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Ch11%20Solutions[1]

Course: COM 315, Spring 2012
School: St. Leo
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11 FORECASTING CHAPTER MODELS SOLUTIONS TO DISCUSSION QUESTIONS 11-1. The steps that are used to develop any forecasting system are: 1. Determine the use of the forecast. 2. Select the items or quantities that are to be forecasted. 3. Determine the time horizon of the forecast. 4. Select the forecasting model. 5. Gather the necessary data. 6. Validate the forecasting model. 7. Make the forecast. 8. Implement the...

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11 FORECASTING CHAPTER MODELS SOLUTIONS TO DISCUSSION QUESTIONS 11-1. The steps that are used to develop any forecasting system are: 1. Determine the use of the forecast. 2. Select the items or quantities that are to be forecasted. 3. Determine the time horizon of the forecast. 4. Select the forecasting model. 5. Gather the necessary data. 6. Validate the forecasting model. 7. Make the forecast. 8. Implement the results. 11-2. A time-series forecasting model uses historical data to predict future trends. 11-3. The only difference between causal models and time-series models is that causal models take into account any factors that may influence the quantity being forecasted. Causal models use historical data as well. Time-series models use only historical data. 11-4. Qualitative models incorporate subjective factors into the forecasting model. Judgmental models are useful when subjective factors are important. When quantitative data are difficult to obtain, qualitative models are appropriate. 11-5. Least squares refers to holding the sum of the square of the difference between the observed values and the regression line to a minimum. 11-6. The disadvantages of the moving average forecasting model are that the averages always stay within past levels, and the moving averages require extensive record keeping of past data. 11-7. When the smoothing value, , is high, more weight is given to recent data. When is low, more weight is given to past data. 11-8. The Delphi technique involves analyzing the predictions that a group of experts have made, and then allowing the experts to review the data again. This process may be repeated several times. After the final analysis, the forecast is developed. The group of experts may be geographically dispersed. 11-9. MAPE is a measure for determining the accuracy of a forecasting model by taking the average of the absolute percent errors. MAPE is important because it can be used to help increase forecasting accuracy. 11-10. We can draw line plots of the actual and forecast values for each observation (or time period). Such line plots are automatically drawn by most forecasting software including ExcelModules. The line plots can be used to show whether there are sizable errors in the forecast. In addition, they can be used to detect whether the forecasting model does a good job of replicating the pattern of actual values over the past few time periods. For the model to be valid, there should be no consistent under- or over-forecast seen, and forecast errors must be randomly distributed. 11-11. The correlation coefficient is a measure of the strength of the linear relationship between two variables. That is, it measures how one variables value is linearly related to changes in the value of the other variable. It is usually denoted by r and can be any number between and including -1 and +1. A value of +1 indicates the two variables are perfectly correlated in a positive manner (i.e., if either variable increases in value, the other one follows suit). A value of -1 indicates the two variables are perfectly correlated in a negative manner. Finally, a value of 0 indicates the two variables are not linearly correlated. 11-12. In order to use Solver to determine the optimal weights in the weighted moving average model, we set the weights as the decision variables (or Changing Cells). The objective (or Target Cell) is the measure of forecast error, such as MAD, MSE, or MAPE, which we wish to minimize. If we want to specify that the weights must add up to 1, we must include it as a constraint in the model. The only other constraint is the non-negativity constraint on the decision variables (weights). The Assume Linear Model option should not be checked in solving this problem since the formula for the objective function is nonlinear. SOLUTIONS TO PROBLEMS 11-13. (a, b, and c) See file P11-13.XLS, sheets 2-MA, 3-MA, 4-MA, 3-WMA, and Exp Sm. Period Actual Value 2-per MA 3-per MA 4-per MA 3-per WMA Exp Sm (0.3) Year 1 4 5.000 Year 2 6 4.700 Year 3 4 5.000 5.090 Year 4 5 5.000 4.667 4.500 4.763 Year 5 10 4.500 5.000 4.750 5.000 4.834 Year 6 8 7.500 6.333 6.250 7.250 6.384 Year 7 7 9.000 7.667 6.750 7.750 6.869 Year 8 9 7.500 8.333 7.500 8.000 6.908 Year 9 12 8.000 8.000 8.500 8.250 7.536 Year 10 14 10.500 9.333 9.000 10.000 8.875 Year 11 15 13.000 11.667 10.500 12.250 10.412 Year 12 14.500 13.667 12.500 14.000 11.789 (d) MAPE2-MA= 22.57%, MAPE3-MA= 22.92%, MAPE4-MA= 27.07%, MAPE3-WMA= 21.17%, MAPEExp Sm = 25.50%. The