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Extra Problem 6 - Solving Decision Trees

Course: EMSE 6020, Fall 2010
School: GWU
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269 EMSE - Elements of Problem Solving and Decision Making EXTRA PROBLEM 6: SOLVING DECISION TREES Read the following decision problem and answer the questions below. A manufacturer produces items that have a probability p of being defective. These items are formed into batches of 150. Past experience indicates that some are of good quality (i.e. p=0.05) and others are of bad quality (i.e. p=0.25). Furthermore,...

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269 EMSE - Elements of Problem Solving and Decision Making EXTRA PROBLEM 6: SOLVING DECISION TREES Read the following decision problem and answer the questions below. A manufacturer produces items that have a probability p of being defective. These items are formed into batches of 150. Past experience indicates that some are of good quality (i.e. p=0.05) and others are of bad quality (i.e. p=0.25). Furthermore, 80% of the batches produced are of good quality and 20% of the batches are of bad quality. These items are then used in an assembly, and ultimately their quality is determined before the final assembly leaves the plant. The manufacturer can either screen each item in a batch and replace defective items at a total average cost of $10 per item or use the items directly without screening. If the latter action is chosen, the cost of rework is ultimately $100 per defective item. For these data, the costs per batch can be calculated as follows: Screen Do not Screen p = 0.05 $1500 $750 p = 0.25 $1500 $3750 Because screening requires scheduling of inspectors and equipment, the decision to screen or not screen must be made 2 days before the potential screening takes place. However, the manufactures may take one item taken from a batch and sent it to a laboratory, and the test results (defective or nondefective) can be reported before the screen/no-screen decision must be made. After the laboratory test, the tested item is returned to its batch. The cost of this initial inspection is $125. Also note that the probability that a random sample item is defective is 0.8 * 0.05 + 0.2 * 0.25 = 0.09, and the probability that an item in a lot is of good quality given a randomly sampled item is defective is 0.444 and the probability that an item in a lot is of good quality given a randomly sampled item is not defective is 0.835. wants The manufactures to minimize his cost. A. Derive the cost figures in the table above. Clearly show your calculations Instructor: Dr. J. R. van Dorp 1 EMSE 269 - Elements of Problem Solving and Decision Making B. What Law of Probability was used in deriving. Provide an Explanation Pr(Sampled Item is Defective) = 0.09 C. Show that: Pr(Good Quality|Sampled Item is Defective) = 0.444 Pr(Good Quality|Sampled Item is Not Defective) = 0.835 Instructor: Dr. J. R. van Dorp 2 EMSE 269 - Elements of Problem Solving and Decision Making D. Calculate and show your calculations: Pr(Bad Quality|Sampled Item is Defective) = ? Pr(Bad Quality|Sampled Item is Not Defective) = ? Instructor: Dr. J. R. van Dorp 3 EMSE 269 - Elements of Problem Solving and Decision Making E. Model the decision problem in a decision tree and fill in ALL the details. Solve the tree using EMV and clearly show your calculations in the tree. Instructor: Dr. J. R. van Dorp 4 EMSE 269 - Elements of Problem Solving and Decision Making F. How many cumulative risk profiles can be drawn for the decision tree under E? Provide an Explanation. Instructor: Dr. J. R. van Dorp 5 EMSE 269 - Elements of Problem Solving and Decision Making G. Solve the tree under E using EMV and clearly show your calculations in the tree under E Instructor: Dr. J. R. van Dorp 6 EMSE 269 - Elements of Problem Solving and Decision Making H. Describe in words the optimal decision strategy. I. Draw the Cumulative Risk Profile for each alternative of the immediate decision, taking optimal decisions from thereon. What can you conclude with respect to dominance considerations? (Hint: You should be drawing 2 Cumulative Risk Profiles). Instructor: Dr. J. R. van Dorp 7 EMSE 269 - Elements of Problem Solving and Decision Making Instructor: Dr. J. R. van Dorp 8
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