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Unit 3 Fact Sheet Fall 2011

Course: MATH 1052, Winter 2012
School: Fanshawe
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3 Unit Fact Sheet D=Ld N=LD N = L (1 d) N = L (1 d1) (1 d2) (1 dn) de = 100% de = [1 (1 d1)(1 d2)(1 dn)] 100% Amount Paid = Amount Credited (1 d) Amount Credited = Days per Month J-31, F-28, M-31, A-30, M-31, J-30, J-31, A-31, S-30, N-30, O-31, D-31 S=C+M M=E+P S=C+E+P BE = C + E ROMC = 100% ROMS = 100% (based on cost) (based on selling price) D=Sd Sred = S D Sale Price = S (1 d) Rate of...

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3 Unit Fact Sheet D=Ld N=LD N = L (1 d) N = L (1 d1) (1 d2) (1 dn) de = 100% de = [1 (1 d1)(1 d2)(1 dn)] 100% Amount Paid = Amount Credited (1 d) Amount Credited = Days per Month J-31, F-28, M-31, A-30, M-31, J-30, J-31, A-31, S-30, N-30, O-31, D-31 S=C+M M=E+P S=C+E+P BE = C + E ROMC = 100% ROMS = 100% (based on cost) (based on selling price) D=Sd Sred = S D Sale Price = S (1 d) Rate of Markdown = 100% T R = Sx TC = FC + VCx NI = TR TC Break-even point: TR = TC x=
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Fanshawe - MATH - 1052
Unit 3 Selected Review Problems SolutionsSection 5.2Added question: 360(.7)(.875)(.95) = $209.475 209.475-199 = 10.475209.475 = .0050005967= 5.00%4. Solution:#List price (L)Series of discounts ratesEquivalent discount rateNet priceAmount of disc
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Exercise 1.1Exercise 1.1, Solution 1:i. 5,249,346Expanded form: 5,000,000 + 200,000 + 40,000 + 9,000 + 300 + 40 + 6Word form: Five million, two hundred forty-nine thousand, three hundred forty-six.ii. 95,275,385Expanded form: 90,000,000 + 5,000,000
Fanshawe - MATH - 1052
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Fanshawe - MATH - 1052
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Fanshawe - MATH - 1052
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Fanshawe - MATH - 1052
Exercises 5.2Calculate the missing values for questions 1 through 4:Exercise 5.2, Solution 1:List price (L)Single discount rate (d)Amount of discount (d L)Net price (N)a$187520%$375$1500b$23012%$27.60$202.40c$80054%$432$368d$5002%
Fanshawe - MATH - 1052
Exercises 6.1Exercise 6.1, Solution 1:Exercise 6.1, Solution 3:a. A lies in the second quadrantb. B lies in the fourth quadrantc. C lies in the first quadrantd. D lies on the X-axise. E lies in the third quadrantf. F lies on the Y-axisExercise 6.
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Fanshawe - MATH - 1052
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Exercise 13.1Exercise 13.1, Solution 1:Face value, FV = $1000.00, n = 2 5 = 10,Coupon rate, b = 0.015 per half-yearPMT = FV b = 1000.00 0.015 = $15.00Yield, i = 0.0125 per half-yearpurchase price = PVPMT + PVFace Value =+=+ 1000(1+0.0125)-10= 140.
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Exercises 14.2Exercise 14.2, Solution 1:j = 10% = 0.10, m = 1i=jm = = 0.1 0Present Value of cash flows:PVAll cash flows = 10,000.00(1+0.10)-1 + 20,000.00(1+0.10)-2 + 30,000.00(1+0.10)-3= 9090.90909. + 16,528.92562. + 22,539.44403.= $48,159.27874.
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