three-year weighted moving average should be selected because it has the lowest MAPE. 11-14. (a and b) See file P11-14.XLS, sheets 3-MA and Exp Sm. Period Actual Value 3-per MA Exp Sm (0.3) Sem 1 2.2 2.200 Sem 2 2.7 2.200 Sem 3 2.5 2.350 Sem 4 2.4 2.467 2.395 Sem 5 3.0 2.533 2.397 Sem 6 Sem 7 Sem 8 Sem 9 Sem 10 MAPE 2.7 2.5 3.6 3.2 2.633 2.700 2.733 2.933 3.100 10.20% 2.578 2.614 2.580 2.886 2.980 11.51% (c) The three-period moving average should be selected, as it has the lowest MAPE. (d) See file P11-14.XLS, sheet 3-WMA. Period Actual Value 3-per WMA Sem 1 2.2 Sem 2 2.7 Sem 3 2.5 Sem 4 2.4 2.320 Sem 5 3.0 2.580 Sem 6 2.7 2.700 Sem 7 2.5 2.520 Sem 8 3.6 2.800 Sem 9 3.2 3.060 Sem 10 2.780 MAPE 7.46% Optimal weights (found using Goal Seek) for WMA are 1.794, 0, and 1.196, respectively, for periods 1 (earliest) to 3 (latest). This is an improvement over the prior methods. 11-15. See file P11-15.XLS, sheets 2-MA, 3-MA, and 4-MA. Period Actual Value 2-per MA 3-per MA Day 1 522 Day 2 318 Day 3 508 420.000 Day 4 652 413.000 449.333 Day 5 488 580.000 492.667 Day 6 556 570.000 549.333 Day 7 589 522.000 565.333 Day 8 575 572.500 544.333 Day 9 606 582.000 573.333 Day 10 625 590.500 590.000 Day 11 615.500 602.000 4-per MA 500.000 491.500 551.000 571.250 552.000 581.500 598.750 11-16. (a and b) See file P11-16.XLS, sheets Exp Sm and LTA. The optimal weight for the exponential smoothing model is 0.27 (found using Solver). The linear trend equation is [438.667 + 19.133 Day]. Period Actual Value Day 1 522 Day 2 318 Day 3 508 Exp Sm 522.000 522.000 466.659 LTA 457.800 476.933 496.067 Day 4 Day 5 Day 6 Day 7 Day 8 Day 9 Day 10 Day 11 652 488 556 589 575 606 625 477.874 525.111 515.043 526.154 543.203 551.829 566.524 582.387 515.200 534.333 553.467 572.600 591.733 610.867 630.000 649.133 (c) The method with the lowest MAPE should be selected. In this case, it is the 4-period moving average model, with MAPE = 6.17%. 11-17. See file P11-17.XLS, sheets 2-MA, 3-MA, and 4-MA. Period Actual Value 2-per MA 3-per MA Week 1 17 Week 2 22 Week 3 25 19.500 Week 4 16 23.500 21.333 Week 5 28 20.500 21.000 Week 6 23 22.000 23.000 Week 7 19 25.500 22.333 Week 8 20 21.000 23.333 Week 9 17 19.500 20.667 Week 10 25 18.500 18.667 Week 11 33 21.000 20.667 Week 12 32 29.000 25.000 Week 13 32.500 30.000 4-per MA 20.000 22.750 23.000 21.500 22.500 19.750 20.250 23.750 26.750 11-18. (a and b) See file P11-18.XLS, sheets 3-WMA and Exp Sm. Optimal weights (found using Solver; Set sum of weights to 1) for WMA are 0, 0.417, and 0.583, respectively, for periods 1 (earliest) to 3 (latest). The optimal weight for the exponential smoothing model (also found using Solver) is 0.14. Period Actual Value 3-per WMA Week 1 17 Week 2 22 Week 3 25 Week 4 16 23.750 Week 5 28 19.750 Week 6 23 23.000 Week 7 19 25.083 Week 8 20 20.667 Week 9 17 19.583 Week 10 25 18.250 Week 11 33 21.667 Week 12 32 29.667 Week 13 32.417 Exp Sm 17.000 17.000 17.702 18.727 18.344 19.700 20.163 20.000 20.000 19.579 20.340 22.118 23.506 (c) Exponential smoothing should be selected because it has the lower MAPE (although both models are close). 11-19. (a, b, and c) See file P11-19.XLS, sheets Exp Sm 0.3, Exp Sm 0.6, Exp Sm 0.9, 3-MA, and LTA. The linear trend equation is [421.2 + 33.6 Year]. Of the three exponential smoothing constants, = 0.9 gives the forecast with the lowest MAPE (7.05%). Period Actual Value Exp Sm (0.3) Exp Sm (0.6) Exp Sm (0.9) Year 1 450 410.000 410.000 410.000 Year 2 495 422.000 434.000 446.000 Year 3 518 443.900 470.600 490.100 Year 4 563 466.130 499.040 515.210 Year 5 584 495.191 537.416 558.221 Year 6 521.834 565.366 581.422 3-per MA 487.667 525.333 555.000 LTA 454.800 488.400 522.000 555.600 589.200 622.800 (d) Of all the models, linear trend analysis is preferred because it has the lower overall MAPE (1.08%). 11-20. (a, b, and c) See file P11-20.XLS, sheets 3-WMA, Exp Sm, and LTA. The linear trend equation is [20.121 + 0.622 Week]. Period Actual Value 3-per WMA Week 1 20 Week 2 24 Week 3 21 Week 4 25 21.714 Week 5 19 23.714 Week 6 23 21.000 Week 7 26 22.143 Week 8 24 24.143 Week 9 27 24.429 Week 10 27 26.000 Week 11 25 26.571 Week 12 29 25.857 Week 13 27.571 Exp Sm 20.000 20.000 21.600 21.360 22.816 21.290 21.974 23.584 23.751 25.050 25.830 25.498 26.899 LTA 20.744 21.366 21.988 22.611 23.233 23.855 24.478 25.100 25.723 26.345 26.967 27.590 28.212 (d) Linear trend analysis should be used because it has the lowest MAPE (7.11%). 11-21. (a) See file P11-21.XLS, sheet Scatterplot for the graph. The observations do not form a perfect straight line but seem to approach linearity over the range shown. (b and c) See file P11-21.XLS, sheet Regress. The linear regression equation is Average Demand = 1.0 + 1.0 TV Appearances. If Green Shades performed 9 times last month, the forecast is for an average demand of 10 brass drums this month. 11-22. (a and b) See file P11-22.XLS, sheets 3-MA and 3-WMA. Month Actual Value 3-per MA 3-per WMA Jan 11 Feb 14 Mar 16 Apr 10 13.667 14.500 May 15 13.333 12.667 Jun 17 13.667 13.500 Jul 11 14.000 15.167 Aug 14 14.333 13.667 Sep 17 14.000 13.500 Oct 12 14.000 15.000 Nov 14 14.333 14.000 Dec 16 14.333 13.833 Jan 11 14.000 14.667 Feb 13.667 13.167 (c) MAPE for 3-per MA is 17.14% while MAPE for 3-per WMA is 21.37. Choose the 3-per MA model. 