TE Lipman, MA Delucchi. Hybrid-electric Vehicle Design: Retail and Life Cycle Cost Analysis. Analysis and Report Prepared for The Energy Foundation. April, 2003. 2.2 You deposit $2000 in a savings account that earns 8% simple interest per year. How many years will it take to double your balance? F = P (1 + N), where F = $4000, P = $2000, and = .08 Solving for N = 12.5 years. (13 years) (2.2) If, you instead, deposit the $2,000 in another savings account that earns 7% interest compounded yearly, how many years will it take to double your balance? F = P (1 + )N Where F = $4000. P = $2000, and = .07 Solving for N = 10.24 years. (11 years) (2.3) 2.5 You are about to borrow $5,000 from a bank at an interest rate of 9% compounded annually. You are required to make five equal annual repayments in the amount of $1,285.46 per year, with the first repayment occurring at the end of year one. For each year, show the interest payment and principal payment. Interest Payment = Last Years Balance x Interest Principal Payment = Annuity Interest Payment Loan Balance = Last Years Balance Principal Payment Period 0 1 2 3 4 5 Principal Payment 0 $835.46 $910.65 $992.61 $1,081.94 $1,179.32 Interest Payment 0 $450.00 $374.81 $292.85 $203.52 $106.14 Loan Balance $5,000 $4,165 $3,254 $2,261 $1,179 $0 2.8 Which of the following alternatives would you choose, assuming the interest rate of 8% compounded annually? Alternative 1: Receive $100 today; Alternative 2: Receive $120 two years from now. Alternative 1: P = $100 Alternative 2: P = $120 (P/F, 8%, 2) = 120 (0.8573) = $102.88 Alternative 2 is preferred 2.10a State the present worth of the following future payments: P=? = 7% , N = 6 $4,500 F = $4,500, 7% compounded annual interest, in 6 years time F = P (1 + )N , Solve for P Or F*(P/F, ,n) = P, with = .07 and N = 6 F*(P/F, 7%, 6) = 4,500 * .6663 = $2,998 (2.3) (using appendix B) 2.17 If $1000 is invested now, $1,500 two years from now, and $2,000 four years from now at an interest rate of 8% compounded annually, what will be the total amount in 10 years. $1000, 0 years F = ?, 10 years $1500, 2 years $2000, 4 years P(1+ ) N = P(F/P, , N) 1000 (F/P, 8%, 10) + 1500(F/P, 8%, 8) + 2000 (F/P, 8%, 6) = F 1000(2.1589) + 1500(1.8509) + 2000 (1.5869) = 2158.9 + 2776.35 + 3173.8 = $8,109.1
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