11-23. (a) See file P11-23.XLS, sheets Exp Sm 0.1, Exp Sm 0.6, and Exp Sm 0.9. Period Actual Value Exp Sm (0.1) Exp Sm (0.6) Exp Sm (0.9) Week 1 50 50.000 50.000 50.000 Week 2 35 50.000 50.000 50.000 Week 3 25 48.500 41.000 36.500 Week 4 40 46.150 31.400 26.150 Week 5 45 45.535 36.560 38.615 Week 6 35 45.482 41.624 44.362 Week 7 20 44.433 37.650 35.936 Week 8 30 41.990 27.060 21.594 Week 9 35 40.791 28.824 29.159 Week 10 20 40.212 32.530 34.416 Week 11 15 38.191 25.012 21.442 Week 12 40 35.872 19.005 15.644 Week 13 55 36.284 31.602 37.564 Week 14 35 38.156 45.641 53.256 Week 15 25 37.840 39.256 36.826 Week 16 55 36.556 30.703 26.183 Week 17 55 38.401 45.281 52.118 Week 18 40 40.061 51.112 54.712 Week 19 35 40.055 44.445 41.471 Week 20 60 39.549 38.778 35.647 Week 21 75 41.594 51.511 57.565 Week 22 50 44.935 65.604 73.256 Week 23 40 45.441 56.242 52.326 Week 24 Week 25 65 44.897 46.907 46.497 57.599 41.233 62.623 (b) Students should note how stable the smoothed values are for = 0.1. When compared to actual week 25 calls of 85, the = 0.6 model appears to do a better job. On the basis of the forecast error also, the = 0.6 model is better. However, other smoothing constants need to be examined. For example, using Solver we find that the smoothing constant that minimizes MAPE is 0.279. The MAPE in this case is 35.06%. 11-24. (a) See file P11-24.XLS, sheets Exp Sm 0.2, Exp Sm 0.5, and Exp Sm 0.9. Period Actual Value Exp Sm (0.2) Exp Sm (0.5) Exp Sm (0.9) Week 1 17 17.000 17.000 17.000 Week 2 21 17.000 17.000 17.000 Week 3 19 17.800 19.000 20.600 Week 4 23 18.040 19.000 19.160 Week 5 18 19.032 21.000 22.616 Week 6 16 18.826 19.500 18.462 Week 7 20 18.260 17.750 16.246 Week 8 18 18.608 18.875 19.625 Week 9 22 18.487 18.438 18.162 Week 10 20 19.189 20.219 21.616 Week 11 15 19.351 20.109 20.162 Week 12 22 18.481 17.555 15.516 Week 13 19.185 19.777 21.352 (b) If = 0.2, MAPE = 13.40%. If = 0.5, MAPE = 14.79%. If = 0.9, MAPE = 18.40%. The forecast with = 0.2 has the lowest MAPE, and should therefore be used. 11-25. (a) See file P11-25.XLS, sheets Exp Sm 0.1 and Exp Sm 0.3. Month Actual Value Exp Sm (0.1) Exp Sm (0.3) Jan 70.0 65.0 65.000 Feb 68.5 65.5 66.500 Mar 64.8 65.8 67.100 Apr 71.7 65.7 66.410 May 71.3 66.3 67.997 Jun 72.8 66.8 68.988 Jul 70.0 65.0 65.000 Aug 67.4 70.132 (b) If = 0.1, MAPE = 5.91%. If = 0.3, MAPE = 4.74%. The forecast with = 0.3 has the lowest MAPE, and should therefore be used. (c) See file P11-25.XLS, sheet Exp Sm Opt. The optimal value for (found using Solver) is 0.7, which results in a MAPE of 3.65%. 11-26. (a) See file P11-26.XLS, sheets (a) Exp Sm, (a) LTA, and (a) Regr. Comparing the MAPE values for the three models, we see that MAPE Exp Sm = 20.89%. MAPELTA = 1019.32%, and MAPERegr = 707.88%. The exponential model smoothing seems to be the clear choice for the best model. (b) We can easily make a case for excluding older data. If we do so, the conclusions may change. For example, if we include the data for just the last 16 years (1989 onwards), the revised MAPE values are MAPEExp Sm = 17.05%, MAPELTA = 14.83%, and MAPEReg = 28.20%. See file P11-26.XLS, sheets (b) Exp Sm, (b) LTA, and (b) Regr. 11-27. (a) See file P11-27.XLS, sheet LTA. The trend equation is Average Ridership = 11.288 + 1.738 Year. The forecasted riderships for years 13, 14, and 15 are 33.879, 35.617, and 37.354, respectively. The MAPE is 26%, indicating that the LTA model may not be very effective. (b) See file P11-27.XLS, sheet Scatterplot. It appears from the graph that the points scatter around a straight line. (c) The linear equation is Average Ridership = 5.060 + 1.593 Tourists. (d) Expected ridership for 10 million tourists is 2,099,000 riders. 11-28. See file P11-28.XLS. The trend equation is Average Patients = 29.733 + 3.285 Year. For years 11, 12 and 13, the forecasted patients are 65.867, 69.152, and 72.436 respectively. Comparing the trend line with the actual observations, we see that the model is reasonably accurate (albeit not exceptionally accurate). The MAPE is 7.01%. 11-29. (a) See file P11-29.XLS, sheet Scatterplot. It appears from the graph that the points scatter around a straight line. (b) Average Patients = 1.229 + 0.545 Crime Rate (c) If crime rate = 131.2, average patients = 72.7. (d) If crime rate = 131.2, average patients = 50.6. 11-30. See file P11-30.XLS. The seasonal indices are 0.90 for fall, 1.30 for winter, 0.63 for spring, and 1.17 for summer. Seasonalized demand in year 3 for these four seasons is forecast to be 270, 390, 189, and 351 radials, respectively. 11-31. See file P11-31.XLS. Seasonalized sales forecast = Trend forecast x seasonal index. Hence the seasonalized forecasts for quarters I to IV are $130,000, $108,000, $98,000, and $176,000 respectively. 11-32. See file P11-32.XLS. (a) Average Dividends = -0.101 + 0.351 EPS (b) The R2 value for this model is 0.69. Hence, earnings per share (EPS) explains 69% of the variance in dividends per share (DPS). (c) When EPS = $0.33, average DPS = $0.015. 11-33. See file P11-33.XLS. (a) Average GPA = 1.028 + 0.003 SAT. As an indication of the usefulness of this relationship, we can calculate the correlation coefficient r = 0.692 and r2 = 0.479. A correlation coefficient of 0.692 is not particularly high. The coefficient of determination indicates that the model explains only 47.9% of the overall variation. Therefore, while the model does provide an estimate of GPA, there is considerable variation in GPA, which is as yet unexplained. (b) If SAT = 450, the average GPA is 2.38 (c) If SAT = 450, the average GPA is 3.77. However, SAT of 800 is outside the range of independent variable values for which this regression model was developed. It may therefore not be appropriate to use this model to predict Sarahs score. 11-34. See file P11-34.XLS. (a) Average Market Value = 17,227.294 - 0.096 Mileage (b) R2 = 0.722, which implies 72.2% of the variation in market value is explained by mileage. (c) At 45,700 miles, the market value is predicted to be $12,861.75. To build a 95% confidence interval, we compute 12,861.75 2.26 standard error. This results in an interval from $10,341.19 to $15,382.32. 11-35. See file P11-35.XLS. (a) The prediction equation is: Average Mileage = 16,699.519 - 0.039 Mileage - 507.303 Age (b) R2 = 0.739, which implies 73.9% of the variation in market value is explained by mileage and age. (c) The revised interval is from $9,754.76 to $14,979.50. Because more variance has been accounted for, the interval changes slightly. 11-36. See file P11-36.XLS. (a) Average GPA = 2.094 + 0.002 GMAT (b) R2 = 0.439, which implies 43.9% of the variation in GPA is explained by GMAT scores. (c) 3.22 to 3.96 11-37. See file P11-37.XLS. (a) Average GPA = 1.378 + 0.002 GMAT + 0.034 Age (b) R2 = 0.695, which implies 69.5% of the variation in GPA is explained by the combination of GMAT scores and age. (c) 3.223 to 3.801. The added predictive power of age changes the size of the confidence interval. 11-38. See file P11-38.XLS. (a) Average Demand = 13.937 +0.005 Advertising dollars (b) R2 = 0.454, which implies 45.4% of the variation in demand is explained by advertising dollars spent. (c) The predicted demand for an advertising budget of $3,600 is 33.244 units. 11-39. See file P11-39.XLS. (a) Average Demand = 13.249 + 0.004 Advertising dollars + 0.104 Snowfall (b) R2 = 0.461, which implies 46.1% of the variation in demand is explained by advertising dollars spent and annual snowfall. (c) The predicted demand for an advertising budget of $3,600 and expected snowfall of 360 inches is 34.030 units. 11-40. See file P11-40.XLS for the calculations using centered moving averages. We have data for 48 periods with 12 seasons (months) per year. The MAPE is 4.58% indicating that the multiplicative decomposition model does a reasonable job of predicting quarterly sales. This is also indicated by the error graph, which shows that the forecasted and actual values are very close to each other. Seasonalized forecasts for the 12 months of 2005 are 56,483.303, 66,054.361, 23,927.390, 28,619.656, 27,562.990, 16,483.092, 17,497.696, 19,545.717, 20,013.797, 62,135.426, 93,005.609, and 83,282.348 respectively. 11-41. See file P11-41.XLS for the calculations using centered moving averages. We have data for 16 periods, with 4 seasons (quarters) per year. The MAPE is just 1.06% indicating that the multiplicative decomposition model does a very good job of predicting quarterly sales. This is also indicated by the error graph, which shows that the forecasted and actual values are nearly identical. Seasonalized forecasts for the 4 quarters of 2005 are 59.451, 66.134, 72.848, and 98.331 respectively. 11-42. (a) See file P11-42.XLS, sheet Exp Sm. The optimal value of (found using Solver) is 1. MAPE = 1.09%. (b) See file P11-42.XLS, sheet LTA. The linear trend equation is Average GNP = 8550.825 + 112.476 Time period. MAPE = 0.76%. Forecast for first quarter of 2005 is 10,462.925. (c) See file P11-42.XLS, sheet 4-MA. MAPE = 2.79%. Forecast for first quarter of 2005 is 10,104. (d) Linear trend analysis should be selected because it has the lowest MAPE. 11-43. See file P11-43.XLS for the calculations using centered moving averages. We have data for 16 periods, with 4 seasons (quarters) per year. The MAPE for this model is 0.76%. Seasonalized forecasts for the 4 quarters of 2005 are 10,473.877, 10,580.211, 10,657.009, and 10,818.609 respectively. 11-44. (a) See file P11-44.XLS, sheet Exp Sm. The gasoline price for January of Year 4 is $1.24. (b) See file P11-44.XLS, sheet Exp Sm. The linear trend equation is Average Gas Price = 1.156 + 0.012 Period. The gasoline price for January of Year 4 is $1.598. (c) Exponential smoothing is more accurate with a MAPE of 5.66%. 11-45. See file P11-45.XLS. We have data for 36 periods with 12 seasons (months) per year. The MAPE for this model is 8.71%. Seasonalized forecasts for the 12 months of Year 4 are 1.490, 1.535, 1.613, 1.658, 1.752, 1.786, 1.696, 1.681, 1.720, 1.690, 1.667, and 1.638 respectively. 11-46. (a) See file P11-46.XLS, sheet 4-MA. Forecast for first quarter of Year 5 is 359.250. MAPE = 8.75%. (b) See file P11-46.XLS, sheet LTA. The linear trend equation is Average Sales = 335.775 + 2.696 Quarter. Forecast for first quarter of Year 5 is 381.6. MAPE = 8.67%. (c) The linear trend model is slightly more accurate as it has a lower MAPE. 11-47. (a) See file P11-47.XLS, sheet Mult. Seasonalized forecasts for the 4 quarters of Year 5 are 335.740, 348.626, 372.056, and 426.170 respectively. MAPE = 4.41%. (a) See file P11-47.XLS, sheet Add. Seasonalized forecasts for the 4 quarters of Year 5 are 335.258, 347.784, 371.059, and 423.335 respectively. MAPE = 4.34%. (c) The additive decomposition model has a slightly lower MAPE. 11-48. (a) See file P11-48.XLS, sheet 4-MA. Forecast for first quarter of year 5 is 448.25. MAPE = 23.31%. (b) See file P11-48.XLS, sheet Exp Sm. Forecast for first quarter of year 5 is 470.606. MAPE = 24.20% (c) The four-period moving average is slightly more accurate as it has a lower MAPE. 11-49. See file P11-49.XLS. (a) See file P11-49.XLS, sheet Mult. Seasonalized forecasts for the 4 quarters of Year 5 are 397.769, 588.836, 587.768, and 446.333 respectively. MAPE = 11.48%. (a) See file P11-49.XLS, sheet Add. Seasonalized forecasts for the 4 quarters of Year 5 are 405.142, 567.794, 564.197, and 452.391 respectively. MAPE = 10.82%. (c) The additive decomposition model has a slightly lower MAPE. Case: North-South Airline See file P11-Airline.XLS. Utilizing ExcelModules, we can develop the following regression equations for the variables of interest. Each regression is shown on a separate worksheet. Northern Airline -- Airframe maintenance cost: Cost = 36.097 + 0.0026 x Airframe age. R2 = 0.769. Coefficient of correlation = 0.877. Northern Airline -- Engine maintenance cost: Cost = 20.571 + 0.0026 x Airframe age. R2 = 0.612. Coefficient of correlation = 0.783. Southeast Airline -- Airframe maintenance cost: Cost = 4.597 + 0.0032 x Airframe age. R2 = 0.390. Coefficient of correlation = 0.625. Southeast Airline -- Engine maintenance cost: Cost = 0.671 + 0.0041 x Airframe age. R2 = 0.460. Coefficient of correlation = 0.678. Northern Airline: There seem to be modest correlations between maintenance costs and airframe age for Northern Airline. There is certainly reason to conclude, however, that airframe age is not the only important factor. Southeast Airline: The relationships between maintenance costs and airframe age for Southeast Airline are much less well defined. It is even more obvious that airframe age is not the only important factor -perhaps not even the most important factor. Overall, it would seem that: Northern Airline has the smallest variance in maintenance costs, indicating that the day-to-day management of maintenance is working pretty well. Maintenance costs seem to be more a function of airline than of airframe age. The airframe and engine maintenance costs for Southeast Airline are not only lower but also more nearly similar than those for Northern Airline, but from the graphs at least, appear to be rising slightly more sharply with age. From an overall perspective, it appears that Southeast Airline may perform more efficiently on sporadic or emergency repairs, and Northern Airline may place more emphasis on preventive maintenance. Ms. Youngs report should conclude that: There is evidence to suggest that maintenance costs could be made to be a function of airframe age by implementing more effective management practices. The difference between maintenance procedures of the two airlines should be investigated. The data with which she is presently working do not provide conclusive results. Case: Southwestern University (1) Since homecoming and the crafts festival occur during the same games each year, we could think of it as there being a seasonal effect on attendance each year. We can therefore develop a multiplicative decomposition model for SWU. We have data for 30 past periods (games), with 5 seasons each year. The calculations using centered moving average are shown in file P11-SWU.XLS. The MAPE is only 3.63% indicating that the multiplicative decomposition model does a reasonable job of predicting football attendance. This is also indicated by the error graph, which shows that the forecasted and actual values are very close to each other. Attendance in the 5 games of 2005 (i.e., games 31 to 35) is 48098, 55055, 51451, 36116, and 49559 respectively. Attendance in the 5 games of 2006 (i.e., games 36 to 40) is 50520, 57799, 53990, 37880, and 51957 respectively. (2) With a ticket price of $20, revenues in 2005 (i.e., games 31 to 35) are expected to be $961,968, $1,101,106, $1,029,023, $722,312, and $991,177 respectively. With a ticket price of $21 (5% increase), revenues in 2006 (i.e., games 36 to 40) are expected to be $1,060,915, $1,213,784, $1,133,793, $795,488, and $1,091,100 respectively. (3) It appears that the school will run out of space for the homecoming game in 2006. It may be time for Dr. Starr to start to a fund raising campaign for a stadium expansion project. Of course, they could run out of space even earlier if SWU does get the number-one ranking next year. Alternatively, attendance could drop off sharply if Pitterno does not achieve what is expected of him.
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3Dive Into Web 2.0Network effects from user contributions are the key to market dominance in the Web 2.0 era.Tim OReillyLink by link, click by click, search is building possibly the most lasting, ponderous, and significant cultural artifact in the his
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4Introduction to XHTMLTo read between the lines was easier than to follow the text.Henry JamesHigh thoughts must have high language.AristophanesOBJECTIVESIn this chapter you will learn:Yea, from the table of my memory Ill wipe away all trivial fon
St. Leo - COM - 340
5Fashions fade, style is eternal.Yves Saint LaurentCascading Style Sheets (CSS)OBJECTIVESIn this chapter you will learn:A style does not go out of style as long as it adapts itself to its period. When there is an incompatibility between the style an
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6Comment is free, but facts are sacred.C. P. ScottJavaScript: Introduction to ScriptingOBJECTIVESIn this chapter you will learn: The creditor hath a better memory than the debtor.James HowellWhen faced with a decision, I always ask, What would be
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7Let's all move one place on.-Lewis CarrollJavaScript: Control Statements IOBJECTIVESIn this chapter you will learn: The wheel is come full circle.-William ShakespeareHow many apples fell on Newton's head before he took the hint!-Robert FrostBa
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8Not everything that can be counted counts, and not every thing that counts can be counted.Albert EinsteinJavaScript: Control Statements IIOBJECTIVESIn this chapter you will learn: Who can control his fate?William ShakespeareThe essentials of cou
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9JavaScript: FunctionsForm ever follows function.Louis SullivanE pluribus unum. (One composed of many.)VirgilOBJECTIVESIn this chapter you will learn:O! call back yesterday, bid time return.William ShakespeareTo construct programs modularly from
St. Leo - COM - 340
10JavaScript: ArraysWith sobs and tears he sorted out Those of the largest size . . .Lewis CarrollAttempt the end, and never stand to doubt; Nothings so hard, but search will find it out.Robert HerrickOBJECTIVESIn this chapter you will learn: To
St. Leo - COM - 340
11JavaScript: ObjectsMy object all sublime I shall achieve in time.W. S. GilbertIs it a world to hide virtues in?William ShakespeareOBJECTIVESIn this chapter you will learn: Good as it is to inherit a library, it is better to collect one.Augusti
Acton School of Business - CIVIL - 201
CIVL04C03Lecture 5: Distance MeasurementKeith MillerIn partnership withDistance Measuremento To examine techniques used in measuring distance. Tape. Electromagnetic (EDM).o Distances provide Scale to control Position topographic detail Set out
Acton School of Business - CIVIL - 201
Geometrics in SurveyingLecture 6: Stadia TacheometryThe use of theodolite and staff to determineposition and height.Keith MillerIn partnership withStadia TacheometryooUse of stadia to determine distances and heightdifference.To define a method
Acton School of Business - CIVIL - 201
Geometrics in SurveyingLecture 7: Detail SurveysKeith MillerIn partnership withDetail SurveysObjectiveso Understand the requirements of a detail survey, and henceplanning issues.o Appreciate the application of control survey work coveredto date i
Acton School of Business - CIVIL - 201
Geometrics in SurveyingLecture 8: Total StationsKeith MillerIn partnership withTotal StationsObjectives for todayo The Surveying Project to understand the proceduresadopted in a typical survey based project.o Survey Control Recap how to establish
Acton School of Business - CIVIL - 201
Geomatics in SurveyingGeomatics in SurveyingLecture 9:Setting Out StructuresStKeith MillerIn partnership withSetting OutObjectiveso Awareness of responsibilities of the setting outengineer and standards that exist.o Understand the procedure for
Acton School of Business - CIVIL - 201
Geomatics in SurveyingGeomatics in SurveyingLecture 10:Setting Out CurvesKeith MillerIn partnership withSetting Out CurvesObjectiveso Define horizontal curves, vertical curves andcompound curves with applications.o Determine the geometry of the
Acton School of Business - CIVIL - 201
Faculty of EngineeringModule code:CIVL04C02Title : Surveying (1)Examination of January 2009SECTION A COMPULSORY QUESTIONQ1. A level loop was run from a bench mark through the bounds of a new construction site to levelmarks that will be used as poin
Acton School of Business - CIVIL - 201
CIVL04C02 (Geometrics in Surveying), Semester 1, 2009/10Practical Exam Schedule for students in Architectural Engineering9:00Sunday3rdJanuary109552 IbrahimMohamedSalaheldin109593 MamdouhAbdlELHamid109596 MarwanMamdouhKassab10946710949110951310960
Acton School of Business - CIVIL - 201
School of EngineeringCivil Eng. DepartmentCIVL04C031st Semester 2009 / 2010Practical Exam ScheduleID No.STUDENT NAME13109433Ahmed Adel Badr El Din4109434Ahmed Alaa Al-Din109448Ahmed Hesham Mahmoud109452Ahmed Khalid Bauomi7109454Ahmed M
Acton School of Business - CIVIL - 201
CIVL04C03 Practical 1LEVELLINGAimTo undertake a levelling exercise that will establish heights for specified locations relative toa defined reference point. In addition to detailing height values, students are expected to showthat quality control pro
Acton School of Business - CIVIL - 201
CIVL04C03 Practical 2THEODOLITE AND ANGLESAimThrough the observation of a number of rounds of horizontal and vertical angles someassessment is to be made of the combined accuracy achieved by the instrument and the observer.This exercise deals with ho
Acton School of Business - CIVIL - 201
School of EngineeringGEOMATICS IN SURVEYINGCIVL04C03 Practical 3Lecturer:Assistant:Keith MillerMaha Hussien and Mohamed HegazyDETAIL SURVEYAimProduce a survey plan of a part of the BUE campus as defined in the group area plan toinclude boundarie
Acton School of Business - CIVIL - 201
CIVL04C03 Practical ExaminationStadia Tacheometry and LevellingThis is an examination arrive punctually. A schedule is also posted.30 minutes is allowed for field work, and the remaining 30 minutes is for calculations.This paper is available to studen
Acton School of Business - CIVIL - 201
School of EngineeringGEOMETRICS IN SURVEYINGCIVL 04C03 (10 Modular weight: 2hrs. Lecture, 1 hrs. Tutorial/Practical)Professor:Dr. Keith MillerPre-requisites:NoneText Books:Elementary Surveying: An Introduction to Geomatics,C. D. Ghilani and P. R.
Acton School of Business - CIVIL - 201
PointBUEIBUECEastInstrumentReferenceReferenceBearing3.420769605 195.9957629.483621.803NorthHeightInst. Ht.939.11001.532912.309Point details in here.East and North from witness diagrams,Height from result of first levelling exercise.Be
Acton School of Business - CIVIL - 201
CONSTRUCTION TECHNOLOGYCONSTRUCTION TECHNOLOGYIntroductionDr MaguidDr. Maguid H.M. HassanHassanExt. 1413Email: mhassan@bue.edu.egDr AmrDr. Amr HelmyExt. 1416 Room 206 Building AEmail: amr.helmy@bue.edu.egContentsContentsReviewReview Course
Holy Names - BUS - 295W
Netflixs Business Model and Strategy in Rending Movies and TV EpisodesNetflix, founded in 1997 by Reed Hastings is the worlds largest online movie rental service;with revenues of 1.2 billion by the end of 2007. Netflix has a library of 100,000 movie tit
USC - CSCI - CSCI460
CS 460: Artificial IntelligenceInstructor: Prof. K. Narayanaswamy (Swamy), swamy@cs3-inc.comOffice hours: For Instructor by appointment; before/after classLectures: Tuesdays 6 p.m. to 8:50 p.m. at GFS 1182 lectures of 1 hour 15/20 minutes with a break
USC - CSCI - CSCI460
Last Time: Acting Humanly: The Full Turing Test Alan Turing's 1950 article Computing Machinery and Intelligencediscussed conditions for considering a machine to be intelligent Can machines think? Can machines behave intelligently? The Turing test (The
USC - CSCI - CSCI460
Last time: Summary Definition of AI? Turing Test? Intelligent Agents: Anything that can be viewed as perceiving its environment throughsensors and acting upon that environment through its effectors tomaximize progress towards its goals. PAGE (Perce
USC - CSCI - CSCI460
Complexity Why worry about complexity of algorithms?because a problem may be solvable in principle but maytake too long to solve in practiceCS 460, Lecture 41Complexity: Tower of HanoiCS 460, Lecture 42Complexity:Tower of HanoiCS 460, Lecture 4
USC - CSCI - CSCI460
A Clean Robust Uniform Cost Search AlgorithmFunction UniformCost-Search(problem, Queuing-Fn) returns a solution, or failureopenmake-queue(make-node(initial-state[problem])closed[empty]loop doif open is empty then return failurecurrnodeRemove-Fron
USC - CSCI - CSCI460
Informed SearchUse heuristics to guide the search What is a heuristic? Guidelines/Intuitions that are based on informationoutsideoutside the problem formulation Best first Greedy Search A* Many variations of A* are used Hill-climbing / Simulated
USC - CSCI - CSCI460
Iterative improvement In many optimization problems, PATH is irrelevant;the goal state itself is the solution. Then, state space = space of complete configurations.Algorithm goal:- find optimal configuration (e.g., TSP), or,- find configuration sati
USC - CSCI - CSCI460
Game PlayingThe minimax algorithmResource limitationsalpha-beta pruningElements of chanceCS 460, Session 81What kind of games? Abstraction: To describe a game we must captureevery relevant aspect of the game. Such as: Chess Tic-tac-toe Accessi
USC - CSCI - CSCI460
2. - pruning: search cutoff Pruning: eliminating a branch of the search tree fromconsideration without exhaustive examination of eachnode - pruning: the basic idea is to prune portions of thesearchsearch tree that cannot improve the utility value of
USC - CSCI - CSCI460
Knowledge and ReasoningKnowledge representationWumpus world exampleLogic in general: models and entailmentPropositional (Boolean) logicNormal formsEquivalence, validity, satisfiabilityInference in propositional logic Forward and Backward Chaining
USC - CSCI - CSCI460
Proof methodsCS 460, Sessions 111Inference Rules Part ICS 460, Sessions 112Inference Rules Part IICS 460, Sessions 113Wumpus world: example Facts: Percepts inject (TELL) facts into the KB [stench at 1,1 and 2,1]S1,1 ; S2,1 Rules: if square ha
USC - CSCI - CSCI460
Pros and cons of propositional logic Propositional logic is declarative Propositional logic allows partial/disjunctive/negated information (unlike most data structures and databases) Propositional logic is compositional: meaning of B1,1 P1,2 is deriv
USC - CSCI - CSCI460
Translating English to FOL No purple mushroom is poisonous.CS 460, Session 131Translating English to FOL No purple mushroom is poisonous.( x) purple(x) mushroom(x) poisonous(x)or, equivalently,( x) (mushroom(x) purple(x) =>poisonous(x)CS 460, Se
USC - CSCI - CSCI460
Inference in First-Order Logic Proofs Unification Generalized modus ponens Forward and backward chaining Completeness Resolution Logic programmingCS 460, Session 141Inference in First-Order Logic Proofs extend propositional logic inference to d
USC - CSCI - CSCI460
UnificationGoal of unification: finding CS 460, Session 151Unificationcfw_ x/OJ , y/John CS 460, Session 152Unification To unify Knows(John,x) and Knows(y,z), = cfw_y/John, x/z or = cfw_y/John, x/John, z/John The first unifier is more general
USC - CSCI - CSCI460
Forward chaining algorithmStandardize-Apart : replaces all variables in the arguments with NEWvariables that will not conflict with any other variables usedCS 460, Session 161Example Knowledge Base. it is a crime for an American to sell weapons to h
USC - CSCI - CSCI460
Logic programming: Prolog I Algorithm = Logic + Control Basis for Prolog: Backward chaining with Horn clauses + A few interesting bells & whistles Widely used in Europe, Japan (basis of 5th Generation project) Compilation techniques 60 million LIPS
USC - CSCI - CSCI460
Completeness As explained earlier, Generalized Modus Ponens requiressentences to be in Horn form: atomic, or an implication with a conjunction of atomic sentences as theantecedent and an atom as the consequent. However, some sentences cannot be expr
USC - CSCI - CSCI460
Planning (some slides from Tom Lenaerts)The Planning problemPlanning with State-space searchPartial-order planningPlanning graphsPlanning with propositional logicAnalysis of planning approachesCS 460, Session 191What we have so far Can TELL KB a
USC - CSCI - CSCI460
Sussman Anomaly in the block worldCS 460, Session 201Sussman Anomaly The Sussman Anomaly shows the limitations of non-interleavedplanning methods Before this was described, people used to do planning byconsidering different subgoals in SEQUENCE Th
USC - CSCI - CSCI460
Knowledge Representation Knowledge engineering: principles and pitfalls Ontologies ExamplesCS 460, Session 211Knowledge Engineer Populates KB with facts and relations Must study and understand domain to pick important objectsand relationships Ma
USC - CSCI - CSCI460
UncertaintyUncertaintyChapter 13 of AIMA1OutlineUncertaintyProbabilitySyntax and SemanticsInferenceIndependence and Bayes' RuleCS 460, Session 222UncertaintyLet action At = leave for airport t minutes before flightWill At get me there on tim
USC - CSCI - CSCI460
What is fuzzy logic?A super set of Boolean logicBuilds upon fuzzy set theoryGraded truth. Truth values between True and False. Not everything iseither/or, true/false, black/white, on/off etc.Grades of membership. Class of tall men, class of far citie
USC - CSCI - CSCI460
Learning Outline of What we will CoverBackgroundLearning agentsInductive learningDecision tree learningBrief Overview of Neural NetworksCS 460, Session 241Learning Learning is essential for unknown environments, i.e., when designer lacks omnisci
USC - CSCI - CSCI460
Neural Networks OverviewSource:Elena MarchioriKees JongfromVrije UniversityAmsterdam, NetherlandsCSCI 460; Lecture 251What are Neural Networks? Simple computational elements forming a largenetwork Emphasis on learning (pattern recognition) Lo
USC - CSCI - CSCI460
IntroductionSource: Elaine Rich (UT Austin)CS 460, Session 261Spoken LanguageThe dream:HAL (2001 A Space Odyssey)Going Both WaysUnderstandingGenerationCS 460, Session 262English: Put the kids cereal on the bottomshelves.CS 460, Session 263
USC - CSCI - CSCI460
Towards intelligent machines (Source: Prof. Itti)Thanks to CSCI460, we now know how to-Search (and play games)Represent problems in propositional logic where appropriateBuild a knowledge base using FOLUse FOL inference to ask questions to the KBPla
USC - CSCI - 460
Final ExaminationCSCI 460: Artificial IntelligenceDecember 14, 2010Instructions:1.2.3.4.5.6.Duration: 120 MinutesDate: 12/14/2010 from 7:00 9:00 pmMaximum credits/points for this midterm: 100 points5 questions.Credits/points for each questio
USC - CSCI - 460
1) Login to aludra.usc.edu using your USC account2) In your home directory, type pico .cshrc (note the period)3) Scroll down all the way to the bottom and set the following path variables by typing:setenv PL_PATH /auto/usc/gnu/prolog/1.3.0setenv PATH
USC - CSCI - 460
CSCI 460 : Introduction to Artificial IntelligenceFall 2010Prof. K. NarayanaswamyHomework # 1Due Date: September 19, 2010QUESTIONMAX POSSIBLEQuestion 130Question 240Question 330TOTAL:POINTS30 Points/ 5 Points per part1) For each of the fol
USC - CSCI - 460
CSCI 460 : Introduction to Artificial IntelligenceFall 2010Prof. K. NarayanaswamyHomework # 2Due Date: October 3, 2010QUESTIONMAX POSSIBLEQuestion 125Question 250Question 325TOTAL:POINTS25 Points1) Consider the graph with 10 nodes A1, A2,
USC - CSCI - 460
CSCI 460 : Introduction to Artificial IntelligenceFall 2010Prof. K. NarayanaswamyHomework # 3Due Date: October 24, 2010QUESTIONMAX POSSIBLEQuestion 1AQuestion 1BQuestion 1CQuestion 1D5555Question 2AQuestion 2BQuestion 2C1488Question 3
USC - CSCI - 460
CSCI460 Introduction to Artificial IntelligenceInstructor: Dr. K. NarayanaswamyAssignment 4 Einsteins RiddleDue: 11/7/2010 11:59:59pmProblem: This is a world-famous logic problem. It is said to be written by AlbertEinstein early during the 20th centu